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  • UITableView Inactive Until Scroll iPhone

    - by dubbeat
    HI, I'm trying to find the cause of some annoying behaviour with my UITableView. In each cell of my table (10 of them ) I asynchronously load an image. The problem is, is that if I don't touch the app at all the imageviews will permanently show a loading icon. However as soon as I scroll a cell off the screen and back on again the image shows straight away. What could be causing this "stuck in the mud" behaviour? Is there a way to force whatever gets called when the list is scrolled to make the needed update happen? #define ASYNC_IMAGE_TAG 9999 #define LABEL_TAG 8888 // Customize the appearance of table view cells. - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { PromoListItem *promo = [promoList objectAtIndex:indexPath.row]; static NSString *CellIdentifier = @"Cell"; AsyncImageView *asyncImageView = nil; UILabel *label = nil; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease]; CGRect frame; frame.origin.x = 0; frame.origin.y = 0; frame.size.width = 100; frame.size.height = 100; asyncImageView = [[[AsyncImageView alloc] initWithFrame:frame] autorelease]; asyncImageView.tag = ASYNC_IMAGE_TAG; [cell.contentView addSubview:asyncImageView]; frame.origin.x = 110; frame.size.width =100; label = [[[UILabel alloc] initWithFrame:frame] autorelease]; label.tag = LABEL_TAG; [cell.contentView addSubview:label]; cell.accessoryType = UITableViewCellAccessoryDisclosureIndicator; } else { asyncImageView = (AsyncImageView *) [cell.contentView viewWithTag:ASYNC_IMAGE_TAG]; label = (UILabel *) [cell.contentView viewWithTag:LABEL_TAG]; } NSURL *url = [NSURL URLWithString:promo.imgurl]; [asyncImageView loadImageFromURL:url]; label.text = promo.artistname; return cell; }

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  • Java webapp: how to implement a web bug (1x1 pixel)?

    - by NoozNooz42
    In the accepted answer in the following question, a SO regular with 13K+ rep suggests to use a "web bug" (non-cacheable 1x1 img) to be able to track requests in the logs: http://stackoverflow.com/questions/1784893 How can I do this in Java? Basically, I've got two issues: how to make sure the 1x1 image is not cacheable (how to set the header)? how to make sure the query for these 1x1 image will appear in the logs? I'm looking for exact piece of code because I know how to write a .jsp/servlet and I know how to serve an 1x1 image :) My question is really about the exact .jsp/servlet that I should write and how/what needs to be done so that Tomcat logs the request. For example I plan to use the following mapping: <servlet-mapping> <servlet-name>WebBugServlet</servlet-name> <url-pattern>/webbug*</url-pattern> </servlet-mapping> and then use an img tag referencing a "webbug.png" (or .gif), so how do I write the .jsp/servlet? What/where should I look for in the logs?

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  • What techniques can be used to detect so called "black holes" (a spider trap) when creating a web crawler?

    - by Tom
    When creating a web crawler, you have to design somekind of system that gathers links and add them to a queue. Some, if not most, of these links will be dynamic, which appear to be different, but do not add any value as they are specifically created to fool crawlers. An example: We tell our crawler to crawl the domain evil.com by entering an initial lookup URL. Lets assume we let it crawl the front page initially, evil.com/index The returned HTML will contain several "unique" links: evil.com/somePageOne evil.com/somePageTwo evil.com/somePageThree The crawler will add these to the buffer of uncrawled URLs. When somePageOne is being crawled, the crawler receives more URLs: evil.com/someSubPageOne evil.com/someSubPageTwo These appear to be unique, and so they are. They are unique in the sense that the returned content is different from previous pages and that the URL is new to the crawler, however it appears that this is only because the developer has made a "loop trap" or "black hole". The crawler will add this new sub page, and the sub page will have another sub page, which will also be added. This process can go on infinitely. The content of each page is unique, but totally useless (it is randomly generated text, or text pulled from a random source). Our crawler will keep finding new pages, which we actually are not interested in. These loop traps are very difficult to find, and if your crawler does not have anything to prevent them in place, it will get stuck on a certain domain for infinity. My question is, what techniques can be used to detect so called black holes? One of the most common answers I have heard is the introduction of a limit on the amount of pages to be crawled. However, I cannot see how this can be a reliable technique when you do not know what kind of site is to be crawled. A legit site, like Wikipedia, can have hundreds of thousands of pages. Such limit could return a false positive for these kind of sites. Any feedback is appreciated. Thanks.

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  • JSF works only with the .xhtml ending

    - by ThreeFingerMark
    Hello, i start with the programming of a JSF Website. At the moment all files have the .xhtml ending. When i go to http://localhost:8080/myProject/start.jsf everything is all right. But when i rename the file from start.xhtml to start.jsf i became a NoClassDefFound Error. What is my mistake? <servlet-name>Faces Servlet</servlet-name> <servlet-class>javax.faces.webapp.FacesServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>Faces Servlet</servlet-name> <url-pattern>*.jsf</url-pattern> </servlet-mapping> <context-param> <param-name>javax.faces.PROJECT_STAGE</param-name> <param-value>Development</param-value> </context-param>

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  • Configurating JOOMLA's e-mail notification for new account

    - by Dion
    I'm using Joomla 1.5 to create a local site for my office. The site will be accessed locally via intranet, and my PC will be the localhost for the site. I'm using a Login pluggin, so that anyone who wanted to enter the site should create an account. In JOOMLA, all user who created their account for the first time will receive a notification e-mail like : "Hello pras, You have been added as a User to Information Center by an Administrator. This e-mail contains your username and password to log in to http://localhost/yaddayadda/ Username: hadisuryo.prasetio Password: xxxx Please do not respond to this message as it is automatically generated and is for information purposes only." but if the user click the URL in the mail, which is, "localhost/yaddayadda/" they will not be directed to my site, but to their own PC's localhost.... My question is : How can I Modified the e-mail or the site configuration so that the URL will not be "localhost/yaddayadda/" anymore, but will be "(My-IP adress)/yaddayadda" I'm not going to host my site to a web hosting service, just using my PC as a host. I've been trying to trace on each config and .ini files...it seems that i have to do something with the "JURI" function or the "$mosConfig_live_site" on the backlink.php file $mosConfig_absolute_path = JPATH_SITE; $mosConfig_live_site = JURI :: base(); $url_array = explode('/', $_SERVER['REQUEST_URI']); Can anyone give me assistance ? Thank You

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  • Update database settings in properties file in Spring

    - by mvg
    Hi all, I am trying to create a Database Manager page which shows the database details on page load and updates the database settings when the user press submit I followed this tutorial and set the database settings in properties file. I managed to update the database settings in properties file programmatically. When I retrieved the database settings using the following code DriverManagerDataSource databaseSource = (DriverManagerDataSource)context.getBean("dataSource"); databaseSource.getUsername(); I managed to get the old value and unable to get the new value This is the mapping in applicationContext.xml file <bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer"> <property name="location"> <value>classpath:/bundle/database.properties</value> </property> </bean> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="${jdbc.driverClassName}" /> <property name="url" value="${jdbc.url}" /> <property name="username" value="${jdbc.username}" /> <property name="password" value="${jdbc.password}" /> </bean> I checked the properties file and found it to be updated with the latest input. What am I missing? Thanks in advance P.S I am using JSF1.2 with Spring 3 Update Just making my requirement simple. I am creating a setparate dbsettings page, so that when user wishes to connect to different database he/she can just enter the details in dbsettings page and connect

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  • curl not returning content length header

    - by Michael P. Shipley
    Trying to get image file size using curl but content length header is not returned: $url ="http://www.collegefashion.net/wp-content/plugins/feed-comments-number/image.php?1263"; $fp = curl_init(); curl_setopt($fp, CURLOPT_NOBODY, true); curl_setopt($fp, CURLOPT_RETURNTRANSFER, 1); curl_setopt($fp, CURLOPT_FAILONERROR,1); curl_setopt($fp, CURLOPT_REFERER,''); curl_setopt($fp, CURLOPT_URL, $url); curl_setopt($fp, CURLOPT_HEADER,1); curl_setopt($fp, CURLOPT_USERAGENT,'Mozilla/5.0'); $body = curl_exec($fp); var_dump($body): HTTP/1.1 200 OK Date: Sun, 02 May 2010 02:50:20 GMT Server: Apache/2.0.63 (CentOS) X-Powered-By: W3 Total Cache/0.8.5.2 X-Pingback: http://www.collegefashion.net/xmlrpc.php Cache-Control: no-cache, must-revalidate Expires: Sat, 26 Jul 1997 05:00:00 GMT Content-Type: image/png It works via ssh though: curl -i http://www.collegefashion.net/wp-content/plugins/feed-comments-number/image.php?1263 HTTP/1.1 200 OK Date: Sun, 02 May 2010 03:38:43 GMT Server: Apache/2.0.63 (CentOS) X-Powered-By: W3 Total Cache/0.8.5.2 X-Pingback: http://www.collegefashion.net/xmlrpc.php Cache-Control: no-cache, must-revalidate Expires: Sat, 26 Jul 1997 05:00:00 GMT Content-Length: 347 Content-Type: image/png

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  • PHP: Best solution for links breaking in a mod_rewrite app

    - by psil
    I'm using mod rewrite to redirect all requests targeting non-existent files/directories to index.php?url=* This is surely the most common thing you do with mod_rewrite yet I have a problem: Naturally, if the page url is "mydomain.com/blog/view/1", the browser will look for images, stylesheets and relative links in the "virtual" directory "mydomain.com/blog/view/". Problem 1: Is using the base tag the best solution? I see that none of the PHP frameworks out there use the base tag, though. I'm currently having a regex replace all the relative links to point to the right path before output. Is that "okay"? Problem 2: It is possible that the server doesn't support mod_rewrite. However, all public files like images, stylesheets and the requests collector index.php are located in the directory /myapp/public. Normally mod_rewrite points all request to /public so it seems as if public was actually the root directory too all users. However if there is no mod_rewrite, I then have to point the users to /public from the root directory with a header() call. That means, however that all links are broken again because suddenly all images, etc. have to be called via /public/myimage.jpg Additional info: When there is no mod_rewrite the above request would look like this: mydomain.com/public/index.php/blog/view/1 What would be the best solutions for both problems?

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  • CSS background images not showing in IE?

    - by Kevin
    In IE8 and below, I'm doing this <ul class="dependants_list" style="border-bottom: dashed 1px #53a1dc"> <li class="dependants_summary"> <strong>Name:</strong> De Silva, Angelina<br /> <strong>Gender:</strong> Female<br /> <strong>Date of birth:</strong> 7/3/2009<br /> </li> <form action="/Dependant/Delete/11413" method="get"><input class="delete btn" id="Delete_this_Profile" name="Delete_this_Profile" type="submit" value="Delete this Profile" /> </form><form action="/Dependant/Edit/11413" method="get"><input class="edit btn" id="Modify_this_Profile" name="Modify_this_Profile" type="submit" value="Modify this Profile" /> </form><br /><hr style="display:none" /> and the CSS for it is: .dependants_summary { overflow: hidden; margin-bottom: 10px; padding-right: 0px; padding-left: 85px; padding-top: 5px; padding-bottom: 5px; width: 430px; float: left; font: 120% Arial, Helvetica, sans-serif; } .dependants_list { padding: 0; } .dependants_list li:nth-child(odd) { background: #fff url("../images/dependant_male.png") no-repeat scroll 8px 9px; } .dependants_list li:nth-child(even) { background: #c9e3f4 url("../images/dependant_male.png") no-repeat scroll 8px 9px; } The images are not being shown in IE, but they are in ffox and chrome

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  • How we Can post Video and Image in ASIHTTPRequest ?

    - by GhostRider
    I want to post one image to my webservice and one video too , but problem is that when it go to video part it give me Excess-bad Error NSString *url = [NSString stringWithFormat:@"http://example.com/add_videoxml.php"]; networkQueue = [[ASINetworkQueue alloc] init]; [networkQueue cancelAllOperations]; [networkQueue setShowAccurateProgress:YES]; //[networkQueue setUploadProgressDelegate:progressBar]; [networkQueue setDelegate:self]; [networkQueue setRequestDidFinishSelector:@selector(requestFinished:)]; [networkQueue setRequestDidFailSelector: @selector(requestFailed:)]; request= [[ASIFormDataRequest alloc] initWithURL:[NSURL URLWithString:url]] ; [request setPostValue:@"284" forKey:@"id"]; [request setPostValue:@"show" forKey:@"show"]; [request addRequestHeader:@"Content-Type" value:@"multipart/form-data;boundary=---------------------------1842378953296356978857151853"]; NSData *imgData=UIImageJPEGRepresentation(userImage, 0.9); if(imgData != nil){ [request setFile:imgData withFileName:@"Loveatnight" andContentType:@"image/jpeg" forKey:@"image"]; } //[request addRequestHeader:@"Content-Type" // value:@"multipart/form-data;boundary=---------------------------1842378953296356978857151853"]; if(videoData != nil){ [request setFile:videoData withFileName:@"Loveishard" andContentType:@"image/jpeg" forKey:@"uploadfile"]; }// error is come on that line [request setTimeOutSeconds:500]; //NSLog(@"%@",request); [networkQueue addOperation:request]; [networkQueue go]; Added by the OP [request setFile:videoData withFileName:@"Loveishard" andContentType:@"video/quicktime" forKey:@"uploadfile"]; i use this becuase my video formate is mov , but it again give error

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  • Downloading a file from a PHP page in C#

    - by FoxyShadoww
    Okay, we have a PHP script that creates an download link from a file and we want to download that file via C#. This works fine with progress etc but when the PHP page gives an error the program downloads the error page and saves it as the requested file. Here is the code we have atm: PHP Code: <?php $path = 'upload/test.rar'; if (file_exists($path)) { $mm_type="application/octet-stream"; header("Pragma: public"); header("Expires: 0"); header("Cache-Control: must-revalidate, post-check=0, pre-check=0"); header("Cache-Control: public"); header("Content-Description: File Transfer"); header("Content-Type: " . $mm_type); header("Content-Length: " .(string)(filesize($path)) ); header('Content-Disposition: attachment; filename="'.basename($path).'"'); header("Content-Transfer-Encoding: binary\n"); readfile($path); exit(); } else { print 'Sorry, we could not find requested download file.'; } ?> C# Code: private void btnDownload_Click(object sender, EventArgs e) { string url = "http://***.com/download.php"; WebClient client = new WebClient(); client.DownloadFileCompleted += new AsyncCompletedEventHandler(client_DownloadFileCompleted); client.DownloadProgressChanged += new DownloadProgressChangedEventHandler(ProgressChanged); client.DownloadFileAsync(new Uri(url), @"c:\temp\test.rar"); } private void ProgressChanged(object sender, DownloadProgressChangedEventArgs e) { progressBar.Value = e.ProgressPercentage; } void client_DownloadFileCompleted(object sender, AsyncCompletedEventArgs e) { MessageBox.Show(print); }

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  • NSString writeToFile operation couldn't be completed

    - by Chonch
    Hey, I have an xml file in my application bundle. I want to copy it to the documents folder at installation and then, every time the app launches, get the newest version of this file from the Internet. I use this code: // Check if the file exists in the documents folder NSString *documentsPath = [NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES) objectAtIndex:0]; if (![[NSFileManager defaultManager] fileExistsAtPath:[documentsPath stringByAppendingPathComponent:@"fileName.xml"]]) // If not, copy it there (from the bundle) [[NSFileManager defaultManager] copyItemAtPath:[[[NSBundle mainBundle] resourcePath] stringByAppendingPathComponent:@"OriginalFile.xml"] toPath:[documentsPath stringByAppendingPathComponent:@"fileName.xml"] error:nil]; // Get the newest version of the file from the server NSURL *url=[[NSURL alloc] initWithString:@"http://www.sitename.com/webservice.asmx/webserviceName"]; NSString *results = [[NSString alloc] initWithContentsOfURL:url]; // Replace the current version with the newest one, only if it is valid if (results != nil) [results writeToFile:[documentsPath stringByAppendingPathComponent:@"fileName.xml"] atomically:NO encoding:NSStringEncodingConversionAllowLossy error:nil]; The problem is that the writeToFile command always returns NO and the file's contents remain identical to the original file I included in my app bundle. I checked the value of results and it's correct. I also made sure that the app does perform the writeToString command, but still, it always returns NO. Can anybody tell me what I'm doing wrong? Thanks,

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  • php curl login not work

    - by Massimo Zampieri
    Hi i have a problem with the curl. I watched an old post Remote Login not Working With Curl, but it not work. I followed baba's advice but the code enter in the if statement. Sorry for my bad english. Can anyone help me? This is the code: $url="http://hipfile.com/"; $urllog="http://hipfile.com/login.html"; $postdata = "login=bnnoor&password=########&op=login"; $ch = curl_init(); curl_setopt ($ch, CURLOPT_URL, $url); curl_setopt ($ch, CURLOPT_SSL_VERIFYPEER, FALSE); curl_setopt ($ch, CURLOPT_USERAGENT, "Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.6) Gecko/20070725 Firefox/2.0.0.6"); curl_setopt ($ch, CURLOPT_TIMEOUT, 60); curl_setopt ($ch, CURLOPT_FOLLOWLOCATION, 1); curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt ($ch, CURLOPT_REFERER, $urllog); curl_setopt ($ch, CURLOPT_POSTFIELDS, $postdata); curl_setopt ($ch, CURLOPT_POST, 1); $result = curl_exec ($ch); if (!$result) { $http_code = curl_getinfo($ch, CURLINFO_HTTP_CODE); curl_close($ch); // make sure we closeany current curl sessions die($http_code.' Unable to connect to server. Please come back later.'); } echo $result; curl_close($ch);

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  • multiple ajax requests with jquery

    - by Emil
    I got problems with the async nature of Javascript / JQuery. Lets say the following (no latency is counted for, in order to not make it so troublesome); I got three buttons (A, B, C) on a page, each of the buttons adds an item into a shopping cart with one ajax-request each. If I put an intentional delay of 5 seconds in the serverside script (PHP) and pushes the buttons with 1 second apart, I want the result to be the following: Request A, 5 seconds Request B, 6 seconds Request C, 7 seconds However, the result is like this Request A, 5 seconds Request B, 10 seconds Request C, 15 seconds This have to mean that the requests are queued and not run simultaneously, right? Isnt this opposite to what async is? I also tried to add a random get-parameter to the url in order to force some uniqueness to the request, no luck though. I did read a little about this. If you avoid using the same "request object (?)" this problem wont occure. Is it possible to force this behaviour in JQuery? This is the code that I am using $.ajax( { url : strAjaxUrl + '?random=' + Math.floor(Math.random()*9999999999), data : 'ajax=add-to-cart&product=' + product, type : 'GET', success : function(responseData) { // update ui }, error : function(responseData) { // show error } }); I also tried both GET and POST, no difference. I want the requests to be sent right when the button is clicked, not when the previous request is finnished. I want the requests to be run simultaneously, not in a queue.

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  • Subscribe through API .net C#

    - by Younes
    I have to submit subscription data to another website. I have got documentation on how to use this API however i'm not 100% sure of how to set this up. I do have all the information needed, like username / passwords etc. This is the API documentation: https://www.apiemail.net/api/documentation/?SID=4 How would my request / post / whatever look like in C# .net (vs 2008) when i'm trying to acces this API? This is what i have now, I think i'm not on the right track: public static string GArequestResponseHelper(string url, string token, string username, string password) { HttpWebRequest myRequest = (HttpWebRequest)WebRequest.Create(url); myRequest.Headers.Add("Username: " + username); myRequest.Headers.Add("Password: " + password); HttpWebResponse myResponse = (HttpWebResponse)myRequest.GetResponse(); Stream responseBody = myResponse.GetResponseStream(); Encoding encode = System.Text.Encoding.GetEncoding("utf-8"); StreamReader readStream = new StreamReader(responseBody, encode); //return string itself (easier to work with) return readStream.ReadToEnd(); Hope someone knows how to set this up properly. Thx!

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  • BeautifulSoup HTMLParseError. What's wrong with this?

    - by user1915496
    This is my code: from bs4 import BeautifulSoup as BS import urllib2 url = "http://services.runescape.com/m=news/recruit-a-friend-for-free-membership-and-xp" res = urllib2.urlopen(url) soup = BS(res.read()) other_content = soup.find_all('div',{'class':'Content'})[0] print other_content Yet an error comes up: /Library/Python/2.7/site-packages/bs4/builder/_htmlparser.py:149: RuntimeWarning: Python's built-in HTMLParser cannot parse the given document. This is not a bug in Beautiful Soup. The best solution is to install an external parser (lxml or html5lib), and use Beautiful Soup with that parser. See http://www.crummy.com/software/BeautifulSoup/bs4/doc/#installing-a-parser for help. "Python's built-in HTMLParser cannot parse the given document. This is not a bug in Beautiful Soup. The best solution is to install an external parser (lxml or html5lib), and use Beautiful Soup with that parser. See http://www.crummy.com/software/BeautifulSoup/bs4/doc/#installing-a-parser for help.")) Traceback (most recent call last): File "web.py", line 5, in <module> soup = BS(res.read()) File "/Library/Python/2.7/site-packages/bs4/__init__.py", line 172, in __init__ self._feed() File "/Library/Python/2.7/site-packages/bs4/__init__.py", line 185, in _feed self.builder.feed(self.markup) File "/Library/Python/2.7/site-packages/bs4/builder/_htmlparser.py", line 150, in feed raise e I've let two other people use this code, and it works for them perfectly fine. Why is it not working for me? I have bs4 installed...

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  • Rails - strip xml import from whitespace and line break

    - by val_to_many
    Hey folks, I am stuck with something quite simple but really annoying: I have an xml file with one node, where the content includes line breaks and whitspaces. Sadly I can't change the xml. <?xml version="1.0" encoding="utf-8" ?> <ProductFeed> ACME Ltd. Fooproduct Foo Root :: Bar Category I get to the node and can read from it without trouble: url = "http://feeds.somefeed/feed.xml.gz" @source = open((url), :http_basic_authentication=>["USER", "PW"]) @gz = Zlib::GzipReader.new(@source) @result = @gz.read @doc = Nokogiri::XML(@result) @doc.xpath("/ProductFeed/Vendors/Vendor").each do |manuf| vendor = manuf.css("Name").first.text manuf.xpath("//child::Product").each do |product| product_name = product.css("Name").text foocat = product.css("Category").text puts "#{vendor} ---- #{product_name} ---- #{foocat} " end end This results in: ACME Ltd. ---- Fooproduct ---- Foo Root :: Bar Category Obviously there are line breaks and tab stops or spaces in the string returned by product.css("Category").text. Does anyone know how to strip the result from linebreaks and taps or spaces right here? Alternatively I could do that in the next step, where I do a find on 'foocat' like barcat = Category.find_by_foocat(foocat) Thanks for helping! Val

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  • Which is more secure GET or POST sending parameters with cURL at PHP

    - by Steve
    I want to connect in a secure way with an API and I am using cURL to do it using HTTPS and SSL. Now, i was wondering what is better in terms of security, sending the data through GET or POST: $ch = curl_init("http://api.website.com/connect.php?user=xxx&pass=xxxx); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE); curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 2); $result = curl_exec($ch); curl_close($ch); Or $param['user'] = 'xxxx'; $param['pass'] = 'xxxx'; $ch = curl_init("http://api.website.com/connect.php); curl_setopt($ch, CURLOPT_POST, true); curl_setopt($ch, CURLOPT_POSTFIELDS, $Parameters); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE); curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 2); $result = curl_exec($ch); curl_close($ch); I also realized that POST is much more slower retrieving the data.

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  • NSURLConnection receives data even if no data was thrown back

    - by Anna Fortuna
    Let me explain my situation. Currently, I am experimenting long-polling using NSURLConnection. I found this and I decided to try it. What I do is send a request to the server with a timeout interval of 300 secs. (or 5 mins.) Here is a code snippet: NSURL *url = [NSURL URLWithString:urlString]; NSURLRequest *request = [NSURLRequest requestWithURL:url cachePolicy:NSURLCacheStorageAllowedInMemoryOnly timeoutInterval:300]; NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:&resp error:&err]; Now I want to test if the connection will "hold" the request if no data was thrown back from the server, so what I did was this: if (data != nil) [self performSelectorOnMainThread:@selector(dataReceived:) withObject:data waitUntilDone:YES]; And the function dataReceived: looks like this: - (void)dataReceived:(NSData *)data { NSLog(@"DATA RECEIVED!"); NSString *string = [NSString stringWithUTF8String:[data bytes]]; NSLog(@"THE DATA: %@", string); } Server-side, I created a function that will return a data once it fits the arguments and returns none if nothing fits. Here is a snippet of the PHP function: function retrieveMessages($vardata) { if (!empty($vardata)) { $result = check_data($vardata) //check_data is the function which returns 1 if $vardata //fits the arguments, and 0 if it fails to fit if ($result == 1) { $jsonArray = array('Data' => $vardata); echo json_encode($jsonArray); } } } As you can see, the function will only return data if the $result is equal to 1. However, even if the function returns nothing, NSURLConnection will still perform the function dataReceived: meaning the NSURLConnection still receives data, albeit an empty one. So can anyone help me here? How will I perform long-polling using NSURLConnection? Basically, I want to maintain the connection as long as no data is returned. So how will I do it? NOTE: I am new to PHP, so if my code is wrong, please point it out so I can correct it.

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  • How to call a javascript function from one frame to another in Chrome/Webkit

    - by bambax
    I have developped an application that has a list of items in one frame; when one clicks on an item it does something in another frame (loads an image). This used to work fine in all browsers, including Chrome 3; now it still works fine in FF but in recent versions of Chrome (I believe since 4) it throws this error: Unsafe JavaScript attempt to access frame with URL (...) from frame with URL (...). Domains, protocols and ports must match. This is obviously a security "feature" but is it possible to get around it? Here is a simple test: index.html: <html> <frameset> <frame src="left.html" name="left"/> <frame src="right.html" name="right"/> </frameset> </html> left.html: <html> <body> <a href="javascript:parent.right.test('hello');">click me</a> </body> </html> right.html: <html> <body> <script> function test(msg) { alert(msg); } </script> </body> </html> The above works in FF 3.6 and Chrome 3 but in Chrome 5 it throws the above error...

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  • Django and json request

    - by Hulk
    In a template i have the following code <script> var url="/mypjt/my_timer" $.post(url, paramarr, function callbackHandler(dict) { alert('got response back'); if (dict.flag == 2) { alert('1'); $.jGrowl("Data could not be saved"); } else if(dict.ret_status == 1) { alert('2'); $.jGrowl("Data saved successfully"); window.location = "/mypjt/display/" + dict.rid; } }, "json" ); </script> In views i have the following code, def my_timer(request): dict={} try: a= timer.objects.get(pk=1) dict({'flag':1}) return HttpResponse(simplejson.dumps(dict), mimetype='application/javascript') except: dict({'flag':1}) return HttpResponse(simplejson.dumps(dict), mimetype='application/javascript') My question is since we are making a json request and in the try block ,after setting the flag ,cant we return a page directly as return render_to_response('mypjt/display.html',context_instance=RequestContext(request,{'dict': dict})) instead of sending the response, because on success again in the html page we redirect the code Also if there is a exception then only can we return the json request. My only concern is that the interaction between client and server should be minimal. Thanks..

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  • trying to center a css menu made on purecssmenu.com

    - by Party Mcfly
    i have a menu that i generated on purecssmenu.com and im having trouble trying to center it on my page here is the code... <!-- Start PureCSSMenu.com STYLE --> <style> #pcm{display:none;} ul.pureCssMenu ul{display:none} ul.pureCssMenu li:hover>ul{display:block} ul.pureCssMenu ul{position: absolute;left:-1px;top:98%;} ul.pureCssMenu ul ul{position: absolute;left:98%;top:-2px;} ul.pureCssMenu,ul.pureCssMenu ul { margin:0px; list-style:none; padding:0px 2px 2px 0px; background-color:#000000; background-repeat:repeat; border-color:#000000; border-width:1px; border-style:solid; } ul.pureCssMenu table {border-collapse:collapse}ul.pureCssMenu { display:block; zoom:1; float: left; } ul.pureCssMenu ul{ width:80.85000000000001px; } ul.pureCssMenu li{ display:block; margin:2px 0px 0px 2px; font-size:0px; } ul.pureCssMenu a:active, ul.pureCssMenu a:focus { outline-style:none; } ul.pureCssMenu a, ul.pureCssMenu li.dis a:hover, ul.pureCssMenu li.sep a:hover { display:block; vertical-align:middle; background-color:#000000; border-width:1px; border-color:#000000; border-style:solid; text-align:left; text-decoration:none; padding:2px 5px 2px 10px; _padding-left:0; font:11px Arial; color: #969696; text-decoration:none; cursor:default; } ul.pureCssMenu span{ overflow:hidden; } ul.pureCssMenu li { float:left; } ul.pureCssMenu ul li { float:none; } ul.pureCssMenu ul a { text-align:left; white-space:nowrap; } ul.pureCssMenu li.sep{ text-align:left; padding:0px; line-height:0; height:100%; } ul.pureCssMenu li.sep span{ float:none; padding-right:0; width:3px; height:100%; display:inline-block; background-color:#cccccc #111111 #111111 #cccccc; background-image:none;} ul.pureCssMenu ul li.sep span{ width:100%; height:3px; } ul.pureCssMenu li:hover{ position:relative; } ul.pureCssMenu li:hover>a{ background-color:#000000; border-color:#000000; border-style:solid; font:11px Arial; color: #ffa500; text-decoration:none; } ul.pureCssMenu li a:hover{ position:relative; background-color:#000000; border-color:#000000; border-style:solid; font:11px Arial; color: #ffa500; text-decoration:none; } ul.pureCssMenu li.dis a { color: #666 !important; } ul.pureCssMenu img {border: none;float:left;_float:none;margin-right:2px;width:16px; height:16px; } ul.pureCssMenu ul img {width:16px; height:16px; } ul.pureCssMenu img.over{display:none} ul.pureCssMenu li.dis a:hover img.over{display:none !important} ul.pureCssMenu li.dis a:hover img.def {display:inline !important} ul.pureCssMenu li:hover > a img.def {display:none} ul.pureCssMenu li:hover > a img.over {display:inline} ul.pureCssMenu a:hover img.over,ul.pureCssMenu a:hover ul img.def,ul.pureCssMenu a:hover a:hover img.over{display:inline} ul.pureCssMenu a:hover img.def,ul.pureCssMenu a:hover ul img.over,ul.pureCssMenu a:hover a:hover img.def{display:none} ul.pureCssMenu a:hover ul{display:block} ul.pureCssMenu span{ display:block; background-image:url(./images/arr_white.gif); background-position:right center; background-repeat: no-repeat; padding-right:12px;} ul.pureCssMenu li:hover>a>span{ background-image:url(./images/arrv_white.gif); } ul.pureCssMenu a:hover span{ _background-image:url(./images/arrv_white.gif)} ul.pureCssMenu ul span,ul.pureCssMenu a:hover table span{background-image:url(./images/arr_white.gif)} </style> <!-- End PureCSSMenu.com STYLE --> and here is the html, witch is probably not even needed in this posted but i figure i would include it.. i just want that menu centered inside my website. <!-- Start PureCSSMenu.com MENU --> <ul class="pureCssMenu pureCssMenum"> <li class="pureCssMenui"><a class="pureCssMenui" href="home.html" target="scare">home</a></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#">about</a></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#"><span>haunts</span><![if gt IE 6]></a><![endif]><!--[if lte IE 6]><table><tr><td><![endif]--> <ul class="pureCssMenum"> <li class="pureCssMenui"><a class="pureCssMenui" href="#">2009</a></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#">2010</a></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#">2011</a></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#">2012</a></li> </ul> <!--[if lte IE 6]></td></tr></table></a><![endif]--></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#">studio</a></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#"><span>products</span><![if gt IE 6]></a><![endif]><!--[if lte IE 6]><table><tr><td><![endif]--> <ul class="pureCssMenum"> <li class="pureCssMenui"><a class="pureCssMenui" href="#">nightmares</a></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#">hauntworks</a></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#">atmosfears</a></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#">frightwears</a></li> </ul> <!--[if lte IE 6]></td></tr></table></a><![endif]--></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#"><span>links</span><![if gt IE 6]></a><![endif]><!--[if lte IE 6]><table><tr><td><![endif]--> <ul class="pureCssMenum"> <li class="pureCssMenui"><a class="pureCssMenui" href="#">haunts</a></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#">suppliers</a></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#">resources</a></li> </ul> <!--[if lte IE 6]></td></tr></table></a><![endif]--></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#">contact</a></li> </ul> <a id="pcm" href="http://www.purecssmenu.com/">CSS Drop Down Menu by PureCSSMenu.com</a> <!-- End PureCSSMenu.com MENU --> thanks in advance for your time.

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  • I dont know how or where to add the correct encoding code to this iPhone code...

    - by BC
    Ok, I understand that using strings that have special characters is an encoding issue. However I am not sure how to adjust my code to allow these characters. Below is the code that works great for text that contains no special characters, but can you show me how and where to change the code to allow for the special characters to be used. Right now those characters crash the app. enter code here - (void)alertView:(UIAlertView *)alertView clickedButtonAtIndex:(NSInteger)buttonIndex{ if (buttonIndex == 1) { //iTunes Audio Search NSString *stringURL = [NSString stringWithFormat:@"http://phobos.apple.com/WebObjects/MZSearch.woa/wa/search?WOURLEncoding=ISO8859_1&lang=1&output=lm&term=\"%@\"",currentSong.title]; stringURL = [stringURL stringByAddingPercentEscapesUsingEncoding:NSASCIIStringEncoding]; NSURL *url = [NSURL URLWithString:stringURL]; [[UIApplication sharedApplication] openURL:url]; } } And this: -(IBAction)launchLyricsSearch:(id)sender{ WebViewController * webView = [[WebViewController alloc] initWithNibName:@"WebViewController" bundle:[NSBundle mainBundle]]; webView.webURL = [NSString stringWithFormat:@"http://www.google.com/m/search?hl=es&q=\"%@\"+letras",currentSong.title]; webView.webTitle = @"Letras"; [self.navigationController pushViewController:webView animated:YES]; } Please show me how and where to do this for these two bits of code.

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  • How to setup Eclipselink with JPA?

    - by deamon
    The Eclipselink documentation says that I need the following entries in my pom.xml to get it with Maven: <dependencies> <dependency> <groupId>org.eclipse.persistence</groupId> <artifactId>eclipselink</artifactId> <version>2.0.0</version> <scope>compile</scope> ... </dependency> <dependencies> ... <repositories> <repository> <id>EclipseLink Repo</id> <url>http://www.eclipse.org/downloads/download.php?r=1&amp;nf=1&amp;file=/rt/eclipselink/maven.repo</url> </repository> ... </repositories> But when I try to use @Entity annotation NetBeans tells me, that the class cannot be found. And indeed: there is no Entity class in the javax.persistence package from Eclipselink. How do I have to setup Eclipselink with Maven?

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  • Error in Getting Youtube Video Title, Description and thumbnail

    - by Muhammad Ayyaz Zafar
    I was getting youtube title and youtube description form the same code but now its not working I am getting following error: Warning: DOMDocument::load() [domdocument.load]: http:// wrapper is disabled in the server configuration by allow_url_fopen=0 in /home/colorsfo/public_html/zaroorat/admin/pages/addSongProcess.php on line 16 Warning: DOMDocument::load(http://gdata.youtube.com/feeds/api/videos/Y7G-tYRzwYY) [domdocument.load]: failed to open stream: no suitable wrapper could be found in /home/colorsfo/public_html/zaroorat/admin/pages/addSongProcess.php on line 16 Warning: DOMDocument::load() [domdocument.load]: I/O warning : failed to load external entity "http://gdata.youtube.com/feeds/api/videos/Y7G-tYRzwYY" in /home/colorsfo/public_html/zaroorat/admin/pages/addSongProcess.php on line 16 .................................... Following Coding is used to get Youtube Video Data: $url = "http://gdata.youtube.com/feeds/api/videos/".$embedCodeParts2[0]; $doc = new DOMDocument; @$doc->load($url); $title = $doc->getElementsByTagName("title")->item(0)->nodeValue; $videoDescription = $doc->getElementsByTagName("description")->item(0)->nodeValue; It was working before (This coding is working fine in Local server but on internet its not working) but now its not working. Please guide me how to fix this error. Thanks for your time.

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