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  • Float compile-time calculation not happening?

    - by Klaim
    A little test program: #include <iostream> const float TEST_FLOAT = 1/60; const float TEST_A = 1; const float TEST_B = 60; const float TEST_C = TEST_A / TEST_B; int main() { std::cout << TEST_FLOAT << std::endl; std::cout << TEST_C << std::endl; std::cin.ignore(); return 0; } Result : 0 0.0166667 Tested on Visual Studio 2008 & 2010. I worked on other compilers that, if I remember well, made the first result like the second result. Now my memory could be wrong, but shouldn't TEST_FLOAT have the same value than TEST_C? If not, why? Is TEST_C value resolved at compile time or at runtime? I always assumed the former but now that I see those results I have some doubts...

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  • Date format error in vb.net ?

    - by ahmed
    I get this error when I run the application Incorrect syntax near 12, on debugging I found that this error is caused due to the # along with the date. Dim backdate as datetime backdate = DateTime.Now.AddDays(-1) on binding the data to the grid to filter the backdate records this error is caused Incorrect syntax near 12. myqry = " select SRNO,SUBJECT,ID where datesend =" backdate Now i am trying to extract only the date or shall I divide the date into day , month and year with DATEPART and take into a variable or convert the date or what should i do , Please help ???

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  • How to choose my own filename format for subscribed podcast files?

    - by meomaxy
    I subscribe to several podcasts where the filenames of the downloaded mp3 files have no particular pattern to them. When I copy the directory of accumulated mp3 files into my mp3 player, the files play in alphabetical order. What I really want is to play the files chronologically by release date. I currently use iTunes on Windows XP to download the files. What I do now is manually rename the files, adding the date in YYYYMMDD format to the start of each filename so that an alphabetical listing of files will correspond to their chronological order when I listen to them later in PocketTunes on my Palm Centro. Is there some way to get the release date into the filename automatically? If so, I could automate or possibly skip the file renaming step. I would switch from iTunes to something else if that would solve my problem. The file creation time on my local disk isn't a reliable indicator because sometimes I download a few days worth of content at one time, and the files don't necessarily get downloaded in chronological order.

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  • recursion tree and binary tree cost calculation

    - by Tony
    Hi all, I've got the following recursion: T(n) = T(n/3) + T(2n/3) + O(n) The height of the tree would be log3/2 of 2. Now the recursion tree for this recurrence is not a complete binary tree. It has missing nodes lower down. This makes sense to me, however I don't understand how the following small omega notation relates to the cost of all leaves in the tree. "... the total cost of all leaves would then be Theta (n^log3/2 of 2) which, since log3/2 of 2 is a constant strictly greater then 1, is small omega(n lg n)." Can someone please help me understand how the Theta(n^log3/2 of 2) becomes small omega(n lg n)?

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  • Efficient calculation of matrix cumulative standard deviation in r

    - by Abiel
    I recently posted this question on the r-help mailing list but got no answers, so I thought I would post it here as well and see if there were any suggestions. I am trying to calculate the cumulative standard deviation of a matrix. I want a function that accepts a matrix and returns a matrix of the same size where output cell (i,j) is set to the standard deviation of input column j between rows 1 and i. NAs should be ignored, unless cell (i,j) of the input matrix itself is NA, in which case cell (i,j) of the output matrix should also be NA. I could not find a built-in function, so I implemented the following code. Unfortunately, this uses a loop that ends up being somewhat slow for large matrices. Is there a faster built-in function or can someone suggest a better approach? cumsd <- function(mat) { retval <- mat*NA for (i in 2:nrow(mat)) retval[i,] <- sd(mat[1:i,], na.rm=T) retval[is.na(mat)] <- NA retval } Thanks.

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  • Optimal two variable linear regression calculation

    - by Dave Jarvis
    Problem Am looking to apply the y = mx + b equation (where m is SLOPE, b is INTERCEPT) to a data set, which is retrieved as shown in the SQL code. The values from the (MySQL) query are: SLOPE = 0.0276653965651912 INTERCEPT = -57.2338357550468 SQL Code SELECT ((sum(t.YEAR) * sum(t.AMOUNT)) - (count(1) * sum(t.YEAR * t.AMOUNT))) / (power(sum(t.YEAR), 2) - count(1) * sum(power(t.YEAR, 2))) as SLOPE, ((sum( t.YEAR ) * sum( t.YEAR * t.AMOUNT )) - (sum( t.AMOUNT ) * sum(power(t.YEAR, 2)))) / (power(sum(t.YEAR), 2) - count(1) * sum(power(t.YEAR, 2))) as INTERCEPT, FROM (SELECT D.AMOUNT, Y.YEAR FROM CITY C, STATION S, YEAR_REF Y, MONTH_REF M, DAILY D WHERE -- For a specific city ... -- C.ID = 8590 AND -- Find all the stations within a 15 unit radius ... -- SQRT( POW( C.LATITUDE - S.LATITUDE, 2 ) + POW( C.LONGITUDE - S.LONGITUDE, 2 ) ) < 15 AND -- Gather all known years for that station ... -- S.STATION_DISTRICT_ID = Y.STATION_DISTRICT_ID AND -- The data before 1900 is shaky; insufficient after 2009. -- Y.YEAR BETWEEN 1900 AND 2009 AND -- Filtered by all known months ... -- M.YEAR_REF_ID = Y.ID AND -- Whittled down by category ... -- M.CATEGORY_ID = '001' AND -- Into the valid daily climate data. -- M.ID = D.MONTH_REF_ID AND D.DAILY_FLAG_ID <> 'M' GROUP BY Y.YEAR ORDER BY Y.YEAR ) t Data The data is visualized here: Question The following results (to calculate the start and end points of the line) appear incorrect. Why are the results off by ~10 degrees (e.g., outliers skewing the data)? (1900 * 0.0276653965651912) + (-57.2338357550468) = -4.66958228 (2009 * 0.0276653965651912) + (-57.2338357550468) = -1.65405406 I would have expected the 1900 result to be around 10 (not -4.67) and the 2009 result to be around 11.50 (not -1.65). Related Sites Least absolute deviations Robust regression Thank you!

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  • Use boost date_time to parse and create HTTP-dates

    - by John Price
    I'm writing a kind of HTTP proxy, so I need to be able to do 3 things: Parse an HTTP-date given any of the 3 formats specified in RFC 2616, sec 3.3, Convert a file date-time to an HTTP-date string, and Output the date to a string. For reference, theses are examples of the date-times I need to parse. I will output only the first format: Sun, 06 Nov 1994 08:49:37 GMT ; RFC 822, updated by RFC 1123 Sunday, 06-Nov-94 08:49:37 GMT ; RFC 850, obsoleted by RFC 1036 Sun Nov 6 08:49:37 1994 ; ANSI C's asctime() format I'm pretty sure Boost date_time can do all of this, but I'm having some trouble with number 1. Does anyone already have code to do this? Perhaps I'm not using google proficiently, but I can't find an example of how to do this with boost anywhere. Thanks for any help!

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  • Selecting rows without a value for Date/Time columns

    - by Ross
    I'm running this query: SELECT TOP 1 [DVD Copy].[Stock No] FROM [DVD Copy] WHERE [DVD Copy].[Catalogue No] =[Forms]![New Rental]![Catalogue No] And [Issue Date] = Null; Which works fine without the null check for Issue Date. I'm trying to select rows without a Date in the Issue Date column. Is Null the wrong kind of value to use for here?

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  • Gnuplot axis scale units

    - by Kami
    I have the following data in a log file: 1270719764.323778250 926 vm-mystery1 1073744528 0 1 1270719764.323815250 926 vm-mystery1 1073746080 0 1 1270719764.323842250 926 vm-mystery1 1075968992 0 1 The first column is a UNIX date that I want to use for my x-axis in a gnuplot graph. My graph looks ugly because the first unit in the x-axis is 1.27072e+09. I would like to have the x-axis looks like the following : x axis [(first row date - first row date) ; (last row date - first row date)] displaying ticks in mili seconds. How to do this ?

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  • Date check for counting 30 days

    - by sijith
    Hi, I want to count the days passed with respect to a given date. I have a predefined date with me and i want to check the days passed, once the day pass 30 days with respect to the given time i want to get a message. example given date is25/03/2010 and when my system date reaches 25/04/2010 i have to get a message. How can i implement it. please give some help

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  • date() function problem

    - by Syom
    i use date function to get day, month and year. $year = date(y); $month = date(m); $day = date(d); but my hosting is in another place where i am, so i need to add 11 hours. could you tell me how can i do that? thanks

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  • Any website/software where I can add some text rows on daily basis

    - by Moorage
    I have few notes or text like few remembering lines on daily or weekly basis. I want to write it. but i should be able to see at any backdate /monthly or yearly. The date-time should also be stored when i enter text. is it possible EDIT: I will explain clearly what i exactly want. Suppose while working on internet 1)i find "ABC is good for BCD". now i want to add that text to some online site where i can see later 2)Now i can add those type of things any time and on internet i can see that in tabular form like click to see montly list , yearly or weekly 3)Other thing is i should be able to add text as easy as possible like in firefox if i can press some shotcut and enter something and it gets added there rather than opening the site and then write The to do list do that sort of thing but they dont have creation date , rather they filter based on due date.

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  • css calculation of the width

    - by marc-andre menard
    I got into a math problem my content box is 700pc wide my hentry (inside content) is 100% wide with padding of 10px wich make the hentry to be wider that the content resulting and overflow... Any solution Here is the page : http://www.equipe94.com I have firebug and removing the width 100% work, but it send by wordpress so how to overwrite a width:100% with nothing ?

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  • How do I get selected date set by jQuery UI Datepicker

    - by Steven
    I'm setting the start date of an event using jQuery UI Datepicker. Now I need to retrieve the date I selected. I'm trying to use $('#startDate').datepicker('getDate'), but this returns NULL. Using FirBug, I see that the input value is nothing <input type="text" name="startDate" value="" id="startDate" class="hasDatepicker"> I'm able to retrieve selected date when using jQuery serialize. So how can I retrieve the selected date?

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  • PHP - Large Interger mod calculation

    - by Kami
    I need to calculate modulus with large number like : <?php $largenum = 95635000009453274121700; echo $largenum % 97; ?> It's not working... beacause $largenum is too big for an int in PHP. Any idea how to do this ?

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  • System time wrong after running ntpdate because DST ignored

    - by Ian Dunn
    When I run ntpdate, my system clock displays the time as an hour behind what it should be. I know that ntpdate does everything in UTC, so I'm guessing there's a timezone setting wrong and it's ignoring Daylight Savings Time, but I can't figure it out. Here's what I've done so far: ln -sf /usr/share/zoneinfo/EST /etc/localtime to set the timezone Set UTC=true in /etc/sysconfig/clock so that DST will be automatically applied date -s hh:mm::ss to set system clock correctly hwclock -systohc --utc to set the hardware clock correctly At this point date and hwclock both display the correct time. But if I then run ntpdate 0.us.pool.ntp.org, the date output is an hour behind what it should be. I've looked at a dozen tutorials and can't figure out what I'm doing wrong. Does anyone have any ideas?

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  • how to apply iddata into calculation?

    - by Sam
    I am trying to figure out how to combine the input and output data into the ARX model and then apply it into the BIC (Bayesian Information Criterion) formula. Below is the code that I am currently working on: for i=1:30; %% Set Model Order data=iddata(output,input,1); model = arx(data,[8 9 i]); yp = predict(model,data); ye = regress(data,yp{1,1}(1:4018,1)); M(i) = var(yp); BIC(i)=(N+i*(log(N)-1))/(N-i)*log(M(i)); end But it does not work. It keep on giving me an error something like below: "The syntax "Data{...}" is not supported. Use the "getexp" command to extract individual experiments from an IDDATA object." I did not understand what does that mean. Can someone explain it to me and where do I do wrong on my piece of code? Thanks in advance. Sam.

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  • Copying single files into a folder that changes name every time the batch file is executed

    - by Daniel Jochem
    Can you please help, I am using this to put the text files made by the batch file into the folder created by the batch file as well. but my problem is that the name is changed of the new folder every time because it is named by the date and time it was created. This is the code: @echo off for /F " tokens=1,2,3* delims=/, " %%i IN ('date /T') DO ( set CUR_DAY_OF_WEEK=%%i set CUR_MONTH=%%j set CUR_DAY=%%k set CUR_YEAR=%%l) for /F " tokens=1,2,3* delims=:, " %%i IN ('time /T') DO ( set CUR_HOUR=%%i set CUR_MIN=%%j set AM_PM=%%k) if not exist E:\Private goto :F cd E:\Private md "E:\Private\%CUR_HOUR%.%CUR_MIN%%AM_PM% %j%%CUR_MONTH%-%CUR_DAY%-%CUR_YEAR%" goto :start :F if not exist F:\Private goto :G cd F:\Private md "F:\Private\%CUR_HOUR%.%CUR_MIN%%AM_PM% %j%%CUR_MONTH%-%CUR_DAY%-%CUR_YEAR%" goto :start :G cd G:\Private md "G:\Private\%CUR_HOUR%.%CUR_MIN%%AM_PM% %j%%CUR_MONTH%-%CUR_DAY%-%CUR_YEAR%" goto :start :start start /min A /stext A.txt start /min B /stext B.txt start /min C /stext C.txt start /min D /stext D.txt (As the directory (E:-G:) changes, how can I check all without an error? And once that is found, then put all these text files into the date folder.

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  • MSTest/NUnit Writing BDD style "Given, When, Then" tests

    - by Charlie
    I have been using MSpec to write my unit tests and really prefer the BDD style, I think it's a lot more readable. I'm now using Silverlight which MSpec doesn't support so I'm having to use MSTest but would still like to maintain a BDD style so am trying to work out a way to do this. Just to explain what I'm trying to acheive, here's how I'd write an MSpec test [Subject(typeof(Calculator))] public class when_I_add_two_numbers : with_calculator { Establish context = () => this.Calculator = new Calculator(); Because I_add_2_and_4 = () => this.Calculator.Add(2).Add(4); It should_display_6 = () => this.Calculator.Result.ShouldEqual(6); } public class with_calculator { protected static Calculator; } So with MSTest I would try to write the test like this (although you can see it won't work because I've put in 2 TestInitialize attributes, but you get what I'm trying to do..) [TestClass] public class when_I_add_two_numbers : with_calculator { [TestInitialize] public void GivenIHaveACalculator() { this.Calculator = new Calculator(); } [TestInitialize] public void WhenIAdd2And4() { this.Calculator.Add(2).Add(4); } [TestMethod] public void ThenItShouldDisplay6() { this.Calculator.Result.ShouldEqual(6); } } public class with_calculator { protected Calculator Calculator {get;set;} } Can anyone come up with some more elegant suggestions to write tests in this way with MSTest? Thanks

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  • Calculate age in days/months/years in OpenOffice

    - by Sanjay
    In need to find the age in days - months - years in OpenOffice. There is DATEDIF() in Microsoft Excel. You can use it to find the difference in days/months/years between two dates. Age Calculation You can calculate a persons age based on their birthday and todays date. The calculation uses the DATEDIF() function. The DATEDIF() is not documented in Excel 5, 7 or 97, but it is in 2000. (Makes you wonder what else Microsoft forgot to tell us!) Birth date : 01-Jan-60 Years lived : 52 =DATEDIF(C8,TODAY(),"y") and the months : 4 =DATEDIF(C8,TODAY(),"ym") and the days : 30 =DATEDIF(C8,TODAY(),"md") One can calculate by below formula, but it is cumbersome to calculate months. Another way to calculate age This method gives you an age which may potentially have decimal places representing the months. If the age is 20.5, the .5 represents 6 months. Birth date : 01-Jan-60 Age is : 52.41 =(TODAY()-C23)/365.25

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  • javascript date validation

    - by Bharanikumar
    Assume in my text box user enter like 18-06-2010 , Validation RULE if date is greater then current date then program should through the validation error like , PELASE ENTER PAST OR CURRENT DATE, DONT CHOOSE FUTURE DATE , Thanks

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  • shipping and handling fee calculation

    - by Newb
    Here is the question: Many companies normally charge a shipping and handling fee for purchases. Create a Web page that allows a user to enter a purchase price into a text box - include a JavaScript function that calculates shipping and handling. Add functionality to the script that adds a minimum shipping and handling fee of $1.50 for any purchase that is less than or equal to $25.00. For any orders over $25.00, add 10% to the total purchase price for shipping and handling, but do not include the $1.50 minimum shipping and handling fee. After you determine the total cost of the order (purchase plus shipping and handling), display it in an alert dialog box. I am beginner at JavaScript and struggling to get my code to work. It does display an alert box with the value entered by the user but doesn't add anything. Although, I don't know why the formula doesn't work. Please help. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Calculating Shipping & Handling</title> <script type="text/javascript"> /* <![CDATA[ */ var price=[]; var shipping=[]; var total=price+shipping; function calculateShipping(){ if (price <= 25){ shipping = (price + 1.5); } else { shipping = (price * 10 / 100); } window.alert("The purchase price with shipping is " + document.calculate.ent.value); } /* ]]> */ </script> </head> <body> <form name ="calculate" action="" > <p>Enter Purchase Price</p> <input type="text" name="ent" > <input type="button" name="button" value="Submit" onClick="calculateShipping()" /> </form> </body> </html>

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