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  • WebMethod Return xml

    - by BabelFish
    I keep reading how everyone states to return XmlDocument when you want to return XML. Is there a way to return raw XML as a string? I have used many web services (written by others) that return string and the string contains XML. If you return XmlDocument how is that method consumed by users that are not on .Net? What is the method to just return the raw XML as string without it having being wrapped with <string></string> Thanks!

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  • JAVA: XML parsers gives null element

    - by Johan
    When I try to parse a XML-file, it gives sometimes a null element by the title. I think it has to do with HTML-tags &#039; How can I solve this problem? I have the follow XML-file: <item> <title>&#039; Nieuwe DVD &#039;</title> <description>tekst, tekst tekst</description> <link>dvd.html</link> <category>nieuws</category> <pubDate>Sat, 1 Jan 2011 9:24:00 +0000</pubDate> </item> And the follow code to parse the xml-file: //DocumentBuilderFactory, DocumentBuilder are used for //xml parsing DocumentBuilderFactory dbf = DocumentBuilderFactory .newInstance(); DocumentBuilder db = dbf.newDocumentBuilder(); //using db (Document Builder) parse xml data and assign //it to Element Document document = db.parse(is); Element element = document.getDocumentElement(); //take rss nodes to NodeList element.normalize(); NodeList nodeList = element.getElementsByTagName("item"); if (nodeList.getLength() > 0) { for (int i = 0; i < nodeList.getLength(); i++) { //take each entry (corresponds to <item></item> tags in //xml data Element entry = (Element) nodeList.item(i); entry.normalize(); Element _titleE = (Element) entry.getElementsByTagName( "title").item(0); Element _categoryE = (Element) entry .getElementsByTagName("category").item(0); Element _pubDateE = (Element) entry .getElementsByTagName("pubDate").item(0); Element _linkE = (Element) entry.getElementsByTagName( "link").item(0); String _title = _titleE.getFirstChild().getNodeValue(); String _category = _categoryE.getFirstChild().getNodeValue(); Date _pubDate = new Date(_pubDateE.getFirstChild().getNodeValue()); String _link = _linkE.getFirstChild().getNodeValue(); //create RssItemObject and add it to the ArrayList RssItem rssItem = new RssItem(_title, _category, _pubDate, _link); rssItems.add(rssItem); conn.disconnect(); }

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  • Querying XML using node numbers

    - by CP
    Okay, so I'm writing a utility that compares 2 XML documents using Microsoft's XML diff patch tool. The result looks something like this: <?xml version="1.0" encoding="utf-16"?><xd:xmldiff version="1.0" srcDocHash="10728157883908851288" options="IgnoreChildOrder IgnoreComments IgnoreWhitespace " fragments="yes" xmlns:xd="http://schemas.microsoft.com/xmltools/2002/xmldiff"><xd:node match="1"><xd:node match="1"><xd:node match="1"><xd:node match="2"><xd:node match="1"><xd:node match="1"><xd:node match="2"><xd:change match="1">testi22n2123</xd:change></xd:node></xd:node><xd:add match="/1/1/1/2/1/8" opid="1" /><xd:node match="7"><xd:node match="1"><xd:change match="1">31</xd:change></xd:node><xd:node match="2"><xd:change match="1">test2ing</xd:change></xd:node></xd:node><xd:remove match="8" opid="1" /></xd:node></xd:node></xd:node></xd:node></xd:node><xd:descriptor opid="1" type="move" /></xd:xmldiff> What I'm trying to do is go back into the source document and get the source data that represents the difference. I initially tried creating an Xpath query, but as I understand it now this XmlDiff thing works off the DOM... which seems like the dinosaur of XML objects these days. What's the best way to get at the node in the source XML by using the numbers provided in the diff result?

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  • How to ignore the validation of Unknown tags ?

    - by infant programmer
    One more challenge to the XSD capability,I have been sending XML files by my clients, which will be having 0 or more undefined or [call] unexpected tags (May appear in hierarchy). Well they are redundant tags for me .. so I have got to ignore their presence, but along with them there are some set of tags which are required to be validated. This is a sample XML: <root> <undefined_1>one</undefined_1> <undefined_2>two</undefined_2> <node>to_be_validated</node> <undefined_3>two</undefined_3> <undefined_4>two</undefined_4> </root> And the XSD I tried with: <xs:element name="root" type="root"></xs:element> <xs:complexType name="root"> <xs:sequence> <xs:any maxOccurs="2" minOccurs="0"/> <xs:element name="node" type="xs:string"/> <xs:any maxOccurs="2" minOccurs="0"/> </xs:sequence> </xs:complexType XSD doesn't allow this, due to certain reasons. The above mentioned example is just a sample. The practical XML comes with the complex hierarchy of XML tags .. Kindly let me know if you can get a hack of it. By the way, The alternative solution is to insert XSL-transformation, before validation process. Well, I am avoiding it because I need to change the .Net code which triggers validation process, which is supported at the least by my company.

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  • Problems using Custom Layout in XML

    - by Kevin
    I've created a new GridLayout class that I want to use in an XML File. The class is in another project. I've created the attrs.xml file in the other project with my properties but when the constructor gets called with the AttributeSet, none of the values are set. In my xml for my screen layout, I refer to the layout with the following: xmlns:gridLayout="@com.mastertechsoftware.AndroidUtil:http://schemas.android.com/apk/res/com.mastertechsoftware.AndroidUtil" Not sure if that is right. I have the attrs.xml file being compiled to R.java in com/mastertechsoftware/AndroidUtil. All the right styleable values are there. In my constructor, I use: TypedArray a = c .obtainStyledAttributes(attrs, R.styleable.GridLayout); this.numRows = a.getInt(R.styleable.GridLayout_numRows, -1); Nothing comes back (-1 does but that means nothing is there) If I use int n = a.getIndexCount(); I get 0.

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  • Write Mysql tables to XML : Security Issue

    - by jasmine
    I want to make a news portal(php) with minimum mysql force. :create a cron, fetch data from mysql and write to a php file . (I dont know is it right way) But Can I use xml instead of php file? Write mysql data to xml. Is this a secure way? What is the best way? XML or php file? Thanks in advance

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  • Help me choose between XML or SQL Lite on android

    - by Ngetha
    I have an android app that periodically, say once a week downloads content from a server in XML. The content is used by the app, different Acitivities use different parts of the content. My question is a design one, should I save the data in SQlite or just keep it as an XML file, which one would be faster to read? The app can only use one content piece at a time, which means subsequent XML content downloads replace the old one.

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  • Serializing a class containing a custom class

    - by Netfangled
    I want to serialize an object as xml that contains other custom classes. From what I understand (I've been reading MSDN and SO mostly), the XmlSerializer doesn't take this into account. This is the line that's confusing me: XML serialization serializes only the public fields and property values of an object into an XML stream. XML serialization does not include type information. For example, if you have a Book object that exists in the Library namespace, there is no guarantee that it will be deserialized into an object of the same type. Taken from MSDN, here For example, I want to serialize an object of type Order, but it contains a list of Products, and each one contains an object of type Category: class Order { List<Product> products; } class Product { Category type; } class Category { string name; string description; } And I want my Order object to be serialized like so: <Order> <Product> <Category Name=""> <Description></Description> </Category> </Product> <Product> <Category Name=""> <Description></Description> </Category> </Product> <Order> Does the XmlSerializer already do this? If not, is there another class that does or do I have to define the serialization process myself?

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  • Update Empty XML Tag in SQL Server

    - by monO
    I'm trying to update an empty XML Tag in my Xml string on sql server; it says the row is updated when i run the following script, but when I view the XML; nothing has changed: Declare @newValue varchar(100) select @newValue = '01' update dbo.UploadReport set XmlTest.insert('replace value of (/CodeFiveReport/Owner/AgencyID/text())[1] with sql:variable("@newValue")') where id = 'myId' The xml after still appears as this in the databse <AgencyID /> What am I doing wrong? I've tried @AgencyID without the text() at the end and still no avail...

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  • Nokogiri extract data from xml

    - by Awea
    Hi guys, i try to extract data from a xml in rails application with the Nokogiri gem, the xml : <item> <description> <img src="something" title="anothething"> <p>text, bla bla...</p> </description> </item> Actually i do something like this to extract data from the xml : def test_content @return = Array.new site = 'http://www.les-encens.com/modules/feeder/rss.php?id_category=0' @doc = Nokogiri::XML(open(site, "UserAgent" => "Ruby-OpenURI")) @doc.xpath("//item").each do |n| @return << [ n.xpath('description') ] end end Could you show me how extract just the src attribute from the img tag ?

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  • Sorting the output from XmlSerializer in C#

    - by prosseek
    In this post, I could get an XML file generated based on C# class. Can I reorder the XML elements based on its element? My code uses var ser = new XmlSerializer(typeof(Module)); ser.Serialize(WriteFileStream, report, ns); WriteFileStream.Close(); to get the XML file, but I need to have the XML file sorted based on a BlocksCovered variable. public class ClassInfo { public string ClassName; public int BlocksCovered; public int BlocksNotCovered; public double CoverageRate; public ClassInfo() {} public ClassInfo(string ClassName, int BlocksCovered, int BlocksNotCovered, double CoverageRate) { this.ClassName = ClassName; this.BlocksCovered = BlocksCovered; this.BlocksNotCovered = BlocksNotCovered; this.CoverageRate = CoverageRate; } } [XmlRoot("Module")] public class Module { [XmlElement("Class")] public List<ClassInfo> ClassInfoList; public int BlocksCovered; public int BlocksNotCovered; public string moduleName; public Module() { ClassInfoList = new List<ClassInfo>(); BlocksCovered = 0; BlocksNotCovered = 0; moduleName = ""; } } Module report = new Module(); ... TextWriter WriteFileStream = new StreamWriter(xmlFileName); XmlSerializerNamespaces ns = new XmlSerializerNamespaces(); ns.Add("", ""); var ser = new XmlSerializer(typeof(Module)); ser.Serialize(WriteFileStream, report, ns); WriteFileStream.Close();

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  • Traverse a XML using Recursive function

    - by Kaja
    How can I traverse (read all the nodes in order) a XML document using recursive functions in c#? What I want is to read all the nodes in xml (which has attributes) and print them in the same structure as xml (but without Node Localname) Thanks

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  • Export XML with only one MySQL request ?

    - by mere-teresa
    I want to export in XML format some data from 7 tables (MySQL database), and then I want to import in another database. And I have a update or insert rule for data. I already have a SQL query retrieving all data, with JOINs on my 7 tables. But...when I try to put data in XML format, I reach a limit. My PHP loop can catch each row, but I would like to benefit from hierachical structure of the XML, and all I have are rows with the same data repeated. It is better to query once and to construct the XML tree in PHP or to query each time I want access to a lower level ?

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  • XML Database in C#.net

    - by rookieinfotech
    I am developing a WPF client program for some websites. It uses XML database. I am new to XML. Would someone please explain how to create,append(Most important),edit,read&encrypt XML file. It is a big question,i know . But, it is urgent.Have to complete the work ASAP. Searched in the internet, not getting correct info.

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  • Read [for xml auto, elements] into DataTable in ADO.NET

    - by ihorko
    Hello All! I have MS SQL Server stored procedure that returns XML (it uses SELECT with for xml auto, elements) I tried read it into DataTable: DataTable retTable = new DataTable(); SqlCommand comm = new SqlCommand("exec MySP", connection); SqlDataAdapter da = new SqlDataAdapter(comm); connection.Open(); da.Fill(retTable); but retTable contains 12 rows with separated full xml thar SQL Server returns. How can I read that XML from DB into DataTable object? Thanks!

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  • From Java/C++ to XML

    - by Greenhouse Gases
    I know Java and C++ but am looking to get in to XML. I don't want to waste time reading over the basics of programming in a book, so has anyone any recommendations for resources for learning XML that assume a knowledge of programming already, or even better highlight how to switch from Java/C++ to XML ie. main differences etcs.

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  • Load php file wth xml header

    - by John Smith
    I have a php file with an xml header and xml code, named test.php. How do I load this file as an xml? The following doesn't work: $xml = simplexml_load_file('test.php'); echo $xml; I just get a white page. The test file is saved as php, as it's dynamic. It's loading data from the tradedoubler api. The xml looks something like this: <voucherList> <voucher> <id>115</id> <programId>111</programId> <programName>Program 111</programName> <code>AF30C5</code> <updateDate>1332422674941</updateDate> <startDate>1332370800000</startDate> <endDate>1363906800000</endDate> <title>Voucher number one</title> <shortDescription>Short description of the voucher.</shortDescription> <description>This is a long version of the voucher description.</description> <voucherTypeId>1</voucherTypeId> <defaultTrackUri>http://clk.tradedoubler.com/click?a(222)p(111)ttid(13)</defaultTrackUri> <siteSpecific>True</siteSpecific> </voucher> <voucher> <id>116</id> <programId>111</programId> <programName>Program 111</programName> <code>F90Z4F</code> <updateDate>1332423212631</updateDate> <startDate>1332370800000</startDate> <endDate>1363906800000</endDate> <title>The second voucher</title> <shortDescription>Short description of the voucher.</shortDescription> <description>This is a long version of the voucher description.</description> <voucherTypeId>1</voucherTypeId> <defaultTrackUri>http://clk.tradedoubler.com/click?a(222)p(111)ttid(13)url(http://www.example.com/product?id=123)</defaultTrackUri> <siteSpecific>False</siteSpecific> <landingUrl>http://www.example.com/product?id=123</landingUrl> </voucher> </voucherList>

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  • Obtaining XML from U.S. Postal Service (USPS) rate calculator API with PHP

    - by Chris F
    hoping somebody here can help me. I'm attempting to pull an XML page from the U.S. Postal Service (USPS) rate calculator, using PHP. Here is the code I am using (with my API login and password replaced of course): <? $api = "http://production.shippingapis.com/ShippingAPI.dll?API=RateV4&XML=<RateV4Request ". "USERID=\"MYUSERID\" PASSWORD=\"MYPASSWORD\"><Revision/><Package ID=\"1ST\">". "<Service>FIRST CLASS</Service><FirstClassMailType>PARCEL</FirstClassMailType>". "<ZipOrigination>12345</ZipOrigination><ZipDestination>54321</ZipDestination>". "<Pounds>0</Pounds><Ounces>9</Ounces><Container/><Size>REGULAR</Size></Package></RateV4Request>"; $xml_string = file_get_contents($api); $xml = simplexml_load_string($xml_string); ?> Pretty straightforward. However it never returns anything. I can paste the URL directly into my browser's address bar: http://production.shippingapis.com/ShippingAPI.dll?API=RateV4&XML=<RateV4RequestUSERID="MYUSERID" PASSWORD="MYPASSWORD"><Revision/><Package ID="1ST"><Service>FIRST CLASS</Service><FirstClassMailType>PARCEL</FirstClassMailType><ZipOrigination>12345</ZipOrigination><ZipDestination>54321</ZipDestination><Pounds>0</Pounds><Ounces>9</Ounces><Container/><Size>REGULAR</Size></Package></RateV4Request> And it returns the XML I need, so I know the URL is valid. But I cannot seem to capture it using PHP. Any help would be tremendously appreciated. Thanks in advance.

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  • receive xml file as a parameter to a .net web service

    - by fizch
    My company is currently looking into bringing a new piece of third party software in for online ordering. The software does not handle pricing so they are requesting the pricing information from a web service. Their software is passing an XML file as a parameter, and expecting an XML file as a response. I would think that returning an XML file would be pretty straight forward, but I cannot think of a way to receive an XML file as a parameter. Has anyone done this, or am I missing something really obvious?

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  • Java: Writing a DOM to an XML file (formatting issues)

    - by Vhaerun
    I'm using org.w3c XML API to open an existing XML file. I'm removing some nodes , and I'm adding others instead . The problem is that the new nodes that are added are written one after another , with no newline and no indentation what so ever. While it's true that the XML file is valid , it is very hard for a human to examnine it. Is there anyway to add indentation , or at least a newline after each node ?

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  • xml parsing takes extra spaces.

    - by SDK
    I have been trying to write/parse xml file in python. The tags are very simple <main> <data> abcdef </data> </main> I have written this xml using xml document writer from xml.dom.minidom. How-ever when i try to parse this and try to fetch data-text value, i get 'abcdef' with spaces/carriage return/newline characters in beg and end. Does parsing does not take of indenting spaces? Following is the parsing snippet (ref from net) dom = parseString(data) clipTag = dom.getElementsByTagName('clipdata')[0].toxml() clipData=clipTag.replace('<clipdata>','').replace('</clipdata>','') Kindly suggest.

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  • Android Java error handling XML file

    - by Paul
    I'm using SAX and XML reader to read XML weather info from the web and it works fine if the page exists. But if for instance the user inputs an invalid city, zip etc the XML page that gets read from is empty and the app force closes with nullpointerexception. The area that generates the error is here right at open inputstream. Any suggestions?: SAXParserFactory spf = SAXParserFactory.newInstance(); SAXParser sp = null; try { sp = spf.newSAXParser(); } catch (ParserConfigurationException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (SAXException e) { // TODO Auto-generated catch block e.printStackTrace(); } /* Get the XMLReader of the SAXParser we created. */ XMLReader xr = null; try { xr = sp.getXMLReader(); } catch (SAXException e) { // TODO Auto-generated catch block e.printStackTrace(); } /* Create a new ContentHandler and apply it to the XML-Reader*/ WeatherHandler myExampleHandler = new WeatherHandler(); xr.setContentHandler(myExampleHandler); /* Parse the xml-data from our URL. */ try { xr.parse(new InputSource(url.openStream())); parsedWeatherDataSet = myExampleHandler.getParsedData(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (SAXException e) { // TODO Auto-generated catch block e.printStackTrace(); } return parsedWeatherDataSet.toString();

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  • Invalid XML Replace Content in PHP

    - by streetparade
    I have a invalid XML like this Warning: count() [function.count]: Node no longer exists in /var/bla/test.php <?xml version="1.0" encoding="ISO-8859-1"?> <nodes> <some>test</some> </nodes> Now i need a regex which would replace the Warning: count() [function.count]: Node no longer exists in /var/bla/test.php with "" how can i do that? The above xml is is not generated on my localmachine, its a api call which returned a invalid xml

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