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  • JQuery fadeIn, fadeOut div

    - by user2908998
    I have a button ("login_button"). Every time I click the button I want a DIV ("login_cont") to appear. And after, if I click anywhere else on the page I want this DIV disappear again. This is my code $(document).ready(function(){ $('#login_button').click(function(e){ $('#login_cont').fadeIn(); }); $(document).click(function(e){ $('#login_cont').fadeOut(); }); }); This looks good to me (I'm new at this). But. Every time I click on the button, the div appears but then also disappears in less than a second... why and how can I fix it?

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  • [Need help]: Issue with submit button and html file input control’s Click() method

    - by somesh
    Scenario: On click of a button, we dynamically create html file input (file upload) control on the page and call that file input controls Click() method. User then selects the file from the disk. There is a “Submit” button to upload the selected file. Problem: The problem is, when clicked on “Submit” button first time, the input value from the file input control is cleared. And the request does not go to the server. When clicked second time, the request goes to server with empty file input value. Why the first click on submit button does not send the request to server. And why it clears the file input control value? Note: The issue is observed only when we call Click() method programmatically. If we let user to click browse, then in that case, the "Submit" does not clear the input value and sends request to server on first click itself. Any help would be appreciated. Thanks in advance. By the way, server side code is in asp.net and client side in java script, testing on IE. -Somesh

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  • How should I solve this MySql problem (PHP) ? (Beginner)

    - by Camran
    I have several tables in a MySql database. I have a classifieds website, and at the bottom I display the users last visited classifieds. I do this by storing the ID:s of the ads to an array in the cookie. Now, my db is made up like this kindof: Main Table: // Stores global information, ie these fields have to be filled out in every record, never be blank ID Price category Seller Item Table: // Stores descriptive info about whats for sale ID AD_ID (FK) //This is the same as ID in the MAIN TABLE Color Size Mileage etc My problem is that I need to know what category the ad is in, in order to query mysql for the right information I think. So I need two variables, but the cookie only has one (ID) stored. Offcourse I could make two queries, first one just matching the ID to the main_table and fetch the category from the Main_table. Then make the second query and fetch all other info from the right table. Here is an example if the category was Vehicles: SELECT * FROM main_table, vehicles_table, WHERE main_table.id=$id_from_cookie AND main_table.ad_id=vehicles_table.ad_id As you can see above, I need the category to write in what table to check, right? But I think there must be a smarter way, like fetching them in one single query using only one variable (id from cookie)? How should I do this? Understand? Let me know if you need more input... Thanks

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  • How would I get an img element to render under a background-image in CSS.

    - by Nat Ryall
    Basically, I am trying to put a semi-transparent div over an image to serve as a background for text for a slideshow. Unfortunately, the browser seems intent on always rendering the img over the background-image. Is there any way to fix this? Here is my current CSS for the semi-transparent div: #slideshow .info { height: 80px; margin-top: -80px; background: url(../../images/slideshow-info-pixel.png) repeat; } ... with slideshow-info-pixel.png being a single pixel, 50% opacity, PNG 24. I have so far tried z-index and the CSS must be compatible with IE6.

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  • How do I add on multiple $_POST['row'] and variables?

    - by Ralph The Mouf
    I am struggling to find out the syntactically correct way in which to add on more variables and rows to these statements: /* WANT TO ADD ON FIVE MORE $_POST[''] */ if(isset($_POST['check_prof']) && $_POST['check_prof'] == 'checked') { $check_prof = "checked"; }else{ $check_prof = "unchecked"; } /* SAME HERE, WANT TO ADD THE OTHER FIVE IN HERE AS WELL */ $query = "UPDATE `Users` SET `check_prof` = '" . $check_prof . "' WHERE `id` = '" . $auth->id . "' LIMIT 1"; mysql_query($query,$connection); $auth->refresh(); }

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  • How to place some text over the DIV without breaking hover area of this DIV?

    - by Andr
    I'm total noob with CSS and it looks like hell =/ I have absolute positioned DIV and I handle mouse events over this DIV with JS like this: <div style='position: absolute; left: 0px; width:50px; height: 50px;' onmouseover='this.style.border="2px solid red"' onmouseout='this.style.border="1px solid black"'> </div> <div style='position: absolute;'>SOME TEXT</div> I need to place some text over this DIV and over the few same DIVs, but if I place any element over this DIV onMouseOut event is firing when mouse cursor switch to text. Tag with text can't be inside the DIV. Playing with z-index didn`t help. My browser is IE8.

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  • How to make up a search box?

    - by dfjhdfjhdf
    How to make up a form that is going to be a search box and work only via Ajax? That is: 1) What to put as the form's action value? (action="what") 2) How to submit it so that nothing else happenes except for calling the JavaScript function?

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  • How to make javascript link target to my iframe?

    - by GanChinHock.com
    I have a iframe and there is a javascript function in it. Basically, I want to create an anchor tag to call the function and activate it in my iframe. Do you have any idea? <p><a href="javascript:document.body.contentEditable='true'; document.designMode='on'; void 0" target="test">Edit Google</a></p> <iframe name="test" src="http://www.google.com"></iframe> It is not working. Any idea?

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  • How can I use Javascript to access sub-elements?

    - by Steve
    I am dynamically creating forms dynamically according to a users actions. It is an entry-box and a two "buttons" for each instance. Each instance will be wrapped in a unique div tag. What I tried to do without success is when I dynamically create the "button" I attach a function with the input variable containing the div of its instance. This a brief excerpt: var newDivClass = document.getElementById("instance"+1); button1.innerHTML = "<a href=\"#\" onclick=\"buttons("+newDivClass+");\" id=\"button1\"> Button1 </a>"; function buttons(selected) { //I want this to select the first instance //of button1 found within div newDivClass selected.getElementById("button1"); //I also tried //this.getElementById("button1"); //selected.getChildren[0]; } The problem appears to be in passing newDivClass to the the actual function.

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  • Input field name starts with a number

    - by fire
    I have an input field whose name is an MD5 string e.g.: <input type="hidden" name="7815696ecbf1c96e6894b779456d330e" value="1"> Now I understand that having a number as the first letter in an input field name is generally bad practice, but are there any side-effects to this such as a certain browser won't send it in the POST request?

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  • Full background using :cover; makes adds horizontal scroll

    - by user1907341
    I am working on a website which needs a header with full background image & 650 height. At the moment i am using background-size: cover; property with 100% width. While, it's working it leaves an awkward horizontal scroll of about 50px on right side. Which is lot more prominent in smaller resolutions. I tried applying background to body instead of header div too. But same thing happens there as well. You can see a preview here - http://nitingarg.com/projects/tfe/

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  • Image not showing in src tag

    - by Nitesh Panchal
    Hello, Can anybody tell me how do i give absolute path of the img tag's src attribute? The following doesn't work <img alt="NO IMAGE" src="/home/administrator/tiger-info0[1].gif"/> I am working On Ubuntu and i am very sure that image exists on this path.

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  • Changing input button to image?

    - by user2970202
    You can view the page I'm referring to here: http://portal.escalatehosting.com/cart.php?a=add&pid=9 Just enter a random domain name and then you'll see 2 buttons at the bottom. The first button (smaller one) works properly, but the second button (bigger one) isn't adding the order to the shopping cart. Here's the code for the first button: <input type="button" value="{$LANG.checkout} &raquo;" class="checkout" onclick="addtocart();" /> Here's the code for the second button that isn't working: <input type="image" src="http://www.escalatehosting.com/images/continueorder.jpg" style="border:0px;" onclick="addtocart();" /> I'm simply trying to replace the first button with the second one so that an image is being used, but can't seem to get the second button to work properly. What have I done wrong? I changed the type to image and the added a src.

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  • div on other div

    - by Gisinior
    i have: <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.6.1/jquery.min.js"></script> <style type="text/css"> #ONE { background-color: #888; width: 500px; height: 500px; } #TWO { background-color: blue; width: 50px; height: 50px; } #THREE { background-color: yellow; width: 200px; height: 200px; display: none; } #four { background-color: red; width: 200px; height: 200px; } </style> <script type="text/javascript"> $(document).ready( function() { $("#TWO").click( function() { $("#THREE").toggle(); }); }); </script> <div id="ONE"><div id="TWO"></div><div id="four"></div><div id="THREE"></div></div> default click for blue div how can i it make? best with transparent :)

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  • How do I display/compare a dynamic value of a mysql row in a if statement?

    - by Ralph The Mouf
    I have a checkboxes on my site that when unchecked, update their row in in the db as unchecked, and if checked,update their row in the db as checked. I am creating an ifstatement that will commence with its command if checked, and not if unchecked. I have echoed the variable and it is holding the proper value (checked or unchecked) but not sure if I am syntactically correct on displaying the state of the row in the db. This is what I am trying and will not work. I am new at php still and thank you very much for any help. if($auth->check_prof == 'checked'){// do the stuff in here}

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