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  • CherryPy and RESTful web api

    - by hyperboreean
    What's the best approach of creating a RESTful web api in CherryPy? I've been looking around for a few days now and nothing seems great. For Django it seems that are lots of tools to do this, but not for CherryPy or I am not aware of them

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  • Fabric methods exceptions

    - by baobee
    I try to make Fabric func, which checks if Apache installed: from fabric.api import * def check_apache(): try: result = local('httpd -v', capture=True) except: print "check_apache exception" But if httpd not installed I get: [root@server-local ~]$ fab check_apache Fatal error: local() encountered an error (return code 127) while executing 'ahttpd -v' Aborting. check_apache exception Done. How can I get correct exception for Fabric local() method ? So I need to get exception and continue executing without any Fabric error messages: [root@server-local ~]$ fab check_apache check_apache exception Done.

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  • Obtaining references to function objects on the execution stack from the frame object?

    - by Marcin
    Given the output of inspect.stack(), is it possible to get the function objects from anywhere from the stack frame and call these? If so, how? (I already know how to get the names of the functions.) Here is what I'm getting at: Let's say I'm a function and I'm trying to determine if my caller is a generator or a regular function? I need to call inspect.isgeneratorfunction() on the function object. And how do you figure out who called you? inspect.stack(), right? So if I can somehow put those together, I'll have the answer to my question. Perhaps there is an easier way to do this?

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  • How can I lookup an attribute in any scope by name?

    - by Wai Yip Tung
    How can I lookup an attribute in any scope by name? My first trial is to use globals() and locals(). e.g. >>> def foo(name): ... a=1 ... print globals().get(name), locals().get(name) ... >>> foo('a') None 1 >>> b=1 >>> foo('b') 1 None >>> foo('foo') <function foo at 0x014744B0> None So far so good. However it fails to lookup any built-in names. >>> range <built-in function range> >>> foo('range') None None >>> int <type 'int'> >>> foo('int') None None Any idea on how to lookup built-in attributes?

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  • How can I draw a log-normalized imshow plot with a colorbar representing the raw data in matplotlib

    - by Adam Fraser
    I'm using matplotlib to plot log-normalized images but I would like the original raw image data to be represented in the colorbar rather than the [0-1] interval. I get the feeling there's a more matplotlib'y way of doing this by using some sort of normalization object and not transforming the data beforehand... in any case, there could be negative values in the raw image. import matplotlib.pyplot as plt import numpy as np def log_transform(im): '''returns log(image) scaled to the interval [0,1]''' try: (min, max) = (im[im > 0].min(), im.max()) if (max > min) and (max > 0): return (np.log(im.clip(min, max)) - np.log(min)) / (np.log(max) - np.log(min)) except: pass return im a = np.ones((100,100)) for i in range(100): a[i] = i f = plt.figure() ax = f.add_subplot(111) res = ax.imshow(log_transform(a)) # the colorbar drawn shows [0-1], but I want to see [0-99] cb = f.colorbar(res) I've tried using cb.set_array, but that didn't appear to do anything, and cb.set_clim, but that rescales the colors completely. Thanks in advance for any help :)

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  • In Django, why is user.is_authenticated a method and not a member variable like is_staff

    - by luc
    Hello all, I've lost some time with a bug in my app due to user authentication. I think that it's a bit confusing but maybe someone can explain the reason and it will appear to me very logical. The user.is_staff is a member variable while user.is_authenticated is a method. However is_authenticated only returns True or False depending if the class is User or AnonymousUser (see http://docs.djangoproject.com/en/dev/topics/auth/) Is there a reason for that? Why user.is_authenticated is a method? Thanks in advance

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  • Simple pygtk and threads example please.

    - by wtzolt
    Hello, Can someone give me a simple example involving threads in this manner, please. Problem with my code is that when I click button One, GUI freezes until its finished. I want buttons to stay responsive when def is being executed. How can i fix that? class fun: wTree = None def __init__( self ): self.wTree = gtk.glade.XML( "ui.glade" ) dic = { "on_buttonOne" : self.one, "on_buttonTwo" : self.two, } self.wTree.signal_autoconnect( dic ) gtk.main() def sone(self, widget): time.sleep(1) print "1" time.sleep(1) print "2" time.sleep(1) print "3" def stwo(self, widget): time.sleep(1) print "4" time.sleep(1) print "5" time.sleep(1) print "6" do=fun() Pretty please, help me.

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  • Pygame Sprite/Font rendering issues

    - by Grimless
    Hey guys. Here's my problem: I have a game class that maintains a HUD overlay that has a bunch of elements, including header and footer background sprites. Everything was working fine until I added a 1024x128 footer sprite. Now two of my text labels will not render, despite the fact that they DO exist in my Group and self.elements array. Is there something I'm missing? When I take out the footerHUDImage line, all of the labels render correctly and everything works fine. When I add the footerHUDImage, two of the labels (the first two) no longer render and the third only sometimes renders. HELP PLEASE! Here is the code: class AoWHUD (object): def __init__(self, screen, delegate, dataSource): self.delegate = delegate self.dataSource = dataSource self.elements = [] headerHudImage = KJRImage("HUDBackground.png") self.elements.append(headerHudImage) headerHudImage.userInteractionEnabled = True footerHUDImage = KJRImage("ControlsBackground.png") self.elements.append(footerHUDImage) footerHUDImage.rect.bottom = screen.get_rect().height footerHUDImage.userInteractionEnabled = True lumberMessage = "Lumber: " + str(self.dataSource.lumber) lumberLabel = KJRLabel(lumberMessage, size = 48, color = (240, 200, 10)) lumberLabel.rect.topleft = (_kSpacingMultiple * 0, 0) self.elements.append(lumberLabel) stoneMessage = "Stone: " + str(self.dataSource.stone) stoneLabel = KJRLabel(stoneMessage, size = 48, color = (240, 200, 10)) stoneLabel.rect.topleft = (_kSpacingMultiple * 1, 0) self.elements.append(stoneLabel) metalMessage = "Metal: " + str(self.dataSource.metal) metalLabel = KJRLabel(metalMessage, size = 48, color = (240, 200, 10)) metalLabel.rect.topleft = (_kSpacingMultiple * 2, 0) self.elements.append(metalLabel) foodMessage = "Food: " + str(len(self.dataSource.units)) + "/" + str(self.dataSource.food) foodLabel = KJRLabel(foodMessage, size = 48, color = (240, 200, 10)) foodLabel.rect.topleft = (_kSpacingMultiple * 3, 0) self.elements.append(foodLabel) self.selectionSprites = {32 : pygame.image.load("Selected32.png").convert_alpha(), 64 : pygame.image.load("Selected64.png")} self._sprites_ = pygame.sprite.Group() for e in self.elements: self._sprites_.add(e) print self.elements def draw(self, screen): if self.dataSource.resourcesChanged: lumberMessage = "Lumber: " + str(self.dataSource.lumber) stoneMessage = "Stone: " + str(self.dataSource.stone) metalMessage = "Metal: " + str(self.dataSource.metal) foodMessage = "Food: " + str(len(self.dataSource.units)) + "/" + str(self.dataSource.food) self.elements[2].setText(lumberMessage) self.elements[2].rect.topleft = (_kSpacingMultiple * 0, 0) self.elements[3].setText(stoneMessage) self.elements[3].rect.topleft = (_kSpacingMultiple * 1, 0) self.elements[4].setText(metalMessage) self.elements[4].rect.topleft = (_kSpacingMultiple * 2, 0) self.elements[5].setText(foodMessage) self.elements[5].rect.topleft = (_kSpacingMultiple * 3, 0) self.dataSource.resourcesChanged = False self._sprites_.draw(screen) if self.delegate.selectedUnit: theSelectionSprite = self.selectionSprites[self.delegate.selectedUnit.rect.width] screen.blit(theSelectionSprite, self.delegate.selectedUnit.rect)

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  • redefine __and__ operator

    - by wiso
    Why I can't redefine the __and__ operator? class Cut(object): def __init__(self, cut): self.cut = cut def __and__(self, other): return Cut("(" + self.cut + ") && (" + other.cut + ")") a = Cut("a>0") b = cut("b>0") c = a and b print c.cut() I want (a>0) && (b>0), but I got b, that the usual behaviour of and

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  • Django says the "id may not be NULL" but why is it?

    - by Oli
    I'm going crazy today. I just tried to insert a new record and it threw back a "post_blogpost.id may not be NULL" error. Here's my model: class BlogPost(models.Model): title = models.CharField(max_length=100) slug = models.SlugField(max_length=100) who = models.ForeignKey(User, default=1) when = models.DateTimeField() intro = models.TextField(blank=True, null=True) content = models.TextField(blank=True, null=True) counter = models.PositiveIntegerField(default=0) published = models.BooleanField(default=False) css = models.TextField(blank=True, null=True) class Meta: ordering = ('-when', 'id') There are a number of functions beneath the model too but I won't include them in full here. Their names are: content_cache_key, clear_cache, __unicode__, reads, read, processed_content. I'm adding through the admin... And I'm running out of hair.

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  • How to make scipy.interpolate give a an extrapolated result beyond the input range?

    - by Salim Fadhley
    I'm trying to port a program which uses a hand-rolled interpolator (developed by a mathematitian colleage) over to use the interpolators provided by scipy. I'd like to use or wrap the scipy interpolator so that it has as close as possible behavior to the old interpolator. A key difference between the two functions is that in our original interpolator - if the input value is above or below the input range, our original interpolator will extrapolate the result. If you try this with the scipy interpolator it raises a ValueError. Consider this program as an example: import numpy as np from scipy import interpolate x = np.arange(0,10) y = np.exp(-x/3.0) f = interpolate.interp1d(x, y) print f(9) print f(11) # Causes ValueError, because it's greater than max(x) Is there a sensible way to make it so that instead of crashing, the final line will simply do a linear extrapolate, continuing the gradients defined by the first and last two pouints to infinity. Note, that in the real software I'm not actually using the exp function - that's here for illustration only!

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  • How to build a Django form which requires a delay to be re-submitted ?

    - by pierre-guillaume-degans
    Hey, In order to avoid spamming, I would like to add a waiting time to re-submit a form (i.e. the user should wait a few seconds to submit the form, except the first time that this form is submitted). To do that, I added a timestamp to my form (and a security_hash field containing the timestamp plus the settings.SECRET_KEY which ensures that the timestamp is not fiddled with). This look like: class MyForm(forms.Form): timestamp = forms.IntegerField(widget=forms.HiddenInput) security_hash = forms.CharField(min_length=40, max_length=40, widget=forms.HiddenInput) # + some other fields.. # + methods to build the hash and to clean the timestamp... # (it is based on django.contrib.comments.forms.CommentSecurityForm) def clean_timestamp(self): """Make sure the delay is over (5 seconds).""" ts = self.cleaned_data["timestamp"] if not time.time() - ts > 5: raise forms.ValidationError("Timestamp check failed") return ts # etc... This works fine. However there is still an issue: the timestamp is checked the first time the form is submitted by the user, and I need to avoid this. Any idea to fix it ? Thank you ! :-)

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  • Raising events and object persistence in Django

    - by Mridang Agarwalla
    Hi, I have a tricky Django problem which didn't occur to me when I was developing it. My Django application allows a user to sign up and store his login credentials for a sites. The Django application basically allows the user to search this other site (by scraping content off it) and returns the result to the user. For each query, it does a couple of queries of the other site. This seemed to work fine but sometimes, the other site slaps me with a CAPTCHA. I've written the code to get the CAPTCHA image and I need to return this to the user so he can type it in but I don't know how. My search request (the query, the username and the password) in my Django application gets passed to a view which in turn calls the backend that does the scraping/search. When a CAPTCHA is detected, I'd like to raise a client side event or something on those lines and display the CAPTCHA to the user and wait for the user's input so that I can resume my search. I would somehow need to persist my backend object between calls. I've tried pickling it but it doesn't work because I get the Can't pickle 'lock' object error. I don't know to implement this though. Any help/ideas? Thanks a ton.

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  • Url open encoding

    - by badc0re
    I have the following code for urllib and BeautifulSoup: getSite = urllib.urlopen(pageName) # open current site getSitesoup = BeautifulSoup(getSite.read()) # reading the site content print getSitesoup.originalEncoding for value in getSitesoup.find_all('link'): # extract all <a> tags defLinks.append(value.get('href')) The result of it: /usr/lib/python2.6/site-packages/bs4/dammit.py:231: UnicodeWarning: Some characters could not be decoded, and were replaced with REPLACEMENT CHARACTER. "Some characters could not be decoded, and were " And when i try to read the site i get: ?7?e????0*"I??G?H????F??????9-??????;??E?YÞBs????????????4i???)?????^W?????`w?Ke??%??*9?.'OQB???V??@?????]???(P??^??q?$?S5???tT*?Z

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  • split twice in the same expression?

    - by UcanDoIt
    Imagine I have the following: inFile = "/adda/adas/sdas/hello.txt" # that instruction give me hello.txt Name = inFile.name.split("/") [-1] # that one give me the name I want - just hello Name1 = Name.split(".") [0] Is there any chance to simplify that doing the same job in just one expression?

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  • Filter zipcodes by proximity in Django with the Spherical Law of Cosines

    - by spiffytech
    I'm trying to handle proximity search for a basic store locater in Django. Rather than haul PostGIS around with my app just so I can use GeoDjango's distance filter, I'd like to use the Spherical Law of Cosines distance formula in a model query. I'd like all of the calculations to be done in the database in one query, for efficiency. An example MySQL query from The Internet implementing the Spherical Law of Cosines like this: SELECT id, ( 3959 * acos( cos( radians(37) ) * cos( radians( lat ) ) * cos( radians( lng ) - radians(-122) ) + sin( radians(37) ) * sin( radians( lat ) ) ) ) AS distance FROM stores HAVING distance < 25 ORDER BY distance LIMIT 0 , 20; The query needs to reference the Zipcode ForeignKey for each store's lat/lng values. How can I make all of this work in a Django model query?

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  • Refactoring code/consolidating functions (e.g. nested for-loop order)

    - by bmay2
    Just a little background: I'm making a program where a user inputs a skeleton text, two numbers (lower and upper limit), and a list of words. The outputs are a series of modifications on the skeleton text. Sample inputs: text = "Player # likes @." (replace # with inputted integers and @ with words in list) lower = 1 upper = 3 list = "apples, bananas, oranges" The user can choose to iterate over numbers first: Player 1 likes apples. Player 2 likes apples. Player 3 likes apples. Or words first: Player 1 likes apples. Player 1 likes bananas. Player 1 likes oranges. I chose to split these two methods of outputs by creating a different type of dictionary based on either number keys (integers inputted by the user) or word keys (from words in the inputted list) and then later iterating over the values in the dictionary. Here are the two types of dictionary creation: def numkey(dict): # {1: ['Player 1 likes apples', 'Player 1 likes...' ] } text, lower, upper, list = input_sort(dict) d = {} for num in range(lower,upper+1): l = [] for i in list: l.append(text.replace('#', str(num)).replace('@', i)) d[num] = l return d def wordkey(dict): # {'apples': ['Player 1 likes apples', 'Player 2 likes apples'..] } text, lower, upper, list = input_sort(dict) d = {} for i in list: l = [] for num in range(lower,upper+1): l.append(text.replace('#', str(num)).replace('@', i)) d[i] = l return d It's fine that I have two separate functions for creating different types of dictionaries but I see a lot of repetition between the two. Is there any way I could make one dictionary function and pass in different values to it that would change the order of the nested for loops to create the specific {key : value} pairs I'm looking for? I'm not sure how this would be done. Is there anything related to functional programming or other paradigms that might help with this? The question is a little abstract and more stylistic/design-oriented than anything.

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