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  • strftimedoesnt display year correctly

    - by paultop6
    Hi guys, i have the following code below: const char* timeformat = "%Y-%m-%d %H:%M:%S"; const int timelength = 20; char timecstring[timelength]; strftime(timecstring, timelength, timeformat, currentstruct); cout << "timecstring is: " << timecstring << "\n"; currentstruct is a tm*. The cout is giving me the date in the correct format, but the year is not 2010, but 3910. I know there is something to do with the year cound starting at 1900, but im not sure how to get strftime to recognise this and not add 1900 to the value of 2010 that is there, can anyone help. Regards Paul

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  • Django display notifications by day

    - by dana
    hi guys, i have a notification list, and i want to order them by day, meaning, that i want to have in my notification list every day a title like 'Monday 16th od September' and the notifications for that day. I did not find anywhere how it should be done thanks a lot!

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  • AbsoluteTime with an integer argument behaves strangely.

    - by dreeves
    This is strange: DateList@AbsoluteTime[596523] returns {2078, 7, 2, 2, 42, 9.7849} But DateList@AbsoluteTime[596524] returns {1942, 5, 26, 20, 28, 39.5596} The question: What's going on? Note that AbsoluteTime with an integer argument is undocumented. (I think I now know what it's doing but figured this is useful to have as a StackOverflow question for future reference; and I'm curious if there's some reason for that magic 596523 number.)

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  • Creating files on a time (hourly) basis

    - by Yaniv
    Hi there, I experimenting with twitter streaming API, I use Phirehose to connect to twitter and fetch the data but having problems storing it in files for further processing. Basically what I want to do is to create a file named date("YmdH")."."txt" for every hour of connection. Here is how my code looks like right now (not handling the hourly change of files) public function enqueueStatus($status) $data = json_decode($status,true); if(isset($data['text'])/*more conditions here*/) { $fp = fopen("/tmp/$time.txt"); fwirte ($status,$fp); fclose($fp); } Help is as always much appreciated :)

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  • Compare two times without regard to Date associated - Ruby

    - by H55nick
    I am trying to find the difference in time (without days/years/months) of two different days. Example: #ruby >1.9 time1 = Time.now - 1.day time2 = Time.now #code to make changes #test: time1 == time2 # TRUE My solution: time1 = time1.strftime("%h:%m").to_time time2 = time2.strftime("%h:%m").to_time #test time1 == time2 #True #passes I was wondering if there was a better way of doing this? Maybe we could keep the Date the same as time1/time2?

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  • Getting age in years in a SQL query

    - by Earlz
    Hello I've been tasked with doing a few queries on a large SQL Server 2000 database. The query I'm having trouble with is "find the number of people between ages 20 and 40" How would I do this? My previous query to get a count of everyone looks like this: select count(rid) from people where ... (with the ... being irrelevant conditions). I've googled some but the only thing I've found for calculating age is so large that I don't see how to embed it into a query, or it is a stored procedure which I do not have the permissions to create. Can someone help me with this?

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  • Is there a faster method to match an arbitrary String to month name in Java

    - by jonc
    Hello, I want to determine if a string is the name of a month and I want to do it relatively quickly. The function that is currently stuck in my brain is something like: boolean isaMonth( String str ) { String[] months = DateFormatSymbols.getInstance().getMonths(); String[] shortMonths = DateFormatSymbols.getInstance().getShortMonths(); int i; for( i = 0; i<months.length(); ++i;) { if( months[i].equals(str) ) return true; if( shortMonths[i].equals(str ) return true; } return false; } However, I will be processing lots of text, passed one string at a time to this function, and most of the time I will be getting the worst case of going through the entire loop and returning false. I saw another question that talked about a Regex to match a month name and a year which could be adapted for this situation. Would the Regex be faster? Is there any other solution that might be faster?

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  • Excel isn't reading sql exported csv properly

    - by mhopkins321
    I have a batch file that calls sqlcmd to run a command and then export the data as a csv. When viewed in a cell the trasancted date for example shows 35:30.0 but if you click on it the formula bar shows 1/1/1900 2:45:00 PM. I need the full timestamp to show in the cell. Any ideas? The batch file is the following sqlcmd -S server -U username -P password -d database -i "D:\path\sqlScript.sql" -s "," > D:\path\report.csv -I -W -k 1 The script is the following. Now I currently have them cast as varchars, but that's simply because i've tried to change it a bit. Varchar doesn't work either. SET NOCOUNT ON; select top(10)BO.Status, cast(tradeDate AS varchar) AS Trade_Date, CAST(closingTime AS varchar) AS Closing_Time, CAST(openingTime AS varchar) AS openingTime FROM GIANT COMPLICATED JOINS OF ALL SORTS OF TABLES

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  • Weird flex date issue

    - by CodeMonkey
    Flex is driving me CRAZY and I think it's some weird gotcha with how it handles leap years and none leap years. So here's my example. I have the below dateDiff method that finds the number of days or milliseconds between two dates. If I run the following three statements I get some weird issues. dateDiff("date", new Date(2010, 0,1), new Date(2010, 0, 31)); dateDiff("date", new Date(2010, 1,1), new Date(2010, 1, 28)); dateDiff("date", new Date(2010, 2,1), new Date(2010, 2, 31)); dateDiff("date", new Date(2010, 3,1), new Date(2010, 3, 30)); If you were to look at the date comparisons above you would expect to get 30, 27, 30, 29 as the number of days between the dates. There weird part is that I get 29 when comparing March 1 to March 31. Why is that? Is it something to do with February only having 28 days? If anyone has ANY input on this that would be greatly appreciated. public static function dateDiff( datePart:String, startDate:Date, endDate:Date ):Number { var _returnValue:Number = 0; switch (datePart) { case "milliseconds": _returnValue = endDate.time - startDate.time; break; case "date": // TODO: Need to figure out DST problem i.e. 23 hours at DST start, 25 at end. // Math.floor causes rounding down error with DST start at dayOfYear _returnValue = Math.floor(dateDiff("milliseconds", startDate, endDate)/(1000 * 60 * 60 * 24)); break; } return _returnValue; }

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  • Find objects between two dates MongoDB

    - by Tom
    I've been playing around storing tweets inside mongodb, each object looks like this: { "_id" : ObjectId("4c02c58de500fe1be1000005"), "contributors" : null, "text" : "Hello world", "user" : { "following" : null, "followers_count" : 5, "utc_offset" : null, "location" : "", "profile_text_color" : "000000", "friends_count" : 11, "profile_link_color" : "0000ff", "verified" : false, "protected" : false, "url" : null, "contributors_enabled" : false, "created_at" : "Sun May 30 18:47:06 +0000 2010", "geo_enabled" : false, "profile_sidebar_border_color" : "87bc44", "statuses_count" : 13, "favourites_count" : 0, "description" : "", "notifications" : null, "profile_background_tile" : false, "lang" : "en", "id" : 149978111, "time_zone" : null, "profile_sidebar_fill_color" : "e0ff92" }, "geo" : null, "coordinates" : null, "in_reply_to_user_id" : 149183152, "place" : null, "created_at" : "Sun May 30 20:07:35 +0000 2010", "source" : "web", "in_reply_to_status_id" : { "floatApprox" : 15061797850 }, "truncated" : false, "favorited" : false, "id" : { "floatApprox" : 15061838001 } How would I write a query which checks the *created_at* and finds all objects between 18:47 and 19:00? Do I need to update my documents so the dates are stored in a specific format? Thanks

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  • Using date functions in android application?

    - by rob
    Hi there, I am displaying some event data based on the todays event and a list of events in a week. Currently I am displaying all the events in form of list from the file, As the file contains out dated events as well but I want to display on the basis of today's date events and a week events then week after. In short I want to restrict the list on the basis of this and extract information. I know there is a class java.util containing Date class, but need some quick idea and help how can I do this? Can anyone quote example? Thanks

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  • If either one of both equals

    - by user1620028
    I have start and end dates which are stored in a database in this format: start date= 20121004 //4th October 2012 end date= 20121004 //16th November 2012 so I can use date format: $date = date("Ymd"); // returns: 20121004 to determine when to display and not display to repopulate my update input boxes I use: $start=(str_split($stdate,4));// START DATE: splits stored date into 2x4 ie: 20121209 = 2012 1209 $syr = $start[0];// re first half ie: 2012 which is the year $start2 = $start[1];//re second half ie: 1209 $start3=(str_split($start2,2));// splits second half date into 2x2 ie: 1209 = 12 09 $smth = $start3[0]; // first half = month ie: 12 $sday = $start3[1]; // second half = day ie: 09 $expiry=(str_split($exdate,4)); ///SAME AGAIN FOR EXPIRY DATE ... $xyr = $expiry[0]; $expiry2 = $expiry[1]; $expiry3=(str_split($expiry2,2)); $xmth = $expiry3[0]; $xday = $expiry3[1]; which works fine but I need to repopulate the input boxes for the month showing the date in the database like this <option value="01">January</option`> using if ($smth==01):$month='January'; endif; if ($xmth==01):$month='January'; endif; // if the start and/or expiry month number = 01 display $month as January if ($smth==02):$smonth='February'; endif; if ($xmth==02):$smonth='February'; endif; if ($smth==03):$month='March'; endif; <select name="stmonth" class="input"> <option value="<?=$smth?>"><?=$month?></option> ... </select> is there an easier way to display IF EITHER ONE EQUALS rather than having to write the same line twice once for each $smth AND $xmth ? re: if ($smth **and or** $xmth ==01):$month='January'; endif;

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