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  • PHP: How to find connections between users so I can create a closed friend circle?

    - by CuSS
    Hi all, First of all, I'm not trying to create a social network, facebook is big enough! (comic) I've chosen this question as example because it fits exactly on what I'm trying to do. Imagine that I have in MySQL a users table and a user_connections table with 'friend requests'. If so, it would be something like this: Users Table: userid username 1 John 2 Amalia 3 Stewie 4 Stuart 5 Ron 6 Harry 7 Joseph 8 Tiago 9 Anselmo 10 Maria User Connections Table: userid_request userid_accepted 2 3 7 2 3 4 7 8 5 6 4 5 8 9 4 7 9 10 6 1 10 7 1 2 Now I want to find circles between friends and create a structure array and put that circle on the database (none of the arrays can include the same friends that another has already). Return Example: // First Circle of Friends Circleid => 1 CircleStructure => Array( 1 => 2, 2 => 3, 3 => 4, 4 => 5, 5 => 6, 6 => 1, ) // Second Circle of Friends Circleid => 2 CircleStructure => Array( 7 => 8, 8 => 9, 9 => 10, 10 => 7, ) I'm trying to think of an algorithm to do that, but I think it will take a lot of processing time because it would randomly search the database until it 'closes' a circle. PS: The minimum structure length of a circle is 3 connections and the limit is 100 (so the daemon doesn't search the entire database) EDIT: I've think on something like this: function browse_user($userget='random',$users_history=array()){ $user = user::get($userget); $users_history[] = $user['userid']; $connections = user::connection::getByUser($user['userid']); foreach($connections as $connection){ $userid = ($connection['userid_request']!=$user['userid']) ? $connection['userid_request'] : $connection['userid_accepted']; // Start the circle array if(in_array($userid,$users_history)) return array($user['userid'] => $userid); $res = browse_user($userid, $users_history); if($res!==false){ // Continue the circle array return $res + array($user['userid'] => $userid); } } return false; } while(true){ $res = browse_user(); // Yuppy, friend circle found! if($res!==false){ user::circle::create($res); } // Start from scratch again! } The problem with this function is that it could search the entire database without finding the biggest circle, or the best match.

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  • Deleting huge chunks of data from mysql innodb

    - by mingyeow
    I need to delete a huge chunk of my data in my production database, which runs about 100GB in size. If possible, i would like to minimize my downtime. My selection criteria for deleting is likely to be DELETE * FROM POSTING WHERE USER.ID=5 AND UPDATED_AT<100 What is the best way to delete it? Build an index? Write a sequential script that deletes via paginating through the rows 1000 at a time?

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  • Correlated SQL Join Query from multiple tables

    - by SooDesuNe
    I have two tables like the ones below. I need to find what exchangeRate was in effect at the dateOfPurchase. I've tried some correlated sub queries, but I'm having difficulty getting the correlated record to be used in the sub queries. I expect a solution will need to follow this basic outline: SELECT only the exchangeRates for the applicable countryCode From 1. SELECT the newest exchangeRate less than the dateOfPurchase Fill in the query table with all the fields from 2. and the purchasesTable. My Tables: purchasesTable: > dateOfPurchase | costOfPurchase | countryOfPurchase > 29-March-2010 | 20.00 | EUR > 29-March-2010 | 3000 | JPN > 30-March-2010 | 50.00 | EUR > 30-March-2010 | 3000 | JPN > 30-March-2010 | 2000 | JPN > 31-March-2010 | 100.00 | EUR > 31-March-2010 | 125.00 | EUR > 31-March-2010 | 2000 | JPN > 31-March-2010 | 2400 | JPN costOfPurchase is in whatever the local currency is for a given countryCode exchangeRateTable > effectiveDate | countryCode | exchangeRate > 29-March-2010 | JPN | 90 > 29-March-2010 | EUR | 1.75 > 30-March-2010 | JPN | 92 > 31-March-2010 | JPN | 91 The results of the query that I'm looking for: > dateOfPurchase | costOfPurchase | countryOfPurchase | exchangeRate > 29-March-2010 | 20.00 | EUR | 1.75 > 29-March-2010 | 3000 | JPN | 90 > 30-March-2010 | 50.00 | EUR | 1.75 > 30-March-2010 | 3000 | JPN | 92 > 30-March-2010 | 2000 | JPN | 92 > 31-March-2010 | 100.00 | EUR | 1.75 > 31-March-2010 | 125.00 | EUR | 1.75 > 31-March-2010 | 2000 | JPN | 91 > 31-March-2010 | 2400 | JPN | 91 So for example in the results, the exchange rate, in effect for EUR on 31-March was 1.75. I'm using Access, but a MySQL answer would be fine too. UPDATE: Modification to Allan's answer: SELECT dateOfPurchase, costOfPurchase, countryOfPurchase, exchangeRate FROM purchasesTable p LEFT OUTER JOIN (SELECT e1.exchangeRate, e1.countryCode, e1.effectiveDate, min(e2.effectiveDate) AS enddate FROM exchangeRateTable e1 LEFT OUTER JOIN exchangeRateTable e2 ON e1.effectiveDate < e2.effectiveDate AND e1.countryCode = e2.countryCode GROUP BY e1.exchangeRate, e1.countryCode, e1.effectiveDate) e ON p.dateOfPurchase >= e.effectiveDate AND (p.dateOfPurchase < e.enddate OR e.enddate is null) AND p.countryOfPurchase = e.countryCode I had to make a couple small changes.

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  • PHP analog of mysql like function

    - by DCrystal
    Suppose it's a nub question, but is there an analog of mysql's LIKE function in php? So, e.g. : like('goo*','google.com');//is true like('*gl*','google.com');//true like('google.com','google.com')//also true I know regex rullez, but don't know any solution to reach this

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  • Mysql::Error: Duplicate entry

    - by Shaliko
    Hi I have a model class Gift < ActiveRecord::Base validates_uniqueness_of :giver_id, :scope => :account_id end add_index(:gifts, [:account_id, :giver_id], :uniq => true) Action def create @gift= Gift.new(params[:gift]) if @gift.save ... else ... end end In the "production" mode, I sometimes get an error ActiveRecord::StatementInvalid: Mysql::Error: Duplicate entry '122394471958-50301499' for key 'index_gifts_on_account_id_and_giver_id' What the problem?

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  • Populating fields in modal form using PHP, jQuery

    - by Benjamin
    I have a form that adds links to a database, deletes them, and -- soon -- allows the user to edit details. I am using jQuery and Ajax heavily on this project and would like to keep all control in the same page. In the past, to handle editing something like details about another website (link entry), I would have sent the user to another PHP page with form fields populated with PHP from a MySQL database table. How do I accomplish this using a jQuery UI modal form and calling the details individually for that particular entry? Here is what I have so far- <?php while ($linkDetails = mysql_fetch_assoc($getLinks)) {?> <div class="linkBox ui-corner-all" id="linkID<?php echo $linkDetails['id'];?>"> <div class="linkHeader"><?php echo $linkDetails['title'];?></div> <div class="linkDescription"><p><?php echo $linkDetails['description'];?></p> <p><strong>Link:</strong><br/> <span class="link"><a href="<?php echo $linkDetails['url'];?>" target="_blank"><?php echo $linkDetails['url'];?></a></span></p></div> <p align="right"> <span class="control"> <span class="delete addButton ui-state-default">Delete</span> <span class="edit addButton ui-state-default">Edit</span> </span> </p> </div> <?php }?> And here is the jQuery that I am using to delete entries- $(".delete").click(function() { var parent = $(this).closest('div'); var id = parent.attr('id'); $("#delete-confirm").dialog({ resizable: false, modal: true, title: 'Delete Link?', buttons: { 'Delete': function() { var dataString = 'id='+ id ; $.ajax({ type: "POST", url: "../includes/forms/delete_link.php", data: dataString, cache: false, success: function() { parent.fadeOut('slow'); $("#delete-confirm").dialog('close'); } }); }, Cancel: function() { $(this).dialog('close'); } } }); return false; }); Everything is working just fine, just need to find a solution to edit. Thanks!

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  • DropDownList not updating value

    - by annelie
    Hello, I posted a question earlier but have another problem after making those changes. The previous thread can be found here: http://stackoverflow.com/questions/2700028/binding-a-dropdownlist-inside-a-detailsview Basically, I've got a dropdownlist that's dynamically populated with a list of regions. It selects the correct region when viewing the dropdown, but when I try to edit it changes the value to null. I think it might be because it doesn't know which field to update. Previously, when the dropdown list was hardcoded, I had SelectedValue='<%# Bind("region_id")%' set on the dropdown list, and when I updated it worked fine. However, I had to move the setting of the selected value into the code behind and now it just gets set to null every time I update. Here's the aspx code: <asp:DetailsView id="DetailsView1" runat="server" AutoGenerateRows="false" DataSourceID="myMySqlDataSrc" DataKeyNames="id" AutoGenerateDeleteButton="True" AutoGenerateEditButton="True" AutoGenerateInsertButton="False" OnDataBound="DetailsView1_DataBound" > <Fields> <snip> <asp:TemplateField HeaderText="Region"> <ItemTemplate><%# Eval("region_name") %></ItemTemplate> <EditItemTemplate> <asp:DropDownList ID="RegionDropdownList" runat="server"> </asp:DropDownList> </EditItemTemplate> </asp:TemplateField> </Fields> </asp:DetailsView> And here's the code behind: protected void DetailsView1_DataBound(object sender, EventArgs e) { ArrayList regionsList = BPBusiness.getRegions(); if (DetailsView1.CurrentMode == DetailsViewMode.Edit) { DropDownList ddlRegions = (DropDownList)DetailsView1.FindControl("RegionDropdownList"); if (ddlRegions != null) { ddlRegions.DataSource = regionsList; ddlRegions.DataValueField = "Value"; ddlRegions.DataTextField = "Text"; ddlRegions.DataBind(); if (ddlRegions.Items.Contains(ddlRegions.Items.FindByValue(objBusiness.iRegionID.ToString()))) { ddlRegions.SelectedIndex = ddlRegions.Items.IndexOf(ddlRegions.Items.FindByValue(objBusiness.iRegionID.ToString())); } } } } EDIT: The database is MySql, and the update statement looks like this: myMySqlDataSrc.UpdateCommand = "UPDATE myTable SET business_name = ?, addr_line_1 = ?, addr_line_2 = ?, addr_line_3 = ?, postcode = ?, county = ?, town_city = ?, tl_url = ?, customer_id = ?, region_id = ?, description = ?, approval_status = ?, tl_user_name = ?, phone = ?, uploaders_own = ? WHERE id = ?"; Thanks, Annelie

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  • I have a php form dropdown menu that needs to send information

    - by shinjuo
    I have a dropdown menu that is filled by a mysql database. I need to select one and have it send the information for use on the next page after clicking submit. It does populate the drop down menu like it is supposed to it just does not seem to catch the data on the next page. Here is what I have: removeMain.php <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title></title> </head> <form action="remove.php" method="post"> <?php $link = mysql_connect('********', '********', '*********'); if (!$link){ die('Could not connect: ' . mysql_error()); } mysql_select_db("********", $link); $res = mysql_query("SELECT * FROM cardLists order by cardID") or die(mysql_error()); echo "<select name = CardID>"; while($row=mysql_fetch_assoc($res)) { echo "<option value=$row[ID]>$row[cardID]</a></option>"; } echo "</select>"; ?> Amount to Remove: <input type="text" name="Remove" /> <input type="submit" /> </form> <body> </body> </html> remove.php <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title></title> </head> <body> <?php $link = mysql_connect('*********', '*********', '*********'); if (!$link){ die('Could not connect: ' . mysql_error()); } mysql_select_db("***********y", $link); $query = sprintf("UPDATE cardLists SET AmountLeft = AmountLeft - %s WHERE cardID = '%s'", mysql_real_escape_string($_POST["Remove"]), mysql_real_escape_string($_POST["CardID"])); mysql_query($query); mysql_close($link); ?> <br /> <a href="removeMain.php"> <input type="submit" name="return" id="return" value="Update More" /></a> <a href="index.php"> <input type="submit" name="main" id="main" value="Return To Main" /></a> </body> </html>

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  • Yii - Custom GridView with Multiple Tables

    - by savinger
    So, I've extended GridView to include an Advanced Search feature tailored to the needs of my organization. Filter - lets you show/hide columns in the table, and you can also reorder columns by dragging the little drag icon to the left of each item. Sort - Allows for the selection of multiple columns, specify Ascending or Descending. Search - Select your column and insert search parameters. Operators tailored to data type of selected column. Version 1 works, albeit slowly. Basically, I had my hands in the inner workings of CGridView, where I snatch the results from the DataProvider and do the searching and sorting in PHP before rendering the table contents. Now writing Version 2, where I aim to focus on clever CDbCriteria creation, allowing MySQL to do the heavy lifting so it will run quicker. The implementation is trivial when dealing with a single database table. The difficulty arises when I'm dealing with 2 or more tables... For example, if the user intends to search on a field that is a STAT relation, I need that relation to be present in my query. Here's the question. How do I assure that Yii includes all with relations in my query so that I include comparisons? I've included all my relations with my criteria in the model's search function and I've tried CDbCriteria's together ... public function search() { $criteria=new CDbCriteria; $criteria->compare('id', $this->id); $criteria->compare( ... ... $criteria->with = array('relation1','relation2','relation3'); $criteria->together = true; return new CActiveDataProvider( get_class($this), array( 'criteria'=>$criteria, 'pagination' => array('pageSize' => 50) ));} But I still get errors like this... CDbCommand failed to execute the SQL statement: SQLSTATE[42S22]: Column not found: 1054 Unknown column 't.relation3' in 'where clause'. The SQL statement executed was: SELECT COUNT(DISTINCT `t`.`id`) FROM `table` `t` LEFT OUTER JOIN `relation_table` `relation0` ON (`t`.`id`=`relation0`.`id`) LEFT OUTER JOIN `relation_table` `relation1` ON (`t`.`id`=`relation1`.`id`) WHERE (`t`.`relation3` < 1234567890) Where relation0 and relation1 are BELONGS_TO relations, but any STAT relations are missing. Furthermore, why is the query a SELECT COUNT(DISTINCT 't'.'id') ?

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  • Problem with PHP 'PHP_SELF'

    - by shinjuo
    I am having a bit of trouble. It does not seem to be a big deal, but I have created a page that the user can edit a MySQL database. Once they click submit it should process the php within the if statement and echo 1 record updated. The problem is that it does not wait to echo the statement. It just seems to ignore the way I wrote my if and display the whole page. Can anyone see where I went wrong. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title></title> </head> <body> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <?php require("serverInfo.php"); ?> <?php $res = mysql_query("SELECT * FROM cardLists order by cardID") or die(mysql_error()); echo "<select name = 'Cards'>"; while($row=mysql_fetch_assoc($res)) { echo "<option value=\"$row[cardID]\">$row[cardID]</option>"; } echo "</select>"; ?> Amount to Add: <input type="text" name="Add" /> <input type="submit" /> </form> <?php if(isset($_POST['submit'])); { require("serverInfo.php"); mysql_query("UPDATE `cardLists` SET `AmountLeft` = `AmountLeft` + ".mysql_real_escape_string($_POST['Add'])." WHERE `cardID` = '".mysql_real_escape_string($_POST['Cards'])."'"); mysql_close($link); echo "1 record Updated"; } ?> <br /> <a href="index.php"> <input type="submit" name="main" id="main" value="Return To Main" /></a> </body> </html>

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  • Explanation of converting exporting an XML document as a relational database using XSLT

    - by Yaaqov
    I would like to better understand the basic steps needed to a take an XML document like this Breakfast Menu... <?xml version="1.0" encoding="ISO-8859-1"?> <breakfast_menu> <food> <name>Belgian Waffles</name> <price>$5.95</price> <description>two of our famous Belgian Waffles with plenty of real maple syrup</description> <calories>650</calories> </food> <food> <name>Strawberry Belgian Waffles</name> <price>$7.95</price> <description>light Belgian waffles covered with strawberries and whipped cream</description> <calories>900</calories> </food> <food> <name>Berry-Berry Belgian Waffles</name> <price>$8.95</price> <description>light Belgian waffles covered with an assortment of fresh berries and whipped cream</description> <calories>900</calories> </food> <food> <name>French Toast</name> <price>$4.50</price> <description>thick slices made from our homemade sourdough bread</description> <calories>600</calories> </food> <food> <name>Homestyle Breakfast</name> <price>$6.95</price> <description>two eggs, bacon or sausage, toast, and our ever-popular hash browns</description> <calories>950</calories> </food> </breakfast_menu> And "export" it to say, an Access or MySQL database using XSLT, creating two joined tables: Table: breakfast_menu Field: menu_item_id Field: food_id Table: food Field: food_id Field: name Field: price Field: description Field: calories If there are online tutorials on this that you know of, I'd be interesting in learning more, as well. Thanks.

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  • How to make a Multilanguage website in php and Mysql

    - by user295239
    Hello to All Group Members. Can any body tell me how i make a dynamic multilanguage website in php and mysql.I have no idea abt it.I search on google and do not find good solution. Any one tell me step by step guide if possible made a demo for multilanguage website. Or please refer me any link where tell the detail abt it.How i do it. Thanks in Advance. Highly Appreciated. Best Regard Hasnat

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  • Best Practice : Import CSV to MYSQL Database using PHP 5.x

    - by ArneRie
    Howdy Folks, what is the best solution to import large amounts of records into an MySQL or Oracle Database. I Think there are two ways : Insert every record with an persistent connection Create on BIG SQL-Statement and query the Database Iam not sure wich is performing better ? Is there any Best Practice Solutions for this kind of operation ??

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  • how can I get data in the table cell that is checked after submit

    - by arnold
    can someone give me help, please. here's my basic html <form action="addSomething.php" method="POST"> <table> <tr> <th>Add Data</th> <th>Description</th> <th>Quantity</th> </tr> <tr> <td><input type="checkbox" name="data[]" value="sample1" /> </td> <td class="desc">Newbie</td> <td>2</td> </tr> <tr> <td><input type="checkbox" name="data[]" value="sample1" /> </td> <td class="desc">Pro</td> <td>1</td> </tr> <tr> <td><input type="checkbox" name="data[]" value="sample1"/> </td> <td class="desc" > Master </td> <td>1</td> </tr> <br/> <input type="submit" name="add" value="SUBMIT"/> ..... how can I get the one with the class "desc" and the column for quantity that is checked after submitting the form because the only I can add when querying in mysql is the value of checkbox but I want also the value of the data in "Description" column and "Quantity" column In my addSomething.php the code I have is if(isset($_POST['add'])) { foreach($_POST['data'] as $value) { $sql = "INSERT INTO tablename (column1) VALUES('$value');" //query stuff } } what I will do , Any hints guys?

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  • mysql_connect() causes page to not display (WAMP)

    - by VOIDHand
    I currently have a website running MySQL and PHP in which this is all working. I've tried installing WAMPServer to be able to work on the site on my own computer, but I have been having issues trying to get the site to work correctly. HTML and PHP files work correctly (by going to http://localhost/index.php, etc.). But some of the pages display "This Webpage is not available" (in Chrome) or "Internet Explorer cannot display this webpage", which leads me to think there is an error is the server, as when the page doesn't exist, it typically dispays "Oops! This link appears to be broken" or IE's standard 404 page. Each page in my site has an include() call to set up an instance of a class to handle all database transactions. This class opens the connection to the database in its constructor. I have found commenting out the contents of the constructor will allow the page to load, although this understandably causes errors later in the page. This is the contents of the included file: class dbAccess { private $db; function __construct() { $this->db = mysql_connect("externalURL","user","password") or die ("Connection for database not found."); mysql_select_db("dbName", $this->db) or die ("Database not selected"); } ... } As a note for what's happening here. I'm attempting to use the database on my site, rather than the local machine. The actual values of externalURL, dbName, user, and password work when I plug them into my database software and the file fine of the site, so I don't think the issue is with those values themselves, but rather some setting with Apache or Wamp. The issue persists if I try a local database as well. This is an excerpt of my Apache error log for one attempt at logging into the site: [Wed Apr 14 15:32:54 2010] [notice] Parent: child process exited with status 255 -- Restarting. [Wed Apr 14 15:32:54 2010] [notice] Apache/2.2.11 (Win32) PHP/5.3.0 configured -- resuming normal operations [Wed Apr 14 15:32:54 2010] [notice] Server built: Dec 10 2008 00:10:06 [Wed Apr 14 15:32:54 2010] [notice] Parent: Created child process 1756 [Wed Apr 14 15:32:55 2010] [notice] Child 1756: Child process is running [Wed Apr 14 15:32:55 2010] [notice] Child 1756: Acquired the start mutex. [Wed Apr 14 15:32:55 2010] [notice] Child 1756: Starting 64 worker threads. [Wed Apr 14 15:32:55 2010] [notice] Child 1756: Starting thread to listen on port 80. For the first line, isLoggedIn (from the first line) is a method of the class above. Assuming that the connection works, this error should disappear. I've tried searching for solutions online, but haven't been able to find anything to help. If you need any further information to help solve this issue, feel free to ask for it. (One more note, I don't even have Skype on this computer, so I can't see it being an issue, as this conflict seems to be the default response for any Wamp issue.) [Edit: Removed entry from the error log as it was solved as an unrelated issue]

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  • SQL (MySQL) vs NoSQL (CouchDB)

    - by christopher-mccann
    I am in the middle of designing a highly-scalable application which must store a lot of data. Just for example it will store lots about users and then things like a lot of their messages, comments etc. I have always used MySQL before but now I am minded to try something new like couchdb or similar which is not SQL. Does anyone have any thoughts or guidance on this?

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  • Stumbleupon type query...

    - by Chris Denman
    Wow, makes your head spin! I am about to start a project, and although my mySql is OK, I can't get my head around what required for this: I have a table of web addresses. id,url 1,http://www.url1.com 2,http://www.url2.com 3,http://www.url3.com 4,http://www.url4.com I have a table of users. id,name 1,fred bloggs 2,john bloggs 3,amy bloggs I have a table of categories. id,name 1,science 2,tech 3,adult 4,stackoverflow I have a table of categories the user likes as numerical ref relating to the category unique ref. For example: user,category 1,4 1,6 1,7 1,10 2,3 2,4 3,5 . . . I have a table of scores relating to each website address. When a user visits one of these sites and says they like it, it's stored like so: url_ref,category 4,2 4,3 4,6 4,2 4,3 5,2 5,3 . . . So based on the above data, URL 4 would score (in it's own right) as follows: 2=2 3=2 6=1 What I was hoping to do was pick out a random URL from over 2,000,000 records based on the current users interests. So if the logged in user likes categories 1,2,3 then I would like to ORDER BY a score generated based on their interest. If the logged in user likes categories 2 3 and 6 then the total score would be 5. However, if the current logged in user only like categories 2 and 6, the URL score would be 3. So the order by would be in context of the logged in users interests. Think of stumbleupon. I was thinking of using a set of VIEWS to help with sub queries. I'm guessing that all 2,000,000 records will need to be looked at and based on the id of the url it will look to see what scores it has based on each selected category of the current user. So we need to know the user ID and this gets passed into the query as a constant from the start. Ain't got a clue! Chris Denman

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  • string categorization strategies

    - by Andrew Heath
    I'm the one-man dev team on a fledgling military history website. One aspect of the site is a catalog of ~1,200 individual battles, including the nations & formations (regiments, divisions, etc) which took part. The formation information (as well as the other battle info) was manually imported from a series of books by a 10-man volunteer team. The formations were listed in groups with varying formatting and abbreviation patterns. At the time I set up the data collection forms I couldn't think of a good way to process that data... and elected to store it all as strings in the MySQL database and sort it out later. Well, "later" - as it tends to happen - has arrived. :-) Each battle has 2+ records in the database - one for each nation that participated. Each record has a formations text string listing the formations present as the volunteer chose to add them. Some real examples: 39th Grenadier Rgmt, 26th Volksgrenadier Division 2nd Luftwaffe Field Division, 246th Infantry Division 247th Rifle Division, 255th Tank Brigade 2nd Luftwaffe Field Division, SS Cavalry Division 28th Tank Brigade, 158th Rifle Division, 135th Rifle Division, 81st Tank Brigade, 242nd Tank Brigade 78th Infantry Division 3rd Kure Special Naval Landing Force, Tulagi Seaplane Base personnel 1st Battalion 505th Infantry Regiment The ultimate goal is for each individual force to have an ID, so that its participation can be traced throughout the battle database. Formation hierarchy, such as the final item above 1st Battalion (of the) 505th Infantry Regiment also needs to be preserved. In that case, 1st Battalion and 505th Infantry Regiment would be split, but 1st Battalion would be flagged as belonging to the 505th. In database terms, I think I want to pull the formation field out of the current battle info table and create three new tables: FORMATION [id] [name] FORMATION_HIERARCHY [id] [parent] [child] FORMATION_BATTLE [f_id] [battle_id] It's simple to explain, but complicated to enact. What I'm looking for from the SO community is just some tips on how best to tackle this problem. Ideally there's some sort of method to solving this that I'm not aware of. However, as a last resort, I could always code a classification framework and call my volunteers back to sort through 2,500+ records...

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  • Drupal, Faceted Search: mysql privilegies

    - by Patrick
    hi, I was considering to use Faceted Search for my Drupal website but I noticed I have to set additional database privilegies. (And I usually don't have access to mysql terminal on the hosting servers. http://drupalcode.org/viewvc/drupal/contributions/modules/faceted_search/README.txt?view=co Consequently, I cannot use Faceted Search on these servers.... thanks

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  • Normalization of database for timesheet tool and ensure data integrity

    - by fireeyedboy
    I'm creating a timesheet application. I have the following entities (amongst others): Company Employee = an employee associated with a company Client = a client associated with a company So far I have the following (abbreviated) database setup: Company - id - name Employee - id - companyId (FK to Company.id) - name Client - id - companyId (FK to Company.id) - name Now, I want an employee to be associated with a client, but only if that client is associated with the company the employee works for. How would you guarantee this data integrity on a database level? Or should I just depend on the application to guarantee this data integrity? I thought about creating a many to many table like this: EmployeeClient - employeeId (FK to Employee.id) - companyId \ (combined FK to Client.companyId, Client.id) - clientId / Thus, when I insert a client for an employee along with the employee's company id, the database should prevent this when the client is not associated with the employee's company id. Does this make sense? Because this still doesn't guarantee the employee is associated with the company. How do you deal with these things? UPDATE The scenario is as followed: A company has multiple employees. Employees will only be linked to one company. A company has multiple clients also. Clients will only be linked to one company. (Company is a sandbox, so to speak). An employee of a company can be linked to a client of it's company, but only if the client is part of the company's clientele. In other words: The application will allow a company to create/add employees and create/add clients (hence the companyId FK in the Employee and Client tables). Next, the company will be allowed to assign certain clients to certain of it's employees (EmployeeClient table). Imagine an employee working on projects for a few clients for which s/he can write billable hours, but the employee must not be allowed to write billable hours for clients they are not assigned to by their employer (the company). So, employees will not automatically have access to all their company's clients, but only to those that the company has selected for them. Hopefully this has shed some more light on the matter.

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