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  • Java XML Output - proper indenting for child items

    - by Dr1Ku
    Hello, I'd like to serialize some simple data model into xml, I've been using the standard java.org.w3c -related code (see below), the indentation is better than no "OutputKeys.INDENT", yet there is one little thing that remains - proper indentation for child elements. I know that this has been asked before on stackoverflow , yet that configuration did not work for me, this is the code I'm using : DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); DocumentBuilder builder = factory.newDocumentBuilder(); Document doc = builder.newDocument(); doc = addItemsToDocument(doc); // The addItemsToDocument method adds childElements to the document. TransformerFactory transformerFactory = TransformerFactory.newInstance(); transformerFactory.setAttribute("indent-number", new Integer(4)); // switching to setAttribute("indent-number", 4); doesn't help Transformer transformer = transformerFactory.newTransformer(); transformer.setOutputProperty(OutputKeys.METHOD, "xml"); transformer.setOutputProperty(OutputKeys.INDENT, "yes"); DOMSource source = new DOMSource(doc); StreamResult result = new StreamResult(outFile); // outFile is a regular File outFile = new File("some/path/foo.xml"); transformer.transform(source, result); The output produced is : <?xml version="1.0" encoding="UTF-8" standalone="no"?> <stuffcontainer> <stuff description="something" duration="240" title="abc"> <otherstuff /> </stuff> </stuffcontainer> Whereas I would want it (for more clarity) like : <?xml version="1.0" encoding="UTF-8" standalone="no"?> <stuffcontainer> <stuff description="something" duration="240" title="abc"> <otherstuff /> </stuff> </stuffcontainer> I was just wondering if there is a way of doing this, make it properly indented for the child elements. Thank you in advance ! Happy Easter coding :-) !

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  • Sencha Tocuh XML Reader Problem

    - by Ploetzeneder
    Hi, i am student and cannot afford the premium support, so my question here: I have quite a simple XML and it gives me the following Error: http://img33.imageshack.us/i/screenprn.png/ Ext.regModel('User', { fields: ['id', 'name', 'email'] }); var store = new Ext.data.Store({ model: 'User', autoLoad:true, proxy: { type: 'ajax', url : 'ajax/user.xml', reader: { type : 'xml', model: 'User', record: 'user' } } });

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  • Libraries/Solutions for using XSL to create interactive web forms from XML

    - by Brabster
    This seems like a pretty straightforward thing to do, but I can't find anything off the open-source shelf. Is there a solution already out there that does the following: can be configured with an arbitrary XSL stylesheet generates a web form based on an arbitrary XML document and the XSL creates edit functionality in appropriate places in the rendered form updates the local representation of the XML document provides capabilities to view, save the new XML document Ideally, one that plugs into a Java web application. Even better if it can generate the XSL based on schema documents - but that might not be feasible, not really thought it through. For context, I'm thinking things like pleasant-for-humans editing of Maven POMs, ANT build.xml, etc. Cheers,

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  • array data taking XML value is not taking css value in as3

    - by Sagar S. Ranpise
    I have xml structure all data comes here inside CDATA I am using css file in it to format text and classes are mentioned in xml Below is the code which shows data but does not format with CSS. Thanks in advance! var myXML:XML = new XML(); var myURLLoader:URLLoader = new URLLoader(); var myURLRequest:URLRequest = new URLRequest("test.xml"); myURLLoader.load(myURLRequest); //////////////For CSS/////////////// var myCSS:StyleSheet = new StyleSheet(); var myCSSURLLoader:URLLoader = new URLLoader(); var myCSSURLRequest:URLRequest = new URLRequest("test.css"); myCSSURLLoader.load(myCSSURLRequest); myCSSURLLoader.addEventListener(Event.COMPLETE,processXML); var i:int; var textHeight:int = 0; var textPadding:int = 10; var txtName:TextField = new TextField(); var myMov:MovieClip = new MovieClip(); var myMovGroup:MovieClip = new MovieClip(); var myArray:Array = new Array(); function processXML(e:Event):void { myXML = new XML(myURLLoader.data); trace(myXML.person.length()); var total:int = myXML.person.length(); trace("total" + total); for(i=0; i<total; i++) { myArray.push({name: myXML.person[i].name.toString()}); trace(myArray[i].name); } processCSS(); } function processCSS():void { myCSS.parseCSS(myCSSURLLoader.data); for(i=0; i<myXML.person.length(); i++) { myMov.addChild(textConvertion(myArray[i].name)); myMov.y = textHeight; textHeight += myMov.height + textPadding; trace("Text: "+myXML.person[i].name); myMovGroup.addChild(myMov); } this.addChild(myMovGroup); } function textConvertion(textConverted:String) { var tc:TextField = new TextField(); tc.htmlText = textConverted; tc.multiline = true; tc.wordWrap = true; tc.autoSize = TextFieldAutoSize.LEFT; tc.selectable = true; tc.y = textHeight; textHeight += tc.height + textPadding; tc.styleSheet = myCSS; return tc; }

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  • How to read an XML file with Java?

    - by Yatendra Goel
    I don't need to read complex XML files. I just want to read the following configuration file with a simplest XML reader <config> <db-host>localhost</db-host> <db-port>3306</db-port> <db-username>root</db-username> <db-password>root</db-password> <db-name>cash</db-name> </config> How to read the above XML file with a XML reader through Java?

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  • xml pahsing issue..

    - by 3gwebtrain
    HI, any one help me in this xml parsing issue? my xml is : name my jquery is : $(function(){ $.get("shop.xml", function(data){ var shopInfo = $(data).find("shop").attr('title'); var showowner = $(data).find("raj").attr('title'); alert(shopInfo+':'+showowner); }) }) when i alret in firefox it alret the shopInfo as "null" and showowner "title" and i case if i check with ie, and chrome, i am getting "null:null" in the alert message. any one tell me what is the wrong i am doing here? i need my jquery need to get xml data properly from to all browsers, for that any suggestion please?

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  • Rails - strip xml import from whitespace and line break

    - by val_to_many
    Hey folks, I am stuck with something quite simple but really annoying: I have an xml file with one node, where the content includes line breaks and whitspaces. Sadly I can't change the xml. <?xml version="1.0" encoding="utf-8" ?> <ProductFeed> ACME Ltd. Fooproduct Foo Root :: Bar Category I get to the node and can read from it without trouble: url = "http://feeds.somefeed/feed.xml.gz" @source = open((url), :http_basic_authentication=>["USER", "PW"]) @gz = Zlib::GzipReader.new(@source) @result = @gz.read @doc = Nokogiri::XML(@result) @doc.xpath("/ProductFeed/Vendors/Vendor").each do |manuf| vendor = manuf.css("Name").first.text manuf.xpath("//child::Product").each do |product| product_name = product.css("Name").text foocat = product.css("Category").text puts "#{vendor} ---- #{product_name} ---- #{foocat} " end end This results in: ACME Ltd. ---- Fooproduct ---- Foo Root :: Bar Category Obviously there are line breaks and tab stops or spaces in the string returned by product.css("Category").text. Does anyone know how to strip the result from linebreaks and taps or spaces right here? Alternatively I could do that in the next step, where I do a find on 'foocat' like barcat = Category.find_by_foocat(foocat) Thanks for helping! Val

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  • Using Qt's XML library for simple operation

    - by David Powers
    I basically want to use the XML parser from Qt in my existing project. I have only used Qt once before, and that was with Qt Designer, and I am not having much luck finding anything on Google about how to just use the XML library. I have downloaded a web page that has one large list, and I want to parse it and add each list item to a c++ list. I found this sample code on Ubuntu forums... http://www.uluga.ubuntuforums.org/showpost.php?p=9112973&postcount=6 I want to use that except I need to know what exactly I need to add to the project to get access to it. One other small question is QDomDocument seems to be for files (makes sense) but I have the XML in a string. What part of the XML library works for contents of a string?

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  • Organising XML results as cells in container (AS3)

    - by PJ Palomaki
    Hi, I'm having some problems figuring out how to organise data pulled off XML in cells within a container. I'm sure this should be a basic thing in AS3, but my head's fried.. can anyone help? Basically an array if fed to callThumbs() which iterates through it and compares the entries with preloaded XML _my_images. If match is found, it's sent to processXML which loads all relevant info and loads a .jpg thumbnail. All this is then fed to createCell which creates a specific cell with position values depending on x_counter and y_counter values (4 cells in a row) and adds the cell into a container _container_mc. The Problem: This all works fine and looks fine, the problem is that the cells within the container do not display in descending order. They are in random order, probably because some of the .jpg's takes longer to load etc. How do I easily organise the cells within the container in descending order by the XML .id value? Or how do I tell Flash to wait till the thumbnail and data is loaded and the cell created and added? Thanks guys, would really appreciate all the help! PJ //Flash (AS3) function callThumbs(_my_results:Array):void { // selector = 1 for specific items, 2 for search items var _thumb_url:XML; for (var r:Number=0; r < _my_results.length; r++) { // iterate through results vector, compare with _my_images XML .id for (var i:Number=0; i < _my_images.length(); i++) { if (_my_images[i][email protected]() == _my_results[r]) { _thumb_url=_my_images[i]; processXML(_thumb_url, i); } } } } // End callThumbs function processXML(imageXML:XML, num:Number) { // Processes XML data and loads .jpg thumbnail var _thumb_loader=new Loader(); _thumb_loader.load(new URLRequest("thumbs/thumb_sm/" + imageXML.@id + "_st.jpg")); _thumb_loader.contentLoaderInfo.addEventListener(Event.COMPLETE,thumbLoaded); _thumb_loader.contentLoaderInfo.addEventListener(IOErrorEvent.IO_ERROR, urlNotFound); var id:XMLList = new XMLList; id = imageXML.@id; var description:XMLList = new XMLList; description = imageXML.@description; function urlNotFound(event:IOErrorEvent):void { trace("The image URL '" + String(imageXML.@id) + "' was not found."); } function thumbLoaded(e:Event):void { var imageLoader:Loader = Loader(e.target.loader); var bm:Bitmap = Bitmap(imageLoader.content); createCell(bm, id, description, num); adjustFooterBar(); // Adjust bottom footer } } // End processXML private function createCell(_image:Bitmap, _id, _description:String, _position):void { // Creates a cell with data, add to container var _cell_mc = new CellTitle(); _cell_mc.initCell(_image, _id, _description, _position, x_counter, y_counter); if (x_counter+1 < 4) { x_counter++; } else { x_counter = 0; y_counter++; } _container_mc.addChild(_cell_mc); // movieclip container } // End createCell

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  • Declaring the datatype dynamically reading from an xml string

    - by NLV
    Hello I've this strange issue. I've an xml string which looks like below - <key><int>5</int></key><value><int>10</int> The above xml is obtained after serializing a Dictionary using Paul's Code. Now i want to convert the xml back to the dictionary. How can i get the type "int" from the xml and declare the dictionary as follows? Dictionary<int, int> Any clues?

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  • A simple way (in java) to remove headers from xml files

    - by Andersson Melo
    I need remove non-xml tags from file generated by another program. The file is some like this: Executing Command - Blah.exe ... -----Command Output----- HTTP/1.1 200 OK Connection: close Content-Type: text/xml <?xml version="1.0"?> <testResults> <right>7</right> <wrong>4</wrong> <ignores>0</ignores> <exceptions>0</exceptions> </finalCounts> </testResults> Exit-Code: 15 How to remove the non-xml text easily in java?

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  • Intercepting Xstream conversion while parsing XML

    - by Shane Bell
    Suppose I have a simple Java class like this: public class User { String firstName; String lastName; public String getFirstName() { return firstName; } public void setFirstName(String firstName) { this.firstName = firstName; } public String getLastName() { return lastName; } public void setLastName(String lastName) { this.lastName = lastName; } } Now, suppose I want to parse the following XML: <user> <firstName>Homer</firstName> <lastName>Simpson</lastName> </user> I can do this with no problems in XStream like so: User homer = (User) xstream.fromXML(xml); Ok, all good so far, but here's my problem. Suppose I have the following XML that I want to parse: <user> <fullName>Homer Simpson</fullName> </user> How can I convert this XML into the same User object using XStream? I'd like a way to implement some kind of callback so that when XStream parses the fullName field, I can split the string in two and manually set the first name and last name fields on the user object. Is this possible? Note that I'm not asking how to split the string in two (that's the easy part), I want to know how to intercept the XML parsing so XStream doesn't try to reflectively set the fullName field on the User object (which obviously doesn't exist). I looked at the converters that XStream provides but couldn't figure out how to use it for this purpose. Any help would be appreciated.

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  • CDATA xml parsing extra greater than problem

    - by Ruchir Shah
    Hi, I am creating an xml using php and parsing that xml in iphone application code. In description field there is some html tags and text. I am using following line to convert this html tags in to xml tag using CDATA. $response .= '<desc><![CDATA['.trim($feed['fulltext']).']]></desc>'; Now, here my $feed['fulltext'] value is like this <span class="ABC">...text...</span> In xml I am getting following response, <desc><![CDATA[><span class"ABC">...text...</span>]]></desc> You can see here, I am getting an extra greater-than symbol just before the value of $feed['fulltext'] starts. (like this: ...text...) Any solution or suggestion for this? Thanks in advance. Cheers.

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  • xml and external swf documents

    - by VideoDnd
    My XML scripts work fine in the local swf. If I load an external swf, can I still retreive XML data from the same way, or do I have to declare the root somewhere? It's a general question. I know that when animating external swf files, you have to set it up differently, if so I would like an example, and a pitcher of beer. It's St. Patrick's weekend. SAMPLE CODE ONLY XML <?xml version="1.0" encoding="utf-8"?> <SESSION> <COUNT TITLE="starting position">-77777</COUNT> </SESSION> loader swf 'nodes' //grab the data as a string myString = myXML.COUNT.text(); //grab the data as an int count = int(myXML.COUNT.text()); external swf 'variables' var myString:String = ""; var count:int = int(myString); trace(count);

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  • FOR XML PATH Query results to file with SSIS

    - by whimsql
    In SSMS I've gotten my for xml path query written and it's beautiful. I put it in an "Execute SQL Task" in the Control Flow, set the resultset to XML. Now how to I get the results into an actual xml file that I can turn around and FTP to a third party? This should have been so easy! I would put the XML into a variable but we are looking at a HUGE file, possibly 100mb+ Do I need to use a Script Task? (I'd like to avoid that if there is another option.)

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  • How to parse XML with special characters?

    - by Snooze
    Whenever I try to parse XML with special characters such as o or ???? I get an error. The xml documents claims to use UTF-8 encoding but that does not seem to be the case. Here is what the troublesome text looks like when I view the XML in Firefox: Bleach: The Diamond Dust Rebellion - MÅ? Hitotsu no HyÅ?rinmaru; Bleach - The DiamondDust Rebellion - Mou Hitotsu no Hyourinmaru On the actual website, Å? is actually the character o. <br /> One day, Doraemon and his friends meet Professor Mangetsu (æº?æ??å??ç??, Professor Mangetsu?), who studies magic and magical beings such as goblins, and his daughter Miyoko (ç¾?å¤?å­?, Miyoko?), and are warned of the dangerous approximation of the &quot;star of the Underworld&quot; to the Earth&#039;s orbit.<br /> <br /> And once again, on the actual website, those characters appear as ???? and ???. The actual XML file is formatted properly other than those special characters, which certainly do not appear to be using the UTF-8 encoding. Is there a way to get NSXML to parse these XML files?

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  • How to merge elements from two XML files?

    - by Googler
    Hi all, I need a c# lang code to merge two xml files into one, from the specified content. XML FILE 1 : <exchange-documents> <documentlegal> <bibliographic-data> <applicants> <applicant-name> <name>CENTURY PRODUCTS CO [US]</name> </applicant-name> </applicants> </bibliographic-data> </documentlegal> </exchange-documents> XML FILE 2: <exchange-documents> <documentpatent> <bibliographic-data> <applicants> <applicant-name> <name>CENTURY PRODUCTS CO [US]</name> </applicant-name> </applicants> </bibliographic-data> </documentpatent> </exchange-documents> I need to read the above two xml files and write it into a new xml files with selected elements? OUTPUT XML: <documentlegal> <bibliographic-data> <applicants> <applicant-name> <name>CENTURY PRODUCTS CO [US]</name> </applicant-name> </applicants> </bibliographic-data> </documentlegal> <documentpatent> <bibliographic-data> <applicants> <applicant-name> <name>CENTURY PRODUCTS CO [US]</name> </applicant-name> </applicants> </bibliographic-data> </documentpatent> I dont need the exchnage document element. Can anyone provide me a c# code to achiev the above scenario?

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  • How to write two-dimensional array to xml in Scala 2.8.0

    - by Shadowlands
    The following code (copied from a question from about a year ago) works fine under Scala 2.7.7, but does not behave correctly under Scala 2.8.0 (Beta 1, RC8). import scala.xml class Person(name : String, age : Int) { def toXml(): xml.Elem = <person><name>{ name }</name><age>{ age }</age></person> } def peopleToXml(people: Array[Person]): xml.Elem = { <people>{ for {person <- people} yield person.toXml }</people> } val data = Array(new Person("joe",40), new Person("mary", 35)) println(peopleToXml(data)) The output (according to 2.7.7) should be: <people><person><name>joe</name><age>40</age></person><person><name>mary</name><age>35</age></person></people> but instead comes out as: <people>\[Lscala.xml.Elem;@17821782</people> How do I get this to behave as it did in 2.7.x?

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  • Simple XML parsing with Google Picasa API and JQuery

    - by zeedog
    I'm starting to look into Google's Picasa API for photo data, which provides you with a big XML file with info about albums and photos. I'm doing some quick and dirty tests to parse the XML file (which is saved locally to my hard drive for now) with JQuery and pull out the album id's, which are stored as "gphoto:id" tags, and display them in a div: $(document).ready(function() { $.get( 'albums.xml', function(data) { $(data).find('entry').each(function() { var albumId = $(this).children('gphoto:id').text(); $('#photos').append(albumId + '<br />'); }) }) }) I'm getting the following error in the console: jquery.js:3321 - Uncaught Syntax error, unrecognized expression: Syntax error, unrecognized expression: id This will work with other tags in the XML file (such as title, author, updated, etc.), but I'm trying to understand what's going on here. Does it have to do with the colon in "gphoto:id", somehow?

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  • In php, Prepare string and create XML/RSS Feed

    - by Bill
    I want to create my own RSS/XML feed. I fetch data from the database to display, but keep getting invalid character errors. If the string has an ampersand or other strange characters in it, the XML will be invalid. I tried using urlencode and htmlentities, but these don't capture all possible characters which need to be escaped. Does anyone know of a PHP function which will prepare a string for XML output?

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  • How to display information contained in XML file from another website

    - by Tristan
    Hello, I have an XML file ( XML file I produce ) which contains information about my parteners. I want them to display on their website information relative to them by picking them into the XML file. I have no idea to do that, ecxept that i need to write a 'parser' in javascript to display information. could you please provide me examples to do that ? (how to write a parser, how to display only information for one partener ?) Thank you, Regards

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