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  • Regex in JavaScript

    - by dfjhdfjhdf
    Suppose we don't know how many slashes we could get in a string but we do not want any extra slashes. So if we get this string '/hello/world///////how/are/you//////////////' we should transform it to the form of '/hello/world/how/are/you/'. How to do it with the help of regular expressions in JavaScript?

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  • regex breaks on \n

    - by Sourabh
    hi segmentText = <input from textarea>; testRgx = [/( \d+\.| [^\W\d_]\.|.)+?([!?.?](?= |$)|$)/g]; arrSegments = segmentText.match(testRgx); This expression fails if segmentText has \n or other white spaces in it.I want to add \n in to the list of chars that the above pattern use [!?.?] = [!?.?\n] so that the segment is separated based on the \n character

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  • get entire line with java.util.scanner.hasNext(regex)

    - by Hussain
    I'm doing something in Java that requires input to be matched against the pattern ^[1-5]$. I should have a while loop looping through each line of input, checking it against the pattern, and outputting an error message if it does not. Sudo code: while (regex_match(/^[^1-5]$/,inputLine)) { print ("Please enter a number between 1 and 5! "); getNextInputLine(); } I can use java.util.Scanner.hasMatch("^[^1-5]$"), but that will only match a single token, not the entire line. Any idea on how to make hasMatch match against the entire line? (Setting the delimiter to "\n" or "\0" doesn't work.)

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  • Using RegEx to Identify parts of a Database Connection String

    - by David_Jarrett
    I'm trying to get to grips with regular expressions: I have a database connection string and I'd like to use a regular expression to identify specific Keys and Values within it. For example server=foo;database=bar;uid=foo;pwd=bar I'd like something to return "database=bar;" using the 'database' key to identify it, ideally it would be case insensitive. I can do this using normal code, but I think that this is exactly the sort of thing for which regular expressions were designed.

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  • PHP regex to search across multiple lines

    - by Gaz
    I'm using preg_* in PHP to search for the pattern <!-- %{data=THIS GETS MATCHED}% --> and pull out the matched text. The pattern for this is: preg_match('#<!-- %{' . $knownString . '\s*=\s*(.*?)}% -->#', ...) What I would like it to do is search across multiple lines for the string. For example: <!-- %{data= THIS GETS MATCHED AND RETURNED }% --> How can I edit my current pattern to have this search ability?

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  • Matlab regex if statement

    - by Dan
    I want to have matlab take user input but accept both cases of a letter. For example I have: function nothing = checkGC(gcfile) if exist(gcfile) reply = input('file exists, would you like to overwrite? [Y/N]: ', 's'); if (reply == [Yy]) display('You have chosen to overwrite!') else $ Do nothing end end The if statement obviously doesn't work, but basically I want to accept a lowercase or uppcase Y. Whats the best way to do this?

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  • Poor performance / speed of regex with lookahead

    - by Hugo Zaragoza
    I have been observing extremely slow execution times with expressions with several lookaheads. I suppose that this is due to underlying data structures, but it seems pretty extreme and I wonder if I do something wrong or if there are known work-arounds. The problem is determining if a set of words are present in a string, in any order. For example we want to find out if two terms "term1" AND "term2" are somewhere in a string. I do this with the expresion: (?=.*\bterm1\b)(?=.*\bterm2\b) But what I observe is that this is an order of magnitude slower than checking first just \bterm1\b and just then \bterm2\b This seems to indicate that I should use an array of patterns instead of a single pattern with lookaheads... is this right? it seems wrong... Here is an example test code and resulting times: public static void speedLookAhead() { Matcher m, m1, m2; boolean find; int its = 1000000; // create long non-matching string char[] str = new char[2000]; for (int i = 0; i < str.length; i++) { str[i] = 'x'; } String test = str.toString(); // First method: use one expression with lookaheads m = Pattern.compile("(?=.*\\bterm1\\b)(?=.*\\bterm2\\b)").matcher(test); long time = System.currentTimeMillis(); ; for (int i = 0; i < its; i++) { m.reset(test); find = m.find(); } time = System.currentTimeMillis() - time; System.out.println(time); // Second method: use two expressions and AND the results m1 = Pattern.compile("\\bterm1\\b").matcher(test); m2 = Pattern.compile("\\bterm2\\b").matcher(test); time = System.currentTimeMillis(); ; for (int i = 0; i < its; i++) { m1.reset(test); m2.reset(test); find = m1.find() && m2.find(); } time = System.currentTimeMillis() - time; System.out.println(time); } This outputs in my computer: 1754 150

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  • PHP Regex Question

    - by oyerli
    Hi, I am developing an application using PHP but I am new to regular expressions, I could not find a solution to my problem. I want to replace all occurences of #word with a link, i have written a preg_match for this: $text=preg_replace('~#([\p{L}|\p{N}]+)~u', '<a href="/?aranan=$1">#$1</a>', $text); The problem is, this regular expression also matches the html character codes like &#039; and gives corrupt output. I need to exclude the words starting with &# but i do not know how to do that using regular expressions. Thanks for your help.

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  • need a regex for matching repeating lines of symbols (example: ------------- or *****************)

    - by Haroldo
    I want to be able to remove linebreaks etc that people make by using recurring characters, for example: **************************************************** ---------------------------------------------------- ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ etc i'd like to not have to specify which characters it will match, maybe all that are NOT \w characters? also note they will not always start/end on a new line.. is this possible?

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  • Perl regex which grabs ALL double letter occurances in a line

    - by phileas fogg
    Hi all, still plugging away at teaching myself Perl. I'm trying to write some code that will count the lines of a file that contain double letters and then place parentheses around those double letters. Now what I've come up with will find the first ocurrance of double letters, but not any other ones. For instance, if the line is: Amp, James Watt, Bob Transformer, etc. These pioneers conducted many My code will render this: 19 Amp, James Wa(tt), Bob Transformer, etc. These pioneers conducted many The "19" is the count (of lines containing double letters) and it gets the "tt" of "Watt" but misses the "ee" in "pioneers". Below is my code: $file = '/path/to/file/electricity.txt'; open(FH, $file) || die "Cannot open the file\n"; my $counter=0; while (<FH>) { chomp(); if (/(\w)\1/) { $counter += 1; s/$&/\($&\)/g; print "\n\n$counter $_\n\n"; } else { print "$_\n"; } } close(FH); What am I overlooking? TIA!

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  • Proper Regex to find and replace escaped UTF-8 strings

    - by Piet Binnenbocht
    (edited) I am reading a JSON file that includes some UTF-8 characters that are encoded like this: "\uf36b". I am trying to write a RegExp to convert this to an HTML entity that looks like "&#x1F36B;". This displays the character correctly in my html page. I haven't been able to correctly display the character that should be associated with "\uf36b", especially when in a longer sentence that also includes other text. How can I write a regexp that replaces strings like "\uf4d6" and "\uf36b" but leaves other text alone? Example: var str = "I need \uf36b #chocolate"; This should be converted to: I need &#x1F36B; #chocolate;

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  • .Net regex: what is the word character \w?

    - by tanascius
    Simple question: What is the pattern for the word character \w in c#, .net? My first thought was that it matches [A-Za-z0-9_] and the documentation tells me: Character class Description Pattern Matches \w Matches any \w "I", "D", "A", "1", "3" word character. in "ID A1.3" which is not very helpful. And \w seems to match äöü, too. What else? Is there a better (exact) definition available?

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  • Regex to replace 'li' with 'option' without losing class and id attributes

    - by Earthman Web
    I am looking for a solution using preg_replace or similar method to change: <li id="id1" class="authorlist" /> <li id="id2" class="authorlist" /> <li id="id3" class="authorlist" /> to <option id="id1" class="authorlist" /> <option id="id2" class="authorlist" /> <option id="id3" class="authorlist" /> I think I have the pattern correct, but not sure how to do the replacement part... Here is the (wordpress) php code: $string = wp_list_authors( $args ); //returns list as noted above $pattern = '<li ([^>]*)'; $replacement = '?????'; echo preg_replace($pattern, $replacement, $string); Suggestions, please?

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  • Regex: Match words in sentence PHP

    - by Granit Luzhnica
    Hi, I have an array with words like $arr = arra("go", "walk", ...) I would like to replace these words with links f they are matched in sentences. But it should be only if they match exactly (for example "walk" should match "Walk" or "walk!" but not also "walking") And the replacement should be a simple link like: < a href='#walk' walk< /a Anybody Any idea?

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  • minifying final html output using regex with codeigniter

    - by Aman
    Google pages suggest you to minify html i.e. remove all the un-necessary spaces. Codeigniter does have feature of giziping output or it can be done via .htaccess. But still I also would like to remove un-necessary spaces from final html output as well. I played a bit with this peace of code to do it, and it seem to work. This does indeed result in html that is without excess spaces and removes other tab formatting. class Welcome extends CI_Controller { function _output() { echo preg_replace('!\s+!', ' ', $output); } function index(){ ... } } Now the problem with this is there may be tag like <pre>,<textarea>, etc.. which may have space in it and regx should remove them. So, how do I remove excess space from final html, without effecting spaces or formatting for these certain tags using regx? Thanks to @Alan Moore got the answer, this worked for me echo preg_replace('#(?ix)(?>[^\S ]\s*|\s{2,})(?=(?:(?:[^<]++|<(?!/?(?:textarea|pre)\b))*+)(?:<(?>textarea|pre)\b|\z))#', ' ', $output); @ridgerunner here did very good job of analyzing this regx, ended up using his solution. Cheers to ridgerunner.

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  • Regex to test if an input string contains a certain number of characters

    - by Dan
    So, I basically would like to test to see if a string contains a range of alphanumeric characters. It's to be used as a client-side validation and I don't want to prevent users from entering whatever they want. Best to give examples of what should/should not pass validation: So to be specific, the expression I'm looking for is to test to make sure string contains anywhere from 3 to 10 alphanumeric characters. I'd like to plug into an ASP.NET client side validator. NOTE: quotes not part of input (but could be!) " f o o " should pass since there are 3 chars "f_0_0" should pass " fo " should not "F......o......o......b.....a......r" should pass thx

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  • RegEx: difference between "(?:...) and normal parentheses

    - by N0thing
    >>> re.findall(r"(?:do|re|mi)+", "mimi") ['mimi'] >>> re.findall(r"(do|re|mi)+", "mimi") ['mi'] According to my understanding of the definitions, it should produce the same answer. The only difference between (...) and (?:...) should be whether or not we can use back-references later. Am I missing something? (...) Matches whatever regular expression is inside the parentheses, and indicates the start and end of a group; the contents of a group can be retrieved after a match has been performed, and can be matched later in the string with the \number special sequence, described below. To match the literals '(' or ')', use ( or ), or enclose them inside a character class: [(] [)]. (?:...) A non-capturing version of regular parentheses. Matches whatever regular expression is inside the parentheses, but the substring matched by the group cannot be retrieved after performing a match or referenced later in the pattern.

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  • Using regex to add leading zeroes

    - by hgpc
    I would like to add a certain number of leading zeroes (say up to 3) to all numbers of a string. For example: Input: /2009/5/song 01 of 3 Output: /2009/0005/song 0001 of 0003 What's the best way to do this with regular expressions?

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  • ColdFusion - pass regex backreference to function call

    - by stubotnik
    Hi, I'm using ColdFusion's reReplace() function for regular expression pattern replacement. I'd like to use a function call for the replacement string, and pass a matched backreference to it. Something like this: <cfset s = "STARTDATE_2010-05-07 00:05:00.0_ENDDATE" /> <cfset s = reReplace(s, "STARTDATE_([\s-.:0-9]*)_ENDDATE", dateAdd("h", 1, "\1")) /> But that fails because "The value of parameter 3, which is currently \1, must be a class java.util.Date value." Is there any other way to achieve this? Thanks, Stu

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  • Help with regex pulling XML data from response body in PHP

    - by spdaly
    I am working on a project that pulls data from JMS queue using PHP and Zend Framework. The HTTP client response is below. All I need is the XML string. I came up with /(.*)<\/RequestDetails/gs which tests ok on http://gskinner.com/RegExr/ but the preg_match call is returning an empty matches array. I'm going to continue to hunt around for a pattern, but thought I would post here as well. Thanks to all who read, etc... Steve UPDATE: I can't get the code to paste correctly. Here's a link to a pastbin: http://pastebin.com/rQxzcfSg

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  • Replace URL with a link using regex in python

    - by user122750
    how do I convert some text to a link? Back in PHP, I used this piece of code that worked well for my purpose: $text = preg_replace("#(^|[\n ])(([\w]+?://[\w\#$%&~.\-;:=,?@\[\]+]*)(/[\w\#$%&~/.\-;:=,?@\[\]+]*)?)#is", "\\1<a href=\"\\2\" target=\"_blank\">\\3</a>", $text); $text = preg_replace("#(^|[\n ])(((www|ftp)\.[\w\#$%&~.\-;:=,?@\[\]+]*)(/[\w\#$%&~/.\-;:=,?@\[\]+]*)?)#is", "\\1<a href=\"http://\\2\" target=\"_blank\">\\3</a>", $text); I tried around in Python, but was unable to get it to work.. Would be very nice if someone could translate this to Python :)..

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  • How to write this regex in PHP?

    - by user198729
    $url = "http://google.com1215http://132.239.7.64:8082/jsp/wej29/en/Vm.jspHUAWEI"; preg_match('/http:\/\/.*?\.jsp/', $url, $match); I want to retrieve http://132.239.7.64:8082/jsp/wej29/en/Vm.jsp from $url,but the above returns more than I want: http://google.com1215http://132.239.7.64:8082/jsp/wej29/en/Vm.jsp How to do it properly?

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