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  • Proper HTML technique to create an web form out of an image

    - by Lars
    I plan to create an interactive golf score card for my website (XHTML). (Btw. thats how such a scorecard looks like: ScoreCard). So at the end one should be able to insert a score for each hole in the appropriated input field in the virtual scorecard on the website. For me it is very important that the interactive scorecard really looks the same as the original (paper-) scorecard does and so my first approach was to scan and slice the scorecard image to reach that appearance. Here you can see the way I sliced the image: The idea was to insert HTML text input for each score field ending up with something like this: After I sliced the image I reconstructed it using the HTML . To do that I put the image slices as the cell background. <table> <tr> <td style="background: url("slice1.jpg") width="58px" height="25px"> <input type="text"></inputText> </td> </tr> ... </table> At the first moment this worked fine (as Gimp offers quite a nice feature for this). Then the problem was that I had to create a HTML table to create the exact layout. As you can see the lower part of the layout is split up into 3 columns. The middle column is split up into several (for each hole) rows. So the left and right column have to be spanned over those rows. Ok finally that worked, but it lead to some kind of scaling problem. If I zoom in or out on the table the middle column (and only that one) is not scaled the right way. Iam not able to fix this, and so I start doubting if this is the right technique for html image virtualization. Iam really no specialist in the area of creating websites, so I would really appriciate any help on this. Maybe there is a complete other and better technique to do that, as I think it is a common job in webcreation. I couldnt find any nice examples or tuts on that.

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  • Jquery remove class from image

    - by user1269625
    Hey ya'll I have these 3 images thumbnails here... <div class="wpcart_gallery" style="text-align:center; padding-top:5px;"> <a class="thickbox cboxElement" title="DSC_0118" href="http://www.taranmarlowjewelry.com/wp-content/uploads/2012/07/DSC_0118.jpg" rel="Teardrop Druzy Amethyst Ring" rev="http://www.taranmarlowjewelry.com/wp-content/uploads/2012/07/DSC_0118.jpg"> <img class="attachment-gold-thumbnails colorbox-736" width="50" height="50" title="DSC_0118" alt="DSC_0118" src="http://www.taranmarlowjewelry.com/wp-content/uploads/2012/07/DSC_0118-50x50.jpg"> </a> <a class="thickbox cboxElement" title="P7230376" href="http://www.taranmarlowjewelry.com/wp-content/uploads/2012/07/P7230376.jpg" rel="Teardrop Druzy Amethyst Ring" rev="http://www.taranmarlowjewelry.com/wp-content/uploads/2012/07/P7230376.jpg"> <img class="attachment-gold-thumbnails colorbox-736" width="50" height="50" title="P7230376" alt="P7230376" src="http://www.taranmarlowjewelry.com/wp-content/uploads/2012/07/P7230376-50x50.jpg"> </a> <a class="thickbox cboxElement" title="P7230378" href="http://www.taranmarlowjewelry.com/wp-content/uploads/2012/07/P7230378.jpg" rel="Teardrop Druzy Amethyst Ring" rev="http://www.taranmarlowjewelry.com/wp-content/uploads/2012/07/P7230378.jpg"> <img class="attachment-gold-thumbnails colorbox-736" width="50" height="50" title="P7230378" alt="P7230378" src="http://www.taranmarlowjewelry.com/wp-content/uploads/2012/07/P7230378-50x50.jpg"> </a> </div> What I am trying to do is come up with a jquery code that would remove the cboxElement from the first image and if I click on one of the images to remove cboxElement and place cboxElement to the other images... I also have this big image and when you click on one of the thumbnails, the image is replaced by the thumbnail and thats really the thumbnail I want to exclude...Could I possible just say if one of the 3 images src = this one image = src remove the class from this thumbnail? Which way would be better? I am very new at jquery :( I hope this makes sense. Here is the code for the big image... <a class="preview_link cboxElement" style="text-decoration:none;" href="http://www.taranmarlowjewelry.com/wp-content/uploads/2012/07/DSC_0118.jpg" rel="Teardrop Druzy Amethyst Ring"> <img id="product_image_736" class="product_image colorbox-736" width="400" src="http://www.taranmarlowjewelry.com/wp-content/uploads/2012/07/DSC_0118.jpg" title="Teardrop Druzy Amethyst Ring" alt="Teardrop Druzy Amethyst Ring"> <br> <div style="text-align:center; color:#F39B91;">Click To Enlarge</div> </a> Any help or a point in the right direction would be awesome!!

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  • How to Add a Business Card, or vCard (.vcf) File, to a Signature in Outlook 2013 Without Displaying an Image

    - by Lori Kaufman
    Whenever you add a Business Card to your signature in Outlook 2013, the Signature Editor automatically generates a picture of it and includes that in the signature as well as attaching the .vcf file. However, there is a way to leave out the image. To remove the business card image from your signature but maintain the attached .vcf file, you must make a change to the registry. NOTE: Before making changes to the registry, be sure you back it up. We also recommend creating a restore point you can use to restore your system if something goes wrong. Before changing the registry, we must add the Business Card to the signature and save it so a .vcf file of the contact is created in the Signatures folder. To do this, click the File tab. Click Options in the menu list on the left side of the Account Information screen. On the Outlook Options dialog box, click Mail in the list of options on the left side of the dialog box. On the Mail screen, click Signatures in the Compose messages section. For this example, we will create a new signature to include the .vcf file for your business card without the image. Click New below the Select signature to edit box. Enter a name for the new signature, such as Business Card, and click OK. Enter text in the signature editor and format it the way you want or insert a different image or logo. Click Business Card above the signature editor. Select the contact you want to include in the signature on the Insert Business Card dialog box and click OK. Click Save below the Select signature to edit box. This creates a .vcf file for the business card in the Signatures folder. Click on the business card image in the signature and delete it. You should only see your formatted text or other image or logo in the signature editor. Click OK to save your new signature and close the signature editor. Close Outlook as well. Now, we will open the Registry Editor to add a key and value to indicate where to find the .vcf to include in the signature we just created. If you’re running Windows 8, press the Windows Key + X to open the command menu and select Run. You can also press the Windows Key + R to directly access the Run dialog box. NOTE: In Windows 7, select Run from the Start menu. In the Open edit box on the Run dialog box, enter “regedit” (without the quotes) and click OK. If the User Account Control dialog box displays, click Yes to continue. NOTE: You may not see this dialog box, depending on your User Account Control settings. Navigate to the following registry key: HKEY_CURRENT_USER\Software\Microsoft\Office\15.0\Outlook\Signatures Make sure the Signatures key is selected. Select New | String Value from the Edit menu. NOTE: You can also right-click in the empty space in the right pane and select New | String Value from the popup menu. Rename the new value to the name of the Signature you created. For this example, we named the value Business Card. Double-click on the new value. In the Value data edit box on the Edit String dialog box, enter the value indicating the location of the .vcf file to include in the signature. The format is: <signature name>_files\<name of .vcf file> For our example, the Value data should be as follows: Business Card_files\Lori Kaufman The name of the .vcf file is generally the contact name. If you’re not sure of what to enter for the Value data for the new key value, you can check the location and name of the .vcf file. To do this, open the Outlook Options dialog box and access the Mail screen as instructed earlier in this article. However, press and hold the Ctrl key while clicking the Signatures button. The Signatures folder opens in Windows Explorer. There should be a folder in the Signatures folder named after the signature you created with “_files” added to the end. For our example, the folder is named Business Card_files. Open this folder. In this folder, you should see a .vcf file with the name of your contact as the name of the file. For our contact, the file is named Lori Kaufman.vcf. The path to the .vcf file should be the name of the folder for the signature (Business Card_files), followed by a “\”, and the name of the .vcf file without the extension (Lori Kaufman). Putting these names together, you get the path that should be entered as the Value data in the new key you created in the Registry Editor. Business Card_files\Lori Kaufman Once you’ve entered the Value data for the new key, select Exit from the File menu to close the Registry Editor. Open Outlook and click New Email on the Home tab. Click Signature in the Include section of the New Mail Message tab and select your new signature from the drop-down menu. NOTE: If you made the new signature the default signature, it will be automatically inserted into the new mail message. The .vcf file is attached to the email message, but the business card image is not included. All you will see in the body of the email message is the text or other image you included in the signature. You can also choose to include an image of your business card in a signature with no .vcf file attached.     

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  • How can I improve this collision detection logic?

    - by Dan
    I’m trying to make an android game and I’m having a bit of trouble getting the collision detection to work. It works sometimes but my conditions aren’t specific enough and my program gets it wrong. How could I improve the following if conditions? public boolean checkColisionWithPlayer( Player player ) { // Top Left // Top Right // Bottom Right // Bottom Left // int[][] PP = { { player.x, player.y }, { player.x + player.width, player.y }, {player.x + player.height, player.y + player.width }, { player.x, player.y + player.height } }; // TOP LEFT - PLAYER // if( ( PP[0][0] > x && PP[0][0] < x + width ) && ( PP[0][1] > y && PP[0][1] < y + height ) && ( (x - player.x) < 0 ) ) { player.isColided = true; //player.isSpinning = false; // Collision On Right if( PP[0][0] > ( x + width/2 ) && ( PP[0][1] - y < ( x + width ) - PP[0][0] ) ) { Log.i("Colision", "Top Left - Right Side"); player.x = ( x + width ) + 1; player.Vh = player.phy.getVelsoityWallColision(player.Vh, player.Cr); } // Collision On Bottom else if( PP[0][1] > ( y + height/2 ) ) { Log.i("Colision", "Top Left - Bottom Side"); player.y = ( y + height ) + 1; if( player.Vv > 0 ) player.Vv = 0; } return true; } // TOP RIGHT - PLAYER // else if( ( PP[1][0] > x && PP[1][0] < x + width ) && ( PP[1][1] > y && PP[1][1] < y + height ) && ( (x - player.x) > 0 ) ) { player.isColided = true; //player.isSpinning = false; // Collision On Left if( PP[1][0] < ( x + width/2 ) && ( PP[1][0] - x < PP[1][1] - y ) ) { Log.i("Colision", "Top Right - Left Side"); player.x = ( x ) + 1; player.Vh = player.phy.getVelsoityWallColision(player.Vh, player.Cr); } // Collision On Bottom else if( PP[1][1] > ( y + height/2 ) ) { Log.i("Colision", "Top Right - Bottom Side"); player.y = ( y + height ) + 1; if( player.Vv > 0 ) player.Vv = 0; } return true; } // BOTTOM RIGHT - PLAYER // else if( ( PP[2][0] > x && PP[2][0] < x + width ) && ( PP[2][1] > y && PP[2][1] < y + height ) ) { player.isColided = true; //player.isSpinning = false; // Collision On Left if( PP[2][0] < ( x + width/2 ) && ( PP[2][0] - x < PP[2][1] - y ) ) { Log.i("Colision", "Bottom Right - Left Side"); player.x = ( x ) + 1; player.Vh = player.phy.getVelsoityWallColision(player.Vh, player.Cr); } // Collision On Top else if( PP[2][1] < ( y + height/2 ) ) { Log.i("Colision", "Bottom Right - Top Side"); player.y = y - player.height; player.Vv = player.phy.getVelsoityWallColision(player.Vv, player.Cr); //player.Vh = -1 * ( player.phy.getVelsoityWallColision(player.Vv, player.Cr) ); int rs = x - player.x; Log.i("RS", String.format("%d", rs)); if( rs > 0 ) { player.direction = -1; player.isSpinning = true; player.Vh = -0.5 * ( player.phy.getVelsoityWallColision(player.Vv, player.Cr) ); } if( rs < 0 ) { player.direction = 1; player.isSpinning = true; player.Vh = 0.5 * ( player.phy.getVelsoityWallColision(player.Vv, player.Cr) ); } player.rotateSpeed = 1 * rs; } return true; } // BOTTOM LEFT - PLAYER // else if( ( PP[3][0] > x && PP[3][0] < x + width ) && ( PP[3][1] > y && PP[3][1] < y + height ) )//&& ( (x - player.x) > 0 ) ) { player.isColided = true; //player.isSpinning = false; // Collision On Right if( PP[3][0] > ( x + width/2 ) && ( PP[3][1] - y < ( x + width ) - PP[3][0] ) ) { Log.i("Colision", "Bottom Left - Right Side"); player.x = ( x + width ) + 1; player.Vh = player.phy.getVelsoityWallColision(player.Vh, player.Cr); } // Collision On Top else if( PP[3][1] < ( y + height/2 ) ) { Log.i("Colision", "Bottom Left - Top Side"); player.y = y - player.height; player.Vv = player.phy.getVelsoityWallColision(player.Vv, player.Cr); //player.Vh = -1 * ( player.phy.getVelsoityWallColision(player.Vv, player.Cr) ); int rs = x - player.x; //Log.i("RS", String.format("%d", rs)); //player.direction = -1; //player.isSpinning = true; if( rs > 0 ) { player.direction = -1; player.isSpinning = true; player.Vh = -1 * ( player.phy.getVelsoityWallColision(player.Vv, player.Cr) ); } if( rs < 0 ) { player.direction = 1; player.isSpinning = true; player.Vh = 1 * ( player.phy.getVelsoityWallColision(player.Vv, player.Cr) ); } player.rotateSpeed = 1 * rs; } //try { Thread.sleep(1000, 0); } //catch (InterruptedException e) {} return true; } else { player.isColided = false; player.isSpinning = true; } return false; }

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  • Rotate triangle so that its tip points in the direction of the point on the screen that we last touched

    - by Sid
    OpenGL ES - Android. Hello all, I am unable to rotate the triangle accordingly in such a way that its tip always points to my finger. What i did : Constructed a triangle in by GL.GL_TRIANGLES. Added touch events to it. I can rotate the triangle along my Z-axis successfully. Even made the vector class for it. What i need : Each time when I touch the screen, I want to rotate the triangle to face the touch point. Need some help. Here's what i implemented. I wonder that where i am going wrong? My code : public class Graphic2DTriangle { private FloatBuffer vertexBuffer; private ByteBuffer indexBuffer; private float[] vertices = { -1.0f,-1.0f, 0.0f, 2.0f, 0.0f, 0.0f, -1.0f, 1.0f, 0.0f }; private byte[] indices = { 0, 1, 2 }; public Graphic2DTriangle() { ByteBuffer vbb = ByteBuffer.allocateDirect(vertices.length * 4); vbb.order(ByteOrder.nativeOrder()); // Use native byte order vertexBuffer = vbb.asFloatBuffer(); // Convert byte buffer to float vertexBuffer.put(vertices); // Copy data into buffer vertexBuffer.position(0); // Rewind // Setup index-array buffer. Indices in byte. indexBuffer = ByteBuffer.allocateDirect(indices.length); indexBuffer.put(indices); indexBuffer.position(0); } public void draw(GL10 gl) { gl.glEnableClientState(GL10.GL_VERTEX_ARRAY); gl.glVertexPointer(3, GL10.GL_FLOAT, 0, vertexBuffer); gl.glDrawElements(GL10.GL_TRIANGLES, indices.length, GL10.GL_UNSIGNED_BYTE, indexBuffer); gl.glDisableClientState(GL10.GL_VERTEX_ARRAY); } } My SurfaceView class where i've done some Touch Events. public class BallThrowGLSurfaceView extends GLSurfaceView{ MySquareRender _renderObj; View _viewObj; float oldX,oldY,dX,dY; final float TOUCH_SCALE_FACTOR = 0.6f; Vector2 touchPos = new Vector2(); float angle=0; public BallThrowGLSurfaceView(Context context) { super(context); // TODO Auto-generated constructor stub _renderObj = new MySquareRender(context); this.setRenderer(_renderObj); this.setRenderMode(RENDERMODE_WHEN_DIRTY); } @Override public boolean onTouchEvent(MotionEvent event) { // TODO Auto-generated method stub touchPos.x = event.getX(); touchPos.y = event.getY(); Log.i("Co-ord", touchPos.x+"hh"+touchPos.y); switch(event.getAction()){ case MotionEvent.ACTION_MOVE : dX = touchPos.x - oldX; dY = touchPos.y - oldY; if(touchPos.y > getHeight()/2){ dX = dX*-1; } if(touchPos.x < getWidth()/2){ dY = dY*-1; } _renderObj.mAngle += (dX+dY) * TOUCH_SCALE_FACTOR; requestRender(); Log.i("AngleCo-ord", _renderObj.mAngle +"hh"); } oldX = touchPos.x; oldY = touchPos.y; Log.i("OldCo-ord", oldX+" hh "+oldY); return true; } } Last but not the least. My vector2 class. public class Vector2 { public static float TO_RADIANS = (1 / 180.0f) * (float) Math.PI; public static float TO_DEGREES = (1 / (float) Math.PI) * 180; public float x, y; public Vector2() { } public Vector2(float x, float y) { this.x = x; this.y = y; } public Vector2(Vector2 other) { this.x = other.x; this.y = other.y; } public Vector2 cpy() { return new Vector2(x, y); } public Vector2 set(float x, float y) { this.x = x; this.y = y; return this; } public Vector2 set(Vector2 other) { this.x = other.x; this.y = other.y; return this; } public Vector2 add(float x, float y) { this.x += x; this.y += y; return this; } public Vector2 add(Vector2 other) { this.x += other.x; this.y += other.y; return this; } public Vector2 sub(float x, float y) { this.x -= x; this.y -= y; return this; } public Vector2 sub(Vector2 other) { this.x -= other.x; this.y -= other.y; return this; } public Vector2 mul(float scalar) { this.x *= scalar; this.y *= scalar; return this; } public float len() { return FloatMath.sqrt(x * x + y * y); } public Vector2 nor() { float len = len(); if (len != 0) { this.x /= len; this.y /= len; } return this; } public float angle() { float angle = (float) Math.atan2(y, x) * TO_DEGREES; if (angle < 0) angle += 360; return angle; } public Vector2 rotate(float angle) { float rad = angle * TO_RADIANS; float cos = FloatMath.cos(rad); float sin = FloatMath.sin(rad); float newX = this.x * cos - this.y * sin; float newY = this.x * sin + this.y * cos; this.x = newX; this.y = newY; return this; } public float dist(Vector2 other) { float distX = this.x - other.x; float distY = this.y - other.y; return FloatMath.sqrt(distX * distX + distY * distY); } public float dist(float x, float y) { float distX = this.x - x; float distY = this.y - y; return FloatMath.sqrt(distX * distX + distY * distY); } public float distSquared(Vector2 other) { float distX = this.x - other.x; float distY = this.y - other.y; return distX * distX + distY * distY; } public float distSquared(float x, float y) { float distX = this.x - x; float distY = this.y - y; return distX * distX + distY * distY; } } PS : i am able to handle the touch events. I can rotate the triangle with the touch of my finger. But i want that ONE VERTEX of the triangle should point at my finger position respective of the position of my finger.

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  • iPhone: image in table cell - wrong position & not scaled correctly in iPhone 3.0

    - by Karsten Silz
    Hi, I have a custom table cell in an iPhone 3.x app to show basketball player data, including a picture. Here's my code from the table controller: UIImageView *theImage = (UIImageView *) [cell viewWithTag:0]; theImage.image = [manager getSmallImageForPlayer: data.number]; theImage.frame = CGRectMake(14, 0, 30, 44); theImage.clipsToBounds = YES; theImage.contentMode = UIViewContentModeScaleAspectFit; theImage.autoresizingMask = UIViewAutoresizingFlexibleHeight && UIViewAutoresizingFlexibleWidth; theImage.autoresizesSubviews = YES; Here's what it looks like in the iPhone SDK 3.0 simulator: Here's what it looks like in the iPhone SDK 3.1.3 simulator: So I have two problems: In both versions, the image view starts at position (0,0) in the table cell, even though I set the frame to start at (14,0). In the 3.0 simulator (and 3.0 device), the image is not shrunk down correctly, even though I set the image view content mode to "UIViewContentModeScaleAspectFit". But the same code works fine in the 3.1.3 simulator / device. Who can help me with either of these two problems?

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  • Can any web-based email program let user paste an image (not link) as part of the email instead of a

    - by Jian Lin
    I think back in the old days, some email programs let users Paste an image right inside the email content. (maybe WinMail or Outlook?) So for example, we can write some text, embed an image, and then write some more text, and embed another image. The recipient will get the email content in the above text-image-text-image order (instead of having all images attached at the end of email) Can any web-based email program do that? Note that the image is not just a link, but a complete file. For example, Gmail lets us paste an image, but it is actually just a link to some web location. Can the actual file content be embedded instead?

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  • "Does not make sense to draw an image" - Warning after upgrade to MountainLion

    - by Tom
    After I upgraded my programming machine to MountainLion and XCode to the new version I get this warning printed into the console everytime I run my application: It does not make sense to draw an image when [NSGraphicsContext currentContext] is nil. This is a programming error. Break on void _NSWarnForDrawingImageWithNoCurrentContext() to debug. This will be logged only once. This may break in the future. I'm not using an Image anywhere in my Application and I searched the whole project for an image but couldn't find one. Does anybody know what could cause this? I'm using 2 nib files btw: One Popover and the Mainwindow. Neither of them contains an image. Edit: I found the line when this appears: [self.popover showRelativeToRect:[appDelegate.menulet frame] ofView:appDelegate.menulet preferredEdge:NSMinYEdge]; But none of those object is nil. Any suggestions? Edit 2: The Menulet is a NSView subclass btw. So I'm passing a view.

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  • Finalizing a Cursor that has not been deactivated or closed non-fatal error

    - by arnold
    Hello all, i'm getting a "Finalizing a Cursor that has not been deactivated or closed" error on this piece of code. The code is used to fill a listview. Since it's a non-fatal error , there is no crash and all seems to works fine..but i don't like the error. If i close the cursor at the end of this code..the listview stay's empty. if i close the cursor in onStop , i get the same error. How do i fix this?? private void updateList() { DBAdapter db = new DBAdapter(this); db.open(); //load all waiting alarm mCursor=db.getTitles("state<2"); setListAdapter(new MyCursorAdapter(this, mCursor)); registerForContextMenu(getListView()); db.close(); } error : E/Cursor ( 2318): Finalizing a Cursor that has not been deactivated or closed. database = /data/data/xxxxxxxxxxxxxxx.db, table = alerts, query = SELECT _id, alert_id, E/Cursor ( 2318): android.database.sqlite.DatabaseObjectNotClosedException: Application did not close the cursor or database object that was opened here E/Cursor ( 2318): at android.database.sqlite.SQLiteCursor.<init>(SQLiteCursor.java:210) E/Cursor ( 2318): at android.database.sqlite.SQLiteDirectCursorDriver.query(SQLiteDirectCursorDr­iver.java: 53) E/Cursor ( 2318): at android.database.sqlite.SQLiteDatabase.rawQueryWithFactory(SQLiteDatabase.j­ava: 1345) E/Cursor ( 2318): at android.database.sqlite.SQLiteDatabase.queryWithFactory(SQLiteDatabase.java­: 1229) .... ....

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  • How to change image and disable UIBarButtonItem

    - by Alex
    I have a NavigationBar app with two views: a parent and a sub view. In the sub view I'm adding a button to the right corner as follows: - (void)viewDidLoad { UIBarButtonItem *tempButton = [[UIBarButtonItem alloc] initWithImage:[UIImage imageNamed:@"lock-unlocked.png"] style:UIBarButtonItemStylePlain target:self action:@selector(lockScreen)]; self.navigationItem.rightBarButtonItem = tempButton; [tempButton release]; } When that button is clicked I want to change the image of this rightBarButtonItem and disable the leftBarButtonItem (which was added automatically by the controller). Basically have two states of a button, locked and unlocked. Question 1: The only way I can find how to change the image is to create a new UIButtonItem with a new image and replace rightBarButtonItem with that new one. But I'm wondering if there's a way to just change the image without creating a new UIBarButtonItem. Am I creating a memory leak if I keep creating new UIBarButtonItem? Question 2: How can I get a hold of self.navigationItem.leftBarButtonItem and disable/enable it? I don't create that one manually, it's created automatically for me by the controller. I don't see any method/property on UIBarButtonItem to enable/disable user interaction with it.

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  • C# winforms: A problem with sending an email cointaining the image background

    - by Tony
    Hi, I'm trying to figure out how to resolve the problem: I create the MailMessage object like that and send it: MailMessage mail = new MailMessage(); mail.From = new MailAddress("[email protected]"); mail.To.Add("[email protected]"); mail.Subject = "This is an email"; AlternateView plainView = AlternateView.CreateAlternateViewFromString("This is my plain text content, viewable by those clients that don't support html", null, MediaTypeNames.Text.Plain); (1) AlternateView htmlView = AlternateView.CreateAlternateViewFromString("Here is an embedded image.<img src=cid:companylogo>", null, "text/html"); LinkedResource logo = new LinkedResource("c:\\cop1.jpg"); logo.ContentId = "companylogo"; htmlView.LinkedResources.Add(logo); mail.AlternateViews.Add(plainView); mail.AlternateViews.Add(htmlView); Everything is OK, the mail has the image in the background. But the problem is, when I change in the paragraph (1) from (click) to (click) everything fails, the image is not recognized and is threated as a attachment ! I think that is caused by the first colon here background-image:cid:companylogo Is it possible to resolve that ?

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  • Add Image to Base64 Encoded ImageStream in Resources (resx)

    - by NickAldwin
    I'm working on an older project, updating it. Part of the program has a toolstrip with many buttons on it, each with an image. I found that the images are stored in a Base64 encoded imagestream in the resx for the form and accessed as such: System.ComponentModel.ComponentResourceManager resources = new System.ComponentModel.ComponentResourceManager(typeof(Form1)); ... this.imageList1 = new System.Windows.Forms.ImageList(this.components); ... this.toolStrip1.ImageList = this.imageList1; ... this.imageList1.ImageStream = ((System.Windows.Forms.ImageListStreamer)(resources.GetObject("imageList1.ImageStream"))); ... this.toolStripButton1.ImageIndex = 0; //There are 41 images, so this can be between 0 and 40 I need to add another button with a new image. How can I add an image to this stream? I cannot use the designer, as it crashes as soon as I load the form (I believe because it uses a custom component with unsafe code). I could always just add a new image resource separate from the stream, but that would make that one button different and thus it would create problems with consistency, causing upkeep problems later. So I'm wondering if there is any way for me to edit the imagestream. I can access the raw base64 string, but I have no idea where to go from here.

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  • ListField with image In Blackberry JDE

    - by Karthick
    I use the following code to retrieve image from the phone or SDCard and I use that image in to my ListField. It gives the output but it takes very Long time to produce the screen. How to solve this problem ?? Can any one help me?? Thanks in advance!!! String text = fileholder.getFileName(); try{ String path="file:///"+fileholder.getPath()+text; //path=”file:///SDCard/BlackBerry/pictures/image.bmp” InputStream inputStream = null; //Get File Connection FileConnection fileConnection = (FileConnection) Connector.open(path); inputStream = fileConnection.openInputStream(); ByteArrayOutputStream baos = new ByteArrayOutputStream(); int j = 0; while((j=inputStream.read()) != -1) { baos.write(j); } byte data[] = baos.toByteArray(); inputStream.close(); fileConnection.close(); //Encode and Resize image EncodedImage eImage = EncodedImage.createEncodedImage(data,0,data.length); int scaleFactorX = Fixed32.div(Fixed32.toFP(eImage.getWidth()), Fixed32.toFP(180)); int scaleFactorY = Fixed32.div(Fixed32.toFP(eImage.getHeight()), Fixed32.toFP(180)); eImage=eImage.scaleImage32(scaleFactorX, scaleFactorY); Bitmap bitmapImage = eImage.getBitmap(); graphics.drawBitmap(0, y+1, 40, 40,bitmapImage, 0, 0); graphics.drawText(text, 25, y,0,width); } catch(Exception e){}

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  • Debugging ADT Eclipse Plugin Install

    - by MPG
    I've installed the Android SDK and the ADT plugin, but Android doesn't show up in the WindowPreferences... dialog. I'm running Galileo. If I go to the Installation Details part of the About Eclipse dialog, it says that I have 0.9.6 of Android DDMS and Android Development Tools. I can run adb from the command line. I tried going around the uninstall/reinstall loop once. I'm on Windows Vista. I also have 2.7.7 of the Scala plugin installed, but I tried uninstalling that. Any ideas on what I should try next? Thanks.

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  • How do I convert a Linux disk image into a sparse file?

    - by endolith
    I have a bunch of disk images, made with ddrescue, on an EXT partition, and I want to reduce their size without losing data, while still being mountable. How can I fill the empty space in the image's filesystem with zeros, and then convert the file into a sparse file so this empty space is not actually stored on disk? For example: > du -s --si --apparent-size Jimage.image 120G Jimage.image > du -s --si Jimage.image 121G Jimage.image This actually only has 50G of real data on it, though, so the second measurement should be much smaller. This supposedly will fill empty space with zeros: cat /dev/zero > zero.file rm zero.file But if sparse files are handled transparently, it might actually create a sparse file without writing anything to the virtual disk, ironically preventing me from turning the virtual disk image into a sparse file itself. :) Does it? Note: For some reason, sudo dd if=/dev/zero of=./zero.file works when cat does not on a mounted disk image.

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  • OutOfMemory exception when loading an image in .Net

    - by Ben
    Hi, Im loading an image from a SQL CE db and then trying to load that into a PictureBox. I am saving the image like this: if (ofd.ShowDialog() == DialogResult.OK) { picArtwork.ImageLocation = ofd.FileName; using (System.IO.FileStream fs = new System.IO.FileStream(ofd.FileName, System.IO.FileMode.Open)) { byte[] imageAsBytes = new byte[fs.Length]; fs.Read(imageAsBytes, 0, imageAsBytes.Length); thisItem.Artwork = imageAsBytes; fs.Close(); } } and then saving to the Db using LINQ To SQL. I load the image back like so: using (FileStream fs = new FileStream(@"C:\Temp\img.jpg", FileMode.CreateNew ,FileAccess.Write )) { byte[] img = (byte[])encoding.GetBytes(ThisFilm.Artwork.ToString()); fs.Write(img, 0, img.Length); } but am getting an OutOfMemoryException. I have read that this is a slight red herring and that there is probably something wrong with the filetype, but i cant figure what. Any ideas? Thanks picArtwork.Image = System.Drawing.Bitmap.FromFile(@"C:\Temp\img.jpg");

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  • Canvas rotate from bottom center image angle?

    - by Tom
    How do you rotate an image with the canvas html5 element from the bottom center angle? See http://uptowar.com/test.php for my current code and image: <html> <head> <title>test</title> <script type="text/javascript"> function startup() { var canvas = document.getElementById('canvas'); var ctx = canvas.getContext('2d'); var img = new Image(); img.src = 'player.gif'; img.onload = function() { ctx.translate(185, 185); ctx.rotate(90 * Math.PI / 180); ctx.drawImage(img, 0, 0, 64, 120); } } </script> </head> <body onload='startup();'> <canvas id="canvas" style="position: absolute; left: 300px; top: 300px;" width="800" height="800"></canvas> </body> </html> Unfortunately this seems to rotate it from the top left angle of the image. Any idea? Edit: in the end the object (space ship) has to rotate like a clock pointer, as if it is turning right/left.

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  • Android Soft Keyboard Keys Layout

    - by Shubh
    Hi friend, I am trying to build an Android Soft keyboard application using avail code at http://developer.android.com/resources/samples/SoftKeyboard/index.html I want to rounded key like iPhone. please suggest me. Thanks in Advance.

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  • How to exclude R*.class files from a proguard build

    - by Jeremy Bell
    I am one step away from making the method described here: http://stackoverflow.com/questions/2761443/targeting-android-with-scala-2-8-trunk-builds work with a single project (vs one project for scala and one for android). I've come across a problem. Using this input file (arguments to) proguard: -injars bin;lib/scala-library.jar(!META-INF/MANIFEST.MF,!library.properties) -outjar lib/scandroid.jar -libraryjars lib/android.jar -dontwarn -dontoptimize -dontobfuscate -dontskipnonpubliclibraryclasses -dontskipnonpubliclibraryclassmembers -keepattributes Exceptions,InnerClasses,Signature,Deprecated, SourceFile,LineNumberTable,*Annotation*,EnclosingMethod -keep public class org.scala.jeb.** { public protected *; } -keep public class org.xml.sax.EntityResolver { public protected *; } Proguard successfully builds scandroid.jar, however it appears to have included the generated R classes that the android resource builder generates and compiles. In this case, they are located in bin/org/jeb/R*.class. This is not what I want. The android dalvik converter cannot build because it thinks there is a duplicate of the R class (it's in scandroid and also the R*.class files). How can I modify the above proguard arguments to exclude the R*.class files from the scandroid.jar so the dalvik converter is happy? Edit: I should note that I tried adding ;bin/org/jeb/R.class;etc... to the -libraryjars argument, and that only seemed to cause it to complain about duplicate classes, and in addition proguard decided to exclude my scala class files too.

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  • Why calling Process.killProcess(Process.myPid()) is a bad idea?

    - by Tal Kanel
    I've read some posts saying using this method is "not good", shouldn't been use, it's not the right way to "close" the application and it's not how android works... I understand and accept the fact that Android OS knows better then me when it's the right time to terminate the process, but I didn't heard yet a good explanation why it's wrong using the killProcess() method?. after all - it's part of the android API... what I do know is that calling this method while other threads doing in potential an important work (operations on files, writing to DB, HTTP requests, running services..) can be terminated in the middle, and it's clearly not good. also I know I can benefit from the fact that "re-open" the application will be faster, cause the system maybe still "holds" in memory state from last time been used, and killProcess() prevents that. beside this reason, in assumption I don't have such operations, and I don't care my application will load from scratch each run, there are other reasons why not using the killProcess() method? I know about finish() method to close an Activity, so don't write me about that please.. finish() is only for Activity. not to all application, and I think I know exactly why and when to use it... and another thing - I'm developing also games with the Unity3D framework, and exporting the project to android. when I decompiled the generated apk, I was very suprised to find out that the java source code created from unity - implementing Unity's - Application.quit() method, with Process.killProcess(Process.myPid()). Application.quit() is suppose to be the right way to close game according to Unity3d guides (is it really?? maybe I'm wrong, and missed something), so how it happens that the Unity's framework developers which doing a very good work as it seems implemented this in native android to killProcess()? anyway - I wish to have a "list of reasons" why not using the killProcess() method, so please write down your answer - if you have something interesting to say about that. TIA

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  • Unable to download .apk via webbrowser from drupal site

    - by ggrell
    I have a drupal-based website where people can log in and see private discussion forums. This is where I want to have my beta testers for my Android application download the beta .apk files. I tested this thoroughly on my Android 1.6 based myTouch 3G, and was able to log in, and download files attached to forum posts without problems. Now comes the interesting part: my testers on Droids and Nexus Ones (Android 2.0.1 and 2.1) were complaining that their downloads are failing. Since I don't have an 2.0 phone, I tried it out in a 2.0 emulator, and lo-and-behold, it didn't work. The download shows the indeterminate progress for a second or two, then shows "Download unsuccessful". Based on what I see in the logs, it is apparent that the server is returning a 404 for the download request from 2.0 browsers. I can download to my desktop and 1.6 phone no problem. The only reason I can think of that the server would return a 404 for a request is that for some reason the credentials or cookies aren't being passed by the download process. Logcat shows: http error 404 for download x Some background: I added the mime type to my .htaccess like this: AddType application/vnd.android.package-archive apk I checked the server logs and see the following for failed downloads: xx.xx.xx.224 - - [28/Jan/2010:20:39:00 -0500] "GET /system/files/grandmajong-beta090.apk HTTP/1.1" 404 - "http://trickybits.com/forums/beta-testing/grandma-jong/latest-version-090-b1" "Mozilla/5.0 (Linux; U; Android 1.6; en-us; sdk Build/Donut) AppleWebKit/528.5+ (KHTML, like Gecko) Version/3.1.2 Mobile Safari/525.20.1"

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  • How to get image's coordinate on JPanel

    - by Jessy
    This question is related to my previous question http://stackoverflow.com/questions/2376027/how-to-generate-cartesian-coordinate-x-y-from-gridbaglayout I have successfully get the coordinate of each pictures, however when I checked the coordinate through (System.out.println) and the placement of the images on the screen, it seems to be wrong. e.g. if on the screen it was obvious that the x point of the first picture is on cell 2 which is on coordinate of 20, but the program shows x=1. Here is part of the code: public Grid (){ setPreferredSize(new Dimension(600,600)); .... setLayout(new GridBagLayout()); GridBagConstraints gc = new GridBagConstraints(); gc.weightx = 1d; gc.weighty = 1d; gc.insets = new Insets(0, 0, 0, 0);//top, left, bottom, and right gc.fill = GridBagConstraints.BOTH; JLabel[][] label = new JLabel[ROWS][COLS]; Random rand = new Random(); // fill the panel with labels for (int i=0;i<IMAGES;i++){ ImageIcon icon = createImageIcon("myPics.jpg"); int r, c; do{ //pick random cell which is empty r = (int)Math.floor(Math.random() * ROWS); c = (int)Math.floor(Math.random() * COLS); } while (label[r][c]!=null); //randomly scale the images int x = rand.nextInt(50)+30; int y = rand.nextInt(50)+30; Image image = icon.getImage().getScaledInstance(x,y, Image.SCALE_SMOOTH); icon.setImage(image); JLabel lbl = new JLabel(icon); // Instantiate GUI components gc.gridx = r; gc.gridy = c; add(lbl, gc); //add(component, constraintObj); label[r][c] = lbl; } I checked the coordinate through this code: Component[] components = getComponents(); for (Component component : components) { System.out.println(component.getBounds()); }

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  • View problem - how to show integer from activity in XML?

    - by Oliver Goossens
    Hi there, I started two days ago with android, gone through the hello android stuff and also started to read the Hello Android book, which is great. PROBLEM: I use in my app - VERY EASY APP- the XML output. So basically the main activity just tells the android to show the XML layout of main. But what if I have in the activity - code defined integer variable and I want this integer variable also be shown on the display? How do I PUSH the integer variable to the XML??? From main XML reference to other strings in XML is easy - @string/app_name ... but how do I use the integer variable from the activity? Please help Thank you Oliver

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  • Asynchronous Image loading in certain custom UITableViewCells

    - by Dan
    So, I'm sure that this issue has been brought up before, but I haven't quite seen a solution for my specific problem. What I'm doing is loading a group of custom UITableViewCell's that are drawn using Loren Brichter's solution, each cell has some content, an icon (representing the user) that is asynchronously loaded into it, and a few other things. Eventually, I'm hoping to add support for images. Not every cell has an image, so in the creation of the cell, it determines if an image is required to be loaded and drawn into the cell. My problem is that I don't know how I can do that while keeping the image loaded asynchronously - with not every cell having the need to load an image (like needed with the icon) I'm not sure how to keep it in order when an cell is thrown off screen and re-rendered when the user scrolls over it. Each cell draws it content from an NSArray containing a custom object called FeedItem. All I'm really looking for is some sort of solution or idea to help me because right now I am at a loss. Thanks guys, I will appreciate the help.

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