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  • trying to fade out a top div on hover to reveal working links in text below using JQuery

    - by Heath
    I need to fade a div (and image) to reveal a div underneath (text with clickable links) using jQuery. <script> $(document).ready(function(){ $("img.a").hover( function() { $(this).stop().animate({"opacity": "0"}, "slow"); }, function() { $(this).stop().animate({"opacity": "1"}, "slow"); }); }); </script> Used the above code and all worked well, until I went to click the links. Seems the top hidden div is preventing me from doing so. Tried the replaceWith function and that allowed me to click the links too - but couldn't get it to go back to showing original div when I moused out. Also, bossman wants the transition to be gradual - like a fade... Any suggestions? Many thanks! Heath

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  • Add domain to relative urls

    - by Rick
    How can I add http://facebook.com to relative URL's contained within #facebook_urls? Eg: <a href="/test.html"> becomes <a href="http://facebook.com/test.html"> #facebook_urls also contains absolute urls, so I want to make sure I don't touch those. Thanks!

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  • How can I remove certain characters from inside angle-brackets, leaving the characters outside alone

    - by Iain Fraser
    Edit: To be clear, please understand that I am not using Regex to parse the html, that's crazy talk! I'm simply wanting to clean up a messy string of html so it will parse Edit #2: I should also point out that the control character I'm using is a special unicode character - it's not something that would ever be used in a proper tag under any normal circumstances Suppose I have a string of html that contains a bunch of control characters and I want to remove the control characters from inside tags only, leaving the characters outside the tags alone. For example Here the control character is the numeral "1". Input The quick 1<strong>orange</strong> lemming <sp11a1n 1class1='jumpe111r'11>jumps over</span> 1the idle 1frog Desired Output The quick 1<strong>orange</strong> lemming <span class='jumper'>jumps over</span> 1the idle 1frog So far I can match tags which contain the control character but I can't remove them in one regex. I guess I could perform another regex on my matches, but I'd really like to know if there's a better way. My regex Bear in mind this one only matches tags which contain the control character. <(([^>])*?`([^>])*?)*?> Thanks very much for your time and consideration. Iain Fraser

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  • Backreferences syntax in replacement strings (why dollar sign?)

    - by polygenelubricants
    In Java, and it seems in a few other languages, backreferences in the pattern is preceded by a slash (e.g. \1, \2, \3, etc), but in a replacement string it's preceded by a dollar sign (e.g. $1, $2, $3, and also $0). Here's a snippet to illustrate: System.out.println( "left-right".replaceAll("(.*)-(.*)", "\\2-\\1") // WRONG!!! ); // prints "2-1" System.out.println( "left-right".replaceAll("(.*)-(.*)", "$2-$1") // CORRECT! ); // prints "right-left" System.out.println( "You want million dollar?!?".replaceAll("(\\w*) dollar", "US\\$ $1") ); // prints "You want US$ million?!?" System.out.println( "You want million dollar?!?".replaceAll("(\\w*) dollar", "US$ \\1") ); // throws IllegalArgumentException: Illegal group reference Questions: Is the use of $ for backreferences in replacement strings unique to Java? If not, what language started it? What flavors use it and what don't? Why is this a good idea? Why not stick to the same pattern syntax? Wouldn't that lead to a more cohesive and an easier to learn language? Wouldn't the syntax be more streamlined if statements 1 and 4 in the above were the "correct" ones instead of 2 and 3?

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  • preg_match problem.

    - by SoLoGHoST
    How do I add the character - within the preg_match? preg_match('#^(\w+/){0,2}\w+\.\w+$#', $string) But it must be before the . within string. I've tried just about everything I know here. I know that the - needs to be escaped. So I tried to escape it in various places, but it's not working :( Thanks :)

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  • preg_match for <?php, <?, and/or ?>

    - by SoLoGHoST
    Hello guys, I'm not very familiar with regEx's and I'm trying to find a preg_match regex for searching for any of the following strings within a file and if found it will halt it. I already have the fopen and fgets setup I just need to use a regex inside of a preg_match for the following php tags: <?php <? ?> Thanks for your help with this :)

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  • Looking for a method to replace a string with a hyperlink

    - by Richard West
    I have a usercontrol in an asp web forms application that I am working on in C#. I am binding to a repeater and outputting a field of information, named "Text", using the following syntax: <%# DataBinder.Eval(Container.DataItem, "Text") %> I am looking for a method that will allow my to search for a keyword within the string that is returned from above, and replace that string with a hyperlink such as <a href="www.anysite.com/keyword">keyword</a>. I'm not very familer with user controls and getting data back in this manner so I am looking for advice on how this might be best handled. Thanks!

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  • Wrap link around links in tweets with php preg_replace

    - by Ben Paton
    Hello I'm trying to display the latest tweet using the code below. This preg_replace works great for wrapping a link round twitter @usernames but doesn't work for web addresses in tweets. How do I get this code to wrap links around urls in tweets. <?php /** Script to pull in the latest tweet */ $username='fairgroceruk'; $format = 'json'; $tweet = json_decode(file_get_contents("http://api.twitter.com/1/statuses/user_timeline/{$username}.{$format}")); $latestTweet = htmlentities($tweet[0]->text, ENT_QUOTES); $latestTweet = preg_replace('/@([a-z0-9_]+)/i', '<a href="http://twitter.com/$1" target="_blank">@$1</a>', $latestTweet); $latestTweet = preg_replace('/http://([a-z0-9_]+)/i', '<a href="http://$1" target="_blank">http://$1</a>', $latestTweet); echo $latestTweet; ?> Thanks for the help, Ben

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  • Pulling specific entries from RSS feed [PHP]

    - by n0s
    So, I have an RSS feed with variations of each item. What I want to do is just get entries that contain a specific section of text. For example: <item> <title>RADIO SHOW - CF64K - 05-20-10 + WRAPUP </title> <link>http://linktoradioshow.com</link> <comments>Radio show from 05-20-10</comments> <pubDate>Thu, 20 May 2010 19:12:12 +0200</pubDate> <category domain="http://linktoradioshow.com/browse/199">Audio / Other</category> <dc:creator>n0s</dc:creator> <guid>http://otherlinktoradioshow.com/</guid> <enclosure url="http://linktoradioshow.com/" length="13005" /> </item> <item> <title>RADIO SHOW - CF128K - 05-20-10 + WRAPUP </title> <link>http://linktoradioshow.com</link> <comments>Radio show from 05-20-10</comments> <pubDate>Thu, 20 May 2010 19:12:12 +0200</pubDate> <category domain="http://linktoradioshow.com/browse/199">Audio / Other</category> <dc:creator>n0s</dc:creator> <guid>http://otherlinktoradioshow.com/</guid> <enclosure url="http://linktoradioshow.com/" length="13005" /> </item> I only want to display the results that contain the string CF64K. While it's probably really simple regex, I can't seem to wrap my head around getting it right. I always get seem to only be able to display the string 'CF64K', and not the stuff that surrounds it. Thanks in advance.

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  • "string" != "string"

    - by Misiur
    Hi. I'm doing some kind of own templates system. I want to change <title>{site('title')}</title> Into function "site" execution with parameter "title". Here's private function replaceFunc($subject) { foreach($this->func as $t) { $args = explode(", ", preg_replace('/\{'.$t.'\(\'([a-zA-Z,]+)\'\)\}/', '$1', $subject)); $subject = preg_replace('/\{'.$t.'\([a-zA-Z,\']+\)\}/', call_user_func_array($t, $args), $subject); } return $subject; } Here's site: function site($what) { global $db; $s = $db->askSingle("SELECT * FROM ".DB_PREFIX."config"); switch($what) { case 'title': return 'Title of page'; break; case 'version': return $s->version; break; case 'themeDir': return 'lolmao'; break; default: return false; } } I've tried to compare $what (which is for this case "title") with "title". MD5 are different. strcmp gives -1, "==", and "===" return false. What is wrong? ($what type is string. You can't change call_user_func_array into call_user_func, because later I'll be using multiple arguments)

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  • Detecting a url using preg_match? without http:// in the string

    - by Stefan
    Hey there, I was wondering how I could check a string broken into an array against a preg_match to see if it started with www. I already have one that check for http://www. $stringToArray = explode(" ",$_POST['text']); foreach($stringToArray as $key=>$val){ $urlvalid = isValidURL($val); if($urlvalid){ $_SESSION["messages"][] = "NO URLS ALLOWED!"; header("Location: http://www.domain.com/post/id/".$_POST['postID']); exit(); } } Thanks! Stefan

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  • Replace into equivalent for postgresql and then autoincrementing an int

    - by Mohamed Ikal Al-Jabir
    Okay no seriously, if a postgresql guru can help out I'm just getting started. Basically what I want is a simple table like such: CREATE TABLE schema.searches ( search_id serial NOT NULL, search_query character varying(255), search_count integer DEFAULT 1, CONSTRAINT pkey_search_id PRIMARY KEY (search_id) ) WITH ( OIDS=FALSE ); I need something like REPLACE INTO for mysql. I don't know if I have to write my own procedure or something? Basically: check if the query already exists if so, just add 1 to the count it not, add it to the db I can do this in my php code but I'd rather all that be done in postgres C engine Thanks for helping

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  • PHP - preg_match_all - iCalendar - REGEX

    - by aSeptik
    Hi All guys! ;-) i need help with creating a regex for putting all values into an array! assuming we have a huge file full of theese: Classic iCalendar style: so we know that each segment start with BEGIN:VEVENT and end with END:VEVENT ... END:VEVENT BEGIN:VEVENT UID:e3cafdf3-c5c7-427e-b8c3-653015e9321a SUMMARY:Some Text Here DESCRIPTION:Some Text Here\n555-555-555 ORGANIZER;CN=Some/Text/Here DTSTART;TZID="Some/Text/Here":20100802T190000 DTEND;TZID="Some/Text/Here":20100802T193000 STATUS:CONFIRMED CLASS:PUBLIC X-MICROSOFT-CDO-INTENDEDSTATUS:BUSY TRANSP:OPAQUE X-MICROSOFT-DISALLOW-COUNTER:TRUE DTSTAMP:20100423T021222Z SEQUENCE:1 END:VEVENT BEGIN:VEVENT ... by using preg_match_all that i think is the best choice for doing this, what's the regex that can hold all theese values into array!? PS: between segments there are no line break this is just for example! thank's to All for the time! Regards Luca Filosfi

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  • PHP: Replace umlauts with closest 7-bit ASCII equivalent in an UTF-8 string

    - by BlaM
    What I want to do is to remove all accents and umlauts from a string, turning "lärm" into "larm" or "andré" into "andre". What I tried to do was to utf8_decode the string and then use strtr on it, but since my source file is saved as UTF-8 file, I can't enter the ISO-8859-15 characters for all umlauts - the editor inserts the UTF-8 characters. Obviously a solution for this would be to have an include that's an ISO-8859-15 file, but there must be a better way than to have another required include? echo strtr(utf8_decode($input), 'ŠŒŽšœžŸ¥µÀÁÂÃÄÅÆÇÈÉÊËÌÍÎÏÐÑÒÓÔÕÖØÙÚÛÜÝßàáâãäåæçèéêëìíîïðñòóôõöøùúûüýÿ', 'SOZsozYYuAAAAAAACEEEEIIIIDNOOOOOOUUUUYsaaaaaaaceeeeiiiionoooooouuuuyy'); UPDATE: Maybe I was a bit inaccurate with what I try to do: I do not actually want to remove the umlauts, but to replace them with their closest "one character ASCII" aequivalent.

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  • Yet another php ereg fix

    - by casben79
    I have a small chunk of coding I need to take from ereg to preg_match. Here is the code. function be_file_list($d, $x) { foreach (array_diff(scandir($d), array('.', '..')) as $f) { if (is_file($d . '/' . $f) && (($x) ? ereg($x.'$',$f) : 1)) { $l[] = $f; } } return $l; } This code works as expected even if it doesn't look too pretty (source: http://www.php.net/manual/en/function.scandir.php) but as ereg is deprecated, I would really like to make it preg_match, or something like that. I have been messing with this all afternoon and the PC is about to go out the window. I would have thought that preg_match("/"$x.'$',$f"/") would have worked but no dice. Any help would be great. Cheers Ben

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  • Helper functions & prototype methods to replace heavy frameworks?

    - by Rob
    All frameworks aside, what are some of the common helper functions/prototype methods you use on a daily basis? Please note I am not arguing against frameworks. I've simply found that the majority of what I do on a daily basis can, most often, be done with a few dozen Array, String and Element.prototype methods. With the addition of a few helper functions like $ (getElementsById) and $$$ (getElementsByClass), I am able to satisfy some of the core benefits, however basic, of a much heavier framework. If you were to collect a small library of basic methods and functions to replace the core functionality of some of the popular frameworks, what would they be?

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  • php - regex- preg_replace - space after line-break!

    - by aSeptik
    Hi all guys! still on regex! i want learn it but i'm still crashing the head into my keybord! ;-) ok very trivial for you, i'm sure! Assuming i have this sting, the \s is where the space actualy is... \n where linebreak is.. DESCRIPTION: The quick brown fox jum`\s\n` `\s`ps over the lazy dog now, what i need to do is remove All the space after the A-Z: that i have achieved by this regex: /\s+(?![A-Z:])/m that produce this result DESCRIPTION: The quick brown fox jum ps over the lazy dog as you can see it leave the space between jum and ps how to have a result like this? DESCRIPTION: The quick brown fox jumps over the lazy dog thank's for the time!

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  • Using installshield to replace a same-versioned DLL in the GAC

    - by Kevin
    We recently put out an update of one of our apps with a "test" DLL from a third party. The third party does not update their assembly versions on the dll's, only the file versions, so multiple apps can reference different "versions" of it. However, the GAC still allows us to keep the newest version, because it also checks the file version which is always updated. What happened is we were not ready to release this DLL, but it got out there on some customer machines. I would like to put our current live version back out there, but it has an older file version (and the same assembly version) as the test DLL. We have multiple apps referencing this DLL, so I can't simply delete it and drop in the new one. Is there a way to replace the DLL in the GAC? I'm using installshield 2009. Perhaps some sort of custom action upon install?

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  • Netlogo: error when putting variable in table, only constants allowe??

    - by Chantal
    Hello, Currently I am working on a Netlogo program where I need to use nodes and links for vehicle routing problem. (links are called streets in the program) Here I have some practical problems of how to input variable linkspeed in a table with another node. Constants like 200 etc are fine. Online I found some examples where variables are used, but I do not know why I keep getting the following error: Expected a constant. (or why netlogo expects a constant) Here is the relevant piece of code: extensions [table] streets-own [linkspeed linktoll] nodes-own [netw] ;; In another piece of code linkspeed is assigned successfully to the links to cheapcalc ;; start conditions set costs very high 300000 ;; state 3 unsearched state 2 searching state 1 searched (for later purposes) ask nodes [ set i 0 set j count nodes set netw table:make while [i < j][ table:put netw (i) [3000000 3] set i (i + 1)]] set i 0 let k 0 ask node 35 ;; here i use node 35 as an example. ;; node 35 is connected to node 34, 36, 20 and 50 [table:put netw (35) [0 1] ;; node need to search costs to travel to itself ;; putting constants is ok. while [i < j] [ask my-links [ask both-ends [if (who != 35) [set color blue ;; set temp ([linkspeed] of street 35 who) ;; here my real goal is to put this in stat of i. but i is easier than linkspeed. table:put netw (who) [ i 2 ] ] ] ] set i (i + 1)] ] ;; next node for later, no it is just repetition of the same. end I hope somebody knows what is going on... Kind regards, Chantal

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  • replace a bunch of show/hide with switch/case in javascript

    - by Adam
    Page has menu items that would replace a 'div id=foo_(current menu item)' with 'div id=foo_(selected menu item)' in 'div class=foo' Here's what I've got, and try to keep your breakfast down... $('#t1').click(function() { $('#attorney').show(); $('#insurance,#financial,#estate,#trust,#death').hide(); }); $('#t2').click(function() { $('#insurance').show(); $('#attorney,#financial,#estate,#trust,#death').hide(); }); $('#t3').click(function() { $('#financial').show(); $('#attorney,#insurance,#estate,#trust,#death').hide(); }); $('#t4').click(function() { $('#estate').show(); $('#attorney,#insurance,#financial,#trust,#death').hide(); }); $('#t5').click(function() { $('#trust').show(); $('#attorney,#insurance,#financial,#estate,#death').hide(); }); $('#t6').click(function() { $('#death').show(); $('#attorney,#insurance,#financial,#estate,#trust').hide(); });

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  • Backslashes in gsub (escaping and backreferencing)

    - by polygenelubricants
    Consider the following snippet: puts 'hello'.gsub(/.+/, '\0 \\0 \\\0 \\\\0') This prints (as seen on ideone.com): hello hello \0 \0 This was very surprising, because I'd expect to see something like this instead: hello \0 \hello \\0 My argument is that \ is an escape character, so you write \\ to get a literal backslash, thus \\0 is a literal backslash \ followed by 0, etc. Obviously this is not how gsub is interpreting it, so can someone explain what's going on? And what do I have to do to get the replacement I want above?

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  • How can I remove HTML span tags with a Perl one liner?

    - by yaya3
    I want to perform the following vim substitution as a one-liner in the terminal with Perl. I would prefer to allow for any occurences of whitespace or newlines, rather than explicitly catering for them as I am below. %s/blockDontForget">\n*\s*<p><span><a\(.*\)<\/span>/blockDontForget"><p><a\1/g I've tried this: perl -pi -e 's/blockDontForget"><p><span><a(.*)<\/span>/blockDontForget"><p><a$1/msg' I presume I am misinterpreting the flags. Where am I going wrong? Thanks. EDIT: The above example is to strip the spans out of the following html: <div class="block blockDontForget"> <p><span><a href="../../../foo/bar/x/x.html">Lorem Ipsum</a></span></p> EDIT: It's just the <span>'s and </span>'s that are inbetween <p> and <a> from the "blockDontForget" class </div> that I want to remove (there are lots or these blockDontForget divs with spans inside anchors that I want to keep).

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  • [PHP] preg_replace: replacing using %

    - by Juan
    Hi all, I'm using the function preg_replace but I cannot figure out how to make it work, the function just doesn't seem to work for me. What I'm trying to do is to convert a string into a link if any word contains the % (percentage) character. For instance if I have the string "go to %mysite", I'd like to convert the mysite word into a link. I tried the following... $data = "go to %mysite"; $result = preg_replace('/(^|[\s\.\,\:\;]+)%([A-Za-z0-9]{1,64})/e', '\\1%<a href=#>\\2</a>', $data); ...but it doesn't work. Any help on this would be much appreciated. Thanks Juan

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