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  • Is there anyway to get pdb and Mac Terminal to play nicely?

    - by Ross
    When debugging my django apps I use pdb for interactive debugging with pdb.set_trace(). However, when I amend a file the local django webserver restarts and then I cant see what I type in the terminal, until I type reset. Is there anyway for this to happen automatically? It can be real annoying, having to cancel the runserver and reset and restart it all the time. I'm told it doesn't happen on other OS's (ubuntu) so is there anyway to make it not happen on the Mac? (I'm using Snow Leopard).

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  • Unity mouse input not working in webplayer build

    - by Califer
    I have a button script with the following code void OnMouseDown() { animation.Play("button-squish"); enlarged = true; audio.PlayOneShot(buttonSound); } void OnMouseUpAsButton() { if (enlarged) { SelectThisButton(); enlarged = false; animation.Play("button-return"); } } void OnMouseExit() { if (enlarged) { enlarged = false; animation.Play("button-return"); } } It works great in the editor, but when I made a build and tested it in Chrome none of the buttons had any response. Further testing revealed that it did work in Firefox. Rather than telling people to change their browser if they want to play, I want to make the button code work. How else can I get the buttons to know when they're being pressed if the built-in stuff isn't working?

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  • rigidbody2d.Addforce( ) behaves wieirdly unity 4.3 [on hold]

    - by Lilz Votca Love
    So guys ive edited the question and here is what my problem is i have a player which has a rigidbody2d attached to it.my player is able to doublejump in the air nicely and stick to walls when colliding with them and slowly slides to the ground.All movement is handle through physics and no transform manipulations.here i did something similar to this in the FixedUpdate of my player. void FixedUpdate() { if(wall && Input.GetButtonDown("Jump")) { if(facingright)//player is facing the left side of the wall { rigidbody2D.Addforce(new vector2(-1f,2f)*jumpforce); /*Now the player should jump backwards following this directional vector and should follow a smooth curve which in this part works well*/ } else { rigidbody2D.Addforce(new vector2(1f,2f)*jumpforce); /*Now this is where everything gets complicated as you should have noticed this is the same directional vector only the opposite x axis value and the same amount of force is used but it behaves like the red curve in the picture below*/ } } } bad behaviour and vector in red .I tested the same thing(both addforce methods) for a simple jump and they exactly behave like mentionned above in the picture.so here is my problem.Jumping diagonally forward with rigidbody2d.addforce() do not have the same impact,do not follow the same curve as jumping the opposite direction with the same exact amount of force.if i could fix this or get past this i could implement a walljump system like a ninja jumping in zigzag between two opposite wall to climb them.Any ideas or alternatives?

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  • How do I get jquery & mootools to play nice?

    - by Vic
    I've been using Mootools 1.2.4 as my JS framework of choice. I've added Checkout by Amazon to one of my pages, and they inject jQuery 1.2.6 into the page and messes up my dollar function (among other things). I have control over Mootools, but not jQuery. I would rather not rewrite my existing code to accomodate jQuery since Checkout by Amazon was an afterthought and plug-in element. Any thoughts or suggestions are recommended. Thanks!

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  • Does Android 2.1's Browser Support HTML 5 and What Video Format Does It Play?

    - by John Giotta
    The company I work for produces allot of video and we want to target as many devices as possible, but the question came up of what does the Android do? I personally own an Android based phone running 2.1, but I can't seem to get the HTML 5 tag to work. Even when I can trigger the browser to playback the video it just throws a notification error that it can't. Are there guidelines to producing Android/HTML 5 compatible videos? Is it truly supported?

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  • MVC controller is being called twice

    - by rboarman
    Hello, I have a controller that is being called twice from an ActionLink call. My home page has a link, that when clicked calls the Index method on the Play controller. An id of 100 is passed into the method. I think this is what is causing the issue. More on this below. Here are some code snippets: Home page: <%= Html.ActionLink(“Click Me”, "Index", "Play", new { id = 100 }, null) %> Play Controller: public ActionResult Index(int? id) { var settings = new Dictionary<string, string>(); settings.Add("Id", id.ToString()); ViewData["InitParams"] = settings.ToInitParams(); return View(); } Play view: <%@ Page Title="" Language="C#" Inherits="System.Web.Mvc.ViewPage" %> (html <head> omitted for brevity) <body> <form id="form1" runat="server" style="height:100%"> Hello </form> </body> If I get rid of the parameter to the Index method, everything is fine. If I leave the parameter in place, then the Index method is called with 100 as the id. After returning the View, the method is called a second time with a parameter of null. I can’t seem to figure out what is triggering the second call. My first thought was to add a specific route like this: routes.MapRoute( "Play", // Route name "Play/{id}", // URL with parameters new {controller = "Play", action = "Index"} // Parameter defaults ); This had no effect other than making a prettier looking link. I am not sure where to go from here. Thank you in advance. Rick

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  • How can I find the song position of a song being played with XACT?

    - by DJ SymBiotiX
    So I'm making a game in XNA and I need to use XACT for my songs (rather than media player). I need to use XACT because each song will have multiple layers that combine when played at the same time (bass, lead, drums) etc. I cant use the media player because the media player can only play one song at a time. Anyways, so lets say I have a song playing with XACT in my project with the following code public SongController() { audioEngine = new AudioEngine(@"Content\Song1\Song1.xgs"); waveBank = new WaveBank(audioEngine, @"Content\Song1\Layers.xwb"); soundBank = new SoundBank(audioEngine, @"Content\Song1\SongLayers.xsb"); songTime = new PlayTime(); Vox = soundBank.GetCue("Vox"); BG = soundBank.GetCue("BG"); Bass = soundBank.GetCue("Bass"); Lead = soundBank.GetCue("Lead"); Other = soundBank.GetCue("Other"); Vox.SetVariable("CueVolume", 100.0f); BG.SetVariable("CueVolume", 100.0f); Bass.SetVariable("CueVolume", 100.0f); Lead.SetVariable("CueVolume", 100.0f); Other.SetVariable("CueVolume", 100.0f); _bassVol = 100.0f; _voxVol = 100.0f; _leadVol = 100.0f; _otherVol = 100.0f; Vox.Play(); BG.Play(); Bass.Play(); Lead.Play(); Other.Play(); } So when I look at the variables in Vox, or BG (they are Cue's btw) I cant seem to find any play position in them. So I guess the question is: Is there a variable I can query to find that data, or do I need to make my own class that starts counting up from the time I start the song? Thanks

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  • Simulated Annealing and Yahtzee!

    - by Jasie
    I've picked up Programming Challenges and found a Yahtzee! problem which I will simplify: There are 13 scoring categories There are 13 rolls by a player (comprising a play) Each roll must fit in a distinct category The goal is to find the maximum score for a play (the optimal placement of rolls in categories); score(play) returns the score for a play Brute-forcing to find the maximum play score requires 13! (= 6,227,020,800) score() calls. I choose simulated annealing to find something close to the highest score, faster. Though not deterministic, it's good enough. I have a list of 13 rolls of 5 die, like: ((1,2,3,4,5) #1 (1,2,6,3,4),#2 ... (1,4,3,2,2) #13 ) And a play (1,5,6,7,2,3,4,8,9,10,13,12,11) passed into score() returns a score for that play's permutation. How do I choose a good "neighboring state"? For random-restart, I can simply choose a random permutation of nos. 1-13, put them in a vector, and score them. In the traveling salesman problem, here's an example of a good neighboring state: "The neighbours of some particular permutation are the permutations that are produced for example by interchanging a pair of adjacent cities." I have a bad feeling about simply swapping two random vector positions, like so: (1,5,6,7, 2 , 3,4,8,9,10, 13, 12,11) # switch 2 and 13 (1,5,6,7, 13, 3,4,8,9,10, 2 , 12,11) # now score this one But I have no evidence and don't know how to select a good neighboring state. Anyone have any ideas on how to pick good neighboring states?

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  • Playing dynamically embedded sound object via Javascript

    - by Vikram Goyal
    I need to background load some WAV files for an HTML page using AJAX. I use AJAX to get the details of the WAV files, then use the embed tag, and I can confirm that the files have loaded successfully because when I set autostart to true, the files play. However, I need the files to play only when the user clicks on a button (or an event is fired). The following is my code to preload these files: function preloadMedia() { for(var i = 0; i < testQuestions.length; i++) { var soundEmbed = document.createElement("embed"); soundEmbed.setAttribute("src", "/media/sounds/" + testQuestions[i].mediaFile); soundEmbed.setAttribute("hidden", true); soundEmbed.setAttribute("id", testQuestions[i].id); soundEmbed.setAttribute("autostart", false); soundEmbed.setAttribute("width", 0); soundEmbed.setAttribute("height", 0); soundEmbed.setAttribute("enablejavascript", true); document.body.appendChild((soundEmbed)); } } I use the following code to play the file (based on what sound file that user wants to play) function soundPlay(which) { var sounder = document.getElementById(which); sounder.Play(); } Something is wrong here, as none of the browsers I have tested on play the files using the code above. There are no errors, and the code just returns. I would have left it at that (that is - I would have convinced the client to convert all WAV's to MP3 and use MooTools). But I realized that I could play the sound files, which were not dynamically embeded. Thus, the same soundPlay function would work for a file embeded in the following manner: <embed src="/media/sounds/hug_sw1.wav" id="sound2" width="0" heigh="0" autostart="false" enablejavascript="true"/> anywhere within the HTML. And it plays well in all the browsers. Anyone have a clue on this? Is this some sort of undocumented security restriction in all the browsers? (Please remember that the files do get preloaded dynamically, as I can confirm by setting the autostart property to true - They all play). Any help appreciated.

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  • Objective-c - How to serialize audio file into small packets that can be played?

    - by vfn
    Hi there, So, I would like to get a sound file and convert it in packets, and send it to another computer. I would like that the other computer be able to play the packets as they arrive. I am using AVAudioPlayer to try to play this packets, but I couldn't find a proper way to serialize the data on the peer1 that the peer2 can play. The scenario is, peer1 has a audio file, split the audio file in many small packets, put them on a NSData and send them to peer2. Peer 2 receive the packets and play one by one, as they arrive. Does anyone have know how to do this? or even if it is possible? EDIT: Here it is some piece of code to illustrate what I would like to achieve. // This code is part of the peer1, the one who sends the data - (void)sendData { int packetId = 0; NSString *soundFilePath = [[NSBundle mainBundle] pathForResource:@"myAudioFile" ofType:@"wav"]; NSData *soundData = [[NSData alloc] initWithContentsOfFile:soundFilePath]; NSMutableArray *arraySoundData = [[NSMutableArray alloc] init]; // Spliting the audio in 2 pieces // This is only an illustration // The idea is to split the data into multiple pieces // dependin on the size of the file to be sent NSRange soundRange; soundRange.length = [soundData length]/2; soundRange.location = 0; [arraySoundData addObject:[soundData subdataWithRange:soundRange]]; soundRange.length = [soundData length]/2; soundRange.location = [soundData length]/2; [arraySoundData addObject:[soundData subdataWithRange:soundRange]]; for (int i=0; i // This is the code on peer2 that would receive an play the piece of audio on each packet - (void) receiveData:(NSData *)data { NSKeyedUnarchiver* unarchiver = [[NSKeyedUnarchiver alloc] initForReadingWithData:data]; if ([unarchiver containsValueForKey:PACKET_ID]) NSLog(@"DECODED PACKET_ID: %i", [unarchiver decodeIntForKey:PACKET_ID]); if ([unarchiver containsValueForKey:PACKET_SOUND_DATA]) { NSLog(@"DECODED sound"); NSData *sound = (NSData *)[unarchiver decodeObjectForKey:PACKET_SOUND_DATA]; if (sound == nil) { NSLog(@"sound is nil!"); } else { NSLog(@"sound is not nil!"); AVAudioPlayer *audioPlayer = [AVAudioPlayer alloc]; if ([audioPlayer initWithData:sound error:nil]) { [audioPlayer prepareToPlay]; [audioPlayer play]; } else { [audioPlayer release]; NSLog(@"Player couldn't load data"); } } } [unarchiver release]; } So, here is what I am trying to achieve...so, what I really need to know is how to create the packets, so peer2 can play the audio. It would be a kind of streaming. Yes, for now I am not worried about the order that the packet are received or played...I only need to get the sound sliced and them be able to play each piece, each slice, without need to wait for the whole file be received by peer2. Thanks!

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  • PHP AJAX mysql event calendar - UI for events spanning multiple days

    - by play
    I have built a PHP calendar system and have pretty much everything done but not sure how to deal with a UI issue involving how the events that stretched out over a couple of days. I want to be able to stretch an event that stretches over couple of days in a div that spans those days in the calendar. Basically I would like to know how to achieve what these guys have achieved with the event that stretches out from 21st to 22nd with the yellow div background. I have been trying to see how I can do it with PHP but I feel like I might be trying the wrong thing. Perhaps this is done with javascript?

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  • HTG Explains: Do Non-Windows Platforms Like Mac, Android, iOS, and Linux Get Viruses?

    - by Chris Hoffman
    Viruses and other types of malware seem largely confined to Windows in the real world. Even on a Windows 8 PC, you can still get infected with malware. But how vulnerable are other operating systems to malware? When we say “viruses,” we’re actually talking about malware in general. There’s more to malware than just viruses, although the word virus is often used to talk about malware in general. Why Are All the Viruses For Windows? Not all of the malware out there is for Windows, but most of it is. We’ve tried to cover why Windows has the most viruses in the past. Windows’ popularity is definitely a big factor, but there are other reasons, too. Historically, Windows was never designed for security in the way that UNIX-like platforms were — and every popular operating system that’s not Windows is based on UNIX. Windows also has a culture of installing software by searching the web and downloading it from websites, whereas other platforms have app stores and Linux has centralized software installation from a secure source in the form of its package managers. Do Macs Get Viruses? The vast majority of malware is designed for Windows systems and Macs don’t get Windows malware. While Mac malware is much more rare, Macs are definitely not immune to malware. They can be infected by malware written specifically for Macs, and such malware does exist. At one point, over 650,000 Macs were infected with the Flashback Trojan. [Source] It infected Macs through the Java browser plugin, which is a security nightmare on every platform. Macs no longer include Java by default. Apple also has locked down Macs in other ways. Three things in particular help: Mac App Store: Rather than getting desktop programs from the web and possibly downloading malware, as inexperienced users might on Windows, they can get their applications from a secure place. It’s similar to a smartphone app store or even a Linux package manager. Gatekeeper: Current releases of Mac OS X use Gatekeeper, which only allows programs to run if they’re signed by an approved developer or if they’re from the Mac App Store. This can be disabled by geeks who need to run unsigned software, but it acts as additional protection for typical users. XProtect: Macs also have a built-in technology known as XProtect, or File Quarantine. This feature acts as a blacklist, preventing known-malicious programs from running. It functions similarly to Windows antivirus programs, but works in the background and checks applications you download. Mac malware isn’t coming out nearly as quick as Windows malware, so it’s easier for Apple to keep up. Macs are certainly not immune to all malware, and someone going out of their way to download pirated applications and disable security features may find themselves infected. But Macs are much less at risk of malware in the real world. Android is Vulnerable to Malware, Right? Android malware does exist and companies that produce Android security software would love to sell you their Android antivirus apps. But that isn’t the full picture. By default, Android devices are configured to only install apps from Google Play. They also benefit from antimalware scanning — Google Play itself scans apps for malware. You could disable this protection and go outside Google Play, getting apps from elsewhere (“sideloading”). Google will still help you if you do this, asking if you want to scan your sideloaded apps for malware when you try to install them. In China, where many, many Android devices are in use, there is no Google Play Store. Chinese Android users don’t benefit from Google’s antimalware scanning and have to get their apps from third-party app stores, which may contain infected copies of apps. The majority of Android malware comes from outside Google Play. The scary malware statistics you see primarily include users who get apps from outside Google Play, whether it’s pirating infected apps or acquiring them from untrustworthy app stores. As long as you get your apps from Google Play — or even another secure source, like the Amazon App Store — your Android phone or tablet should be secure. What About iPads and iPhones? Apple’s iOS operating system, used on its iPads, iPhones, and iPod Touches, is more locked down than even Macs and Android devices. iPad and iPhone users are forced to get their apps from Apple’s App Store. Apple is more demanding of developers than Google is — while anyone can upload an app to Google Play and have it available instantly while Google does some automated scanning, getting an app onto Apple’s App Store involves a manual review of that app by an Apple employee. The locked-down environment makes it much more difficult for malware to exist. Even if a malicious application could be installed, it wouldn’t be able to monitor what you typed into your browser and capture your online-banking information without exploiting a deeper system vulnerability. Of course, iOS devices aren’t perfect either. Researchers have proven it’s possible to create malicious apps and sneak them past the app store review process. [Source] However, if a malicious app was discovered, Apple could pull it from the store and immediately uninstall it from all devices. Google and Microsoft have this same ability with Android’s Google Play and Windows Store for new Windows 8-style apps. Does Linux Get Viruses? Malware authors don’t tend to target Linux desktops, as so few average users use them. Linux desktop users are more likely to be geeks that won’t fall for obvious tricks. As with Macs, Linux users get most of their programs from a single place — the package manager — rather than downloading them from websites. Linux also can’t run Windows software natively, so Windows viruses just can’t run. Linux desktop malware is extremely rare, but it does exist. The recent “Hand of Thief” Trojan supports a variety of Linux distributions and desktop environments, running in the background and stealing online banking information. It doesn’t have a good way if infecting Linux systems, though — you’d have to download it from a website or receive it as an email attachment and run the Trojan. [Source] This just confirms how important it is to only run trusted software on any platform, even supposedly secure ones. What About Chromebooks? Chromebooks are locked down laptops that only run the Chrome web browser and some bits around it. We’re not really aware of any form of Chrome OS malware. A Chromebook’s sandbox helps protect it against malware, but it also helps that Chromebooks aren’t very common yet. It would still be possible to infect a Chromebook, if only by tricking a user into installing a malicious browser extension from outside the Chrome web store. The malicious browser extension could run in the background, steal your passwords and online banking credentials, and send it over the web. Such malware could even run on Windows, Mac, and Linux versions of Chrome, but it would appear in the Extensions list, would require the appropriate permissions, and you’d have to agree to install it manually. And Windows RT? Microsoft’s Windows RT only runs desktop programs written by Microsoft. Users can only install “Windows 8-style apps” from the Windows Store. This means that Windows RT devices are as locked down as an iPad — an attacker would have to get a malicious app into the store and trick users into installing it or possibly find a security vulnerability that allowed them to bypass the protection. Malware is definitely at its worst on Windows. This would probably be true even if Windows had a shining security record and a history of being as secure as other operating systems, but you can definitely avoid a lot of malware just by not using Windows. Of course, no platform is a perfect malware-free environment. You should exercise some basic precautions everywhere. Even if malware was eliminated, we’d have to deal with social-engineering attacks like phishing emails asking for credit card numbers. Image Credit: stuartpilbrow on Flickr, Kansir on Flickr     

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  • c# - wmplib - playing 2 mp3 files but can get them in synic

    - by Ciarán
    I have 2 windowsMediaPlayer objects setup Both objects have the same mp3 song file but when I play them at the same time they are out of sync by a few seconds. The code I call to play them looks like this sound1.controls.play(); sound2.controls.play(); Is it just because one play method is executed before the other and thus one fast then the other. Is their anyway I could sync them? I have tired messing with the rate of one track to match the other, but not getting it prefect. Thanks

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  • avaudioplayer interferes with mpmovieplayer on ipad

    - by user175826
    my app plays video and audio. however, i have a problem where once i play an audio file using avaudioplayer, the video refuses to play. when i play the video first, everything is fine. but if the audio is played first, any time i try to play the video it simply pops up the video player but will not play the actual video (you can use the scroller to go to any point in the video, but no playback will happen). this issue does not come up on the iphone, nor on the ipad simulator. clearly there is some resource conflict here, probably related to the audio, and i'd welcome some input on how to address it.

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  • Taking video from video camera and displaying it with MPMoviePlayerController IPhone SDK

    - by Daniel
    Has anyone tried taking a video from the camera and then using the video player provided to play it? When you take the video in portrait mode, sometimes the movie will play (when the player puts it in landscape mode) and when it puts it in portrait mode you cannot view the movie all you hear is sound,sometimes in landscape mode is flickers and does not play right, has anyone encountered this and found a way to fix it? My code to play the video looks like this: - (void)imagePickerController:(UIImagePickerController *)picker didFinishPickingMediaWithInfo:(NSDictionary *)info { NSURL *urls=[info objectForKey:@"UIImagePickerControllerMediaURL"] ; moviePlayer = [[MPMoviePlayerController alloc] initWithContentURL:[info urls]]; if (moviePlayer) { [moviePlayer play]; } } I checked settings on the docs nothing seems like it would fix this...Thanks

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