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  • How to fix Java Image Fetcher error ?

    - by Frank
    My code looks like this : private static JFileChooser fc; if (fc==null) { fc=new JFileChooser(Image_Dir); fc.addChoosableFileFilter(new Image_Filter()); // Add a custom file filter and disable the default (Accept All) file filter. fc.setAcceptAllFileFilterUsed(false); fc.setAccessory(new Image_Preview(fc)); // Add the preview pane. } int returnVal=fc.showDialog(JFileChooser_For_Image.this,"Get Image"); // Show it. After I select an image from the panel, I got the following error message : Exception in thread "Image Fetcher 0" java.lang.UnsatisfiedLinkError: Native Library C:\Program Files (x86)\Java\jre6\bin\jpeg.dll already loaded in another classloader at java.lang.ClassLoader.loadLibrary0(Unknown Source) at java.lang.ClassLoader.loadLibrary(Unknown Source) at java.lang.Runtime.loadLibrary0(Unknown Source) at java.lang.System.loadLibrary(Unknown Source) at sun.security.action.LoadLibraryAction.run(Unknown Source) at java.security.AccessController.doPrivileged(Native Method) at sun.awt.image.JPEGImageDecoder.<clinit>(Unknown Source) at sun.awt.image.InputStreamImageSource.getDecoder(Unknown Source) at sun.awt.image.FileImageSource.getDecoder(Unknown Source) at sun.awt.image.InputStreamImageSource.doFetch(Unknown Source) at sun.awt.image.ImageFetcher.fetchloop(Unknown Source) at sun.awt.image.ImageFetcher.run(Unknown Source) When I run it from an executable Jar file, it works fine, but after I wrapped it into an exe file, I got the above error, why ? How to fix it ?

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  • PHP Outputting File Attachments with Headers

    - by OneNerd
    After reading a few posts here I formulated this function which is sort of a mishmash of a bunch of others: function outputFile( $filePath, $fileName, $mimeType = '' ) { // Setup $mimeTypes = array( 'pdf' => 'application/pdf', 'txt' => 'text/plain', 'html' => 'text/html', 'exe' => 'application/octet-stream', 'zip' => 'application/zip', 'doc' => 'application/msword', 'xls' => 'application/vnd.ms-excel', 'ppt' => 'application/vnd.ms-powerpoint', 'gif' => 'image/gif', 'png' => 'image/png', 'jpeg' => 'image/jpg', 'jpg' => 'image/jpg', 'php' => 'text/plain' ); // Send Headers //-- next line fixed as per suggestion -- header('Content-Type: ' . $mimeTypes[$mimeType]); header('Content-Disposition: attachment; filename="' . $fileName . '"'); header('Content-Transfer-Encoding: binary'); header('Accept-Ranges: bytes'); header('Cache-Control: private'); header('Pragma: private'); header('Expires: Mon, 26 Jul 1997 05:00:00 GMT'); readfile($filePath); } I have a php page (file.php) which does something like this (lots of other code stripped out): // I run this thru a safe function not shown here $safe_filename = $_GET['filename']; outputFile ( "/the/file/path/{$safe_filename}", $safe_filename, substr($safe_filename, -3) ); Seems like it should work, and it almost does, but I am having the following issues: When its a text file, I am getting a strange symbol as the first letter in the text document When its a word doc, it is corrupt (presumably that same first bit or byte throwing things off). I presume all other file types will be corrupt - have not even tried them Any ideas on what I am doing wrong? Thanks - UPDATE: changed line of code as suggested - still same issue.

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  • How to test if a user has SELECTED a file to upload ?

    - by Tristan
    Hello, on a page, i have : if (!empty($_FILES['logo']['name'])) { $dossier = 'upload/'; $fichier = basename($_FILES['logo']['name']); $taille_maxi = 100000; $taille = filesize($_FILES['logo']['tmp_name']); $extensions = array('.png', '.jpg', '.jpeg'); $extension = strrchr($_FILES['logo']['name'], '.'); if(!in_array($extension, $extensions)) { $erreur = 'ERROR you must upload the right type'; } if($taille>$taille_maxi) { $erreur = 'too heavy'; } if(!empty($erreur)) { ....................... } The problem is, if the users wants to edit information WITHOUT uploading a LOGO, it raises an error : 'error you must upload the right type' So, if a user didn't put anything in the inputbox in order to upload it, i don't want to enter in these conditions test. i tested : if (!empty($_FILES['logo']['name']) and if (isset($_FILES['logo']['name']) but both doesn't seems to work. Any ideas? edit : maybe i wasn't so clear, i don't want to test if he uploaded a logo, i want to test IF he selected a file to upload, because right now, if he doesn't select a file to upload, php raises an error telling he must upload with the right format. thanks.

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  • Resize an image and maintain quality?

    - by JasonS
    Hi, I have a problem with resizing images. What happens is that if you upload a file larger than the stated parameters, the image is cropped, then saved at 100% quality. So if I upload a large jpeg which is 272Kb. The image is cropped by 100 odd pixels. The file size then goes up to 1.2Mb. We are saving images at a 100% quality. I assume that this is what is causing the problem. The image is exported from Photoshop at 30% quality which reduces the file size. Resaving the image at 100% quality creates the same image but I assume with a lot of redundant file data. Has anyone encountered this before? Does anyone have a solution? This is what we are using. $source_im = imagecreatefromjpeg ($file); $dest_im = imagecreatetruecolor ($newsize_x, $newsize_y); imagecopyresampled ( $dest_im, $source_im, 0, 0, $offset_x, $offset_y, $newsize_x, $newsize_y, $sourceWidth, $sourceHeight ); imagedestroy ($source_im); if ($greyscale) { $dest_im = $this->imageconvertgreyscale ($dest_im); } imagejpeg($dest_im, $save_to_file, $quality); break;

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  • java gui image problem : doesn't display in the background

    - by thegamer
    Hello, i have a query about why is my image not being displayed in my background of my program. I mean i did all the steps necessary and still it would'nt be displayed. The code runs perfectly but without having the image displayed. The directory is written in the good location of the image. I am using java with gui. If anyone could help me solve my problem, i would appreciate :) here is the code below: import java.awt.*; import java.awt.event.*; import javax.swing.*; public class hehe extends JPanel{ public hehe(){ setOpaque(false); setLayout(new FlowLayout()); } public static void main (String args[]){ JFrame win = new JFrame("yooooo"); // it is automaticcally hidden JPanel mainPanel = new JPanel(new BorderLayout()); win.add(mainPanel); JLabel titleLabel = new JLabel("title boss"); titleLabel.setFont(new Font("Arial",Font.BOLD,18)); titleLabel.setForeground(Color.blue); mainPanel.add(titleLabel,BorderLayout.NORTH); win.setSize(382,269); // the dimensions of the image win.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); win.setVisible(true); } public void paint(Graphics g) { Image a = Toolkit.getDefaultToolkit().getImage("C:\\Users\\andrea\\Desktop\\Gui\\car"); // car is the name of the image file and is in JPEG g.drawImage(a,0,0,getSize().width,getSize().height,this); super.paint(g); } }

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  • public class ImageHandler : IHttpHandler

    - by Ken
    cmd.Parameters.AddWithValue("@id", new system.Guid (imageid)); What using System reference would this require? Here is the handler: using System; using System.Collections.Specialized; using System.Web; using System.Web.Configuration; using System.Web.Security; using System.Globalization; using System.Configuration; using System.Data.SqlClient; using System.Data; using System.IO; using System.Web.Profile; using System.Drawing; public class ImageHandler : IHttpHandler { public void ProcessRequest(HttpContext context) { string imageid; if (context.Request.QueryString["id"] != null) imageid = (context.Request.QueryString["id"]); else throw new ArgumentException("No parameter specified"); context.Response.ContentType = "image/jpeg"; Stream strm = ShowProfileImage(imageid.ToString()); byte[] buffer = new byte[8192]; int byteSeq = strm.Read(buffer, 0, 8192); while (byteSeq > 0) { context.Response.OutputStream.Write(buffer, 0, byteSeq); byteSeq = strm.Read(buffer, 0, 8192); } //context.Response.BinaryWrite(buffer); } public Stream ShowProfileImage(String imageid) { string conn = ConfigurationManager.ConnectionStrings["MyConnectionString1"].ConnectionString; SqlConnection connection = new SqlConnection(conn); string sql = "SELECT image FROM Profile WHERE UserId = @id"; SqlCommand cmd = new SqlCommand(sql, connection); cmd.CommandType = CommandType.Text; cmd.Parameters.AddWithValue("@id", new system.Guid (imageid));//Failing Here!!!! connection.Open(); object img = cmd.ExecuteScalar(); try { return new MemoryStream((byte[])img); } catch { return null; } finally { connection.Close(); } } public bool IsReusable { get { return false; } } }

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  • Access denied to path , when uploading image to folder in server

    - by apekshabs
    Am getting error when you are going to upload the file on specified folder in the server. Here I am going to upload P6100083.jpg in storeimg folder. When I am going to upload I am getting the following error: Access to the path 'C:\inetpub\vhosts\bookmygroups.com\httpdocs\storeimg\P6100083.jpg' is denied. Can anyone help me... How to use permisiion and were to use... My code is while uploading image if (FileUpload1.HasFile) { float fileSize = FileUpload1.PostedFile.ContentLength; float floatConverttoKB = fileSize / 1024; float floatConverttoMB = floatConverttoKB / 1024; string DirName = "storeimg"; string savepath = Server.MapPath(DirName + "/"); DirectoryInfo dir = new DirectoryInfo(savepath); // string savepath = "C:\\Documents and Settings\\ssis3\\My Documents\\Visual Studio 2005\\WebSites\\finalbookgroups\\" + DirName + "\\"; if (fileSize < 4194304) { string filename = Server.HtmlEncode(FileUpload1.FileName); string extension = System.IO.Path.GetExtension(filename).ToUpper(); if (extension.Equals(".jpg") || extension.Equals(".JPG") || extension.Equals(".JPEG") || extension.Equals(".GIF")) { savepath += filename; FileUpload1.SaveAs(savepath); } } Thanks in advance

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  • HTML email image inverts on link click Outlook 07/10/13

    - by Matt Maclennan
    I'm having an issue on a HTML email in Word rendered Outlooks (2007, 2010, 2013) where I click an image link, and when the mouse is clicked, the image inverts... Here is the code below... <td align="left" width="360" valign="top" style="mso-table-lspace: 0pt; mso-table-rspace: 0pt; border-collapse: collapse;" class="hide"> <a href="#" target="_blank"> <img src="test.jpg" width="360" height="528" alt="alt tag" style="display:block;" class="img_mob centertable" border="0" align="left"> </a> </td> Here is a comparison on the image clicked/not clicked... I have tried putting a text-decoration: none on the link. All the links are styled inline as well. This is the only image that it is having this issue on the email, so tried re-saving the image with no luck. The image is saved as a JPEG and SRGB from a Photoshop PSD. Any ideas? Thanks.

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  • Which is the best way to encode batch videos on server side?

    - by albanx
    Hello I am making a general question since I am a developer and I have no advance experience on video elaboration. I have to preparare a web application with the purpose to allow video files upload on our company server and then video elaboration by server, on user command. The purpose of the web application is to allow to the user to make some elaboration on video depending on user action launch from the web app: (server has to ) convert video in different format(mp4, flv...) extact keyframes from video and saves them in jpeg format possibility to extract audio from video automatic control of quality audio & video (black frames,silences detection) change scene detection and keyframe extraction ..... This what's my bosses wanted from the web based application (with the server support obviously), and I understand only the first 3 points of this list, the rest for me was arabic.... My question is: Which is the best and fastest server side application for this works, that can support multiple batch video conversions, from command line (comand line for php-soap-socket interaction or something else..)? Is suitable Adobe Media Server for batch video conversion? Which are adobe products that can be used for this purpose? Note: I have experience with Indesign Server scripting programing (sending xml with php and soap call...), and I am looking to something similiar for video elaboration. I will appreciate any answers. THANKS ALL

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  • IIS 6.0 Rewrite rules for Wordpress (Forward slash not working and other things)

    - by DigitalBlade
    Hi, I am using Wordpress 3.0.4 on IIS 6.0 and Windows Server 2003, hosted by a company. I was having lots of issues using permalinks. I have fixed most, but now I have an issue with a forward-slash not being added to the address. This would be fine on most websites, but not on IIS for some reason. Specifically, if I go to "mysite.com/wp-admin" I can log-in and get to the dashboard, but as soon as I click anything there i am redirected to a broken link. For example: "mysite.com/post-new.php". If I add the slash at the end it's fine. So I tried to have a rewrite rule to automatically add the slash to such address: RewriteRule /wp-admin /wp-admin/ [L] But it still doesn't work. For your reference, here's the complete file: [ISAPI_Rewrite] RewriteBase / RewriteCond ${REQUEST_FILENAME} !-f RewriteCond ${REQUEST_FILENAME} !-d # For special WordPress folders (e.g. theme, admin, etc.) RewriteRule /wp-admin /wp-admin/ [L] RewriteRule /wp-(.*) /wp-$1 [L] RewriteRule /(.*\.(?:jpg|jpeg|gif|css|txt|xml|html|png|js)) /$1 [I,L] # Rules to ensure that normal content gets through RewriteRule /images/(.*) /images/$1 [L] RewriteRule /favicon.ico /favicon.ico [L] RewriteRule /robots.txt /robots.txt [L] RewriteRule /phpmyadmin/(.*) /phpmyadmin/$1 [L] RewriteRule /phpmyadmin /phpmyadmin/ [L] # For all WordPress pages RewriteRule ^/$ /index.php [L] RewriteRule /(.*) /index.php/$1 [L] Any ideas? Thanks in advance

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  • Extracting DCT coefficients from encoded images and video

    - by misha
    Is there a way to easily extract the DCT coefficients (and quantization parameters) from encoded images and video? Any decoder software must be using them to decode block-DCT encoded images and video. So I'm pretty sure the decoder knows what they are. Is there a way to expose them to whomever is using the decoder? I'm implementing some video quality assessment algorithms that work directly in the DCT domain. Currently, the majority of my code uses OpenCV, so it would be great if anyone knows of a solution using that framework. I don't mind using other libraries (perhaps libjpeg, but that seems to be for still images only), but my primary concern is to do as little format-specific work as possible (I don't want to reinvent the wheel and write my own decoders). I want to be able to open any video/image (H.264, MPEG, JPEG, etc) that OpenCV can open, and if it's block DCT-encoded, to get the DCT coefficients. In the worst case, I know that I can write up my own block DCT code, run the decompressed frames/images through it and then I'd be back in the DCT domain. That's hardly an elegant solution, and I hope I can do better. Presently, I use the fairly common OpenCV boilerplate to open images: IplImage *image = cvLoadImage(filename); // Run quality assessment metric The code I'm using for video is equally trivial: CvCapture *capture = cvCaptureFromAVI(filename); while (cvGrabFrame(capture)) { IplImage *frame = cvRetrieveFrame(capture); // Run quality assessment metric on frame } cvReleaseCapture(&capture); In both cases, I get a 3-channel IplImage in BGR format. Is there any way I can get the DCT coefficients as well?

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  • Conditionally colour data points outside of confidence bands in R

    - by D W
    I need to colour datapoints that are outside of the the confidence bands on the plot below differently from those within the bands. Should I add a separate column to my dataset to record whether the data points are within the confidence bands? Can you provide an example please? Example dataset: ## Dataset from http://www.apsnet.org/education/advancedplantpath/topics/RModules/doc1/04_Linear_regression.html ## Disease severity as a function of temperature # Response variable, disease severity diseasesev<-c(1.9,3.1,3.3,4.8,5.3,6.1,6.4,7.6,9.8,12.4) # Predictor variable, (Centigrade) temperature<-c(2,1,5,5,20,20,23,10,30,25) ## For convenience, the data may be formatted into a dataframe severity <- as.data.frame(cbind(diseasesev,temperature)) ## Fit a linear model for the data and summarize the output from function lm() severity.lm <- lm(diseasesev~temperature,data=severity) jpeg('~/Desktop/test1.jpg') # Take a look at the data plot( diseasesev~temperature, data=severity, xlab="Temperature", ylab="% Disease Severity", pch=16, pty="s", xlim=c(0,30), ylim=c(0,30) ) title(main="Graph of % Disease Severity vs Temperature") par(new=TRUE) # don't start a new plot ## Get datapoints predicted by best fit line and confidence bands ## at every 0.01 interval xRange=data.frame(temperature=seq(min(temperature),max(temperature),0.01)) pred4plot <- predict( lm(diseasesev~temperature), xRange, level=0.95, interval="confidence" ) ## Plot lines derrived from best fit line and confidence band datapoints matplot( xRange, pred4plot, lty=c(1,2,2), #vector of line types and widths type="l", #type of plot for each column of y xlim=c(0,30), ylim=c(0,30), xlab="", ylab="" )

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  • FileNotFoundExcecption while inserting image into SDCard.

    - by Are
    Hi, I want to insert images into my SDCard.So I used below code m_cImagePath = "/sdcard/"+ String.format("%d.jpg", System.currentTimeMillis()); FileOutputStream lObjOutStream = null; try { lObjOutStream = new FileOutputStream(m_cImagePath); if (null != lObjOutStream && null != finalBitmap) { finalBitmap.compress(Bitmap.CompressFormat.JPEG, 85, lObjOutStream); lObjOutStream.close(); }catch(FileNotFoundException fe){ fe.printStackTrace(); } Sometimes it is giving FileNotFoundException even my SDCard had memory.When I remove some images from sdcard again it is working smoothly.Why this Happend?How can i know that file is inserted successfully in SDCard and Is there any functionality in Java1.5 to know available space of the SDCard like java 1.6?How can i know file length which is not before inserting into the SDCard(I searched in google and found that "when the file is not physically there then file.length() always gives 0" ).But before inserting i want to know the length of the file.Then Comparing this space to available SDCard space is simple. Note :I had an idea to use Unix command df sdcard using in Runtime class to found SDCard space. Please give me an idea in this problem. Regards, Android Developer

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  • SQL query error while trying to put a file in the database

    - by DaGhostman Dimitrov
    Hey Guys I have a big problem that I have no Idea why.. I have few forms that upload files to the database, all of them work fine except one.. I use the same query in all(simple insert). I think that it has something to do with the files i am trying to upload but I am not sure. Here is the code: if ($_POST['action'] == 'hndlDocs') { $ref = $_POST['reference']; // Numeric value of $doc = file_get_contents($_FILES['doc']['tmp_name']); $link = mysqli_connect('localhost','XXXXX','XXXXX','documents'); mysqli_query($link,"SET autocommit = 0"); $query = "INSERT INTO documents ({$ref}, '{$doc}', '{$_FILES['doc']['type']}') ;"; mysqli_query($link,$query); if (mysqli_error($link)) { var_dump(mysqli_error($link)); mysqli_rollback($link); } else { print("<script> window.history.back(); </script>"); mysqli_commit($link); } } The database has only these fields: DATABASE documents ( reference INT(5) NOT NULL, //it is unsigned zerofill doc LONGBLOB NOT NULL, //this should contain the binary data mime_type TEXT NOT NULL // the mime type of the file php allows only application/pdf and image/jpeg ); And the error I get is : You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '00001, '????' at line 1 I will appreciate every help. Cheers!

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  • Android How do you save an image with your own unique Image Name?

    - by Usmaan
    This sounds like a issue a beginner like me would only have...this is my code... private void saveAvatar(Bitmap avatar) { String strAvatarFilename = Id + ".jpg"; try { avatar.compress(CompressFormat.JPEG, 100, openFileOutput(strAvatarFilename, MODE_PRIVATE)); } catch (Exception e) { Log.e(DEBUG_TAG, "Avatar compression and save failed.", e); } Uri imageUriToSaveCameraImageTo = Uri.fromFile(new File(PhotoActivity.this.getFilesDir(), strAvatarFilename)); Editor editor = Preferences.edit(); editor.putString(PREFERENCES_AVATAR, imageUriToSaveCameraImageTo.getPath()); editor.commit(); ImageButton avatarButton = (ImageButton) findViewById(R.id.ImageButton_Avatar); String strAvatarUri = Preferences.getString(PREFERENCES_AVATAR, ""); Uri imageUri = Uri.parse(strAvatarUri); avatarButton.setImageURI(null); avatarButton.setImageURI(imageUri); } This does save the image but when i go to look at the image on the sd card ti is called imag001 etc not the ID i am labelling it. How do i save the image with a name i want to call it? regards

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  • My method is too specific. How can I make it more generic?

    - by EricBoersma
    I have a class, the outline of which is basically listed below. import org.apache.commons.math.stat.Frequency; public class WebUsageLog { private Collection<LogLine> logLines; private Collection<Date> dates; WebUsageLog() { this.logLines = new ArrayList<LogLine>(); this.dates = new ArrayList<Date>(); } SortedMap<Double, String> getFrequencyOfVisitedSites() { SortedMap<Double, String> frequencyMap = new TreeMap<Double, String>(Collections.reverseOrder()); //we reverse order to sort from the highest percentage to the lowest. Collection<String> domains = new HashSet<String>(); Frequency freq = new Frequency(); for (LogLine line : this.logLines) { freq.addValue(line.getVisitedDomain()); domains.add(line.getVisitedDomain()); } for (String domain : domains) { frequencyMap.put(freq.getPct(domain), domain); } return frequencyMap; } } The intention of this application is to allow our Human Resources folks to be able to view Web Usage Logs we send to them. However, I'm sure that over time, I'd like to be able to offer the option to view not only the frequency of visited sites, but also other members of LogLine (things like the frequency of assigned categories, accessed types [text/html, img/jpeg, etc...] filter verdicts, and so on). Ideally, I'd like to avoid writing individual methods for compilation of data for each of those types, and they could each end up looking nearly identical to the getFrequencyOfVisitedSites() method. So, my question is twofold: first, can you see anywhere where this method should be improved, from a mechanical standpoint? And secondly, how would you make this method more generic, so that it might be able to handle an arbitrary set of data?

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  • Generating random thumbnails with PHP+FFMPEG

    - by MrGhost
    I am trying to generate thumbnails from movies using FFMPEG and the FFMPEG-PHP extension. My script works OK however takes 20 minutes just to generate 5-10 thumbnails! The script works by generating random numbers which are used as frame numbers later. All numbers generated are within the movies frame count. Can you work out why this script is taking 20 mins to finish? <?php //Dont' timeout set_time_limit(0); //Load the file (This can be any file - still takes ages) $mov = new ffmpeg_movie('1486460.mp4'); //Get the total frames within the movie $total_frames = $mov->getFrameCount(); //Loop 5 times to generate random frame times for ($i = 1; $i <= 5; ) { // Generate a number within 200 and the total number of frames. $frame = mt_rand(200,$total_frames); $getframe = $mov->getFrame($frame); // Check if the frame exists within the movie // If it does, place the frame number inside an array and break the current loop if($getframe){ $frames[$frame] = $getframe ; $i++; } } //For each frame found generate a thumbnail foreach ($frames as $key => $getframe) { $gd_image = $getframe->toGDImage(); imagejpeg($gd_image, "images/shot_".$key.'.jpeg'); imagedestroy($gd_image); echo $key.'<br/>'; } ?> The script SHOULD be generating frame numbers which are valid? Anything within START - END should be valid frame numbers? Yet the loop takes ages!

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  • Nginx - Treats PHP as binary

    - by Think Floyd
    We are running Nginx+FastCgi as the backend for our Drupal site. Everything seems to work like fine, except for this one url. http:///sites/all/modules/tinymce/tinymce/jscripts/tiny_mce/plugins/smimage/index.php (We use TinyMCE module in Drupal, and the url above is invoked when user tries to upload an image) When we were using Apache, everything was working fine. However, nginx treats that above url Binary and tries to Download it. (We've verified that the file pointed out by the url is a valid PHP file) Any idea what could be wrong here? I think it's something to do with the NGINX configuration, but not entirely sure what that is. Any help is greatly appreciated. Config: Here's the snippet from the nginx configuration file: root /var/www/; index index.php; if (!-e $request_filename) { rewrite ^/(.*)$ /index.php?q=$1 last; } error_page 404 index.php; location ~* \.(engine|inc|info|install|module|profile|po|sh|.*sql|theme|tpl(\.php)?|xtmpl)$|^(code-style\.pl|Entries.*|Repository|Root|Tag|Template)$ { deny all; } location ~* ^.+\.(jpg|jpeg|gif|png|ico)$ { access_log off; expires 7d; } location ~* ^.+\.(css|js)$ { access_log off; expires 7d; } location ~ .php$ { include /etc/nginx/fcgi.conf; fastcgi_pass 127.0.0.1:8888; fastcgi_index index.php; fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name; fastcgi_param QUERY_STRING $query_string; fastcgi_param REQUEST_METHOD $request_method; fastcgi_param CONTENT_TYPE $content_type; fastcgi_param CONTENT_LENGTH $content_length; } location ~ /\.ht { deny all; }

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  • uploading images with the help of arrays and fetch errors

    - by bonny
    i use a script to upload a couple of images to a directory. the code works great in case of just one picture will be uploaded. if i like to upload two images or more and have an extension that is not accepted, the script will upload the one with the extension that is allowed to upload and shows the errormessage for the one who is not accepted. but the upload takes place. that's my first problem. second problem will be: in case of an errormessage i would like to display a message in which it is said, which of the images will be not allowed. i do not know how to fetch this one that has an unaccepted ending into a variable that i can echo to the errormessage. here is the code i use: if(!empty($_FILES['image']['tmp_name'])){ $allowed_extension = array('jpg', 'jpeg', 'png', 'bmp', 'tiff', 'gif'); foreach($_FILES['image']['name'] as $key => $array_value){ $file_name = $_FILES['image']['name'][$key]; $file_size = $_FILES['image']['size'][$key]; $file_tmp = $_FILES['image']['tmp_name'][$key]; $file_extension = strtolower(end(explode('.', $file_name))); if (in_array($file_extension, $allowed_extension) === false){ $errors[] = 'its an unaccepted format in picture $variable_that_count'; continue; } if ($file_size > 2097152){ $errors[] = 'reached maxsize of 2MB per file in picture $variable_that_count'; } if (count($errors) == 0){ $path = "a/b/c/"; $uploadfile = $path."/".basename($_FILES['image']['name'][$key]); if (move_uploaded_file($_FILES['image']['tmp_name'][$key], $uploadfile)){ echo "success."; } } } } hope it will be clear what i like to approach. if there is someone who could help out i really would appreciate. thanks a lot.

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  • PHP: exif_imagetype() not working?

    - by Karem
    I have this extension checker: $upload_name = "file"; $max_file_size_in_bytes = 8388608; $extension_whitelist = array("jpg", "gif", "png", "jpeg"); /* checking extensions */ $path_info = pathinfo($_FILES[$upload_name]['name']); $file_extension = $path_info["extension"]; $is_valid_extension = false; foreach ($extension_whitelist as $extension) { if (strcasecmp($file_extension, $extension) == 0) { $is_valid_extension = true; break; } } if (!$is_valid_extension) { echo "{"; echo "error: 'ext not allowed!'\n"; echo "}"; exit(0); } And then i added this: if (exif_imagetype($_FILES[$upload_name]['name']) != IMAGETYPE_GIF OR exif_imagetype($_FILES[$upload_name]['name']) != IMAGETYPE_JPEG OR exif_imagetype($_FILES[$upload_name]['name']) != IMAGETYPE_PNG) { echo "{"; echo "error: 'This is no photo..'\n"; echo "}"; exit(0); } As soon when I added this to my imageupload function, the function stops working. I dont get any errors, not even the one i made myself "this is no photo", what could be wrong? Just checked with my host. They support the function exif_imagetype()

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  • PHP: Problem with reading Files

    - by mathiregister
    hello guys, i wonder what i'm doing wrong! i want to read a folder and run through the existing files, checking if they are either images or textfiles. if there are textfiles they should be put into a div, if there are images the should be output as an image. <?php $path = 'thumbs'; if ($handle = opendir($path)) { while (false !== ($file = readdir($handle))) { $ext = pathinfo($file, PATHINFO_EXTENSION); if ($ext == "jpg" || $ext == "jpeg" || $ext == "gif" || $ext == "png") { print "<img class='thumb' src='$path/$file'/>"; } else if ($ext == "txt" || $ext == "rtf") { //read text $lines = file_get_contents($file); $lines = str_replace("\n","<br/>",$lines); print "<div class='text'>" . $lines . "</div>"; //read text } } closedir($handle); } ?> there seems to be a problem i can't find, because ALL IMAGES get put out, however only ONE of a few textfiles gets printed. Any ideas why it only prints out one textfile??? thank you for your help!

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  • Saving image to server with php

    - by salmon
    Hey i have the following script, basicaly a flash file sends it some data and it creates a image and then opens a save as dialog box for the user so that they can save the image to there system.Here the problem comes in, how would i go about also saving the image to my server? <?php $to = $_POST['to']; $from = $_POST['from']; $fname = $_POST['fname']; $send = $_POST['send']; $data = explode(",", $_POST['img']); $width = $_POST['width']; $height = $_POST['height']; $image=imagecreatetruecolor( $width ,$height ); $background = imagecolorallocate( $image ,0 , 0 , 0 ); //Copy pixels $i = 0; for($x=0; $x<=$width; $x++){ for($y=0; $y<=$height; $y++){ $int = hexdec($data[$i++]); $color = ImageColorAllocate ($image, 0xFF & ($int >> 0x10), 0xFF & ($int >> 0x8), 0xFF & $int); imagesetpixel ( $image , $x , $y , $color ); } } //Output image and clean #header("Content-Disposition: attachment; filename=test.jpg" ); header("Content-type: image/jpeg"); ImageJPEG( $image ); imagedestroy( $image ); ?> Help would be greatly appreciated!

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  • Query not being executed

    - by user2385241
    I'm trying to create a script that allows me to upload an image, grab the details sent through inputs (a description and chosen project number) and insert this information into a table. I currently have this function: public function NewEntry() { $connect = new dbconnect; $_SESSION['rnd'] = substr(number_format(time() * rand(),0,'',''),0,15); $allowedExts = array("gif", "jpeg", "jpg", "png"); $size = $_FILES["file"]["size"]; $path = $_FILES["file"]["name"]; $extension = pathinfo($path, PATHINFO_EXTENSION); $pr = $_POST['project']; $cl = $_POST['changelog']; $file = $_SESSION['rnd'] . "." . $extension; if (in_array($extension, $allowedExts) && $size < 200000000) { if ($_FILES["file"]["error"] == 0) { if (!file_exists("../uploads/" . $_SESSION['rnd'])) { move_uploaded_file($_FILES["file"]["tmp_name"], "../uploads/" . $_SESSION['rnd'] . "." . $extension); } } } else { echo "File validation failed."; } $row = $connect->queryExecute("INSERT INTO entries(project,file,changelog)VALUES($pr,$file,$cl)"); header('location:http://www.example.com/admin'); } When the form is posted the function runs, the image uploads but the query isn't executed. The dbconnect class isn't at fault as it's untampered and has been used in past projects. The error logs don't give any output and no MySQL errors show. Any ideas?

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  • how to unzip uploaded zip file?

    - by Jaydeepsinh Jadeja
    I am trying to upload a zipped file using codeigniter framework with following code function do_upload() { $name=time(); $config['upload_path'] = './uploadedModules/'; $config['allowed_types'] = 'zip|rar'; $this->load->library('upload', $config); if ( ! $this->upload->do_upload()) { $error = array('error' => $this->upload->display_errors()); $this->load->view('upload_view', $error); } else { $data = array('upload_data' => $this->upload->data()); $this->load->library('unzip'); // Optional: Only take out these files, anything else is ignored $this->unzip->allow(array('css', 'js', 'png', 'gif', 'jpeg', 'jpg', 'tpl', 'html', 'swf')); $this->unzip->extract('./uploadedModules/'.$data['upload_data']['file_name'], './application/modules/'); $pieces = explode(".", $data['upload_data']['file_name']); $title=$pieces[0]; $status=1; $core=0; $this->addons_model->insertNewModule($title,$status,$core); } } But the main problem is that when extract function is called, it extract the zip but the result is empty folder. Is there any way to overcome this problem?

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  • URL Rewrite ASP.net

    - by wandos
    i have an asp.net website where i need to use URL re-write so i have written an HTTP module and i have implemented it and it works correctly the only problem is when the page redirect to its corresponding address the images and the styles are not loaded. here is the http module: // Your BeginRequest event handler. private void Application_BeginRequest(Object source, EventArgs e) { HttpApplication application = (HttpApplication)source; string URL = application.Request.Url.ToString(); //int pid = Convert.ToInt32(application.Request.QueryString["pid"]); if ((URL.ToLower().Contains(".aspx")) || (URL.ToLower().Contains(".js")) || (URL.ToLower().Contains(".css")) || (URL.ToLower().Contains(".gif")) || (URL.ToLower().Contains(".png")) || (URL.ToLower().Contains(".jpeg")) || (URL.ToLower().Contains(".jpe")) || (URL.ToLower().Contains(".jpg")) || (URL.ToLower().Contains(".ashx"))) return; else { string mname = URL.Substring(URL.LastIndexOf("/") + 1).ToString(); Merchand ms = merchantDB.GetMerchant(mname); HttpContext context = application.Context; if (ms != null) { string url = "~/pages/Merchant.aspx?mid=" + ms.MerchandID + "&catid=" + ms.MainCategory + "&subcatid=0"; context.RewritePath(VirtualPathUtility.ToAppRelative(url)); } else { //(""); string url = "~/pages/default.aspx"; context.RewritePath(VirtualPathUtility.ToAppRelative(url)); } } } when i open the page from it normal URL it opens fine, but when i use the url rewrite it open but with out images or styles. when i open firebug i get an error that the css and the javascript are not found

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