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  • How to make a request from an android app that can enter a Spring Security secured webservice method

    - by johnrock
    I have a Spring Security (form based authentication) web app running CXF JAX-RS webservices and I am trying to connect to this webservice from an Android app that can be authenticated on a per user basis. Currently, when I add an @Secured annotation to my webservice method all requests to this method are denied. I have tried to pass in credentials of a valid user/password (that currently exists in the Spring Security based web app and can log in to the web app successfully) from the android call but the request still fails to enter this method when the @Secured annotation is present. The SecurityContext parameter returns null when calling getUserPrincipal(). How can I make a request from an android app that can enter a Spring Security secured webservice method? Here is the code I am working with at the moment: Android call: httpclient.getCredentialsProvider().setCredentials( //new AuthScope("192.168.1.101", 80), new AuthScope(null, -1), new UsernamePasswordCredentials("joeuser", "mypassword")); String userAgent = "Android/" + getVersion(); HttpGet httpget = new HttpGet(MY_URI); httpget.setHeader("User-Agent", userAgent); httpget.setHeader("Content-Type", "application/xml"); HttpResponse response; try { response = httpclient.execute(httpget); HttpEntity entity = response.getEntity(); ... parse xml Webservice Method: @GET @Path("/payload") @Produces("application/XML") @Secured({"ROLE_USER","ROLE_ADMIN","ROLE_GUEST"}) public Response makePayload(@Context Request request, @Context SecurityContext securityContext){ Payload payload = new Payload(); payload.setUsersOnline(new Long(200)); if (payload == null) { return Response.noContent().build(); } else{ return Response.ok().entity(payload).build(); } }

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  • Powershell 2.0 Hang When Run From MsDeploy pre- post- ops using c/

    - by SonOfNun
    I am trying to invoke powershell during the preSync call in a MSDeploy command, but powershell does not exit the process after it has been called. The command (from command line): "tools/MSDeploy/msdeploy.exe" -verb:sync -preSync:runCommand="powershell.exe -NoLogo -NoProfile -NonInteractive -ExecutionPolicy Unrestricted -Command C:/MyInstallPath/deploy.ps1 Set-WebAppOffline Uninstall-Service ",waitInterval=60000 -usechecksum -source:dirPath="build/for-deployment" -dest:wmsvc=BLUEPRINT-X86,username=deployer,password=deployer,dirPath=C:/MyInstallPath I used a hack here (http://therightstuff.de/2010/02/06/How-We-Practice-Continuous-Integration-And-Deployment-With-MSDeploy.aspx) that gets the powershell process and kills it but that didn't work. I also tried taskkill and the sysinternals equivalent, but nothing will kill the process so that MSDeploy errors out. The command is executed, but then just sits there. Any ideas what might be causing powershell to hang like this? I have found a few other similar issues around the web but no answers. Environment is Win 2K3, using Powershell 2.0. UPDATE: Here is a .vbs script I use to invoke my powershell command now. Invoke using 'cscript.exe path/to/script.vbs': Option Explicit Dim oShell, appCmd,oShellExec Set oShell = CreateObject("WScript.Shell") appCmd = "powershell.exe -NoLogo -NoProfile -NonInteractive -ExecutionPolicy Unrestricted -Command ""&{ . c:/development/materialstesting/deploy/web/deploy.ps1; Set-WebAppOffline }"" " Set oShellExec = oShell.Exec(appCmd) oShellExec.StdIn.Close()

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  • "NT AUTHORITY\ANONYMOUS LOGON" error in Windows 7 (ASP.NET & Web Service)

    - by Tony_Henrich
    I have an asp.net web app which works fine in Windows XP machine in a domain. I am porting it to a Windows 7 stand alone machine. The app uses a web service which makes a call to sql server. The web server (IIS 7.5) and SQL Server are on the same stand alone machine. I enabled Windows authentication for the website and web service. The web service uses a trusted connection connection string. The web service credentials uses System.Net.CredentialCache.DefaultCredentials. I noticed username, password and domainname are blank after the call! The webservice and web site use an application pool with identity "Network Service". I am getting an exception "NT AUTHORITY\ANONYMOUS LOGON" in the database call in the web service. I am assuming it's related to the blank credentials. I am expecting ASPNET user to be the security token to the database. Why is this not happening? (Usually this happens when sql server and web server are on two different machines in a domain, delegation & double hopping, but in my case everything is on a dev box)

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  • How to connect to Oracle using JRuby & JDBC

    - by Rob
    First approach: bare metal require 'java' require 'rubygems' require "c:/ruby/jruby-1.2.0/lib/ojdbc14.jar" # should be redundant, but tried it anyway odriver = Java::JavaClass.for_name("oracle.jdbc.driver.OracleDriver") puts odriver.java_class url = "jdbc:oracle:thin:@myhost:1521:mydb" puts "About to connect..." con = java.sql.DriverManager.getConnection(url, "myuser", "mypassword"); if con puts " connection good" else puts " connection failed" end The result of the above is: sqltest.rb:4: cannot load Java class oracle.jdbc.driver.OracleDriver (NameError) Second approach: Active Record require 'rubygems' gem 'ActiveRecord-JDBC' require 'jdbc_adapter' require 'active_record' require 'active_record/version' require "c:/ruby/jruby-1.2.0/lib/ojdbc14.jar" # should be redundant... ActiveRecord::Base.establish_connection( :adapter => 'jdbc', :driver => 'oracle.jdbc.driver.OracleDriver', :url => 'jdbc:oracle:thin:@myhost:1521:mydb', :username=>'myuser', :password=>'mypassword' ) ActiveRecord::Base.connection.execute("SELECT * FROM mytable") The result of this is: C:/ruby/jruby-1.2.0/lib/ruby/gems/1.8/gems/activerecord-jdbc-adapter-0.9.1/lib/active_recordconnection_adapters/jdbc_adapter.rb:330:in `initialize': The driver encountered an error: cannot load Java class oracle.jdbc.driver.OracleDriver (RuntimeError) Essentially the same error no matter how I go about it. I'm using JRuby 1.2.0 and I have ojdbc14.jar in my JRuby lib directory Gems: ActiveRecord-JDBC (0.5) activerecord-jdbc-adapter (0.9.1) activerecord (2.2.2) What am I missing? Thanks,

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  • SOAP Messages on iPhone

    - by CocoaNewBee
    Hello everyone !! I have to use several SOAP messages to get data from a web service. I got some examples how to do that but they all have the XML (http://icodeblog.com/2008/11/03/iphone-programming-tutorial-intro-to-soap-web-services/) // ---- LOGIN ----- NSString *soapMessage = [NSString stringWithFormat: @"<?xml version=\"1.0\" encoding=\"utf-8\"?>\n" "<soap12:Envelope xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:soap12=\"http://www.w3.org/2003/05/soap-envelope\">\n" "<soap12:Body>\n" "<Login xmlns=\"http://tempuri.org/\">\n" "<sUserID>USER</sUserID>\n" "<sUserPw>PASSWORD</sUserPw>\n" "<sDomain>SERVER</sDomain>\n" "</Login>\n" "</soap12:Body>\n" "</soap12:Envelope>\n" ]; NSString *urlToSend = [[NSString alloc] initWithString:@"http://SERVER/DIRECTORY/WSDL_FILE.ASMX"]; NSString *callTOMake = [[NSString alloc] initWithString:@"http://WEBSERVER/Login"]; TWO questions: 1) Does it make sense to read the SOAP Message from a class or a file into xcode?? or sould I just define them thru the code ?? 2) I used SOAPUI & .NET to query the service. It works fine... but when I do it from the iphone simulator it returns the following: 2010-03-10 15:13:54.773 Hello_SOAP[91204:207] soap:ClientServer did not recognize the value of HTTP Header SOAPAction: http://WEBSERVER/DIRECTORY/Login How can I figure out what the issue is that's causing the said error on the simulator??

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  • need to add secure ftp file upload area to a client's website

    - by user346602
    This is a variation on a previous question as I am having tons of trouble finding answers in all my relentless online searches. Am designing a website for an architecture firm. They want their clients to be able to upload files to them, through a link on their site, via ftp. They also want to have a sign in for their clients, and ensure the uploads are secure. I can figure out how to make a form that has a file upload area - but just don't understand the ftp and the secure part... I understand html, css and a bit of JQuery; the rest is still very challenging to me. Have found something called net2ftp that claims to do what I'm looking for - but the even the installation instructions (for administrators, here: http://www.net2ftp.com/help.html) confuse me. Do I need a MySQL database? Where do I put in Admin password they refer to? It goes on... Is there anything "easier" out there that anyone knows of? I have read that I should be Googling "file managers" - but don't know if these can be embedded in a client's website. I even need to understand of what happens to said file, and where it ends up, when client clicks the upload link. Oh - I am so in over head on this one.

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  • SQL to CodeIgniter Array Missing Data Issue

    - by SamD
    $query = $this->db->query("SELECT t1.numberofbets, t1.profit, t2.seven_profit, t3.28profit, user.user_id, username, password, email, balance, user.date_added, activation_code, activated FROM user LEFT JOIN (SELECT user_id, SUM(amount_won) AS profit, count(tip_id) AS numberofbets FROM tip GROUP BY user_id) as t1 ON user.user_id = t1.user_id LEFT JOIN (SELECT user_id, SUM(amount_won) AS seven_profit FROM tip WHERE date_settled > '$seven_daystime' GROUP BY user_id) as t2 ON user.user_id = t2.user_id LEFT JOIN (SELECT user_id, SUM(amount_won) AS 28profit FROM tip WHERE date_settled > '$twoeight_daystime' GROUP BY user_id) as t3 ON user.user_id = t3.user_id where activated = 1 GROUP BY user.user_id ORDER BY user.date_added DESC"); return $query->result_array(); The query works fine running it in phpMyAdmin and returns complete results (in image attached). However, printing the array in CodeIgniter, it has no value for one field ,seven_profit, where it is there in the SQL query ran in phpMyAdmin, just the discrepancy in this one field, from sql to php array... I just can’t see why, when printing the array, that one field, which should have value of 26, contains nothing? Any ideas? I changed the field name from starting with a number in attempt to fix it, but no difference. I know this is complex and looks horrible, any help or just people coming across something similar would be great to know about, thanks. Sam

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  • Using a string inside the DocumentBuilder parse method (need it for parsing XML using XPath)

    - by dierre
    Hi guys! I'm trying to create a RESTful webservice using a Java Servlet. The problem is I have to pass via POST method to a webserver a request. The content of this request is not a parameter but the body itself. So I basically send from ruby something like this: url = URI.parse(@host) req = Net::HTTP::Post.new('/WebService/WebServiceServlet') req['Content-Type'] = "text/xml" # req.basic_auth 'account', 'password' req.body = data response = Net::HTTP.start(url.host, url.port){ |http| puts http.request(req).body } Then I have to retrieve the body of this request in my servlet. I use the classic readline, so I have a string. The problem is when I have to parse it as XML: private void useXML( final String soft, final PrintWriter out) throws ParserConfigurationException, SAXException, IOException, XPathExpressionException, FileNotFoundException { DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance(); domFactory.setNamespaceAware(true); // never forget this! DocumentBuilder builder = domFactory.newDocumentBuilder(); Document doc = builder.parse(soft); XPathFactory factory = XPathFactory.newInstance(); XPath xpath = factory.newXPath(); XPathExpression expr = xpath.compile("//software/text()"); Object result = expr.evaluate(doc, XPathConstants.NODESET); NodeList nodes = (NodeList) result; for (int i = 0; i < nodes.getLength(); i++) { out.println(nodes.item(i).getNodeValue()); } } The problem is that builder.parse() accepts: parse(File f), parse(InputSource is), parse(InputStream is). Is there any way I can transform my xml string in an InputSource or something like that? I know it could be a dummy question but Java is not my thing, I'm forced to use it and I'm not very skilled.

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  • Are these settings correct for sending mail through Rails/Gmail?

    - by aressidi
    Hi there, I spend a good deal of time building an email system for my Rails app that uses Gmail to send bulk mail to a list of opt-in users. I realize a shortcomming of using Google Apps for my mail, namely a rate limit on the number of emails it will send out (i believe 500). Anyway, I have reached out to my users to see how many have received the email, and a lot of them have not, though some have. The list I tried sending to was about 540 users, so I would have expected more "yes, got it," then "nope, still waiting" responses. I have two questions: Do these settings look correct for outgoing bulk mailing through Gmail? Again, using google apps to manage my domain and i know some people (including myself) have received the mailer. This is in a mail.rb initializer in my app. ActionMailer::Base.delivery_method = :sendmail ActionMailer::Base.smtp_settings = { :address => "smtp.gmail.com", :port => 25, :domain => "mydomain.com", :authentication => :login, :user_name => "[email protected]", :password => "mypass" } Is there any way I can test if the mail was delivered, or at least attempted to be delivered? I can't tell where in the list the mailer stops mailing! The way I generate the list is through a query which then passes the user info to a mailer worker which sends the emails out via Starling/Workling. Any advice here would be useful. Happy to post code, but want to make sure the method I'm using is sound. Thanks for the help!

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  • cakephp read and display from more than one related table

    - by z22
    I have 2 tables Users and Artists. User: id name password city_id state_id country_id Artist: id user_id description I wish to create add and edit form(single form acts as add and edit). But on click of edit link, I wish to fill in the form fields from user as well as artist table. How do i do that? Below is my controller code: public function artist_register() { $this->country_list(); if ($this->request->is('post')) { $this->request->data['User']['group_id'] = 2; if ($this->{$this->modelClass}->saveAll($this->request->data)) { $this->redirect(array('controller' => 'Users', 'action' => 'login')); } } $this->render('artist_update'); } public function artist_update($id) { $artist = $this->{$this->modelClass}->findByuser_id($id); $artist_id = $artist[$this->modelClass]['id']; if($this->request->is('get')) { $this->request->data = $this->{$this->modelClass}->read(null, $artist_id); $this->request->data = $this->{$this->modelClass}->User->read(null, $id); } else { if($this->{$this->modelClass}->save($this->request->data)) { $this->Session->setFlash('Your Profile has been updated'); $this->redirect(array('action' => 'index')); } } } The code doesnt work. how do i solve it?

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  • Java MySQL Query Problem MySQLSyntaxErrorException When Creating a Table

    - by Aqib Mushtaq
    I fairly new to MySQL with Java, but I have executed a few successful INSERT queries however cannot seem to get the CREATE TABLE query to execute without getting the 'MySQLSyntaxErrorException' exception. My code is as follows: import java.sql.*; Statement stmt; Class.forName("com.mysql.jdbc.Driver"); String url = "jdbc:mysql://localhost:3306/mysql"; Connection con = DriverManager.getConnection(url, "root", "password"); stmt = con.createStatement(); String tblSQL = "CREATE TABLE IF NOT EXISTS \'dev\'.\'testTable\' (\n" + " \'id\' int(11) NOT NULL AUTO_INCREMENT,\n" + " \'date\' smallint(6) NOT NULL\n" + ") ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;"; stmt.executeUpdate(tblSQL); stmt.close(); con.close(); And the error is as follows: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''dev'.'testTable' ( 'id' int(11) NOT NULL AUTO_INCREMENT, 'date' smallint(6) N' at line 1 I would appreciate it if anyone could spot the mistake in this query, as I've tried executing this within phpMyAdmin and it works as it should. Thanks in advance.

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  • import the data in xls file and open them without Microsoft Excel

    - by user3669577
    I need to perform an application that cath values from SQL database after the esecution of a query. I must import the data in xls file and open them without Microsoft Excel. I'm a beginner and have too many problem. Can anyone help me. This is my code, at the moment: Option Infer On Imports System.Linq Imports System.Data.SqlClient Imports System Imports System.IO Imports System.Drawing Imports System.Drawing.Printing Imports System.Windows.Forms Imports ExcelLibrary.SpreadSheet Public Class frmLottiCaricati Dim CnSql As SqlConnection Private Sub frmLottiCaricati_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load Me.MdiParent = Inizio 'TB_MinusValenza.Text = VariazionePrezzi.MinusValenza 'TB_Periodo.Text = VariazionePrezzi.Periodo 'DG_Prodotti.AutoGenerateColumns = False Try Dim StringaSql = "Integrated Security=SSPI;Persist Security Info=False;Initial Catalog=" + Inizio.DatabaseSql + ";Data Source=" + Inizio.ServerSql + ";User ID=" + Inizio.UtenteSql + ";Password=" + Inizio.PwdSql CnSql = New SqlConnection(StringaSql) CnSql.Open() Dim command As SqlCommand Dim dadapter As New SqlDataAdapter Dim DS_Prodotti As New Data.DataSet Dim qry_Prodotti = "SELECT sistemaf.prodscadenze.Ministeriale, sistemaf.prodscadenze.Lotto, sistemaf.prodscadenze.Scadenza " & _ "FROM sistemaf.Prodscadenze " 'INNER JOIN sistemaf.Prodscadenze ON sistemaf.prodbase.Cod39 = sistemaf.prodscadenze.Ministeriale ;" command = New SqlCommand(qry_Prodotti, CnSql) dadapter.SelectCommand = command dadapter.Fill(DS_Prodotti) DG_Prodotti.DataSource = DS_Prodotti.Tables(0) 'DG_Prodotti.Columns("Descrizione").Width = 220 'DG_Prodotti.Columns("Ministeriale").Width = 60 DG_Prodotti.Columns("Lotto").Width = 60 'DG_Prodotti.Columns("Descrizione").AutoSizeMode = DataGridViewAutoSizeColumnMode.AllCells 'DG_Prodotti.Columns("Totale").DefaultCellStyle.Alignment = DataGridViewContentAlignment.MiddleRight Catch ex As Exception MessageBox.Show(ex.Message) End Try End Sub End Class I can open the data only with Microsoft Excel now. Have any suggestions?

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  • Simple continuously running XMPP client in python

    - by tom
    I'm using python-xmpp to send jabber messages. Everything works fine except that every time I want to send messages (every 15 minutes) I need to reconnect to the jabber server, and in the meantime the sending client is offline and cannot receive messages. So I want to write a really simple, indefinitely running xmpp client, that is online the whole time and can send (and receive) messages when required. My trivial (non-working) approach: import time import xmpp class Jabber(object): def __init__(self): server = 'example.com' username = 'bot' passwd = 'password' self.client = xmpp.Client(server) self.client.connect(server=(server, 5222)) self.client.auth(username, passwd, 'bot') self.client.sendInitPresence() self.sleep() def sleep(self): self.awake = False delay = 1 while not self.awake: time.sleep(delay) def wake(self): self.awake = True def auth(self, jid): self.client.getRoster().Authorize(jid) self.sleep() def send(self, jid, msg): message = xmpp.Message(jid, msg) message.setAttr('type', 'chat') self.client.send(message) self.sleep() if __name__ == '__main__': j = Jabber() time.sleep(3) j.wake() j.send('[email protected]', 'hello world') time.sleep(30) The problem here seems to be that I cannot wake it up. My best guess is that I need some kind of concurrency. Is that true, and if so how would I best go about that? EDIT: After looking into all the options concerning concurrency, I decided to go with twisted and wokkel. If I could, I would delete this post.

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  • How can I change the back button function in navigation toolbar?

    - by jackrobert
    I have developed a simple web application using JSP. It has a login page which contains username, password fields and sumbit button. It has a logout page which contains a link to the login page. And there are some pages like page1, page2, page3, page4, etc. Normal workflow is the following: After login comes page1. Then click some action and it will go to page2. Then click some action and it will go to page3. Then click some action and it will go to page4. So now I am in page4. Now click back button in navigation toolbar in browser, generally go to previous page (page3). But my requirement is, if you click back button in navigation toolbar from any page in the application, then you should go to logout page. For example: if you are in page4 and press the back button, then you should go to logout page and not to page3. How to achieve this? Is it anyway possible? Maybe with Javascript?

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  • svnsync looses revision properties although hook installed

    - by roesslerj
    Hello all! I have a pretty weird problem. We have setup an SVN-Mirror via cronjob (because it needs to go from inside to outside of a firewall, so no post-commit-hook possible) and svnsync. We installed a pre-revprop-hook just as told. Everything seems to work fine, except that it doesn't. E.g. when manually executing the script. # svnsync --non-interactive sync file://<path-to-mirror> --source-username <usr> --source-password <pwd> Committed revision 19817. Copied properties for revision 19817. No error, no complaints. But if checking for the revision properties it says: # svnlook info <path-to-mirror> 0 # svn info -r HEAD file://<path-to-mirror> 2>&1 Path: <root-of-mirror> URL: file://<path-to-mirror> Repository Root: file://<path-to-mirror> Repository UUID: <uid> Revision: 19817 Node Kind: directory Last Changed Rev: 19817 So somehow the author and timestamp information gets lost. But we need that information for our internal processes. Since no error or warning is produced I have absolutely no idea even where to start to look. Everything is local (except for the remote master), so there are no server-logs to look at. Any ideas how I could approach that problem, or even better -- how to solve it? Any ideas appreciated.

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  • Yii user rights extension

    - by jailed abroad
    i have installed the yii rights extension and here is my code after installation, database tables are created after installation. 'modules'=>array( // uncomment the following to enable the Gii tool 'rights'=>array( 'superuserName'=>'Admin', // Name of the role with super user privileges. 'authenticatedName'=>'Authenticated', //// Name of the authenticated user role. 'userIdColumn'=>'id',// Name of the user id column in the database. 'userNameColumn'=>'username', // Name of the user name column in the database. 'enableBizRule'=>true, // Whether to enable authorization item business rules. 'enableBizRuleData'=>false, //Whether to enable data for business rules. 'displayDescription'=>true, // Whether to use item description instead of name. ' // Key to use for setting success flash messages. 'flashErrorKey'=>'RightsError', / Key to use for setting error flash messages. // 'install'=>true, // Whether to install rights. 'baseUrl'=>'/rights', // Base URL for Rights. Change if module is nested. 'layout'=>'rights.views.layouts.main', // Layout to use for displaying Rights. 'appLayout'=>'application.views.layouts.main', //Application layout. 'cssFile'=>'rights.css', // Style sheet file to use for Rights. ' 'install'=>false, // Whether to enable installer. 'debug'=>false, ), 'gii'=>array( 'class'=>'system.gii.GiiModule', 'password'=>'1234', // If removed, Gii defaults to localhost only. Edit carefully to taste. 'ipFilters'=>array('127.0.0.1','::1'), ), ), But when i type url http://localhost/rightsTest/index.php/rights then it says There must be at least one superuser! I have tried many things but unable to find answer. Thanks for your help.

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  • XML-RPC over SSL with Ruby: end of file reached (EOFError)

    - by Michael Conigliaro
    Hello, I have some very simple Ruby code that is attempting to do XML-RPC over SSL: require 'xmlrpc/client' require 'pp' server = XMLRPC::Client.new2("https://%s:%d/" % [ 'api.ultradns.net', 8755 ]) pp server.call2('UDNS_OpenConnection', 'sponsor', 'username', 'password') The problem is that it always results in the following EOFError exception: /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/net/protocol.rb:135:in `sysread': end of file reached (EOFError) So it appears that after doing the POST, I don't get anything back. Interestingly, this is the behavior I would expect if I tried to make an HTTP connection on the HTTPS port (or visa versa), and I actually do get the same exact exception if I change the protocol. Everything I've looked at indicates that using "https://" in the URL is enough to enable SSL, but I'm starting wonder if I've missed something. Note that Even though the credentials I'm using in the RPC are made up, I'm expecting to at least get back an XML error page (similar to if you access https://api.ultradns.net:8755/ with a web browser). I've tried running this code on OSX and Linux with the exact same result, so I have to conclude that I'm just doing something wrong here. Does anyone have any examples of doing XML-RPC over SSL with Ruby?

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  • Doctrine/symfony: getSqlQuery() output in phpMyAdmin/SQL tab

    - by user248959
    Hi, i have created this query that works OK: $q1 = Doctrine_Query::create() ->from('Usuario u') ->leftJoin('u.AmigoUsuario a ON u.id = a.user2_id OR u.id = a.user1_id') ->where("a.user2_id = ? OR a.user1_id = ?", array($id,$id)) ->andWhere("u.id <> ?", $id) ->andWhere("a.estado LIKE ?", 1); echo $q1->getSqlQuery(); The calling to getSqlQuery outputs this clause: SELECT s.id AS s_id, s.username AS s_username, s.algorithm AS s_algorithm, s.salt AS s_salt, s.password AS s__password, s.is_active AS s__is_active, s.is_super_admin AS s__is_super_admin, s.last_login AS s__last_login, s.email_address AS s__email_address, s.nombre_apellidos AS s__nombre_apellidos, s.sexo AS s__sexo, s.fecha_nac AS s__fecha_nac, s.provincia AS s_provincia, s.localidad AS s_localidad, s.fotografia AS s_fotografia, s.avatar AS s_avatar, s.avatar_mensajes AS s__avatar_mensajes, s.created_at AS s__created_at, s.updated_at AS s__updated_at, a.id AS a__id, a.user1_id AS a__user1_id, a.user2_id AS a__user2_id, a.estado AS a__estado FROM sf_guard_user s LEFT JOIN amigo_usuario a ON ((s.id = a.user2_id OR s.id = a.user1_id)) WHERE ((a.user2_id = ? OR a.user1_id = ?) AND s.id < ? AND a.estado LIKE ?) If i take that clause to phpmyadmin SQL tab i get this error 1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '? OR a.user1_id = ?) AND s.id < ? AND a.estado LIKE ?) LIMIT 0, 30' at line 1 Why i'm getting this error? Regards Javi

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  • Cannot send email in ASP.NET through Godaddy servers.

    - by Jared
    I have an ASP.NET application hosted on Godaddy that I want to send email from. When it runs, I get: Mailbox name not allowed. The server response was: sorry, relaying denied from your location. The important parts of the code and Web.config are below: msg = new MailMessage("[email protected]", email); msg.Subject = "GreekTools Registration"; msg.Body = "You have been invited by your organization to register for the GreekTools recruitment application.<br/><br/>" + url + "<br/><br/>" + "Sincerely,<br/>" + "The GreekTools Team"; msg.IsBodyHtml = true; client = new SmtpClient(); client.Host = "relay-hosting.secureserver.net"; client.Send(msg); <system.net> <mailSettings> <smtp from="[email protected]"> <network host="relay-hosting.secureserver.net" port="25" userName="********" password="*********" /> </smtp> </mailSettings>

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  • General JDBC Setup

    - by AeroDroid
    So I have a MySQL database set up on a Debian server and it works fine from a phpMyAdmin client. I'm currently working on a project to write a Java server that would be able to use the MySQL database that is already on this server through a JDBC connection. I've looked at many tutorials and documentations but all of them seem to just explain how to do client-side code, but I have yet to figure out how to even successfully open a JDBC connection to the server. As far as I am concerned, I believe that program has the drivers properly set up because it's not crashing anymore (I simply direct the Java Build Path of my program to the Connector/J provided by MySQL). As far as my program goes, this is what it looks like... import java.sql.*; public class JDBCTest { public static void main(String[] args) { System.out.println("Started!"); try { DriverManager.registerDriver(new com.mysql.jdbc.Driver()); System.out.println("Driver registered. Connecting..."); Connection conn = DriverManager.getConnection("jdbc:mysql://localhost/", "root", "password"); System.out.println("Connected!"); conn.close(); } catch (SQLException e) { System.out.println("Error!"); e.printStackTrace(); } } } This is what's printed... Started! Driver registered. Connecting... It's as if the DriverManager.getConnection(String) just freezes there. I'm sure this is a problem with the server because when I intentionally misspell localhost, or an IP address, the program crashes within 20 seconds. This just hangs there forever. Sorry about this wall of text, but my final question is if anyone has any information what I should do or install on the server to get this to work? Thank you so much!

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  • Attachment empty/blank when sending mail using phpmailer

    - by chupinette
    Hello! I am using phpmailer class to send email and i am attaching a file to the mail. The email is sent successfully but the attachment which is an sql file is empty which should not be the case. I have tried with an image file, but it seems that every file that i attach is empty. Can anyone help me solve this problem please? $mail = new PHPMailer(); $body = "Reminder"; $mail->IsSMTP(); $mail->Host = "mail.yourdomain.com"; $mail->SMTPDebug = 1; $mail->SMTPAuth = true; $mail->SMTPSecure = "ssl"; $mail->Host = "smtp.gmail.com"; $mail->Port = 465; $mail->Username = "[email protected]"; $mail->Password = "abc"; $mail->SetFrom('[email protected]', 'blbla'); $mail->AddReplyTo("[email protected]","First Last"); $mail->Subject = "Your order has been successfully placed" $mail->MsgHTML($body); $mail->AddAddress("[email protected]","xyz"); $mail->AddAttachment("D:\b2\shop3.sql","shop3.sql"); I have tried to display the size of the file before attaching it, and it actually displays the file size. Can anyone help me please?

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  • Windows Service doesn't start process with different credentials

    - by Marcus
    I have a Windows Service, running as a user, that should start several processes under different user credentials. I'm using the following code to start a process: Dim winProcess As New System.Diagnostics.Process With winProcess .StartInfo.Arguments = "some_args" .StartInfo.CreateNoWindow = True .StartInfo.ErrorDialog = False .StartInfo.FileName = "C:\TEMP\ProcessFromService\ProcessFromService\bin\Debug\ProcessFromService.exe" .StartInfo.UseShellExecute = False .StartInfo.WindowStyle = ProcessWindowStyle.Hidden 'Opgave WorkingDirectory kan soms tot problemen leiden, indien betreffende directory 'niet bereikbaar (rechten) is voor opgegeven gebruiker. 'Beter dus om deze niet op te geven. '.StartInfo.WorkingDirectory = My.Computer.FileSystem.SpecialDirectories.Temp .StartInfo.Domain = "" .StartInfo.UserName = "MyUserId" Dim strPassword As String = "MyPassword" Dim ssPassword As New Security.SecureString For Each chrPassword As Char In strPassword.ToCharArray ssPassword.AppendChar(chrPassword) Next .StartInfo.Password = ssPassword .Start() End With The process is correctly started when I use the same credentials as of which the Windows Service is running under. The process is not started, without any error, when I use different credentials. In other words: If the Windows Service is running as UserA then I can start a process running as UserA. If the Windows Service is running as UserB then I can not start a process running as UserA. I have created a test project in which I can reproduce this problem. If you put this project in C:\Temp then the used paths will be correct. You can download this test project here: https://dl.dropboxusercontent.com/u/5391091/ProcessFromService.zip NB: I hope this info is enough to explain it. If you need more info, please let me know and I will add it.

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  • UITableView only pushes to one controller

    - by Mitochondria
    So I have my UITableView, with 2 sections and 1 cell in each, and if I click the first one, it works, then the second one, it goes to the first controller. RootViewController is a navigationController, trying to push to ViewControllers. Here's the code for the tableView: // Customize the number of sections in the table view. - (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView { return 2; } // Customize the number of rows in the table view. - (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section { if(section == 0) return 1; else return 1; } - (NSString *)tableView:(UITableView *)tableView titleForHeaderInSection:(NSInteger)section{ if(section == 0){ return @"Terminal/SSH Guides"; }else{ return @"Cydia Tutorials"; } } // Customize the appearance of table view cells. - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *CellIdentifier = @"Cell"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithFrame:CGRectZero reuseIdentifier:CellIdentifier] autorelease]; } // Set up the cell... if(indexPath.section == 0){ cell.text = @"Changing Password for root"; } else { cell.text = @"Hiding Sections"; } return cell; } - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { id newController; switch (indexPath.row) { case 0: newController = [[rootpassword alloc] initWithNibName:@"rootpassword" bundle:nil]; break; case 1: newController = [[hidingsections alloc] initWithNibName:@"hidingsections" bundle:nil]; break; default: break; } [self.navigationController pushViewController:newController animated:TRUE]; [tableView deselectRowAtIndexPath:indexPath animated:TRUE]; } I'm also having trouble adding more sections and rows/cells to sections. Thanks.

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  • Submit form using javascript, work in FF but not in IE

    - by Permana
    I have this code. The code below is working in Firefox, but it is not in IE <body> <?php $data = getLoginData($_SESSION['whoyouare']); ?> <form name="frm_redirect_dfr" action="<?php echo $data['url']; ?>" method="POST" id="frm_redirect_dfr" style="display: none;"> <input name="DFRNet_User" value="<?php echo $data['username']; ?>" type="hidden" /> <input name="DFRNet_Pass" value="<?php echo $data['password']; ?>" type="hidden" /> <input name="tbllogin" value="login" type="hidden" /> <input type="submit" value="submit" /> </form> <script language="javascript" type="text/javascript"> document.forms["frm_redirect_dfr"].submit(); </script> </body> What I want to do is, when user access the page, it first will try to get login data, echo it in the form, and submit the form automatically using javascript

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  • authentication question (security code generation logic)

    - by Stick it to THE MAN
    I have a security number generator device, small enough to go on a key-ring, which has a six digit LCD display and a button. After I have entered my account name and password on an online form, I press the button on the security device and enter the security code number which is displayed. I get a different number every time I press the button and the number generator has a serial number on the back which I had to input during the account set-up procedure. I would like to incorporate similar functionality in my website. As far as I understand, these are the main components: Generate a unique N digit aplha-numeric sequence during registration and assign to user (permanently) Allow user to generate an N (or M?) digit aplha-numeric sequence remotely For now, I dont care about the hardware side, I am only interested in knowing how I may choose a suitable algorithm that will allow the user to generate an N (or M?) long aplha-numeric sequence - presumably, using his unique ID as a seed Identify the user from the number generated in step 2 (which decryption method is the most robust to do this?) I have the following questions: Have I identified all the steps required in such an authentication system?, if not please point out what I have missed and why it is important What are the most robust encryption/decryption algorithms I can use for steps 1 through 3 (preferably using 64bits)?

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