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  • Right way to return proxy model instance from a base model instance in Django ?

    - by sotangochips
    Say I have models: class Animal(models.Model): type = models.CharField(max_length=255) class Dog(Animal): def make_sound(self): print "Woof!" class Meta: proxy = True class Cat(Animal): def make_sound(self): print "Meow!" class Meta: proxy = True Let's say I want to do: animals = Animal.objects.all() for animal in animals: animal.make_sound() I want to get back a series of Woofs and Meows. Clearly, I could just define a make_sound in the original model that forks based on animal_type, but then every time I add a new animal type (imagine they're in different apps), I'd have to go in and edit that make_sound function. I'd rather just define proxy models and have them define the behavior themselves. From what I can tell, there's no way of returning mixed Cat or Dog instances, but I figured maybe I could define a "get_proxy_model" method on the main class that returns a cat or a dog model. Surely you could do this, and pass something like the primary key and then just do Cat.objects.get(pk = passed_in_primary_key). But that'd mean doing an extra query for data you already have which seems redundant. Is there any way to turn an animal into a cat or a dog instance in an efficient way? What's the right way to do what I want to achieve?

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  • Inlines in Django Admin

    - by Oli
    I have two models, Order and UserProfile. Each Order has a ForeignKey to UserProfile, to associate it with that user. On the django admin page for each Order, I'd like to display the UserProfile associated with it, for easy processing of information. I have tried inlines: class UserInline(admin.TabularInline): model = UserProfile class ValuationRequestAdmin(admin.ModelAdmin): list_display = ('address1', 'address2', 'town', 'date_added') list_filter = ('town', 'date_added') ordering = ('-date_updated',) inlines = [ UserInline, ] But it complains that UserProfile "has no ForeignKey to" Order - which it doesn't, it's the other way around. Is there a way to do what I want?

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  • Which is faster??

    - by kaki
    is opening a large file once reading it completely once to list faster (or) opening smaller files whose total sum of size is equal to large file and loading smaller file into list manupalating one by one faster? which is faster?? is the difference is time large enough to impact my program?? total time difference of lesser then of 30 sec is negligible for me

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  • Google App Engine - Document Editor Creation/Tap Into Google Docs?

    - by Josh Patton
    What is the best way to create a custom document editor in GAE? I'm making a website meant for a School Robotics Club (With support for any other organization - DRY). We currently use Google services for online collaboration, I'm wondering if there is a way to tap into Google Docs and allow users to edit a Google Document without using Google Accounts or the Google Doc interface. If that is not possible (I've researched and I don't think it is), what is the best way to make a document editor? I want it completely on the website I'm creating, so I'm assuming just some javascript editor like TinyMCE + Ajax + Datastore. Is their anything that replicates Google Doc's/Microsoft Offices's/OpenOffice.org's feature set as far as fonts, spacing, alignment, justification, etc.?

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  • Segment string into array, regex?

    - by Hanpan
    I have a string which looks like this: "[segment1][segment2][segment2]" What I'd like is to be able to split the string into an array, so I'd end up with: Array[0] = "segment1", Array[1] = "segment2", Array[2] = "segment3" I've tried using the string split function, but it doesn't seem to do exactly what I want. I was wondering if anyone has some regex which might help me out? Thanks in advance

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  • Does urllib2.urlopen() actually fetch the page?

    - by beagleguy
    hi all, I was condering when I use urllib2.urlopen() does it just to header reads or does it actually bring back the entire webpage? IE does the HTML page actually get fetch on the urlopen call or the read() call? handle = urllib2.urlopen(url) html = handle.read() The reason I ask is for this workflow... I have a list of urls (some of them with short url services) I only want to read the webpage if I haven't seen that url before I need to call urlopen() and use geturl() to get the final page that link goes to (after the 302 redirects) so I know if I've crawled it yet or not. I don't want to incur the overhead of having to grab the html if I've already parsed that page. thanks!

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  • SQLAlchemy: a better way for update with declarative?

    - by hadrien
    I am a SQLAlchemy noob. Let's say I have an user table in declarative mode: class User(Base): __tablename__ = 'user' id = Column(u'id', Integer(), primary_key=True) name = Column(u'name', String(50)) When I know user's id without object loaded into session, I update such user like this: ex = update(User.__table__).where(User.id==123).values(name=u"Bob Marley") Session.execute(ex) I dislike using User.__table__, should I stop worrying with that? Is there a better way to do this? Thanx!

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  • pyInotify performance

    - by tranimatronic
    I have a very large directory tree I am wanting pyInotify to watch. Is it better to have pyInotify watch the entire tree or is it better to have a number of watches reporting changes to specific files ? Thanks

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  • How to give points for each indices of list

    - by Eric Jung
    def voting_borda(rank_ballots): '''(list of list of str) -> tuple of (str, list of int) The parameter is a list of 4-element lists that represent rank ballots for a single riding. The Borda Count is determined by assigning points according to ranking. A party gets 3 points for each first-choice ranking, 2 points for each second-choice ranking and 1 point for each third-choice ranking. (No points are awarded for being ranked fourth.) For example, the rank ballot shown above would contribute 3 points to the Liberal count, 2 points to the Green count and 1 point to the CPC count. The party that receives the most points wins the seat. Return a tuple where the first element is the name of the winning party according to Borda Count and the second element is a four-element list that contains the total number of points for each party. The order of the list elements corresponds to the order of the parties in PARTY_INDICES.''' #>>> voting_borda([['GREEN','NDP', 'LIBERAL', 'CPC'], ['GREEN','CPC','LIBERAL','NDP'], ['LIBERAL','NDP', 'CPC', 'GREEN']]) #('GREEN',[4, 6, 5, 3]) list_of_party_order = [] for sublist in rank_ballots: for party in sublist[0]: if party == 'GREEN': GREEN_COUNT += 3 elif party == 'NDP': NDP_COUNT += 3 elif party == 'LIBERAL': LIBERAL_COUNT += 3 elif party == 'CPC': CPC_COUNT += 3 for party in sublist[1]: if party == 'GREEN': GREEN_COUNT += 2 elif party == 'NDP': NDP_COUNT += 2 elif party == 'LIBERAL': LIBERAL_COUNT += 2 elif party == 'CPC': CPC_COUNT += 2 for party in sublist[2]: if party == 'GREEN': GREEN_COUNT += 1 elif party == 'NDP': NDP_COUNT += 1 elif party == 'LIBERAL': LIBERAL_COUNT += 1 elif party == 'CPC': CPC_COUNT += 1 I don't know how I would give points for each indices of the list MORE SIMPLY. Can someone please help me? Without being too complicated. Thank you!

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  • Images to video - converting to IplImage makes video blue

    - by user891908
    I want to create a video from images using opencv. The strange problem is that if i will write image (bmp) to disk and then load (cv.LoadImage) it it renders fine, but when i try to load image from StringIO and convert it to IplImage, it turns video to blue. Heres the code: import StringIO output = StringIO.StringIO() FOREGROUND = (0, 0, 0) TEXT = 'MY TEXT' font_path = 'arial.ttf' font = ImageFont.truetype(font_path, 18, encoding='unic') text = TEXT.decode('utf-8') (width, height) = font.getsize(text) # Create with background with place for text w,h=(600,600) contentimage=Image.open('0.jpg') background=Image.open('background.bmp') x, y = contentimage.size # put content onto background background.paste(contentimage,(((w-x)/2),0)) draw = ImageDraw.Draw(background) draw.text((0,0), text, font=font, fill=FOREGROUND) pi = background pi.save(output, "bmp") #pi.show() #shows image in full color output.seek(0) pi= Image.open(output) print pi, pi.format, "%dx%d" % pi.size, pi.mode cv_im = cv.CreateImageHeader(pi.size, cv.IPL_DEPTH_8U, 3) cv.SetData(cv_im, pi.tostring()) print pi.size, cv.GetSize(cv_im) w = cv.CreateVideoWriter("2.avi", cv.CV_FOURCC('M','J','P','G'), 1,(cv.GetSize(cv_im)[0],cv.GetSize(cv_im)[1]), is_color=1) for i in range(1,5): cv.WriteFrame(w, cv_im) del w

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  • remove border of a gtk.button

    - by spanctus
    Hi, I want to remove the border of the gtk.button, but i Don't know how to do it. I tried with : button = gtk.Button() button.set_style("inner-border",0) but i have an error : the property doesn't exist. I tried too to create a new gtk.Style and use it for the button, but same error. Anyone has an idea ? Thanks

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  • Regex and unicode

    - by dbr
    I have a script that parses the filenames of TV episodes (show.name.s01e02.avi for example), grabs the episode name (from the www.thetvdb.com API) and automatically renames them into something nicer (Show Name - [01x02].avi) The script works fine, that is until you try and use it on files that have Unicode show-names (something I never really thought about, since all the files I have are English, so mostly pretty-much all fall within [a-zA-Z0-9'\-]) How can I allow the regular expressions to match accented characters and the likes? Currently the regex's config section looks like.. config['valid_filename_chars'] = """0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ!@£$%^&*()_+=-[]{}"'.,<>`~? """ config['valid_filename_chars_regex'] = re.escape(config['valid_filename_chars']) config['name_parse'] = [ # foo_[s01]_[e01] re.compile('''^([%s]+?)[ \._\-]\[[Ss]([0-9]+?)\]_\[[Ee]([0-9]+?)\]?[^\\/]*$'''% (config['valid_filename_chars_regex'])), # foo.1x09* re.compile('''^([%s]+?)[ \._\-]\[?([0-9]+)x([0-9]+)[^\\/]*$''' % (config['valid_filename_chars_regex'])), # foo.s01.e01, foo.s01_e01 re.compile('''^([%s]+?)[ \._\-][Ss]([0-9]+)[\.\- ]?[Ee]([0-9]+)[^\\/]*$''' % (config['valid_filename_chars_regex'])), # foo.103* re.compile('''^([%s]+)[ \._\-]([0-9]{1})([0-9]{2})[\._ -][^\\/]*$''' % (config['valid_filename_chars_regex'])), # foo.0103* re.compile('''^([%s]+)[ \._\-]([0-9]{2})([0-9]{2,3})[\._ -][^\\/]*$''' % (config['valid_filename_chars_regex'])), ]

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  • class inheretence of a attribute which is itself a class

    - by alex
    i have a class which inherets a attribute from a super-class. this attribute is a class itself. class classA(superClass): def func(self,x): if self.attributeB is None: do somthing and in the other class i have class superClass: self.attributB = classB() i get the error AttributeError: class classA has no attribute 'attributeB' when i access the attribute like i showed but if on command line i can see it works, x = classA() x.attributeB is None True so the test works. whats going on in the above code?

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  • django link format words joined with hypens

    - by soField
    href="http://www.torontolife.com/daily/daily-dish/restauranto/2010/03/10/best-new-restaurants-2010-james-chatto-names-five-honourable-mentions/"Best new restaurants 2010: honourable mentions is django has built in mechanism to format links above i mean words joined with hypens how can achieve this ?

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  • How do I compare two complex data structures?

    - by Phil H
    I have some nested datastructures, each something like: [ ('foo', [ {'a':1, 'b':2}, {'a':3.3, 'b':7} ]), ('bar', [ {'a':4, 'd':'efg', 'e':False} ]) ] I need to compare these structures, to see if there are any differences. Short of writing a function to explicitly walk the structure, is there an existing library or method of doing this kind of recursive comparison?

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  • How can I merge two lists and sort them working in 'linear' time?

    - by Sergio Tapia
    I have this, and it works: # E. Given two lists sorted in increasing order, create and return a merged # list of all the elements in sorted order. You may modify the passed in lists. # Ideally, the solution should work in "linear" time, making a single # pass of both lists. def linear_merge(list1, list2): finalList = [] for item in list1: finalList.append(item) for item in list2: finalList.append(item) finalList.sort() return finalList # +++your code here+++ return But, I'd really like to learn this stuff well. :) What does 'linear' time mean?

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