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• Core Data migration of to-one relationship to to-many relationship

  - by westsider

  I have a deployed app that samples measurements from sensors (e.g., Temp °C, Pressure kPa). The user can create Experiments and collect samples. Each sample is stored as a Run, such that there is a one-to-many relationship from Experiment to Run. In the interest of performance, Run has a to-one relationship with Data entity (which is where the actual raw data is stored); this allows some Run attributes to be loaded without necessarily loading lots of data. Most of our sensors have multiple measurements, so it would be nice to store all the data that is actually being sampled. But this means that the Run <--- Data relationship needs to become Run <-- Data (to use Xcode's convention). I am faced with trying to migrate data from old Run to-one Data model to new Run to-many Data model. Can this be done using Mapping Models? If so, does anyone have any pointers to examples? If not, does anyone have any pointers to examples of how to do that? Thanks for any pointers or advice.

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• ASP.NET/C# - Deserialize XML, XSD.exe created multiple classes

  - by Barryman9000

  I'm trying to deserialize some XML (returned from a web service) into an object that I created using XSD.exe. The XSD executable created a .CS file with a different partial class for each parent node in the XML. For Example, the beginning of the XML looks like this (why can't I post xml here? sorry, this is ugly): <disclaimer><notificationDescription>Additional charges will apply.</notificationDescription></disclaimer><quote><masterQuote></masterQuote></quote> And the Class generated by the XSD.exe has a partial class named disclaimer with a get; set; string for notificationDescription. And another partial class for quoteMasterQuote with the corresponding child nodes as public strings. How can I deserialize this XML file into multiple classes? I found this code, but it seems like it'll only work for one object. public static PricingResponse2 DeSerialize(string _xml) { PricingResponse2 _resp = new PricingResponse2(); StringReader _strReader = new StringReader(_xml); XmlSerializer _serializer = new XmlSerializer(_resp.GetType()); XmlReader _xmlReader = new XmlTextReader(_strReader); try { _resp = (PricingResponse2)_serializer.Deserialize(_xmlReader); return _resp; } catch (Exception ex) { string _error = ex.Message; throw; } finally { _xmlReader.Close(); _strReader.Close(); _strReader.Dispose(); } } This is the first time I've tried this, so I'm a little lost.

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• Problems with zend-tool reporting that providers are not valid

  - by Mario

  I have recently setup XAMPP 1.7.3 and ZendFramework 1.10.4 on a new computer and many of the commands that I normally use now fail. Here are the steps I used to setup and test ZF. First I added the ZF library folder (C:\xampp\php\ZendFramework-1.10.4\library) to the include path in php.ini. Then I added the ZF bin folder (C:\xampp\php\ZendFramework-1.10.4\bin) to my Path system variable. To test that everything is configured correctly I ran the command "zf show version" from the command line. The result is "Zend Framework Version: 1.9.6". Immediately something appears to be wrong. The file that is downloaded is "ZendFramework-1.10.4.zip" and the reported version is 1.9.6. I have re-downloaded the latest version (1.10.4) and removed old copy. Still the incorrect version number problem persisted. Having done some research there is a bug in the ZF knowledgebase that version 1.10.3 reports a wrong version number. So that may explain the version number problem. Moving forward I tried to run some zf-tool commands and certain commands reports that the action or provider is not valid. Example: C:\xampp\htdocs>zf create project test Creating project at C:/xampp/htdocs/test C:\xampp\htdocs>cd test C:\xampp\htdocs\test>zf create controller Test Creating a controller at C:\xampp\htdocs\test/application/controllers/TestController.php ... Updating project profile 'C:\xampp\htdocs\test/.zfproject.xml' C:\xampp\htdocs\test>zf create action test Test Creating an action named test inside controller at C:\xampp\htdocs\test/application/controllers/TestController.php ... Updating project profile 'C:\xampp\htdocs\test/.zfproject.xml' C:\xampp\htdocs\test>zf enable layout An Error Has Occurred Action 'enable' is not a valid action. ... C:\xampp\htdocs\test>zf create form Test An Error Has Occurred Provider 'form' is not a valid provider. ... Can any one provide insight into these errors and how to correct them?

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• OData / WCF Data Service - HTTP 500 Error

  - by Eric

  I have created an OData/WCF service using Visual Studio 2010 on Windows XP SP3 with all current patches installed. When I click on "view in browser", the service opens and I see the 3 tables from my EF model. However, when I add a table name ("Commands" in this case) to the end of the query string, rather than seeing the data from the table, I get an HTTP 500 error. (This error (HTTP 500 Internal Server Error) means that the website you are visiting had a server problem which prevented the webpage from displaying.). I have not only followed the examples from 2 sites, but have also tried running the sample application that the blog poster sent me (that works on his machine), and still am not having any luck. The blog post is at Exposing OData from an Entity Framework Model Does anyone have an idea why this is occurring and how to resolve it? Here is the output of the "View in Browser": <?xml version="1.0" encoding="utf-8" standalone="yes" ?> - <service xml:base="http://localhost:1883/VistaDBCommandService.svc/" xmlns:atom="http://www.w3.org/2005/Atom" xmlns:app="http://www.w3.org/2007/app" xmlns="http://www.w3.org/2007/app"> - <workspace> <atom:title>Default</atom:title> - <collection href="Commands"> <atom:title>Commands</atom:title> </collection> - <collection href="Databases"> <atom:title>Databases</atom:title> </collection> - <collection href="Statuses"> <atom:title>Statuses</atom:title> </collection> </workspace> </service> ============================= Thanks, Eric

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• Django forms, inheritance and order of form fields

  - by Hannson

  I'm using Django forms in my website and would like to control the order of the fields. Here's how I define my forms: class edit_form(forms.Form): summary = forms.CharField() description = forms.CharField(widget=forms.TextArea) class create_form(edit_form): name = forms.CharField() The name is immutable and should only be listed when the entity is created. I use inheritance to add consistency and DRY principles. What happens which is not erroneous, in fact totally expected, is that the name field is listed last in the view/html but I'd like the name field to be on top of summary and description. I do realize that I could easily fix it by copying summary and description into create_form and loose the inheritance but I'd like to know if this is possible. Why? Imagine you've got 100 fields in edit_form and have to add 10 fields on the top in create_form - copying and maintaining the two forms wouldn't look so sexy then. (This is not my case, I'm just making up an example) So, how can I override this behavior? Edit: Apparently there's no proper way to do this without going through nasty hacks (fiddling with .field attribute). The .field attribute is a SortedDict (one of Django's internal datastructures) which doesn't provide any way to reorder key:value pairs. It does how-ever provide a way to insert items at a given index but that would move the items from the class members and into the constructor. This method would work, but make the code less readable. The only other way I see fit is to modify the framework itself which is less-than-optimal in most situations. In short the code would become something like this: class edit_form(forms.Form): summary = forms.CharField() description = forms.CharField(widget=forms.TextArea) class create_form(edit_form): def __init__(self,*args,**kwargs): forms.Form.__init__(self,*args,**kwargs) self.fields.insert(0,'name',forms.CharField()) That shut me up :)

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• Why can't c# use inline anonymous lambdas or delegates?

  - by Samuel Meacham

  I hope I worded the title of my question appropriately. In c# I can use lambdas (as delegates), or the older delegate syntax to do this: Func<string> fnHello = () => "hello"; Console.WriteLine(fnHello()); Func<string> fnHello2 = delegate() { return "hello 2"; }; Console.WriteLine(fnHello2()); So why can't I "inline" the lambda or the delegate body, and avoid capturing it in a named variable (making it anonymous)? // Inline anonymous lambda not allowed Console.WriteLine( (() => "hello inline lambda")() ); // Inline anonymous delegate not allowed Console.WriteLine( (delegate() { return "hello inline delegate"; })() ); An example that works in javascript (just for comparison) is: alert( (function(){ return "hello inline anonymous function from javascript"; })() ); Which produces the expected alert box. UPDATE: It seems you can have an inline anonymous lambda in C#, if you cast appropriately, but the amount of ()'s starts to make it unruly. // Inline anonymous lambda with appropriate cast IS allowed Console.WriteLine( ((Func<string>)(() => "hello inline anonymous lambda"))() ); Perhaps the compiler can't infer the sig of the anonymous delegate to know which Console.WriteLine() you're trying to call? Does anyone know why this specific cast is required?

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• json-framework: EXC_BAD_ACCESS on stringWithObject

  - by Vegar

  UPDATE: I found that the reason for the previous error was an error in the documentation. The method should be named proxyForJson, not jsonProxyObject... But I'm still stuck, though. I now get an EXC_BAD_ACCESS error inside stringWithObject some where. Any clues? UPDATE 2: My proxyForJson implementation is a cut-n-paste from then documentation: - (id)proxyForJson { return [NSDictionary dictionaryWithObjectsAndKeys: Navn, @"Navn", Adresse, @"Adresse", Alder, @"Alder", nil]; } Trying to make json serialization work for my custom objective-c class. As I understand the documentation, json-framework can serialize custom objects, if they implement the jsonProxyObject method. So I have this class: @interface MyObject : NSObject { NSString *Name; NSString *Addresse; NSInteger Age; } @property (nonatomic, retain) NSString *Name; @property (nonatomic, retain) NSString *Addresse; @property (nonatomic, assign) NSInteger Age; - (id)jsonProxyObject; @end And I try to serialize an array with some instances in it: [json stringWithObject:list error:&error]; But all I get is he following error: "JSON serialisation not supported for MyObject" I guess the jsonWriter can't find my jsonProxyObject method for some reason, buy why? Regards.

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• Problem Binding a ObservableCollection to a ListBox in WPF/MVVM

  - by alexqs

  I'm working in some code , using wpf and starting to use mvvm. So far i have no problem, when i have one element and I have to show the values of it in the screen (binding of the specific name of the property). But now, i have to work with a property list , not knowing the names of it. So I created a class, named GClass, that only have two propierties, name and value. I created the ObservableCollection, and fill for now with direct values, and asign the view (lstview) datacontext with the object i have created. But I cant see any result, it always shows a blank listbox. Can someone tell me if see why is happening ? Code of c# VDt = new ObservableCollection<GClass>(); var vhDt = message.SelectSingleElement(typeof (Vh)) as Vehiculo; if(vhDt != null) { VDt.Add(new GClass() {Name = "Numero: ", Value = ""}); VDt.Add(new GClass() {Name = "Marca: ", Value = ""}); VDt.Add(new GClass() {Name = "Conductor: ", Value = ""}); lstview.DataContext = this; _regionManager.RegisterViewWithRegionInIndex(RegionNames.MainRegion, lstview, 0); Code of the view <ListBox Margin="5,5,5,25" ItemsSource="{Binding VDt}"> <ListBox.Template> <ControlTemplate> <ListViewItem Content="{Binding Name}"></ListViewItem> <ListViewItem Content="{Binding Value}"></ListViewItem> </ControlTemplate> </ListBox.Template> </ListBox> I have research here, but i cant see, what I'm doing wrong. I will apreciate if someone help me.

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• php.ini file creation in server

  - by tibin mathew

  Hi, I am developing a php website. I cant see php.ini file in my server. my host will not provide it. So i'm now going to create a copy of that php.ini file. so i have tried system() i searched in google and i got this link. http://drupal.org/node/290592 Here they are using like this system("cp /usr/local/php5/lib/php.ini /home/YOURUSERNAME/php.ini"); in my server when i looked the phpinfo my php.ini location is /ms/svc/php5/conf/php.ini and when i looked for the current directory of my server using this $dir_path = str_replace( $_SERVER['DOCUMENT_ROOT'], "", dirname(realpath(FILE)) ) . DIRECTORY_SEPARATOR; i got my current directory as /netapp/whnas-swamp/s11/s11/01712/www.sample.com/webdocs/ so my system command will now look lke this system("/ms/svc/php5/conf/php.ini /netapp/whnas-swamp/s11/s11/01712/www.sample.com/webdocs/php.ini"); i have named this page as getthephpini.php and when i b rowse this page i got a blank page but no new php.ini file created in my server. Is any mistake in that code??? Can any one show me the correct way Please help me Thanks

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• Asp.net Webdeployment Project override applicationSettings

  - by citronas

  I got a web deyploment project for a web application project in vs 2008. While building the web deployment project, I want to replace properties in the web.config. My settings are autogenrated by the deisgner. <applicationSettings> <NAMESPACE.Properties.Settings> <setting name="Testenvironment" serializeAs="String"> <value>True</value> </setting> </NAMESPACE.Properties.Settings> </applicationSettings> In the config file which contains the settings for the specific server looks like the following: <?xml version="1.0"?> <applicationSettings> <NAMESPACE.Properties.Settings> <setting name="Testenvironment" serializeAs="String"> <value>False</value> </setting> </NAMESPACE.Properties.Settings> </applicationSettings> Sadly, this does not work. I get an error "The format of a configSource file must be an element containing the name of the section" that highlights the second line (2nd example code). How must the Tag be named in order to make evertything work? Edit: Deleting the "applicationSetting"-Tags does not work either.

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• Reversing Django URLs With Extra Options

  - by Justin Voss

  Suppose I have a URLconf like below, and 'foo' and 'bar' are valid values for page_slug. urlpatterns = patterns('', (r'^page/(?P<page_slug>.*)/', 'myapp.views.someview'), ) Then, I could reconstruct the URLs using the below, right? >>> from django.core.urlresolvers import reverse >>> reverse('myapp.views.someview', kwargs={'page_slug': 'foo'}) '/page/foo/' >>> reverse('myapp.views.someview', kwargs={'page_slug': 'bar'}) '/page/bar/' But what if I change my URLconf to this? urlpatterns = patterns('', (r'^foo-direct/', 'myapp.views.someview', {'page_slug': 'foo'}), (r'^my-bar-page/', 'myapp.views.someview', {'page_slug': 'bar'}), ) I expected this result: >>> from django.core.urlresolvers import reverse >>> reverse('myapp.views.someview', kwargs={'page_slug': 'foo'}) '/foo-direct/' >>> reverse('myapp.views.someview', kwargs={'page_slug': 'bar'}) '/my-bar-page/' However, this throws a NoReverseMatch exception. I suspect I'm trying to do something impossible. Any suggestions on a saner way to accomplish what I want? Named URLs aren't an option, since I don't want other apps that link to these to need to know about the specifics of the URL structure (encapsulation and all that).

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• Backend raising (INotify)PropertyChanged events to all connected clients?

  - by Jörg Battermann

  One of our 'frontend' developers keeps requesting from us backend developers that the backend notifies all connected clients (it's a client/server environment) of changes to objects. As in: whenever one user makes a change, all other connected clients must be notified immediately of the change. At the moment our architecture does not have a notification system of that kind and we don't have a sort of pub/sub model for explicitly chosen objects (e.g. the one the frontend is currently implementing).. which would make sense in such a usecase imho, but obviously requires extra implementation. However, I thought frontends typically check for locks for concurrently existing user changes on the same object and rather pull for changes / load on demand and in the background rather than the backend pushing all changes to all clients for all objects constantly.. which seems rather excessive to me. However, it's being argumented that e.g. the MS Entity Framework does in fact publish (INotify)PropertyChanged not only for local changes, but for all such changes including other client connections, but I have found no proof or details regarding this. Can anyone shed some light into this? Do other e.g. ORMs etc provide broadcasted (INotify)PropertyChanged events on entities?

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• ACL architechture for a Software As a service in Spring 3.0

  - by geoaxis

  I am making a software as a service using Spring 3.0 (Spring MVC, Spring Security, Spring Roo, Hibernate) I have to come up with a flexible access control list mechanism.I have three different kinds of users System (who can do any thing to the system, includes admin and internal daemons) Operations (who can add and delete users, organizations, and do maintenance work on behalf of users and organizations) End Users (they belong to one or more organization, for each organization, the user can have one or more roles, like being organization admin, or organization read-only member) (role like orgadmin can also add users for that organization) Now my question is, how should i model the entity of User? If I just take the End User, it can belong to one or more organizations, so each user can contain a set of references to its organizations. But how do we model the users role for each organization, So for example User UX belongs to organizations og1, og2 and og3, and for og1 he is both orgadmin, and org-read-only-user, where as for og2 he is only orgadmin and for og3 he is only org-read-only-user I have the possibility of making each user belong to one organization alone, but that's making the system bounded and I don't like that idea (although i would still satisfy the requirement) If you have a better extensible ACL architecture, please suggest it. Since its a software as a service, one would expect that alot of different organizations would be part if the same system. I had one concern that it is not a good idea to keep og1 and og2 data on the same DB (if og1 decides to spawn a 100 reports on the system, og2 should not suffer) But that is some thing advanced for now and is not directly related to ACL but to the physical distribution of data and setup of services based on those ACLs This is a community Wiki question, please correct any thing which you wish to do so. Thanks

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• java: <identifier> expected with ArrayList

  - by A-moc

  I have a class named Storage. Storage contains an arraylist of special objects called Products. Each product contains information such as name, price, etc. My code is as follows: class Storage{ Product sprite = new Product("sprite",1.25,30); Product pepsi = new Product("pepsi",1.85,45); Product orange = new Product("orange",2.25,36); Product hershey = new Product("hershey",1.50,33); Product brownie = new Product("brownie",2.30,41); Product apple = new Product("apple",2.00,15); Product crackers = new Product("peanut",3.90,68); Product trailmix = new Product("trailmix",1.90,45); Product icecream = new Product("icecream",1.65,28); Product doughnut = new Product("doughnut",2.75,18); Product banana = new Product("banana",1.25,32); Product coffee = new Product("coffee",1.30,40); Product chips = new Product("chips",1.70,35); ArrayList<Product> arl = new ArrayList<Product>(); //add initial elements to arraylist arl.add(sprite); arl.add(pepsi); arl.add(orange); arl.add(hershey); arl.add(brownie); arl.add(apple); arl.add(peanut); arl.add(trailmix); arl.add(icecream); arl.add(doughnut); arl.add(banana); arl.add(coffee); arl.add(chips); } Whenever I compile, I get an error message on lines 141-153 stating <identifier> expected. I know it's an elementary problem, but I can't seem to figure this out. Any help is much appreciated.

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• Loading Liferay Properties from Spring IoC container (to get jdbc connection parameters)

  - by mox601

  I'm developing some portlets for Liferay Portal 5.2.3 with bundled tomcat 6.0.18 using Spring IoC container. I need to map the User_ table used in Liferay database to an entity with Hibernate, so I need to use two different dataSources to separate the liferay db from the db used by portlets. My jdbc.properties has to hold all connection parameters for both databases: no problem for the one used by portlets, but I am having issues determining which database uses liferay to hold its data. My conclusion is that i should have something like this: liferayConnection.url=jdbc:hsqldb:${liferay.home}/data/hsql/lportal in order to get the database url dynamically loaded, according to Liferay properties found in portal-ext.properties. (Or, better, load the whole portal-ext.properties and read database properties from there). The problem is that the placeholder is not resolved: Caused by: org.springframework.beans.factory.BeanDefinitionStoreException: Invalid bean definition with name 'liferayDataSource' defined in class path resource [WEB-INF/applicationContext.xml]: Could not resolve placeholder 'liferay.home' To dodge this problem I tried to load explicitly portal-ext.properties with a Spring bean: <bean id="liferayPropertiesConfigurer" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer" p:location="../../portal-ext.properties"/> but no luck: liferay.home is not resolved but there aren't other errors. How can I resolve the placeholder defined by Liferay? Thanks

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• Mark duplicates in MySql with php (without deleting)

  - by Adam

  So, I'm having some problems with a MySQL query (see other question), and decided to try a different approach. I have a database table with some duplicate rows, which I actually might need for future reference, so I don't want to remove. What I'm looking for is a way to display the data without those duplicates, but without removing them. I can't use a simple select query (as described in the other question). So what I need to do is write a code that does the following: 1. Go through my db Table. 2. Spot duplicates in the "ip" column. 3. Mark the first instance of each duplicate with "0" (in a column named "duplicate") and the rest with "1". This way I can later SELECT only the rows WHERE duplicate=0. NOTE: If your solution is related to the SELECT query, please read this other question first - there's a reason I'm not just using GROUP BY / DISTINCT. Thanks in advance.

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• Jackson object mapping - map incoming JSON field to protected property in base class

  - by Pete

  We use Jersey/Jackson for our REST application. Incoming JSON strings get mapped to the @Entity objects in the backend by Jackson to be persisted. The problem arises from the base class that we use for all entities. It has a protected id property, which we want to exchange via REST as well so that when we send an object that has dependencies, hibernate will automatically fetch these dependencies by their ids. Howevery, Jackson does not access the setter, even if we override it in the subclass to be public. We also tried using @JsonSetter but to no avail. Probably Jackson just looks at the base class and sees ID is not accessible so it skips setting it... @MappedSuperclass public abstract class AbstractPersistable<PK extends Serializable> implements Persistable<PK> { @Id @GeneratedValue(strategy = GenerationType.AUTO) private PK id; public PK getId() { return id; } protected void setId(final PK id) { this.id = id; } Subclasses: public class A extends AbstractPersistable<Long> { private String name; } public class B extends AbstractPersistable<Long> { private A a; private int value; // getter, setter // make base class setter accessible @Override @JsonSetter("id") public void setId(Long id) { super.setId(id); } } Now if there are some As in our database and we want to create a new B via the REST resource: @POST @Consumes(MediaType.APPLICATION_JSON) @Produces(MediaType.APPLICATION_JSON) @Transactional public Response create(B b) { if (b.getA().getId() == null) cry(); } with a JSON String like this {"a":{"id":"1","name":"foo"},"value":"123"}. The incoming B will have the A reference but without an ID. Is there any way to tell Jackson to either ignore the base class setter or tell it to use the subclass setter instead? I've just found out about @JsonTypeInfo but I'm not sure this is what I need or how to use it. Thanks for any help!

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• MDX equivalent to SQL subqueries with aggregation

  - by James Lampe

  I'm new to MDX and trying to solve the following problem. Investigated calculated members, subselects, scope statements, etc but can't quite get it to do what I want. Let's say I'm trying to come up with the MDX equivalent to the following SQL query: SELECT SUM(netMarketValue) net, SUM(CASE WHEN netMarketValue > 0 THEN netMarketValue ELSE 0 END) assets, SUM(CASE WHEN netMarketValue < 0 THEN netMarketValue ELSE 0 END) liabilities, SUM(ABS(netMarketValue)) gross someEntity1 FROM ( SELECT SUM(marketValue) netMarketValue, someEntity1, someEntity2 FROM <some set of tables> GROUP BY someEntity1, someEntity2) t GROUP BY someEntity1 In other words, I have an account ledger where I hide internal offsetting transactions (within someEntity2), then calculate assets & liabilities after aggregating them by someEntity2. Then I want to see the grand total of those assets & liabilities aggregated by the bigger entity, someEntity1. In my MDX schema I'd presumably have a cube with dimensions for someEntity1 & someEntity2, and marketValue would be my fact table/measure. I suppose i could create another DSV that did what my subquery does (calculating net), and simply create a cube with that as my measure dimension, but I wonder if there is a better way. I'd rather not have 2 cubes (one for these net calculations and another to go to a lower level of granularity for other use cases), since it will be a lot of duplicate info in my database. These will be very large cubes.

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• Problem with non blocking fifo in bash

  - by timdel

  Hi! I'm running a few Team Fortress 2 servers and I want to write a little management script. Basically the TF2 servers are a fg process which provides a server console, so I can start the server, type status and get an answer from it: ***@purple:~/tf2$ ./start_server_testing Auto detecting CPU Using AMD Optimised binary. Server will auto-restart if there is a crash. Console initialized. [bla bla bla] Connection to Steam servers successful. VAC secure mode is activated. status hostname: Team Fortress version : 1.0.6.1/15 3883 secure udp/ip : ***.***.133.31:27600 map : ctf_2fort at: 0 x, 0 y, 0 z players : 0 (2 max) # userid name uniqueid connected ping loss state adr Great, now I want to create a script which sends the command sm_reloadadmins to all my servers. The best way I found to do this is using a fifo named pipe. Now what I want to do is having this pipe readonly and non blocking to the server process, so I can write into the pipe and the server executes it, but still I want to write via console one the server, so if I switch back to the fg process of the server and I type status I want an answer printed. I tried this (assuming serverfifo is mkfifo serverfifo): ./start_server_testing < serverfifo Not working, the server won't start until something is written to the pipe. ./start_server_testing <> serverfifo Thats actually working pretty good, I can see the console output of the server and I can write to the fifo and the server executes the commands, but I can't write via console to the server anymore. Also, if I write 'exit' to the pipe (which should end the server) and I'm running it in a screen the screen window is getting killed for some reason (wtf why?). I only need the server to read the fifo without blocking AND all my keyboard input on the server itself should be send to the server AND all server ouput should be written to the console. Is that possible? If yes, how?

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• Building error in Eclipse with build.xml

  - by Zachary

  I am working on a Java project with Eclipse. This project requires a second project (not mine), named sams in its build-path. The sams is provided with a build.xml file and it should generate some code using Apache CXF when building it. When I use Apache ANT on Eclipse and run the cxf.generated command from its build file I get the following error: Buildfile: C:\Docs\ZacRocha\Desktop\sams\build.xml cxf.generated: [echo] Generating code using Apache CXF wsdl2java... [java] 16-Jun-2010 16:04:08 org.apache.cxf.binding.corba.CorbaConduit prepare [java] SEVERE: Could not resolve target object [java] 16-Jun-2010 16:04:08 org.apache.cxf.binding.corba.CorbaConduit prepare [java] SEVERE: Could not resolve target object [java] WSDLToJava Error: org.apache.cxf.wsdl11.WSDLRuntimeException: Fail to create wsdl definition from : file:/C:/Docs/ZacRocha/Desktop/sams/$%7barchivesoftware.wsdl%7d [java] Caused by : WSDLException: faultCode=PARSER_ERROR: Problem parsing 'file:/C:/Docs/ZacRocha/Desktop/sams/$%7barchivesoftware.wsdl%7d'.: java.io.FileNotFoundException: C:\Docs\ZacRocha\Desktop\sams\${archivesoftware.wsdl} (The system cannot find the file specified) [java] 16-Jun-2010 16:04:10 org.apache.cxf.binding.corba.CorbaConduit prepare [java] SEVERE: Could not resolve target object [java] 16-Jun-2010 16:04:10 org.apache.cxf.binding.corba.CorbaConduit prepare [java] SEVERE: Could not resolve target object [java] WSDLToJava Error: org.apache.cxf.wsdl11.WSDLRuntimeException: Fail to create wsdl definition from : file:/C:/Docs/ZacRocha/Desktop/sams/$%7barchivehardware.wsdl%7d [java] Caused by : WSDLException: faultCode=PARSER_ERROR: Problem parsing 'file:/C:/Docs/ZacRocha/Desktop/sams/$%7barchivehardware.wsdl%7d'.: java.io.FileNotFoundException: C:\Docs\ZacRocha\Desktop\sams\${archivehardware.wsdl} (The system cannot find the file specified) BUILD SUCCESSFUL Total time: 4 seconds I am used to program on Eclipse and I know very little about building with Apache ANT. Can someone tell me where exactly the problem may be? Thanks in advance!

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• WCF, ASMX Basic HTTP binding and IIS

  - by Brennan Mann

  Hello, I have been doing a lot of work with WCF "self" hosted applications. I recently was requested to write a web service where the calling client was a Linux based program named "WGET". I would like to use WCF instead of a traditional ASMX web service. The web service is returning a standard XML response. I am not sure of the underlining details between the two technologies but I know WCF is the proper route. I created a WCF service to be hosted in IIS ( using basicHttpBinding). 1.) Did classic ASMX web services ( standard HTTP POST/GET) use SOAP to return responses? I created an class from XSD for the web service response. What is really going on behind the scenes? Is there just special XML HTTP headers that know how to handle to response? Is the response not wrapped in SOAP? The traditional ASMX web service worked perfectly with the class I generated using the .Net "XSD" program. 2.) I want to use WCF for this service. Will using basicHttpBinding work? As I have read, that is the correct binding to use for ASMX clients. Does this use SOAP, standard HTTP headers, or something else? 3.) This is a dumb question because I have not done a lot of web service programming. I noticed on the ASMX default landing page there were examples for responses and code to invoke the functionality. When I create the same service using WCF, I had to create a client application to perform these tasks. Is there a way to expose the WCF endpoint like a classic ASMX service or is the WSDL the only route? As always, I really appreciate the feedback. Thanks, Brennan

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• Problems with ltk (common lisp)

  - by Silvanus

  I installed ltk to Steel Bank Common Lisp with asdf-install, but I can't even start using it V_V. The code below is the simplest example in the documentation, and is copied almost verbatim. asdf:operate 'asdf:load-op :ltk) (defun hello-1() (with-ltk () (let ((b (make-instance 'button :master nil :text "Press Me" :command (lambda () (format t "Hello World!~&"))))) (pack b)))) (hello-1) This is the error message I get from sbcl: ; in: LAMBDA NIL ; (PACK B) ; ; caught STYLE-WARNING: ; undefined function: PACK ; (WITH-LTK NIL ; (LET ((B (MAKE-INSTANCE 'BUTTON :MASTER NIL :TEXT "Press Me" :COMMAND #))) ; (PACK B))) ; ; caught STYLE-WARNING: ; undefined function: WITH-LTK ; ; compilation unit finished ; Undefined functions: ; PACK WITH-LTK ; caught 2 STYLE-WARNING conditions debugger invoked on a SIMPLE-ERROR in thread #: There is no class named BUTTON. Type HELP for debugger help, or (SB-EXT:QUIT) to exit from SBCL. restarts (invokable by number or by possibly-abbreviated name): 0: [ABORT] Exit debugger, returning to top level. (SB-PCL::FIND-CLASS-FROM-CELL BUTTON NIL T)

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• Scapy Installed, when i use it as module Its full of errors ???

  - by Rami Jarrar

  I installed scapy 2.xx (after get some missed modules to make it install),, then i'm trying to use it as module in my python programs,, but i cant it give me alot of errors, I download and installed some missed modules and finally i'm depressed, because this error, after hard work i got this Traceback (most recent call last): File "<pyshell#0>", line 1, in <module> from scapy.all import * File "C:\Python26\scapy\all.py", line 43, in <module> from crypto.cert import * File "C:\Python26\scapy\crypto\cert.py", line 15, in <module> from Crypto.PublicKey import * File "C:\Python26\lib\Crypto\PublicKey\RSA.py", line 34, in <module> from Crypto import Random File "C:\Python26\lib\Crypto\Random\__init__.py", line 29, in <module> import _UserFriendlyRNG File "C:\Python26\lib\Crypto\Random\_UserFriendlyRNG.py", line 36, in <module> from Crypto.Random.Fortuna import FortunaAccumulator File "C:\Python26\lib\Crypto\Random\Fortuna\FortunaAccumulator.py", line 36, in <module> import FortunaGenerator File "C:\Python26\lib\Crypto\Random\Fortuna\FortunaGenerator.py", line 32, in <module> from Crypto.Util import Counter File "C:\Python26\lib\Crypto\Util\Counter.py", line 27, in <module> import _counter ImportError: No module named _counter by do the following code: from scapy.all import * p=sr1(IP(dst=ip_dst)/ICMP()) if p: p.show() so what should i do,, is there a solution for this ???

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• git branch naming best practices

  - by skiphoppy

  I've been using a local git repository interacting with my group's CVS repository for several months, now. I've made an almost neurotic number of branches, most of which have thankfully merged back into my trunk. But naming is starting to become an issue. If I have a task easily named with a simple label, but I accomplish it in three stages which each include their own branch and merge situation, then I can repeat the branch name each time, but that makes the history a little confusing. If I get more specific in the names, with a separate description for each stage, then the branch names start to get long and unwieldy. I did learn looking through old threads here that I could start naming branches with a / in the name, i.e., topic/task, or something like that. I may start doing that and seeing if it helps keep things better organized. What are some best practices for naming git branches? Edit: Nobody has actually suggested any naming conventions. I do delete branches when I'm done with them. I just happen to have several around due to management constantly adjusting my priorities. :) As an example of why I might need more than one branch on a task, suppose I need to commit the first discrete milestone in the task to the group's CVS repository. At that point, due to my imperfect interaction with CVS, I would perform that commit and then kill that branch. (I've seen too much weirdness interacting with CVS if I try to continue to use the same branch at that point.)

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• Django 1.4.1 error loading MySQLdb module when attempting 'python manage.py shell'

  - by Paul

  I am trying to set up MySQL, and can't seem to be able to enter the Django manage.py shell interpreter. Getting the output below: rrdhcp-10-32-44-126:django pavelfage$ python manage.py shell Traceback (most recent call last): File "manage.py", line 10, in <module> execute_from_command_line(sys.argv) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/__init__.py", line 443, in execute_from_command_line utility.execute() File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/__init__.py", line 382, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/base.py", line 196, in run_from_argv self.execute(*args, **options.__dict__) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/base.py", line 232, in execute output = self.handle(*args, **options) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/base.py", line 371, in handle return self.handle_noargs(**options) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/commands/shell.py", line 45, in handle_noargs from django.db.models.loading import get_models File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/__init__.py", line 40, in <module> backend = load_backend(connection.settings_dict['ENGINE']) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/__init__.py", line 34, in __getattr__ return getattr(connections[DEFAULT_DB_ALIAS], item) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/utils.py", line 92, in __getitem__ backend = load_backend(db['ENGINE']) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/utils.py", line 24, in load_backend return import_module('.base', backend_name) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/utils/importlib.py", line 35, in import_module __import__(name) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/backends/mysql/base.py", line 16, in <module> raise ImproperlyConfigured("Error loading MySQLdb module: %s" % e) django.core.exceptions.ImproperlyConfigured: Error loading MySQLdb module: No module named _mysql Any suggestions really appreciated.

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