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  • I want to consolidate two sites into a third. Will my search engine rankings be penalized if I rewrite and redirect pages one by one?

    - by Patrick Kenny
    I have two Drupal sites with different content-- let's call them Apple and Orange. I recently developed a much more sophisticated third Drupal site-- let's call it Tree. For a large number of reasons, the content on Apple and Orange is useful for the users of Tree, so I want to move the content to Tree. However, much of the content is out of date. (This whole process took about five years.) To update the content, I will rewrite it one article at a time myself. Now here's my question: if I move the articles one by one (as I rewrite them) and then redirect the old articles (using a 301 redirect) on Apple/Orange to the new site on Tree, will this have a huge negative effect on my search engine rankings? Is there a good way to redirect among sites when they merge like this, or would I be better off keeping the old articles on Apple/Orange and simply linking them to the new, rewritten articles on Tree?

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  • Jquery hiding all descendents of a ul tag...showing child elements as tree menu...

    - by Ronedog
    I want to hide all the descendents of the "ul" for my tree menu when the page loads up, then as each "main" "li" link is clicked display the direct child, and if the direct child has children (grandchild), when the the "Child" is clicked I want it to show the "grandchild" elements. should be simple, but some how I screwed things up and when i click on the main "li" (Heading 1) it displays all of the descendents (Including the "Sub page A - 1"), instead of just the direct children ("Sub Page A"). Which I think means the children, grandchildren, etc. were never hidden to begin with with the .hide(). What I really want to happen is to hide all the descendents (except the main top-level headings) and as I walk down the tree display the children as needed. Any tips on how to make this work? Here's the HTML: <ul id="nav"> <li>Heading 1 <ul> <li>Sub page A <ul> <li>Sub page A - 1</li> <li>Sub page A - 3</li> <li>Sub page A - 2</li> </ul> </li> <li>Sub page B</li> <li>Sub page C</li> </ul> </li> <li>Heading 2 <ul> <li>Sub page D</li> <li>Sub page E</li> <li>Sub page F</li> </ul> </li> <li>Heading 3 <ul> <li>Sub page G</li> <li>Sub page H</li> <li>Sub page I</li> </ul> </li> Here's my Jquery: $(function(){ $('#nav ul').hide(); //Supposed to Hide all <ul> tags for all descendents, but doesn't work $('#nav>li').mouseover(function(){ $(this).addClass("a_hand") }); //Add the class that displays the hand $('#nav>li').toggle(function() { $(this).find('ul').slideDown(200); }, function() { $(this).find('ul').slideUp(200); });//END TOGGLE });//END MAIN FUNCTION thanks.

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  • Android Eclipse test projects cannot be used with a project being built in an Android build tree

    - by orospakr
    An Android Java project placed in a git repository and built in an Android tree in /packages/apps needs to have the project files located at the root of the git repository. This is problematic for creating a complementary Test project, which should ideally be included in the same git repository so commits are atomic for both code and tests. Eclipse gets very unhappy if you include the Test project as a subdirectory. Is there an appropriate approach for dealing with this other than creating a second repository?

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  • How to write a recursive function that returns a linked list of nodes, when given a binary tree of n

    - by Jian Lin
    I was once asked of this in an interview: How to write a recursive function that returns a linked list of nodes, when given a binary tree of nodes? (flattening the data) For some reason, I tend to need more than 3 to 5 minutes to solve any recursive problem. Usually, 15 to 20 minutes will be more like it. How could we attack this problem, such as a very systematic way of reaching a solution, so that they can be solved in 3 to 5 minute time frame?

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  • Calculate the Hilbert value of a point for use in a Hilbert R-Tree?

    - by wrt
    I have an application where a Hilbert R-Tree (wikipedia) (citeseer) would seem to be an appropriate data structure. Specifically, it requires reasonably fast spatial queries over a data set that will experience a lot of updates. However, as far as I can see, none of the descriptions of the algorithms for this data structure even mention how to actually calculate the requisite Hilbert Value; which is the distance along a Hilbert Curve to the point. So any suggestions for how to go about calculating this?

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  • In Ant, copy all files from a tree of folders into a single folder?

    - by Sam Washburn
    Is it possible to use Ant to copy all the files (not folders) from a hierarchy of folders into one destination folder? For instance, I have a tree like this: res |-images | |-fg.png | +-bg.png +-sounds +-music.mp3 And I would like a result like this: data |-fg.png |-bg.png +-music.mp3 The way things are named, filename conflicts are not an issue. Is this possible to do with Ant?

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  • Where should I initialize variables for an OO Recursive Descent Parse Tree?

    - by Vasto
    I'd like to preface this by stating that this is for a class, so please don't solve this for me. One of my labs for my cse class is creating an interpreter for a BNF that was provided. I understand most of the concepts, but I'm trying to build up my tree and I'm unsure where to initialize values. I've tried in both the constructor, and in the methods but Eclipse's debugger still only shows the left branch, even though it runs through completely. Here is my main procedure so you can get an idea of how I'm calling the methods. public class Parser { public static void main(String[] args) throws IOException { FileTokenizer instance = FileTokenizer.Instance(); FileTokenizer.main(args); Prog prog = new Prog(); prog.ParseProg(); prog.PrintProg(); prog.ExecProg(); } Now here is My Prog class: public class Prog { private DeclSeq ds; private StmtSeq ss; Prog() { ds = new DeclSeq(); ss = new StmtSeq(); } public void ParseProg() { FileTokenizer instance = FileTokenizer.Instance(); instance.skipToken(); //Skips program (1) // ds = new DeclSeq(); ds.ParseDS(); instance.skipToken(); //Skips begin (2) // ss = new StmtSeq(); ss.ParseSS(); instance.skipToken(); } I've tried having Prog() { ds = null; ss = null; } public void ParseProg() { FileTokenizer instance = FileTokenizer.Instance(); instance.skipToken(); //Skips program (1) ds = new DeclSeq(); ds.ParseDS(); ... But it gave me the same error. I need the parse tree built up so I can do a pretty print and an execute command, but like I said, I only get the left branch. Any help would be appreciated. Explanations why are even more so appreciated. Thank you, Vasto

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  • C++ linked list based tree structure. Sanely move nodes between lists.

    - by krunk
    The requirements: Each Node in the list must contain a reference to its previous sibling Each Node in the list must contain a reference to its next sibling Each Node may have a list of child nodes Each child Node must have a reference to its parent node Basically what we have is a tree structure of arbitrary depth and length. Something like: -root(NULL) --Node1 ----ChildNode1 ------ChildOfChild --------AnotherChild ----ChildNode2 --Node2 ----ChildNode1 ------ChildOfChild ----ChildNode2 ------ChildOfChild --Node3 ----ChildNode1 ----ChildNode2 Given any individual node, you need to be able to either traverse its siblings. the children, or up the tree to the root node. A Node ends up looking something like this: class Node { Node* previoius; Node* next; Node* child; Node* parent; } I have a container class that stores these and provides STL iterators. It performs your typical linked list accessors. So insertAfter looks like: void insertAfter(Node* after, Node* newNode) { Node* next = after->next; after->next = newNode; newNode->previous = after; next->previous = newNode; newNode->next = next; newNode->parent = after->parent; } That's the setup, now for the question. How would one move a node (and its children etc) to another list without leaving the previous list dangling? For example, if Node* myNode exists in ListOne and I want to append it to listTwo. Using pointers, listOne is left with a hole in its list since the next and previous pointers are changed. One solution is pass by value of the appended Node. So our insertAfter method would become: void insertAfter(Node* after, Node newNode); This seems like an awkward syntax. Another option is doing the copying internally, so you'd have: void insertAfter(Node* after, const Node* newNode) { Node *new_node = new Node(*newNode); Node* next = after->next; after->next = new_node; new_node->previous = after; next->previous = new_node; new_node->next = next; new_node->parent = after->parent; } Finally, you might create a moveNode method for moving and prevent raw insertion or appending of a node that already has been assigned siblings and parents. // default pointer value is 0 in constructor and a operator bool(..) // is defined for the Node bool isInList(const Node* node) const { return (node->previous || node->next || node->parent); } // then in insertAfter and friends if(isInList(newNode) // throw some error and bail I thought I'd toss this out there and see what folks came up with.

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  • Tree Menu? In JS?

    - by acidzombie24
    I need a tree menu. But instead of a listview where you expand/collapse i need a dropdown box with the list and when you click on a element i need the box to update (with the first entry being 'Back') so the menu stays in a neat little dialog. Does this menu have a name? Does anyone know where i can get code to do this?

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  • How to build a tree from a list of items and their children recursively in php?

    - by k1lljoy
    I have a list of items stored in the DB, simplified schema is like this: id, parent, name I need to generate a tree structure (in a form of a multi-dimensional array) that can be infinite levels deep. Top level items would have parent = 0. Next level down would have parent equal to the the id of the parent item, fairly straight forward. What would be the best way to do this, while consuming as little resources as possible?

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  • Program to change/obfuscate all hashes (MD5/SHA1) in a directory tree?

    - by anon
    Hi fellas, A) Are there any FOSS programs out there that can manage to hashchange all files in a directory tree? B) Failing that, what methods could be used to develop this capability in a (crappy) self-written program without requiring the program to be sophisticated and content-aware? Is there any (roughly) universally safe location within a file (for example, around EOF?) where on could one simply append/add psuedorandom data so the resulting hash is different? Is there a better/more elegant solution? Muchos gracias

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  • How to automate the java Applet(tree view) from my .NET application.

    - by rajeev-vj
    Hi I have a java applet (tree view) on Internet Explorer. when i Click on this applet (+) it collapes, as the information is based on this plus sign. I need to automate this java applet to click automatically from my C#.NET winforms application but am not able to get the details of the java applet. How to get the details of the java applet from browser and how to automate the java applet? Thanks

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  • Confused about Huffman Trees

    - by ShrimpCrackers
    A quick tutorial on generating a huffman tree Confused about Huffman Trees. Near the end of that link above, it shows the tree with 2 elements left, and then the completed tree. I'm confused about the way that it is branched. Is there a specific way a huffman tree needs to be branched? For example, 57:* with its right child 35:* is branched off to the right. Could it have been 35 branched to the left with 22 branched to the right? Also, why wasn't 22:* paired up with 15:4 - it just paired with 20:5 to create a new tree. From initial obersvations it seems the tree does not need to be balanced or have any specific order other than that the frequencies of a leaf add up to the value of the parent node. Could two people creating a huffman tree with the same data end up with different encoding values?

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  • List of generic algorithms and data structures

    - by Jake Petroules
    As part of a library project, I want to include a plethora of generic algorithms and data structures. This includes algorithms for searching and sorting, data structures like linked lists and binary trees, path-finding algorithms like A*... the works. Basically, any generic algorithm or data structure you can think of that you think might be useful in such a library, please post or add it to the list. Thanks! (NOTE: Because there is no single right answer I've of course placed this in community wiki... and also, please don't suggest algorithms which are too specialized to be provided by a generic library) The List: Data structures AVL tree B-tree B*-tree B+-tree Binary tree Binary heap Binary search tree Linked lists Singly linked list Doubly linked list Stack Queue Sorting algorithms Binary tree sort Bubble sort Heapsort Insertion sort Merge sort Quicksort Selection sort Searching algorithms

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  • SortedDictionary and SortedList

    - by Simon Cooper
    Apart from Dictionary<TKey, TValue>, there's two other dictionaries in the BCL - SortedDictionary<TKey, TValue> and SortedList<TKey, TValue>. On the face of it, these two classes do the same thing - provide an IDictionary<TKey, TValue> interface where the iterator returns the items sorted by the key. So what's the difference between them, and when should you use one rather than the other? (as in my previous post, I'll assume you have some basic algorithm & datastructure knowledge) SortedDictionary We'll first cover SortedDictionary. This is implemented as a special sort of binary tree called a red-black tree. Essentially, it's a binary tree that uses various constraints on how the nodes of the tree can be arranged to ensure the tree is always roughly balanced (for more gory algorithmical details, see the wikipedia link above). What I'm concerned about in this post is how the .NET SortedDictionary is actually implemented. In .NET 4, behind the scenes, the actual implementation of the tree is delegated to a SortedSet<KeyValuePair<TKey, TValue>>. One example tree might look like this: Each node in the above tree is stored as a separate SortedSet<T>.Node object (remember, in a SortedDictionary, T is instantiated to KeyValuePair<TKey, TValue>): class Node { public bool IsRed; public T Item; public SortedSet<T>.Node Left; public SortedSet<T>.Node Right; } The SortedSet only stores a reference to the root node; all the data in the tree is accessed by traversing the Left and Right node references until you reach the node you're looking for. Each individual node can be physically stored anywhere in memory; what's important is the relationship between the nodes. This is also why there is no constructor to SortedDictionary or SortedSet that takes an integer representing the capacity; there are no internal arrays that need to be created and resized. This may seen trivial, but it's an important distinction between SortedDictionary and SortedList that I'll cover later on. And that's pretty much it; it's a standard red-black tree. Plenty of webpages and datastructure books cover the algorithms behind the tree itself far better than I could. What's interesting is the comparions between SortedDictionary and SortedList, which I'll cover at the end. As a side point, SortedDictionary has existed in the BCL ever since .NET 2. That means that, all through .NET 2, 3, and 3.5, there has been a bona-fide sorted set class in the BCL (called TreeSet). However, it was internal, so it couldn't be used outside System.dll. Only in .NET 4 was this class exposed as SortedSet. SortedList Whereas SortedDictionary didn't use any backing arrays, SortedList does. It is implemented just as the name suggests; two arrays, one containing the keys, and one the values (I've just used random letters for the values): The items in the keys array are always guarenteed to be stored in sorted order, and the value corresponding to each key is stored in the same index as the key in the values array. In this example, the value for key item 5 is 'z', and for key item 8 is 'm'. Whenever an item is inserted or removed from the SortedList, a binary search is run on the keys array to find the correct index, then all the items in the arrays are shifted to accomodate the new or removed item. For example, if the key 3 was removed, a binary search would be run to find the array index the item was at, then everything above that index would be moved down by one: and then if the key/value pair {7, 'f'} was added, a binary search would be run on the keys to find the index to insert the new item, and everything above that index would be moved up to accomodate the new item: If another item was then added, both arrays would be resized (to a length of 10) before the new item was added to the arrays. As you can see, any insertions or removals in the middle of the list require a proportion of the array contents to be moved; an O(n) operation. However, if the insertion or removal is at the end of the array (ie the largest key), then it's only O(log n); the cost of the binary search to determine it does actually need to be added to the end (excluding the occasional O(n) cost of resizing the arrays to fit more items). As a side effect of using backing arrays, SortedList offers IList Keys and Values views that simply use the backing keys or values arrays, as well as various methods utilising the array index of stored items, which SortedDictionary does not (and cannot) offer. The Comparison So, when should you use one and not the other? Well, here's the important differences: Memory usage SortedDictionary and SortedList have got very different memory profiles. SortedDictionary... has a memory overhead of one object instance, a bool, and two references per item. On 64-bit systems, this adds up to ~40 bytes, not including the stored item and the reference to it from the Node object. stores the items in separate objects that can be spread all over the heap. This helps to keep memory fragmentation low, as the individual node objects can be allocated wherever there's a spare 60 bytes. In contrast, SortedList... has no additional overhead per item (only the reference to it in the array entries), however the backing arrays can be significantly larger than you need; every time the arrays are resized they double in size. That means that if you add 513 items to a SortedList, the backing arrays will each have a length of 1024. To conteract this, the TrimExcess method resizes the arrays back down to the actual size needed, or you can simply assign list.Capacity = list.Count. stores its items in a continuous block in memory. If the list stores thousands of items, this can cause significant problems with Large Object Heap memory fragmentation as the array resizes, which SortedDictionary doesn't have. Performance Operations on a SortedDictionary always have O(log n) performance, regardless of where in the collection you're adding or removing items. In contrast, SortedList has O(n) performance when you're altering the middle of the collection. If you're adding or removing from the end (ie the largest item), then performance is O(log n), same as SortedDictionary (in practice, it will likely be slightly faster, due to the array items all being in the same area in memory, also called locality of reference). So, when should you use one and not the other? As always with these sort of things, there are no hard-and-fast rules. But generally, if you: need to access items using their index within the collection are populating the dictionary all at once from sorted data aren't adding or removing keys once it's populated then use a SortedList. But if you: don't know how many items are going to be in the dictionary are populating the dictionary from random, unsorted data are adding & removing items randomly then use a SortedDictionary. The default (again, there's no definite rules on these sort of things!) should be to use SortedDictionary, unless there's a good reason to use SortedList, due to the bad performance of SortedList when altering the middle of the collection.

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  • C++ linked list based tree structure. Sanely copy nodes between lists.

    - by krunk
    edit Clafification: The intention is not to remove the node from the original list. But to create an identical node (data and children wise) to the original and insert that into the new list. In other words, a "move" does not imply a "remove" from the original. endedit The requirements: Each Node in the list must contain a reference to its previous sibling Each Node in the list must contain a reference to its next sibling Each Node may have a list of child nodes Each child Node must have a reference to its parent node Basically what we have is a tree structure of arbitrary depth and length. Something like: -root(NULL) --Node1 ----ChildNode1 ------ChildOfChild --------AnotherChild ----ChildNode2 --Node2 ----ChildNode1 ------ChildOfChild ----ChildNode2 ------ChildOfChild --Node3 ----ChildNode1 ----ChildNode2 Given any individual node, you need to be able to either traverse its siblings. the children, or up the tree to the root node. A Node ends up looking something like this: class Node { Node* previoius; Node* next; Node* child; Node* parent; } I have a container class that stores these and provides STL iterators. It performs your typical linked list accessors. So insertAfter looks like: void insertAfter(Node* after, Node* newNode) { Node* next = after->next; after->next = newNode; newNode->previous = after; next->previous = newNode; newNode->next = next; newNode->parent = after->parent; } That's the setup, now for the question. How would one move a node (and its children etc) to another list without leaving the previous list dangling? For example, if Node* myNode exists in ListOne and I want to append it to listTwo. Using pointers, listOne is left with a hole in its list since the next and previous pointers are changed. One solution is pass by value of the appended Node. So our insertAfter method would become: void insertAfter(Node* after, Node newNode); This seems like an awkward syntax. Another option is doing the copying internally, so you'd have: void insertAfter(Node* after, const Node* newNode) { Node *new_node = new Node(*newNode); Node* next = after->next; after->next = new_node; new_node->previous = after; next->previous = new_node; new_node->next = next; new_node->parent = after->parent; } Finally, you might create a moveNode method for moving and prevent raw insertion or appending of a node that already has been assigned siblings and parents. // default pointer value is 0 in constructor and a operator bool(..) // is defined for the Node bool isInList(const Node* node) const { return (node->previous || node->next || node->parent); } // then in insertAfter and friends if(isInList(newNode) // throw some error and bail I thought I'd toss this out there and see what folks came up with.

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  • QTreeWidget insertTopLevelItem - index given not accurately displayed in Tree?

    - by mleep
    I am unable to properly insert a QTreeWidgetItem at a specific index, in this case I am removing all QTreeWidgetItems from the tree, doing a custom sort on their Date Objects and then inserting them back into the QTreeWidget. However, upon inserting (even one at a time) the QTreeWidgetItem is not inserted into the correct place. The code below prints out: index 0: 0 index 0: 1 index 1: 0 index 0: 2 index 1: 1 index 2: 0 index 0: 3 index 1: 2 index 2: 0 index 3: 1 index 0: 4 index 1: 2 index 2: 0 index 3: 1 index 4: 3 print 'index 0: ', self.indexOfTopLevelItem(childrenList[0]) self.insertTopLevelItem(0, childrenList[1]) print 'index 0: ', self.indexOfTopLevelItem(childrenList[0]), ' index 1: ',\ self.indexOfTopLevelItem(childrenList[1]) self.insertTopLevelItem(0, childrenList[2]) print 'index 0: ', self.indexOfTopLevelItem(childrenList[0]), ' index 1: ',\ self.indexOfTopLevelItem(childrenList[1]), ' index 2: ', \ self.indexOfTopLevelItem(childrenList[2]) self.insertTopLevelItem(0, childrenList[3]) print 'index 0: ', self.indexOfTopLevelItem(childrenList[0]), ' index 1: ',\ self.indexOfTopLevelItem(childrenList[1]), ' index 2: ',\ self.indexOfTopLevelItem(childrenList[2]), 'index 3: ',\ self.indexOfTopLevelItem(childrenList[3]) self.insertTopLevelItem(0, childrenList[4]) print 'index 0: ', self.indexOfTopLevelItem(childrenList[0]),\ ' index 1: ', self.indexOfTopLevelItem(childrenList[1]),\ ' index 2: ', self.indexOfTopLevelItem(childrenList[2]),\ 'index 3: ', self.indexOfTopLevelItem(childrenList[3]),\ 'index 4: ', self.indexOfTopLevelItem(childrenList[4])

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  • How can I generate an Expression tree that queries an object with List<T> as a property?

    - by David Robbins
    Forgive my clumsy explanation, but I have a class that contains a List: public class Document { public int OwnerId { get; set; } public List<User> Users { get; set; } public Document() { } } public class User { public string UserName { get; set; } public string Department { get; set; } } Currently I use PredicateBuilder to perform dynmica queries on my objects. How can I turn the following LINQ statement into an Expression Tree: var predicate= PredicateBuilder.True<User>(); predicate= predicate.And<User>(user => user.Deparment == "HR"); var deptDocs = documents.AsQueryable() .Where(doc => doc.Users .AsQueryable().Count(predicate) > 0) .ToList(); In other words var deptDocs = documents.HasUserAttributes("Department", "HR").ToList();

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