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  • How to order <script> tags vs. <style> tags in HTML markup for best results.

    - by Tchalvak
    I'm building up my site over at http://royronalds.com, and I'm trying to figure out what order of elements in the <head> makes most sense. Just to take from what I current have, I have: <head> <style> external stylesheet <meta> <title> <link> to favicon <script> for jQuery <script> main javascript for site <script> google analytics, asynchronous script. </head> Are there reasons to order these differently so that load times and other issues happen more smoothly, and if so, what would the ideal order be?

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  • Page upload data again on page refresh in ASP.NET

    - by Etienne
    For some reason when the user click on the submit button and he re-fresh the page the same data get's uploaded again to my SQL Server 2005 database. I do not what this to happen........... Why is this happening? I am making use of a SQL Data Source!! My code Try 'See if user typed the correct code. If Me.txtSecurity.Text = Session("Captcha") Then If Session("NotifyMe") = "Yes" Then SendEmailNS() End If RaterRate.Insert() RaterRate.Update() DisableItems() lblResultNS.Text = "Thank you for leaving a comment" LoadCompanyList() LoadRateRecords() txtCommentNS.Text = "" txtSecurity.Text = "" lblResultNS.Focus() Else Session("Captcha") = GenerateCAPTCHACode() txtSecurity.Text = "" txtSecurity.Focus() Validator10.Validate() End If Catch ex As Exception lblResultNS.Visible = True lblResultNS.Text = ex.Message.ToString lblResultNS.Focus() End Try

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  • A Python Wrapper for Shutterfly. Uploading an Image

    - by iJames
    I'm working on a Django app in which I want to order prints through Shutterfly's Open API: http://www.shutterfly.com/documentation/start.sfly So far I've been able to build the appropriate POSTs and GETs using the modules and suggested code snippets including httplib, httplib2, urllib, urllib2, mimetype, etc. But I'm stuck on the image uploading when placing an order (the ordering process is not the same process as uploading images to albums which I haven't tried.) From what I can tell, I'm supposed to basically create the multipart form data by concatenating the HTTP request body together with the binary data of the image. I take the strings: --myuniqueboundary1273149960.175.1 Content-Disposition: form-data; name="AuthenticationID" auniqueauthenticationid --myuniqueboundary1273149960.175.1 Content-Disposition: file; name="Image.Data"; filename="1_41_orig.jpg" Content-Type: image/jpeg and I put this data into it and end with the final boundary: ...\xb5|\xf88\x1dj\t@\xd9\'\x1f\xc6j\x88{\x8a\xc0\x18\x8eGaJG\x03\xe9J-\xd8\x96[\x91T\xc3\x0eTu\xf4\xaa\xa5Ty\x80\x01\x8c\x9f\xe9Z\xad\x8cg\xba# g\x18\xe2\xaa:\x829\x02\xb4["\x17Q\xe7\x801\xea?\xad7j\xfd\xa2\xdf\x81\xd2\x84D\xb6)\xa8\xcb\xc8O\\\x9a\xaf(\x1cqM\x98\x8d*\xb8\'h\xc8+\x8e:u\xaa\xf3*\x9b\x95\x05F8\xedN%\xcb\xe1B2\xa9~Tw\xedF\xc4\xfe\xe8\xfc\xa9\x983\xff\xd9... That ends up making it look like this (when I use print to debug): ... --myuniqueboundary1273149960.175.1 Content-Disposition: file; name="Image.Data"; filename="1_41_orig.jpg" Content-Type: image/jpeg ????q?ExifMM* ? ??(1?2?<??i?b?NIKON CORPORATIONNIKON D40HHQuickTime 7.62009:02:17 13:05:25Mac OS X 10.5.6%??????"?'??0220?????? ???? ? ?|_???,b???50??5 ... --myuniqueboundary1273149960.175.1-- My code for grabbing the binary data is pretty much this: filedata = open('myjpegfile.jpeg','rb').read() Which I then add to the rest of the body. I've see something like this code everywhere. I'm then using this to post the full request (with the headers too): response = urllib2.urlopen(request).read() This seems to me to be the standard way that form POSTS with files happens. Am I missing something here? At some point I might be able to make this into a library worth posting up on github, but this problem has stopped me cold in my tracks. Thanks for any insight!

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  • Sample code for image upload

    - by Michael
    Hi, In would like to write a simple Android application that takes a picture from the camera and uploads it to a webserver. Additionaly, I would like it to print in the screen the response from the server wich is a simple text string. Do you know if there is any sample code that does something like that? Thank you, Michael

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  • Alert show when extension of FileUpLoads are not allowed

    - by Vy Clarks
    I have a asp FileUpload control in my aspx page. And the code behind to check file's extension and then insert them into database: private string Write(HttpPostedFile file, string table) { string fileNameMain = Path.GetFileName(file.FileName); // check for the valid file extension string fileExtension = Path.GetExtension(fileNameMain).ToLower(); if (fileExtension.Equals(".pdf") || fileExtension.Equals(".doc")) { ...insert fileupload into database } else { LabelError.Text = "Extension of files are not allowed."; return null; } } With the code above, it checks the extension and then show the message "Extension of files are not allowed." in a LabelError if the fileupload is not allowed. Now, I'm required to do the "check-extension" in the other way: at the moment the client click and choose FileUpload, an alert show "Extension of files are not allowed.". I need a way to make an alert show at the momment the FileUpload choosed in browser. Help!!!!

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  • HTTP POST prarameters order / REST urls

    - by pq
    Let's say that I'm uploading a large file via a POST HTTP request. Let's also say that I have another parameter (other than the file) that names the resource which the file is updating. The resource cannot be not part of the URL the way you can do it with REST (e.g. foo.com/bar/123). Let's say this is due to a combination of technical and political reasons. The server needs to ignore the file if the resource name is invalid or, say, the IP address and/or the logged in user are not authorized to update the resource. Looks like, if this POST came from an HTML form that contains the resource name first and file field second, for most (all?) browsers, this order is preserved in the POST request. But it would be naive to fully rely on that, no? In other words the order of HTTP parameters is insignificant and a client is free to construct the POST in any order. Isn't that true? Which means that, at least in theory, the server may end up storing the whole large file before it can deny the request. It seems to me that this is a clear case where RESTful urls have an advantage, since you don't have to look at the POST content to perform certain authorization/error checking on the request. Do you agree? What are your thoughts, experiences?

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  • File upload in asp.net mvc using ajax

    - by Maxim
    Hello! i have a simple html form with two controls: input-text and input-file i need to write an ajax query (using jquery is better) to send data (file and value from text field to mvc acton) i wrote $.ajax({ type: "POST", url: "/controller/acton", enctype: 'multipart/form-data', data: 'text=' + $("#text").val() + '&file=' + $("#file").val() ... and in controller: [HttpPost] public ActionResult StoreItem(FormCollection forms) { foreach (string inputTagName in Request.Files) ... returns null in Request... Thank you

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  • multipart file-upload post request from java

    - by Martin
    I'm trying to make a program that uploads a image to a webserver that accepts multipart file-uploads. More specificly i want to make a http POST request to http://iqs.me that sends a file in the variable "pic". I've made a lot of tries but i don't know if i've even been close. The hardest part seems to be to get a HttpURLConnection to make a request of the type POST. The response i get looks like it makes a GET. (And i want to do this without any third party libs) UPDATE: non-working code goes here (no errors but doesn't seem to do a POST): HttpURLConnection conn = null; BufferedReader br = null; DataOutputStream dos = null; DataInputStream inStream = null; InputStream is = null; OutputStream os = null; boolean ret = false; String StrMessage = ""; String exsistingFileName = "myScreenShot.png"; String lineEnd = "\r\n"; String twoHyphens = "--"; String boundary = "*****"; int bytesRead, bytesAvailable, bufferSize; byte[] buffer; int maxBufferSize = 1*1024*1024; String responseFromServer = ""; String urlString = "http://iqs.local.com/index.php"; try{ FileInputStream fileInputStream = new FileInputStream( new File(exsistingFileName) ); URL url = new URL(urlString); conn = (HttpURLConnection) url.openConnection(); conn.setDoInput(true); conn.setDoOutput(true); conn.setRequestMethod("POST"); conn.setUseCaches(false); conn.setRequestProperty("Connection", "Keep-Alive"); conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary); dos = new DataOutputStream( conn.getOutputStream() ); dos.writeBytes(twoHyphens + boundary + lineEnd); dos.writeBytes("Content-Disposition: form-data; name=\"pic\";" + " filename=\"" + exsistingFileName +"\"" + lineEnd); dos.writeBytes(lineEnd); bytesAvailable = fileInputStream.available(); bufferSize = Math.min(bytesAvailable, maxBufferSize); buffer = new byte[bufferSize]; bytesRead = fileInputStream.read(buffer, 0, bufferSize); while (bytesRead > 0){ dos.write(buffer, 0, bufferSize); bytesAvailable = fileInputStream.available(); bufferSize = Math.min(bytesAvailable, maxBufferSize); bytesRead = fileInputStream.read(buffer, 0, bufferSize); } dos.writeBytes(lineEnd); dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd); fileInputStream.close(); dos.flush(); dos.close(); }catch (MalformedURLException ex){ System.out.println("Error:"+ex); }catch (IOException ioe){ System.out.println("Error:"+ioe); } try{ inStream = new DataInputStream ( conn.getInputStream() ); String str; while (( str = inStream.readLine()) != null){ System.out.println(str); } inStream.close(); }catch (IOException ioex){ System.out.println("Error: "+ioex); }

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  • iPhone Development: Use POST to submit a form

    - by Mario
    I've got the following html form: <form method="post" action="http://shk.ecomd.de/up.php" enctype="multipart/form-data"> <input type="hidden" name="id" value="12345" /> <input type="file" name="pic" /> <input type="submit" /> </form> And the following iPhone SDK Submit method: - (void)sendfile { UIImage *tempImage = [UIImage imageNamed:@"image.jpg"]; NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init]; [request setHTTPMethod:@"POST"]; [request setURL:[NSURL URLWithString:@"http://url..../form.php"]]; NSString *boundary = @"------------0xKhTmLbOuNdArY"; NSString *contentType = [NSString stringWithFormat:@"multipart/form-data; boundary=%@",boundary]; [request addValue:contentType forHTTPHeaderField: @"Content-Type"]; NSMutableData *body = [NSMutableData data]; [body appendData:[[NSString stringWithFormat:@"\r\n%@\r\n",boundary] dataUsingEncoding:NSASCIIStringEncoding]]; [body appendData:[@"Content-Disposition: form-data; name=\"id\"\r\n\r\n" dataUsingEncoding:NSASCIIStringEncoding]]; [body appendData:[@"12345" dataUsingEncoding:NSUTF8StringEncoding]]; [body appendData:[[NSString stringWithFormat:@"\r\n%@\r\n",boundary] dataUsingEncoding:NSASCIIStringEncoding]]; [body appendData:[@"Content-Disposition: form-data; name=\"pic\"; filename=\"photo.png\"\r\n" dataUsingEncoding:NSASCIIStringEncoding]]; [body appendData:[@"Content-Type: application/octet-stream\r\n\r\n" dataUsingEncoding:NSASCIIStringEncoding]]; [body appendData:[NSData dataWithData:UIImageJPEGRepresentation(tempImage, 90)]]; [body appendData:[[NSString stringWithFormat:@"\r\n%@",boundary] dataUsingEncoding:NSASCIIStringEncoding]]; // setting the body of the post to the reqeust [request setHTTPBody:body]; NSError *error; NSURLResponse *response; NSData* result = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error]; NSString* aStr = [[[NSString alloc] initWithData:result encoding:NSASCIIStringEncoding] autorelease]; NSLog(@"Result: %@", aStr); [request release]; } This does not work, but I have no clue why. Can you please help me?!! What am I doing wrong?

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  • MeioUpload and phpThumb() does not exist error

    - by Cameeob2003
    I am currently using CakePHP v2.2.1 and MeioUpload 4.0 along with phpThumb() to try and generate image uploads and thumbnails for those images. If i set my $actAs = array() without the thumbsizes property everything is uploaded well, but when I add the following: 'thumbsizes' => array( 'small' => array('width' => 165, 'height' => 115), 'medium' => array('width' => 800, 'height' => 600) ), to generate thumbnails I get an error stating the following: "E:/xampp/htdocs/site/vendors/phpthumb/img/posts/image-name.jpg" does not exist I have tried several different methods of fixing this from around the web and nothing seems to work. I am new to cakephp so this may be an easy fix and I am just not connecting the dots to find the solution. Any help would be very much appreciated.

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  • How can I write a file on an ftps-server with PHP?

    - by Daniel
    Hi, I hope someone here could help me, because I couldn't find any solution with Google. What I have to do is to generate a XML-string (that works) an save that directly into a file on an ftps-server. So far, so good... I used the following code with ftp and it works to, but not with ftps. So I either need another options-configuration for the stream or a different way to solve that task. Here my current code: $host = 'ftp.example.com'; $port = 22; $user = 'xxxxxx'; $pass = 'xxxxxx'; $file = 'test_' . time() . '.txt'; $ftpPath = sprintf('ftp://%s:%s@%s:%d/%s', $user, $pass, $host, $port, $file); $context = stream_context_create(array('ftp' = array('overwrite' = true))); file_put_contents($ftpPath, 'test', 0, $context);

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  • This regx does not work only in Chrome

    - by Deeptechtons
    Hi i just put up a validation function in jScript to validate filename in fileupload control[input type file]. The function seems to work fine in FF and sometimes in ie but never in Chrome. Basically the function tests if File name is atleast 1 char upto 25 characters long.Contains only valid characters,numbers [no spaces] and are of file types in the list. Could you throw some light on this function validate(Uploadelem) { var objRgx = new RegExp(/^[\w]{1,25}\.*\.(jpg|gif|png|jpeg|doc|docx|pdf|txt|rtf)$/); objRgx.ignoreCase = true; if (objRgx.test(Uploadelem.value)) { document.getElementById('moreUploadsLink').style.display = 'block'; } else { document.getElementById('moreUploadsLink').style.display = 'none'; } }

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  • Basic CHMOD restriction

    - by Marshall Mathews
    i have an uploads folder on my website. What i want to do is restrict users from accessing like i dont want them to go to www.mysite.com/uploads/ and see the files in there and it should show forbidden, but they should be able to download via my website, for example www.mysite.com/downloads.php?id=1 If thats not possible, how can i atleast not show them the directory index on /uploads How is it that file sharing websites does this? An htaccess with deny from all stops php from accessing the file as well Please tell me a solution if you would know, i googled and asked on irc a few days ago about this issue, its pretty confusing to me.

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  • Flash uploader that can handle >2GB files?

    - by Alvin SMith
    Is there an open source Flash uploader that can handle files larger than 2 GB? ASP.net implementations like SlickUpload are not an option, and SWFUpload (and others that I've seen) do not handle files larger than 2 GB. Nor is requiring the user to have Java installed to run applets. This would be for both IE and Firefox. I've seen a couple "large file transfer" sites that have a Flash uploader and claim to go past the 2GB limit (which is the limit for http uploads for most browsers) so I know it is technically possible.

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  • Redirect uploaded files to another server, using nginx

    - by Serg ikS
    I am creating a web service of scheduled posts to some soc. network.Need help dealing with file uploads under high traffic. Process overview: User uploads files to SomeServer (not mine). SomeServer then responds with a JSON string. My web app should store that JSON response. Opt. 1 — Save, cURL POST, delete tmp The stupid way I made it work: User uploads files to MyWebApp; MyWebApp cURL's the file further to SomeServer, getting the response. Opt.2 — JS magic The smart way it could be perfect: User uploads the file directly to SomeServer, from within an iFrame; MyWebApp gets the response through JavaScript. But this is(?) impossible due to the 'Same Origin Policy', isn't it? Opt. 3 — nginx proxying? The better way for a production server: User uploads files to MyWebApp; nginx intercepts the file uploads and sends them directly to the SomeServer; JSON response is also intercepted by nginx and processed by MyWebApp. Does this make any sense, and what would be the nginx config for, say, /fileupload Location to proxy it to SomeServer ?

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