Search Results

Search found 20677 results on 828 pages for 'python team'.

Page 379/828 | < Previous Page | 375 376 377 378 379 380 381 382 383 384 385 386  | Next Page >

  • Perceptron Classification and Model Training

    - by jake pinedo
    I'm having an issue with understanding how the Perceptron algorithm works and implementing it. cLabel = 0 #class label: corresponds directly with featureVectors and tweets for m in range(miters): for point in featureVectors: margin = answers[cLabel] * self.dot_product(point, w) if margin <= 0: modifier = float(lrate) * float(answers[cLabel]) modifiedPoint = point for x in modifiedPoint: if x != 0: x *= modifier newWeight = [modifiedPoint[i] + w[i] for i in range(len(w))] w = newWeight self._learnedWeight = w This is what I've implemented so far, where I have a list of class labels in answers and a learning rate (lrate) and a list of feature vectors. I run it for the numbers of iterations in miter and then get the final weight at the end. However, I'm not sure what to do with this weight. I've trained the perceptron and now I have to classify a set of tweets, but I don't know how to do that. EDIT: Specifically, what I do in my classify method is I go through and create a feature vector for the data I'm given, which isn't a problem at all, and then I take the self._learnedWeight that I get from the earlier training code and compute the dot-product of the vector and the weight. My weight and feature vectors include a bias in the 0th term of the list so I'm including that. I then check to see if the dotproduct is less than or equal to 0: if so, then I classify it as -1. Otherwise, it's 1. However, this doesn't seem to be working correctly.

    Read the article

  • How to share memory buffer across sessions in Django?

    - by afriza
    I want to have one party (or more) sends a stream of data via HTTP request(s). Other parties will be able to receive the same stream of data in almost real-time. The data stream should be accessible across sessions (according to access control list). How can I do this in Django? If possible I would like to avoid database access and use in memory buffer (along with some synchronization mechanism)

    Read the article

  • How do i use repoze.who?

    - by misterwebz
    I'm having some trouble understanding how repoze.who works. I've followed a tutorial i found by searching on google and here's what i already have: This is what i added in my middleware.py file from repoze.who.config import make_middleware_with_config as make_who_with_config app = make_who_with_config(app, global_conf, app_conf['who.config_file'], app_conf['who.log_file'], app_conf['who.log_level']) Here's the who.ini : http://pastebin.com/w5Tba2Fp Here's repoze_auth.py in /lib/auth/: from paste.httpexceptions import HTTPFound from iwant.model import User class UserModelPlugin(object): def authenticate(self, environ, identity): try: username = identity['login'] password = identity['password'] except KeyError: return None success = User.authenticate(username, password) return success def add_metadata(self, environ, identity): username = identity.get('repoze.who.userid') user = User.get(username) if user is not None: identity['user'] = user I've also checked the plugins in the repoze.who folder, but i failed to understand how it's supposed to be used. I'd appreciate it if someone would push me in the right direction.

    Read the article

  • Loading Files in AppEngine

    - by Chris M
    I've got a tiny bit of code to display a file in app.yaml - url: /(.*\.(gif|png|jpg)) static_files: static/\1 upload: static/(.*\.(gif|png|jpg)) in main.py ... class ShowImage(webapp.RequestHandler): def get(self): rootpath = os.path.dirname(__file__) file = rootpath + "/static/tracker.gif"; fh=open(file, 'r') self.response.out.write(fh.read()) fh.close ... I can see the files gone up by going to my *.appspot.com/tracker.gif (as per the app.yaml) But using *.appspot.com/showimage returns Traceback (most recent call last): File "/base/python_lib/versions/1/google/appengine/ext/webapp/__init__.py", line 510, in __call__ handler.get(*groups) File "/base/data/home/apps/APPNAME/2.341131266814384624/main.py", line 170, in get fh=open(file, 'r') IOError: [Errno 2] No such file or directory: '/base/data/home/apps/APPNAME/2.341131266814384624/static/tracker.gif'

    Read the article

  • Modern, Non-trivial, Pygame Tutorials?

    - by Gregg Lind
    What are some 'good', non-trivial Pygame tutorials? I realize good is relative. As an example, a good one (to me) is the one that describes how to use pygame.camera. It's recent uses a modern PyGame (1.9) non-trivial, in that it shows how to use it the module for a real application. I'd like to find others. A lot of the ones on the Pygame site are from 1.3 era or earlier! Info on related projects, like Gloss is welcome as well. (If your answer is "read the source of some pygame games", please link to the source of particular ones and note what is good about them)

    Read the article

  • How to add a separator in a PyGTK combobox?

    - by mkotechno
    I'm using gtk.combo_box_new_text() to make combobox list, this uses a gtk.ListStore to store only strings, so there are some way to add a separator between items without use a complex gtk.TreeModel? If this is not possible, what is the simplest way to use a gtk.TreeModel to able secuential widget addition?

    Read the article

  • pyparsing ambiguity

    - by Claudiu
    I'm trying to parse some text using PyParser. The problem is that I have names that can contain white spaces. So my input might look like this: Joe Bob Jimmy Foo Joe decides to eat. Bob decides to not eat. Jimmy Foo decides to eat. How can I create a parser for the decides to eat line? If I create my name parser naively, meaning with alphabetic characters plus space characters, then it will match the entire line.

    Read the article

  • Inside a decorator-class, access instance of the class which contains the decorated method

    - by ifischer
    I have the following decorator, which saves a configuration file after a method decorated with @saveconfig is called: class saveconfig(object): def __init__(self, f): self.f = f def __call__(self, *args): self.f(object, *args) # Here i want to access "cfg" defined in pbtools print "Saving configuration" I'm using this decorator inside the following class. After the method createkvm is called, the configuration object self.cfg should be saved inside the decorator: class pbtools() def __init__(self): self.configfile = open("pbt.properties", 'r+') # This variable should be available inside my decorator self.cfg = ConfigObj(infile = self.configfile) @saveconfig def createkvm(self): print "creating kvm" My problem is that i need to access the object variable self.cfg inside the decorator saveconfig. A first naive approach was to add a parameter to the decorator which holds the object, like @saveconfig(self), but this doesn't work. How can I access object variables of the method host inside the decorator? Do i have to define the decorator inside the same class to get access?

    Read the article

  • Can a CLSID be different for the same program installed on two different machines?

    - by uberjumper
    I am using comtypes to generate wrappers for a certain com library. I am having certain issues with a few things, that are not being generated properly. I can get around this by doing the missing work, manually. However can i depend on the fact that CLSID's will not change? Lets say: I install a program with the com library Foo 1.0, now i install the exact same version of that program on another PC, will the CLSID's of the interfaces change? This might be a terribly dumb question.

    Read the article

  • load a pickle file from a zipfile

    - by eric.frederich
    For some reason I cannot get cPickle.load to work on the file-type object returned by ZipFile.open(). If I call read() on the file-type object returned by ZipFile.open() I can use cPickle.loads though. Example .... import zipfile import cPickle # the data we want to store some_data = {1: 'one', 2: 'two', 3: 'three'} # # create a zipped pickle file # zf = zipfile.ZipFile('zipped_pickle.zip', 'w', zipfile.ZIP_DEFLATED) zf.writestr('data.pkl', cPickle.dumps(some_data)) zf.close() # # cPickle.loads works # zf = zipfile.ZipFile('zipped_pickle.zip', 'r') sd1 = cPickle.loads(zf.open('data.pkl').read()) zf.close() # # cPickle.load doesn't work # zf = zipfile.ZipFile('zipped_pickle.zip', 'r') sd2 = cPickle.load(zf.open('data.pkl')) zf.close() Note: I don't want to zip just the pickle file but many files of other types. This is just an example.

    Read the article

  • How do I pass a lot of parameters to views in Dango?

    - by Mark
    I'm very new to Django and I'm trying to build an application to present my data in tables and charts. Till now my learning process went very smooth, but now I'm a bit stuck. My pageview retrieves large amounts of data from a database and puts it in the context. The template then generates different html-tables. So far so good. Now I want to add different charts to the template. I manage to do this by defining <img src=".../> tags. The Matplotlib chart is generate in my chartview an returned via: response=HttpResponse(content_type='image/png') canvas.print_png(response) return response Now I have different questions: the data is retrieved twice from the database. Once in the pageview to render the tables, and again in the chartview for making the charts. What is the best way to pass the data, already in the context of the page to the chartview? I need a lot of charts, each with different datasets. I could make a chartview for each chart, but probably there is a better way. How do I pass the different dataset names to the chartview? Some charts have 20 datasets, so I don't think that passing these dataset parameters via the url (like: <imgm src="chart/dataset1/dataset2/.../dataset20/chart.png />) is the right way. Any advice?

    Read the article

  • wx Menu disappears from frame when shown as a popup

    - by Adam Fraser
    I'm trying to create a wx.Menu that will be shared between a popup (called on right-click), and a sub menu accessible from the frame menubar. The following code demonstrates the problem. If you open the "MENUsubmenu" from the menubar the item "asdf" is visible. If you right click on the frame content area, "asdf" will be visible from there as well... however, returning to the menubar, you will find that "MENUsubmenu" is vacant. Why is this happening and how can I fix it? import wx app = wx.PySimpleApp() m = wx.Menu() m.Append(-1, 'asdf') def show_popup(evt): ''' R-click callback ''' f.PopupMenu(m, (evt.X, evt.Y)) f = wx.Frame(None) f.SetMenuBar(wx.MenuBar()) frame_menu = wx.Menu() f.MenuBar.Append(frame_menu, 'MENU') frame_menu.AppendMenu(-1,'submenu', m) f.Show() f.Bind(wx.EVT_RIGHT_DOWN, show_popup) app.MainLoop() Interestingly, appending the menu to MenuBar works, but is not the behavior I want: import wx app = wx.PySimpleApp() m = wx.Menu() m.Append(-1, 'asdf') def show_popup(evt): f.PopupMenu(m, (evt.X, evt.Y)) f = wx.Frame(None) f.SetMenuBar(wx.MenuBar()) f.MenuBar.Append(m, 'MENU') f.Show() f.Bind(wx.EVT_RIGHT_DOWN, show_popup) app.MainLoop()

    Read the article

  • Javascript with Django?

    - by Rosarch
    I know this has been asked before, but I'm having a hard time setting up JS on my Django web app, even though I'm reading the documentation. I'm running the Django dev server. My file structure looks like this: mysite/ __init__.py MySiteDB manage.py settings.py urls.py myapp/ __init__.py admin.py models.py test.py views.py templates/ index.html Where do I want to put the Javascript and CSS? I've tried it in a bunch of places, including myapp/, templates/ and mysite/, but none seem to work. From index.html: <head> <title>Degree Planner</title> <script type="text/javascript" src="/scripts/JQuery.js"></script> <script type="text/javascript" src="/media/scripts/sprintf.js"></script> <script type="text/javascript" src="/media/scripts/clientside.js"></script> </head> From urls.py: (r'^admin/', include(admin.site.urls)), (r'^media/(?P<path>.*)$', 'django.views.static.serve', {'document_root': 'media'}) (r'^.*', 'mysite.myapp.views.index'), I suspect that the serve() line is the cause of errors like: TypeError at /admin/auth/ 'tuple' object is not callable Just to round off the rampant flailing, I changed these settings in settings.py: MEDIA_ROOT = '/media/' MEDIA_URL = 'http://127.0.0.1:8000/media'

    Read the article

  • Refining data stored in SQLite - how to join several contacts?

    - by Krab
    Problem background Imagine this problem. You have a water molecule which is in contact with other molecules (if the contact is a hydrogen bond, there can be 4 other molecules around my water). Like in the following picture (A, B, C, D are some other atoms and dots mean the contact). A B . . O / \ H H . . C D I have the information about all the dots and I need to eliminate the water in the center and create records describing contacts of A-C, A-D, A-B, B-C, B-D, and C-D. Database structure Currently, I have the following structure in the database: Table atoms: "id" integer PRIMARY KEY, "amino" char(3) NOT NULL, (HOH for water or other value) other columns identifying the atom Table contacts: "acceptor_id" integer NOT NULL, (the atom near to my hydrogen, here C or D) "donor_id" integer NOT NULL, (here A or B) "directness" char(1) NOT NULL, (this should be D for direct and W for water-mediated) other columns about the contact, such as the distance Current solution (insufficient) Now, I'm going through all the contacts which have donor.amino = "HOH". In this sample case, this would select contacts from C and D. For each of these selected contacts, I look up contacts having the same acceptor_id as is the donor_id in the currently selected contact. From this information, I create the new contact. At the end, I delete all contacts to or from HOH. This way, I am obviously unable to create C-D and A-B contacts (the other 4 are OK). If I try a similar approach - trying to find two contacts having the same donor_id, I end up with duplicate contacts (C-D and D-C). Is there a simple way to retrieve all six contacts without duplicates? I'm dreaming about some one page long SQL query which retrievs just these six wanted rows. :-) It is preferable to conserve information about who is donor where possible, but not strictly necessary. Big thanks to all of you who read this question to this point.

    Read the article

  • Silence output from SimpleXMLRPCServer

    - by Corey Goldberg
    I am running an xml-rpc server using SimpleXMLRPCServer from the stdlib. My code looks something like this: import SimpleXMLRPCServer import socket class RemoteStarter: def start(self): return 'foo' rs = RemoteStarter() host = socket.gethostbyaddr(socket.gethostname())[0] port = 9000 server = SimpleXMLRPCServer.SimpleXMLRPCServer((host, port)) server.register_instance(rs) server.serve_forever() every time the 'start' method gets called remotely, the server prints an access line like this: <server_name> - - [10/Mar/2010 13:06:20] "POST /RPC2 HTTP/1.0" 200 - I can't figure out a way to silence the output so it doesn't print these access lines to stdout. anyone?

    Read the article

  • Is there a way in Sphinx/Pygments to emphasize one or more lines of code in literal includes?

    - by Casey
    In some sphinx docs I am writing, I am including code samples from an ancillary file like so: .. literalinclude:: mymodule.py :pyobject: MyClass :linenos: This particular doc is a tutorial, where the classes are build up step by step. What I would like to do is include the entire class or a single method, and emphasize only the lines of interest to that section. That way the context is preserved but the interesting parts are obvious at a glance. Right now I have resorted to just referring to line numbers in the text, which is ok, but far from ideal. Looking at the docs and code for sphinx and pygments I don't find an obvious way to do this. I'm not opposed to patching them or doing something tricky in conf.py, but I wondered if anyone had solved this.

    Read the article

  • Real-time data on webpage with jQuery

    - by Steven Hepting
    I would like a webpage that constantly updates a graph with new data as it arrives. Regularly, all the data you have is passed to the page at the beginning of the request. However, I need the page to be able to update itself with fresh information every few seconds to redraw the graph. Background The webpage will be similar to this http://www.panic.com/blog/2010/03/the-panic-status-board/. The data coming in will temperature values to be graphed measured by an Arduino and saved to the Django database (this part is already complete). Update It sounds as though the solution is to use the jQuery.ajax() function ( http://api.jquery.com/jQuery.ajax/) with a function as the .complete callback that will schedule another request several seconds later to a URL that will return the data in JSON format. How can that method be scheduled? With the .delay() function?

    Read the article

  • Stream a file to the HTTP response in Pylons

    - by Evgeny
    I have a Pylons controller action that needs to return a file to the client. (The file is outside the web root, so I can't just link directly to it.) The simplest way is, of course, this: with open(filepath, 'rb') as f: response.write(f.read()) That works, but it's obviously inefficient for large files. What's the best way to do this? I haven't been able to find any convenient methods in Pylons to stream the contents of the file. Do I really have to write the code to read a chunk at a time myself from scratch?

    Read the article

< Previous Page | 375 376 377 378 379 380 381 382 383 384 385 386  | Next Page >