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  • 2 dimensional arraylists in java

    - by Chris Maness
    So here's the deal I'm working on a project that requires me to have a 2 dimensional arraylist of 1 dimensional arrays. But every time I try to load in my data I get an error: Can't do this opperation because of bad input java.lang.IndexOutOfBoundsException: Index: 1, Size: 0 On some of the inputs. I've got no idea where I'm going wrong on this one. A little help please? Source Code: import java.io.BufferedInputStream; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.IOException; import java.util.ArrayList; import java.util.Scanner; import javax.swing.JOptionPane; import java.io.InputStream; public class Facebull { public static void main (String[] args) { if(args.length != 0){ load(args[0]); } else{ load("testFile"); } } public static void load(String fname) { int costOfMach = 0; ArrayList <Integer> finalMach = new ArrayList<Integer>(); ArrayList <ArrayList<int[]>>machines = new ArrayList<ArrayList<int[]>>(); Scanner inputFile = null; File f = new File(fname); if (f.exists ()) { try { inputFile = new Scanner (f); } catch (FileNotFoundException e) { JOptionPane.showMessageDialog(null,"Can't find the file\n" + e); } int i = 0; while (inputFile.hasNext ( )) { String str = inputFile.nextLine ( ); String [ ] fields = str.split ("[\t ]"); System.out.println(str); if (!(fields[0].isEmpty() || fields[0].equals (""))){ fields[0] = fields[0].substring(1); fields[1] = fields[1].substring(1); fields[2] = fields[2].substring(1); try { //data to be inputed is 0 and 3 location of data is 1 and 2 int[] item = new int[2]; item[1] = Integer.parseInt(fields[0]); item[0] = Integer.parseInt(fields[3]); if(machines.size() < Integer.parseInt(fields[1])){ ArrayList<int[]> column = new ArrayList<int[]>(); machines.add (Integer.parseInt(fields[1])-1, column); System.out.println("we're in the if"); } machines.get(Integer.parseInt(fields[1])-1).add(Integer.parseInt(fields[2])-1, item); } //catches any exception catch (Exception e) { System.out.println("Can't do this opperation because of bad input \n" + e); } } } inputFile.close ( ); } System.out.print(machines); }//end load }

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  • Yii file upload issue

    - by user1289853
    Couple of months ago,I developed a simple app using YII,one of the feature was to upload file. The feature was working well in my dev machine,couple of days ago client found the file upload feature is not working in his server since deployment. And after that I test my dev machine that was not working too. My controller looks: public function actionEntry() { if (!Yii::app()->user->isGuest) { $model = new TrackForm; if (isset($_POST['TrackForm'])) { $entry = new Track; try { $entry->product_image = $_POST['TrackForm']['product_image']; $entry->product_image = CUploadedFile::getInstance($model, 'product_image'); if ($entry->save()) { if ($entry->product_image) { $entry->product_image->saveAs($entry->product_image->name, '/trackshirt/uploads'); } } $this->render('success', array('model' => $model)); // redirect to success page } } catch (Exception $e) { echo 'Caught exception: ', $e->getMessage(), "\n"; } } else { $this->render('entry', array('model' => $model)); } } } Model is like below: <?php class Track extends CActiveRecord { public static function model($className=__CLASS__) { return parent::model($className); } public function tableName() { return 'product_details'; } } My view looks: <?php $form = $this->beginWidget('CActiveForm', array( 'id' => 'hide-form', 'enableClientValidation' => true, 'clientOptions' => array( 'validateOnSubmit' => true, ), 'htmlOptions' => array('enctype' => 'multipart/form-data'), )); ?> <p class="auto-style2"><strong>Administration - Add New Product</strong></p> <table align="center" style="width: 650px"><td class="auto-style3" style="width: 250px">Product Image</td> <td> <?php echo $form->activeFileField($model, 'product_image'); ?> </td> </tr> </table> <p class="auto-style1"> <div style="margin-leftL:-100px;"> <?php echo CHtml::submitButton('Submit New Product Form'); ?> </div> <?php $this->endWidget(); ?> Any idea where is the problem?I tried to debug it but every time it returns Null. Thanks.

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  • Large or small company?

    - by James
    Hi, I would like to hear some opinions regarding working in small companies versus large corporations. So far, my personal experience has been that esp. for junior programmers small companies have given a more solid background, as follow-up is with experienced workers. In larger corporations on the other hand, the experienced have already worked they way way out of reach. Is this a general feeling or just my bad experience?

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  • JSLint with Textmate

    - by mehdi
    I tried the instructions at this tutorial (http://www.phpied.com/jslint-on-mac-textmate/) to run jslint with textmate but getting stuck at step at the last step of "Step 1" Here is the error: Exception in thread "main" java.lang.NoClassDefFoundError: org/mozilla/javascript/tools/shell/Main Caused by: java.lang.ClassNotFoundException: org.mozilla.javascript.tools.shell.Main at java.net.URLClassLoader$1.run(URLClassLoader.java:202) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:190) at java.lang.ClassLoader.loadClass(ClassLoader.java:307) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301) at java.lang.ClassLoader.loadClass(ClassLoader.java:248) Thanks

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  • editing a string using BufferedReader in Java

    - by pbs
    Exception handling aside, I'm using the following to input a line of text in Java: BufferedReader strin = new BufferedReader(new InputStreamReader(System.in)); String txt = null; txt = strin.readLine(); However, I want to be able to edit an existing string, so that if txt were initialized to "hello" instead of null, then the readLine() would have the "hello" text in the buffer for me to edit. I can't see how to do this. Any help would be appreciated.

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  • How to insert a WebView into a cocoa app?

    - by spamoom
    I'm rather new with the whole OSX programming, I wanted to stick a WebView into an empty app. Apparently it isn't as simple as sticking a WebView on a window in interface builder and creating an outlet. IBOutlet WebView *webView; It gives me a expected specifier-qualifier-list before 'WebView' and when I don't use an outlet, it terminates due to uncaught exception. I'm not too sure what these error messages mean. Seems it isn't that simple!

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  • Usability of an endless/infinite scroll

    - by Anton Gogolev
    What are pros and cons of this technique (see Softfolio for an example). Two things I personally thought of are as follows: Impossible to tell someone where an item of interest is located (like, you probably won't say "324-th row, second column") Broken navigation when you return back to an infinitely scrolled page. What else can you think of? And what do you personally think of this approach in general. Would you use this in you projects?

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  • database transaction rollback processing in PHP

    - by user198729
    try { $con->beginTransaction(); $this->doSave($con); $con->commit(); } catch (Exception $e) { $con->rollBack(); throw $e; } The code above is quite standard an approach to deal with transactions, but my question is:what if $con->rollBack() also fails? It may cause db lock,right?If so,what's the perfect way to go?

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  • python print end=' '

    - by Hath
    i have this python script where i need to run 'gdal_retile.py' but i get this an exception on this line: if Verbose: print(Building internam Index for %d tile(s) ..." % len(inputTiles), end=' ') the end='' is invalid syntax just curious as to why.. and what the author probably meant to do. I'm new to python if you haven't already guessed.

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  • Why (and when to) use stored procedures?

    - by mr.b
    What would be appropriate scenario when stored procedures should be used? I stumbled upon implementation where almost whole data manipulation was handled by store procedures, even simplest form of INSERT/DELETE statements were wrapped and used via SP's. So, what's the rationale for using stored procedures in general? Sorry for such a beginners question..

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  • C# ApplicationContext usage

    - by rd42
    Apologies if my terminology is off, I'm new to C#. I'm trying to use an ApplicationContext file to store mysql conn values, like dbname, username, password. The class with mysql conn string is "using" the namespace for the ApplicationContext, but when I print out the connection string, the values are making it. A friend said, "I'm not initializing it" but couldn't stay to expand on what "it" was. and the "Console.WriteLine("1");" in ApplicationContext.cs never shows up. Do I need to create an ApplicationContext object and the call Initialize() on that object? Thanks for any help. ApplicationContext.cs: namespace NewApplication.Context { class ApplicationContext { public static string serverName; public static string username; public static string password; public static void Initialize() { //need to read through config here try { Console.WriteLine("1"); XmlDocument xDoc = new XmlDocument(); xDoc.Load(".\\Settings.xml"); XmlNodeList serverNodeList = xDoc.GetElementsByTagName("DatabaseServer"); XmlNodeList usernameNodeList = xDoc.GetElementsByTagName("UserName"); XmlNodeList passwordNodeList = xDoc.GetElementsByTagName("Password"); } catch (Exception ex) { // MessageBox.Show(ex.ToString()); //TODO: Future write to log file username = "user"; password = "password"; serverName = "localhost"; } } } } MySQLManager.cs: note: dbname is the same as the username as you'll see in the code, I copied this from a friend who does that. using System; using System.Collections.Generic; using System.Linq; using System.Text; using MySql.Data; using MySql.Data.MySqlClient; using NewApplication.Context; namespace NewApplication.DAO { class MySQLManager { private static MySqlConnection conn; public static MySqlConnection getConnection() { if (conn == null || conn.State == System.Data.ConnectionState.Closed) { string connStr = "server=" + ApplicationContext.serverName + ";user=" + ApplicationContext.username + ";database=" + ApplicationContext.username + ";port=3306;password=" + ApplicationContext.password + ";"; conn = new MySqlConnection(connStr); try { Console.WriteLine("Connecting to MySQL... "); Console.WriteLine("Connection string: " + connStr + "\n"); conn.Open(); // Perform databse operations // conn.Close(); } catch (Exception ex) { Console.WriteLine(ex.ToString()); } } return conn; } } } and, thanks for still reading, this is the code that uses the two previous files: class LogDAO { MySqlConnection conn; public LogDAO() { conn = MySQLManager.getConnection(); } Thank you, rd42

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  • Writing String into a File

    - by Halo
    I'm implementing a WebScript using Alfresco's JavaScript. l'm trying to insert string to a file, but I can't do it. When I write another file's content like: file.properties.content.write(content); It works, and the file's contents are copied into my file. But I can't insert string directly, like: file.properties.content.write("Stuff like that"); it gives an exception. How can I write string into this file?

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  • Actual use of finally block

    - by Jibu P C_Adoor
    I asked to my friend about this question, he said that it is used for destroying the object created during the exception handling. But in c# GC is there for destroying such kinds of unused objects, then what is the actual use of finally block. Tell me with a scenario related to that.

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  • Shared/Static Variable Should Be Nothing but Isn't - what gives?

    - by Denis
    I have the following code: Public Class TestClass Public Sub Test() If theGlobal IsNot Nothing Then Throw New Exception("What gives!") End Sub Private Shared theGlobal As Object = Nothing Private Shared ReadOnly Property Global Get If theGlobal Is Nothing Then theGlobal = New Object() End If Return theGlobal End Get End Property End Class Am stumped... Why is theGlobal object NOT Nothing?

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  • Large transactions causing "System.Data.SqlClient.SqlException: Timeout expired" error?

    - by Michael
    My application requires a user to log in and allows them to edit a list of things. However, it seems that if the same user always logs in and out and edits the list, this user will run into a "System.Data.SqlClient.SqlException: Timeout expired." error. I've read comments about increasing the timeout period but I've also read a comment about it possibly caused by uncommitted transactions. And I do have one going in the application. I'll provide the code I'm working with and there is an IF statement in there that I was a little iffy about but it seemed like a reasonable thing to do. I'll just go over what's going on here, there is a list of objects to update or add into the database. New objects created in the application are given an ID of 0 while existing objects have their own ID's generated from the DB. If the user chooses to delete some objects, their IDs are stored in a separate list of Integers. Once the user is ready to save their changes, the two lists are passed into this method. By use of the IF statement, objects with ID of 0 are added (using the Add stored procedure) and those objects with non-zero IDs are updated (using the Update stored procedure). After all this, a FOR loop goes through all the integers in the "removal" list and uses the Delete stored procedure to remove them. A transaction is used for all this. Public Shared Sub UpdateSomethings(ByVal SomethingList As List(Of Something), ByVal RemovalList As List(Of Integer)) Using DBConnection As New SqlConnection(conn) DBConnection.Open() Dim MyTransaction As SqlTransaction MyTransaction = DBConnection.BeginTransaction() Try For Each SomethingItem As Something In SomethingList Using MyCommand As New SqlCommand() MyCommand.Connection = DBConnection If SomethingItem.ID > 0 Then MyCommand.CommandText = "UpdateSomething" Else MyCommand.CommandText = "AddSomething" End If MyCommand.Transaction = MyTransaction MyCommand.CommandType = CommandType.StoredProcedure With MyCommand.Parameters If MyCommand.CommandText = "UpdateSomething" Then .Add("@id", SqlDbType.Int).Value = SomethingItem.ID End If .Add("@stuff", SqlDbType.Varchar).Value = SomethingItem.Stuff End With MyCommand.ExecuteNonQuery() End Using Next For Each ID As Integer In RemovalList Using MyCommand As New SqlCommand("DeleteSomething", DBConnection) MyCommand.Transaction = MyTransaction MyCommand.CommandType = CommandType.StoredProcedure With MyCommand.Parameters .Add("@id", SqlDbType.Int).Value = ID End With MyCommand.ExecuteNonQuery() End Using Next MyTransaction.Commit() Catch ex As Exception MyTransaction.Rollback() 'Exception handling goes here End Try End Using End Sub There are three stored procedures used here as well as some looping so I can see how something can be holding everything up if the list is large enough. Other users can log in to the system at the same time just fine though. I'm using Visual Studio 2008 to debug and am using SQL Server 2000 for the DB.

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  • Connection reset SQLException with jetty

    - by robinmag
    Hi, I've switched my webserver from tomcat to jetty and encounter a "java.sql.SQLException: Io exception: Connection reset" when back from idle time (eg. i go out for a while) :( This issue doesn't appear when i use tomcat. Does it come from jetty or i've done something wrong ? Thank you!

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  • In MVC framworks (such as Ruby on Rails), do usually Model spell as singular and controller and view

    - by Jian Lin
    I usually see Ruby on Rails books using script/generate model Story name:string link:string which is a singular Story, while when it is controller script/generate controller Stories index then the Story now is Stories, which is plural. Is this a standard on Ruby on Rails? Is it true in other MVC frameworks too, like CakePHP, Symfony, Django, or TurboGears? I see that in the book Rails Space, the controller is also called User, which is the same as the model name, and it is the only exception I see.

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  • How to pass non-fatal warnings from a library

    - by wRAR
    A library function parses a file and returns an object. If a parser encounters unknown data, missing values etc., it shouldn't throw an exception and stop parsing (because this is not fatal), but there should be a way to pass information about these things to a caller (so that warnings can be displayed in the UI, for example). How can these warning be returned? I'm thinking of passing a callback function/object into the library, are there any other possible solutions?

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  • Xcode App Crash-When connecting to the ODATA services [on hold]

    - by user3685677
    Can someone help me resolving the following issue: When trying to connect from iPad app to SAP ECC system through ODATA channel services via SUP, it is allowing me to login for the first time and could retrieve the data successfully from SAP system. But when I logout and try logging in again with the same session, application gets crashed. Below is the crash report for your reference. I am using SDM Parser to connect the SAP system. SDMODataServiceDocumentParser *sdmDocParser = [[SDMODataServiceDocumentParser alloc] init]; [sdmDocParser parse:aServiceDocument]; m_serviceDocument = sdmDocParser.serviceDocument; //Load the object with metadata xml: SDMODataMetaDocumentParser *sdmMetadataParser = [[SDMODataMetaDocumentParser alloc] initWithServiceDocument:m_serviceDocument]; [sdmMetadataParser parse:aMetadata]; After initiated the service, setting the URL. [service setServiceDocumentUrl:m_serviceDocumentURL]; Using SDMconnectivityhelper to connect the URL id<SDMRequesting> serviceDocumentRequest2 = [connectivityHelper executeBasicSyncRequestWithQuery3:[[ODataQuery alloc]initWithURL:[NSURL URLWithString:encodedStrUrl]]] ; - (id <SDMRequesting>)executeBasicSyncRequestWithQuery3:(ODataQuery *)aQuery { id<SDMRequesting> request = [self createRequestWithQuery:aQuery]; [request setTimeOutSeconds:TIMEOUT_SEC]; [request setRequestMethod:@"GET"]; [request addRequestHeader:@"Content-Type" value:@"application/xml"]; [request startSynchronous];**[App getting CRASH in this line]** return request; } - (id <SDMRequesting>)createRequestWithQuery:(ODataQuery *)aQuery { if (isSUPMode) { [SDMRequestBuilder setRequestType:SUPRequestType]; } else { [SDMRequestBuilder setRequestType:HTTPRequestType]; } id <SDMRequesting> request = [SDMRequestBuilder requestWithURL:aQuery.URL]; request.username = self.username; request.password = self.password; return request; } Crash Report:- Incident Identifier: 347511BA-5F7F-45D4-8662-D5DCD2F88EA7 CrashReporter Key: 9a4d38cf19b1a94476eb6b2170d4f56678d6ca60 Hardware Model: iPad3,4 Path: /var/mobile/Applications/F38AD64F-03F8-4A21- Exception Type: EXC_BAD_ACCESS (SIGSEGV) Exception Subtype: KERN_INVALID_ADDRESS at 0x00000000 Triggered by Thread: 0 Thread 0 Crashed: 0 libsystem_platform.dylib 0x393a94c0 _platform_memmove$VARIANT $Swift + 160 1 Eby Sales Order 0x0015a2c8 0xb7000 + 668360 2 Eby Sales Order 0x0015a8b8 0xb7000 + 669880 3 Eby Sales Order 0x003331ee 0xb7000 + 2605550 4 Eby Sales Order 0x0031856e 0xb7000 + 2495854 5 Eby Sales Order 0x00338454 0xb7000 + 2626644 6 Eby Sales Order 0x000e6ad8 0xb7000 + 195288 7 Eby Sales Order 0x000e99a0 0xb7000 + 207264 8 Eby Sales Order 0x000ea442 0xb7000 + 209986 9 Eby Sales Order 0x000eb0d6 0xb7000 + 213206 10 Eby Sales Order 0x000c13d0 0xb7000 + 41936 11 Foundation 0x2ec93112 __NSFireDelayedPerform + 410 12 CoreFoundation 0x2e27ef4c __CFRUNLOOP_IS_CALLING_OUT_TO_A_TIMER_CALLBACK_FUNCTION__ + 12 13 CoreFoundation 0x2e27eb66 __CFRunLoopDoTimer + 790 14 CoreFoundation 0x2e27ceee __CFRunLoopRun + 1214 15 CoreFoundation 0x2e1e7764 CFRunLoopRunSpecific + 520 16 CoreFoundation 0x2e1e7546 CFRunLoopRunInMode + 102 17 GraphicsServices 0x331216ce GSEventRunModal + 134 18 UIKit 0x30b4688c UIApplicationMain + 1132 19 Eby Sales Order 0x000bd8da 0xb7000 + 26842 20 Eby Sales Order 0x000bd89c 0xb7000 + 26780

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  • Replace a control on the screen

    - by Rob Bonner
    Hello all, I have an instance of a FlowCoverView (a great library that emulates cover flow on the iPhone). And it works great, with the exception of an update. When I update my table behind the scenes, I have no way of telling this control (that is defined in IB) that it has been updated, and to reload. (much like you can with a table using reloadData) To the question, is there a way to replace a control that is on the screen with another control to force the reload?

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