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• How to set umask globally?

  - by DevSolar

  I am using a private user group setup, i.e. a user foo's home directory is owned by foo:foo, not foo:users. For this to work, I need to set the umask to 002 globally. After a quick grep -RIi umask /etc/*, it seemed for a moment that modifying the UMASK entry in /etc/login.defs should do the trick. It does, too -- but only for console logins. If I log in to my desktop, and open a terminal there, I still get to see the default umask 022. Same goes for files created from apps started through the menu. Apparently, the display manager (or whatever X11 component responsible) does source some different setting than a console login does, and damned if I could tell which one it is. (I tried changing the setting in /etc/init.d/rc, and no, it did not help.) How / where do I set umask globally (and for all users), so that the X11 desktop environment gets the memo as well? (The system is Linux Mint / Ubuntu, in case that changes anything...)

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• Give access to specific services on Windows 7 Professional machines?

  - by Chad Cook

  We have some machines running Windows 7 Professional at our office. The typical user needs to have access to stop and start a service for a local program they run. These machines have a local web server and database installed and we need to restrict access to certain folders and services related to the web server and database for these users. The setup I have tried so far is to add the typical user as a Power User. I have been able to successfully restrict them from accessing certain folders (as far as I can tell) but now they do not have access to the service needed for starting and stopping the local program. My thought was to give them access to the specific service but I have not had any luck yet. In searching the web for solutions the only results I have found relate to Windows Server 2000 and 2003 and involve creating security templates and databases through the Microsoft Management Console. I am hesitant to try an approach like this as these articles are typically older and I worry this method is outdated. Is there a better way to accomplish the end goal of giving the user permission to run the service and restrict their access to certain folders? If any clarification is needed on the setup or what we are trying to achieve, please let me know. Thanks in advance.

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• What is the most secure way to allow a user read access to a log file?

  - by gAMBOOKa

  My application requires read access to /var/log/messages, which belongs to user and group root. What is the minimal exposure level required on /var/log/messages so my application can read it? Presently, my plan is to change the group ownership of /var/log/messages to a new group, and add root and my application user to it, but this would also give the application write privileges to /var/log/messages. OS: Centos 5.5

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• SAMBA and Linux ACLs -- "Permission denied" on write to share but file written nevertheless

  - by MCH

  I set up a writable share directory "/home/net/share" with acl like this: sudo mkdir -p "/home/net/share" sudo setfacl -m "u:localuser:rwx,u:remoteuser:rwx,g:users:rwx" "/home/net/share" My /etc/samba/smb.conf looks like this: [global] workgroup = w server string = server security = user load printers = no log file = /var/log/samba/%m.log max log size = 50 dns proxy = no printing = bsd printcap name = /dev/null disable spoolss = yes encrypt passwords = true invalid users = nobody root follow symlinks = yes wide links = yes [share] comment = Writable by localuser and remoteuser path = /home/net/share valid users = remoteuser read only = no public = no printable = no Locally, localuser and remoteuser have user accounts and smbpasswds and can both read, create and delete files in /home/net/share. But when I log on from a different machine (like this: sudo mount -t cifs //server/share mountpoint/ -o username=remoteuser ), I get "Permission denied" both when trying to create directories and files, oddly though, it does create files (not directories!) despite these messages! How can I get this working?

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• How is it possible to list all folders that a particular user/group has permissions on?

  - by Lord Torgamus

  Is it possible to list all folders/files that a given group has explicit permissions on, for a machine running Windows Server 2003? If so, how? It would be nice to see inherited permissions as well, but I could do with just explicit permissions. A little background: I'm trying to update groups/permissions on a test server. One of the groups, Devs, wasn't implemented correctly when it was created, and my goal is to remove it from the system. It has been replaced by LeadDevelopers, which has permissions on many — but naturally not all — of the same folders. I want to make sure that I don't accidentally orphan any folders or cause any other issues when I remove Devs. It did have some admin-level permissions.

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• Access is denied when running batch file on Windows7

  - by Radek

  I have a bat file on Windows7 that I used to run. Now I am not able to run it because of Access is denied error. My account is part of administrator group. C:\EduTester\others>mysqlbackup.bat Access is I am able to see the file via more mysqlbackup.bat when inside the directory where the file sits. C:\EduTester\others>more mysqlbackup.bat @echo off rem settings etc etch In fact I used to run the bat file as administrator using runas command runas /savecred /user:yogurt\administrator "c:\EduTester\others\mysqlbackup.bat" Attempting to start c:\EduTester\others\mysqlbackup.bat as user "yogurt\administrator" ... RUNAS ERROR: Unable to run - c:\EduTester\others\mysqlbackup.bat 2: The system cannot find the file It used to run ok few days ago. I am not aware that I would change something that could affect this. I have just tried to restart the Windows7 computer and I am experiencing the same. UPDATE In event viewer I can see this Windows cannot load the user's profile but has logged you on with the default profile for the system I think it might the be cause...

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• How to set an executable white list?

  - by izabera

  Under Linux, is it possible to set a white-list of executables for a certain group of users? I need them to be unable to use, for example, make, gcc and executables on removable disks. How can this be done? Edit, let me explain better. I'm dealing with a high school IT system, young geeks that (during the lessons) want to play, surf the net, damage those computer however they can. The major step to achieve this goal was to remove the system they're familiar with and install Ubuntu in all the computers. This actually works quite well, but recent events proved that this is not enough. I want to allow them to execute certain safe programs, like Open Office, and to deny any other program, whether it is preinstalled software, something they carry in usb drives, a downloaded program or a script they program on site. It's possible to remove the 'x' permission on any file on the pc, but of course it would be impractical. Furthermore, they would be able to run anything they download. I thought the best solution would be to make a white-list of safe programs and to deny anything else, but I don't really know how to do it. Any idea is helpful.

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• Windows 7 Sharing issue on RAID 5 Array(s)

  - by K.A.I.N

  Greetings all, I'm having a very odd error with a windows 7 ultimate x64 system. The network system setup is as follows: 2x XP Pro 32 Bit machines 1x Vista ultimate x64 machine 2x Windows 7 x64 Ultimate machines all chained into 1x 16 port netgear prosafe gigabit switch, the windows 7 & vista machines are duplexed. Also there is a router (netgear Rangemax) chained off the switch I am basically using one of the windows 7 machines to host storage & stream media to other machines. To this end i have put 2x 3tb hardware RAID 5 arrays in it and assorted other spare disks which i have shared the roots of. The unusual problems start when i am getting Access denied, Please contact administrator for permission blah blah blah when trying to access both of the RAID 5 arrays but not the other stand alones. I have checked the permission settings, i have added everyone to the read permission for the root, i have tried moving things into sub directories then sharing them. I have tried various setting combinations in HKEY_LOCAL_MACHINE\SYSTEM\CurrentControlSet\Control\Lsa and always the same. I have tried flushing caches all round, disabling and re-enabling shares & sharing after restart as well as several other things & the result is always the same... No problem on individual drives but access denied on both the RAID arrays from both XP & Vista & Windows 7 machines. One interesting quirk that may lead to an answer is that there is no "offline status" information regarding the folders when you select the RAID 5s from a windows 7 machine yet there is on the normal drives which say they are online. It is as if the raid is present but turned off or spun down but as far as i was aware windows will spin an array back up on network request and on the machine itself the drives seem to be online and can be accessed. Have to admit this has me stumped. Any suggestions anyone? Thanks in advance for any fellow geek assistance. K.A.I.N

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• Komodo Edit 5.2 Django Template Syntax Error - Info: <head> previously mentioned

  - by Lance McNearney

  I am using Komodo Edit 5.2 for editing html and Django template files. It always shows a single syntax error inside the first {% block %} area on the first tag of my template. For example: {% extends "base.html" %} {% load i18n %} {% block title %}Hello{% endblock %} {% block content %} <p>Hello</p> <-- Syntax error on this single line <p>Other lines have no errors</p> {% endblock %} {% block footer %} <p>No errors here</p> {% endblock %} The syntax error given is: Info: <head> previously mentioned I know for a fact that the error has nothing to do with my <head> tag since it occurs in the base template and in child templates (and the IDE isn't smart enough to process the base templates when in a child, etc.) All of my html tags are closed properly and everything validates for XHTML strict. This forum post mentions a similar problem but offers no solution (and may be specific to Smarty syntax highlighting). Any ideas on how to resolve this error (or disable it from being shown)?

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• django-mptt: how to successfully move nodes around

  - by Parand

  django-mptt seems determined to drive me out of my mind. I'm trying to do something relatively simple: I'm going to delete a node, and need to do something reasonable with the node's children. Namely, I'd like to move them up one level so they're children of their current parent's parent. That is, if the tree looks like: Root | Grandpa | Father | | C1 C2 I'm going to delete Father, and would like C1 and C2 to be children of Grandpa. Here's the code I'm using: class Node(models.Model): first_name = models.CharField(max_length=80, blank=True) parent = models.ForeignKey('self', null=True, blank=True, related_name='children') def reparent_children(self, parent): print "Reparenting" for child in self.get_children(): print "Working on", child.first_name, "to parent", parent.email parent = Node.objects.get(id=parent.id) child.move_to(parent, 'last-child') child.save() So I'd call: father.reparent_children(grandpa) father.parent = None father.save() This works - almost. The children report their parents as Grandpa: c1.parent == grandpa # True Grandpa counts C1 and C2 among its children c1 in grandpa.children.all() # True However, Root disowns these kids. c1.get_root() == father # c1's root is father, instead of Root c1 in root.get_descendants() # False How do I get the children to move and their root not get corrupted?

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• Limiting choices from an intermediary ManyToMany junction table in Django

  - by Matthew Rankin

  Background I've created three Django models—Inventory, SalesOrder, and Invoice—to model items in inventory, sales orders for those items, and invoices for a particular sales order. Each sales order can have multiple items, so I've used an intermediary junction table—SalesOrderItems—using the through argument for the ManyToManyField. Also, partial billing of a sales orders is allowed, so I've created a ForeignKey in the Invoice model related to the SalesOrder model, so that a particular sales order can have multiple invoices. Here's where I deviate from what I've normally seen. Instead of relating the Invoice model to the Item model via a ManyToManyField, I've related the Invoice model to the SalesOrderItem intermediary junction table through the intermediary junction table InvoiceItem. I've done this because it better models reality—our invoices are tied to sales orders and can only include items that are tied to that sales order as opposed to any item in inventory. I will admit that it does seem strange having the intermediary junction table of a ManyToManyField related to the intermediary junction table of another ManyToManyField. Question How can I limit the choices available for the invoice_items in the Invoice model to just the sales_order_items of the SalesOrder model for that particular Invoice? (I tried using limit_choices_to= {'sales_order': self.invoice.sales_order}) as part of the item = models.ForeignKey(SalesOrderItem) in the InvoiceItem model, but that didn't work. Am I correct in thinking that limiting the choices for the invoice_items should be handled in the model instead of in a form? Code class Item(models.Model): item_num = models.SlugField(unique=True) default_price = models.DecimalField(max_digits=10, decimal_places=2, blank=True, null=True) class SalesOrderItem(models.Model): item = models.ForeignKey(Item) sales_order = models.ForeignKey('SalesOrder') unit_price = models.DecimalField(max_digits=10, decimal_places=2) quantity = models.DecimalField(max_digits=10, decimal_places=4) class SalesOrder(models.Model): customer = models.ForeignKey(Party) so_num = models.SlugField(max_length=40, unique=True) sales_order_items = models.ManyToManyField(Item, through=SalesOrderItem) class InvoiceItem(models.Model): item = models.ForeignKey(SalesOrderItem) invoice = models.ForeignKey('Invoice') unit_price = models.DecimalField(max_digits=10, decimal_places=2) quantity = models.DecimalField(max_digits=10, decimal_places=4) class Invoice(models.Model): invoice_num = models.SlugField(max_length=25) sales_order = models.ForeignKey(SalesOrder) invoice_items = models.ManyToManyField(SalesOrderItem, through='InvoiceItem')

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• Left Join with a OneToOne field in Django

  - by jamida

  I have 2 tables, simpleDB_all and simpleDB_some. The "all" table has an entry for every item I want, while the "some" table has entries only for some items that need additional information. The Django models for these are: class all(models.Model): name = models.CharField(max_length=40) important_info = models.CharField(max_length=40) class some(models.Model): all_key = models.OneToOneField(all) extra_info = models.CharField(max_length=40) I'd like to create a view that shows every item in "all" with the extra info if it exists in "some". Since I'm using a 1-1 field I can do this with almost complete success: allitems = all.objects.all() for item in allitems: print item.name, item.important_info, item.some.extra_info but when I get to the item that doesn't have a corresponding entry in the "some" table I get a DoesNotExist exception. Ideally I'd be doing this loop inside a template, so it's impossible to wrap it around a "try" clause. Any thoughts? I can get the desired effect directly in SQL using a query like this: SELECT all.name, all.important_info, some.extra_info FROM all LEFT JOIN some ON all.id = some.all_key_id; But I'd rather not use raw SQL.

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• Custom template for Django's comments application does not display fields

  - by Jannis

  Hi, I want to use django.contrib.comments in a blogging application and customize the way the form is displayed. My problem is that I can't get the fields to display although displaying the hidden fields works just fine. I had a look at the docs and compared it with the regular way of displaying forms but honestly I don't know why the following doesn't work out: {% get_comment_form for comments_object as form %} <form action="{% comment_form_target %}" method="POST"> […] {% for hidden in form.hidden_fields %} {{ hidden }} {% endfor %} {% for field in form.fields %} {{field}} {% endfor %} […] </form> The output looks like this: <form action="/comments/post/" method="POST"> <input type="hidden" name="content_type" value="flatpages.flatpage" id="id_content_type" /> <input type="hidden" name="object_pk" value="1" id="id_object_pk" /> <input type="hidden" name="timestamp" value="1269522506" id="id_timestamp" /> <input type="hidden" name="security_hash" value="ec4…0fd" id="id_security_hash" /> content_type object_pk timestamp security_hash name email url comment honeypot […] </form> </div> Can you tell me what I'm doing wrong? Thanks in advance

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• Django: how to cleanup form fields and avoid code duplication

  - by Alexander Konstantinov

  Quite often I need to filter some form data before using it (saving to database etc.) Let's say I want to strip whitespaces and replace repeating whitespaces with a single one in most of the text fields, in many forms. It's not difficult to do this using clean_<fieldname> methods: # Simplified model with two text fields class MyModel(models.Model): title = models.CharField() description = models.CharField() # Model-based form class MyForm(forms.ModelForm): class Meta: model = MyModel def clean_title(self): title = self.cleaned_data['title'] return re.sub(r'\s{2,}', ' ', title.strip()) def clean_description(self): description = self.cleaned_data['description'] return re.sub(r'\s{2,}', ' ', description.strip()) It does exactly what I need, and has a nice side effect which I like: if user enters only whitespaces, the field will be considered empty and therefore invalid (if it is required) and I don't even have to throw a ValidationError. The obvious problem here is code duplication. Even if I'll create some function for that, say my_text_filter, I'll have to call it for every text field in all my forms: from myproject.filters import my_text_filter class MyForm(forms.ModelForm): class Meta: model = MyModel def clean_title(self): return my_text_filter(self.cleaned_data['title']) def clean_description(self): return my_text_filter(self.cleaned_data['description']) The question: is there any standard and simple way in Django (I use version 1.2 if that matters) to do this (like, for example, by adding property validators = {'title': my_text_filter, 'description': my_text_filter} to MyModel), or at least some more or less standard workaround? I've read about form validation and validators in the documentation, but couldn't find what I need there.

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• Practiaal rules for Django MiddleWare ordering?

  - by o_O Tync

  The official documentation is a bit messy: 'before' & 'after' are used for ordering MiddleWare in a tuple, but in some places 'before'&'after' refers to request-response phases. Also, 'should be first/last' are mixed and it's not clear which one to use as 'first'. I do understand the difference.. however it seems to complicated for a newbie in Django. Can you suggest some correct ordering for builtin MiddleWare classes (assuming we enable all of them) and — most importantly — explain WHY one goes before/after other ones? here's the list, with the info from docs I managed to find: UpdateCacheMiddleware Before those that modify 'Vary:' SessionMiddleware, GZipMiddleware, LocaleMiddleware GZipMiddleware Before any MW that may change or use the response body After UpdateCacheMiddleware: Modifies 'Vary:' ConditionalGetMiddleware Before CommonMiddleware: uses its 'Etag:' header when USE_ETAGS=True SessionMiddleware After UpdateCacheMiddleware: Modifies 'Vary:' Before TransactionMiddleware: we don't need transactions here LocaleMiddleware, One of the topmost, after SessionMiddleware, CacheMiddleware After UpdateCacheMiddleware: Modifies 'Vary:' After SessionMiddleware: uses session data CommonMiddleware Before any MW that may change the response (it calculates ETags) After GZipMiddleware so it won't calculate an E-Tag on gzipped contents Close to the top: it redirects when APPEND_SLASH or PREPEND_WWW CsrfViewMiddleware AuthenticationMiddleware After SessionMiddleware: uses session storage MessageMiddleware After SessionMiddleware: can use Session-based storage XViewMiddleware TransactionMiddleware After MWs that use DB: SessionMiddleware (configurable to use DB) All *CacheMiddleWare is not affected (as an exception: uses own DB cursor) FetchFromCacheMiddleware After those those that modify 'Vary:' if uses them to pick a value for cache hash-key After AuthenticationMiddleware so it's possible to use CACHE_MIDDLEWARE_ANONYMOUS_ONLY FlatpageFallbackMiddleware Bottom: last resort Uses DB, however, is not a problem for TransactionMiddleware (yes?) RedirectFallbackMiddleware Bottom: last resort Uses DB, however, is not a problem for TransactionMiddleware (yes?) (I will add suggestions to this list to collect all of them in one place)

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• Django forms: how to dynamically create ModelChoiceField labels

  - by Henri

  I would like to create dynamic labels for a forms.ModelChoiceField and I'm wondering how to do that. I have the following form class: class ProfileForm(forms.ModelForm): def __init__(self, data=None, ..., language_code='en', family_name_label='Family name', horoscope_label='Horoscope type', *args, **kwargs): super(ProfileForm, self).__init__(data, *args, **kwargs) self.fields['family_name'].label = family_name_label . . self.fields['horoscope'].label = horoscope_label self.fields['horoscope'].queryset = Horoscope.objects.all() class Meta: model = Profile family_name = forms.CharField(widget=forms.TextInput(attrs={'size':'80', 'class': 'contact_form'})) . . horoscope = forms.ModelChoiceField(queryset = Horoscope.objects.none(), widget=forms.RadioSelect(), empty_label=None) The default labels are defined by the unicode function specified in the Profile definition. However the labels for the radio buttons created by the ModelChoiceField need to be created dynamically. First I thought I could simply override ModelChoiceField as described in the Django documentation. But that creates static labels. It allows you to define any label but once the choice is made, that choice is fixed. So I think I need to adapt add something to init like: class ProfileForm(forms.ModelForm): def __init__(self, data=None, ..., language_code='en', family_name_label='Family name', horoscope_label='Horoscope type', *args, **kwargs): super(ProfileForm, self).__init__(data, *args, **kwargs) self.fields['family_name'].label = family_name_label . . self.fields['horoscope'].label = horoscope_label self.fields['horoscope'].queryset = Horoscope.objects.all() self.fields['horoscope'].<WHAT>??? = ??? Anyone having any idea how to handle this? Any help would be appreciated very much.

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• Django Template For Loop Removing <img> Self-Closing

  - by Zack

  Django's for loop seems to be removing all of my <img> tag's self-closing...ness (/>). In the Template, I have this code: {% for item in item_list %} <li> <a class="left" href="{{ item.url }}">{{ item.name }}</a> <a class="right" href="{{ item.url }}"> <img src="{{ item.icon.url }}" alt="{{ item.name }} Logo." /> </a> </li> {% endfor %} It outputs this: <li> <a class="left" href="/some-url/">This is an item</a> <a class="right" href="/some-url/"> <img src="/media/img/some-item.jpg" alt="This is an item Logo."> </a> </li> As you can see, the <img> tag is no longer closed, and thus the page doesn't validate. This isn't a huge issue since it'll still render properly in all browsers, but I'd like to know how to solve it. I've tried wrapping the whole for loop in {% autoescape off %}...{% endautoescape %} but that didn't change anything. All other self-closed <img> tags in the document outside the for loop still properly close.

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• Custom Django Field is deciding to work as ForiegnKey for no reason

  - by Joe Simpson

  Hi, i'm making a custom field in Django. There's a problem while trying to save it, it's supposed to save values like this 'user 5' and 'status 9' but instead in the database these fields show up as just the number. Here is the code for the field: def find_key(dic, val): return [k for k, v in dic.items() if v == val][0] class ConnectionField(models.TextField): __metaclass__ = models.SubfieldBase serialize = False description = 'Provides a connection for an object like User, Page, Group etc.' def to_python(self, value): if type(value) != unicode: return value value = value.split(" ") if value[0] == "user": return User.objects.get(pk=value[1]) else: from social.models import connections return get_object_or_404(connections[value[0]], pk=value[1]) def get_prep_value(self, value): from social.models import connections print value, "prep" if type(value) == User: return "user %s" % str(value.pk) elif type(value) in connections.values(): o= "%s %s" % (find_key(connections, type(value)), str(value.pk)) print o, "return" return o else: print "CONNECTION ERROR!" raise TypeError("Value is not connectable!") Connection is just a dictionary with the "status" text linked up to the model for a StatusUpdate. I'm saving a model like this which is causing the issue: Relationship.objects.get_or_create(type="feedback",from_user=request.user,to_user=item) Please can someone help, Many Thanks Joe *_*

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• Suggestions for a django db structure

  - by rh0dium

  Hi Say I have the unknown number of questions. For example: Is the sky blue [y/n] What date were your born on [date] What is pi [3.14] What is a large integ [100] Now each of these questions poses a different but very type specific answer (boolean, date, float, int). Natively django can happily deal with these in a model. class SkyModel(models.Model): question = models.CharField("Is the sky blue") answer = models.BooleanField(default=False) class BirthModel(models.Model): question = models.CharField("What date were your born on") answer = models.DateTimeField(default=today) class PiModel(models.Model) question = models.CharField("What is pi") answer = models.FloatField() But this has the obvious problem in that each question has a specific model - so if we need to add a question later I have to change the database. Yuck. So now I want to get fancy - How do a set up a model where by the answer type conversion happens automagically? ANSWER_TYPES = ( ('boolean', 'boolean'), ('date', 'date'), ('float', 'float'), ('int', 'int'), ('char', 'char'), ) class Questions(models.model): question = models.CharField(() answer = models.CharField() answer_type = models.CharField(choices = ANSWER_TYPES) default = models.CharField() So in theory this would do the following: When I build up my views I look at the type of answer and ensure that I only put in that value. But when I want to pull that answer back out it will return the data in the format specified by the answer_type. Example 3.14 comes back out as a float not as a str. How can I perform this sort of automagic transformation? Or can someone suggest a better way to do this? Thanks much!!

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• Django Many-to-Many Question

  - by DZ

  My questions seems like a common problem that when I have seen any questions on it is never really asked right or not answered. So Im going to try to get the question right, and maybe someone knows how to resolve the issue, or correct my understanding. The problem: When you have a many-to-many relation ship (related_name not through) and you are trying to use the admin interface you are required to input one of the rleationships even though it does not have to exsist for you to create the first entry. Meaning you have to assign a group to an event to create the group. Wow that sounds complicated. So I can see why the question is not getting answered. Lets try the non code explanation example... First and important versions: Django 1.1.1 Phython 2.6 So I have a model where I created a many-to-many realtionship and Im using the related_name Im creating an app that is an event organizer, for simplicty lets say events although they could be anytype). For this first post Im going to stay away from the code and just try to explain. A few keys: (explaining comment) ** - many-to-many So in the model we have 1) The Main Event (this is main model) 2) Groups (link to events and their can be many events for a group) a) Events** I have simplified this example a little becuase I recognize that what does it matter. Just create the event first... But there are specific varations where that will not work. What the many-to-many related_name does it created another table with the indecies of the two other tables. Nothing says that this extra table HAS to be populated. Becuase if I look in the database and work within myPHPadmin I can create a group with out registering an event, since the connection between the two is a seperate table the DB does not care. How do I make the admin interface this realize it? Ok I know thats a lot so I hope I have explained it clearly. Thank you anyone for your comments/thoughts/advice

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• Reordering fields in Django model

  - by Alex Lebedev

  I want to add few fields to every model in my django application. This time it's created_at, updated_at and notes. Duplicating code for every of 20+ models seems dumb. So, I decided to use abstract base class which would add these fields. The problem is that fields inherited from abstract base class come first in the field list in admin. Declaring field order for every ModelAdmin class is not an option, it's even more duplicate code than with manual field declaration. In my final solution, I modified model constructor to reorder fields in _meta before creating new instance: class MyModel(models.Model): # Service fields notes = my_fields.NotesField() created_at = models.DateTimeField(auto_now_add=True) updated_at = models.DateTimeField(auto_now=True) class Meta: abstract = True last_fields = ("notes", "created_at", "updated_at") def __init__(self, *args, **kwargs): new_order = [f.name for f in self._meta.fields] for field in self.last_fields: new_order.remove(field) new_order.append(field) self._meta._field_name_cache.sort(key=lambda x: new_order.index(x.name)) super(TwangooModel, self).__init__(*args, **kwargs) class ModelA(MyModel): field1 = models.CharField() field2 = models.CharField() #etc ... It works as intended, but I'm wondering, is there a better way to acheive my goal?

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• Django Admin Running Same Query Thousands of Times for Model

  - by Tom

  Running into an odd . . . loop when trying to view a model in the Django admin. I have three related models (code trimmed for brevity, hopefully I didn't trim something I shouldn't have): class Association(models.Model): somecompany_entity_id = models.CharField(max_length=10, db_index=True) name = models.CharField(max_length=200) def __unicode__(self): return self.name class ResidentialUnit(models.Model): building = models.CharField(max_length=10) app_number = models.CharField(max_length=10) unit_number = models.CharField(max_length=10) unit_description = models.CharField(max_length=100, blank=True) association = models.ForeignKey(Association) created = models.DateTimeField(auto_now_add=True) updated = models.DateTimeField(auto_now=True) def __unicode__(self): return '%s: %s, Unit %s' % (self.association, self.building, self.unit_number) class Resident(models.Model): unit = models.ForeignKey(ResidentialUnit) type = models.CharField(max_length=20, blank=True, default='') lookup_key = models.CharField(max_length=200) jenark_id = models.CharField(max_length=20, blank=True) user = models.ForeignKey(User) is_association_admin = models.BooleanField(default=False, db_index=True) show_in_contact_list = models.BooleanField(default=False, db_index=True) created = models.DateTimeField(auto_now_add=True) updated = models.DateTimeField(auto_now=True) _phones = {} home_phone = None work_phone = None cell_phone = None app_number = None account_cache_key = None def __unicode__(self): return '%s' % self.user.get_full_name() It's the last model that's causing the problem. Trying to look at a Resident in the admin takes 10-20 seconds. If I take 'self.association' out of the __unicode__ method for ResidentialUnit, a resident page renders pretty quickly. Looking at it in the debug toolbar, without the association name in ResidentialUnit (which is a foreign key on Resident), the page runs 14 queries. With the association name put back in, it runs a far more impressive 4,872 queries. The strangest part is the extra queries all seem to be looking up the association name. They all come from the same line, the __unicode__ method for ResidentialUnit. Each one is the exact same thing, e.g., SELECT `residents_association`.`id`, `residents_association`.`jenark_entity_id`, `residents_association`.`name` FROM `residents_association` WHERE `residents_association`.`id` = 1096 ORDER BY `residents_association`.`name` ASC I assume I've managed to create a circular reference, but if it were truly circular, it would just die, not run 4000x and then return. Having trouble finding a good Google or StackOverflow result for this.

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• Refactoring a custom User model to user UserProfile: Should I create a custom UserManager or add use

  - by BryanWheelock

  I have been refactoring an app that had customized the standard User model from django.contrib.auth.models by creating a UserProfile and defining it with AUTH_PROFILE_MODULE. The problem is the attributes in UserProfile are used throughout the project to determine the User sees. I had been creating tests and putting in this type of statement repeatedly: user = User.objects.get(pk=1) user_profile = user.get_profile() if user_profile.karma > 10: do_some_stuff() This is tedious and I'm now wondering if I'm violating the DRY principle. Would it make more sense to create a custom UserManager that automatically loads the UserProfile data when the user is requested. I could even iterate over the UserProfile attributes and append them to the User model. This would save me having to update all the references to the custom model attributes that litter the code. Of course, I'd have to reverse to process for to allow the User and UserProfile models to be updated correctly. Which approach is more Django-esque?

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• Query list items based on what permissions they have

  - by Janis Veinbergs

  Don't know how to google for such, but is there a way to query all the items where Permissions are unique to listitem These unique permissions contains assignment for specific group X.

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• SharePoint Permissions - Repeated Login Boxes

  - by Ryan Smith

  I have a SharePoint site that is locked down through standard Windows permissions. I keep getting an repeated login box prompt, and it appears that it has to do with the Themes images and the CSS style sheets. Where do I need to update permissions so that these files have the same permissions as the rest of the site and the user only needs to login once? Thanks.

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