Search Results

Search found 8279 results on 332 pages for 'django permissions'.

Page 37/332 | < Previous Page | 33 34 35 36 37 38 39 40 41 42 43 44  | Next Page >

  • Access to field in extended flatpage in django

    - by Stanislav Feldman
    How to access field in extended flatpage in django? I wrote this: class ExtendedFlatPage(FlatPage): teaser = CharField(max_length=150) class ExtendedFlatPageForm(FlatpageForm): teaser = CharField(max_length=150) class Meta: model = ExtendedFlatPage class ExtendedFlatPageAdmin(FlatPageAdmin): form = ExtendedFlatPageForm fieldsets = ( (None, {'fields': ('url', 'title', 'teaser', 'content', 'sites',)}), ) admin.site.unregister(FlatPage) admin.site.register(ExtendedFlatPage, ExtendedFlatPageAdmin) And creation in admin is ok. But then in flatpages/default.html I tried this: <html> <body> <h1>{{ flatpage.title }}</h1> <strong>{{ flatpage.teaser }}</strong> <p>{{ flatpage.content }}</p> </body> </html> And there was no flatpage.teaser! What is wrong?

    Read the article

  • in django am facing url problem.....

    - by dpaksp
    am using django.0.97 version i have model called profile in that i have few fields eg like name ,email...ects and it's backend also ready..i.e database . and all users profile is created...i have given all permission to all users. when i login ,click on profile..i able to see list of all user name thr when i click on it ,it's goin to model page where i can edit the user profile..instead of that i want to navigate to a template when i can display the user details ,i have set the URl for it so that when url of that type request comes it should call a view from view it will call my template to display user details,.....the problem is it's not calling my view.... i think my problem is brief....if any information still required ?? pls ask me....and help me

    Read the article

  • (Django) Trim whitespaces from charField

    - by zardon
    How do I strip whitespaces (trim) from the end of a charField in Django? Here is my Model, as you can see I've tried putting in clean methods but these never get run. I've also tried doing name.strip(), models.charField().strip() but these do not work either. Is there a way to force the charField to trim automatically for me? Thanks. class Employee(models.Model): """(Workers, Staff, etc)""" name = models.CharField(blank=True, null=True, max_length=100) # This never gets run def clean_variable(self): data = self.cleaned_data['variable'].strip() return data def __unicode__(self): return self.name class Meta: verbose_name_plural = 'Employees' # This never gets run either class EmployeesForm(forms.ModelForm): class Meta: model = Employee def clean_description(self): #if not self.cleaned_data['description'].strip(): # raise forms.ValidationError('Your error message here') self.cleaned_data['name'].strip()

    Read the article

  • Override Django inlineformset_factory has_changed() to always return True

    - by John
    Hi, I am using the django inlineformset_factory function. a = get_object_or_404(ModelA, pk=id) FormSet = inlineformset_factory(ModelA, ModelB) if request.method == 'POST': metaform = FormSet (instance=a, data=request.POST) if metaform.is_valid(): f = metaform.save(commit=False) for instance in f: instance.updated_by = request.user instance.save() else: metaform = FormSet(instance=a) return render_to_response('nodes/form.html', {'form':metaform}) What is happening is that if I change any of the data then everything works ok and all the data gets updated. However if I don't change any of the data then the data is not updated. i.e. only entries which are changed go through the for loop to be saved. I guess this makes sense as there is no point saving data if it has not changed. However I need to go through and save every object in the form regardless of whether it has any changes on not. So my question is how do I override this so that it goes through and saves every record whether it has any changes or not? Hope this makes sense Thanks

    Read the article

  • Django: query spanning multiple many-to-many relationships

    - by Brant
    I've got some models set up like this: class AppGroup(models.Model): users = models.ManyToManyField(User) class Notification(models.Model): groups_to_notify = models.ManyToManyField(AppGroup) The User objects come from django's authentication system. Now, I am trying to get all the notifications pertaining to the groups that the current user is a part of. I have tried.. notifications = Notification.objects.filter(groups_to_notify=AppGroup.objects.filter(users=request.user)) But that gives an error: more than one row returned by a subquery used as an expression Which I suppose is because the groups_to_notify is checking against several groups. How can I grab all the notifications meant for the user based on the groups he is a part of?

    Read the article

  • Setting a preferred item of a many-to-one in Django

    - by Mike DeSimone
    I'm trying to create a Django model that handles the following: An Item can have several Names. One of the Names for an Item is its primary Name, i.e. the Name displayed given an Item. (The model names were changed to protect the innocent.) The models.py I've got looks like: class Item(models.Model): primaryName = models.OneToOneField("Name", verbose_name="Primary Name", related_name="_unused") def __unicode__(self): return self.primaryName.name class Name(models.Model): item = models.ForeignKey(Item) name = models.CharField(max_length=32, unique=True) def __unicode__(self): return self.name class Meta: ordering = [ 'name' ] The admin.py looks like: class NameInline(admin.TabularInline): model = Name class ItemAdmin(admin.ModelAdmin): inlines = [ NameInline ] admin.site.register(Item, ItemAdmin) It looks like the database schema is working fine, but I'm having trouble with the admin, so I'm not sure of anything at this point. My main questions are: How do I explain to the admin that primaryName needs to be one of the Names of the item being edited? Is there a way to automatically set primaryName to the first Name found, if primaryName is not set, since I'm using inline admin for the names?

    Read the article

  • Django test client gets 301 redirection when accessing url

    - by Michal Klich
    I am writing unittests for django views. I have observed that one of my views returns redirection code 301, which is not expected. Here is my views.py mentioned earlier. def index(request): return render(request, 'index.html', {'form': QueryForm()}) def query(request): if request.is_ajax(): form = QueryForm(request.POST) return HttpResponse('valid') Below is urls.py. urlpatterns = patterns('', url(r'^$', 'core.views.index'), url(r'^query/$', 'core.views.query') ) And unittest that will fail. def so_test(self): response = self.client.post('/') self.assertEquals(response.status_code, 200) response = self.client.post('/query', {}) self.assertEquals(response.status_code, 200) My question is: why there is status 301 returned?

    Read the article

  • Django: where do I call settings.configure?

    - by RexE
    The Django docs say that I can call settings.configure instead of having a DJANGO_SETTINGS_MODULE. I would like my website's project to do this. In what file should I put the call to settings.configure so that my settings will get configured at the right time? Edit in response to Daniel Roseman's comment: The reason I want to do this is that settings.configure lets you pass in the settings variables as a kwargs dict, e.g. {'INSTALLED_APPS': ..., 'TEMPLATE_DIRS': ..., ...}. This would allow my app's users to specify their settings in a dict, then pass that dict to a function in my app that augments it with certain settings necessary to make my app work, e.g. adding entries to INSTALLED_APPS. What I envision looks like this. Let's call my app "rexe_app". In wsgi.py, my app's users would do: import rexe_app my_settings = {'INSTALLED_APPS': ('a','b'), ...} updated_settings = rexe_app.augment_settings(my_settings) # now updated_settings is {'INSTALLED_APPS': ('a','b','c'), 'SESSION_SAVE_EVERY_REQUEST': True, ...} settings.configure(**updated_settings)

    Read the article

  • ModelName(django.contrib.auth.models.User) vs ModelName(models.Model)

    - by amr.negm
    I am developing a django project. I created some apps, some of those are related to User model, for instance, I have a feeds app that handles user feeds, and another app that deals with extra user data like age, contacts, and friends. for each of these, I created a table that should be connected to the User model, which I using for storing and authenticating users. I found two ways to deal with this issue. One, is through extending User model to be like this: ModelName(User): friends = models.ManyToMany('self') ..... Two, is through adding a foreign key to the new table like this: ModelName(models.Model): user = models.ForeignKey(User, unique=True) friends = friends = models.ManyToMany('self') ...... I can't decide which to use in which case. in other words, what are the core differences between both?

    Read the article

  • Django admin proper urls inside listview

    - by hinnye
    Hi, My current target is to give users the chance to download CSV files from the admin site of my application. I successfully managed to create an additional column in the model's list view this way: def doc_link(self): return '<a href="files/%s">%s</a>' % (self.output, self.output) doc_link.allow_tags = True This shows the file name and creates the link, but sadly - because it's inside my 'searches' view - it has an URL: my_site/my_app/searches/files/13.csv. This is my problem, I would like to have my files stored in the admin media directory, like this: http://my_site/media/files/13.csv Does somebody know how to give url which points "outer" from the model's directory? Maybe somehow tell Django to use the ADMIN_MEDIA_PREFIX in the link? I'd really appreciate any help, thanks!

    Read the article

  • Django: Site-Wide URL Prefix

    - by Tom
    I've built a Django site that will live at the root when it's live. Right now it's functioning perfectly at the IP address. For testing purposes, the client has pointed a proxy url at it, but the url has /folder/path in it, so none of the URL patterns match. I put (/folder/path)? into all the url patterns so they now respond, but all of the links are broken because I'm using the {% url %} tag and while the url patterns will match the optional path, they don't include it in that tag. Clearly I can just hard-code /folder/path into all of my urls (well, into all of the url includes) until testing is complete, but is there a better way to do this?

    Read the article

  • Saving data in a inherited django model

    - by aldeano
    I'm building an app to save data and some calculations made with those datas, the idea is keep the data in one model and the calculations in other. So, the models are like this: class FreshData(models.Model): name = models.CharField(max_length=20) one = models.IntegerField() two = models.IntegerField() def save(self, *args, **kwargs): Calculations() Calculations.three = self.one + self.two super(FreshData, self).save(*args, **kwargs) Calculations.save() class Calculations(FreshData): three = models.IntegerField() I've got a valueerror pointing out "self.one" and "self.two" as without value. I keep the idea in witch my design is wrong and django has a simpler way to store related data.

    Read the article

  • Django model class and custom property

    - by dArignac
    Howdy - today a weird problem occured to me: I have a modle class in Django and added a custom property to it that shall not be saved into the database and therefore is not represent in the models structure: class Category(models.Model): groups = models.ManyToManyField(Group) title = defaultdict() Now, when I'm within the shell or writing a test and I do the following: c1 = Category.objects.create() c1.title['de'] = 'german title' print c1.title['de'] # prints "german title" c2 = Category.objects.create() print c2.title['de'] # prints "german title" <-- WTF? It seems that 'title' is kind of global. If I change title to a simple string it works as expected, so it has to do something with the dict? I also tried setting title as a property: title = property(_title) But that did not work, too. So, how can I solve this? Thank you in advance! enter code here

    Read the article

  • Django 1.2: Dates in admin forms don't work with Locales (I10N=True)

    - by equalium
    I have an application in Django 1.2. Language is selectable (I18N and Locale = True) When I select the english lang. in the site, the admin works OK. But when I change to any other language this is what happens with date inputs (spanish example): Correctly, the input accepts the spanish format %d/%m/%Y (Even selecting from the calendar, the date inserts as expected). But when I save the form and load it again, the date shows in the english form: %Y-%m-%d The real problem is that when I load the form to change any other text field and try to save it I get an error telling me to enter a valid date, so I have to write all dates again or change the language in the site to use the admin. I haven't specified anything for DATE_INPUT_FORMATS in settings nor have I overridden forms or models. Surely I am missing something but I can't find it. Can anybody give me a hint?

    Read the article

  • get foreign key objects in a single query - Django

    - by John
    Hi I have 2 models in my django code: class ModelA(models.Model): name = models.CharField(max_length=255) description = models.CharField(max_length=255) created_by = models.ForeignKey(User) class ModelB(models.Model): category = models.CharField(max_length=255) modela_link = models.ForeignKey(ModelA, 'modelb_link') functions = models.CharField(max_length=255) created_by = models.ForeignKey(User) Say ModelA has 100 records, all of which may or may not have links to ModelB Now say I want to get a list of every ModelA record along with the data from ModelB I would do: list_a = ModelA.objects.all() Then to get the data for ModelB I would have to do for i in list_a: i.additional_data = i.modelb_link.all() However this runs a query on every instance of i. Thus making 101 queries to run. Is there any way of running this all in just 1 query. Or at least less than the 101 queries. I've tried putting in ModelA.objects.select_related().all() but this didn't seem to have any effect. Thanks

    Read the article

  • Django Template - Convert python list into a javascript object

    - by amcashcow
    I am working on a django / python website I have a page where I want to display a table of search results The list of results is passed in to the template as normal I also want to make this list of objects accessible to the javascript code My first solution was just create another view that returned json format. But each page load required calling the query twice. So then I tried only downloading the data using the json view and printing the table using javascript. but this is also not desirable as now the presentation layer is mixed into the javascript code. is there a way to create a javascript object from the python list as the page is rendered?

    Read the article

  • Django: Converting an entire Model into a single dictionary

    - by LarrikJ
    Is there a good way in Django to convert an entire model to a dictionary? I mean, like this: class DictModel(models.Model): key = models.CharField(20) value = models.CharField(200) DictModel.objects.all().to_dict() ... with the result being a dictionary with the key/value pairs made up of records in the Model? Has anyone else seen this as being useful for them? Thanks. Update I just wanted to add is that my ultimate goal is to be able to do a simple variable lookup inside a Template. Something like: {{ DictModel.exampleKey }} With a result of DictModel.objects.get(key__exact=exampleKey).value Overall, though, you guys have really surprised me with how helpful allof your responses are, and how different the ways to approach it can be. Thanks a lot.

    Read the article

  • OpenSUSE Yast permissions for user

    - by pajton
    I have an OpenSUSE 11.4 box with Kde 4.6. I am currently working to create a sandbox environment for the user, let's call hime bob. Bob isn't allowed to do much in the system, but I'd like to let him configure certain things in yast. I have dektop shortcuts for particular yast modules, e.g. the shortcut executes xdg-su -c "/sbin/yast2 lan" to launch yast lan configuration. Now, I do not want Bob to have to enter password to launch this configuration (just please don't tell me it's insecure - I know this, in this particular setting it is going to be OK). I wanted to do this with setuid, but obiously setting it on *.desktop shortcut doesn't work. There is sudo approach, but I would have to allow Bob to use all yast modules. So, is there anything more fine-grained to set the permissions for exact yast modules? Thanks in advance!

    Read the article

  • Backup Permissions for an Active Directory Profile Directory

    - by Earls
    I have Folder Redirection turned on so the profiles are on a Windows shared folder on a File and Print Server... \folders\Profiles I want to back up the entire Profiles directory, but as Domain Admin I don't seem to have the privileges to "select all and copy" the entire directory structure. The user profile subfolders (Appdata, Documents, Desktop, Pictures, etc.) throw access denied errors... I tried to grant Domain Admins full privileges to the Profiles directory and thought the subfolders would inherit the privileges, but I get access denied errors just trying to set the permissions... How can I assign a user to the Profiles directory so that I can copy the entire directory tree to back it up?

    Read the article

  • Windows 7 external 2.5 hard drive read write permissions format

    - by user76918
    Working with Windows 7 professional. While trying to format western digital 250GB sata laptop drive; receiving error not initialized. Went to elevated command line to diskpart to clean all; received error message write protected. Went to Disk Management & Virtual disk drive shows as disk 2 not initialized. No format options available greyed out. Went back to command line tried to see attributes disk is read only. How do I take owner ship to change the permissions & format.

    Read the article

  • built in "Offer Remote Assistance" not working because of permissions

    - by Caleb_S
    I'm trying to enable permissions for a user on a Windows7 machine to use the built in feature called "Offer Remote Assistance" or "Windows Remote Assistance". This feature works fine if the user is added to the "domain admins" security group, but for security reasons, I cannot leave him in that group. This is within a SBS2003 Domain. I have added the user and also a group that he is apart of to the Small Business Server Remote Assistance Policy, after following some documentation I was able to find, but this has not worked. Can you tell me how to enable this feature for this user and or a user group? http://content.screencast.com/users/CASEIT/folders/Forum%20Pictures/media/2a518bc9-4184-4520-8b76-cdf46555f568/2011-08-18_1330.png

    Read the article

  • DB2 UDF Permissions

    - by WernerCD
    I have a custom function that I'm working on... the problem I'm having is simple: Permssions. example function: drop function circle_area go CREATE FUNCTION circle_area (radius FLOAT) RETURNS FLOAT LANGUAGE SQL BEGIN DECLARE pi FLOAT DEFAULT 3.14; DECLARE area FLOAT; SET area = pi * radius * radius; RETURN area; END GO if I then log out of my "admin" account... and log into test account I get a "Not authorized" error when I try to run something "Select circle_area(foo) from library.bar". I can log into iSeries Navigator, navigate to schema functions permissions and change the permission for public from Exclude to All. bam it works. How do I grant permission to all, either in the CREATE FUNCTION or after?

    Read the article

  • IIS7 folder permissions

    - by Eanna
    I build a basic WCF service that I now want to host in IIS7 under Windows Server 2008 R2. I added the service as an application under the default web site but whenever i try to run the application I get the following error: HTTP Error 500.19 - Internal Server Error The requested page cannot be accessed because the related configuration data for the page is invalid. Config Error - Cannot read configuration file due to insufficient permissions The only way I can get this service working is if i choose to "connect as" the server Administrator when adding the service. the "application user (pass-through authentication)" option does not seem to work. Could anyone help me out, I've just started using IIS7 and have no idea what to do... Thanks

    Read the article

  • Trouble with cross network permissions for an image through iis7 in an asp.net virtual directory

    - by EdenMachine
    I have load balanced web servers My web application has a function that allows the user to upload their company logo to display in the application header obviously, when they upload the logo image file, it needs to be in a central location or otherwise, the file will not be accessible to the other server on the load balancer. in order to be able to upload the image through the application other on one of either servers and then display it on both servers I need a virtual directory in IIS on both servers that point to a third "file server" (this is the "AcctData" directory shown below with a sub folder "images") the problem is that no matter what I do, I run into a permissioning issue If I use pass-through authentication I get a 401 error. If I use a specific user that's set up on both boxes, I get a 500 error. The "Default" application under "CP" (shown in the image below) uses an AppPool that is a Domain Account that has admin permissions on all the servers. I've also tried sticking a Web.config file in the "AcctData" directory allowing anonymous access. Nothing is working though.

    Read the article

  • Mac OS X Snow Leopard: permissions changed on /var results in dns lookup issues

    - by Ivan
    I was attempting to solve an issue ("/var/log/msmtp.log: permissions denied" error when attempting to send mail using msmtp) when I did this: > chmod -R 770 /var After that, my machine would not resolve domain names via cURL. (ping also fails) But, oddly, I can enter domain names into Safari and visit any web pages w/o a problem... I'm actually not sure if the chmod command is the cause of the problem, but I suspect it is. Also, if I ls -l on /var (or /private/var) it doesn't seem that any of the subdirectories or files there actually changed permission, but there are many, so I can't say that conclusively... Incidentally, I fixed the original error (msmtp.log permission denied) by setting TMPDIR=/tmp in my local environment (bash). Now the error goes away, but I get this error: msmtp: cannot locate host domainname.org: nodename nor servname provided, or not known Any ideas about how to go about getting DNS working again?

    Read the article

< Previous Page | 33 34 35 36 37 38 39 40 41 42 43 44  | Next Page >