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  • C Library for Parsing Date Time

    - by adk
    Is one aware of a date parsing function for c. I am looking for something like: time = parse_time("9/10/2009"); printf("%d\n", time->date); time2 = parse_time("Monday September 10th 2009") time2 = parse_time("Monday September 10th 2009 12:30 AM") Thank you

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  • Solr date range problem and specific date problem

    - by Hamid
    I index some data include date in solr but when search for specific date, i get some record (not all record) include some record in next day for example: http://localhost:8080/solr/select/?q=pubdate:[2010-03-25T00:00:00Z TO 2010-03-25T23:59:59Z]&start=0&rows=10&indent=on&sort=pubdate desc i have 625000 record in 2010-03-25 but above query result return 325412 that include 14 record from 2010-03-26. Also i try with below query, but not get right result http://localhost:8080/solr/select/?q=pubdate:"2010-03-25T00:00:00Z"&start=0&rows=10&indent=on&sort=pubdate desc How to get right result for specific date ??? Could you please help me? Thanks in advanced Hamid

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  • Rails helper, show word not date.

    - by dannymcc
    Hi Everyone, A follow on from this questions: http://stackoverflow.com/questions/3032598/rails-created-at-on-display-if-today Is it possible to output the word TODAY rather than the date when using the following helper? def created_today k k.created_at if k.created_at.to_date == Date.today end <%=h created_today(k) %> Thanks, Danny

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  • How to determine which date is on friday?

    - by poo
    I have two dropdownlists - one for year and one for weeks. How to determine the chosen weeks date should be the friday. So for example I chose week 34 and year 2011 then I should know the date on friday, in format like this: 2011-08-23. And preferably in javascript too.

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  • Creating a new coloumn for date info with specific date format

    - by Ayan
    Dear All I am working with a file which has few years data and I am trying to create an aditional coloumn that reads the year and month info from the date coloumn (e.g. 01/01/1997 12:00) and create a new coloumn with month and year together(e.g. Jan-97). I am not sure how to proceed with this but what I am trying to code is the coloumn with name "new_date" in the following picture: my sample data = > dput(df) structure(list(date = structure(c(1L, 4L, 7L, 2L, 5L, 8L, 3L, 6L, 9L), .Label = c("01/01/1997 12:00", "01/01/1998 15:00", "01/01/1999 18:00", "01/02/1997 13:00", "01/02/1998 16:00", "01/02/1999 19:00", "01/03/1997 14:00", "01/03/1998 17:00", "01/03/1999 19:00"), class = "factor"), value = c(29L, 31L, 42L, 42L, 52L, 61L, 57L, 55L, 56L)), .Names = c("date", "value"), row.names = c(NA, -9L), class = "data.frame") I would really appreciate if you could advise me about how should I proceed with this, Many thanks, Ayan

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  • How to get SQL Server Date in its native format?

    - by RoguePlanetoid
    I need to get a Date from an SQL Server Database (SQL Server 2000), the date is stored as such: 2009-09-30 00:00:00.000 I want to pass this date into a Classic ASP function to use this date in the Database somewhere else, however when I get the date, it converts in my ASP code to a locale-dependant version, such as: 30/09/2009 I just want the date as-is as formatting the date so it is correct again seems unnecessary, although if this the only way then fine - is there any way to treat it as string data so it stays like that, so it can be inserted back into the database as the same date, without needing conversion?

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  • new Date() timezone in grails

    - by xain
    Hi, I'm inserting a date in grails using "new Date()" and when I read the record, it's three hours ahead the O.S.'s system time. Is there a configuration to fix this ? Thanks in advance.

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  • How to login as another user and then log out in bash script?

    - by Neuquino
    Hi, I need to write a bash script to do something as another user and then return to the initial user... Suppose I run the following as root: #!/bin/bash USER=zaraza su - "${USER}" #do some stuff as zaraza ________ #here I should logout zaraza #continue doing things as root In the console I should write "exit", but in bash is a keyword and it exits the script... Thanks in advance,

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  • php, get an end date based on start date and number of months

    - by mike
    Hi! I need to calculate an end date based on todays date and a number of months. For example, todays date 04/01/2010 and the number of months is 6. Are there any functions I can use to do some math that would return "10/01/2010"? Also, I think it's important to note that I am storing the result in MySQL as a "DATETIME" so I guess I would have to do something with the time as well... ??? Thanks!

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  • php get future date time

    - by Sanjay
    I don't know how to explain this correctly but just some sample for you guys so that you can really get what Im trying to say. Today is April 09, 2010 7 days from now is April 16,2010 Im looking for a php code, which can give me the exact date giving the number of days interval prior to the current date. I've been looking for a thread which can solve or even give a hint on how to solve this one but I found none.

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  • Converting time/date from XML file into MYSQL format

    - by IconicDigital
    One of the affiliate networks provides a feed with the following time/date format. <startDate>1349992800000</startDate> <endDate>1355266799999</endDate> My problem is I am trying to convert this to a MYSQL format, I have tried mktime and strtotime with no luck the date seems to come out wrong. I know this is the time since the Equinox, I am just not sure how to convert this to a MYSQL format.

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  • problem in getting desired date format in loop

    - by Rishi2686
    Hi there, I have a date format like this : $date1 = "Sun May 09 20:07:50 +0000 2010"; and I have to convert it to: 09-05-2010 I am using date("d-m-Y", $date1)); When I print this individually it gives proper result but I am using it in loop it gives me results like: 31-12-1969 I don't understand why this is so? Can you help, please?

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  • How to intialize a variable from another script in bash?

    - by Zombies
    How can I set my intial variables in a re-usable way? I tried to do this by invoking something like this in my child script: ./init.bash And inside init.bash: prod="false" if [ "$prod" == "prod" ] then RUN_DIR=/home/windsor/.scripts/websites JAVA_DIR=/home/windsor/prog/websitechecker OUT_DIR=/tmp/ DB="prod" else if [ ! -a /tmp/test ] then mkdir /tmp/test fi DB="mydb" OUT_DIR=/tmp/test/ RUN_DIR=/home/windsor/workspaces/bash/websites JAVA_DIR=/home/windsor/workspaces/java/testrun fi cd $RUN_DIR

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  • SQL: count days in date range?

    - by John Isaacks
    I have a query like this: SELECT COUNT(*) AS amount FROM daily_individual_tracking WHERE sales = 'YES' AND daily_individual_tracking_date BETWEEN '2010-01-01' AND '2010-03-31' I am selected from a date range. Is there a way to also get the total days in the date range?

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  • Convert date in text format to datetime format in T-SQL

    - by Rob
    I have a client supplied file that is loaded in to our SQL Server database. This file contains text based date values i.e. (05102010) and I need to read them from a db column and convert them to a normal date time value = '2010-05-10 00:00:00.000' as part of a clean-up process. Any guidance would be greatly appreciated.

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  • Set Date in a single line

    - by hibernate
    According to the java API, the constructor Date(year, month, day) is depreciated. I know that I can replace it with the following code: Calendar myCal = Calendar.getInstance(); myCal.set(Calendar.YEAR, theYear); myCal.set(Calendar.MONTH, theMonth); myCal.set(Calendar.DAY_OF_MONTH, theDay); Date theDate = myCal.getTime(); However, I would like something shorter to replace it with (ideally one-two lines). Any suggestions?

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  • C# calcuate date ranges from a list of dates.

    - by nakulringshia
    Hi Given a list of dates (which may not be sorted), I want to build a list of date ranges - E.g. Assuming MM/DD format, Input - 5/1, 5/5, 5/6, 5/15, 5/7, 5/8, 5/19,5/20, 5/23 Output - Date Range 1: 5/1 to 5/1 Date Range 2: 5/5 to 5/8 Date Range 3: 5/15 to 5/15 Date Range 4: 5/19 to 5/20 Date Range 5: 5/23 to 5/23 Basically, a range should be continuous. Thanks Nakul Ringshia

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  • [PHP] Check Valid date type

    - by yukou
    may be this question had been asked, I've searched but still not confident about my problem.. my problem is checking valid date from string $a='23-June-11'; //valid $b='Normal String';//invalid I want to convert $a and $b using strtotime() before I do that, of course i want to validate whether $a or $b is a valid date format From $a i can get 23, 11 using explode function, but how about 'June'? using function above, 'June' is not numeric

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