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Search found 15674 results on 627 pages for 'bash date'.

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  • Bash: how to supress newlines?

    - by gilgongo
    I'm trying to extract fields from a pipe-delimited file and provide them as arguments to an external program in a loop. The file contains lines like this: value1|value2 value3|value4 So I came up with: while read line; do echo -n "${line}" | awk -F '|' '{print $1}'; echo -n " something "; echo -n "${line}" | awk -F '|' '{print $2}'; echo " somethingelse"; done < <(cat $FILE) I want to see the following output: value1 something value2 somethingelse value3 something value4 somethingelse But instead I'm getting: value1 something value2 somethingelse value3 something value4 somethingelse Perhaps I shouldn't be using echo?

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  • Extracting numeric value from output of a uder defined aggregate in netezza using bash script

    - by Ankit
    I am executing a shell script to execute my user defined aggregate which is taking inputs yavg=nzsql -c 'select avg(x) from Input1' which is giving output like this AVG ---------- 2.000000 (1 row) I want to pass only the numeric(double) value which is 2.0000(where xavg is expected) from this to S4(x,y,$xavg,$yavg) where x and y are the whole column from table Input1, xavg=nzsql -c 'select avg(y) from Input1' Below is my InputTable.txt which is a text file from which I am popluating my "Input1" table in the shell script. 1 2 3 2 1 2 3 2 1 nzsql -c 'create table Input1(x integer, y integer, v integer)' nzload -t Input1 -df InputTable.txt nzsql -c 'select * from Input1 yavg=`nzsql -c 'select avg(x) from Input1'` xavg=`nzsql -c 'select avg(y) from Input1' nzsql -c 'select S4(x,y,$xavg,$yavg) from test' Below is the output : xavg := AVG ---------- 2.000000 (1 row) yavg := AVG ---------- 1.666667 (1 row) and i am passing this value to S4(x,y,$xavg,$yavg) which is a User defined aggregate

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  • How to change icon/emblem of a directory from bash

    - by Question Mark
    I'm playing around with get_iplayer (fantastic) it's running every few hours to grab any new episodes of whatever.... After it has finished grabbing anything new i'd like to change the emblem of ~/Videos to add a plus or star (nautilus emblem preferably) Do i go about this via nautilus? Do i need to change something in gnome-config? I'm sure this can't be FS level? Cheers for any links and advice.

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  • Bash loop command until file contains n duplicate entries (lines)

    - by Andrew
    Hello, I'm writing a script and I need to create a loop that will execute same commands until file does contain a specified number of duplicate entries. For example, with each loop I will echo random string to file results. And I want loop to stop when there are 10 lines of of the same string. I thought of something like while [ `some command here (maybe using uniq)` -lt 10 ] do command1 command2 command3 done Do you have any idea how can this problem be solved? Using grep can't be done since I don't know what string I need to look for. Thank you for your suggestions.

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  • Run command with space characters in bash script

    - by ??iu
    I have a file that contains a list of files: 02 of Clubs.eps 02 of Diamonds.eps 02 of Hearts.eps 02 of Spades.eps ... I am attempting to mass-convert these to png format in several sizes. The script I am using to do this is: while read -r line do for i in 80 35 200 do convert $(sed 's/ /\\ /g' <<< Cards/${line}) -size ${i}x${i} ../img/card/$(basename $(tr ' ' '_' <<< ${line} | tr '[A-Z]' '[a-z]') .eps)_${i}.png; done done < card_list.txt However, this doesn't work, apparently trying to split on each word, resulting in the following error output: convert: unable to open image `Cards/02\': No such file or directory @ error/blob.c/OpenBlob/2514. convert: no decode delegate for this image format `Cards/02\' @ error/constitute.c/ReadImage/532. convert: unable to open image `of\': No such file or directory @ error/blob.c/OpenBlob/2514. convert: no decode delegate for this image format `of\' @ error/constitute.c/ReadImage/532. convert: unable to open image `Clubs.eps': No such file or directory @ error/blob.c/OpenBlob/2514. If I change the convert to an echo the result looks right and if I copy a line and run it myself in the shell it works fine: convert Cards/02\ of\ Clubs.eps -size 80x80 ../img/card/02_of_clubs_80.png convert Cards/02\ of\ Clubs.eps -size 35x35 ../img/card/02_of_clubs_35.png convert Cards/02\ of\ Clubs.eps -size 200x200 ../img/card/02_of_clubs_200.png convert Cards/02\ of\ Diamonds.eps -size 80x80 ../img/card/02_of_diamonds_80.png convert Cards/02\ of\ Diamonds.eps -size 35x35 ../img/card/02_of_diamonds_35.png convert Cards/02\ of\ Diamonds.eps -size 200x200 ../img/card/02_of_diamonds_200.png convert Cards/02\ of\ Hearts.eps -size 80x80 ../img/card/02_of_hearts_80.png convert Cards/02\ of\ Hearts.eps -size 35x35 ../img/card/02_of_hearts_35.png convert Cards/02\ of\ Hearts.eps -size 200x200 ../img/card/02_of_hearts_200.png convert Cards/02\ of\ Spades.eps -size 80x80 ../img/card/02_of_spades_80.png UPDATE: Just adding quotes (see below) has the same result as the above, where I had been using sed to add backslashes convert '"'Cards/${line}'"' -size ${i}x${i} ../img/card/$(basename $(tr ' ' '_' <<< ${line} | tr '[A-Z]' '[a-z]') .eps)_${i}.png; I've tried both double and single quotes

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  • Format stdin in bash

    - by User1
    I have a multi-line string coming from another program that I want to convert to a SQL command. I was hoping that printf could help me, but it doesn't seem to work: echo -e '1\n2\n3'|printf 'SELECT %s INTO MyTable' I was hoping to see: SELECT '1 2 3' INTO MyTable But I got: SELECT INTO MyTable How can I get the %s to read stdin?

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  • PHP - error when insert date into MySQL

    - by Michael Mao
    Hello everyone: I've got a typical problem when trying to insert a date into MySQL. The column defined in MySQL is of type DATE. My PHP version is 5.3.0 Apart from this date-related issue, the rest of my code works just fine. And this is my PHP script to do this: $tablename = BOOKS_TABLE; $insert = mysql_query("INSERT INTO $tablename (barcode, book_name, volume_num,". " author, publisher, item_type, buy_price, buy_date) VALUES ". "(". "'" . $barcode . "', ". "'" . $bookname . "', ". "'" . $volumenum . "', ". "'" . $author . "', ". "'" . $publisher . "', ". "'" . $itemtype . "', ". "'" . $buyprice . "', ". "'" . getMySQLDateString($buydate). //"'STR_TO_DATE('".$buydate ."', '%d/%m/%Y'))'". //nothing changes in MySQL ")"); And this is the faulty function : function getMySQLDateString($buydate) //typical buydate : 04/21/2009 { $mysqlDateString = date('Y-m-d H:i:s', $strtotime($buydate)); return $mysqlDateString; } The first commented out line wouldn't do anything, the script is executed with no error, however, there is nothing changed in datebase after this. The current approach will cause a Fatal error saying function name must be a string in this line. Actually I followed this thread on SO, but just cannot pass the date into MySQL... Can anyone help me figure out which part is not right? How would you do it, in this case, to get it right? Sorry about such a journeyman-like question, thanks a lot in advance.

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  • Writing " to a file in bash.

    - by S1syphus
    Simply I need to write "echo" t${count} = "$"t${count}" To a text file, including all the So the output would be something like: echo " t1 = $t1" With " as they are. So I have tried: count=1 saveIFS="$IFS" IFS=$'\n' array=($(<TEST.txt)) IFS="$saveIFS" for i in "${array[@]}" do echo "echo" t${count} = "$"t${count}"" (( count++ )) done >> long1.txt And variations on this such as: echo "echo" """"" t${count} = "$"t${count}"" But I guess the wrapping in double " is only for variables. Ideas?

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  • How to prevent filename expansion in for loop in bash

    - by cagri
    In a for loop like this, for i in `cat *.input`; do echo "$i" done if one of the input file contains entries like *a, it will, and give the filenames ending in 'a'. Is there a simple way of preventing this filename expansion? Because of use of multiple files, globbing (set -o noglob) is not a good option. I should also be able to filter the output of cat to escape special characters, but for i in `cat *.input | sed 's/*/\\*'` ... still causes *a to expand, while for i in `cat *.input | sed 's/*/\\\\*'` ... gives me \*a (including backslash). [ I guess this is a different question though ]

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  • Replacing a column in CSV file with another in bash

    - by user2525881
    I have a csv file with a number of columns. I am trying to replace the second column with the second to last column from the same file. For example, if I have a file, sample.csv 1,2,3,4,5,6 a,b,c,d,e,f g,h,i,j,k,l I want to output: 1,5,3,4,5,6 a,e,c,d,e,f g,k,i,j,k,l Can anyone help me with this task? Also note that I will be discarding the last two columns afterwards with the cut function so I am open to separating the csv file to begin with so that I can replace the column in one csv file with another column from another csv file. Whichever is easier to implement. Thanks in advance for any help.

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  • Resolve bash variable containted in another variable

    - by kogut
    I have code like that: TEXT_TO_FILTER='I would like to replace this $var to proper value' var=variable All I want to get is: TEXT_AFTER_FILTERED="I'd like to replace this variable to proper value" So I did: TEXT_AFTER_FILTERED=`eval echo $TEXT_TO_FILTER` TEXT_AFTER_FILTERED=`eval echo $(eval echo $TEXT_TO_FILTER)` Or even more weirder things, but without any effects. I remember that someday I had similar problem and I did something like that: cat << EOF > tmp.sh echo $TEXT_TO_FILTER EOF chmod +x tmp.sh TEXT_AFTER_FILTERED=`. tmp.sh` But this solution seems to be to much complex. Have any of You heard about easier solution?

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  • Good book for learning Bash shell?

    - by John Isaacks
    I want to learn how to write shell scripts. Particularly I want to write a svn post-commit script to upload files from a test server to a production server. I am sure I will want to write more as I get more into it. I have very little linux/unix knowledge. Can anyone recommend a good book?

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  • Escaping Problem in bash using isql

    - by latz
    Hi there, I am currently working on a little backup script from some firebird databases and I've come up with a weird escaping problem that I don't seem to be able to solve. Here's the thing in my script I create a variable called sqllog in which I would like to put the output of a chain of commands, here it is. sqllog=echo "SELECT * FROM RDB\$DATABASE;" | isql -u SYSDBA -pass mypasswd localhost:mydatabase | tail -n 2 | head -n 1 | wc -l if I try to execute this in shell I get the following error Statement failed, SQLCODE = -204 Dynamic SQL Error -SQL error code = -204 -Table unknown -RDB -At line 1, column 15. Table unknown RDB means it didn't take my try to escape the $. thx for any help :)

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  • [bash] checking wget's return value [if]

    - by wwrob
    I'm writing a script to download a bunch of files, and I want it to inform when a particular file doesn't exist. r=`wget -q www.someurl.com` if [ $r -ne 0 ] then echo "Not there" else echo "OK" fi But it gives the following error on execution: ./file: line 2: [: -ne: unary operator expected What's wrong?

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  • help with using alias in bash shell

    - by ajsie
    i want to have an alias "t" to enter a folder and list the content there. i tried with: alias t="cd $1; ls -la" but it just listed the folder i typed but did not enter it. i wonder why? cause when i use this one: alias b="cd ..; ls" it went back to the parent and listed the content. so i want the "t" do enter the folder i type in too. someone knows how to do this right?

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  • Source From Standard In (Bash on OSX)

    - by yar
    I am trying to do something like this ruby test.rb | source /dev/stdin where test.rb just prints out cd /. There are no errors, but it doesn't do anything either. If I use this: ruby test.rb > /eraseme; source /eraseme it works fine, but I want to avoid the intermediate file.

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  • Unexpected variable update when using bash's $(( )) operator for arithmetic

    - by philo
    I'm trying to trim a few lines from a file. I know exactly how many lines to remove (say, 2 from the top), but not how many total lines are in the file. So I tried this straightforward solution: $ wc -l $FILENAME 119559 my_filename.txt $ LINES=$(wc -l $FILENAME | awk '{print $1}') $ tail -n $(($LINES - 2)) $FILENAME > $OUTPUT_FILE The output is fine, but what happened to LINES?? $ wc -l $OUTPUT_FILE 119557 my_output_file.txt $ echo $LINES 107 Hoping someone can help me understand what's going on.

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