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  • Parsing html for domain links

    - by Hallik
    I have a script that parses an html page for all the links within it. I am getting all of them fine, but I have a list of domains I want to compare it against. So a sample list contains list=['www.domain.com', 'sub.domain.com'] But I may have a list of links that look like http://domain.com http://sub.domain.com/some/other/page I can strip off the http:// just fine, but in the two example links I just posted, they both should match. The first I would like to match against the www.domain.com, and the second, I would like to match against the subdomain in the list. Right now I am using url2lib for parsing the html. What are my options in completely this task?

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  • Extend argparse to write set names in the help text for optional argument choices and define those sets once at the end

    - by Kent
    Example of the problem If I have a list of valid option strings which is shared between several arguments, the list is written in multiple places in the help string. Making it harder to read: def main(): elements = ['a', 'b', 'c', 'd', 'e', 'f'] parser = argparse.ArgumentParser() parser.add_argument( '-i', nargs='*', choices=elements, default=elements, help='Space separated list of case sensitive element names.') parser.add_argument( '-e', nargs='*', choices=elements, default=[], help='Space separated list of case sensitive element names to ' 'exclude from processing') parser.parse_args() When running the above function with the command line argument --help it shows: usage: arguments.py [-h] [-i [{a,b,c,d,e,f} [{a,b,c,d,e,f} ...]]] [-e [{a,b,c,d,e,f} [{a,b,c,d,e,f} ...]]] optional arguments: -h, --help show this help message and exit -i [{a,b,c,d,e,f} [{a,b,c,d,e,f} ...]] Space separated list of case sensitive element names. -e [{a,b,c,d,e,f} [{a,b,c,d,e,f} ...]] Space separated list of case sensitive element names to exclude from processing What would be nice It would be nice if one could define an option list name, and in the help output write the option list name in multiple places and define it last of all. In theory it would work like this: def main_optionlist(): elements = ['a', 'b', 'c', 'd', 'e', 'f'] # Two instances of OptionList are equal if and only if they # have the same name (ALFA in this case) ol = OptionList('ALFA', elements) parser = argparse.ArgumentParser() parser.add_argument( '-i', nargs='*', choices=ol, default=ol, help='Space separated list of case sensitive element names.') parser.add_argument( '-e', nargs='*', choices=ol, default=[], help='Space separated list of case sensitive element names to ' 'exclude from processing') parser.parse_args() And when running the above function with the command line argument --help it would show something similar to: usage: arguments.py [-h] [-i [ALFA [ALFA ...]]] [-e [ALFA [ALFA ...]]] optional arguments: -h, --help show this help message and exit -i [ALFA [ALFA ...]] Space separated list of case sensitive element names. -e [ALFA [ALFA ...]] Space separated list of case sensitive element names to exclude from processing sets in optional arguments: ALFA {a,b,c,d,e,f} Question I need to: Replace the {'l', 'i', 's', 't', 's'} shown with the option name, in the optional arguments. At the end of the help text show a section explaining which elements each option name consists of. So I ask: Is this possible using argparse? Which classes would I have to inherit from and which methods would I need to override? I have tried looking at the source for argparse, but as this modification feels pretty advanced I don´t know how to get going.

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  • Numpy Matrix keeps giving me an Error,

    - by uberjumper
    Okay this is werid, i keep getting the error, randomly. ValueError: matrix must be 2-dimensional So i tracked it down, and cornered it to basically something like this: a_list = [[(1,100) for _ in range(32)] for _ in range(32)] numpy.matrix(a_list) Whats wrong with this? If i print a_list it is clearly a 2d matrix of tuples, however numpy does not believe so.

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  • In plain English, what are Django generic views?

    - by allyourcode
    The first two paragraphs of this page explain that generic views are supposed to make my life easier, less monotonous, and make me more attractive to women (I made up that last one): http://docs.djangoproject.com/en/dev/topics/generic-views/#topics-generic-views I'm all for improving my life, but what do generic views actually do? It seems like lots of buzzwords are being thrown around, which confuse more than they explain. Are generic views similar to scaffolding in Ruby on Rails? The last bullet point in the intro seems to indicate this. Is that an accurate statement?

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  • Creating a Group of Groups in Django

    - by Greg
    I'm creating my own Group model; I'm not referring to the builtin Group model. I want each hroup to be a member of another group (it's parent), but there is the one "top" group that doesn't have a parent group. The admin interface won't let me create a group without entering a parent. I get the error personnel_group.parent_id may not be NULL. My Group model looks like this: class Group(models.Model): name = models.CharField(max_length=50) parent = models.ForeignKey('self', blank=True, null=True) order = models.IntegerField() icon = models.ImageField(upload_to='groups', blank=True, null=True) description = models.TextField(blank=True, null=True) How can I accomplish this? Thanks.

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  • pyramid traversal resource url no attribute __name__

    - by Santana
    So I have: resources.py: def _add(obj, name, parent): obj.__name__ = name obj.__parent__ = parent return obj class Root(object): __parent__ = __name__ = None def __init__(self, request): super(Root, self).__init__() self.request = request self.collection = request.db.post def __getitem__(self, key): if u'profile' in key: return Profile(self.request) class Profile(dict): def __init__(self, request): super(Profile, self).__init__() self.__name__ = u'profile' self.__parent__ = Root self.collection = request.db.posts def __getitem__(self, name): post = Dummy(self.collection.find_one(dict(username=name))) return _add(post, name, self) and I'm using MongoDB and pyramid_mongodb views.py: @view_config(context = Profile, renderer = 'templates/mytemplate.pt') def test_view(request): return {} and in mytemplate.pt: <p tal:repeat='item request.context'> ${item} </p> I can echo what's in the database (I'm using mongodb), but when I provided a URL for each item using resource_url() <p tal:repeat='item request.context'> <a href='${request.resource_url(item)}'>${item}</a> </p> I got an error: 'dict' object has no attribute '__name__', can someone help me?

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  • Accessing CSR extension stack in M2Crypto

    - by Charles Duffy
    Howdy! I have a certificate signing request with an extension stack added. When building a certificate based on this request, I would like to be able to access that stack to use in creating the final certificate. However, while M2Crypto.X509.X509 has a number of helpers for accessing extensions (get_ext, get_ext_at and the like), M2Crypto.X509.Request appears to provide only a member for adding extensions, but no way to inspect the extensions already associated with a given object. Am I missing something here?

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  • Validating key/certificate pairs with M2Crypto when a certificate chain is needed

    - by Charles Duffy
    M2Crypto.X509.X509 objects have a verify(pkey) method, which provide a means of testing that a given certificate does in fact sign a specified key. This is a good and useful thing -- except that sometimes the certificate I want to verify in this way is invalid without the use of an intermediate certificate, which this API does not appear to allow a way to specify. Is there an alternate means of validating a certificate / private key pair which will work even when the certificate is unable to stand alone?

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  • Estimating the boundary of arbitrarily distributed data

    - by Dave
    I have two dimensional discrete spatial data. I would like to make an approximation of the spatial boundaries of this data so that I can produce a plot with another dataset on top of it. Ideally, this would be an ordered set of (x,y) points that matplotlib can plot with the plt.Polygon() patch. My initial attempt is very inelegant: I place a fine grid over the data, and where data is found in a cell, a square matplotlib patch is created of that cell. The resolution of the boundary thus depends on the sampling frequency of the grid. Here is an example, where the grey region are the cells containing data, black where no data exists. OK, problem solved - why am I still here? Well.... I'd like a more "elegant" solution, or at least one that is faster (ie. I don't want to get on with "real" work, I'd like to have some fun with this!). The best way I can think of is a ray-tracing approach - eg: from xmin to xmax, at y=ymin, check if data boundary crossed in intervals dx y=ymin+dy, do 1 do 1-2, but now sample in y An alternative is defining a centre, and sampling in r-theta space - ie radial spokes in dtheta increments. Both would produce a set of (x,y) points, but then how do I order/link neighbouring points them to create the boundary? A nearest neighbour approach is not appropriate as, for example (to borrow from Geography), an isthmus (think of Panama connecting N&S America) could then close off and isolate regions. This also might not deal very well with the holes seen in the data, which I would like to represent as a different plt.Polygon. The solution perhaps comes from solving an area maximisation problem. For a set of points defining the data limits, what is the maximum contiguous area contained within those points To form the enclosed area, what are the neighbouring points for the nth point? How will the holes be treated in this scheme - is this erring into topology now? Apologies, much of this is me thinking out loud. I'd be grateful for some hints, suggestions or solutions. I suspect this is an oft-studied problem with many solution techniques, but I'm looking for something simple to code and quick to run... I guess everyone is, really! Cheers, David

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  • beautifulsoup can't find exist href in file

    - by young001
    I have a html file like following: <form action="/2811457/follow?gsid=3_5bce9b871484d3af90c89f37" method="post"> <div> <a href="/2811457/follow?page=2&amp;gsid=3_5bce9b871484d3af90c89f37">next_page</a> &nbsp;<input name="mp" type="hidden" value="3" /> <input type="text" name="page" size="2" style='-wap-input-format: "*N"' /> <input type="submit" value="jump" />&nbsp;1/3 </div> </form> how to extract the "1/3" from the file? It is a part of html,I intend to make it clear. When I use beautifulsoup, I'm new to beautifulsoup,and I have look the document,but still confused. how to extract"1/3" from the html file? total_urls_num = soup.find(re.compile('.*/d\//d.*')) doesn't work As JBernardo said,\d should be a number,When I change to .*\d/\d.*,it doesn't work too. my code: from BeautifulSoup import BeautifulSoup import re with open("html.txt","r") as f: response = f.read() print response soup = BeautifulSoup(response) delete_urls = soup.findAll('a', href=re.compile('follow\?page')) #works print delete_urls #total_urls_num = soup.find(re.compile('.*\d/\d.*')) total_urls_num = soup.find('input',style='submit') #can't work print total_urls_num

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  • Why is django.test.client.Client not keeping me logged in.

    - by Mystic
    I'm using django.test.client.Client to test whether some text shows up when a user is logged in. However, I the Client object doesn't seem to be keeping me logged in. This test passes if done manually with Firefox but not when done with the Client object. class Test(TestCase): def test_view(self): user.set_password(password) user.save() client = self.client # I thought a more manual way would work, but no luck # client.post('/login', {'username':user.username, 'password':password}) login_successful = client.login(username=user.username, password=password) # this assert passes self.assertTrue(login_successful) response = client.get("/path", follow=True) #whether follow=True or not doesn't seem to work self.assertContains(response, "needle" ) When I print response it returns the login form that is hidden by: {% if not request.user.is_authenticated %} ... form ... {% endif %} This is confirmed when I run ipython manage.py shell. The problem seems to be that the Client object is not keeping the session authenticated.

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  • How to display multiple images?

    - by misterwebz
    I'm trying to get multiple image paths from my database in order to display them, but it currently doesn't work. Here's what i'm using: def get_image(self, userid, id): image = meta.Session.query(Image).filter_by(userid=userid) permanent_file = open(image[id].image_path, 'rb') if not os.path.exists(image.image_path): return 'No such file' data = permanent_file.read() permanent_file.close() response.content_type = guess_type(image.image_path)[0] or 'text/plain' return data I'm getting an error regarding this part: image[id].image_path What i want is for Pylons to display several jpg files on 1 page. Any idea how i could achieve this?

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  • Distance between numpy arrays, columnwise

    - by Jaapsneep
    I have 2 arrays in 2D, where the column vectors are feature vectors. One array is of size F x A, the other of F x B, where A << B. As an example, for A = 2 and F = 3 (B can be anything): arr1 = np.array( [[1, 4], [2, 5], [3, 6]] ) arr2 = np.array( [[1, 4, 7, 10, ..], [2, 5, 8, 11, ..], [3, 6, 9, 12, ..]] ) I want to calculate the distance between arr1 and a fragment of arr2 that is of equal size (in this case, 3x2), for each possible fragment of arr2. The column vectors are independent of each other, so I believe I should calculate the distance between each column vector in arr1 and a collection of column vectors ranging from i to i + A from arr2 and take the sum of these distances (not sure though). Does numpy offer an efficient way of doing this, or will I have to take slices from the second array and, using another loop, calculate the distance between each column vector in arr1 and the corresponding column vector in the slice?

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  • Sqlalchemy complex in_ clause

    - by lostlogic
    I'm trying to find a way to cause sqlalchemy to generate sql of the following form: select * from t where (a,b) in ((a1,b1),(a2,b2)); Is this possible? If not, any suggestions on a way to emulate it? Thanks kindly!

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  • Search for a String and replace it with a variable

    - by chrissygormley
    Hello, I am trying to use regular expression to search a document fo a UUID number and replace the end of it with a new number. The code I have so far is: read_file = open('test.txt', 'r+') write_file = open('test.txt', 'w') r = re.compile(r'(self.uid\s*=\s*5EFF837F-EFC2-4c32-A3D4\s*)(\S+)') for l in read_file: m1 = r.match(l) if m1: new=(str,m1.group(2)) new?????? This where I get stuck. The file test.txt has the below UUID stored in it: self.uid = '5EFF837F-EFC2-4c32-A3D4-D15C7F9E1F22' I want to replace the part D15C7F9E1F22. I have also tried this: r = re.compile(r'(self.uid\s*=\s*)(\S+)') for l in fp: m1 = r.match(l) new=map(int,m1.group(2).split("-") new[4]='RHUI5345JO' But I cannot seem to match the string. Thanks in advance for any help.

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  • Creating form object for variable kind of form.

    - by Bunny Rabbit
    i want to create a form for users to submit questions in django ..so far the models i have created are class Question(models.Model): statement=models.CharField(max_length=100) class Choice(models.Model): statement=models.CharField(max_length=100) value=models.IntegerField() question=models.ForeignKey(Question) Now i want to write a Form class for creating a above form but the problem is the number of choices are variable,a user can decide how many choices a question must have .How do i do that in django?

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  • Connecting slots and events in PyQt4 in a loop

    - by LukaD
    Im trying to build a calculator with PyQt4 and connecting the 'clicked()' signals from the buttons doesn't as expected. Im creating my buttons for the numbers inside a for loop where i try to connect them afterwards. def __init__(self): for i in range(0,10): self._numberButtons += [QPushButton(str(i), self)] self.connect(self._numberButtons[i], SIGNAL('clicked()'), lambda : self._number(i)) def _number(self, x): print(x) When I click on the buttons all of them print out '9'. Why is that so and how can i fix this?

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  • Moving a turtle to the center of a circle.

    - by Maggie
    I've just started using the turtle graphics program, but I can't figure out how to move the turtle automatically to the center of a circle (no matter where the circle is located) without it drawing any lines. I thought I could use the goto.() function but it's too specific and I need something general.

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  • cx_Oracle and output variables

    - by Tim
    I'm trying to do this again an Oracle 10 database: cursor = connection.cursor() lOutput = cursor.var(cx_Oracle.STRING) cursor.execute(""" BEGIN %(out)s := 'N'; END;""", {'out' : lOutput}) print lOutput.value but I'm getting DatabaseError: ORA-01036: illegal variable name/number Is it possible to define PL/SQL blocks in cx_Oracle this way?

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  • How different protocols interact with eachother in Twisted

    - by stsupermouse
    The scenario I want two different protocols interact with each other is as below: A and B is two different protocols. First A will interact with the server and retrieve some values. Only after A finishes retrieving the values , B will start to interact with the server. Now my problem is that is there an elegant way to initial B when A retrieves the values. Currently I just initial B in A's data process function. But i don't think that this is an elegant way. What I mean an elegant way is that the initialization of B is done by a flow controller or something like that, but not another protocol. Is there an elegant way? such using defered or any other things. I'm just new to twisted, not knowing very much about defered.... Thank you very much!

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  • Find next lower item in a sorted list

    - by Sebastian
    Hey guys, let's say I have a sorted list of Floats. Now I'd like to get the index of the next lower item of a given value. The usual for-loop aprroach has a complexity of O(n). Since the list is sorted there must be a way to get the index with O(log n). My O(n) approach: index=0 for i,value in enumerate(mylist): if value>compareValue: index=i-1 Is there a datatype for solving that problem in O(log n)? best regards Sebastian

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  • remove border of a gtk.button

    - by spanctus
    Hi, I want to remove the border of the gtk.button, but i Don't know how to do it. I tried with : button = gtk.Button() button.set_style("inner-border",0) but i have an error : the property doesn't exist. I tried too to create a new gtk.Style and use it for the button, but same error. Anyone has an idea ? Thanks

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  • Can pydoc/help hide the documentation for inherited class methods and attributes?

    - by EOL
    When declaring a class that inherits from a specific class: class C(dict): added_attribute = 0 the documentation for C lists all the methods of dict (either through help(C) or pydoc). Is there a way to hide the inherited methods from the automatically generated documentation (the documentation string can refer to the base class, for non-overwritten methods)? This would be useful: pydoc lists the functions defined in a module after its classes. Thus, when the classes have a very long documentation, a lot of less than useful information is printed before the new functions provided by the module are presented, which makes the documentation harder to exploit (you have to skip all the documentation for the inherited methods until you reach something specific to the module being documented).

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