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  • PHP radio button check if null

    - by Dallox
    So in class we get this school task where we need to check if one of the fields in unfilled and display an error. No we did this but for some strange reason it doesnt display a error when a radio button is unchecked. (textfield null check works fine) I've tried with a friend many possabilities but they all doesnt seem to work. We have been stuck at this task for 2 hours. Now we have tried making seperate if's but that doesnt seem to work too. These are the important parts: <p> <input type="hidden" name="taal" value="false"> Choose a language <input type="radio" name="taal" value="N"> Dutch <input type="radio" name="taal" value="E"> English <input type="radio" name="taal" value="S"> Spanish if (@$_POST['taal'] == null){ echo "No Language gotten"; return; }

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  • Get Form Input via Ajax

    - by user3651491
    I have a jqgrid plugin which I call via Ajax. I have index.php and a getGridData.php. How will I pass form input in getGridData.php via ajax and use it in getGridData.php? I tried serialize but I can't pass or access it on getGridData.php. I need it as parameters for mysql. Here's my code. <script language="javascript" type="text/javascript"> function jgGrid() { $(document).ready(function () { $("#grid").jqGrid({ url: "inc/Controller/getGridData.php"+$("#thisForm").serialize(), data : formData, datatype: "json", mtype: "POST", colNames: ["SiteID", "TerminalID", "TransactionType", "Amount", "ServiceStatus"], colModel: [ { name: "SiteID"}, { name: "TerminalID"}, { name: "TransactionType"}, { name: "Amount"}, { name: "ServiceStatus"}, ], pager: "#pager", rowNum: 10, rowList: [10,20], sortname: "SiteID", sortorder: "asc", height: 'auto', viewrecords: true, gridview: true, caption: "" }); }); } </script> getGridData.php include('../Model/Queries.php'); $cardnumber = $_POST['cardnumber']; $transact_type = $_POST['transact_type']; $fromdate = $_POST['fromdate']; $todate = $_POST['todate']; $loyalty = new Queries(); $get_mid = $loyalty->loyaltyConn($cardnumber); $somedata = json_encode($loyalty->nposConn($get_mid, $transact_type, $fromdate, $todate)); echo $somedata;

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  • filter by atributs php script

    - by cosy
    I have the table : id id_products id_atribut name value 1 13 8 autdio 2.1 2 13 9 hdd 200 Gb 3 13 10 cd-rom 2 4 20 8 audio 2.1 the problem is, how can i select from this table where id_products=13 and name="audio" and value="2.1" and name="hdd" and value="200 gb" .... How can i do this?

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  • sqlalchemy natural sorting

    - by teggy
    Currently, i am querying with this code: meta.Session.query(Label).order_by(Label.name).all() and it returns me objects sorted by Label.name in this manner ['1','7','1a','5c']. Is there a way i can have the objects returned in the order with their Label.name sorted like this ['1','1a','5c','7'] Thanks!

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  • MySQL Multiple Table Join

    - by hitman001
    I have a 3 tables that I'm trying to join and get distinct results. CREATE TABLE `car` ( `id` int(10) unsigned NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL DEFAULT '', PRIMARY KEY (`id`) ) ENGINE=InnoDB mysql> select * from car; +----+-------+ | id | name | +----+-------+ | 1 | acura | +----+-------+ CREATE TABLE `tires` ( `id` int(10) unsigned NOT NULL AUTO_INCREMENT, `tire_desc` varchar(255) DEFAULT NULL, `car_id` int(10) unsigned NOT NULL, PRIMARY KEY (`id`), KEY `new_fk_constraint` (`car_id`), CONSTRAINT `new_fk_constraint` FOREIGN KEY (`car_id`) REFERENCES `car` (`id`) ON DELETE CASCADE ON UPDATE CASCADE ) ENGINE=InnoDB mysql> select * from tires; +----+-------------+--------+ | id | tire_desc | car_id | +----+-------------+--------+ | 1 | front_right | 1 | | 2 | front_left | 1 | +----+-------------+--------+ CREATE TABLE `lights` ( `id` int(10) unsigned NOT NULL AUTO_INCREMENT, `lights_desc` varchar(255) NOT NULL, `car_id` int(10) unsigned NOT NULL, PRIMARY KEY (`id`), KEY `new1_fk_constraint` (`car_id`), CONSTRAINT `new1_fk_constraint` FOREIGN KEY (`car_id`) REFERENCES `car` (`id`) ON DELETE CASCADE ON UPDATE CASCADE ) ENGINE=InnoDB mysql> select * from lights; +----+-------------+--------+ | id | lights_desc | car_id | +----+-------------+--------+ | 1 | right_light | 1 | | 2 | left_light | 1 | +----+-------------+--------+ Here is my query. mysql> SELECT name, group_concat(tire_desc), group_concat(lights_desc) FROM car left join tires on car.id = tires.car_id left join lights on car.id = car_id group by car.id; +-------+-----------------------------------------------+-----------------------------------------------+ | name | group_concat(tire_desc) | group_concat(lights_desc) | +-------+-----------------------------------------------+-----------------------------------------------+ | acura | front_right,front_right,front_left,front_left | right_light,left_light,right_light,left_light | +-------+-----------------------------------------------+-----------------------------------------------+ I get duplicate entires and this is what I would like to get. +-------+-----------------------------------------------+--------------------------------+ | name | group_concat(tire_desc) | group_concat(lights_desc) | +-------+-----------------------------------------------+--------------------------------+ | acura | front_right,front_left | right_light,left_light | +-------+-----------------------------------------------+--------------------------------+ I cannot use distinct in group_concat because I might have legitimate duplicates which I would like to keep. Is there any way to do this query using joins and not using inner selects like the statement below? SELECT name, (select group_concat(tire_desc) from tires where car.id = tires.car_id), (select group_concat(lights_desc) from lights where car.id = lights.car_id) FROM car Also, if I will use inner selects, will there be any performance issues over joins?

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  • jQuery Load MySQL Fetch Array

    - by Robert Hanson
    I'm a beginner in jQuery area and I have simple question like this : I want to load (AJAX) MySQL result in array, let's say : $row[0] = first name $row[1] = last name $row[2] = phone number I have no problem with PHP part, but I have difficulties to display each of that array content on different id. because syntax I found loads everything processed by PHP : <script type="text/javascript"> $(document).ready(function(){ $('#mysql-result').load('ajax.php'); }); </script> how to get 'First Name', 'Last Name' and 'Phone Number' from PHP with only one time load and still I can put the result in different . thank you.

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  • Why Enumerable doesn't inherits from IEnumerable<T>

    - by sajjadlove
    Hi All I'm very confused about this issue and can't to underestand it.In the Enumerable Documentation, I readed this: that implement System.Collections.Generic.IEnumerable and some methods like Select() return IEnumerable that we can use from other methods like Where() after using that.for example: names.Select(name => name).Where(name => name.Length > 3 ); but Enumerable doesn't inherits from IEnumerable and IEnumerable doesn't contain Select(),Where() and etc too... have i wrong ? or exists any reason for this?

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  • How to insert item which type is QString to a ComboBox in Qt?

    - by Hanny
    I have an item which type is QString: for example: QString name="Name" the question is: How can I put this name variable into a combobox? I've read the Qt 4.6.2 docs but still cant figure out how to do that. Please dont refer me back to that Qt 4.6.2 docs again.. Please help me ASAP!! this is really urgent! thank you very much!! :)

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  • Get URL parameter function that gets value of url part or returns true if it's there but with no val

    - by LLer
    I'm using the following function to get a URL parameter. function gup(name, url) { name = name.replace(/[\[]/, '\\\[').replace(/[\]]/, '\\\]'); var results = new RegExp('[\\?&]'+name+'=?([^&#]*)').exec(url || window.location.href); return results == null ? null : results[1]; } It works only if the parameter has a value, for example. gup('a', 'http://example.com/page.php?a=1&b=2'); will return 1. But if I try gup('a', 'http://example.com/page.php?a&b=2'); It returns null. I want it to return true because parameter "a" exists in that url, even though it has no value it's still there and gup() should return true. Could I get a bit of help rewriting this? I'm not that good with regex.

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  • $_FILES empty on image upload

    - by zvir
    i need help, i'm programing some kind of catalogue and i have a page where clients can upload their logo or images. every page i make is included in index.php and my url looks like something like this www.url.com/index.php?s=upload where "upload" is name of upload.php file. when i create form on that upload.php file and submit it, $_FILES array is empty. echo "<form method=\"post\" enctype=\"multipart/form-data\" action=\"index.php\" />\n"; echo "<input type=\"file\" name=\"image\">\n"; echo "<input type=\"hidden\" name=\"s\" value=\"upload\">\n"; echo "<input type=\"submit\" name=\"submit\" value=\"Spremi\">\n"; echo "</form>\n"; i tried everything and nothing works. $_POST items are returned but $_FILES are empty...

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  • Cant update table in using isset

    - by Ali Munandar
    I have a table called settings, when I would change or enter data into the form it did not change the data in the table. In addition on form an image upload file is not running, There may be the wrong code below. <div class="maintitle">Site Settings</div> <?php $act=isset($_GET['act'])?$_GET['act']:""; if($act=='sub'){ $name=isset($_POST['site'])?$_POST['site']:""; $keys=isset($_POST['keywords'])?$_POST['keywords']:""; $desc=isset($_POST['descrp'])?$_POST['descrp']:""; $email=isset($_POST['email'])?$_POST['email']:""; $fbpage=isset($_POST['fbpage'])?$_POST['fbpage']:""; $twitter=isset($_POST['twitter'])?$_POST['twitter']:""; $gplus=isset($_POST['gplus'])?$_POST['gplus']:""; $disclaimer=isset($_POST['disclaimer'])?$_POST['disclaimer']:""; $template=isset($_POST['template'])?$_POST['template']:""; mysql_query("UPDATE settings SET site='$name',keywords='$keys',descrp='$desc',email='$email',fbpage='$fbpage',twitter='$twitter',gplus='$gplus',disclaimer='$disclaimer',template='$template' WHERE id=1"); if($_FILES["file"]["name"]!=''){ move_uploaded_file($_FILES["file"]["tmp_name"], "../images/logo.png"); }?> <div class="infomsgbox">Settings updated successfully.</div> <?php } $q=mysql_query("select * from settings where id=1"); $s=mysql_fetch_assoc($q); ?> <div class="box"> <div class="inbox"> <!--form--> <form action="index.php?act=sub" method="post" enctype="multipart/form-data"> <label class="artlbl">Site Name</label> <div class="formdiv"> <input type="text" name='site' value='<?php echo $s['name']?>'/> </div> <label class="artlbl">Logo (264px x 85px)</label> <div class="formdiv"> <input type='file' class="file" name='file'/> </div> <div class="clear"></div> <label class="artlbl">Meta Keywords (Separated by Commas)</label> <div class="formdiv"> <textarea name='keywords' cols=40 rows=5 ><?php echo $s['keywords']?></textarea> </div> <label class="artlbl">Meta Description</label> <div class="formdiv"> <textarea name='descrp' cols=40 rows=5 ><?php echo $s['descrp']?></textarea> </div> <label class="artlbl">Email</label> <div class="formdiv"> <input type="text" name='email' value='<?php echo $s['email']?>'/> </div> <label class="artlbl">Facebook Fan Page</label> <div class="formdiv"> <input type="text" name='fbpage' value='<?php echo $s['fbpage']?>'/> </div> <label class="artlbl">Twitter URL</label> <div class="formdiv"> <input type="text" name='twitter' value='<?php echo $s['twitter']?>'/> </div> <label class="artlbl">Google+ URL</label> <div class="formdiv"> <input type="text" name='gplus' value='<?php echo $s['gplus']?>'/> </div> <label class="artlbl">Site Disclaimer</label> <div class="formdiv"> <textarea name='disclaimer' cols=40 rows=5 ><?php echo $s['disclaimer']?></textarea> </div> <label class="artlbl">Template</label> <div class="formdiv"> <select name="template" id="template"> <option value="<?php echo $s['template'];?>"><?php echo ucfirst($s['template']);?></option> <?php foreach(glob('../templates/*', GLOB_ONLYDIR) as $dir) { $TemplateDir = substr($dir, 13); $TemplateName = ucfirst($TemplateDir) ?> <option value="<?php echo $TemplateDir;?>"><?php echo $TemplateName;?></option> <?php }?> </select> </div> <div class="clear"></div> </br> <div class="formdiv"> <div class="sbutton"><input type="submit" id="submit" value="Update Site Settings"/></div> </div> </form> </div> </div><!--box--> Maybe someone can help me Related to this.

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  • TextAppearance_Holo_Large - No resource found

    - by npmaster
    When compiling my app I get the following error: android-apt-compiler: ... \res\values-v14\styles.xml:12: error: Error retrieving parent for item: No resource found that matches the given name '@android:style/TextAppearance_Holo_Large. The code it is complaining about is: <style name="Title" parent="@android:style/TextAppearance_Holo_Large"> <item name="android:layout_height">wrap_content</item> <item name="android:layout_width">wrap_content</item> </style> I checked my manifest file and I have set the SDK to: <uses-sdk android:minSdkVersion="14" android:targetSdkVersion="17" /> Which i believe allows for using the Holo Themes. I am using Android Studio though I doubt that is the cause of the error. Any ideas what I am doing wrong?

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  • How to get a specific attribute from an object list?

    - by anarhikos
    I've an array keeping a list of Group objects. I want to set this list to the DropDownChoice component. However I want to show the end user only the name attribute of Group objects, and then get the selected values' id attribute to add database. What to do? private List<Group> groupTypes; DatabaseApp db = new DatabaseApp(); groupTypes = db.getGroups(); groupDropDownChoice = new DropDownChoice("type", groupTypes); ... ... addUserForm.add(new Button("submit"){ @Override public void onSubmit(){ Group group = (Group) groupDropDownChoice.getModelObject(); ... ... db.addUser(group.getId(), den, name, login, email, password1); DatabaseApp.java public List<Group> getGroups() throws SQLException{ List<Group> groups = new ArrayList<Group>(); try { String query = "SELECT * FROM [GROUP]"; Statement statement = db.createStatement(); ResultSet result = statement.executeQuery(query); while(result.next()){ int id = result.getInt("ID"); String name = result.getString("NAME"); groups.add(new Group(id, name)); } result.close(); } catch (SQLException ex) { throw new SQLException(ex.getMessage()); } return groups; }

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  • Index is outside the bounds of the array

    - by coffeeaddict
    Ok, I cannot get this. I've looked at it and I don't see why it's out of bounds. I get the error at paypalItems[paypalItems.Length] = new PaymentDetailsItemType PaymentDetailsItemType[] paypalItems = new PaymentDetailsItemType[order.OrderItems.Count]; for (int i = 0; i < order.OrderItems.Count; i++) { paypalItems[i] = new PaymentDetailsItemType { Name = order.OrderItems[i].Name, Amount = ApiUtility.CreateBasicAmount(order.OrderItems[i].Price), Description = order.OrderItems[i].Name, Number = order.OrderItems[i].Sku, }; } if (giftCardsTotal != 0) { // add Coupons & Discounts line item paypalItems[paypalItems.Length] = new PaymentDetailsItemType { Name = "Gift Cards", Amount = ApiUtility.CreateBasicAmount(giftCardsTotal), Description = "Gift Cards" }; }

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  • Image upload not functioning correctly

    - by PurpleSmurf
    I'm still trying to get to grips with PHP, and I'm trying to make a form that uploads a picture to a database. I don't have permissions for move_uploaded_file so I'm using the copy() as an alternative. Everywhere I've seen experiencing similar problems have all been with move_uploaded_file so I'm rather stuck. Trying to copy the image from the desktop doesn't seem to be working, it's not throwing up any more PHP errors but is displaying the error message for if something goes wrong. The form sends data to two tables in the database but I'm mainly concerned with the upload not working. There's over 200 lines so I'll post a snippet of the upload code, thank you in advance: function getExtension($str) { $i = strrpos($str,"."); if (!$i) { return ""; } $l = strlen($str) - $i; $ext = substr($str,$i+1,$l); return $ext; } //This variable is used as a flag. The value is initialized with 0 (meaning no error found) and it will be changed to 1 if an errro occures. If the error occures the file will not be uploaded. $errors=0; //checks if the form has been submitted if(isset($_POST['submitted'])) { //reads the name of the file the user submitted for uploading $image=$_FILES['image']['name']; //if it is not empty if ($image) { //get the original name of the file from the clients machine $filename = stripslashes($_FILES['image']['name']); //get the extension of the file in a lower case format $extension = getExtension($filename); $extension = strtolower($extension); //if it is unknown extension, class as an error and do not upload the file, otherwise continue if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif")) { //print error message echo '<h1>Unknown extension!</h1>'; $errors=1; } else { //get the size of the image in bytes //$_FILES['image']['tmp_name'] is the temporary filename of the file in which the uploaded file was stored on the server $size=filesize($_FILES['image']['tmp_name']); //give an unique name, for example the time in unix time format $image_name=time().'.'.$extension; //the new name will be containing the full path where will be stored (images folder) $newname="/home/k0929907/www/uploads/".$image_name; //verify if the image has been uploaded, and print error instead $copied = copy($_FILES['image']['tmp_name'], $newname); if (!$copied) { echo '<h1>Copy unsuccessfull!</h1>'; $errors=1; } } } }

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  • Core Data to-many relationship in code

    - by Jan Bezemer
    I have three entities: Session, User and Test. A session has 0-many users and a user can perform 0-6 tests. (I say 0 but in the real application always at least 1 is required, at least 1 user for a session and at least 1 test for a user. But I say 0 to express an empty start.) All entities have their own specific data attributes too. A user has a name, A session has a name, a test has six values to be filled in by the user, and so on. But my issue is with the relationships. How do I set multiple users and have them added to one session (same goes for multiple tests for one user). How do I show the content in a right way? How do I show a session that has multiple users and these users having completed multiple tests? Here's my code so far with regard to issue 1: Session *session = [NSEntityDescription insertNewObjectForEntityForName:@"Session" inManagedObjectContext:context]; session.name = @"Session 1"; User *users = [NSEntityDescription insertNewObjectForEntityForName:@"User" inManagedObjectContext:context]; users.age = [NSNumber numberWithInt:28]; users.session = session; //sessie.users = users; [sessie addUserObject:users]; With regard to issue 2: I can log the session, but I can't get the user(s) logged from a session. NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init]; NSEntityDescription *entity = [NSEntityDescription entityForName:@"Session" inManagedObjectContext:context]; [fetchRequest setEntity:entity]; NSArray *fetchedObjects = [context executeFetchRequest:fetchRequest error:&error]; for (Session *info in fetchedObjects) { NSLog(@"Name: %@", info.name); NSLog(@"Having problems with this: %@",info.user); //User *details = info.user; //NSLog(@"User: %@", details.age); }

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  • Trying to link a domain to a IP

    - by user248959
    Hi, I have registered mydomain.com now i want to redirect to my IP hosting account. The DNS editor shows two fields: Name and Address. In Address i wrote the IP i want the domain redirects. And in Name I wrote mydomain.com. After submitting the form, the page shows this line: Name Type Record mydomain.mydomain.com. A 173.203.58.251 I expected it shows this: Name Type Record mydomain.com. A 173.203.58.251 Is that OK? or am i doing some wrong? Regards Javi

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  • Hibernate many-to-many relationship

    - by Capitan
    I have two mapped types, related many-to-many. @Entity @Table(name = "students") public class Student{ ... @ManyToMany(fetch = FetchType.EAGER) @JoinTable( name = "students2courses", joinColumns = { @JoinColumn( name = "student_id", referencedColumnName = "_id") }, inverseJoinColumns = { @JoinColumn( name = "course_id", referencedColumnName = "_id") }) public Set<Course> getCourses() { return courses; } public void setCourses(Set<Course> courses) { this.courses = courses; } ... } __ @Entity @Table(name = "courses") public class Course{ ... @ManyToMany(fetch = FetchType.EAGER, mappedBy = "courses") public Set<Student> getStudents() { return students; } public void setStudents(Set<Student> students) { this.students = students; } ... } But if I update/delete Course entity, records are not created/deleted in table students2courses. (with Student entity updating/deleting goes as expected) I wrote abstract class HibObject public abstract class HibObject { public String getRemoveMTMQuery() { return null; } } which is inherited by Student and Course. In DAO I added this code (for delete() method): String query = obj.getRemoveMTMQuery(); if (query != null) { session.createSQLQuery(query).executeUpdate(); } and I ovrerided method getRemoveMTMQuery() for Course @Override @Transient public String getRemoveMTMQuery() { return "delete from students2courses where course_id = " + id + ";"; } Now it works but I think it's a bad code. Is there a best way to solve this problem?

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  • Returning string in java using 3 parameters

    - by user2905118
    Need to write a method describePerson() that takes 3 parameters, a String giving a person’s name, a boolean indicating their gender (true for female, false for male), and an integer giving their age. The method should return a String formatted as in the following examples: Lark is female. She is 2 years old. Or Jay is male. He is 1 year old. I am not sure how to write it correctly (my code): int describePerson(String name, boolean gender, int age) { String words=""; if(gender==true) return (name + "is "+gender+". "+"She is"+age+ "years old.); else return (name + "is "+gender+". "+"She is"+age+ "years old.); } The outcome "year" and "years" is also differs, but i don't know how to make it correct..

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  • Can't import clojure records

    - by Zubair
    I have created a record like this: (defrecord User [user-id email]) :but when I try to access it from another name-space I get the error: (User. "name" "email") java.lang.IllegalArgumentException: Unable to resolve classname: User It works when I do: (oe.model.modelcore.User. "name" "email") : I know I will need to import the Java class, but is there any way for clojure to do this automatically when I do: (use 'oe.model.modelcore :reload)

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  • How do customize the g:sortableColumn?

    - by kakaotalk
    Well, I have one column in my list that I need to customize, the thing is grails' own g:sortable doesn't work. For instance, my first column shows employee ids, then my second column, shows the employees full name where full name is a combination of first name and last name. I got it to work, sorting and all, but when I try to place it in a table with g:sortable, the g:sortable just wouldn't work. I'm thinking about passing params around but it's a bit tricky. Any suggestions? I've looked around the internet, and seems like nothing. :\

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  • jquery convert serialized form inputs to xml string

    - by user590586
    Hi , I'm trying to get all my form inputs and then create with them an xml string containing there values in order to send them via ajax. i want this : <form id="formtest"> <input type="text" name="test1" id="test1"/> <input type="text" name="test2" id="test2"/> <input type="text" name="test3" id="test3"/> <input type="text" name="test4" id="test4"/> <input type="text" name="test5" id="test5"/> </form> to become: <formtest> <test1></test1> <test2></test2> <test3></test3> <test4></test4> <test5></test5> </formtest> How can this be done? Thank's In Advance.

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  • Maintain Constant Title Across Website

    - by Jason
    If I am creating a website in ASP.NET, is it possible to programmatically set the title of the page be some predefined value with some extra information tacked on? For example: Home Page Title = Site Name Links Title = Site Name: Links Stuff Title = Site Name: Stuff Basically, whatever I defined as the main title on the page I'm currently on, I want to tack ": Name" onto the end of the title so it stays consistent across the website. I was thinking of defining it as a ContentPlaceHolder and wrapping some logic around it, but it doesn't appear to work how I thought it would (AKA, not at all).

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  • How to use XML namespace prefixes without xmlns="..." everywhere? (.NET)

    - by LonelyPixel
    The subject is probably too short to explain it... I'm writing out XML files with no namespace stuff at all, for some application. That part I cannot change. But now I'm going to extend those files with my own application-defined element names, and I'd like to put them in a different namespace. For this, the result should look like this: <doc xmlns:x="urn:my-app-uri"> <a>existing element name</a> <x:addon>my additional element name</x:addon> </doc> I've used an XmlNamespaceManager and added my URI with the prefix "x" to it. I've also passed it to each CreateElement for my additional element names. But the nearest I can get is this: <doc> <a>existing element name</a> <addon xmlns="urn:my-app-uri">my additional element name</addon> </doc> Or maybe also <x:addon xmlns:x="urn:my-app-uri">my additional element name</x:addon> So the point is that my URI is written to every single of my additional elements, and no common prefix is written to the document element where I'd like to have it. How can I get the above XML result with .NET?

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