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  • Laptop hot after format [migrated]

    - by Dany Khalife
    I recently formatted an HP G62 Laptop and installed all drivers from the HP site that should be installed for this model. But i noticed a very strange behavior, using Coretemp, the temp is always above 50 (on idle) and reaches 70 very quickly sometimes (Critical is 90) If i open youtube or skype alone, i can get temperatures as high as 83. Normally it was around 32 (on idle) and reaches 70 when i open games but not youtube.... I have a i3 processor and AMD graphics so i am wondering if somehow it's a graphics card issue (since i3 has integrated graphics as far as i know) Device manager shows only AMD graphics card tho, not sure if i3 graphics should appear here too. Any ideas what i might have forgotten to do after the format ?

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  • Generating and collaborating on network map diagrams?

    - by Ian C.
    I have to turn out some network topology maps for very large networks. I'd like the format for the maps to be something other people can also edit and contribute to regardless of what software I'm using on my Mac to build them. I don't mind spending money on my end for software, but I can't require that my clients spend any money. I also can't promise my clients are also using OS X -- they could be running Linux or Windows. Is there a best software application on OS X for producing maps that I can share with other, non-OS X, users? Is there a best format for sharing topology maps that I should use when exporting the maps to disk?

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  • In Excel format number with optional decimal places

    - by Ray
    Simple: I have numbers in cells in excel. I want the numbers formatted so that if they have decimal places they show to a maximum of 2DP and if they have no decimal places it doesn't show any. For example. 15 should be formatted as 15 NOT 15.00 14.3453453 should be formatted as 14.35 12.1 should be formatted as 12.1 0 should be formatted as 0 The closest custom format code I've come up with is 0.##. Unfortunately this formats 15.00 as 15. (note the extra decimal place). Edit: To further complicate the issues, the spreadsheet is a result of an export from SQL Server Reporting Services. So no macros are possible. Oh well, it looks like 0.## is my best bet, and they can just live with the extra period.

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  • How to copy and paste code with retaining the format

    - by Sab
    This question may have been asked before but I was unable to find any solution. So here goes: When I browse and see some code that I would like to copy I simply use ctrl+c and ctrl+v. Most of the time this works fine. But in some cases (websites like stackoverflow and others ) when I copy the code and paste it , it only comes on one line in eclipse. I have tried pasting this code into eclipse and select all and hitting auto format but this doesnt help either. I have also pasted the code into komodo and word. But to no avail. The code simply refuses to align itself. Does anyone know any solution to this?

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  • unable to format external drive to HFS+ for Mac

    - by dtlussier
    I have an external hard drive (1 TB Western Digital) that is currently formatted as FAT32 and I want to reformat it to a single partition of HFS+ for my Mac. I realize that I can read FAT32 from my Mac but want HFS as it has other feathers like permissions that I'd like to have. I have tried using Disk Utility to format the drive as I have done in the past, but when I go through the process it fails and throws out an error stating that it is unable to reformat the drive to HFS. What might be the reasons that this could happen? Are there any diagnostics I could run on the physical disk to check if it is running well?

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  • Writing good looking documentation in pdf format on a mac [closed]

    - by Matthew
    I'd like to write some documentation that will be written in sections (1.1, 1.2, 2.1, 2.2, 2.3, etc). I'd like to use something that will generate the table of contents in the end or at least have it "linked" up so that when I make changes everything is still accurate (if I merge section 2.1 and 2.2 or something). The end result needs to be in pdf. I don't want to pay $350 for Acrobat Pro either... I've got microsoft word, but every little thing is a pain (for example, having one background of a page be a different color than another). Any ideas on how to create quality documentation in a pdf format?

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  • Installed Ubuntu on usb drive, now it's read-only and can't be formatted

    - by weiszam
    I installed Ubuntu (ubuntu-13.04-desktop-amd64) on a 8 gb pendrive. Because it worked pretty slow, I wanted to change it back to a normal pendrive. But this is what happened. Windows7 can't open the usb drive, can't view files or anything, can't access attributes. When I select to format, it says it can't format it because it is write-protected. Tried the same running from an Ubuntu, and trying from a booted GParted thing. When I view the partitions, they can't be deleted either. What should I do to get it formatted?

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  • Password format not liked by installer

    - by Box293
    I'm installing Chargeback and I get to the database-related information page (step 5 on page 17 of the users guide). Using a Windows account (it is an administrator of the server and I am logged on as that user) Username: DOMAIN\ServiceVMware-CB Password: #$%UuuU2u (this isn't the password but it does start with #$% and is the same length and case) I click the Test Connected and it returns back OK. I click Next and then I am given a warning telling me that the account does not have the right permissions. Check that it has log on as a service etc etc etc. I quit the installer. I change the password in the domain to Uuuuuu3 I reboot the server I restart the server The installer has no problems with the newer password. I'm not fussed either way, I'm just trying to save someone else the pain and perhaps the allowed password format could be added to the documentation. BTW I am using Server 2008 SP2 x64 with SQL Express 2005 x64.

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  • strange bundler error: tar_input.rb:49:in `initialize': not in gzip format (Zlib::GzipFile::Error) o

    - by z3cko
    i am getting a strange bundler error when running bundle pack with bundler 0.9.12 any ideas? (see pastie for a better formatted code: http://pastie.org/881328 ) /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/site_ruby/1.8/rubygems/package/tar_input.rb:49:in `initialize': not in gzip format (Zlib::GzipFile::Error) from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/site_ruby/1.8/rubygems/package/tar_input.rb:49:in `new' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/site_ruby/1.8/rubygems/package/tar_input.rb:49:in `initialize' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/site_ruby/1.8/rubygems/package/tar_reader.rb:63:in `each' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/site_ruby/1.8/rubygems/package/tar_reader.rb:54:in `loop' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/site_ruby/1.8/rubygems/package/tar_reader.rb:54:in `each' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/site_ruby/1.8/rubygems/package/tar_input.rb:32:in `initialize' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/site_ruby/1.8/rubygems/package/tar_input.rb:17:in `new' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/site_ruby/1.8/rubygems/package/tar_input.rb:17:in `open' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/site_ruby/1.8/rubygems/package.rb:55:in `open' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/site_ruby/1.8/rubygems/format.rb:63:in `from_io' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/site_ruby/1.8/rubygems/format.rb:51:in `from_file_by_path' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/site_ruby/1.8/rubygems/format.rb:50:in `open' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/site_ruby/1.8/rubygems/format.rb:50:in `from_file_by_path' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/source.rb:115:in `specs' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/source.rb:114:in `each' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/source.rb:114:in `specs' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/index.rb:32:in `from_cached_specs' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/index.rb:23:in `application_cached_gems' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/index.rb:15:in `cached_gems' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/index.rb:5:in `build' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/index.rb:14:in `cached_gems' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/environment.rb:15:in `index' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/index.rb:5:in `build' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/environment.rb:13:in `index' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/runtime.rb:86:in `specs' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/runtime.rb:130:in `details' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/runtime.rb:119:in `write_yml_lock' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/runtime.rb:65:in `lock' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/cli.rb:89:in `lock' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/cli.rb:131:in `package' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/vendor/thor/task.rb:33:in `send' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/vendor/thor/task.rb:33:in `run' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/vendor/thor/invocation.rb:109 from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/vendor/thor/invocation.rb:116:in `call' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/vendor/thor/invocation.rb:116:in `invoke' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/vendor/thor.rb:137:in `start' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/vendor/thor/base.rb:378:in `start' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/lib/bundler/vendor/thor.rb:124:in `start' from /opt/ruby-enterprise-1.8.7-2010.01/lib/ruby/gems/1.8/gems/bundler-0.9.12/bin/bundle:11 from /opt/REE/bin/bundle:19:in `load' from /opt/REE/bin/bundle:19

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  • What is the RSA SecurID packet format?

    - by bmatthews68
    I am testing a client application that authenticates using RSA SecurID hardware tokens. The authentication is failing and I am not finding any useful information in the log files. I am using Authentication Manager 8.0 and the Java SDK. I have a traffic capture which I would like to analyze with Wireshark to and from port 5500 on the authentication agent. But I can't find the packet format searching the internet or on the the RSA SecurCare knowledge base. Can anybody direct me to the packet format? Here is an extract from the rsa_api_debug.log file which dumps the UDP payload of the request and the response: [2013-11-06 15:11:08,602] main - b.a():? - Sending 508 bytes to 192.168.10.121; contents: 5c 5 0 3 3 5 0 0 2 0 0 0 0 0 1 ea 71 ee 50 6e 45 83 95 8 39 4 72 e 55 cf cc 62 6d d5 a4 10 79 89 13 d5 23 6a c1 ab 33 8 c3 a1 91 92 93 4f 1e 4 8d 2a 22 2c d0 c3 7 fc 96 5f ba bf 0 80 60 60 9d 1d 9c b9 f3 58 4b 43 18 5f e0 6d 5e f5 f4 5d df bf 41 b9 9 ae 46 a0 a9 66 2d c7 6 f6 d7 66 f1 4 f8 ad 8a 9f 4d 7e e5 9c 45 67 16 15 33 70 f0 1 d5 c0 38 39 f5 fd 5e 15 4f e3 fe ea 70 fa 30 c9 e0 18 ab 64 a9 fe 2c 89 78 a2 96 b6 76 3e 2e a2 ae 2e e0 69 80 8d 51 9 56 80 f4 1a 73 9a 70 f3 e7 c1 49 49 c3 41 3 c6 ce 3e a8 68 71 3f 2 b2 9b 27 8e 63 ce 59 38 64 d1 75 b7 b7 1f 62 eb 4d 1d de c7 21 e0 67 85 b e6 c3 80 0 60 54 47 e ef 3 f9 33 7b 78 e2 3e db e4 8e 76 73 45 3 38 34 1e dd 43 3e 72 a7 37 72 5 34 8e f4 ba 9d 71 6c e 45 49 fa 92 a f6 b bf 5 b 4f dc bd 19 0 7e d2 ef 94 d 3b 78 17 37 d9 ae 19 3a 7e 46 7d ea e4 3a 8c e1 e5 9 50 a2 eb df f2 57 97 bc f2 c3 a7 6f 19 7f 2c 1a 3f 94 25 19 4b b2 37 ed ce 97 f ae f ec c9 f5 be f0 8f 72 1c 34 84 1b 11 25 dd 44 8b 99 75 a4 77 3d e1 1d 26 41 58 55 5f d5 27 82 c d3 2a f8 4 aa 8d 5e e4 79 0 49 43 59 27 5e 15 87 a f4 c4 57 b6 e1 f8 79 3b d3 20 69 5e d0 80 6a 6b 9f 43 79 84 94 d0 77 b6 fc f 3 22 ca b9 35 c0 e8 7b e9 25 26 7f c9 fb e4 a7 fc bb b7 75 ac 7b bc f4 bb 4f a8 80 9b 73 da 3 94 da 87 e7 94 4c 80 b3 f1 2e 5b d8 2 65 25 bb 92 f4 92 e3 de 8 ee 2 30 df 84 a4 69 a6 a1 d0 9c e7 8e f 8 71 4b d0 1c 14 ac 7c c6 e3 2a 2e 2a c2 32 bc 21 c4 2f 4d df 9a f3 10 3e e5 c5 7f ad e4 fb ae 99 bf 58 0 20 0 0 0 0 0 0 0 0 0 0 [2013-11-06 15:11:08,602] main - b.b():? - Enterring getResponse [2013-11-06 15:11:08,618] main - b.a():? - Enterring getTimeoutValue(AceRequest AceAuthV4Request[AbstractAceRequest[ hdr=AcePacketHeader[Type=92 Ver=5 AppID=3 Enc=ENCRYPT Hi-Proto=5 Opt=0 CirID=0] created=1383750668571 trailer=AcePackeTrailer[nonce=39e7a607b517c4dd crc=722833884]] user=bmatthews node-sec-req=0 wpcodes=null resp-mac=0 m-resp-mac=0 client=192.168.10.3 passcode==ZTmY|? sec-sgmt=AceSecondarySegments[ cnt=3] response=none]) [2013-11-06 15:11:08,618] main - b.a():? - acm base timeout: 5 [2013-11-06 15:11:08,618] main - b.b():? - Timeout is 5000 [2013-11-06 15:11:08,618] main - b.b():? - Current retries: 0 [2013-11-06 15:11:10,618] main - b.b():? - Received 508 bytes from 192.168.10.121; contents: 6c 5 0 3 3 6 0 0 0 0 0 1 4d 18 55 ca 18 df 84 49 70 ee 24 4a a5 c3 1c 4e 36 d8 51 ad c7 ef 49 89 6e 2e 23 b4 7e 49 73 4 15 d f4 d5 c0 bf fc 72 5b be d1 62 be e0 de 23 56 bf 26 36 7f b f0 ba 42 61 9b 6f 4b 96 88 9c e9 86 df c6 82 e5 4c 36 ee dc 1e d8 a1 0 71 65 89 dc ca ee 87 ae d6 60 c 86 1c e8 ef 9f d9 b9 4c ed 7 55 77 f3 fc 92 61 f9 32 70 6f 32 67 4d fc 17 4e 7b eb c3 c7 8c 64 3f d0 d0 c7 86 ad 4e 21 41 a2 80 dd 35 ba 31 51 e2 a0 ef df 82 52 d0 a8 43 cb 7c 51 c 85 4 c5 b2 ec 8f db e1 21 90 f5 d7 1b d7 14 ca c0 40 c5 41 4e 92 ee 3 ec 57 7 10 45 f3 54 d7 e4 e6 6e 79 89 9a 21 70 7a 3f 20 ab af 68 34 21 b7 1b 25 e1 ab d 9f cd 25 58 5a 59 b1 b8 98 58 2f 79 aa 8a 69 b9 4c c1 7d 36 28 a3 23 f5 cc 2b ab 9e f a1 79 ab 90 fd 5f 76 9f d9 86 d1 fc 4c 7a 4 24 6d de 64 f1 53 22 b0 b7 91 9a 7c a2 67 2a 35 68 83 74 6a 21 ac eb f8 a2 29 53 21 2f 5a 42 d6 26 b8 f6 7f 79 96 5 3b c2 15 3a b d0 46 42 b7 74 4e 1f 6a ad f5 73 70 46 d3 f8 e a3 83 a3 15 29 6e 68 2 df 56 5c 88 8d 6c 2f ab 11 f1 5 73 58 ec 4 5f 80 e3 ca 56 ce 8 b9 73 7c 79 fc 3 ff f1 40 97 bb e3 fb 35 d1 8d ba 23 fc 2d 27 5b f7 be 15 de 72 30 b e d6 5c 98 e8 44 bd ed a4 3d 87 b8 9b 35 e9 64 80 9a 2a 3c a2 cf 3e 39 cb f6 a2 f4 46 c7 92 99 bc f7 4a de 7e 79 9d 9b d9 34 7f df 27 62 4f 5b ef 3a 4c 8d 2e 66 11 f7 8 c3 84 6e 57 ba 2a 76 59 58 78 41 18 66 76 fd 9d cb a2 14 49 e1 59 4a 6e f5 c3 94 ae 1a ba 51 fc 29 54 ba 6c 95 57 6b 20 87 cc b8 dc 5f 48 72 9c c0 2c dd 60 56 4e 4c 6c 1d 40 bd 4 a1 10 4e a4 b1 87 83 dd 1c f2 df 4c [2013-11-06 15:11:10,618] main - a.a():? - Response status is: 1 [2013-11-06 15:11:10,618] main - a.a():? - Authenticaton failed for bmatthews ! [2013-11-06 15:11:10,618] main - AuthSessionFactory.shutdown():? - RSA Authentication API shutdown invoked [2013-11-06 15:11:10,618] main - AuthSessionFactory.shutdown():? - RSA Authentication API shutdown successful

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  • Linq 2 Sql DateTime format to string yyyy-MM-dd

    - by Bogdan Maxim
    Basically, i need the equivalent of T-SQL CONVERT(NVARCHAR(10), datevalue, 126) I've tried: from t in ctx.table select t.Date.ToString("yyyy-MM-dd") but it throws not supported exception from t in ctx.table select "" + t.Date.Year + "-" + t.Date.Month + "-" + t.Date.Day but i don't think it's an usable solution, because i might need to be able to change the format. The only option I see is to use Convert.ToString(t.Date, FormatProvider), but i need a format provider, and I'm not sure it works either.

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  • Advanced CSS layout problem

    - by Tower
    Hi, I want to create a dialog with a title, borders (left, right, bottom) as well as the content. The current source code: <html> <body> <div style="background: #0ff; width: 152px; height: 112px; position: absolute; top: 24px; left: 128px; display: table"> <div style="display: table-row;"> <div style="background: #f00; width: 100%; display: table-cell;height: 24px;">top</div> </div> <div style="display: table-row;"> <div style="background: #0f0; width: 100%; display: table-cell;"> <div style="display: table;"> <div style="display: table-row;"> <div style="display: table-cell; width: 4px; height: 100%; background: #000;"></div> <div style="display: table-cell;"> <div style="overflow: scroll; white-space: nowrap"> cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe <br /> cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe <br /> cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe <br /> cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe <br /> cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe <br /> cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe <br /> cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe <br /> cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe <br /> cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe cwe <br /> </div> </div> <div style="display: table-cell; width: 4px; height: 100%; background: #000;"></div> </div> </div> </div> </div> <div style="display: table-row;"> <div style="background: #000; width: 100%; display: table-cell; height: 4px;"></div> </div> </div> </body> </html> produces an output of what happened to the left and the right borders and why does the size exceed the width specified in the top parent (152px)?

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  • Format all elements of a list

    - by Curious2learn
    I want to print a list of numbers, but I want to format each member of the list before it is printed. For example, theList=[1.343465432, 7.423334343, 6.967997797, 4.5522577] I want the following output printed given the above list as an input: [1.34, 7.42, 6.97, 4.55] For any one member of the list, I know I can format it by using, print "%.2f" % member Is there a command/function that can do this for the whole list. I can write one, but was wondering if one already exists. Thanks.

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  • Advanced Python list comprehension

    - by Yuval A
    Given two lists: chars = ['ab', 'bc', 'ca'] words = ['abc', 'bca', 'dac', 'dbc', 'cba'] how can you use list comprehensions to generate a filtered list of words by the following condition: given that each word is of length n and chars is of length n as well, the filtered list should include only words that each i-th character is in the i string in words. In this case, we should get ['abc', 'bca'] as a result. (If this looks familiar to anyone, this was one of the questions in the previous Google code jam)

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  • Set different line format for a graph with more than one serie with pChart

    - by woodgate
    I am actually using the pChart PHP library for generate graphs. I wanna know if it's possible to give a different line format for a graph with multiple series. I need a line with for example 3px of width but other line with 1px of width. Is that possible? In the official documentation only appears a function that give format to the lines of all series: http://pchart.sourceforge.net/documentation.php?topic=pChart#setLineStyle Thanks a lot.

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  • advanced opensource iphone applications for developers

    - by Naveen
    The appstore does not allow your app out of a sandbox or allow it an interpreter. But is there any issue with distributing open source apps that run arbitrary code, and let iphone developers install them on their own development devices using xcode itself ? Also, is there anything you can not do with xcode that you may be able to do with ssh after jailbreaking ?

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  • Advanced SQL Data Compare throught multiple tables

    - by podosta
    Hello, Consider the situation below. Two tables (A & B), in two environments (DEV & TEST), with records in those tables. If you look the content of the tables, you understand that functionnal data are identical. I mean except the PK and FK values, the name Roger is sill connected to Fruit & Vegetable. In DEV environment : Table A 1 Roger 2 Kevin Table B (italic field is FK to table A) 1 1 Fruit 2 1 Vegetable 3 2 Meat In TEST environment : Table A 4 Roger 5 Kevin Table B (italic field is FK to table A) 7 4 Fruit 8 4 Vegetable 9 5 Meat I'm looking for a SQL Data Compare tool which will tell me there is no difference in the above case. Or if there is, it will generate insert & update scripts with the right order (insert first in A then B) Thanks a lot guys, Grégoire

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  • CakePHP 1.3 advanced installation

    - by Miguel
    Using cakephp 1.3.0, I am editing index.php to setup the app, cake and webroot directories. I have the following dir's setup: httpdocs/app httpdocs/cake httpdocs/webroot I have done this countless times in 1.2.xx and according to the cakebook this hasn't changed but I keep getting missing controller Error: WebrootController could not be found. Am I missing something here in 1.3? Thanks in advance for any help.

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  • How do I create a scheduled task, via command line, which includes advanced options

    - by David
    I'm trying to create a scheduled task (in WinXP) which runs every 10 minutes, starting at 16:00:00 to 06:00:00, daily, from the command line. Currently, I can create a scheduled task which runs every 10 minutes, starting at 16:00:00, daily, by using the following command: SCHTASKS.EXE /CREATE /SC MINUTE /MO 10 /TN "Scheduled task name" /ST 16:00:00 /SD 01/01/2000 /TR task.bat /RU SYSTEM The question is, how do I modify the previous command so that it stops running at 06:00:00?

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  • How to find the file format from binary data

    - by acadia
    Hello, We have a Oracle 9i database and OrderDetails table which has a column to store binary data for product images. These images can be viewed only using a 3rd party tool. I have no idea which 3rd party tool. and I have no idea of the format of the image. Is there anyway from the binary data we can find what format is the image? Thanks

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  • Advanced Django query with subselects and custom JOINS

    - by Bryan Ward
    I have been investigating this number theoretic function (found in the Height model) and I need to query for things based on the prime factorization of the primary key, or id. I have created a model for Factors of the id which maintains all of the prime factors. class Height(models.Model): b = models.IntegerField(null=True, blank=True) c = models.IntegerField(null=True, blank=True) d = models.FloatField(null=True, blank=True) class Factors(models.Model): height = models.ForeignKey(Height, null=True, blank=True) factor = models.IntegerField(null=True, blank=True) degree = models.IntegerField(null=True, blank=True) prime_id = models.IntegerField(null=True, blank=True) For example, if id=24, then the associated entries in the factors table would be height_id=24,factor=2,degree=3,prime_id=0 height_id=24,factor=3,degree=1,prime_id=1 the prime_id keep track of the relative order of the primes. Now let p < q < r < s all be prime numbers and a,b,c,d be positive integers. Then I want to be able to query for all Heights of the form id=(p**a)*(q**b)*(r**c)*(s**d). Now this is simple in the case that all of p,q,r,s,a,b,c,d are known in that I can just run Height.objects.get(id=(p**a)*(q**b)*(r**c)*(s**d)) But I need to be able to query for something like (2**a)*(3**2)*(r**c)*(s**d) where r,s,a,d are unknown and all Heights of such form will be returned. Furthermore, not all of the rows in Height will have exactly four prime factors, so I need to make sure that I am not matching rows of the form id=(p**a)*(q**b)*(r**c)*(s**d)*(t**e)... From what I can tell, the following MySQL query accomplishes this, but I would like to do it through the Django ORM. I also don't know if this MySQL query is the proper way to go about doing things. SELECT h.*,count(f.height_id) AS factorsCount FROM height AS h LEFT JOIN factors AS f ON ( f.height_id = h.id AND f.height_id IN (SELECT height_id FROM factors where prime_id=1 AND factor=2 AND degree=1) AND f.height_id IN (SELECT height_id FROM factors where prime_id=2 AND factor=3 AND degree=2) AND f.height_id IN (SELECT height_id FROM factors where prime_id=3 AND factor=5 AND degree=1) AND f.height_id IN (SELECT height_id FROM factors where prime_id=4 AND factor=7 ANd degree=1) ) GROUP BY h.id HAVING factorsCount=4 ORDER BY h.id; Any ideas or suggestions for things to try?

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  • More advanced usage of interfaces

    - by owca
    To be honest I'm not quite sure if I understand the task myself :) I was told to create class MySimpleIt, that implements Iterator and Iterable and will allow to run the provided test code. Arguments and variables of objects cannot be either Collections or arrays. The code : MySimpleIt msi=new MySimple(10,100, MySimpleIt.PRIME_NUMBERS); for(int el: msi) System.out.print(el+" "); System.out.println(); msi.setType(MySimpleIterator.ODD_NUMBERS); msi.setLimits(15,30); for(int el: msi) System.out.print(el+" "); System.out.println(); msi.setType(MySimpleIterator.EVEN_NUMBERS); for(int el: msi) System.out.print(el+" "); System.out.println(); The result I should obtain : 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97 15 17 19 21 23 25 27 29 16 18 20 22 24 26 28 30 And here's my code : import java.util.Iterator; interface MySimpleIterator{ static int ODD_NUMBERS=0; static int EVEN_NUMBERS = 1; static int PRIME_NUMBERS = 2; int setType(int i); } public class MySimpleIt implements Iterable, Iterator, MySimpleIterator { public MySimple my; public MySimpleIt(MySimple m){ my = m; } public int setType(int i){ my.numbers = i; return my.numbers; } public void setLimits(int d, int u){ my.down = d; my.up = u; } public Iterator iterator(){ Iterator it = this.iterator(); return it; } public void remove(){ } public Object next(){ Object o = new Object(); return o; } public boolean hasNext(){ return true; } } class MySimple { public int down; public int up; public int numbers; public MySimple(int d, int u, int n){ down = d; up = u; numbers = n; } } In the test code I have error in line when creating MySimpleIt msi object, as it finds MySimple instead of MySimpleIt. Also I have errors in for-each loops, because compiler wants 'ints' there instead of Object. Anyone has any idea on how to solve it ?

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  • Advanced Array Sorting in Ruby

    - by Ruby Beginner
    I'm currently working on a project in ruby, and I hit a wall on how I should proceed. In the project I'm using Dir.glob to search a directory and all of its subdirectories for certain file types and placing them into an arrays. The type of files I'm working with all have the same file name and are differentiated by their extensions. For example, txt_files = Dir.glob("**/*.txt") doc_files = Dir.glob("**/*.doc") rtf_files = Dir.glob("**/*.rtf") Would return something similar to, FILECON.txt ASSORTED.txt FIRST.txt FILECON.doc ASSORTED.doc FIRST.doc FILECON.rtf ASSORTED.rtf FIRST.rtf So, the question I have is how I could break down these arrays efficiently (dealing with thousands of files) and placing all files with the same filename into an array. The new array would look like, FILECON.txt FILECON.doc FILECON.rtf ASSORTED.txt ASSORTED.doc ASSORTED.rtf etc. etc. I'm not even sure if glob would be the correct way to do this (all the files with the same file name are in the same folders). Any help would be greatly appreciated!

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