Search Results

Search found 19375 results on 775 pages for 'codeigniter url'.

Page 385/775 | < Previous Page | 381 382 383 384 385 386 387 388 389 390 391 392  | Next Page >

  • Java webapp: how to implement a web bug (1x1 pixel)?

    - by NoozNooz42
    In the accepted answer in the following question, a SO regular with 13K+ rep suggests to use a "web bug" (non-cacheable 1x1 img) to be able to track requests in the logs: http://stackoverflow.com/questions/1784893 How can I do this in Java? Basically, I've got two issues: how to make sure the 1x1 image is not cacheable (how to set the header)? how to make sure the query for these 1x1 image will appear in the logs? I'm looking for exact piece of code because I know how to write a .jsp/servlet and I know how to serve an 1x1 image :) My question is really about the exact .jsp/servlet that I should write and how/what needs to be done so that Tomcat logs the request. For example I plan to use the following mapping: <servlet-mapping> <servlet-name>WebBugServlet</servlet-name> <url-pattern>/webbug*</url-pattern> </servlet-mapping> and then use an img tag referencing a "webbug.png" (or .gif), so how do I write the .jsp/servlet? What/where should I look for in the logs?

    Read the article

  • Google Reader API - feed/[FEEDURL]/ is coming back as Not found

    - by JustinXXVII
    There is one feed I'm subscribed to which always turns up as NOT FOUND when I try to use the API. I return an array of Dictionaries, containing 3 objects. The first in the list represents the user himself, like so: { FeedID = "user/MY_UNIQUE_NUMBER/state/com.google/reading-list"; Timestamp = 1273448807271463; Unread = 59; } The Unread count is very important. My client depends on downloading 59 items from Google before it refreshes. If a feed doesn't download properly, the count is off and the client won't update. An example of a working Feed is here: { FeedID = "feed/http://arstechnica.com/index.rssx"; Timestamp = 1273447158484528; Unread = 13; } The FeedID value combines with a specially formatted URL string and gives back a list of articles. The above example works fine. However, the following feed always returns NOT FOUND on Google, and if I paste the URL verbatim into a browser, it never turns up. See here: { FeedID = "feed/http://www.peopleofwalmart.com/?feed=rss2"; Timestamp = 1273424138183529; Unread = 6; } http://www.google.com/reader/api/0/stream/contents/feed/http://www.peopleofwalmart.com/?feed=rss2?ot=1&r=n&xt=user/-/state/com.google/read&n=6&ck=1273449028&client=testClient If you are at all proficient with the API, can you please help me? Like I said, since Google always says NOT FOUND when I search for that feed, my download count is off by N articles and won't update. I would rather not hack around it, honestly. Thanks!

    Read the article

  • unable to get data from iphone application

    - by user317192
    Hi, I have made a php web services that takes the username and password from iPhone application and saves the data in the users table. I call that web service from my button touchup event like this: NSLog(userName.text); NSLog(password.text); NSString * dataTOB=[userName.text stringByAppendingString:password.text]; NSLog(dataTOB); NSData * postData=[dataTOB dataUsingEncoding:NSUTF8StringEncoding allowLossyConversion:YES]; NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]]; NSLog(postLength); NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease]; NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"http://localhost:8888/write.php"]]; [request setURL:url]; [request setHTTPMethod:@"POST"]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"]; [request setHTTPBody:postData]; NSURLResponse *response; NSError *error; [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error]; if(error==nil) NSLog(@"Error is nil"); else NSLog(@"Error is not nil"); NSLog(@"success!"); I am getting nothing from Iphone side into the web service and I am unable to understand why this is happening. Although i debugged and found that everything is fine at the iphone application level but the call to the web service doesn't works as expected...... Please suggest..... Thanks Ashish

    Read the article

  • $.ajax not loading data data everytime from server

    - by Ted
    I have written a simple jQuery.ajax function which loads a user control from the server on click of a button. The first time I click the button, it goes to the server and gets me the user control. But each subsequent click of the same button does not goes to the server to fetch me the user control. Since my user control fetches data from db, I need to reload the user control everytime i hit the button. But if anyhow I get my user control to unload from the page, and re-click the button, it goes to the server and fetches me the user control. Here's the code: $("#btnLoad").click(function() { if ($(this).attr("value") == "Load Control") { $.ajax({ url: "AJAXHandler.ashx", data: { "lt": "loadcontrol" }, dataType: "html", success: function(data) { content.html(data); } }); $(this).attr("value", "Unload Control"); } else { $.ajax({ url: "AJAXHandler.ashx", data: { "lt": "unloadcontrol" }, dataType: "html", success: function(data) { content.html(data); } }); $(this).attr("value", "Load Control"); } }); Please let me know if there is any other way I can get my user control loaded from server everytime I click the button.

    Read the article

  • UISplitView's DetailView not changing its content

    - by Knodel
    I have an iPad app with a UISplitView. In the Root View I have a two level UITableView (it takes its content from a plist). In the Detail View I have a UIWebView. - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { //Get the dictionary of the selected data source. NSDictionary *dictionary = [self.tableDataSource objectAtIndex:indexPath.row]; //Get the children of the present item. NSArray *Children = [dictionary objectForKey:@"Children"]; RootViewController *rvController = [[RootViewController alloc] init]; rvController.CurrentTitle = [dictionary objectForKey:@"Title"]; rvController.CurrentLevel = +1; //Push the new table view on the stack [self.navigationController pushViewController:rvController animated:YES]; rvController.tableDataSource = Children; NSString *name = [NSString stringWithFormat:@"%@.rtfd.zip", rvController.CurrentTitle ]; NSString* resourcePath = [[NSBundle mainBundle] resourcePath]; NSString* sourceFilePath = [resourcePath stringByAppendingPathComponent:name]; NSURL* url = [NSURL fileURLWithPath:sourceFilePath isDirectory:NO]; NSURLRequest* request = [NSURLRequest requestWithURL:url]; [detailViewController.webView loadRequest:request]; } That's how I want the UIWebView's content to be changed. If I name the .rtfd.zip file the same as a first level cell of the UITableView, it works, UIWebView's content changes. But this doesn't work with the second level UITableView. What am I doing wrong? Thanks in advance!

    Read the article

  • UITableView Inactive Until Scroll iPhone

    - by dubbeat
    HI, I'm trying to find the cause of some annoying behaviour with my UITableView. In each cell of my table (10 of them ) I asynchronously load an image. The problem is, is that if I don't touch the app at all the imageviews will permanently show a loading icon. However as soon as I scroll a cell off the screen and back on again the image shows straight away. What could be causing this "stuck in the mud" behaviour? Is there a way to force whatever gets called when the list is scrolled to make the needed update happen? #define ASYNC_IMAGE_TAG 9999 #define LABEL_TAG 8888 // Customize the appearance of table view cells. - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { PromoListItem *promo = [promoList objectAtIndex:indexPath.row]; static NSString *CellIdentifier = @"Cell"; AsyncImageView *asyncImageView = nil; UILabel *label = nil; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease]; CGRect frame; frame.origin.x = 0; frame.origin.y = 0; frame.size.width = 100; frame.size.height = 100; asyncImageView = [[[AsyncImageView alloc] initWithFrame:frame] autorelease]; asyncImageView.tag = ASYNC_IMAGE_TAG; [cell.contentView addSubview:asyncImageView]; frame.origin.x = 110; frame.size.width =100; label = [[[UILabel alloc] initWithFrame:frame] autorelease]; label.tag = LABEL_TAG; [cell.contentView addSubview:label]; cell.accessoryType = UITableViewCellAccessoryDisclosureIndicator; } else { asyncImageView = (AsyncImageView *) [cell.contentView viewWithTag:ASYNC_IMAGE_TAG]; label = (UILabel *) [cell.contentView viewWithTag:LABEL_TAG]; } NSURL *url = [NSURL URLWithString:promo.imgurl]; [asyncImageView loadImageFromURL:url]; label.text = promo.artistname; return cell; }

    Read the article

  • Too many open files in one of my java routine.

    - by Irfan Zulfiqar
    I have a multithreaded code that has to generated a set of objects and write them to a file. When I run it I sometime get "Too many open files" message in Exception. I have checked the code to make sure that all the file streams are being closed properly. Here is the stack trace. When I do ulimit -a, open files allowed is set to 1024. We think increasing this number is not a viable option / solution. [java] java.io.FileNotFoundException: /export/event_1_0.dtd (Too many open files) [java] at java.io.FileInputStream.open(Native Method) [java] at java.io.FileInputStream.<init>(FileInputStream.java:106) [java] at java.io.FileInputStream.<init>(FileInputStream.java:66) [java] at sun.net.www.protocol.file.FileURLConnection.connect(FileURLConnection.java:70) [java] at sun.net.www.protocol.file.FileURLConnection.getInputStream(FileURLConnection.java:161) [java] at java.net.URL.openStream(URL.java:1010) Now what we have identified so far by looking closely at the list of open files is that the VM is opening same class file multiple times. /export/BaseEvent.class 236 /export/EventType1BaseEvent.class 60 /export/EventType2BaseEvent.class 48 /export/EventType2.class 30 /export/EventType1.class 14 Where BaseEvent is partent of all the classes and EventType1 ant EventType2 inherits EventType1BaseEvent and EventType2BaseEvent respectively. Why would a class loader load the same class file 200+ times. It seems it is opening up the base class as many time it create any child instance. Is this normal? Can it be handler any other way apart from increasing the number of open files?

    Read the article

  • Equal Column Heights

    - by cjmcjm
    I want the east and west divs to extend down to match the height of the center div... possible? Thanks so much. .con{ padding-left: 22px; padding-right: 22px; overflow: hidden; } .col{ position: relative; float: left; } .west{ width: 7px; right: 22px; margin-left: -100%; background: url(http://www.example.com/west.png) repeat-y; padding: 0 0 0 15; } .east{ width: 7px; margin-right: -22px; background: url(http://www.example.com/east.png) repeat-y; padding: 0 15 0 0; } .center{ width: 100%; } <div class="con"> <div class="center col"> Test Text<br/> Test Text<br/> Test Text<br/> Test Text<br/> </div> <div class="west col"> </div> <div class="east col"> </div> </div>

    Read the article

  • Calling javascript function from android webview?

    - by Edmond Tamas
    I try to call a javascript function from directly form my application (webview.apk), in order to start a script which would autoplay a html5 video clip, I have tried to add itt right after webview loadURL but wwithout luck. Maybe someone could take a look at the code. What am I missing? Thanks! package tscolari.mobile_sample; import android.app.Activity; import android.os.Bundle; import android.view.View; import android.webkit.WebSettings; import android.webkit.WebView; import android.webkit.WebViewClient; import android.webkit.WebChromeClient; import android.media.MediaPlayer; public class InfoSpotActivity extends Activity { /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); WebView mainWebView = (WebView) findViewById(R.id.mainWebView); WebSettings webSettings = mainWebView.getSettings(); webSettings.setJavaScriptEnabled(true); mainWebView.setWebChromeClient(new WebChromeClient()); mainWebView.setWebViewClient(new MyCustomWebViewClient()); mainWebView.setScrollBarStyle(View.SCROLLBARS_INSIDE_OVERLAY); mainWebView.loadUrl("http://server.info-spot.net"); mainWebView.loadUrl("javascript:playVideo()"); } private class MyCustomWebViewClient extends WebViewClient { @Override public boolean shouldOverrideUrlLoading(WebView view, String url) { view.loadUrl(url); return true; } } }

    Read the article

  • Doctrine Default Primary Key Problem (Again)

    - by 01010011
    Hi, Should I change all of my uniquely-named MySQL database primary keys to 'id' to avoid getting errors related to Doctrine's default primary key set in the plugin 'doctrine_pi.php'? To further elaborate, I am getting the following reoccurring error, this time after trying to login to my login page: SQLSTATE[42S22]: Column not found: 1054 Unknown column 'u.book_id' in 'field list'' in... I suspect the problem resides at a MySQL table used for my login, of which has a primary key called id Marc B originally solved an identical problem for me in this post http://stackoverflow.com/questions/2702229/doctrine-codeigniter-mysql-crud-errors when I had the same problem with a different table within the same database. Following his suggestion, I changed the default primary key located at system/application/plugins/doctrine_pi.php from 'id' to 'book_id': <?php // system/application/plugins/doctrine_pi.php ... // set the default primary key to be named 'id', integer, 4 bytes Doctrine_Manager::getInstance()->setAttribute( Doctrine::ATTR_DEFAULT_IDENTIFIER_OPTIONS, array('name' => 'book_id', 'type' => 'integer', 'length' => 4)); and that solved my previous problem. However, my login page stopped working. So what is the safe thing to do? Change all of my primary keys to 'id' (will that solve the problem without causing some other problem I am not aware of). Or should I add some lines of code in doctrine_pi.php?

    Read the article

  • ASP.Net MVC 2 - How to set up a Cancel button with client side navigation

    - by arame3333
    Thanks to a previous question I found a useful link on multiple buttons. http://weblogs.asp.net/dfindley/archive/2009/05/31/asp-net-mvc-multiple-buttons-in-the-same-form.aspx What I want to do is have a cancel button on my page, similar to this; <button name="button" type="button" onclick="document.location.href=$('#cancelUrl').attr('href')">Cancel</button> <a id="cancelUrl" href="<%: Url.Action("Index", "Home") %>" style="display:none;"></a> However although this code works, I really want to go back to the previous page. For Web Forms I could use the javascript Back() or Go(-1) functions, but they relied on postbacks. I could of course hard code the previous page and controller as I have done above. However I am struggling to find links that explain to me how Url.Action works. Because if I do this, I also need to include an index parameter, and I am not clear how the syntax works for that. It seems odd the amount of coding to do this. Out of curiosity, I am also wondering how you TDD client side code like this.

    Read the article

  • how to make the user add and delete in android

    - by user3678019
    i have 1 activity .. and in this activity i have 2 web view next to each other , i would like to add , ADD and Delete Button that can add one more web view next to the last web view , and the delete wish will delete any of the web view the user choose . and i want to make the user but it in the order he want like webview 1 first then webview 2 second how can i do this this is mu main.xml <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" xmlns:tools="http://schemas.android.com/tools" android:layout_width="match_parent" android:layout_height="match_parent" tools:context="test.zezo.test.Main$PlaceholderFragment" > <HorizontalScrollView android:id="@+id/horizontalScrollView2" android:layout_width="match_parent" android:layout_height="match_parent" android:layout_alignParentLeft="true" android:layout_alignParentRight="true" android:layout_alignParentTop="true" > <LinearLayout android:layout_width="match_parent" android:layout_height="match_parent" android:orientation="horizontal" > <WebView android:id="@+id/webView1" android:layout_width="350dp" android:layout_height="match_parent" android:layout_alignParentLeft="true" /> <WebView android:id="@+id/webView22" android:layout_width="350dp" android:layout_height="match_parent" android:layout_toRightOf="@+id/webView1" android:layout_alignParentLeft="true" /> </LinearLayout> </HorizontalScrollView> and this is a part of my main.java webView = (WebView) findViewById(R.id.webView1); String url = "http://google.com"; webView.getSettings().setJavaScriptEnabled(true); webView.loadUrl(url); webView.setWebChromeClient(new WebChromeClient()); webView.setWebViewClient(new WebViewClient()); WebView webView22 = (WebView)findViewById(R.id.webView22); webView22.getSettings().setJavaScriptEnabled(true); webView22.loadUrl("google.com); webView22.setWebChromeClient(new WebChromeClient()); webView22.setWebViewClient(new WebViewClient()); so how can i do the ADD and DELETE and re Order Buttons to it and one more thing it should be save so when he reopen the app it will be the same as after he add or delete or re order

    Read the article

  • Designing a general database interface in PHP

    - by lamas
    I'm creating a small framework for my web projects in PHP so I don't have to do the basic work over and over again for every new website. It is not my goal to create a second CakePHP or Codeigniter and I'm also not planning to build my websites with any of the available frameworks as I prefer to use things I've created myself in general. I have no problems in designing that framework when it comes to parts like the core structure, request handling, and so on but I'm getting stuck with designing the database interface for my modules. I've already thought about using the MVC pattern but thought that it would be a bit of a overkill. So the exact problem I'm facing is how my frameworks modules (viewCustomers could be a module, for example) should interact with the database. Is it a good idea to write SQL directly in PHP (mysql_query( 'SELECT firstname, lastname(.....))? How could I abstract a query like SELECT firstname, lastname FROM customers WHERE id=X Would MySQL helper functions like $this->db->get( array('firstname', 'lastname'), array('id'=>X) ) be a good idea? I suppose not because they actually make everything more complicated by requiring arrays to be created and passed. Is the Model pattern from MVC my only real option?

    Read the article

  • JSF works only with the .xhtml ending

    - by ThreeFingerMark
    Hello, i start with the programming of a JSF Website. At the moment all files have the .xhtml ending. When i go to http://localhost:8080/myProject/start.jsf everything is all right. But when i rename the file from start.xhtml to start.jsf i became a NoClassDefFound Error. What is my mistake? <servlet-name>Faces Servlet</servlet-name> <servlet-class>javax.faces.webapp.FacesServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>Faces Servlet</servlet-name> <url-pattern>*.jsf</url-pattern> </servlet-mapping> <context-param> <param-name>javax.faces.PROJECT_STAGE</param-name> <param-value>Development</param-value> </context-param>

    Read the article

  • ListView Parsing Persian xml

    - by Namikaze Minato
    I used a tutorial about listview parsing xm from internet and using LasyAdapter shows the items in listview. When I add persian characters in xml (into one of childnodes) the result is some boxes in listview (after showing the text in listview). The format of xml is UTF-8, too. I used typeface too (but didn't work). Besides when I type Pwesian into the application it shows alright but it can't show Persiann content parsed from xml. Thanks in advance. I updated the post with original XMLparser (which was the problem). public String getXmlFromUrl(String url) { String xml = null; try { // defaultHttpClient DefaultHttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(url); HttpResponse httpResponse = httpClient.execute(httpPost); HttpEntity httpEntity = httpResponse.getEntity(); xml = EntityUtils.toString(httpEntity); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } // return XML return xml; } public Document getDomElement(String xml) { Document doc = null; DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); try { DocumentBuilder db = dbf.newDocumentBuilder(); InputSource is = new InputSource(); is.setCharacterStream(new StringReader(xml)); doc = db.parse(is); } catch (ParserConfigurationException e) { Log.e("Error: ", e.getMessage()); return null; } catch (SAXException e) { Log.e("Error: ", e.getMessage()); return null; } catch (IOException e) { Log.e("Error: ", e.getMessage()); return null; } return doc; }

    Read the article

  • Apply a Quartz filter while saving PDF under Mac OS X 10.6.3

    - by olpa
    Using Mac OS X API, I'm trying to save a PDF file with a Quartz filter applied, just like it is possible from the "Save As" dialog in the Preview application. So far I've written the following code (using Python and pyObjC, but it isn't important for me): -- filter-pdf.py: begin from Foundation import * from Quartz import * import objc page_rect = CGRectMake (0, 0, 612, 792) fdict = NSDictionary.dictionaryWithContentsOfFile_("/System/Library/Filters/Blue \ Tone.qfilter") in_pdf = CGPDFDocumentCreateWithProvider(CGDataProviderCreateWithFilename ("test .pdf")) url = CFURLCreateWithFileSystemPath(None, "test_out.pdf", kCFURLPOSIXPathStyle, False) c = CGPDFContextCreateWithURL(url, page_rect, fdict) np = CGPDFDocumentGetNumberOfPages(in_pdf) for ip in range (1, np+1): page = CGPDFDocumentGetPage(in_pdf, ip) r = CGPDFPageGetBoxRect(page, kCGPDFMediaBox) CGContextBeginPage(c, r) CGContextDrawPDFPage(c, page) CGContextEndPage(c) -- filter-pdf.py: end Unfortunalte, the filter "Blue Tone" isn't applied, the output PDF looks exactly as the input PDF. Question: what I missed? How to apply a filter? Well, the documentation doesn't promise that such way of creating and using "fdict" should cause that the filter is applied. But I just rewritten (as far as I can) sample code /Developer/Examples/Quartz/Python/filter-pdf.py, which was distributed with older versions of Mac (meanwhile, this code doesn't work too): ----- filter-pdf-old.py: begin from CoreGraphics import * import sys, os, math, getopt, string def usage (): print ''' usage: python filter-pdf.py FILTER INPUT-PDF OUTPUT-PDF Apply a ColorSync Filter to a PDF document. ''' def main (): page_rect = CGRectMake (0, 0, 612, 792) try: opts,args = getopt.getopt (sys.argv[1:], '', []) except getopt.GetoptError: usage () sys.exit (1) if len (args) != 3: usage () sys.exit (1) filter = CGContextFilterCreateDictionary (args[0]) if not filter: print 'Unable to create context filter' sys.exit (1) pdf = CGPDFDocumentCreateWithProvider (CGDataProviderCreateWithFilename (args[1])) if not pdf: print 'Unable to open input file' sys.exit (1) c = CGPDFContextCreateWithFilename (args[2], page_rect, filter) if not c: print 'Unable to create output context' sys.exit (1) for p in range (1, pdf.getNumberOfPages () + 1): #r = pdf.getMediaBox (p) r = pdf.getPage(p).getBoxRect(p) c.beginPage (r) c.drawPDFDocument (r, pdf, p) c.endPage () c.finish () if __name__ == '__main__': main () ----- filter-pdf-old.py: end

    Read the article

  • multiple ajax requests with jquery

    - by Emil
    I got problems with the async nature of Javascript / JQuery. Lets say the following (no latency is counted for, in order to not make it so troublesome); I got three buttons (A, B, C) on a page, each of the buttons adds an item into a shopping cart with one ajax-request each. If I put an intentional delay of 5 seconds in the serverside script (PHP) and pushes the buttons with 1 second apart, I want the result to be the following: Request A, 5 seconds Request B, 6 seconds Request C, 7 seconds However, the result is like this Request A, 5 seconds Request B, 10 seconds Request C, 15 seconds This have to mean that the requests are queued and not run simultaneously, right? Isnt this opposite to what async is? I also tried to add a random get-parameter to the url in order to force some uniqueness to the request, no luck though. I did read a little about this. If you avoid using the same "request object (?)" this problem wont occure. Is it possible to force this behaviour in JQuery? This is the code that I am using $.ajax( { url : strAjaxUrl + '?random=' + Math.floor(Math.random()*9999999999), data : 'ajax=add-to-cart&product=' + product, type : 'GET', success : function(responseData) { // update ui }, error : function(responseData) { // show error } }); I also tried both GET and POST, no difference. I want the requests to be sent right when the button is clicked, not when the previous request is finnished. I want the requests to be run simultaneously, not in a queue.

    Read the article

  • Using AJAX to get a specific DOM Element (using Javascript, not jQuery)

    - by Matt Frost
    How do you use AJAX (in plain JavaScript, NOT jQuery) to get a page (same domain) and display just a specific DOM Element? (Such as the DOM element marked with the id of "bodyContent"). I'm working with MediaWiki 1.18, so my methods have to be a little less conventional (I know that a version of jQuery can be enabled for MediaWiki, but I don't have access to do that so I need to look at other options). I apologize if the code is messy, but there's a reason I need to build it this way. I'm mostly interested in seeing what can be done with the Javascript. Here's the HTML code: <div class="mediaWiki-AJAX"><a href="http://www.domain.com/whatever"></a></div> Here's the Javascript I have so far: var AJAXs = document.getElementsByClassName('mediaWiki-AJAX'); if (AJAXs.length > 0) { for (var i = AJAXs.length - 1; i >= 0; i--) { var URL = AJAXs[i].getElementsByTagName('a')[0].href; xmlhttp = new XMLHttpRequest(); xmlhttp.onreadystatechange = function() { if (xmlhttp.readyState == 4 && xmlhttp.status == 200) { AJAXs[i].innerHTML = xmlhttp.responseText; } } xmlhttp.open('GET',URL,true); xmlhttp.send(); } }

    Read the article

  • Subscribe through API .net C#

    - by Younes
    I have to submit subscription data to another website. I have got documentation on how to use this API however i'm not 100% sure of how to set this up. I do have all the information needed, like username / passwords etc. This is the API documentation: https://www.apiemail.net/api/documentation/?SID=4 How would my request / post / whatever look like in C# .net (vs 2008) when i'm trying to acces this API? This is what i have now, I think i'm not on the right track: public static string GArequestResponseHelper(string url, string token, string username, string password) { HttpWebRequest myRequest = (HttpWebRequest)WebRequest.Create(url); myRequest.Headers.Add("Username: " + username); myRequest.Headers.Add("Password: " + password); HttpWebResponse myResponse = (HttpWebResponse)myRequest.GetResponse(); Stream responseBody = myResponse.GetResponseStream(); Encoding encode = System.Text.Encoding.GetEncoding("utf-8"); StreamReader readStream = new StreamReader(responseBody, encode); //return string itself (easier to work with) return readStream.ReadToEnd(); Hope someone knows how to set this up properly. Thx!

    Read the article

  • PHP: Best solution for links breaking in a mod_rewrite app

    - by psil
    I'm using mod rewrite to redirect all requests targeting non-existent files/directories to index.php?url=* This is surely the most common thing you do with mod_rewrite yet I have a problem: Naturally, if the page url is "mydomain.com/blog/view/1", the browser will look for images, stylesheets and relative links in the "virtual" directory "mydomain.com/blog/view/". Problem 1: Is using the base tag the best solution? I see that none of the PHP frameworks out there use the base tag, though. I'm currently having a regex replace all the relative links to point to the right path before output. Is that "okay"? Problem 2: It is possible that the server doesn't support mod_rewrite. However, all public files like images, stylesheets and the requests collector index.php are located in the directory /myapp/public. Normally mod_rewrite points all request to /public so it seems as if public was actually the root directory too all users. However if there is no mod_rewrite, I then have to point the users to /public from the root directory with a header() call. That means, however that all links are broken again because suddenly all images, etc. have to be called via /public/myimage.jpg Additional info: When there is no mod_rewrite the above request would look like this: mydomain.com/public/index.php/blog/view/1 What would be the best solutions for both problems?

    Read the article

  • How can I properly handle 404s in ASP.NET MVC?

    - by Brian
    I am just getting started on ASP.NET MVC so bear with me. I've searched around this site and various others and have seen a few implementations of this. EDIT: I forgot to mention I am using RC2 Using URL Routing: routes.MapRoute( "Error", "{*url}", new { controller = "Errors", action = "NotFound" } //404s ); The above seems to take care of requests like this (assuming default route tables setup by initial MVC project): "/blah/blah/blah/blah" Overriding HandleUnknownAction() in the controller itself: //404s - handle here (bad action requested protected override void HandleUnknownAction(string actionName) { ViewData["actionName"] = actionName; View("NotFound").ExecuteResult(this.ControllerContext); } However the previous strategies do not handle a request to a Bad/Unknown controller. For example, I do not have a "/IDoNotExist", if I request this I get the generic 404 page from the web server and not my 404 if I use routing + override. So finally, my question is: Is there any way to catch this type of request using a route or something else in the MVC framework itself? OR should I just default to using Web.Config customErrors as my 404 handler and forget all this? I assume if I go with customErrors I'll have to store the generic 404 page outside of /Views due to the Web.Config restrictions on direct access. Anyway any best practices or guidance is appreciated.

    Read the article

  • Django and json request

    - by Hulk
    In a template i have the following code <script> var url="/mypjt/my_timer" $.post(url, paramarr, function callbackHandler(dict) { alert('got response back'); if (dict.flag == 2) { alert('1'); $.jGrowl("Data could not be saved"); } else if(dict.ret_status == 1) { alert('2'); $.jGrowl("Data saved successfully"); window.location = "/mypjt/display/" + dict.rid; } }, "json" ); </script> In views i have the following code, def my_timer(request): dict={} try: a= timer.objects.get(pk=1) dict({'flag':1}) return HttpResponse(simplejson.dumps(dict), mimetype='application/javascript') except: dict({'flag':1}) return HttpResponse(simplejson.dumps(dict), mimetype='application/javascript') My question is since we are making a json request and in the try block ,after setting the flag ,cant we return a page directly as return render_to_response('mypjt/display.html',context_instance=RequestContext(request,{'dict': dict})) instead of sending the response, because on success again in the html page we redirect the code Also if there is a exception then only can we return the json request. My only concern is that the interaction between client and server should be minimal. Thanks..

    Read the article

  • Jqyery Bugs?? Long decimal number after two numbers multiply...

    - by Jerry
    Hi all I am working on a shopping site and I am trying to calculate the subtotal of products. I got my price from a array and quantity from getJSON response array. Two of them multiply comes to my subtotal. I can change the quantity and it will comes out different subtotal. However,when I change the quantity to certain number, the final subtotal is like 259.99999999994 or some long decimal number. I use console.log to check the $price and $qty. Both of them are in the correct format ex..299.99 and 6 quantity.I have no idea what happen. I would appreciate it if someone can help me about it. Here is my Jquery code. $(".price").each(function(index, price){ $price=$(this); //get the product id and the price shown on the page var id=$price.closest('tr').attr('id'); var indiPrice=$($price).html(); //take off $ indiPrice=indiPrice.substring(1) //make sure it is number format var aindiPrice=Number(indiPrice); //push into the array productIdPrice[id]=(aindiPrice); var url=update.php $.getJSON( url, {productId:tableId, //tableId is from the other jquery code which refers to qty:qty}, productId function(responseProduct){ $.each(responseProduct, function(productIndex, Qty){ //loop the return data if(productIdPrice[productIndex]){ //get the price from the previous array we create X Qty newSub=productIdPrice[productIndex]*Number(Qty); //productIdPrice[productIndex] are the price like 199.99 or 99.99 // Qty are Quantity like 9 or 10 or 3 sum+=newSub; newSub.toFixed(2); //try to solve the problem with toFixed but didn't work console.log("id: "+productIdPrice[productIndex]) console.log("Qty: "+Qty); console.log(newSub); **//newSub sometime become XXXX.96999999994** }; Thanks again!

    Read the article

  • Rails - strip xml import from whitespace and line break

    - by val_to_many
    Hey folks, I am stuck with something quite simple but really annoying: I have an xml file with one node, where the content includes line breaks and whitspaces. Sadly I can't change the xml. <?xml version="1.0" encoding="utf-8" ?> <ProductFeed> ACME Ltd. Fooproduct Foo Root :: Bar Category I get to the node and can read from it without trouble: url = "http://feeds.somefeed/feed.xml.gz" @source = open((url), :http_basic_authentication=>["USER", "PW"]) @gz = Zlib::GzipReader.new(@source) @result = @gz.read @doc = Nokogiri::XML(@result) @doc.xpath("/ProductFeed/Vendors/Vendor").each do |manuf| vendor = manuf.css("Name").first.text manuf.xpath("//child::Product").each do |product| product_name = product.css("Name").text foocat = product.css("Category").text puts "#{vendor} ---- #{product_name} ---- #{foocat} " end end This results in: ACME Ltd. ---- Fooproduct ---- Foo Root :: Bar Category Obviously there are line breaks and tab stops or spaces in the string returned by product.css("Category").text. Does anyone know how to strip the result from linebreaks and taps or spaces right here? Alternatively I could do that in the next step, where I do a find on 'foocat' like barcat = Category.find_by_foocat(foocat) Thanks for helping! Val

    Read the article

  • How to read properties file in Greek using Java

    - by Subhendu Mahanta
    I am trying to read from a properties file which have keys in English & values in greek.My code is like this: public class I18NSample { static public void main(String[] args) { String language; String country; if (args.length != 2) { language = new String("el"); country = new String("GR"); } else { language = new String(args[0]); country = new String(args[1]); } Locale currentLocale; ResourceBundle messages; currentLocale = new Locale(language, country); messages = ResourceBundle.getBundle("MessagesBundle",currentLocale, new CustomClassLoader("E:\\properties")); System.out.println(messages.getString("greetings")); System.out.println(messages.getString("inquiry")); System.out.println(messages.getString("farewell")); } } import java.io.File; import java.net.MalformedURLException; import java.net.URL; public class CustomClassLoader extends ClassLoader { private String path; public CustomClassLoader(String path) { super(); this.path = path; } @Override protected URL findResource(String name) { File f = new File(path + File.separator + name); try { return f.toURL(); } catch (MalformedURLException e) { e.printStackTrace(); } return super.findResource(name); } } MessagesBundle_el_GR.properties greetings=??µ. ?a??et? farewell=ep?f. a?t?? inquiry=t? ???e?s, t? ???ete I am compiling like this javac -encoding UTF8 CustomClassLoader.java javac -encoding UTF8 I18Sample.java When I run this I get garbled output.If the properies file is in English,French or German it works fine. Please help. Regards, Subhendu

    Read the article

< Previous Page | 381 382 383 384 385 386 387 388 389 390 391 392  | Next Page >