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  • SQLite3 and "cascade" SELECTion

    - by SK9
    I have a parent table and a child table related to the parent table by some REFERENCE. Suppose I exec a SELECT statement on the child and that it returns the at least one result. Can I arrange for my search to automatically yield all the content of all related parents with this child too? Or must I always take the reference from the child and put this in a second SELECT statement and exec this myself?

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  • display php foreach values in div

    - by San82moon
    Hi, I have foreach ($a as $key = $value) { echo $value; } which displays result one below other, like 1234 5678 2010-05-20 5678 1590 2010-05-19 but i want it in a table like structure like 1234 5678 2010-05-20 5678 1590 2010-05-19 how can i do that?

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  • How to store opening weekdays in a database

    - by JoaoPedro
    I have a group of checkboxes where the user selects some of the weekdays (the opening days of a store). How can I save the selected days? Should I save something like 0111111 (zero means closed on sunday) on the same field and split the result when reading the data? Or create a field for each day and store 0 or 1 on each (weird)?

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  • MySQL, how to use returned data?

    - by aejo
    Well, I know there is a funciton mysql_fetch_array() and we can use it like this: while ($row = mysql_fetch_array($result)) { echo $row['name'] . "<br />"; } But is there any other way? For example, if there is only one element that can be returned, and not an array. Thanks)

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  • How to search mulitple value seperated by commas in mysql

    - by Fero
    Hi all, How to search multiple values separated by commas. ex: table name : searchTest id name keyword 1 trophy1 test1,test2,test3 2 trophy2 test2,test5 Points: If i search for test2 both results trophy1 and trophy2 should be display. If i search for trophy1 then trophy1 should be as result. How to solve this issue. thanks in advance

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  • fill array with binary numbers

    - by davit-datuashvili
    hi, first of all this is not homework!! my question is from book: Algorithms in C++ third edition by robert sedgewick question is: there is given array of size n by 2^n(two dimensional) and we should fill it by binary numbers with bits size exactly n or for example n=5 so result will be 00001 00010 00011 00100 00101 00110 00111 and so on we should put this sequence of bits into arrays please help me

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  • How to understand such C macro expansion

    - by upton
    A macro definition: #define HTTP_ERRNO_MAP(XX) \ /* No error */ \ XX(OK, "success") \ \ /* Callback-related errors */ \ XX(CB_message_begin, "the on_message_begin callback failed") \ XX(CB_url, "the on_url callback failed") \ /* Define HPE_* values for each errno value above */ #define HTTP_ERRNO_GEN(n, s) HPE_##n, enum http_errno { HTTP_ERRNO_MAP(HTTP_ERRNO_GEN) }; #undef HTTP_ERRNO_GEN After expand it by "gcc -E", enum http_errno { HPE_OK, HPE_CB_message_begin, HPE_CB_url,}; How does the macro expand to the result?

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  • Oracle - Count distinct values of a column

    - by Luciana Borela
    Hi I have this table: Reason|Area_Code|Id x dig 1 x dig 2 y dig 3 h util 4 x dig 5 I'm trying for a SQL that returns: Reason|Amount of distinct Reason|Area_code x 3 dig y 1 dig h 1 util I will use this result to plot a chart. I don´t have any idea on how this SQL can be done. Could you help me?

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  • Select only half the records

    - by coffeeaddict
    I am trying to figure out how to select half the records where an ID is null. I want half because I am going to use that result set to update another ID field. Then I am going to update the rest with another value for that ID field. So essentially I want to update half the records someFieldID with one number and the rest with another number splitting the update basically between two values for someFieldID the field I want to update.

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  • How to Count tickets as DateWise

    - by user560716
    I have a query regarding my report, the report format is as under **Date** **Received** **Closed** **Pending** 12/01/10 1000 900 100 12/02/10 2000 1000 1000 12/03/10 1500 1300 200 The above report shows the Help Desk tickets Received, Closed, Pending Count as date wise. How can I create a dynamic SQL query to show above result? Received Tickets is calculated on SubmitedDate Closed Tickets is calculated on ClosedDate with status "Closed" same for Pending Tickets whose status is "Pending". Please provide me the idea or some sample SQL queries.

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  • Difference between "and" and "where" in joins

    - by Midhat
    Whats the difference between SELECT DISTINCT field1 FROM table1 cd JOIN table2 ON cd.Company = table2.Name and table2.Id IN (2728) and SELECT DISTINCT field1 FROM table1 cd JOIN table2 ON cd.Company = table2.Name where table2.Id IN (2728) both return the same result and both have the same explain output

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  • New help with SQL Server select statement

    - by gio_333m
    I need help with select statement in SQL Server / T-SQL My table looks like this: Id (int) QuestionId (int) GenreId (int) I want to select random N rows from this table so that maximum number of same GenreId in the result set is less than X for all GenreId-s except one. For that one GenreId, I need row count with that GenreId to be equal to Y.

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  • join two tables but want one matching columns instead of showing it separately sql server 2008

    - by amby
    Hi i want to display join result of two tables but don't want to show matching column separately. I want it one instead of two. so please tell me what query should i use for this. I m using sql server 2008 and my query is like: select * from Customer_Order, optRelation where Customer_Order.orderNumber = optRelation.orderNumber AND optRelation.orderNumber = 21. please reply soon

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  • Selecting count(*) while checking for a value in the results

    - by Rob
    SELECT COUNT(*) as Count, IF(sch.HomeTeamID = 34,true,false) AS Hawaii FROM schedule sch JOIN schools s ON s.ID = 83 WHERE (sch.HomeTeamID = 83 OR sch.AwayTeamID = 83) AND sch.SeasonID = 4 I'm trying to use count() to simplify my result but also include a field that represents wether any of the results' specific column contained a certain value. Is this possible? I'd basically like a row response with all the info I need.

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  • How do I pass a conditional expression as a parameter in Ruby?

    - by srayhan
    For example this what I am trying to do, def method_a(condition, params={}, &block) if condition method_b(params, &block) else yield end end and I am trying to call the method like this, method_a(#{@date > Date.today}, {:param1 => 'value1', :param2 => 'value2'}) do end The result is the condition is always evaluated to true. How do I make it work?

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  • piping to variables

    - by lego69
    cut -d" " -f2 ${2} | $callsTo hello, can somebody please explain can I pipe the result of cut to variable callsTo, and how will it be stored, as the string or list?

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  • Float to binary in C++

    - by Eric
    Hi, I'm wondering if there is a way to represent a float using a char in C++? For example: int main() { float test = 4.7567; char result = charRepresentation(test); return 0; } I read that probably using bitset I can do it but I'm not pretty sure.

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  • How To Get YEARWEEK() To See Sunday As The Start Of The Week?

    - by tan
    I'm trying to get the YEARWEEK function to see Sunday as the 1st day of the week. An example date is: Sunday 1st Mar 2009 Here is my sql SELECT YEARWEEK('2009-03-01') and the result is - 200909 Which is week 9. I believe it is telling me this is week 9 because it sees the sunday as the last day of the previous week. How would I get this function to see sunday as the 1st day of the week and therefore return as week 10?

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  • Why does (360 / 24) / 60 = 0 ... in Java

    - by Ankur
    I am trying to compute (360 / 24) / 60 I keep getting the answer 0.0 when I should get 0.25 In words: I want to divide 360 by 24 and then divide the result by 60 public class Divide { public static void main(String[] args){ float div = ((360 / 24) / 60); System.out.println(div); } } This prints out: 0.0 Why is that? Am I doing something really stupid, or is there a good reason for this

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  • mysql search using for loop from php.

    - by deb
    hi, i am a beginner. but I'm practicing a lot for few days with php mysql, and I am trying to use for loop to search an exploded string, one by one from mysql server. Till now I have no results. I'm giving my codes, <?php // Example 1 $var = @$_GET['s'] ; $limit=500; echo " "; echo "$var"; echo " "; $trimmed_array = explode(" ", $var); echo "$trimmed_array[0]"; // piece1 echo " "; $count= count($trimmed_array); echo $count; for($j=0;$j<$count;$j++) { e cho "$trimmed_array[$j]";; echo " "; } echo " "; for($i=0; $i<$count ; $i++){ $query = "select * from book where name like \"%$trimmed_array[$i]%\" order by name"; $numresults=mysql_query($query); $numrows =mysql_num_rows($numresults); if ($numrows == 0) { echo "<h4>Results</h4>"; echo "<p>Sorry, your search: &quot;" . $trimmed_array[i] . "&quot; returned zero results</p>"; } if (empty($s)) { $s=0; } $query .= " limit $s,$limit"; $result = mysql_query($query) or die("Couldn't execute query"); echo "<p>You searched for: &quot;" . $var . "&quot;</p>"; echo "Results<br /><br />"; $count=1; while ($row= mysql_fetch_array($result)) { $name = $row["name"]; $publisher=$row["publisher"]; $total=$row["total"]; $issued=$row["issued"]; $available=$row["available"]; $category=$row["category"]; echo "<table border='1'><tr><td>$count)</td><td>$name&nbsp;</td><td>$publisher&nbsp;</td><td>$total&nbsp;</td><td>$issued&nbsp;</td><td>$available&nbsp;</td><td>$category&nbsp;</td></tr></table>" ; $count++ ; } } ?>

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  • How to execute query with empty fields?

    - by Kliver Max
    I have a SQL Query: SELECT documents.*, t_rights.rights, documents_list.docs FROM documents INNER JOIN t_rights on t_rights.num=documents.type_right INNER JOIN documents_list on documents_list.num=documents.document1 WHERE code_document=1 or code_document=1 In case if i have fields documents.document1 and documents.document1 with some value all works fine. But if this field empty i get empty query result. Its possible make query like this with empty fields?

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