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  • How can I convert German characters during XML read and PHP write into mysql?

    - by kitenski
    Morning, I am inputting data from an XML file into my database, but have any isse with German words (that are in the XML by mistake) For example the word für appears in my XML as für and thus appears the same in my database. I know I could do a simple search/replace for that exact phrase, but I was wondering if there was a smarter way to do it as I can't predict if any other German words may one day appear in the XML? ADDING SOME MORE DETAIL The XML source says: and in my PHP I have $domString = utf8_encode($dom-saveXML($element)); If I look into the XML file before I start reading it, it has - <title> - <![CDATA[ CoPilot Live v8 Europa für Android 8.0.0.644 ]]> </title> Thanks. Greg

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  • How to handle right to left languages in Flash (pre version 10)?

    - by Maan Ashgar
    Hello, We are currently working with Flex creating a web application. We are having trouble taking Arabic text from the user and displaying correctly (like in a chat feature). While presumably Flash 10 will solve this problem, we don't want to force our users to upgrade. Flash flips the order of the sentence's words. so if I wrote something like "Hello World" in the text field, it will appear as "World Hello" in the chat area. Is there a standard way to work with Right to Left languages in Flash? *We currently flip the order of the words with a function, but it things get messed up when using English or special characters in the chat like :) or :D *

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  • What's the best way to match a query to a set of keywords?

    - by Ryan Detzel
    Pretty much what you would assume Google does. Advertisers come in and big on keywords, lets say "ipod", "ipod nano", "ipod 60GB", "used ipod", etc. Then we have a query, "I want to buy an ipod nano" or "best place to buy used ipods" what kind of algorithms and systems are used to match those queries to the keyword set. I would imagine that some of those keyword sets are huge, 100k keywords made up of one or more actual words. on top of that queries can be 1-n words as well. Any thoughts, links to wikipedia I can start reading? From what I know already I would use some stemmed hash in disk(CDB?) and a bloom filter to check to see if I should even go to disk.

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  • Tag Suggestion system, approaches and ideas

    - by Galois
    Hi guys! -- I am working on a (auto) tag suggestion system (NOT tag autocomplete). Lets say I want to suggest tags for a given question like here on SO (although SO's tagging system is auto-complete). My main idea is to get the intersection between the tags_set and the given question.split()_set. (In python the set_intersection is efficient enough). Also, in order to make it a little bit more accurate I might use words-distance to count as 'the same' very close words i.e movie == movies. For now I am not thinking about using any Collaborative Filtering technique looking for the tags to similar questions and so on, because I believe since the question text is pretty short (comparing with a blog article or a paper) it is not worth the effort. So I was wondering if you have any other (more) efficient approaches to suggest. Any ideas, specially from people who they have done something like that before, are more than welcome.

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  • Split string on non-alphanumerics in PHP? Is it possible with php's native function?

    - by Jehanzeb.Malik
    I was trying to split a string on non-alphanumeric characters or simple put I want to split words. The approach that immediately came to my mind is to use regular expressions. Example: $string = 'php_php-php php'; $splitArr = preg_split('/[^a-z0-9]/i', $string); But there are two problems that I see with this approach. It is not a native php function, and is totally dependent on the PCRE Library running on server. An equally important problem is that what if I have punctuation in a word Example: $string = 'U.S.A-men's-vote'; $splitArr = preg_split('/[^a-z0-9]/i', $string); Now this will spilt the string as [{U}{S}{A}{men}{s}{vote}] But I want it as [{U.S.A}{men's}{vote}] So my question is that: How can we split them according to words? Is there a possibility to do it with php native function or in some other way where we are not dependent? Regards

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  • Recursion Interview Questions [closed]

    - by halivingston
    Given a string, "ABC", print all permutations Given a dollar bill, fill out possible ways it can summed up using .25, .10, .5, etc. Given a phone number (123-456), print out all it's word counter parters like (ADG-XYZ) A B C D E F G H I J K L M N O P In the above 2D matrix, print all possible words (just literally all words, and sure we could check if it's exists in a dictionary). The base case is I think here is that reaching the same i, j positions. Any others you can think of?

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  • bitshift large strings for encoding QR Codes

    - by icekreaman
    As an example, suppose a QR Code data stream contains 55 data words (each one byte in length) and 15 error correction words (again one byte). The data stream begins with a 12 bit header and ends with four 0 bits. So, 12 + 4 bits of header/footer and 15 bytes of error correction, leaves me 53 bytes to hold 53 alphanumeric characters. The 53 bytes of data and 15 bytes of ec are supplied in a string of length 68 (str68). The problem seems simple enough - concatenate 2 bytes of (right-shifted) header data with str68 and then left shift the entire 70 bytes by 4 bits. This is the first time in many years of programming that I have ever needed to do something like this, I am a c and bit shifting noob, so please be gentle... I have done a little investigation and so far have not been able to figure out how to bitshift 70 bytes of data; any help would be greatly appreciated. Larger QR codes can hold 2000 bytes of data...

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  • working validation hint, working word counter but not working together

    - by Sriyani Rathnayaka
    I added a word counter to a my form's textarea... it is something like this... <div> <label>About you:</label> <textarea id="qualification" class="textarea hint_needed" rows="4" cols="30" ></textarea> <span class="hint">explain about you</span> <script type="text/javascript"> $("textarea").textareaCounter(); </script> </div> My problem is when I add textaracounter() like this my validation hint is not working.. when I remover the counter function validation hint is working... this is the jquery for hint message.. $(".hint").css({ "display":"none" }); $("input.hint_needed, select.hint_needed, textarea.hint_needed, radio.hint_needed").on("mouseenter", function() { $(this).next(".hint").css({ "display":"inline" }); }).on("mouseleave", function() { $(this).next(".hint").css({ "display":"none" }); }); this is for the word counter.. (function($){ $.fn.textareaCounter = function(options) { // setting the defaults // $("textarea").textareaCounter({ limit: 100 }); var defaults = { limit: 150 }; var options = $.extend(defaults, options); // and the plugin begins return this.each(function() { var obj, text, wordcount, limited; obj = $("#experience"); obj.after('<span style="font-weight: bold; color:#6a6a6a; clear: both; margin: 3px 0 0 150px; float: left; overflow: hidden;" id="counter-text">Max. '+options.limit+' words</span>'); obj.keyup(function() { text = obj.val(); if(text === "") { wordcount = 0; } else { wordcount = $.trim(text).split(" ").length; } if(wordcount > options.limit) { $("#counter-text").html('<span style="color: #DD0000;">0 words left</span>'); limited = $.trim(text).split(" ", options.limit); limited = limited.join(" "); $(this).val(limited); } else { $("#counter-text").html((options.limit - wordcount)+' words left'); } }); }); }; })(jQuery); can anybody tell me what is the problem there? Thank you..

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  • Data on the Frequency of Edit Operations Required to Correct a Misspelt Word

    - by gvkv
    Does anybody know of any data that relates to the frequency of the types of mistakes the people make when they misspell a word? I'm not referring to words themselves, but tje errors that are made by the typist. For example, I personally make transposition errors the most followed by deletion errors (that is, not including a letter I should), substitution errors and lastly, insertion errors. However, it would not surprise me to find out that typing a wrong letter (a substitution error, e.g., xat instead of cat) is more frequent than not including a letter. My purpose is to be able to make best guesses at correcting a word when I only have the original user's input. The idea being that if one type of error is more frequent than others, then it's more likely that correcting a word via that type of operation is correct. I don't object to using a database of commonly misspelt words but I prefer an algorithmic solution to depending on a corpus--especially if it might be faster.

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  • Problem With Inserts of multibyte (converted to utf-8) strings in the mysql tables of utf_unicode_ci encoding

    - by user381595
    http://domainsoutlook.com/sandbox/keyword/?s=http://bhaskar.com raw example of my keyword density analyser. Every keyword shows up properly with no problems in unicode conversions etc. Now, When I am adding these words to the database column of a table, the words show up as messed up. http domainsoutlook.com/b/site/bhaskar.com.html For example on this front end page if you see there is a keyword that is shown as a blank but still occurs on the website 8 times. (It isnt empty in the database though). I have checked and there is no problem with mysql_real_escape_String...because the output stays the same before and after the word is gone through mysql_real_escape_String. Another problem was that I wanted to fix my urls for arabic language. They should be showing up as /word-{1st letter of the word}/{whole word}.html but its showing as /word-{whole word}/{1st letter of the word}.html I really need answers for these two questions.

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  • How to split up a long list using \n

    - by pypy
    Here is a long string that I convert to a list so I can manipulate it, and then join it back together. I am having some trouble being able to have an iterator go through the list and when the iterator reach, let us say every 5th object, it should insert a '\n' right there. Here is an example: string = "Hello my name is Josh I like pizza and python I need this string to be really really long" string = string.split() # do the magic here string = ' '.join(string) print(string) Output: Hello my name is Josh I like pizza and python I need this string to be really really long Any idea how i can achieve this? I tried using: for words in string: if words % 5 == 0: string.append('\n') but it doesn't work. What am I missing?

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  • Strange sql query result from Mysql and from PHP mysqli_query!

    - by qinHaiXiang
    this is the query command echo from php web page: SELECT DISTINCT FT.file_type_name AS type,FT.file_type_en AS tp,FT.file_type_id AS fti, MATCH(keywords) AGAINST ('words <2' IN BOOLEAN MODE ) AS score FROM movie AS M,file_type AS FT WHERE MATCH (keywords) AGAINST ('words <2' IN BOOLEAN MODE ) AND M.type_cn = FT.file_type_id HAVING score >=1 ORDER BY FT.file_type_order; I am running above query in MySQL tools HeidiSQL and got only tow row records which score are 1.66666 and 2. If I remove the HAVING clause I would got three row records with one's score less than 1. But the same query I get from PHP mysqli_query() were all the three records and the one which score less than 1 became 1. What is the problem. Any tips will be pleasure. Thank you very much!!

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  • converting ID to column name and also replacing NULL with last known value.

    - by stackoverflowuser
    TABLE_A Rev ChangedBy ----------------------------- 1 A 2 B 3 C TABLE_B Rev Words ID ---------------------------- 1 description_1 52 1 history_1 54 2 description_2 52 3 history_2 54 Words column datatype is ntext. TABLE_C ID Name ----------------------------- 52 Description 54 History OUTPUT Rev ChangedBy Description History ------------------------------------------------ 1 A description_1 history_1 2 B description_2 history_1 3 C description_2 history_2 Description and History column will have the previous known values if they dont have value for that Rev no. i.e. Since for Rev no. 3 Description does not have an entry in TABLE_B hence the last known value description_2 appears in that column for Rev no. 3 in the output.

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  • Can not search my company howto blog site anylonger... i can only search my mysites and users...

    - by Worldunix
    I have a Howto company Blog site that i post to for my clients to access for help. For some reason it has stopped letting anyone search on it. I can search for Mysites or users. But when you drop down the tab to search: This Site: "blog site name" you get the following reply: No results matching your search were found. Check your spelling. Are the words in your query spelled correctly? Try using synonyms. Maybe what you're looking for uses slightly different words. Make your search more general. Try more general terms in place of specific ones. Try your search in a different scope. Different scopes can have different results. I have tried the following command: from the Index server net stop osearch net start osearch iisreset /noforce But still not able to search a local blog site I can only search for users and Sites. please help Don

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  • How do I do proximity search in Oracle right?

    - by hko19
    Oracle's NEAR operator for full text search returns a score based on the proximity of two or more query terms. For example: near((dog, bite), 6) matches if 'dog' and 'bite' occurs within 6 words. What if I'd like it to match if either 'dog' or 'cat' or any other type of animal occurs within 6 words of the word 'bite'? I tried: near(((dog OR cat OR animal), bite), 6) but I got: NEAR operand not a phrase, equivalence or another NEAR expression Rather than expanding all possible combination into multiple NEAR and 'or' them together, what is the proper way to write such query?

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  • Using excel, how can I count the number of cells in a column containing the text "true" or "false"?

    - by Jay Elston
    I have a spreadsheet that has a column of cells where each cell contains a single work. I would like to count the occurrences of some words. I can use the COUNTIF function for most words, but if the word is "true" or "false", I get 0. A B 1 apples 2 2 true 0 3 false 0 4 oranges 1 5 apples In the above spreadsheet table, I have these formulas in cells B1, B2, B3 and B4: =COUNTIF(A1:A5,"apples") =COUNTIF(A1:A5,"true") =COUNTIF(A1:A5,"false") =COUNTIF(A1:A5,"oranges) As you can see, I can count apples, but not true or false. I have also tried this: =COUNTIF(A1:A5,TRUE) But that does not work either. Note -- I am using Excel 2007.

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  • Mod_rewrite works on local, not on remote, version?

    - by TylerT
    I have this site. Let's call it htp://www.mysite.com I have a rewrite rule to change htp://www.mysite.com/?q=words%20etc/0/10 into http://www.mysite.com/words%20etc/0/10 (or http://www.mysite.com//0/10 or http://www.mysite.com/0/10) .htaccess:ErrorDocument 404 htp://www.mysite.com/404.html options +FollowSymlinks rewriteEngine on rewriteCond %{REQUEST_URI} !-f rewriteCond %{REQUEST_URI} !-d rewriteCond %{REQUEST_URI} !index\.php rewriteRule ^/?([^/]+?)?/?([0-9]+?)/([0-9]+?)$ index.php/%{THE_REQUEST} [NC] Now, this works on my local apache 2.2.11 server, no errors. However on my host's apache 1.3.41 server, I get the following error: [Sat Mar 5 21:42:14 2011] [alert] [client [ip]] /home/_/public_html/mysite.com/.htaccess: RewriteRule: cannot compile regular expression '^/?([^/]+?)?/?([0-9]+?)/([0-9]+?)$'\n I imagine it's something quirky about the apache version as other sites on this host use mod_rewrite without a hitch. I've tried removing the +followSymlinks line, even the rewrite engine line. I haven't tried removing the conditions cause I don't think I should have to, I'm probably wrong.

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  • 'Scanner' does not name a type error in g++

    - by Max
    Hi. I'm trying to compile code in g++ and I get the following errors: In file included from scanner.hpp:8, from scanner.cpp:5: parser.hpp:14: error: ‘Scanner’ does not name a type parser.hpp:15: error: ‘Token’ does not name a type Here's my g++ command: g++ parser.cpp scanner.cpp -Wall Here's parser.hpp: #ifndef PARSER_HPP #define PARSER_HPP #include <string> #include <map> #include "scanner.hpp" using std::string; class Parser { // Member Variables private: Scanner lex; // Lexical analyzer Token look; // tracks the current lookahead token // Member Functions <some function declarations> }; #endif and here's scanner.hpp: #ifndef SCANNER_HPP #define SCANNER_HPP #include <iostream> #include <cctype> #include <string> #include <map> #include "parser.hpp" using std::string; using std::map; enum { // reserved words BOOL, ELSE, IF, TRUE, WHILE, DO, FALSE, INT, VOID, // punctuation and operators LPAREN, RPAREN, LBRACK, RBRACK, LBRACE, RBRACE, SEMI, COMMA, PLUS, MINUS, TIMES, DIV, MOD, AND, OR, NOT, IS, ADDR, EQ, NE, LT, GT, LE, GE, // symbolic constants NUM, ID, ENDFILE, ERROR }; class Token { public: int tag; int value; string lexeme; Token() {tag = 0;} Token(int t) {tag = t;} }; class Num : public Token { public: Num(int v) {tag = NUM; value = v;} }; class Word : public Token { public: Word() {tag = 0; lexeme = "default";} Word(int t, string l) {tag = t; lexeme = l;} }; class Scanner { private: int line; // which line the compiler is currently on int depth; // how deep in the parse tree the compiler is map<string,Word> words; // list of reserved words and used identifiers // Member Functions public: Scanner(); Token scan(); string printTag(int); friend class Parser; }; #endif anyone see the problem? I feel like I'm missing something incredibly obvious.

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  • What is on the 68000 stack when classic MacOS enters a program?

    - by John Källén
    I'm trying to understand an old classic Mac application's entry point. I've disassembled the first CODE resource (not CODE#0, which is the jump table). The code refers to some variables off the stack: a word at 0004(A7), an array of long words of starting at 000C(A7) whose length is the value at 0004(A7), and a final long word beyond that array that seems to be a pointer to a character string. The array of long words looks like strings at first glance, so it looks superficially like we're dealing with an (int argc, char ** argv) situation, except the "argv" array is inline in the stack frame. What should a program be expecting on its stack / registers when it first gets called by the Mac OS?

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  • Access outer class from inner class: Why is it done this way?

    - by Vuntic
    So most of us know how to access an outer class from an inner class. Searches with those words give oodles of answered questions on that topic. But what I want to know is why the syntax is the way it is. Example: public class A { private class B { public void c() {A.this.d();} } public void d() {System.out.println("You've called d()! Go, you!");} } Why is it A.this.d()? It looks like this is a static field of class A, but... * am confused * Forgive me if this is a repeat; like I said, searches with those words give how-answers.

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  • Minimum 4 Characters or Show Nothing - PHP

    - by ali
    Hi, I want to show up only words with minimum 4 Characters, actually I can limit the hits and show only words with min. 100 hits - but how can I set a min. character length? thank you! function sm_list_recent_searches($before = '', $after = '', $count = 20) { // List the most recent successful searches. global $wpdb, $table_prefix; $count = intval($count); $results = $wpdb->get_results( "SELECT `terms`, `datetime` FROM `{$table_prefix}searchmeter_recent` WHERE 100 < `hits` ORDER BY `datetime` DESC LIMIT $count"); if (count($results)) { foreach ($results as $result) { echo '<a href="'. get_settings('home') . '/search/' . urlencode($result->terms) . '">'. htmlspecialchars($result->terms) .'</a>'.", "; } } }

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  • Regular Expression for accurate word-count using JavaScript

    - by Haidon
    I'm trying to put together a regular expression for a JavaScript command that accurately counts the number of words in a textarea. One solution I had found is as follows: document.querySelector("#wordcount").innerHTML = document.querySelector("#editor").value.split(/\b\w+\b/).length -1; But this doesn't count any non-Latin characters (eg: Cyrillic, Hangul, etc); it skips over them completely. Another one I put together: document.querySelector("#wordcount").innerHTML = document.querySelector("#editor").value.split(/\s+/g).length -1; But this doesn't count accurately unless the document ends in a space character. If a space character is appended to the value being counted it counts 1 word even with an empty document. Furthermore, if the document begins with a space character an extraneous word is counted. Is there a regular expression I can put into this command that counts the words accurately, regardless of input method?

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