Search Results

Search found 3569 results on 143 pages for 'django celery'.

Page 37/143 | < Previous Page | 33 34 35 36 37 38 39 40 41 42 43 44  | Next Page >

• Django 'ImproperlyConfigured' error after deployment on google app engine

  - by oreon

  Hello, I'm currently trying to get my first django project running on Google App Engine. I followed the instructions given here http://www.allbuttonspressed.com/projects/djangoappengine as best I could. Unfortunately I have run into some issues. Locally everything runs fine, no problems. I then tried to deploy my project to the cloud. This is where I'm totally stuck. I always receive 500 Server Errors coupled with google.appengine.runtime.DeadlineExceededError's. Every now and then I get the following error message in my logs, which I think is the root of the problem : <class 'django.core.exceptions.ImproperlyConfigured'>: ImportError projectyalanda.pricecompare: No module named projectyalanda.pricecompare Obviously something is wrong in the way I reference my django app. Why this is only an issue in the cloud is a mystery to me. The interesting part in the settings.py file is setup as following: INSTALLED_APPS = ( 'djangotoolbox', # 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'projectyalanda.pricecompare', ) I absolutely can't figure out why django/appengine wouldn't be able to find the module, especially since everything works perfectly locally. So where else can I look? The local folder structure is of course also correct as automatically done by django, so maybe something is messed up during deployment? How would I be able to find out? Please help me ;-) Thanks

  Read the article

• Django - The included urlconf doesn't have any patterns in it

  - by unsorted

  My website, which was working before, suddenly started breaking with the error "ImproperlyConfigured at / The included urlconf resume.urls doesn't have any patterns in it" The project base is called resume. In settings.py I have set ROOT_URLCONF = 'resume.urls' Here's my resume.urls, which sits in the project root directory. from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', # Example: # (r'^resume/', include('resume.foo.urls')), # Uncomment the admin/doc line below and add 'django.contrib.admindocs' # to INSTALLED_APPS to enable admin documentation: (r'^admin/doc/', include('django.contrib.admindocs.urls')), # Uncomment the next line to enable the admin: (r'^admin/', include(admin.site.urls)), (r'^accounts/login/$', 'django.contrib.auth.views.login'), #(r'^employer/', include(students.urls)), (r'^ajax/', include('urls.ajax')), (r'^student/', include('students.urls')), (r'^club/(?P<object_id>\d+)/$', 'resume.students.views.club_detail'), (r'^company/(?P<object_id>\d+)/$', 'resume.students.views.company_detail'), (r'^program/(?P<object_id>\d+)/$', 'resume.students.views.program_detail'), (r'^course/(?P<object_id>\d+)/$', 'resume.students.views.course_detail'), (r'^career/(?P<object_id>\d+)/$', 'resume.students.views.career_detail'), (r'^site_media/(?P<path>.*)$', 'django.views.static.serve', {'document_root': 'C:/code/django/resume/media'}), ) I have a folder called urls and a file ajax.py inside. (I also created a blank init.py in the same folder so that urls would be recognized.) This is ajax.py. from django.conf.urls.defaults import * urlpatterns = patterns('', (r'^star/(?P<object_id>\d+)$', 'resume.students.ajax-calls.star'), ) Anyone know what's wrong? This is driving me crazy. Thanks,

  Read the article

• CentOS: make python 2.6 see django

  - by NP

  In a harrowing attempt to get mod_wsgi to run on CentOS 5.4, I've added python 2.6 as an optional library following the instructions here. The configuration seems fine except that when trying to ping the server the Apache log prints this error: mod_wsgi (pid=20033, process='otalo', application='127.0.0.1|'): Loading WSGI script '...django.wsgi'. [Sat Mar 27 16:11:45 2010] [error] [client 171.66.52.218] mod_wsgi (pid=20033): Target WSGI script '...django.wsgi' cannot be loaded as Python module. [Sat Mar 27 16:11:45 2010] [error] [client 171.66.52.218] mod_wsgi (pid=20033): Exception occurred processing WSGI script '...django.wsgi'. [Sat Mar 27 16:11:45 2010] [error] [client 171.66.52.218] Traceback (most recent call last): [Sat Mar 27 16:11:45 2010] [error] [client 171.66.52.218] File "...django.wsgi", line 8, in [Sat Mar 27 16:11:45 2010] [error] [client 171.66.52.218] import django.core.handlers.wsgi [Sat Mar 27 16:11:45 2010] [error] [client 171.66.52.218] ImportError: No module named django.core.handlers.wsgi when I go to my python2.6 install's command line and try 'import django', the module is not found (ImportError). However, my default python 2.4 installation (still working fine) is able to import successfully. How do I point python 2.6 to django? Thanks in advance.

  Read the article

• Django: DatabaseError column does not exist

  - by Rosarch

  I'm having a problem with Django 1.2.4. Here is a model: class Foo(models.Model): # ... ftw = models.CharField(blank=True) bar = models.ForeignKey(Bar) Right after flushing the database, I use the shell: Python 2.6.6 (r266:84292, Sep 15 2010, 15:52:39) [GCC 4.4.5] on linux2 Type "help", "copyright", "credits" or "license" for more information. (InteractiveConsole) >>> from apps.foo.models import Foo >>> Foo.objects.all() Traceback (most recent call last): File "<console>", line 1, in <module> File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 67, in __repr__ data = list(self[:REPR_OUTPUT_SIZE + 1]) File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 82, in __len__ self._result_cache.extend(list(self._iter)) File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 271, in iterator for row in compiler.results_iter(): File "/usr/local/lib/python2.6/dist-packages/django/db/models/sql/compiler.py", line 677, in results_iter for rows in self.execute_sql(MULTI): File "/usr/local/lib/python2.6/dist-packages/django/db/models/sql/compiler.py", line 732, in execute_sql cursor.execute(sql, params) File "/usr/local/lib/python2.6/dist-packages/django/db/backends/util.py", line 15, in execute return self.cursor.execute(sql, params) File "/usr/local/lib/python2.6/dist-packages/django/db/backends/postgresql_psycopg2/base.py", line 44, in execute return self.cursor.execute(query, args) DatabaseError: column foo_foo.bar_id does not exist LINE 1: ...t_omg", "foo_foo"."ftw", "foo_foo... What am I doing wrong here?

  Read the article

• Configure Django project in a subdirectory using mod_python. Admin not working.

  - by David

  HI guys. I was trying to configure my django project in a subdirectory of the root, but didn't get things working.(LOcally it works perfect). I followed the django official django documentarion to deploy a project with mod_python. The real problem is that I am getting "Page not found" errors, whenever I try to go to the admin or any view of my apps. Here is my python.conf file located in /etc/httpd/conf.d/ in Fedora 7 LoadModule python_module modules/mod_python.so SetHandler python-program PythonHandler django.core.handlers.modpython SetEnv DJANGO_SETTINGS_MODULE mysite.settings PythonOption django.root /mysite PythonDebug On PythonPath "['/var/www/vhosts/mysite.com/httpdocs','/var/www/vhosts/mysite.com/httpdocs/mysite'] + sys.path" I know /var/www/ is not the best place to put my django project, but I just want to send a demo of my work in progress to my customer, later I will change the location. For example. If I go to www.domain.com/mysite/ I get the index view I configured in mysite.urls. But I cannot access to my app.urls (www.domain.com/mysite/app/) and any of the admin.urls.(www.domain.com/mysite/admin/) Here is mysite.urls: urlpatterns = patterns('', url(r'^admin/password_reset/$', 'django.contrib.auth.views.password_reset', name='password_reset'), (r'^password_reset/done/$', 'django.contrib.auth.views.password_reset_done'), (r'^reset/(?P<uidb36>[0-9A-Za-z]+)-(?P<token>.+)/$', 'django.contrib.auth.views.password_reset_confirm'), (r'^reset/done/$', 'django.contrib.auth.views.password_reset_complete'), (r'^$', 'app.views.index'), (r'^admin/', include(admin.site.urls)), (r'^app/', include('mysite.app.urls')), (r'^photologue/', include('photologue.urls')), ) I also tried changing admin.site.urls with ''django.contrib.admin.urls' , but it didn't worked. I googled a lot to solve this problem and read how other developers configure their django project, but didn't find too much information to deploy django in a subdirectory. I have the admin enabled in INSTALLED_APPS and the settings.py is ok. Please if you have any guide or telling me what I am doing wrong it will be much appreciated. THanks.

  Read the article

• Java PlayFramework & Python Django GAE

  - by Maik Klein

  I already know Java, C# and C++. Now I want to start with web development and I saw that some really big sites are built with Python/C++. I like the coding style of Python, it looks really clean, but some other things like no errors before runtime is really strange. However, I don't know what I should learn now. I started with Python but then I saw that Google App Engine also supports Java and the PlayFramework looks amazing too. Now I am really confused. Should I go with Python or Java? I found the IDE for Python "PyCharm" really amazing for web development. Does Java have something similar, eclipse maybe? I know that this question isn't constructive, but it will help me with my decision. What are pro and cons of both languages?

  Read the article

• Django vs Ruby on Rails [closed]

  - by Michal Gumny

  I know that this is not place for languages war, but my question is quite specific. I'm iOS developer and I have friend who is Android developer, we have idea to make some commercial project together, but we will need quite advaned back-end. We want to learn one of this two frameworks and their languages from scratch, so my question is what language is faster to learn, and write app, which is better for small start up

  Read the article

• Django - how should I implement generic apps that have dependencies on other generic apps?

  - by MikeRand

  Hi all, I'm using Marty Alchin's Django app that creates historical records (add, change, delete) based on models found in other Django apps (found in chapter 11 of Pro Django). Question: how do I implement this historical_records app into my other generic Django apps while still maintaining loose coupling? For example, I have a generic app (forecast) that manages a Forecast (of any other model). For one project, I'd like to use historical_records so that I can track changes to a Forecast instance. But I don't want to require all future projects that might want to use forecast to also use historical_records. Any guidance would be greatly appreciated. Thanks, Mike

  Read the article

• Next steps for Asp.Net C# developer (RoR vs Python Django vs PhP Drupal)

  - by ProfessorB

  A majority of my web development experience has been on the .Net stack (mainly Asp.net C#). I am looking to learn something new in my spare time, for the use of personal projects and possibly for use professionally (as an ISV). I know some Python, done some scripting with it in the past, nothing on the web though. Php has been around for a long time and RoR has gained a lot of popularity. Are there any developers from the .NET world that have migrated over to one or more of the other platforms? If so, which do you prefer and why? Which would you suggest and why?

  Read the article

• What sorts of tools make a Django Developer valuable? [closed]

  - by MrOodles

  I am a Django Consultant and I want to increase the value that I provide to clients. My first question was an epic failure according to the FAQ. So I'll try again before I delete it. What types of tools should a Django developer have in his tool belt to increase the value to the client? Would a collection of project templates be useful? Are there open-source project templates available that can be forked and altered? Is there a proper way to configure templates to include dependencies for certain types of projects? What about deployment scripts using tools like Puppet or Chef? Does it make a lot of sense to fork Django apps on GitHub and make contributions to open source projects there? Would clients percieve extra value in programmers that are contributing to open source projects? Are there industry best practices for implementing continuous integration in a Django project? I want the answer to be open ended, as I'm at the beginning of my research. I am curious to know what sorts of tools other Django consultants use on a daily and per-project basis, and how they use them.

  Read the article

• Show models.ManyToManyField as inline, with the same form as models.ForeignKey inline

  - by Kristian

  I have a model similar to the following (simplified): models.py class Sample(models.Model): name=models.CharField(max_length=200) class Action(models.Model): samples=models.ManyToManyField(Sample) title=models.CharField(max_length=200) description=models.TextField() Now, if Action.samples would have been a ForeignKey instead of a ManyToManyField, when I display Action as a TabularInline in Sample in the Django Admin, I would get a number of rows, each containing a nice form to edit or add another Action. However; when I display the above as an inline using the following: class ActionInline(admin.TabularInline): model=Action.samples.through I get a select box listing all available actions, and not a nifty form to create a new Action. My question is really: How do I display the ManyToMany relation as an inline with a form to input information as described? In principle it should be possible since, from the Sample's point of view, the situation is identical in both cases; Each Sample has a list of Actions regardless if the relation is a ForeignKey or a ManyToManyRelation. Also; Through the Sample admin page, I never want to choose from existing Actions, only create new or edit old ones.

  Read the article

• CharField values disappearing after save (readonly field)

  - by jamida

  I'm implementing simple "grade book" application where the teacher would be able to update the grades w/o being allowed to change the students' names (at least not on the update grade page). To do this I'm using one of the read-only tricks, the simplest one. The problem is that after the SUBMIT the view is re-displayed with 'blank' values for the students. I'd like the students' names to re-appear. Below is the simplest example that exhibits this problem. (This is poor DB design, I know, I've extracted just the relevant parts of the code to showcase the problem. In the real example, student is in its own table but the problem still exists there.) models.py class Grade1(models.Model): student = models.CharField(max_length=50, unique=True) finalGrade = models.CharField(max_length=3) class Grade1OForm(ModelForm): student = forms.CharField(max_length=50, required=False) def __init__(self, *args, **kwargs): super(Grade1OForm,self).__init__(*args, **kwargs) instance = getattr(self, 'instance', None) if instance and instance.id: self.fields['student'].widget.attrs['readonly'] = True self.fields['student'].widget.attrs['disabled'] = 'disabled' def clean_student(self): instance = getattr(self,'instance',None) if instance: return instance.student else: return self.cleaned_data.get('student',None) class Meta: model=Grade1 views.py from django.forms.models import modelformset_factory def modifyAllGrades1(request): gradeFormSetFactory = modelformset_factory(Grade1, form=Grade1OForm, extra=0) studentQueryset = Grade1.objects.all() if request.method=='POST': myGradeFormSet = gradeFormSetFactory(request.POST, queryset=studentQueryset) if myGradeFormSet.is_valid(): myGradeFormSet.save() info = "successfully modified" else: myGradeFormSet = gradeFormSetFactory(queryset=studentQueryset) return render_to_response('grades/modifyAllGrades.html',locals()) template <p>{{ info }}</p> <form method="POST" action=""> <table> {{ myGradeFormSet.management_form }} {% for myform in myGradeFormSet.forms %} {# myform.as_table #} <tr> {% for field in myform %} <td> {{ field }} {{ field.errors }} </td> {% endfor %} </tr> {% endfor %} </table> <input type="submit" value="Submit"> </form>

  Read the article

• working on lists in python

  - by owca

  I'm trying to make a small modification to django lfs project, that will allow me to deactivate products with no stocks. Unfortunatelly I'm just beginning to learn python, so I have big trouble with its syntax. That's what I'm trying to do. I'm using method 'has_variants' which returns true if product has any. Then I'm building a list from variants for this product. Next for every product in this list (I've called it 'set') I check it's stock and set bool variable 'inactive' to true if product has no stocks and to false if there are any. Finally if 'inactive' is false I'm setting self.active to 0. Code fails in line with: set[] = s How to correct it ? def deactivate(self): """If there are no stocks, deactivate the product. Used in last step of checkout. """ if self.has_variants(): for s in self.variants.filter(active=True): set[] = s for var in set: if var.get_stock_amount() == 0: inactive = True else: inactive = False else: if self.get_stock_amount() == 0: inactive = True if inactive: self.active = False return 0 error log : Traceback (most recent call last): File "manage.py", line 11, in <module> execute_manager(settings) File "/home/purplecow/rails/purpledev/site-packages/django/core/management/__i nit__.py", line 362, in execute_manager utility.execute() File "/home/purplecow/rails/purpledev/site-packages/django/core/management/__i nit__.py", line 303, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/home/purplecow/rails/purpledev/site-packages/django/core/management/bas e.py", line 195, in run_from_argv self.execute(*args, **options.__dict__) File "/home/purplecow/rails/purpledev/site-packages/django/core/management/bas e.py", line 213, in execute translation.activate('en-us') File "/home/purplecow/rails/purpledev/site-packages/django/utils/translation/_ _init__.py", line 73, in activate return real_activate(language) File "/home/purplecow/rails/purpledev/site-packages/django/utils/translation/_ _init__.py", line 43, in delayed_loader return g['real_%s' % caller](*args, **kwargs) File "/home/purplecow/rails/purpledev/site-packages/django/utils/translation/t rans_real.py", line 205, in activate _active[currentThread()] = translation(language) File "/home/purplecow/rails/purpledev/site-packages/django/utils/translation/t rans_real.py", line 194, in translation default_translation = _fetch(settings.LANGUAGE_CODE) File "/home/purplecow/rails/purpledev/site-packages/django/utils/translation/t rans_real.py", line 180, in _fetch app = import_module(appname) File "/home/purplecow/rails/purpledev/site-packages/django/utils/importlib.py" , line 35, in import_module __import__(name) File "/home/purplecow/rails/purpledev/lfs/caching/__init__.py", line 1, in <mo dule> from listeners import * File "/home/purplecow/rails/purpledev/lfs/caching/listeners.py", line 10, in < module> from lfs.cart.models import Cart File "/home/purplecow/rails/purpledev/lfs/cart/models.py", line 8, in <module> from lfs.catalog.models import Product File "/home/purplecow/rails/purpledev/lfs/catalog/__init__.py", line 1, in <mo dule> from listeners import * File "/home/purplecow/rails/purpledev/lfs/catalog/listeners.py", line 5, in <m odule> from lfs.catalog.models import PropertyGroup File "/home/purplecow/rails/purpledev/lfs/catalog/models.py", line 589 set[] = s ^ SyntaxError: invalid syntax

  Read the article

• How to prevent HTTP 304 in Django test server

  - by Augusto Men

  I have a couple of projects in Django and alternate between one and another every now and then. All of them have a /media/ path, which is served by django.views.static.serve, and they all have a /media/css/base.css file. The problem is, whenever I run one project, the requests to base.css return an HTTP 304 (not modified), probably because the timestamp hasn't changed. But when I run the other project, the same 304 is returned, making the browser use the file cached by the previous project (and therefore, using the wrong stylesheet). Just for the record, here are the middleware classes: MIDDLEWARE_CLASSES = ( 'django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'django.middleware.transaction.TransactionMiddleware', ) I always use the default address http://localhost:8000. Is there another solution (other than using different ports - 8001, 8002, etc.)?

  Read the article

• Django 1.2 object level permissions - third party solutions?

  - by mawimawi

  Since Django 1.2 final is almost out, I am curious if there are already projects that use the new object level permissions / row level permissions system. [django-authority][1] which is a possible solution for Django up to 1.1 has not been updated for a while, and does not (yet) use the new permissions system. It seems to me that Django-Authority is in a comatose state. Does someone know about upcoming or maybe even finished solutions? I'd appreciate any good links to active projects with at least some downloadable content very much. [1]: http://packages.python.org/django-authority/ django-authority

  Read the article

• django urls.py regex isn't working

  - by Phil

  This is for Django 1.2.5 and Python 2.7 on Wamp Server running apache version 2.2.17. My problem is that the my URLConf in urls.py isn't redirecting, it's just throwing a 404 error. urls.py: from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: #from django.contrib import admin #admin.autodiscover() urlpatterns = patterns('', (r'^app/$', include('app.views.index')), # Uncomment the admin/doc line below to enable admin documentation: #(r'^admin/doc/', include('django.contrib.admindocs.urls')), # Uncomment the next line to enable the admin: #(r'^admin/', include(admin.site.urls)), ) views.py from django.http import HttpResponse def index(request): return HttpResponse("Hello World") I'm getting the following error: ImportError at /app/ No module named index I'm stumped as I'm only learning Django, can anybody see something wrong with my code? Here's my PythonPath: ['C:\Windows\system32\python27.zip', 'C:\Python27\Lib', 'C:\Python27\DLLs', 'C:\Python27\Lib\lib-tk', 'C:\wamp\bin\apache\Apache2.2.17', 'C:\wamp\bin\apache\apache2.2.17\bin', 'C:\Python27', 'C:\Python27\lib\site-packages', 'c:\wamp\www\seetwo']

  Read the article

• Must See Conference Videos for Python/Django Developers

  - by Koobz

  There's lots of good conference videos online regarding Python and Django development. Instead of watching ST:TNG at the computer, I figure it'd more productive to hone my knowledge . Fire away with some of your most inspiring and educational Python, Django, or simply programming related talks. Provide an explanation of why you found the talk useful. Examples: James Bennet on Re-usable Apps - Got me to take a serious look at django apps. Put together a fairly robust site in two days afterwards with django-cms, django-photologue, django-contact-form. Good advice on when your app is crossing boundaries and why it's good to err on the site of 'make it a separate app.'

  Read the article

• Trouble using South with Django and Heroku

  - by Dan

  I had an existing Django project that I've just added South to. I ran syncdb locally. I ran manage.py schemamigration app_name locally I ran manage.py migrate app_name --fake locally I commit and pushed to heroku master I ran syncdb on heroku I ran manage.py schemamigration app_name on heroku I ran manage.py migrate app_name on heroku I then receive this: $ heroku run python notecard/manage.py migrate notecards Running python notecard/manage.py migrate notecards attached to terminal... up, run.1 Running migrations for notecards: - Migrating forwards to 0005_initial. > notecards:0003_initial Traceback (most recent call last): File "notecard/manage.py", line 14, in <module> execute_manager(settings) File "/app/lib/python2.7/site-packages/django/core/management/__init__.py", line 438, in execute_manager utility.execute() File "/app/lib/python2.7/site-packages/django/core/management/__init__.py", line 379, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/app/lib/python2.7/site-packages/django/core/management/base.py", line 191, in run_from_argv self.execute(*args, **options.__dict__) File "/app/lib/python2.7/site-packages/django/core/management/base.py", line 220, in execute output = self.handle(*args, **options) File "/app/lib/python2.7/site-packages/south/management/commands/migrate.py", line 105, in handle ignore_ghosts = ignore_ghosts, File "/app/lib/python2.7/site-packages/south/migration/__init__.py", line 191, in migrate_app success = migrator.migrate_many(target, workplan, database) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 221, in migrate_many result = migrator.__class__.migrate_many(migrator, target, migrations, database) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 292, in migrate_many result = self.migrate(migration, database) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 125, in migrate result = self.run(migration) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 99, in run return self.run_migration(migration) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 81, in run_migration migration_function() File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 57, in <lambda> return (lambda: direction(orm)) File "/app/notecard/notecards/migrations/0003_initial.py", line 15, in forwards ('user', self.gf('django.db.models.fields.related.ForeignKey')(to=orm['auth.User'])), File "/app/lib/python2.7/site-packages/south/db/generic.py", line 226, in create_table ', '.join([col for col in columns if col]), File "/app/lib/python2.7/site-packages/south/db/generic.py", line 150, in execute cursor.execute(sql, params) File "/app/lib/python2.7/site-packages/django/db/backends/util.py", line 34, in execute return self.cursor.execute(sql, params) File "/app/lib/python2.7/site-packages/django/db/backends/postgresql_psycopg2/base.py", line 44, in execute return self.cursor.execute(query, args) django.db.utils.DatabaseError: relation "notecards_semester" already exists I have 3 models. Section, Semester, and Notecards. I've added one field to the Notecards model and I cannot get it added on Heroku. Thank you.

  Read the article

• Making Django ignore string literals

  - by James

  UPDATE: It turns out this is a deeper question than I thought at first glance - the issue is that python is replacing the string literals before they ever get to django. I will do more investigating and update this if I find a solution. I'm using django to work with LaTeX templates for report generation, and am running into a lot of problems with the way Django replaces parts of strings. Specficially, I've run into two problems where I try to insert a variable containing latex code. The first was that it would replace HTML characters, such as the less than symbol, with their HTML codes, which are of course gibberish to a LaTeX interpreter. I fixed this by setting the context to never autoescape, like so: c = Context(inputs) c.autoescape = False However, I still have my second issue, which is that Django replaces string literals with their corresponding characers, so a double backslash becomes \, and \b becomes a backspace. How can I force Django to leave these characters in place, so inputs['variable'] = '{\bf this is code} \\' won't get mangled when I use {{variable}} to reference it in the django template?

  Read the article

• Which Django 1.2.x multilingual application to use?

  - by mawimawi

  There are a couple of different applications for internationalized content in Django. As of now I only have used http://code.google.com/p/django-multilingual/ in my production environments, but I wonder if there are "better" solutions for my wishes. What my staff users need is the following: An object is being created by a staff user in any language (e.g. "de") This object should be displayed in the german version of the website. When a staff user translates the object into a different language (e.g. "fr"), then the page must be visible in the french version as well. If an object is not translated in the visitor's currently selected language (e.g. "en"), then calling the objects url shall raise a 404 Error (or even better a notice that the object is only available in the languages "de" and "fr", and the visitor might be able to select one of the languages) My staff users are working in the admin interface, so the multilingual application must support this as well. I don't really care whether the multilingual app uses a single table with many fields (like title_en, title_de, title_fr) or a foreign key to a related table (as it is implemented in django-multlingual). I only want it to have a good admin interface and no "default" language, because some content might be available just in "de", and some other just in "fr" and "en". And the most important issue of course is compatibility with Django 1.2.x. What are your experiences and preferred apps, and why?

  Read the article

• What are the options for overriding Django's cascading delete behaviour?

  - by Tom

  Django models generally handle the ON DELETE CASCADE behaviour quite adequately (in a way that works on databases that don't support it natively.) However, I'm struggling to discover what is the best way to override this behaviour where it is not appropriate, in the following scenarios for example: ON DELETE RESTRICT (i.e. prevent deleting an object if it has child records) ON DELETE SET NULL (i.e. don't delete a child record, but set it's parent key to NULL instead to break the relationship) Update other related data when a record is deleted (e.g. deleting an uploaded image file) The following are the potential ways to achieve these that I am aware of: Override the model's delete() method. While this sort of works, it is sidestepped when the records are deleted via a QuerySet. Also, every model's delete() must be overridden to make sure Django's code is never called and super() can't be called as it may use a QuerySet to delete child objects. Use signals. This seems to be ideal as they are called when directly deleting the model or deleting via a QuerySet. However, there is no possibility to prevent a child object from being deleted so it is not usable to implement ON CASCADE RESTRICT or SET NULL. Use a database engine that handles this properly (what does Django do in this case?) Wait until Django supports it (and live with bugs until then...) It seems like the first option is the only viable one, but it's ugly, throws the baby out with the bath water, and risks missing something when a new model/relation is added. Am I missing something? Any recommendations?

  Read the article

• why does django-registration use an "activation window" for activating accounts?

  - by bharal

  i'm using django-registration, which is a django lib that helps with users registering on a django-built website. All well and dandy, except that it insists i have an "activation email" associated with all new users. It defaults to a 7 day window, after which, if someone signed up (and we then sent an email to confirm their email address) but didn't click on the link in the sent email within the 7 days, then they cannot sign up. Instead, they need to do the whole process all over again. I'm sure this is a concept that exists generally in web design, because why would django-registration make its own arbitrary signup process up? Anyway, the question is why? What do i gain by having the peace of mind knowing that all the users of my site are the kind of go-getters that click on registration emails with 7 days of receiving them? Why should i sleep easier knowing that my database isn't filled with users who, for whatever reason, clicked through to sign up but didn't actually want to sign up? cheers!

  Read the article

• Python-MySQLdb problem: wrong ELF class: ELFCLASS32

  - by jsalonen

  As part of trying out django CMS (http://www.django-cms.org/), I'm struggling with getting Python-MySQLdb to work (http://pypi.python.org/pypi/MySQL-python/). I have installed Django CMS and all of its dependencies (Python 2.5, Django, django-south, MySQL server) I'm trying out the example code within Django CMS code with MySQL as chosen database type When I execute python manage.py syncdb, the following error occurs: django.core.exceptions.ImproperlyConfigured: Error loading MySQLdb module: /root/.python-eggs/MySQL_python-1.2.3c1-py2.5-linux-i686.egg-tmp/_mysql.so: wrong ELF class: ELFCLASS32 I have been able to trace the problem specifically to python-mySQLdb (as also visible in the stack trace). Other than that, I am completely puzzled. I don't have a clue what ELFCLASS32 means, or what ELF class is anyway. I suspect that this error could have something to do with the fact that I am running 64-bit version of Debian 5 (on a VPS). Any good ideas how to troubleshoot?

  Read the article

• django app using amazon aws s3 storage in stead of DB?

  - by farble1670

  new to python here so bear with me ... i'm looking at django for a rapid prototype to a photo sharing app with an amazon aws s3 storage back end. however, as far as i can tell, django is tailored toward the typical database MVC type of pattern. is there a way to for example provide a custom django model implementation that talks to s3 in stead of a DB? a custom DB engine? would either of these be practical, or am i looking in the wrong direction? thanks.

  Read the article

• Storing hierarchical (parent/child) data in Python/Django: MPTT alternative?

  - by Parand

  I'm looking for a good way to store and use hierarchical (parent/child) data in Django. I've been using django-mptt, but it seems entirely incompatible with my brain - I end up with non-obvious bugs in non-obvious places, mostly when moving things around in the tree: I end up with inconsistent state, where a node and its parent will disagree on their relationship. My needs are simple: Given a node: find its root find its ancestors find its descendants With a tree: easily move nodes (ie. change parent) My trees will be smallish (at most 10k nodes over 20 levels, generally much much smaller, say 10 nodes with 1 or 2 levels). I have to think there has to be an easier way to do trees in python/django. Are there other approaches that do a better job of maintaining consistency?

  Read the article

< Previous Page | 33 34 35 36 37 38 39 40 41 42 43 44  | Next Page >