Search Results

Search found 14016 results on 561 pages for 'mysql 5 5'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 356/561 | < Previous Page | 352 353 354 355 356 357 358 359 360 361 362 363  | Next Page >

  • Problem updating values in combobox in vb.net

    - by user225269
    I have this code, but I have a problem. When I update but do not really made any changes to the value and press the update button, the data becomes null. And it will seem that I deleted the value. I've taught of a solution, that is to add both combobox1.selectedtext and combobox1.selecteditem to the function. But it doesn't work. combobox1.selecteditem is working when you try to alter the values when you update. But will save a null value when you don't alter the values using the combobox combobox1.selectedtext will save the data into the database even without altering. But will not save the data if you try to alter it. -And I incorporated both of them, but still only one is performing, and I think it is the one that I added first: Dim shikai As New Updater Try shikai.id = TextBox1.Text shikai.fname = TextBox2.Text shikai.mi = TextBox3.Text shikai.lname = TextBox4.Text shikai.ad = TextBox5.Text shikai.contact = TextBox9.Text shikai.year = ComboBox1.SelectedText shikai.section = ComboBox2.SelectedText shikai.gender = ComboBox3.SelectedText shikai.religion = ComboBox4.SelectedText shikai.year = ComboBox1.SelectedItem shikai.section = ComboBox2.SelectedItem shikai.gender = ComboBox3.SelectedItem shikai.religion = ComboBox4.SelectedItem shikai.bday = TextBox6.Text shikai.updates() MsgBox("Successfully updated!") Please help, what would be a simple workaround to solve this problem?

    Read the article

  • problem in counting two fields in one query

    - by Mac Taylor
    hey guys i need to count new private messages and old one from a table so first thing come to mind is using mysql_num_rows and easy thing to do // check new pms $user_id = $userinfo['user_id']; $sql = "SELECT author_id FROM bb3privmsgs_to WHERE user_id='$user_id' AND (pm_new='1' OR pm_unread='1')"; $result = $db->sql_query($sql) ; $new_pms = $db->sql_numrows($result); $db->sql_freeresult($result); // check old pms $sql = "SELECT author_id FROM bb3privmsgs_to WHERE user_id='$user_id' AND (pm_new='0' OR pm_unread='0')"; $result = $db->sql_query($sql) ; $old_pms = $db->sql_numrows($result); $db->sql_freeresult($result); but how can i count these two fields just in one statement and shorter lines ?~

    Read the article

  • How to compare a string with an option value

    - by user225269
    I have this html form which has options: <tr> <td width="30" height="35"><font size="3">*List:</td> <td width="30"><input name="specific" type="text" id="specific" maxlength="25" value=""> </td> <td><font size="3">*By:</td> <td> <select name="general" id="general"> <font size="3"> <option value="YEAR">Year</option> <option value="ADDRESS">Address</option> </select></td></td> </tr> And I'm trying to have this as the form action: if ('{$_POST["ADDRESS"]}'="ADDRESS") Which will compare if the value in the option in the html form matches the word "Address". If it matches then it will execute this query: $saddress= mysql_real_escape_string($_POST['specific']);<--this is the input form where the user will put the specific address to search. mysql_query("SELECT * FROM student WHERE ADDRESS='$saddress'"); Please I need help in here, I thinks its wrong: if ('{$_POST["ADDRESS"]}'="ADDRESS")

    Read the article

  • why is there extra using where in execution plan of query

    - by user366534
    I see plan of query: EXPLAIN SELECT * FROM `subscribers` WHERE state =4 AND date_added < '2010-12-23 11:47:45' It shows: id select_type table type possible_keys key key_len ref rows Extra 1 SIMPLE subscribers range state_date_added state_date_added 9 NULL 8 Using where Here is indexes of table: Table Non_unique Key_name Seq_in_index Column_name Collation Cardinality Sub_part Packed Null Index_type Comment subscribers 0 PRIMARY 1 subscriber_id A 382039 NULL NULL BTREE subscribers 0 email_list_id 1 email_address A 191019 NULL NULL BTREE subscribers 0 email_list_id 2 list_id A 382039 NULL NULL BTREE subscribers 1 FK_list_id 1 list_id A 10 NULL NULL BTREE subscribers 1 state_date_added 1 state A 12 NULL NULL BTREE subscribers 1 state_date_added 2 date_added A 8128 NULL NULL BTREE The last two lines describes index what is supposed for the query. Why is there in extra column using where? Even If I fetch only state and date_added column, it has in extra column: Using where; Using index. I understand why it has using index, but I don't understand Using where here.

    Read the article

  • How to make an id auto_increment from where it last left off after a record delete?

    - by Sammy
    This isn't that big of a deal but I was wondering if it can be done. Right now when I insert a new record, the id field which is auto_increment and set as primary key increases it's value by one: id | first_name | last_name ------------------------------ 1 | John | Smith 2 | Jane | Doe But if I delete record 2, the next one I insert is going to have an id of 3. Is there any way to make it have an id of 2 automatically (without having to manually insert it)?

    Read the article

  • Object of class mysqli_result could not be converted to string

    - by Joann
    I asked Google to help me I got no luck. :-( Here's the particular code that generates the error: $this->conn->query("UPDATE tz_members SET confirm='yes' WHERE usr='".$uname."'"); The whole function is the following: function update_confirm_field($code) { $uname = $this->conn->query("SELECT usr FROM tz_members WHERE confirm='".$code."'"); $this->conn->query("UPDATE tz_members SET confirm='yes' WHERE usr='".$uname."'"); } Forgive me if I have missed something stupid. Can anyone tell me what's causing the problem please???

    Read the article

  • PHP Show all data in column

    - by user342391
    I am trying to show all of the data in the 'status' column of my table but am having troubles. What am I doing wrong: <?php $query1 = "SELECT id, status FROM alerts WHERE customerid='".$_SESSION['customerid']."' ORDER BY id LIMIT $start, $limit "; $result = mysql_query($query1); while ($row = mysql_fetch_array($result)) { echo $row['status'] ; } ?>

    Read the article

  • The maximum row size for the used table type, not counting BLOBs, is 65535. You have to change some columns to TEXT or BLOBs

    - by Matthew Chambers
    Hello I am getting the below message on a table i am trying to create The maximum row size for the used table type, not counting BLOBs, is 65535. You have to change some columns to TEXT or BLOBs Anyone know the answer to this please -- Table warrington_central.job -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS warrington_central.job ( id MEDIUMINT(8) UNSIGNED NOT NULL AUTO_INCREMENT , alias_title VARCHAR(255) NOT NULL , reference_number VARCHAR(100) NOT NULL , title VARCHAR(255) NOT NULL , primary_category SMALLINT(5) UNSIGNED NOT NULL , secondary_category SMALLINT(5) UNSIGNED NOT NULL , tertiary_category SMALLINT(5) UNSIGNED NULL , address_id BIGINT(20) UNSIGNED NOT NULL , geolocation_id BIGINT(20) UNSIGNED NULL , company VARCHAR(255) NOT NULL , description VARCHAR(10000) NOT NULL , skills_required VARCHAR(10000) NOT NULL , job_type TINYINT(2) UNSIGNED NOT NULL , experience_months_required TINYINT(2) UNSIGNED NOT NULL , experience_years_required TINYINT(2) UNSIGNED NOT NULL , salary_range VARCHAR(30) NOT NULL , extra_benefits_above_salary VARCHAR(500) NOT NULL , available_from DATE NULL , available_to DATE NULL , extra_location_details VARCHAR(1000) NOT NULL , contact_email VARCHAR(100) NOT NULL , contact_phone_number VARCHAR(20) NOT NULL , contact_mobile_number VARCHAR(20) NOT NULL , terms_conditions_application VARCHAR(5000) NOT NULL , link_to_profile ENUM('0','1') NOT NULL , created_on DATETIME NOT NULL , updated_on DATETIME NOT NULL , updated_by BIGINT(20) UNSIGNED NOT NULL , add_contact_form ENUM('0','1') NOT NULL , admin_package_id TINYINT(1) UNSIGNED NOT NULL , package_start_date DATETIME NOT NULL , package_end_date DATETIME NULL , package_comment VARCHAR(500) NOT NULL , viewable_to_members_only ENUM('0','1') NOT NULL , advertise_to DATETIME NULL , show_comment ENUM('0','1') NOT NULL , hits BIGINT(20) UNSIGNED NOT NULL DEFAULT 0 , visible ENUM('0','1') NOT NULL DEFAULT '0' , approved ENUM('I/* large SQL query (3.9 KB), snipped at 2,000 characters / / SQL Error (1118): Row size too large. The maximum row size for the used table type, not counting BLOBs, is 65535. You have to change some columns to TEXT or BLOBs */ SHOW WARNINGS;

    Read the article

  • Echoing a pseudo column value after a COUNT

    - by rob - not a robber
    Hi Gang... Please don't beat me if this is elementary. I searched and found disjointed stuff relating to pseudo columns. Nothing spot on about what I need. Anyway... I have a table with some rows. Each record has a unique ID, an ID that relates to another entity and finally a comment that relates to that last entity. So, I want to COUNT these rows to basically find what entity has the most comments. Instead of me explaining the query, I'll print it SELECT entity_id, COUNT(*) AS amount FROM comments GROUP BY entity_id ORDER BY amount DESC The query does just what I want, but I want to echo the values from that pseudo column, 'amount' Can it be done, or should I use another method like mysql_num_rows? Thank you!!!

    Read the article

  • How to insert <br/> after each 5 results?

    - by Axel
    This is my code: $query = mysql_query("SELECT * FROM books ORDER BY id") or die(mysql_error()); while($row = mysql_fetch_assoc($query)) { echo $row["bookname"]." - "; } How to make only 5 books displayed in each line, by inserting a at the start if the row is 5 or 10 or 15 etc... Thanks

    Read the article

  • INSERT INTO table doesn't work???

    - by Joann
    I found a tutorial from nettuts and it has a source code in it so tried implementing it in my site.. It is working now. However, it doesn't have a Registration system so I am making one. The thing is, as I have expected, my code is not working... It doesn't seem to know how to INSERT into the database. Here's the function that inserts data into the db. function register_User($un, $email, $pwd) { $query = "INSERT INTO users( username, password, email ) VALUES(:uname, :pwd, :email) LIMIT 1"; if($stmt = $this->conn->prepare($query)) { $stmt->bind_param(':uname', $un); $stmt->bind_param(':pwd', $pwd); $stmt->bind_param(':email', $email); $stmt->execute(); if($stmt->fetch()) { $stmt->close(); return true; } else return "The username or email you entered is already in use..."; } } I have debugged the connection to the database from within the class, it says it's connected. I tried using this method instead: function register($un, $email, $pwd) { $registerquery = $this->conn->query( "INSERT INTO users(uername, password, email) VALUES('".$un."', '".$pwd."', '".$email."')"); if($registerquery) { echo "<h4>Success</h4>"; } else { echo "<h4>Error</h4>"; } } And it echos "Error"... Can you please help me pen point the error in this??? :(

    Read the article

  • How to construct this query? (Ordering by COUNT() and joining with users table)

    - by Andrew
    users table: id-user-other columns scores table: id-user_id-score-other columns They're are more than one rows for each user, but there's only two scores you can have. (0 or 1, == win or loss). So I want to output all the users ordered by the number of wins, and all the users ordered by the numbers of losses. I know how to do this by looping through each user, but I was wondering how to do it with one query. Any help is appreciated!

    Read the article

  • Magento - Data is not inserted into database, but the id is autoincremented

    - by Joseph
    I am working on a new payment module for Magento and have come across an issue that I cannot explain. The following code that runs after the credit card is verified: $table_prefix = Mage::getConfig()->getTablePrefix(); $tableName = $table_prefix.'authorizecim_magento_id_link'; $resource = Mage::getSingleton('core/resource'); $writeconnection = $resource->getConnection('core_write'); $acPI = $this->_an_customerProfileId; $acAI = $this->_an_customerAddressId; $acPPI = $this->_an_customerPaymentProfileId; $sql = "insert into {$tableName} values ('', '$customerId', '$acPI', '$acPI', '3')"; $writeconnection->query($sql); $sql = "insert into {$tableName} (magCID, anCID, anOID, anObjectType) values ('$customerId', '$acPI', '$acAI', '2')"; $writeconnection->query($sql); $sql = "insert into {$tableName} (magCID, anCID, anOID, anObjectType) values ('$customerId', '$acPI', '$acPPI', '1')"; $writeconnection->query($sql); I have verified using Firebug and FirePHP that the SQL queries are syntactically correct and no errors are returned. The odd thing here is that I have checked the database, and the autoincrement value is incremented on every run of the code. However, no rows are inserted in the database. I have verified this by adding a die(); statement directly after the first write. Any ideas why this would be occuring? The relative portion of the config.xml is this: <config> <global> <models> <authorizecim> <class>CPAP_AuthorizeCim_Model</class> </authorizecim> <authorizecim_mysql4> <class>CPAP_AuthorizeCim_Model_Mysql4</class> <entities> <anlink> <table>authorizecim_magento_id_link</table> </anlink> </entities> <entities> <antypes> <table>authorizecim_magento_types</table> </antypes> </entities> </authorizecim_mysql4> </models> <resources> <authorizecim_setup> <setup> <module>CPAP_AuthorizeCim</module> <class>CPAP_AuthorizeCim_Model_Resource_Mysql4_Setup</class> </setup> <connection> <use>core_setup</use> </connection> </authorizecim_setup> <authorizecim_write> <connection> <use>core_write</use> </connection> </authorizecim_write> <authorizecim_read> <connection> <use>core_read</use> </connection> </authorizecim_read> </resources> </global> </config>

    Read the article

  • Sample/Example needed for a table/field setup

    - by acctman
    Can someone explain the statement below to me with a working sample/example. thanks in advance. You can not create duplicate fields, but simply add a single extra field, "coupleId", which would have a unique id for each couple; and two rows (one for each person) per couple; then JOIN the table against itself with a constraint like a.coupleId = b.coupleId AND a.id < b.id so that you can condense the data into a single result row for a given couple.

    Read the article

  • What database field should this be?

    - by alex
    I have a table called "Event". A column has "duration"--which is...how long that event lasts. What database type should this be? Integer? (in seconds)? In the future, I will do statements such as: If now() > event.duration THEN don't display the event.

    Read the article

  • Using sqlalchemy to query using multiple column where in clause

    - by crunkchitis
    I'm looking to execute this query using sqlalchemy. SELECT name, age, favorite_color, favorite_food FROM kindergarten_classroom WHERE (favorite_color, favorite_food) IN (('lavender','lentil soup'),('black','carrot juice')); I only want kids that like (lavender AND lentil soup) OR (black and carrot juice). This is similar, but doesn't get me all of the way there: Sqlalchemy in clause

    Read the article

  • group by query issue

    - by user319088
    gorup by query issue i have one table, which has three fields and data. Name , Top , total cat , 1 ,10 dog , 2, 7 cat , 3 ,20 hourse 4, 4 cat, 5,10 Dog 6 9 i want to select record which has highest value of "total" for each Name so my result should be like this. Name , Top , total cat , 3 , 20 hourse , 4 , 4 Dog , 6 , 9 i tried group by name order by total, but it give top most record of group by result. any one can guide me , please!!!!

    Read the article

  • SQL: Find the max record per group

    - by user319088
    I have one table, which has three fields and data. Name , Top , Total cat , 1 , 10 dog , 2 , 7 cat , 3 , 20 horse , 4 , 4 cat , 5 , 10 dog , 6 , 9 I want to select the record which has highest value of Total for each Name, so my result should be like this: Name , Top , Total cat , 3 , 20 horse , 4 , 4 Dog , 6 , 9 I tried group by name order by total, but it give top most record of group by result. Can anyone guide me, please?

    Read the article

  • inserting large number of dates

    - by Radhe
    How can I insert all dates in an year(or more) in a table using sql My dates table has following structure dates(date1 date); Suppose I want to insert dates between "2009-01-01" to "2010-12-31" inclusive. Is there any sql query for the above?

    Read the article

  • Slope requires a real as parameter 2?

    - by Dave Jarvis
    Question How do you pass the correct value to udf_slope's second parameter type? Attempts CAST(Y.YEAR AS FLOAT), but that failed (SQL error). Y.YEAR + 0.0, but that failed, too (see error message). slope(D.AMOUNT, 1.0), failed as well Error Message Using udf_slope fails due to: Can't initialize function 'slope'; slope() requires a real as parameter 2 Code SELECT D.AMOUNT, Y.YEAR, slope(D.AMOUNT, Y.YEAR + 0.0) as SLOPE, intercept(D.AMOUNT, Y.YEAR + 0.0) as INTERCEPT FROM YEAR_REF Y, DAILY D Here, D.AMOUNT is a FLOAT and Y.YEAR is an INTEGER. Create Function The slope function was created as follows: CREATE AGGREGATE FUNCTION slope RETURNS REAL SONAME 'udf_slope.so'; Function Signature From udf_slope.cc: double slope( UDF_INIT* initid, UDF_ARGS* args, char* is_null, char* is_error ) Example Usages Reading the fine manual reveals: UDF intercept() Calculates the intercept of the linear regression of two sets of variables. Function name intercept Input parameter(s) 2 (dependent variable: REAL, independent variable: REAL) Examples SELECT intercept(income,age) FROM customers UDF slope() Calculates the slope of the linear regression of two sets of variables. Function name slope Input parameter(s) 2 (dependent variable: REAL, independent variable: REAL) Examples SELECT slope(income,age) FROM customers Thoughts? Thank you!

    Read the article

  • What are the best practices for storing PHP session data in a database?

    - by undefined
    I have developed a web application that uses a web server and database hosted by a web host (on the ground) and a server running on Amazon Web Services EC2. Both servers may be used by a user during a session and both will need to know some session information about a user. I don't want to POST the information that is needed by both servers because I dont want it to be visible to browsers / Firebug etc. So I need my session data to persist across servers. And I think that this means that the best option is to store all / some of the data that I need in the database rather than in a session. The easiest thing to do seems to be to keep the sessions but to POST the session_id between servers and use this as the key to lookup the data I need from a 'user_session_data' table in the database. I have looked at Tony Marston's article "Saving PHP Session Data to a database" - should I use this or will a table with the session data that I need and session_id as key suffice? What would be the downside of creating my own table and set of methods for storing the data I need in the database?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 352 353 354 355 356 357 358 359 360 361 362 363  | Next Page >