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  • Python Naming Conventions for Dictionaries/Maps/Hashes

    - by pokstad
    While other questions have tackled the broader category of sequences and modules, I ask this very specific question: "What naming convention do you use for dictionaries and why?" Some naming convention samples I have been considering: # 'value' is the data type stored in the map, while 'key' is the type of key value_for_key={key1:value1, key2,value2} value_key={key1:value1, key2,value2} v_value_k_key={key1:value1, key2,value2} Don't bother answering the 'why' with "because my work tells me to", not very helpful. The reason driving the choice is more important. Are there any other good considerations for a dictionary naming convention aside from readability?

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  • pythonic way to associate list elements with their indices

    - by Dragan Chupacabrovic
    Hello Everybody, I have a list of values and I want to put them in a dictionary that would map each value to it's index. I can do it this way: >>> t = (5,6,7) >>> d = dict(zip(t, range(len(t)))) >>> d {5: 0, 6: 1, 7: 2} this is not bad, but I'm looking for something more elegant. I've come across the following, but it does the opposite of what I need: >>> d = dict(enumerate(t)) >>> d {0: 5, 1: 6, 2: 7} Please share your solutions, Thank you

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  • Multiple levels of 'collection.defaultdict' in Python

    - by Morlock
    Thanks to some great folks on SO, I discovered the possibilities offered by collections.defaultdict, notably in readability and speed. I have put them to use with success. Now I would like to implement three levels of dictionaries, the two top ones being defaultdict and the lowest one being int. I don't find the appropriate way to do this. Here is my attempt: from collections import defaultdict d = defaultdict(defaultdict) a = [("key1", {"a1":22, "a2":33}), ("key2", {"a1":32, "a2":55}), ("key3", {"a1":43, "a2":44})] for i in a: d[i[0]] = i[1] Now this works, but the following, which is the desired behavior, doesn't: d["key4"]["a1"] + 1 I suspect that I should have declared somewhere that the second level defaultdict is of type int, but I didn't find where or how to do so. The reason I am using defaultdict in the first place is to avoid having to initialize the dictionary for each new key. Any more elegant suggestion? Thanks pythoneers!

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  • Dynamic Operator Overloading on dict classes in Python

    - by Ishpeck
    I have a class that dynamically overloads basic arithmetic operators like so... import operator class IshyNum: def __init__(self, n): self.num=n self.buildArith() def arithmetic(self, other, o): return o(self.num, other) def buildArith(self): map(lambda o: setattr(self, "__%s__"%o,lambda f: self.arithmetic(f, getattr(operator, o))), ["add", "sub", "mul", "div"]) if __name__=="__main__": number=IshyNum(5) print number+5 print number/2 print number*3 print number-3 But if I change the class to inherit from the dictionary (class IshyNum(dict):) it doesn't work. I need to explicitly def __add__(self, other) or whatever in order for this to work. Why?

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  • convert string to dict using list comprehension in python

    - by Pavel
    I have came across this problem a few times and can't seem to figure out a simple solution. Say I have a string string = "a=0 b=1 c=3" I want to convert that into a dictionary with a, b and c being the key and 0, 1, and 3 being their respective values (converted to int). Obviously I can do this: list = string.split() dic = {} for entry in list: key, val = entry.split('=') dic[key] = int(val) But I don't really like that for loop, It seems so simple that you should be able to convert it to some sort of list comprehension expression. And that works for slightly simpler cases where the val can be a string. dic = dict([entry.split('=') for entry in list]) However, I need to convert val to an int on the fly and doing something like this is syntactically incorrect. dic = dict([[entry[0], int(entry[1])] for entry.split('=') in list]) So my question is: is there a way to eliminate the for loop using list comprehension? If not, is there some built in python method that will do that for me?

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  • Throttle or limit resources used by a user in a database?

    - by Eduardo
    I would like to know how databases (like MySQL) are able to manage per user resources (like Oracle Database Resource Manager does) to be able to have users that may only get resources only when the database is mostly idle. http://stackoverflow.com/questions/2418581/is-there-a-way-to-throttle-or-limit-resources-used-by-a-user-in-oracle

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  • Python: Data Object or class

    - by arg20
    I enjoy all the python libraries for scraping websites and I am experimenting with BeautifulSoup and IMDB just for fun. As I come from Java, I have some Java-practices incorporated into my programming styles. I am trying to get the info of a certain movie, I can either create a Movie class or just use a dictionary with keys for the attributes. My question is, should I just use dictionaries when a class will only contain data and perhaps almost no behaviour? In other languages creating a type will help you enforce certain restrictions and because of type checks the IDE will help you program, this is not always the case in python, so what should I do? Should I resort to creating a class only when there's both, behaviour and data? Or create a movie class even though it'll probably be just a data container? This all depends on your model, in this particular case either one is fine but I'm wondering about what's a good practice.

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  • Write Unit test for sorting

    - by user175084
    I need to write a unit test for a method where I arrange data according to another default list. This is the method. internal AData[] GetDataArrayInInitialSortOrder(ABData aBData) { Dictionary<string,AData > aMap = aBData.ADataArray.ToDictionary(v => v.GroupName, v => v); List<AData> newDataList = new List<AData>(); foreach (AData aData in _viewModel.ADList) newDataList.Add(aMap[aData.GroupName]); return newDataList.ToArray(); } Please help I am new in unit testing and this is not easy for me. Any sample or links are appreciated Thanks

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  • Multiple levels of 'collection.defaultdict' in Python

    - by Morlock
    Thanks to some great folks on SO, I discovered the possibilities offered by collections.defaultdict, notably in readability and speed. I have put them to use with success. Now I would like to implement three levels of dictionaries, the two top ones being defaultdict and the lowest one being int. I don't find the appropriate way to do this. Here is my attempt: from collections import defaultdict d = defaultdict(defaultdict) a = [("key1", {"a1":22, "a2":33}), ("key2", {"a1":32, "a2":55}), ("key3", {"a1":43, "a2":44})] for i in a: d[i[0]] = i[1] Now this works, but the following, which is the desired behavior, doesn't: d["key4"]["a1"] + 1 I suspect that I should have declared somewhere that the second level defaultdict is of type int, but I didn't find where or how to do so. The reason I am using defaultdict in the first place is to avoid having to initialize the dictionary for each new key. Any more elegant suggestion? Thanks pythoneers!

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  • How can I re-create Microsoft Cluster Service resource groups on a different cluster?

    - by PersonalNexus
    I use Microsoft Cluster Service on a cluster of Windows Server 2003 machines containing several dozen resource groups. In the process of migrating to newer hardware, I would like move resources to the new machines on resource group at a time spread out over a few days to ease the migration and minimize risk. I was wondering of there was a smarter way to do this than manually re-creating resources on the new and then deleting them on the old cluster? The cluster has already been set up properly, the only missing is the resource groups and the resources they contain (IP, network names, services...). I have looked through the options of the cluster admin GUI and cluster.exe's commandline options, but haven't found anything like an import/export feature to copy over the configuration of a resource or entire resource group. Does something like this exist?

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  • Maven error: Unable to get resource / Server redirected too many times

    - by tewe
    Our proxy went down and I tried to update dependencies with maven while it was off. Since then I can't download anything with maven. I get this error for everything. I tried -U option, deleting my local repository and tried different maven version (2.0.9, 2.2.1) but it doesn't work. Any idea how to solve this? Earlier it also said 'repository will be blacklisted' to all of them. Downloading: http://repo1.maven.org/maven2/org/apache/maven/plugins/maven-compiler-plugin/2.1/maven-compiler-plugin-2.1.pom [WARNING] Unable to get resource 'org.apache.maven.plugins:maven-compiler-plugin:pom:2.1' from repository central (http://repo1.maven.org/maven2): Error transferring file: Server redirected too many times (20) org.apache.maven.plugins:maven-compiler-plugin:pom:2.1 from the specified remote repositories: jboss-snapshot (http://snapshots.jboss.org/maven2), central (http://repo1.maven.org/maven2), JBoss Repo (http://repository.jboss.com/maven2), spring-maven-snapshot (http://maven.springframework.org/snapshot), com.springsource.repository.bundles.external (http://repository.springsource.com/maven/bundles/external), com.springsource.repository.bundles.snapshot (http://repository.springsource.com/maven/bundles/snapshot), jboss (http://repository.jboss.com/maven2), com.springsource.repository.bundles.release (http://repository.springsource.com/maven/bundles/release), jboss-snapshot-plugins (http://snapshots.jboss.org/maven2), com.springsource.repository.bundles.milestone (http://repository.springsource.com/maven/bundles/milestone), jboss-plugins (http://repository.jboss.com/maven2) at org.apache.maven.artifact.resolver.DefaultArtifactResolver.resolve(DefaultArtifactResolver.java:228) at org.apache.maven.artifact.resolver.DefaultArtifactResolver.resolve(DefaultArtifactResolver.java:90) at org.apache.maven.project.DefaultMavenProjectBuilder.findModelFromRepository(DefaultMavenProjectBuilder.java:558) ... 25 more Caused by: org.apache.maven.wagon.ResourceDoesNotExistException: Unable to download the artifact from any repository at org.apache.maven.artifact.manager.DefaultWagonManager.getArtifact(DefaultWagonManager.java:404) at org.apache.maven.artifact.resolver.DefaultArtifactResolver.resolve(DefaultArtifactResolver.java:216) ... 27 more

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  • "Error generating Win32 resource" in Visual Studio, Windows 7 x64

    - by Jerad Rose
    My co-developers and I recently upgraded machines to Windows 7 Ultimate 64 bit. Some of us are seeing a new error we used to never see when building solutions in Visual Studio (happens in both 2008 and 2010): Error generating Win32 resource: The process cannot access the file because it is being used by another process. It always points to some temp file in our output folder, for example: MyProject\obj\Debug\CSC5123.tmp This happens about once every four or so builds. We then will try to run the same exact build again, and it will usually succeed. In some cases though, it will fail again on the same project, and in same cases, it will fail on a different project. There's really no rhyme or reason to it. But it's very frustrating, especially when it doesn't happen until the build has been running for 20 or so seconds. This also doesn't happen to all of our coworkers. It happens to about one out of four developers. For the one, it happens about one of four builds, and for the other three, it never happens. Oh, and did I mention we're all using machines built from the same image? :) Thanks in advance for any direction you can provide.

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  • HTML 4, HTML 5, XHTML, MIME types - the definitive resource

    - by deceze
    The topics of HTML vs. XHTML and XHTML as text/html vs. XHTML as XHTML are quite complex. Unfortunately it's hard to get a complete picture, since information is spread mostly in bits and pieces around the web or is buried deep in W3C tech jargon. In addition there's some misinformation being circulated. I propose to make this the definite SO resource about the topic, describing the most important aspects of: HTML 4 HTML 5 XHTML 1.0/1.1 as text/html XHTML 1.0/1.1 as XHTML What are the practical implications of each? What are common pitfalls? What is the importance of proper MIME types for each? How do different browsers handle them? I'd like to see one answer per technology. I'm making this a community wiki, so rather than contributing redundant answers, please edit answers to complete the picture. Feel free to start with stubs. Also feel free to edit this question.

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  • HTML 4, HTML 5, XHTML, MIME types - the definite resource

    - by deceze
    The topics of HTML vs. XHTML and XHTML as text/html vs. XHTML as XHTML are quite complex. Unfortunately it's hard to get a complete picture, since information is spread mostly in bits and pieces around the web or is buried deep in W3C tech jargon. In addition there's some misinformation being circulated. I propose to make this the definite SO resource about the topic, describing the most important aspects of: HTML 4 HTML 5 XHTML 1.0/1.1 as text/html XHTML 1.0/1.1 as XHTML What are the practical implications of each? What are common pitfalls? What is the importance of proper MIME types for each? How do different browsers handle them? I'd like to see one answer per technology. I'm making this a community wiki, so rather than contributing redundant answers, please edit answers to complete the picture. Feel free to start with stubs. Also feel free to edit this question.

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  • asp.net Impersonate User for network resource access

    - by lonelycoder
    code: System.Security.Principal.WindowsImpersonationContext impersonationContext; impersonationContext = ((System.Security.Principal.WindowsIdentity)User.Identity).Impersonate(); //access network resources. impersonationContext.Undo(); web.config: <authentication mode="Windows"> </authentication> <identity impersonate="true" userName="user" password="password"></identity> As clear from web.config file, the app runs in an impersonated mode. I need to impersonate temporarily on top of that to access a network resource. I do that as shown above. This works fine on server if I browse to the website on the local IE installed on the server but when I access the app from my PC or any other PC, I get a access denied. Btw, this is all within an enterprise domain environment. so IE in both cases is passing a valid authenticated token. Any ideas what is going on. thanks.

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  • Can't find compiled resource bundles

    - by user351032
    I am using Adobe Flash Builder 4. I've run into this issue with my latest project, but I was able to re-create it with an almost empty project. Here is what I've done. Created a new Flex Project Created a locale/en_US folder within this project. Added a class that extends SparkDownloadProgressBar. All this class does is attempt to create a Label. When I try to debug this application, I get the following error. Error: Could not find compiled resource bundle 'components' for locale 'en_US'. at mx.resources::ResourceManagerImpl/installCompiledResourceBundle()[E:\dev\4.0.0\frameworks\projects\framework\src\mx\resources\ResourceManagerImpl.as:340] at mx.resources::ResourceManagerImpl/installCompiledResourceBundles()[E:\dev\4.0.0\frameworks\projects\framework\src\mx\resources\ResourceManagerImpl.as:269] at mx.resources::ResourceManagerImpl/processInfo()[E:\dev\4.0.0\frameworks\projects\framework\src\mx\resources\ResourceManagerImpl.as:387] at mx.resources::ResourceManagerImpl()[E:\dev\4.0.0\frameworks\projects\framework\src\mx\resources\ResourceManagerImpl.as:122] at mx.resources::ResourceManager$/getInstance()[E:\dev\4.0.0\frameworks\projects\framework\src\mx\resources\ResourceManager.as:111] at mx.core::UIComponent()[E:\dev\4.0.0\frameworks\projects\framework\src\mx\core\UIComponent.as:3728] at spark.components.supportClasses::TextBase()[E:\dev\4.0.0\frameworks\projects\spark\src\spark\components\supportClasses\TextBase.as:154] at spark.components::Label()[E:\dev\4.0.0\frameworks\projects\spark\src\spark\components\Label.as:384] at Preloader()[C:\SVN\Games\Social\Test\src\Preloader.as:21] at mx.preloaders::Preloader/initialize()[E:\dev\4.0.0\frameworks\projects\framework\src\mx\preloaders\Preloader.as:253] at mx.managers::SystemManager/http://www.adobe.com/2006/flex/mx/internal::initialize()[E:\dev\4.0.0\frameworks\projects\framework\src\mx\managers\SystemManager.as:1925] at mx.managers::SystemManager/initHandler()[E:\dev\4.0.0\frameworks\projects\framework\src\mx\managers\SystemManager.as:2419] The Flex Compiler/Additional Compiler Arguments section does contain "-locale en_US", but I do not want to just remove this as I am planning to have this load different property files based on the localization region at run-time and how I understand it, I will need to add each locale that I am planning to use on the compile argument line. I am at a loss as to how to attack this problem. If you need anymore information from me to help with this, I will be more than happy to provide it. Thanks ahead of time for the help!

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  • Spring HandlerInterceptor or Spring Security to protect resource

    - by richever
    I've got a basic Spring Security 3 set up using my own login page. My configuration is below. I have the login and sign up page accessible to all as well as most everything else. I'm new to Spring Security and understand that if a user is trying to access a protected resource they will be taken to the defined login page. And upon successful login they are taken to some other page, home in my case. I want to keep the latter behavior; however, I'd like specify that if a user tries to access certain resources they are taken to the sign up page, not the login page. Currently, in my annotated controllers I check the security context to see if the user is logged in and if not I redirect them to the sign up page. I only do this currently with two urls and no others. This seemed redundant so I tried creating a HandlerInterceptor to redirect for these requests but realized that with annotations, you can't specify specific requests to be handled - they all are. So I'm wondering if there is some way to implement this type of specific url handling in Spring Security, or is going the HandlerInterceptor route my only option? Thanks! <http auto-config="true" use-expressions="true"> <intercept-url pattern="/login*" access="permitAll"/> <intercept-url pattern="/signup*" access="permitAll"/> <intercept-url pattern="/static/**" filters="none" /> <intercept-url pattern="/" access="permitAll"/> <form-login login-page="/login" default-target-url="/home"/> <logout logout-success-url="/home"/> <anonymous/> <remember-me/> </http>

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  • Devise not allowing active resource to access the services

    - by Saurabh Pandit
    In my application there are two folders one for a rails application and another for a ruby application. In the ruby folder I have created a ruby file in which I have written code to access some model which is present in the rails application using active resource. Sample code is shown below : active_resource_example.rb require 'rubygems' require 'active_resource' class Website < ActiveResource::Base self.site = "http://localhost:3000/admin/" self.user = "user" self.password = "password" end websites = Website.find(:all) puts websites.inspect In my rails application I have used ActiveAdmin gem which uses devise for authentication. On rails Server I get the following result : Started GET "/admin/websites.json" for 192.168.1.37 at 2011-11-12 14:41:06 +0530 Processing by Admin::WebsitesController#index as JSON Completed in 43ms And on my terminal where I executed active_resource_example.rb, I got following error : user@user:~/Desktop$ ruby active_resource_example.rb /home/user/.rvm/gems/ruby-1.9.2-p180/gems/activeresource-3.1.1/lib/active_resource/connection.rb:132:in `handle_response': Failed. Response code = 401. Response message = Unauthorized . (ActiveResource::UnauthorizedAccess) from /home/user/.rvm/gems/ruby-1.9.2-p180/gems/activeresource-3.1.1/lib/active_resource/connection.rb:115:in `request' from /home/user/.rvm/gems/ruby-1.9.2-p180/gems/activeresource-3.1.1/lib/active_resource/connection.rb:80:in `block in get' from /home/user/.rvm/gems/ruby-1.9.2-p180/gems/activeresource-3.1.1/lib/active_resource/connection.rb:218:in `with_auth' from /home/user/.rvm/gems/ruby-1.9.2-p180/gems/activeresource-3.1.1/lib/active_resource/connection.rb:80:in `get' from /home/user/.rvm/gems/ruby-1.9.2-p180/gems/activeresource-3.1.1/lib/active_resource/base.rb:894:in `find_every' from /home/user/.rvm/gems/ruby-1.9.2-p180/gems/activeresource-3.1.1/lib/active_resource/base.rb:806:in `find' from active_resource_example.rb:12:in `<main>' user@user:~/Desktop$ I tried this with another application in which Devise authentication is not used with the same configuration I used in active_resource_example.rb, there I got the result. Desperately need some solution to this issue.

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  • Magento resource model for table with compound primary key

    - by sdek
    I am creating a custom module for a Magento ecommerce site, and the module will center around a new (ie, custom) table that has a compound/composite primary key, or rather the table has two columns that make up the primary key. Does anybody know how to create your models/resource models based on a table with a compound key? To give a few more details, I have looked up several tutorials and also used the excellent moduleCreator script. But it seems like all the tutorials revolve around the table having a PK with just one column in it. Something like this: class <Namespace>_<Module>_Model_Mysql4_<Module> extends Mage_Core_Model_Mysql4_Abstract { public function _construct(){ $this->_init('<module_alias>/<table_alias>', '<table_primary_key_id>'); } } Also, I just noticed that looking at the database model almost all tables have a single primary key. I understand this has much to do with the EAV-style db structure, but still is it possible to use a table with a compound PK? I want to stick with the Magento framework/conventions if possible. Is it discouraged? Should I just change the structure of my custom table to have some dummy id column? I do have the ability to do that, but geez! (Another side note that I thought I would mention is that it looks like the Zend Framework provides a way to base a class on a table with compound primary key (see Example #20 on this page - about half-way down), so it seems that the Magento framework should also provide for it... I just don't see how.)

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  • RESTfully Nesting Resource Routes with Single Identifiers

    - by Craig Walker
    In my Rails app I have a fairly standard has_many relationship between two entities. A Foo has zero or more Bars; a Bar belongs to exactly one Foo. Both Foo and Bar are identified by a single integer ID value. These values are unique across all of their respective instances. Bar is existence dependent on Foo: it makes no sense to have a Bar without a Foo. There's two ways to RESTfully references instances of these classes. Given a Foo.id of "100" and a Bar.id of "200": Reference each Foo and Bar through their own "top-level" URL routes, like so: /foo/100 /bar/200 Reference Bar as a nested resource through its instance of Foo: /foo/100 /foo/100/bar/200 I like the nested routes in #2 as it more closely represents the actual dependency relationship between the entities. However, it does seem to involve a lot of extra work for very little gain. Assuming that I know about a particular Bar, I don't need to be told about a particular Foo; I can derive that from the Bar itself. In fact, I probably should be validating the routed Foo everywhere I go (so that you couldn't do /foo/150/bar/200, assuming Bar 200 is not assigned to Foo 150). Ultimately, I don't see what this brings me. So, are there any other arguments for or against these two routing schemes?

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  • Actionscript project that loads a Flex SWF, "Could not find resource bundle" Error when using Layout

    - by Leeron
    Hi guys. I'm using an actionsciprt only project (under FlashDevelop) to load an .swf flex file built by another department of the company I work for. Using the follwing code: var mLoader:Loader = new Loader(); var mRequest:URLRequest = new URLRequest('flexSWF.swf'); mLoader.contentLoaderInfo.addEventListener(Event.COMPLETE, onCompleteHandler); mLoader.contentLoaderInfo.addEventListener(ProgressEvent.PROGRESS, onProgressHandler); mLoader.load(mRequest); That worked fine until I wanted to use Flex's mx.managers.LayoutManager. I've added the this line to my class: import mx.managers.ILayoutManagerClient; import mx.managers.LayoutManager; . . . private var _layoutManager:LayoutManager; And I get this run time error: Error: Could not find resource bundle messaging at mx.resources::ResourceBundle$/getResourceBundle()[C:\autobuild\3.5.0\frameworks\projects\framework\src\mx\resources\ResourceBundle.as:143] at mx.utils::Translator$cinit() at global$init() at mx.messaging.config::ServerConfig$cinit() at global$init() at _app_FlexInit$/init() at mx.managers::SystemManager/http://www.adobe.com/2006/flex/mx/internal::docFrameHandler()[C:\autobuild\3.5.0\frameworks\projects\framework\src\mx\managers\SystemManager.as:3217] at mx.managers::SystemManager/docFrameListener()[C:\autobuild\3.5.0\frameworks\projects\framework\src\mx\managers\SystemManager.as:3069] commenting the LayoutManager line, the swf works fine. But I do want to use LayoutManager. Any hints?

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  • How to design a RESTful collection resource?

    - by Suresh Kumar
    I am trying to design a "collection of items" resource. I need to support the following operations: Create the collection Remove the collection Add a single item to the collection Add multiple items to the collection Remove a single item from the collection Remove multiple items from the collection This is as far as I have gone: Create collection: ==> POST /service Host: www.myserver.com Content-Type: application/xml <collection name="items"> <item href="item1"/> <item href="item2"/> <item href="item3"/> </collection> <== 201 Created Location: http://myserver.com/service/items Content-Type: application/xml ... Remove collection: ==> DELETE /service/items <== 200 OK Removing a single item from the collection: ==> DELETE /service/items/item1 <== 200 OK However, I am finding supporting the other operations a bit tricky i.e. what methods can I use to: Add single or multiple items to the collection. (PUT doesn't seem to be right here as per HTTP 1.1 RFC Remove multiple items from the collection in one transaction. (DELETE doesn't seem to right here either)

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  • No resource type specified (at 'id' with value '@+id\st')

    - by Refaat
    I'm new at android programming, I'm now trying to make some buttons, I configured these buttons using the following code: The MainActivity class : public class MainActivity extends Activity { /** Called when the activity is first created. */ Button st,nd,center; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); st = (Button)findViewById(R.id.st); st = (Button)findViewById(R.id.center); st = (Button)findViewById(R.id.nd); } } and the XML Layout: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" android:background="@drawable/background" > <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="Hello from animation!!" /> <button android:layout_width="100dp" android:layout_height="50dp" android:text="1st half" android:id="@+id\st" /> // and the other two points defined the same way </LinearLayout> And i got that syntax error: error: Error: No resource type specified (at 'id' with value '@+id\st'). // and the same error with the other two buttons HINT: The R class is imported and accessible from the MainActivity class but it can't read R.id.

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  • tomcat resource missing, servlet not running

    - by user2837260
    import javax.servlet.*; import java.io.*; public class MyServlet implements Servlet { public void init(ServletConfig con) {} public void service(ServletRequest req, ServletResponse res) throws IOException,ServletException { res.setContentType("text/html"); PrintWriter out=res.getWriter(); String s="blah"; String s1="blah"; out.println("<html><body>"); if((s.equals(req.getParameter("firstname")))&&(s1.equals(req.getParameter("pwd")))) out.println("passwords match"); else out.println("password and name combo does not match"); out.println("</body></html>"); } public void destroy() {} public ServletConfig getServletConfig() { return null;} public String getServletInfo() { return null;} } this is my java file with the servlet class.its saved with the name MyServlet.java and so is the class file. and here is the xml file: <web-app> <servlet> <servlet-name>demoo</servlet-name> <servlet-class>MyServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>demoo</servlet-name> <url-pattern>/demo</url-pattern> </servlet-mapping> </web-app> i have made the folder as WEB-INF and then classes... WEB-INF also contains the .xml file but when i try to run the servlet , it says resource not found ps- i am already looking for the servlet with the name :demo localhost:8081/s1/demo* s1 is the war file * a html file in the war file seems to run fine on the server though. *

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  • C# Interop.Word Adding an Image from project resource folder

    - by iamnobody
    Hi guys. Having some image problem with Interop.Word and C#. I want to add an image in the header of the document that I am going to generate. I have this code working perfectly section.Headers[Word.WdHeaderFooterIndex.wdHeaderFooterPrimary].Shapes.AddPicture(@"C:\Logo.jpg", ref x, ref x, ref x, ref x, ref x, ref x, ref x); Problem is that I can't have "C:\Logo.jpg" in the code since after publishing the project, there would most probably be no Logo.jpg in the C folder of the user. The image is already in my project's resource folder. I've used Image.FromFile("Logo.jpg") before but .AddPicture requires a string and not an image. Any ideas? Any help would be greatly appreciated. Thanks! -- edit -- Saw this over the net: string anyPath = @"C:\logo.jpg"; Properties.Resources.logo.Save(anyPath); section.Headers.[...].Shapes.AddPicture(anyPath, ... but then I still get a generic error in GDI+ or ExternalException was unhandled.

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