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  • How to count the Chinese word in a file using regex in perl?

    - by Ivan
    I tried following perl code to count the Chinese word of a file, it seems working but not get the right thing. Any help is greatly appreciated. The Error message is Use of uninitialized value $valid in concatenation (.) or string at word_counting.pl line 21, <FILE> line 21. Total things = 125, valid words = which seems to me the problem is the file format. The "total thing" is 125 that is the string number (125 lines). The strangest part is my console displayed all the individual Chinese words correctly without any problem. The utf-8 pragma is installed. #!/usr/bin/perl -w use strict; use utf8; use Encode qw(encode); use Encode::HanExtra; my $input_file = "sample_file.txt"; my ($total, $valid); my %count; open (FILE, "< $input_file") or die "Can't open $input_file: $!"; while (<FILE>) { foreach (split) { #break $_ into words, assign each to $_ in turn $total++; next if /\W|^\d+/; #strange words skip the remainder of the loop $valid++; $count{$_}++; # count each separate word stored in a hash ## next comes here ## } } print "Total things = $total, valid words = $valid\n"; foreach my $word (sort keys %count) { print "$word \t was seen \t $count{$word} \t times.\n"; } ##---Data---- sample_file.txt ??????,???????,????.??????.????:"?????????????,??????,????????.????????,?????????, ???????????.????????,???????????,??????,??????.???:`??,???????????.'?????, ??????????."??????,??????.????.???, ????????????,????,??????,?????????,??????????????. ????????,??????,???????????,????????,????????.????,????,???????, ??????????,??????,????????.??????.

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  • All applications quit when printing on Mac OS X 10.5.8

    - by Tamany
    I recently ran a software update. I'm not sure if my problems are associated with this but I'm pretty sure they are as I printed successfully before update. I checked the log at time of printing: 03/05/2010 22:03:15 Microsoft Word[697] *** -[NSCFString _getValue:forType:]: unrecognized selector sent to instance 0x17a82b50 03/05/2010 22:03:15 [0x0-0x51051].com.microsoft.Word[697] Ignoring Quickdraw drawing between QDBeginCGContext and QDEndCGContext 03/05/2010 22:03:16 [0x0-0x51051].com.microsoft.Word[697] Ignoring Quickdraw drawing between QDBeginCGContext and QDEndCGContext 03/05/2010 22:03:16 [0x0-0x51051].com.microsoft.Word[697] Ignoring Quickdraw drawing between QDBeginCGContext and QDEndCGContext 03/05/2010 22:03:16 [0x0-0x51051].com.microsoft.Word[697] Ignoring Quickdraw drawing between QDBeginCGContext and QDEndCGContext 03/05/2010 22:03:16 [0x0-0x51051].com.microsoft.Word[697] Ignoring Quickdraw drawing between QDBeginCGContext and QDEndCGContext 03/05/2010 22:03:16 [0x0-0x51051].com.microsoft.Word[697] Ignoring Quickdraw drawing between QDBeginCGContext and QDEndCGContext 03/05/2010 22:03:17 [0x0-0x51051].com.microsoft.Word[697] Mon May 3 22:03:17 leopards-imac-2.local Word[697] <Error>: The function `CGPDFDocumentGetMediaBox' is obsolete and will be removed in an upcoming update. Unfortunately, this application, or a library it uses, is using this obsolete function, and is thereby contributing to an overall degradation of system performance. Please use `CGPDFPageGetBoxRect' instead. 03/05/2010 22:22:09 Microsoft Word[697] *** -[NSCFString _getValue:forType:]: unrecognized selector sent to instance 0x1b036500 Any thoughts on how to fix this?

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  • Is there a limit to how many sites can be hosted on a single IP address when using HTTP Host Headers on Windows 2008?

    - by Kev
    For reasons that are lost in the mists of time, our older Windows (2000, 2003) servers have been configured with a "Administrative" IP address and three further "Hosting" IP addresses. There are also additional IP's for sites with SSL certificates. The "Administrative" IP address is where all our internal provisioning, monitoring and other such apps are bound to. We lock this down and don't permit access to it from the outside world (other than over our VPN). The three "Hosting" IP addresses are used for IIS website hosting (in conjunction with host headers). Historically, new site IP address allocations have been rotated through these three IP addresses. I'm not really sure why. I'm building a new batch of servers and I'm considering just having a single hosting IP address. Our servers can host up to 1200 sites on a single machine. Is there a technical limit to the number of IIS sites that can bind to a single IP address? Our Linux platform seems to do just fine with just a single shared IP + host headers. I initially thought this might be an SEO thing, but given that IPv4 address space conservation is paramount I hardly think Google or other search engines could reasonably penalise site rankings just because hundreds of sites hang off the same IP.

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  • Connecting to Aerohive AP's from Laptops running Win. 7 using authentication from a Windows 2008 domain server

    - by user264116
    I have deployed a wireless network using Aerohive access points. 2 of them are set up as radius servers. I want my users to be able to use the same user name and password they use when they log onto our domain. They are able to do this from android devices or computers running Windows 8. It will not work on Windows 7 machines. How do I remedy this situation, keeping in mind that the machines are personal machines not company owned and I will have no way to change their hardware or software.

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  • How do I create/use a Fluent NHibernate convention to map UInt32 properties to an SQL Server 2008 da

    - by dommer
    I'm trying to use a convention to map UInt32 properties to a SQL Server 2008 database. I don't seem to be able to create a solution based on existing web sources, due to updates in the way Fluent NHibernate works - i.e. examples are out of date. Here's my code as it currently stands (which, when I try to expose the schema, fails due to SQL Server not supporting UInt32). Apologies for the code being a little long, but I'm not 100% sure what is relevant to the problem, so I'm erring on the side of caution. I think I'll need a relatively comprehensive example, as I don't seem to be able to pull the pieces together into a working solution, at present. FluentConfiguration configuration = Fluently.Configure() .Database(MsSqlConfiguration.MsSql2008 .ConnectionString(connectionString)) .Mappings(mapping => mapping.AutoMappings.Add( AutoMap.AssemblyOf<Product>() .Conventions.Add<UInt32UserTypeConvention>())); configuration.ExposeConfiguration(x => new SchemaExport(x).Create(false, true)); namespace NHibernateTest { public class UInt32UserTypeConvention : UserTypeConvention<UInt32UserType> { // Empty. } } namespace NHibernateTest { public class UInt32UserType : IUserType { // Public properties. public bool IsMutable { get { return false; } } public Type ReturnedType { get { return typeof(UInt32); } } public SqlType[] SqlTypes { get { return new SqlType[] { SqlTypeFactory.Int32 }; } } // Public methods. public object Assemble(object cached, object owner) { return cached; } public object DeepCopy(object value) { return value; } public object Disassemble(object value) { return value; } public new bool Equals(object x, object y) { return (x != null && x.Equals(y)); } public int GetHashCode(object x) { return x.GetHashCode(); } public object NullSafeGet(IDataReader rs, string[] names, object owner) { int? i = (int?)NHibernateUtil.Int32.NullSafeGet(rs, names[0]); return (UInt32?)i; } public void NullSafeSet(IDbCommand cmd, object value, int index) { UInt32? u = (UInt32?)value; int? i = (Int32?)u; NHibernateUtil.Int32.NullSafeSet(cmd, i, index); } public object Replace(object original, object target, object owner) { return original; } } }

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  • In Java, how do you parse through a single word string?

    - by Fraz
    I'm trying to parse though a string made up of a single word. How would you go about assigning the last letter of the word to a variable? I was thinking of using the Scanner class to parse the word and make each letter an element in an array but it seems Scanner.next() only goes through whole words and not the individual letters. Any help?

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  • How to load MS Word document in C# (.NET)?

    - by Skuta
    Hi, How do I load MS Word document (.doc and .docx) to memory (variable) without doing this?: wordApp.Documents.Open I don't want to open MS Word, I just want that text inside. You gave me answer for DOCX, but what about DOC? I want free and high performance solution - not to open 12.000 instances of Word to process all of them. :( Aspose is commercial product, and 900$ is a way too much for what I do.

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  • In place SQL 2008 upgrade vs. Side by side?

    - by Jim
    I have a SQL 2005 Std edition server with 5 databases in production, 4 db's are used by web-based apps the 5th is a desktop application. My question is should I perform an in-place upgrade or a side-by-side by creating an sql2008 instance on the same box? The machine is a VM on vmware and I'm planning on taking a snapshot before the upgrade and having a 'blackout' window during the upgrade so that I could roll back to the snapshot if things go really bad. Any previous experience and advice is appreciated.

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  • How does KMS (Windows Server 2008 R2) differentiate clients?

    - by Joe Taylor
    I have recently installed a KMS Server in our domain and deployed 75 new Windows 7 machines using an image I made using Acronis True Image. There are 2 variations of this image rolled out currently. When I go to activate the machines it returns that the KMS count is not sufficient. On the server with a slmgr /dlv it shows: Key Management Service is enabled on this machine. Current count: 2 Listening on Port: 1688 DNS publishing enabled KMS Priority: Normal KMS cumulative requests received from clients: 366 Failed requests received: 2 Requests with License status unlicensed: 0 Requests with License status licensed: 0 Requests with License status Initial Grace period: 1 Requests with License statusLicense expired or hardware out of tolerance: 0 Requests with License status Non genuine grace period: 0 Requests with License status Notification: 363 Is it to do with the fact that I've used the same image for all the PC's? If so how do I get round this. Would changing the SID help? OK knowing I've been thick whats the best way to rectify the situation. Can I sysprep the machines to OOBE on each individual machine? Or would NewSID work?

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  • How do you make a regular expression that matches a word with one randomly inserted character?

    - by Dfowj
    Hey all, i want to use a regular expression to match a word with one specified character randomly placed within it. I also want to keep that 'base' word's characters in their original order. For example, with the 'base' word of test and the specified character of 'y', i want the regular expression to match all the following, and ONLY the following: ytest, tyest, teyst, tesyt, testy Incase it matters, im working in javascript and using the dojo toolkit. Thanks!

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  • [AS 3.0] How to use the string.match method to find multiple occurrences of the same word in a strin

    - by Steven
    In Actionscript and Adobe Flex, I'm using a pattern and regexp (with the global flag) with the string.match method and it works how I'd like except when the match returns multiple occurrences of the same word in the text. In that case, all the matches for that word point only to the index for the first occurrence of that word. For example, if the text is "cat dog cat cat cow" and the pattern is a search for cat*, the match method returns an array of three occurrences of "cat", however, they all point to only the index of the first occurrence of cat when i use indexOf on a loop through the array. I'm assuming this is just how the string.match method is (although please let me know if i'm doing something wrong or missing something!). I want to find the specific indices of every occurrence of a match, even if it is of a word that was already previously matched. I'm wondering if that is just how the string.match method is and if so, if anyone has any idea what the best way to do this would be. Thanks.

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  • MapReduce

    - by kaleidoscope
    MapReduce is a programming model and an associated implementation for processing and generating large data sets. Users specify a map function that processes a key/value pair to generate a set of  intermediate key/value pairs, and a reduce function that merges all intermediate values associated with the same intermediate key. Many real world tasks are expressible in this model, as shown in the paper. Programs written in this functional style are automatically parallelized and executed on a large cluster of commodity machines. The run-time system takes care of the details of partitioning the input data,  scheduling the program's execution across a set of machines, handling machine failures, and managing the required inter-machine communication. This allows programmers without any experience with parallel and distributed systems to easily utilize the resources of a large distributed system. Example: A process to count the appearances of each different word in a set of documents void map(String name, String document):   // name: document name   // document: document contents   for each word w in document:     EmitIntermediate(w, 1); void reduce(String word, Iterator partialCounts):   // word: a word   // partialCounts: a list of aggregated partial counts   int result = 0;   for each pc in partialCounts:     result += ParseInt(pc);   Emit(result); Here, each document is split in words, and each word is counted initially with a "1" value by the Map function, using the word as the result key. The framework puts together all the pairs with the same key and feeds them to the same call to Reduce, thus this function just needs to sum all of its input values to find the total appearances of that word.   Sarang, K

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  • SQL Server 2008 full-text search doesn't find word in words?

    - by Martijn
    In the database I have a field with a .mht file. I want to use FTS to search in this document. I got this working, but I'm not satisfied with the result. For example (sorry it's in dutch, but I think you get my point) I will use 2 words: zieken and ziekenhuis. As you can see, the phrase 'zieken' is in the word 'ziekenhuis'. When I search on 'ziekenhuis' I get about 20 results. When I search on 'zieken' I get 7 results. How is this possible? I mean, why doesn't the FTS resturn the minimal results which I get from 'ziekenhuis'? Here's the query I use: SELECT DISTINCT d.DocID 'Id', d.Titel, (SELECT afbeeldinglokatie FROM tbl_Afbeelding WHERE soort = 'beleid') as Pic, 'belDoc' as DocType FROM docs d JOIN kpl_Document_Lokatie dl ON d.DocID = dl.DocID JOIN HandboekLokaties hb ON dl.LokatieID = hb.LokatieID WHERE hb.InstellingID = @instellingId AND ( FREETEXT(d.Doel, @searchstring) OR FREETEXT(d.Toepassingsgebied, @searchstring) OR FREETEXT(d.HtmlDocument, @searchstring) OR FREETEXT (d.extraTabblad, @searchstring) ) AND d.StatusID NOT IN( 1, 5)

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  • Project Euler 17: (Iron)Python

    - by Ben Griswold
    In my attempt to learn (Iron)Python out in the open, here’s my solution for Project Euler Problem 17.  As always, any feedback is welcome. # Euler 17 # http://projecteuler.net/index.php?section=problems&id=17 # If the numbers 1 to 5 are written out in words: # one, two, three, four, five, then there are # 3 + 3 + 5 + 4 + 4 = 19 letters used in total. # If all the numbers from 1 to 1000 (one thousand) # inclusive were written out in words, how many letters # would be used? # # NOTE: Do not count spaces or hyphens. For example, 342 # (three hundred and forty-two) contains 23 letters and # 115 (one hundred and fifteen) contains 20 letters. The # use of "and" when writing out numbers is in compliance # with British usage. import time start = time.time() def to_word(n): h = { 1 : "one", 2 : "two", 3 : "three", 4 : "four", 5 : "five", 6 : "six", 7 : "seven", 8 : "eight", 9 : "nine", 10 : "ten", 11 : "eleven", 12 : "twelve", 13 : "thirteen", 14 : "fourteen", 15 : "fifteen", 16 : "sixteen", 17 : "seventeen", 18 : "eighteen", 19 : "nineteen", 20 : "twenty", 30 : "thirty", 40 : "forty", 50 : "fifty", 60 : "sixty", 70 : "seventy", 80 : "eighty", 90 : "ninety", 100 : "hundred", 1000 : "thousand" } word = "" # Reverse the numbers so position (ones, tens, # hundreds,...) can be easily determined a = [int(x) for x in str(n)[::-1]] # Thousands position if (len(a) == 4 and a[3] != 0): # This can only be one thousand based # on the problem/method constraints word = h[a[3]] + " thousand " # Hundreds position if (len(a) >= 3 and a[2] != 0): word += h[a[2]] + " hundred" # Add "and" string if the tens or ones # position is occupied with a non-zero value. # Note: routine is broken up this way for [my] clarity. if (len(a) >= 2 and a[1] != 0): # catch 10 - 99 word += " and" elif len(a) >= 1 and a[0] != 0: # catch 1 - 9 word += " and" # Tens and ones position tens_position_value = 99 if (len(a) >= 2 and a[1] != 0): # Calculate the tens position value per the # first and second element in array # e.g. (8 * 10) + 1 = 81 tens_position_value = int(a[1]) * 10 + a[0] if tens_position_value <= 20: # If the tens position value is 20 or less # there's an entry in the hash. Use it and there's # no need to consider the ones position word += " " + h[tens_position_value] else: # Determine the tens position word by # dividing by 10 first. E.g. 8 * 10 = h[80] # We will pick up the ones position word later in # the next part of the routine word += " " + h[(a[1] * 10)] if (len(a) >= 1 and a[0] != 0 and tens_position_value > 20): # Deal with ones position where tens position is # greater than 20 or we have a single digit number word += " " + h[a[0]] # Trim the empty spaces off both ends of the string return word.replace(" ","") def to_word_length(n): return len(to_word(n)) print sum([to_word_length(i) for i in xrange(1,1001)]) print "Elapsed Time:", (time.time() - start) * 1000, "millisecs" a=raw_input('Press return to continue')

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  • Error with ReportViewer in ASP.NET: "The server is not a compatible version" ?

    - by fritz
    I deployed some SSRS reports created in Visual Studio 2008 to localhost:8080/ReportServer. ( Using VS 2008 .NET , Version 9.0.21022.8, SQL Server 2008 and XP Prof.) Calling them in the Webbrowser works fine, but now I'm trying to use them in an ASP.NET app with ReportViewer in VS 2008 and using local ASP.NET Development Server. Excecuting the following Code: ReportViewer1.ProcessingMode = ProcessingMode.Remote; IReportServerCredentials irsc = new CustomReportCredentials("xxx", "xxx", "xxx"); ReportViewer1.ServerReport.ReportServerCredentials = irsc; ReportViewer1.ServerReport.ReportServerUrl = new Uri("http://localhost:8080/ReportServer/ReportService2005.asmx?wsdl"); ReportViewer1.ServerReport.ReportPath = @"/AdventureWorks Sample Reports/Sales Order Detail"; ReportViewer1.ServerReport.Refresh(); results in the following exception: "# The version of the report server web service definition (WSDL) is either not valid or unrecognized. The server is not a compatible version. * System.Web.Services.Protocols.SoapException: Server did not recognize the value of HTTP Header 'SOAPAction': http://schemas.microsoft.com/sqlserver/2005/06/30/reporting/reportingservices/LoadReport..." The report file .rdl contains the namespace: xmlns="http://schemas.microsoft.com/sqlserver/reporting/2008/01/reportdefinition" and "http://localhost:8080/ReportServer?&rs%3aCommand=ListChildren" in the Webbrowser shows the report directories and "Microsoft SQL Server Reporting Services, Version 10.0.1600.22" The file "ReportService2005.wsdl" contains a lot of "soapAction="http://schemas.microsoft.com/sqlserver/2005/06/30/reporting/reportingservices/..." attributes. So it sounds like a 2005 / 2008 incompability ? (but as mentioned: i'm using only 2008 products) Any ideas ?

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  • Strange (Undefined?) Behavior of Free in C

    - by Chris Cirefice
    This is really strange... and I can't debug it (tried for about two hours, debugger starts going haywire after a while...). Anyway, I'm trying to do something really simple: Free an array of strings. The array is in the form: char **myStrings. The array elements are initialized as: myString[index] = malloc(strlen(word)); myString[index] = word; and I'm calling a function like this: free_memory(myStrings, size); where size is the length of the array (I know this is not the problem, I tested it extensively and everything except this function is working). free_memory looks like this: void free_memory(char **list, int size) { for (int i = 0; i < size; i ++) { free(list[i]); } free(list); } Now here comes the weird part. if (size> strlen(list[i])) then the program crashes. For example, imagine that I have a list of strings that looks something like this: myStrings[0] = "Some"; myStrings[1] = "random"; myStrings[2] = "strings"; And thus the length of this array is 3. If I pass this to my free_memory function, strlen(myStrings[0]) > 3 (4 3), and the program crashes. However, if I change myStrings[0] to be "So" instead, then strlen(myStrings[0]) < 3 (2 < 3) and the program does not crash. So it seems to me that free(list[i]) is actually going through the char[] that is at that location and trying to free each character, which I imagine is undefined behavior. The only reason I say this is because I can play around with the size of the first element of myStrings and make the program crash whenever I feel like it, so I'm assuming that this is the problem area. Note: I did try to debug this by stepping through the function that calls free_memory, noting any weird values and such, but the moment I step into the free_memory function, the debugger crashes, so I'm not really sure what is going on. Nothing is out of the ordinary until I enter the function, then the world explodes. Another note: I also posted the shortened version of the source for this program (not too long; Pastebin) here. I am compiling on MinGW with the c99 flag on. PS - I just thought of this. I am indeed passing numUniqueWords to the free function, and I know that this does not actually free the entire piece of memory that I allocated. I've called it both ways, that's not the issue. And I left it how I did because that is the way that I will be calling it after I get it to work in the first place, I need to revise some of my logic in that function. Source, as per request (on-site): #include <stdio.h> #include <string.h> #include <ctype.h> #include <stdlib.h> #include "words.h" int getNumUniqueWords(char text[], int size); int main(int argc, char* argv[]) { setvbuf(stdout, NULL, 4, _IONBF); // For Eclipse... stupid bug. --> does NOT affect the program, just the output to console! int nbr_words; char text[] = "Some - \"text, a stdin\". We'll have! also repeat? We'll also have a repeat!"; int length = sizeof(text); nbr_words = getNumUniqueWords(text, length); return 0; } void free_memory(char **list, int size) { for (int i = 0; i < size; i ++) { // You can see that printing the values is fine, as long as free is not called. // When free is called, the program will crash if (size > strlen(list[i])) //printf("Wanna free value %d w/len of %d: %s\n", i, strlen(list[i]), list[i]); free(list[i]); } free(list); } int getNumUniqueWords(char text[], int length) { int numTotalWords = 0; char *word; printf("Length: %d characters\n", length); char totalWords[length]; strcpy(totalWords, text); word = strtok(totalWords, " ,.-!?()\"0123456789"); while (word != NULL) { numTotalWords ++; printf("%s\n", word); word = strtok(NULL, " ,.-!?()\"0123456789"); } printf("Looks like we counted %d total words\n\n", numTotalWords); char *uniqueWords[numTotalWords]; char *tempWord; int wordAlreadyExists = 0; int numUniqueWords = 0; char totalWordsCopy[length]; strcpy(totalWordsCopy, text); for (int i = 0; i < numTotalWords; i++) { uniqueWords[i] = NULL; } // Tokenize until all the text is consumed. word = strtok(totalWordsCopy, " ,.-!?()\"0123456789"); while (word != NULL) { // Look through the word list for the current token. for (int j = 0; j < numTotalWords; j ++) { // Just for clarity, no real meaning. tempWord = uniqueWords[j]; // The word list is either empty or the current token is not in the list. if (tempWord == NULL) { break; } //printf("Comparing (%s) with (%s)\n", tempWord, word); // If the current token is the same as the current element in the word list, mark and break if (strcmp(tempWord, word) == 0) { printf("\nDuplicate: (%s)\n\n", word); wordAlreadyExists = 1; break; } } // Word does not exist, add it to the array. if (!wordAlreadyExists) { uniqueWords[numUniqueWords] = malloc(strlen(word)); uniqueWords[numUniqueWords] = word; numUniqueWords ++; printf("Unique: %s\n", word); } // Reset flags and continue. wordAlreadyExists = 0; word = strtok(NULL, " ,.-!?()\"0123456789"); } // Print out the array just for funsies - make sure it's working properly. for (int x = 0; x <numUniqueWords; x++) { printf("Unique list %d: %s\n", x, uniqueWords[x]); } printf("\nNumber of unique words: %d\n\n", numUniqueWords); // Right below is where things start to suck. free_memory(uniqueWords, numUniqueWords); return numUniqueWords; }

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  • lnk2019 error in very simple c++ program

    - by Erin
    I have tried removing various parts and building, but nothing makes the lnk2019 error go away, or even produces any normal errors. Everything is in the one file at the moment (it won't be later when it is finished). The program has three lists of words and makes a jargon phrase out of them, and you are supposed to be able to add words, remove words, view the lists, restore defaults, save changes to file, and load changes from file. #include "stdafx.h" #include <iostream> #include <string.h> using namespace std; const int maxlist = 20; string adj1[maxlist], adj2[maxlist], noun[maxlist]; void defaultlist(int list) { if(list == 1) { adj1[0] = "green"; adj1[1] = "red"; adj1[2] = "yellow"; adj1[3] = "blue"; adj1[4] = "purple"; int i = 5; while(i != maxlist) { adj1[i] = ""; i = i + 1; } } if(list == 2) { adj2[0] = "shiny"; adj2[1] = "hard"; adj2[2] = "soft"; adj2[3] = "spiky"; adj2[4] = "furry"; int i = 5; while(i != maxlist) { adj2[i] = ""; i = i + 1; } } if(list == 3) { noun[0] = "cat"; noun[1] = "dog"; noun[2] = "desk"; noun[3] = "chair"; noun[4] = "door"; int i = 5; while(i != maxlist) { noun[i] = ""; i = i + 1; } } return; } void printlist(int list) { if(list == 1) { int i = 0; while(!(i == maxlist)) { cout << adj1[i] << endl; i = i + 1; } } if(list == 2) { int i = 0; while(!(i == maxlist)) { cout << adj2[i] << endl; i = i + 1; } } if(list == 3) { int i = 0; while(!(i == maxlist)) { cout << noun[i] << endl; i = i + 1; } } return; } string makephrase() { int num1 = rand()%maxlist; int num2 = rand()%maxlist; int num3 = rand()%maxlist; int num4 = rand()%1; string word1, word2, word3; if(num4 = 0) { word1 = adj1[num1]; word2 = adj2[num2]; } else { word1 = adj2[num1]; word2 = adj1[num2]; } word3 = noun[num3]; return word1 + " ," + word2 + " " + word3; } string addword(string word, int list) { string result; if(list == 1) { int i = 0; while(!(adj1[i] == "" || i == maxlist)) { i = i + 1; } if(i == maxlist) result = "List is full. Please try again."; if(adj1[i] == "") { adj1[i] = word; result = "Word was entered successfully."; } } if(list == 2) { int i = 0; while(!(adj2[i] == "" || i == maxlist)) { i = i + 1; } if(i == maxlist) result = "List is full. Please try again."; if(adj2[i] == "") { adj2[i] = word; result = "Word was entered successfully."; } } if(list == 3) { int i = 0; while(!(noun[i] == "" || i == maxlist)) { i = i + 1; } if(i == maxlist) result = "List is full. Please try again."; if(noun[i] == "") { noun[i] = word; result = "Word was entered successfully."; } } return result; } string removeword(string word, int list) { string result; if(list == 1) { int i = 0; while(!(adj1[i] == word || i == maxlist)) { i = i + 1; } if(i == maxlist) result = "Word is not on the list. Please try again."; if(adj1[i] == word) { adj1[i] = ""; result = "Word was removed successfully."; } } if(list == 2) { int i = 0; while(!(adj2[i] == word || i == maxlist)) { i = i + 1; } if(i == maxlist) result = "Word is not on the list. Please try again."; if(adj2[i] == word) { adj2[i] = ""; result = "Word was removed successfully."; } } if(list == 3) { int i = 0; while(!(noun[i] == word || i == maxlist)) { i = i + 1; } if(i == maxlist) result = "Word is not on the list. Please try again."; if(noun[i] == word) { noun[i] = ""; result = "Word was removed successfully."; } } return result; } /////////////////////////////main/////////////////////////////////// int main() { string mainselection; string makeselection; string phrase; defaultlist(1); defaultlist(2); defaultlist(3); cout << "This program generates jargon phrases made of two adjectives and one noun,"; cout << " on three lists. Each list may contain a maximum of " << maxlist << "elements."; cout << " Please choose from the following menu by typing the appropriate number "; cout << "and pressing enter." << endl; cout << endl; cout << "1. Make a jargon phrase." << endl; cout << "2. View a list." << endl; cout << "3. Add a word to a list." << endl; cout << "4. Remove a word from a list." << endl; cout << "5. Restore default lists." << endl; cout << "More options coming soon!." << endl; cin mainselection if(mainselection == 1) { phrase = makephrase(); cout << "Your phrase is " << phrase << "." << endl; cout << "To make another phrase, press 1. To go back to the main menu,"; cout << " press 2. To exit the program, press 3." << endl; cin makeselection; while(!(makeselection == "1" || makeselection == "2" || makeselection == "3")) { cout << "You have entered an invalid selection. Please try again." << endl; cin makeselection; } while(makeselection == "1") { phrase = makephrase(); cout << "To make another phrase, press 1. To go back to the main menu,"; cout << " press 2. To exit the program, press 3." << endl; } if(makeselection == "2") main(); if(makeselection == "3") return 0; } return 0; } //Rest of the options coming soon!

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  • What word processor can manage left and right pages separately?

    - by chtfn
    I was after a word processor that can manage left and right pages separately so I can have my text on the right pages and my illustrations on the left pages. I know LibeOffice can set "left page" and "right page" formats, but there is no simple way to make the text jump from right page to right page when writing. I don't know what would be the best way to do that, but I guess I need an app that is designed for writing books and do that kind of thing, or an app that can associate a page format with an object format (so the "illustration" format can be exclusively associated with "left page" format, and "text body" exclusively associated with "right page", for example). Or is there an extension for LO or OOo out there that I didn't hear about? Cheers!

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  • Row Number Transformation

    The Row Number Transformation calculates a row number for each row, and adds this as a new output column to the data flow. The column number is a sequential number, based on a seed value. Each row receives the next number in the sequence, based on the defined increment value. The final row number can be stored in a variable for later analysis, and can be used as part of a process to validate the integrity of the data movement. The Row Number transform has a variety of uses, such as generating surrogate keys, or as the basis for a data partitioning scheme when combined with the Conditional Split transformation. Properties Property Data Type Description Seed Int32 The first row number or seed value. Increment Int32 The value added to the previous row number to make the next row number. OutputVariable String The name of the variable into which the final row number is written post execution. (Optional). The three properties have been configured to support expressions, or they can set directly in the normal manner. Expressions on components are only visible on the hosting Data Flow task, not at the individual component level. Sometimes the data type of the property is incorrectly set when the properties are created, see the Troubleshooting section below for details on how to fix this. Installation The component is provided as an MSI file which you can download and run to install it. This simply places the files on disk in the correct locations and also installs the assemblies in the Global Assembly Cache as per Microsoft’s recommendations. You may need to restart the SQL Server Integration Services service, as this caches information about what components are installed, as well as restarting any open instances of Business Intelligence Development Studio (BIDS) / Visual Studio that you may be using to build your SSIS packages. For 2005/2008 Only - Finally you will have to add the transformation to the Visual Studio toolbox manually. Right-click the toolbox, and select Choose Items.... Select the SSIS Data Flow Items tab, and then check the Row Number transformation in the Choose Toolbox Items window. This process has been described in detail in the related FAQ entry for How do I install a task or transform component? We recommend you follow best practice and apply the current Microsoft SQL Server Service pack to your SQL Server servers and workstations, and this component requires a minimum of SQL Server 2005 Service Pack 1. Downloads The Row Number Transformation  is available for SQL Server 2005, SQL Server 2008 (includes R2) and SQL Server 2012. Please choose the version to match your SQL Server version, or you can install multiple versions and use them side by side if you have more than one version of SQL Server installed. Row Number Transformation for SQL Server 2005 Row Number Transformation for SQL Server 2008 Row Number Transformation for SQL Server 2012 Version History SQL Server 2012 Version 3.0.0.6 - SQL Server 2012 release. Includes upgrade support for both 2005 and 2008 packages to 2012. (5 Jun 2012) SQL Server 2008 Version 2.0.0.5 - SQL Server 2008 release. (15 Oct 2008) SQL Server 2005 Version 1.2.0.34 – Updated installer. (25 Jun 2008) Version 1.2.0.7 - SQL Server 2005 RTM Refresh. SP1 Compatibility Testing. Added the ability to reuse an existing column to hold the generated row number, as an alternative to the default of adding a new column to the output. (18 Jun 2006) Version 1.2.0.7 - SQL Server 2005 RTM Refresh. SP1 Compatibility Testing. Added the ability to reuse an existing column to hold the generated row number, as an alternative to the default of adding a new column to the output. (18 Jun 2006) Version 1.0.0.0 - Public Release for SQL Server 2005 IDW 15 June CTP (29 Aug 2005) Screenshot Code Sample The following code sample demonstrates using the Data Generator Source and Row Number Transformation programmatically in a very simple package. Package package = new Package(); package.Name = "Data Generator & Row Number"; // Add the Data Flow Task Executable taskExecutable = package.Executables.Add("STOCK:PipelineTask"); // Get the task host wrapper, and the Data Flow task TaskHost taskHost = taskExecutable as TaskHost; MainPipe dataFlowTask = (MainPipe)taskHost.InnerObject; // Add Data Generator Source IDTSComponentMetaData100 componentSource = dataFlowTask.ComponentMetaDataCollection.New(); componentSource.Name = "Data Generator"; componentSource.ComponentClassID = "Konesans.Dts.Pipeline.DataGenerator.DataGenerator, Konesans.Dts.Pipeline.DataGenerator, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b2ab4a111192992b"; CManagedComponentWrapper instanceSource = componentSource.Instantiate(); instanceSource.ProvideComponentProperties(); instanceSource.SetComponentProperty("RowCount", 10000); // Add Row Number Tx IDTSComponentMetaData100 componentRowNumber = dataFlowTask.ComponentMetaDataCollection.New(); componentRowNumber.Name = "FlatFileDestination"; componentRowNumber.ComponentClassID = "Konesans.Dts.Pipeline.RowNumberTransform.RowNumberTransform, Konesans.Dts.Pipeline.RowNumberTransform, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b2ab4a111192992b"; CManagedComponentWrapper instanceRowNumber = componentRowNumber.Instantiate(); instanceRowNumber.ProvideComponentProperties(); instanceRowNumber.SetComponentProperty("Increment", 10); // Connect the two components together IDTSPath100 path = dataFlowTask.PathCollection.New(); path.AttachPathAndPropagateNotifications(componentSource.OutputCollection[0], componentRowNumber.InputCollection[0]); #if DEBUG // Save package to disk, DEBUG only new Application().SaveToXml(String.Format(@"C:\Temp\{0}.dtsx", package.Name), package, null); #endif package.Execute(); foreach (DtsError error in package.Errors) { Console.WriteLine("ErrorCode : {0}", error.ErrorCode); Console.WriteLine(" SubComponent : {0}", error.SubComponent); Console.WriteLine(" Description : {0}", error.Description); } package.Dispose(); Troubleshooting Make sure you have downloaded the version that matches your version of SQL Server. We offer separate downloads for SQL Server 2005, SQL Server 2008 and SQL Server 2012. If you get an error when you try and use the component along the lines of The component could not be added to the Data Flow task. Please verify that this component is properly installed.  ... The data flow object "Konesans ..." is not installed correctly on this computer, this usually indicates that the internal cache of SSIS components needs to be updated. This is held by the SSIS service, so you need restart the the SQL Server Integration Services service. You can do this from the Services applet in Control Panel or Administrative Tools in Windows. You can also restart the computer if you prefer. You may also need to restart any current instances of Business Intelligence Development Studio (BIDS) / Visual Studio that you may be using to build your SSIS packages. Once installation is complete you need to manually add the task to the toolbox before you will see it and to be able add it to packages - How do I install a task or transform component? Please also make sure you have installed a minimum of SP1 for SQL 2005. The IDtsPipelineEnvironmentService was added in SQL Server 2005 Service Pack 1 (SP1) (See  http://support.microsoft.com/kb/916940). If you get an error Could not load type 'Microsoft.SqlServer.Dts.Design.IDtsPipelineEnvironmentService' from assembly 'Microsoft.SqlServer.Dts.Design, Version=9.0.242.0, Culture=neutral, PublicKeyToken=89845dcd8080cc91'. when trying to open the user interface, it implies that your development machine has not had SP1 applied. Very occasionally we get a problem to do with the properties not being created with the correct data type. Since there is no way to programmatically to define the data type of a pipeline component property, it can only infer it. Whilst we set an integer value as we create the property, sometimes SSIS decides to define it is a decimal. This is often highlighted when you use a property expression against the property and get an error similar to Cannot convert System.Int32 to System.Decimal. Unfortunately this is beyond our control and there appears to be no pattern as to when this happens. If you do have more information we would be happy to hear it. To fix this issue you can manually edit the package file. In Visual Studio right click the package file from the Solution Explorer and select View Code, which will open the package as raw XML. You can now search for the properties by name or the component name. You can then change the incorrect property data types highlighted below from Decimal to Int32. <component id="37" name="Row Number Transformation" componentClassID="{BF01D463-7089-41EE-8F05-0A6DC17CE633}" … >     <properties>         <property id="38" name="UserComponentTypeName" …>         <property id="41" name="Seed" dataType="System.Int32" ...>10</property>         <property id="42" name="Increment" dataType="System.Decimal" ...>10</property>         ... If you are still having issues then contact us, but please provide as much detail as possible about error, as well as which version of the the task you are using and details of the SSIS tools installed.

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