Link
public Node merge(Node x, Node y) {
if(x == null)
return y;
if(y == null)
return x;
// if this was a max height biased leftist tree, then the
// next line would be: if(x.element < y.element)
if(x.element.compareTo(y.element) > 0) {
// x.element > y.element
Node temp = x;
x = y;
y = temp;
}
x.rightChild = merge(x.rightChild, y);
if(x.leftChild == null) {
// left child doesn't exist, so move right child to the left side
x.leftChild = x.rightChild;
x.rightChild = null;
x.s = 1;
} else {
// left child does exist, so compare s-values
if(x.leftChild.s < x.rightChild.s) {
Node temp = x.leftChild;
x.leftChild = x.rightChild;
x.rightChild = temp;
}
// since we know the right child has the lower s-value, we can just
// add one to its s-value
x.s = x.rightChild.s + 1;
}
return x;
}
What makes me ask this question is:
if(x.element.compareTo(y.element) > 0) {
// x.element > y.element
Node temp = x;
x = y;
y = temp;
}
Isn't that just not gonna work, since the references are only switched inside the method?
