Search Results

Search found 26704 results on 1069 pages for 'row size'.

Page 385/1069 | < Previous Page | 381 382 383 384 385 386 387 388 389 390 391 392  | Next Page >

  • Writing algorithm on 2D data set in plain english

    - by Alexandre P. Levasseur
    I have started an introductory Java class and the material is absolutely horrendous and I have to get excellent grades to be accepted into the master's degree, hence my very beginner question: In my assignment I have to write algorithms (no pseudo-code yet) to solve a board game (Sudoku). Essentially, the notes say that an algorithm is specification of the input(s), the output(s) and the treatments applied to the input to get the output. My question lies on the wording of algorithms because I could probably code it but I can't seem to put it on paper in a coherent way. The game has a 9x9 board and one of the algorithms to write has to find the solution by looking at 3 squares (either horizontal or vertical) and see if one of the three sub-squares match the number you are looking for. If none match then the number you are looking to place is in one of the other 2 set of 3 sub-squares (see image to get a better idea). I really can't get my head around how to formulate the solution into the terms described above or maybe it's just too simple, here's what I was thinking: Input: A 2-dimensional set of data of size 9 by 9 to be solved and a number to search for. Ouput: A 2-dimensional set of data of size 9 by 9 either solved or partially solved. Treatment: Scan each set of 3x9 and 9x3 squares. For each line or column of a 3x3 square check if the number matches a line (or column). If it does then move to the next line (or column). If not then proceed to the next 3x3 square in the same line (or column). Rinse and repeat. Does that make sense as an algorithm written in plain english ? I'm not looking for an answer to the algorithm per se but rather on the formulation of algorithms in plain english.

    Read the article

  • Upon reboot, Linux software raid fails to include one device of a RAID1 array

    - by user1389890
    One of my four Linux software raid arrays drops one of its two devices when I reboot my system. The other three arrays work fine. I am running RAID1 on kernel version 2.6.32-5-amd64 (Debian Squeeze). Every time I reboot, /dev/md2 comes up with only one device. I can manually add the device by saying $ sudo mdadm /dev/md2 --add /dev/sdc1. This works fine, and mdadm confirms that the device has been re-added as follows: mdadm: re-added /dev/sdc1 After adding the device and allowing the array time to resynch, this is what the output of $ cat /proc/mdstat looks like: Personalities : [raid1] md3 : active raid1 sda4[0] sdb4[1] 244186840 blocks super 1.2 [2/2] [UU] md2 : active raid1 sdc1[0] sdd1[1] 732574464 blocks [2/2] [UU] md1 : active raid1 sda3[0] sdb3[1] 722804416 blocks [2/2] [UU] md0 : active raid1 sda1[0] sdb1[1] 6835520 blocks [2/2] [UU] unused devices: <none> Then after I reboot, this is what the output of $ cat /proc/mdstat looks like: Personalities : [raid1] md3 : active raid1 sda4[0] sdb4[1] 244186840 blocks super 1.2 [2/2] [UU] md2 : active raid1 sdd1[1] 732574464 blocks [2/1] [_U] md1 : active raid1 sda3[0] sdb3[1] 722804416 blocks [2/2] [UU] md0 : active raid1 sda1[0] sdb1[1] 6835520 blocks [2/2] [UU] unused devices: <none> During reboot, here is the output of $ sudo cat /var/log/syslog | grep mdadm : Jun 22 19:00:08 rook mdadm[1709]: RebuildFinished event detected on md device /dev/md2 Jun 22 19:00:08 rook mdadm[1709]: SpareActive event detected on md device /dev/md2, component device /dev/sdc1 Jun 22 19:00:20 rook kernel: [ 7819.446412] mdadm: sending ioctl 1261 to a partition! Jun 22 19:00:20 rook kernel: [ 7819.446415] mdadm: sending ioctl 1261 to a partition! Jun 22 19:00:20 rook kernel: [ 7819.446782] mdadm: sending ioctl 1261 to a partition! Jun 22 19:00:20 rook kernel: [ 7819.446785] mdadm: sending ioctl 1261 to a partition! Jun 22 19:00:20 rook kernel: [ 7819.515844] mdadm: sending ioctl 1261 to a partition! Jun 22 19:00:20 rook kernel: [ 7819.515847] mdadm: sending ioctl 1261 to a partition! Jun 22 19:00:20 rook kernel: [ 7819.606829] mdadm: sending ioctl 1261 to a partition! Jun 22 19:00:20 rook kernel: [ 7819.606832] mdadm: sending ioctl 1261 to a partition! Jun 22 19:03:48 rook kernel: [ 8027.855616] mdadm: sending ioctl 1261 to a partition! Jun 22 19:03:48 rook kernel: [ 8027.855620] mdadm: sending ioctl 1261 to a partition! Jun 22 19:03:48 rook kernel: [ 8027.855950] mdadm: sending ioctl 1261 to a partition! Jun 22 19:03:48 rook kernel: [ 8027.855952] mdadm: sending ioctl 1261 to a partition! Jun 22 19:03:49 rook kernel: [ 8027.962169] mdadm: sending ioctl 1261 to a partition! Jun 22 19:03:49 rook kernel: [ 8027.962171] mdadm: sending ioctl 1261 to a partition! Jun 22 19:03:49 rook kernel: [ 8028.054365] mdadm: sending ioctl 1261 to a partition! Jun 22 19:03:49 rook kernel: [ 8028.054368] mdadm: sending ioctl 1261 to a partition! Jun 22 19:10:23 rook kernel: [ 9.588662] mdadm: sending ioctl 1261 to a partition! Jun 22 19:10:23 rook kernel: [ 9.588664] mdadm: sending ioctl 1261 to a partition! Jun 22 19:10:23 rook kernel: [ 9.601990] mdadm: sending ioctl 1261 to a partition! Jun 22 19:10:23 rook kernel: [ 9.601991] mdadm: sending ioctl 1261 to a partition! Jun 22 19:10:23 rook kernel: [ 9.602693] mdadm: sending ioctl 1261 to a partition! Jun 22 19:10:23 rook kernel: [ 9.602695] mdadm: sending ioctl 1261 to a partition! Jun 22 19:10:23 rook kernel: [ 9.605981] mdadm: sending ioctl 1261 to a partition! Jun 22 19:10:23 rook kernel: [ 9.605983] mdadm: sending ioctl 1261 to a partition! Jun 22 19:10:23 rook kernel: [ 9.606138] mdadm: sending ioctl 800c0910 to a partition! Jun 22 19:10:23 rook kernel: [ 9.606139] mdadm: sending ioctl 800c0910 to a partition! Jun 22 19:10:48 rook mdadm[1737]: DegradedArray event detected on md device /dev/md2 Here is the result of $ cat /etc/mdadm/mdadm.conf: ARRAY /dev/md0 metadata=0.90 UUID=92121d42:37f46b82:926983e9:7d8aad9b ARRAY /dev/md1 metadata=0.90 UUID=9c1bafc3:1762d51d:c1ae3c29:66348110 ARRAY /dev/md2 metadata=0.90 UUID=98cea6ca:25b5f305:49e8ec88:e84bc7f0 ARRAY /dev/md3 metadata=1.2 name=rook:3 UUID=ca3fce37:95d49a09:badd0ddc:b63a4792 Here is the output of $ sudo mdadm -E /dev/sdc1 after re-adding the device and letting it resync: /dev/sdc1: Magic : a92b4efc Version : 0.90.00 UUID : 98cea6ca:25b5f305:49e8ec88:e84bc7f0 (local to host rook) Creation Time : Sun Jul 13 08:05:55 2008 Raid Level : raid1 Used Dev Size : 732574464 (698.64 GiB 750.16 GB) Array Size : 732574464 (698.64 GiB 750.16 GB) Raid Devices : 2 Total Devices : 2 Preferred Minor : 2 Update Time : Mon Jun 24 07:42:49 2013 State : clean Active Devices : 2 Working Devices : 2 Failed Devices : 0 Spare Devices : 0 Checksum : 5fd6cc13 - correct Events : 180998 Number Major Minor RaidDevice State this 0 8 33 0 active sync /dev/sdc1 0 0 8 33 0 active sync /dev/sdc1 1 1 8 49 1 active sync /dev/sdd1 Here is the output of $ sudo mdadm -D /dev/md2 after re-adding the device and letting it resync: /dev/md2: Version : 0.90 Creation Time : Sun Jul 13 08:05:55 2008 Raid Level : raid1 Array Size : 732574464 (698.64 GiB 750.16 GB) Used Dev Size : 732574464 (698.64 GiB 750.16 GB) Raid Devices : 2 Total Devices : 2 Preferred Minor : 2 Persistence : Superblock is persistent Update Time : Mon Jun 24 07:42:49 2013 State : clean Active Devices : 2 Working Devices : 2 Failed Devices : 0 Spare Devices : 0 UUID : 98cea6ca:25b5f305:49e8ec88:e84bc7f0 (local to host rook) Events : 0.180998 Number Major Minor RaidDevice State 0 8 33 0 active sync /dev/sdc1 1 8 49 1 active sync /dev/sdd1 I also ran $ sudo smartctl -t long /dev/sdc and no hardware issues were detected. As long as I do not reboot, /dev/md2 seems to work fine. Does anyone have any suggestions?

    Read the article

  • How do you organise the cables in your racks?

    - by Tim
    I'm migrating my current half-size rack to a full-size rack and want to take the opportunity to reorganize and sort our spaghetti-hell of ethernet cables. What system do you use for organising your cables? Do you use any tracking software? Do you physically label the cables? What are you identifying when you label each end? Mac address? Port number? Asset number? What do you use to label them? I was looking at a hand held labeler, but the wrap around laser printer sheets might work. The Brady ID PAL seems good, but it's pricey. Ideas?

    Read the article

  • What will Larry Ellison’s first tweet be about?

    - by Maria Sandu
    Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-family:"Calibri","sans-serif"; mso-ascii- mso-ascii-theme-font:minor-latin; mso-fareast- mso-fareast-theme-font:minor-latin; mso-hansi- mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} Oracle CEO Larry Ellison will send his first tweet Wednesday, June 6. He will announce Oracle’s plans for new cloud-based software products and computing services. Follow @LarryEllison and find out http://twitter.com/larryellison

    Read the article

  • Tokyo Tyrant ulog / update log management.

    - by Nathan Milford
    I'm testing Tokyo Tyrant in a master-master setup and have found the ulog grows out of control and locks up the disk. At first I found the -ulim option useful and limited the logfile size, however it simply rolls over to a new log, leaving the old ones to clutter up the partition. I suppose I'll write a shell script that will delete ulogs older than X, once I find out how far back Tokyo Tyrant needs in the update log in order to failover. Does anyone have any experience with this Tokyo Tyrant? Do you have a feel (acknowledging that every install is different based on what is being stored) for the optimal ulog size vs how far back a Tokyo Tyrant instance needs to look in the ulog to assume master status? Thanks, nathan

    Read the article

  • Standards Corner: OAuth WG Client Registration Problem

    - by Tanu Sood
    Phil Hunt is an active member of multiple industry standards groups and committees (see brief bio at the end of the post) and has spearheaded discussions, creation and ratifications of  Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-family:"Calibri","sans-serif"; mso-ascii- mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi- mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} industry standards including the Kantara Identity Governance Framework, among others. Being an active voice in the industry standards development world, we have invited him to share his discussions, thoughts, news & updates, and discuss use cases, implementation success stories (and even failures) around industry standards on this monthly column. Author: Phil Hunt This afternoon, the OAuth Working Group will meet at IETF88 in Vancouver to discuss some important topics important to the maturation of OAuth. One of them is the OAuth client registration problem.OAuth (RFC6749) was initially developed with a simple deployment model where there is only monopoly or singleton cloud instance of a web API (e.g. there is one Facebook, one Google, on LinkedIn, and so on). When the API publisher and API deployer are the same monolithic entity, it easy for developers to contact the provider and register their app to obtain a client_id and credential.But what happens when the API is for an open source project where there may be 1000s of deployed copies of the API (e.g. such as wordpress). In these cases, the authors of the API are not the people running the API. In these scenarios, how does the developer obtain a client_id? An example of an "open deployed" API is OpenID Connect. Connect defines an OAuth protected resource API that can provide personal information about an authenticated user -- in effect creating a potentially common API for potential identity providers like Facebook, Google, Microsoft, Salesforce, or Oracle. In Oracle's case, Fusion applications will soon have RESTful APIs that are deployed in many different ways in many different environments. How will developers write apps that can work against an openly deployed API with whom the developer can have no prior relationship?At present, the OAuth Working Group has two proposals two consider: Dynamic RegistrationDynamic Registration was originally developed for OpenID Connect and UMA. It defines a RESTful API in which a prospective client application with no client_id creates a new client registration record with a service provider and is issued a client_id and credential along with a registration token that can be used to update registration over time.As proof of success, the OIDC community has done substantial implementation of this spec and feels committed to its use. Why not approve?Well, the answer is that some of us had some concerns, namely: Recognizing instances of software - dynamic registration treats all clients as unique. It has no defined way to recognize that multiple copies of the same client are being registered other then assuming if the registration parameters are similar it might be the same client. Versioning and Policy Approval of open APIs and clients - many service providers have to worry about change management. They expect to have approval cycles that approve versions of server and client software for use in their environment. In some cases approval might be wide open, but in many cases, approval might be down to the specific class of software and version. Registration updates - when does a client actually need to update its registration? Shouldn't it be never? Is there some characteristic of deployed code that would cause it to change? Options lead to complexity - because each client is treated as unique, it becomes unclear how the clients and servers will agree on what credentials forms are acceptable and what OAuth features are allowed and disallowed. Yet the reality is, developers will write their application to work in a limited number of ways. They can't implement all the permutations and combinations that potential service providers might choose. Stateful registration - if the primary motivation for registration is to obtain a client_id and credential, why can't this be done in a stateless fashion using assertions? Denial of service - With so much stateful registration and the need for multiple tokens to be issued, will this not lead to a denial of service attack / risk of resource depletion? At the very least, because of the information gathered, it would difficult for service providers to clean up "failed" registrations and determine active from inactive or false clients. There has yet to be much wide-scale "production" use of dynamic registration other than in small closed communities. Client Association A second proposal, Client Association, has been put forward by Tony Nadalin of Microsoft and myself. We took at look at existing use patterns to come up with a new proposal. At the Berlin meeting, we considered how WS-STS systems work. More recently, I took a review of how mobile messaging clients work. I looked at how Apple, Google, and Microsoft each handle registration with APNS, GCM, and WNS, and a similar pattern emerges. This pattern is to use an existing credential (mutual TLS auth), or client bearer assertion and swap for a device specific bearer assertion.In the client association proposal, the developer's registration with the API publisher is handled by having the developer register with an API publisher (as opposed to the party deploying the API) and obtaining a software "statement". Or, if there is no "publisher" that can sign a statement, the developer may include their own self-asserted software statement.A software statement is a special type of assertion that serves to lock application registration profile information in a signed assertion. The statement is included with the client application and can then be used by the client to swap for an instance specific client assertion as defined by section 4.2 of the OAuth Assertion draft and profiled in the Client Association draft. The software statement provides a way for service provider to recognize and configure policy to approve classes of software clients, and simplifies the actual registration to a simple assertion swap. Because the registration is an assertion swap, registration is no longer "stateful" - meaning the service provider does not need to store any information to support the client (unless it wants to). Has this been implemented yet? Not directly. We've only delivered draft 00 as an alternate way of solving the problem using well-known patterns whose security characteristics and scale characteristics are well understood. Dynamic Take II At roughly the same time that Client Association and Software Statement were published, the authors of Dynamic Registration published a "split" version of the Dynamic Registration (draft-richer-oauth-dyn-reg-core and draft-richer-oauth-dyn-reg-management). While some of the concerns above are addressed, some differences remain. Registration is now a simple POST request. However it defines a new method for issuing client tokens where as Client Association uses RFC6749's existing extension point. The concern here is whether future client access token formats would be addressed properly. Finally, Dyn-reg-core does not yet support software statements. Conclusion The WG has some interesting discussion to bring this back to a single set of specifications. Dynamic Registration has significant implementation, but Client Association could be a much improved way to simplify implementation of the overall OpenID Connect specification and improve adoption. In fairness, the existing editors have already come a long way. Yet there are those with significant investment in the current draft. There are many that have expressed they don't care. They just want a standard. There is lots of pressure on the working group to reach consensus quickly.And that folks is how the sausage is made.Note: John Bradley and Justin Richer recently published draft-bradley-stateless-oauth-client-00 which on first look are getting closer. Some of the details seem less well defined, but the same could be said of client-assoc and software-statement. I hope we can merge these specs this week. Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-family:"Calibri","sans-serif"; mso-ascii- mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi- mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} About the Writer: Phil Hunt joined Oracle as part of the November 2005 acquisition of OctetString Inc. where he headed software development for what is now Oracle Virtual Directory. Since joining Oracle, Phil works as CMTS in the Identity Standards group at Oracle where he developed the Kantara Identity Governance Framework and provided significant input to JSR 351. Phil participates in several standards development organizations such as IETF and OASIS working on federation, authorization (OAuth), and provisioning (SCIM) standards.  Phil blogs at www.independentid.com and a Twitter handle of @independentid.

    Read the article

  • SQL Contest – Win 10 Amazon Gift Cards worth (USD 200) and 10 NuoDB T-Shirts

    - by Pinal Dave
    This month, we have yet not run any contest so we will be running a very interesting contest with the help of good guys at NuoDB. NuoDB has just released version 2.0 and You can download NuoDB from here. NuoDB’s NewSQL distributed database is designed to be a single database that works across multiple servers, which can scale easily, and scale on demand. That’s one system that gives high connectivity but no latency, complexity or maintenance issues. MySQL works in some circumstances, but a period of growth isn’t one of them. So as a company moves forward, the MySQL database can’t keep pace. Data storage and data replication errors creep in. Soon the diaspora of the offices becomes a problem. Your telephone system isn’t just distributed, it is literally all over the place. You can read my detailed article about how Why VoIP Service Providers Should Think About NuoDB’s Geo Distribution. Here is the contest: Contest Part 1: NuoDB R2.0 delivered a long list of improvements and new features. List three of the major features of NuoDB 2.0. Here is the hint1, hint2, hint3. Contest Part 2: Download NuoDB using this link. Once you download NuoDB, leave a comment over here with the name of the platform and installer size. (For example Windows Platform Size abc.dd MB) Here is the what you can win! Giveaways 10 Amazon Gift Card (Each of USD 20 – total USD 200) 10 Amazingly looking NuoDB T-Shirts (For the first 10 downloads) Rules Participate before Oct 28, 2013. All the valid answers will be published after Oct 28, 2013 and winners will receive an email on Nov 1st, 2013. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL Tagged: NuoDB

    Read the article

  • SQL SERVER – What is Fill Factor and What is the Best Value for Fill Factor

    - by pinaldave
    Working in performance tuning area, one has to know about Index and Index Maintenance. For any Index the most important property is Fill Factor. Fill factor is the value that determines the percentage of space on each leaf-level page to be filled with data. In an SQL Server, the smallest unit is a page, which is made of  Page with size 8K. Every page can store one or more rows based on the size of the row. The default value of the Fill Factor is 100, which is same as value 0. The default Fill Factor (100 or 0) will allow the SQL Server to fill the leaf-level pages of an index with the maximum numbers of the rows it can fit. There will be no or very little empty space left in the page, when the fill factor is 100. I have written following two article about Fill Factor. What is Fill factor? – Index, Fill Factor and Performance – Part 1 What is the best value for the Fill Factor? – Index, Fill Factor and Performance – Part 2 I strongly encourage read them and provide your feedback. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Index, SQL Performance, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

    Read the article

  • Free space not reclaimed after online resizing ext4 in Ubuntu 9.10

    - by TiansHUo
    My root partition was filling up, with only 500 mbs left, I wanted to resize my root partition from 20 Gb to 40Gb So I resized my partition by using these steps: Using Gparted to resize another partition to give space for the EXT4 Using fdisk, deleting the root partition (on /dev/sda2), and creating it again using the new size resize2fs /dev/sda2 Updating grub2 But now the problem is that although I can boot in my new partition and the new partition shows it is 40Gb, but the free size was still 500mb. So I booted from a LiveCD and checked with e2fsck -p /dev/sda2, it reported clean. So I added the -f flag (force check), still, the drive is full.

    Read the article

  • Global Cache CR Requested But Current Block Received

    - by Liu Maclean(???)
    ????????«MINSCN?Cache Fusion Read Consistent» ????,???????????? ??????????????????: SQL> select * from V$version; BANNER -------------------------------------------------------------------------------- Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production PL/SQL Release 11.2.0.3.0 - Production CORE 11.2.0.3.0 Production TNS for Linux: Version 11.2.0.3.0 - Production NLSRTL Version 11.2.0.3.0 - Production SQL> select count(*) from gv$instance; COUNT(*) ---------- 2 SQL> select * from global_name; GLOBAL_NAME -------------------------------------------------------------------------------- www.oracledatabase12g.com ?11gR2 2??RAC??????????status???XG,????Xcurrent block???INSTANCE 2?hold?,?????INSTANCE 1?????????,?????: SQL> select * from test; ID ---------- 1 2 SQL> select dbms_rowid.rowid_block_number(rowid),dbms_rowid.rowid_relative_fno(rowid) from test; DBMS_ROWID.ROWID_BLOCK_NUMBER(ROWID) DBMS_ROWID.ROWID_RELATIVE_FNO(ROWID) ------------------------------------ ------------------------------------ 89233 1 89233 1 SQL> alter system flush buffer_cache; System altered. INSTANCE 1 Session A: SQL> update test set id=id+1 where id=1; 1 row updated. INSTANCE 1 Session B: SQL> select state,cr_scn_bas from x$bh where file#=1 and dbablk=89233 and state!=0; STATE CR_SCN_BAS ---------- ---------- 1 0 3 1755287 SQL> oradebug setmypid; Statement processed. SQL> oradebug dump gc_elements 255; Statement processed. SQL> oradebug tracefile_name; /s01/orabase/diag/rdbms/vprod/VPROD1/trace/VPROD1_ora_19111.trc GLOBAL CACHE ELEMENT DUMP (address: 0xa4ff3080): id1: 0x15c91 id2: 0x1 pkey: OBJ#76896 block: (1/89233) lock: X rls: 0x0 acq: 0x0 latch: 3 flags: 0x20 fair: 0 recovery: 0 fpin: 'kdswh11: kdst_fetch' bscn: 0x0.146e20 bctx: (nil) write: 0 scan: 0x0 lcp: (nil) lnk: [NULL] lch: [0xa9f6a6f8,0xa9f6a6f8] seq: 32 hist: 58 145:0 118 66 144:0 192 352 197 48 121 113 424 180 58 LIST OF BUFFERS LINKED TO THIS GLOBAL CACHE ELEMENT: flg: 0x02000001 lflg: 0x1 state: XCURRENT tsn: 0 tsh: 2 addr: 0xa9f6a5c8 obj: 76896 cls: DATA bscn: 0x0.1ac898 BH (0xa9f6a5c8) file#: 1 rdba: 0x00415c91 (1/89233) class: 1 ba: 0xa9e56000 set: 5 pool: 3 bsz: 8192 bsi: 0 sflg: 3 pwc: 0,15 dbwrid: 0 obj: 76896 objn: 76896 tsn: 0 afn: 1 hint: f hash: [0x91f4e970,0xbae9d5b8] lru: [0x91f58848,0xa9f6a828] lru-flags: debug_dump obj-flags: object_ckpt_list ckptq: [0x9df6d1d8,0xa9f6a740] fileq: [0xa2ece670,0xbdf4ed68] objq: [0xb4964e00,0xb4964e00] objaq: [0xb4964de0,0xb4964de0] st: XCURRENT md: NULL fpin: 'kdswh11: kdst_fetch' tch: 2 le: 0xa4ff3080 flags: buffer_dirty redo_since_read LRBA: [0x19.5671.0] LSCN: [0x0.1ac898] HSCN: [0x0.1ac898] HSUB: [1] buffer tsn: 0 rdba: 0x00415c91 (1/89233) scn: 0x0000.001ac898 seq: 0x01 flg: 0x00 tail: 0xc8980601 frmt: 0x02 chkval: 0x0000 type: 0x06=trans data ??????block: (1/89233)?GLOBAL CACHE ELEMENT DUMP?LOCK????X ??XG , ??????Current Block????Instance??modify???,????????????? ????Instance 2 ????: Instance 2 Session C: SQL> update test set id=id+1 where id=2; 1 row updated. Instance 2 Session D: SQL> select state,cr_scn_bas from x$bh where file#=1 and dbablk=89233 and state!=0; STATE CR_SCN_BAS ---------- ---------- 1 0 3 1756658 SQL> oradebug setmypid; Statement processed. SQL> oradebug dump gc_elements 255; Statement processed. SQL> oradebug tracefile_name; /s01/orabase/diag/rdbms/vprod/VPROD2/trace/VPROD2_ora_13038.trc GLOBAL CACHE ELEMENT DUMP (address: 0x89fb25a0): id1: 0x15c91 id2: 0x1 pkey: OBJ#76896 block: (1/89233) lock: XG rls: 0x0 acq: 0x0 latch: 3 flags: 0x20 fair: 0 recovery: 0 fpin: 'kduwh01: kdusru' bscn: 0x0.1acdf3 bctx: (nil) write: 0 scan: 0x0 lcp: (nil) lnk: [NULL] lch: [0x96f4cf80,0x96f4cf80] seq: 61 hist: 324 21 143:0 19 16 352 329 144:6 14 7 352 197 LIST OF BUFFERS LINKED TO THIS GLOBAL CACHE ELEMENT: flg: 0x0a000001 state: XCURRENT tsn: 0 tsh: 1 addr: 0x96f4ce50 obj: 76896 cls: DATA bscn: 0x0.1acdf6 BH (0x96f4ce50) file#: 1 rdba: 0x00415c91 (1/89233) class: 1 ba: 0x96bd4000 set: 5 pool: 3 bsz: 8192 bsi: 0 sflg: 2 pwc: 0,15 dbwrid: 0 obj: 76896 objn: 76896 tsn: 0 afn: 1 hint: f hash: [0x96ee1fe8,0xbae9d5b8] lru: [0x96f4d0b0,0x96f4cdc0] obj-flags: object_ckpt_list ckptq: [0xbdf519b8,0x96f4d5a8] fileq: [0xbdf519d8,0xbdf519d8] objq: [0xb4a47b90,0xb4a47b90] objaq: [0x96f4d0e8,0xb4a47b70] st: XCURRENT md: NULL fpin: 'kduwh01: kdusru' tch: 1 le: 0x89fb25a0 flags: buffer_dirty redo_since_read remote_transfered LRBA: [0x11.9e18.0] LSCN: [0x0.1acdf6] HSCN: [0x0.1acdf6] HSUB: [1] buffer tsn: 0 rdba: 0x00415c91 (1/89233) scn: 0x0000.001acdf6 seq: 0x01 flg: 0x00 tail: 0xcdf60601 frmt: 0x02 chkval: 0x0000 type: 0x06=trans data GCS CLIENT 0x89fb2618,6 resp[(nil),0x15c91.1] pkey 76896.0 grant 2 cvt 0 mdrole 0x42 st 0x100 lst 0x20 GRANTQ rl G0 master 1 owner 2 sid 0 remote[(nil),0] hist 0x94121c601163423c history 0x3c.0x4.0xd.0xb.0x1.0xc.0x7.0x9.0x14.0x1. cflag 0x0 sender 1 flags 0x0 replay# 0 abast (nil).x0.1 dbmap (nil) disk: 0x0000.00000000 write request: 0x0000.00000000 pi scn: 0x0000.00000000 sq[(nil),(nil)] msgseq 0x1 updseq 0x0 reqids[6,0,0] infop (nil) lockseq x2b8 pkey 76896.0 hv 93 [stat 0x0, 1->1, wm 32768, RMno 0, reminc 18, dom 0] kjga st 0x4, step 0.0.0, cinc 20, rmno 6, flags 0x0 lb 0, hb 0, myb 15250, drmb 15250, apifrz 0 ?Instance 2??????block: (1/89233)? GLOBAL CACHE ELEMENT Lock Convert?lock: XG ????GC_ELEMENTS DUMP???XCUR Cache Fusion?,???????X$ VIEW,??? X$LE X$KJBR X$KJBL, ???X$ VIEW???????????????????: INSTANCE 2 Session D: SELECT * FROM x$le WHERE le_addr IN (SELECT le_addr FROM x$bh WHERE obj IN (SELECT data_object_id FROM dba_objects WHERE owner = 'SYS' AND object_name = 'TEST') AND class = 1 AND state != 3); ADDR INDX INST_ID LE_ADDR LE_ID1 LE_ID2 ---------------- ---------- ---------- ---------------- ---------- ---------- LE_RLS LE_ACQ LE_FLAGS LE_MODE LE_WRITE LE_LOCAL LE_RECOVERY ---------- ---------- ---------- ---------- ---------- ---------- ----------- LE_BLKS LE_TIME LE_KJBL ---------- ---------- ---------------- 00007F94CA14CF60 7003 2 0000000089FB25A0 89233 1 0 0 32 2 0 1 0 1 0 0000000089FB2618 PCM Resource NAME?[ID1][ID2],[BL]???, ID1?ID2 ??blockno? fileno????, ??????????GC_elements dump?? id1: 0x15c91 id2: 0×1 pkey: OBJ#76896 block: (1/89233)?? ,?  kjblname ? kjbrname ??”[0x15c91][0x1],[BL]” ??: INSTANCE 2 Session D: SQL> set linesize 80 pagesize 1400 SQL> SELECT * 2 FROM x$kjbl l 3 WHERE l.kjblname LIKE '%[0x15c91][0x1],[BL]%'; ADDR INDX INST_ID KJBLLOCKP KJBLGRANT KJBLREQUE ---------------- ---------- ---------- ---------------- --------- --------- KJBLROLE KJBLRESP KJBLNAME ---------- ---------------- ------------------------------ KJBLNAME2 KJBLQUEUE ------------------------------ ---------- KJBLLOCKST KJBLWRITING ---------------------------------------------------------------- ----------- KJBLREQWRITE KJBLOWNER KJBLMASTER KJBLBLOCKED KJBLBLOCKER KJBLSID KJBLRDOMID ------------ ---------- ---------- ----------- ----------- ---------- ---------- KJBLPKEY ---------- 00007F94CA22A288 451 2 0000000089FB2618 KJUSEREX KJUSERNL 0 00 [0x15c91][0x1],[BL][ext 0x0,0x 89233,1,BL 0 GRANTED 0 0 1 0 0 0 0 0 76896 SQL> SELECT r.* FROM x$kjbr r WHERE r.kjbrname LIKE '%[0x15c91][0x1],[BL]%'; no rows selected Instance 1 session B: SQL> SELECT r.* FROM x$kjbr r WHERE r.kjbrname LIKE '%[0x15c91][0x1],[BL]%'; ADDR INDX INST_ID KJBRRESP KJBRGRANT KJBRNCVL ---------------- ---------- ---------- ---------------- --------- --------- KJBRROLE KJBRNAME KJBRMASTER KJBRGRANTQ ---------- ------------------------------ ---------- ---------------- KJBRCVTQ KJBRWRITER KJBRSID KJBRRDOMID KJBRPKEY ---------------- ---------------- ---------- ---------- ---------- 00007F801ACA68F8 1355 1 00000000B5A62AE0 KJUSEREX KJUSERNL 0 [0x15c91][0x1],[BL][ext 0x0,0x 0 00000000B48BB330 00 00 0 0 76896 ??????Instance 1???block: (1/89233),??????Instance 2 build cr block ????Instance 1, ?????????? ????? Instance 1? Foreground Process ? Instance 2?LMS??????RAC  TRACE: Instance 2: [oracle@vrh2 ~]$ ps -ef|grep ora_lms|grep -v grep oracle 23364 1 0 Apr29 ? 00:33:15 ora_lms0_VPROD2 SQL> oradebug setospid 23364 Oracle pid: 13, Unix process pid: 23364, image: [email protected] (LMS0) SQL> oradebug event 10046 trace name context forever,level 8:10708 trace name context forever,level 103: trace[rac.*] disk high; Statement processed. SQL> oradebug tracefile_name /s01/orabase/diag/rdbms/vprod/VPROD2/trace/VPROD2_lms0_23364.trc Instance 1 session B : SQL> select state,cr_scn_bas from x$bh where file#=1 and dbablk=89233 and state!=0; STATE CR_SCN_BAS ---------- ---------- 3 1756658 3 1756661 3 1755287 Instance 1 session A : SQL> alter session set events '10046 trace name context forever,level 8:10708 trace name context forever,level 103: trace[rac.*] disk high'; Session altered. SQL> select * from test; ID ---------- 2 2 SQL> select state,cr_scn_bas from x$bh where file#=1 and dbablk=89233 and state!=0; STATE CR_SCN_BAS ---------- ---------- 3 1761520 ?x$BH?????,???????Instance 1???build??CR block,????? TRACE ??: Instance 1 foreground Process: PARSING IN CURSOR #140336527348792 len=18 dep=0 uid=0 oct=3 lid=0 tim=1335939136125254 hv=1689401402 ad='b1a4c828' sqlid='c99yw1xkb4f1u' select * from test END OF STMT PARSE #140336527348792:c=2999,e=2860,p=0,cr=0,cu=0,mis=1,r=0,dep=0,og=1,plh=1357081020,tim=1335939136125253 EXEC #140336527348792:c=0,e=40,p=0,cr=0,cu=0,mis=0,r=0,dep=0,og=1,plh=1357081020,tim=1335939136125373 WAIT #140336527348792: nam='SQL*Net message to client' ela= 6 driver id=1650815232 #bytes=1 p3=0 obj#=0 tim=1335939136125420 *** 2012-05-02 02:12:16.125 kclscrs: req=0 block=1/89233 2012-05-02 02:12:16.125574 : kjbcro[0x15c91.1 76896.0][4] *** 2012-05-02 02:12:16.125 kclscrs: req=0 typ=nowait-abort *** 2012-05-02 02:12:16.125 kclscrs: bid=1:3:1:0:f:1e:0:0:10:0:0:0:1:2:4:1:20:0:0:0:c3:49:0:0:0:0:0:0:0:0:0:0:0:0:0:0:0:0:0:0:4:3:2:1:2:0:1c:0:4d:26:a3:52:0:0:0:0:c7:c:ca:62:c3:49:0:0:0:0:1:0:14:8e:47:76:1:2:dc:5:a9:fe:17:75:0:0:0:0:0:0:0:0:0:0:0:0:99:ed:0:0:0:0:0:0:10:0:0:0 2012-05-02 02:12:16.125718 : kjbcro[0x15c91.1 76896.0][4] 2012-05-02 02:12:16.125751 : GSIPC:GMBQ: buff 0xba0ee018, queue 0xbb79a7b8, pool 0x60013fa0, freeq 0, nxt 0xbb79a7b8, prv 0xbb79a7b8 2012-05-02 02:12:16.125780 : kjbsentscn[0x0.1ae0f0][to 2] 2012-05-02 02:12:16.125806 : GSIPC:SENDM: send msg 0xba0ee088 dest x20001 seq 177740 type 36 tkts xff0000 mlen x1680198 2012-05-02 02:12:16.125918 : kjbmscr(0x15c91.1)reqid=0x8(req 0xa4ff30f8)(rinst 1)hldr 2(infosz 200)(lseq x2b8) 2012-05-02 02:12:16.126959 : GSIPC:KSXPCB: msg 0xba0ee088 status 30, type 36, dest 2, rcvr 1 *** 2012-05-02 02:12:16.127 kclwcrs: wait=0 tm=1233 *** 2012-05-02 02:12:16.127 kclwcrs: got 1 blocks from ksxprcv WAIT #140336527348792: nam='gc cr block 2-way' ela= 1233 p1=1 p2=89233 p3=1 obj#=76896 tim=1335939136127199 2012-05-02 02:12:16.127272 : kjbcrcomplete[0x15c91.1 76896.0][0] 2012-05-02 02:12:16.127309 : kjbrcvdscn[0x0.1ae0f0][from 2][idx 2012-05-02 02:12:16.127329 : kjbrcvdscn[no bscn <= rscn 0x0.1ae0f0][from 2] ???? kjbcro[0x15c91.1 76896.0][4] kjbsentscn[0x0.1ae0f0][to 2] ?Instance 2??SCN=1ae0f0=1761520? block: (1/89233),???’gc cr block 2-way’ ??,?????????CR block? Instance 2 LMS TRACE 2012-05-02 02:12:15.634057 : GSIPC:RCVD: ksxp msg 0x7f16e1598588 sndr 1 seq 0.177740 type 36 tkts 0 2012-05-02 02:12:15.634094 : GSIPC:RCVD: watq msg 0x7f16e1598588 sndr 1, seq 177740, type 36, tkts 0 2012-05-02 02:12:15.634108 : GSIPC:TKT: collect msg 0x7f16e1598588 from 1 for rcvr -1, tickets 0 2012-05-02 02:12:15.634162 : kjbrcvdscn[0x0.1ae0f0][from 1][idx 2012-05-02 02:12:15.634186 : kjbrcvdscn[no bscn1, wm 32768, RMno 0, reminc 18, dom 0] kjga st 0x4, step 0.0.0, cinc 20, rmno 6, flags 0x0 lb 0, hb 0, myb 15250, drmb 15250, apifrz 0 GCS CLIENT END 2012-05-02 02:12:15.635211 : kjbdowncvt[0x15c91.1 76896.0][1][options x0] 2012-05-02 02:12:15.635230 : GSIPC:AMBUF: rcv buff 0x7f16e1c56420, pool rcvbuf, rqlen 1103 2012-05-02 02:12:15.635308 : GSIPC:GPBMSG: new bmsg 0x7f16e1c56490 mb 0x7f16e1c56420 msg 0x7f16e1c564b0 mlen 152 dest x101 flushsz -1 2012-05-02 02:12:15.635334 : kjbmslset(0x15c91.1)) seq 0x4 reqid=0x6 (shadow 0xb48bb330.xb)(rsn 2)(mas@1) 2012-05-02 02:12:15.635355 : GSIPC:SPBMSG: send bmsg 0x7f16e1c56490 blen 184 msg 0x7f16e1c564b0 mtype 33 attr|dest x30101 bsz|fsz x1ffff 2012-05-02 02:12:15.635377 : GSIPC:SNDQ: enq msg 0x7f16e1c56490, type 65521 seq 118669, inst 1, receiver 1, queued 1 *** 2012-05-02 02:12:15.635 kclccctx: cleanup copy 0x7f16e1d94798 2012-05-02 02:12:15.635479 : [kjmpmsgi:compl][type 36][msg 0x7f16e1598588][seq 177740.0][qtime 0][ptime 1257] 2012-05-02 02:12:15.635511 : GSIPC:BSEND: flushing sndq 0xb491dd28, id 1, dcx 0xbc516778, inst 1, rcvr 1 qlen 0 1 2012-05-02 02:12:15.635536 : GSIPC:BSEND: no batch1 msg 0x7f16e1c56490 type 65521 len 184 dest (1:1) 2012-05-02 02:12:15.635557 : kjbsentscn[0x0.1ae0f1][to 1] 2012-05-02 02:12:15.635578 : GSIPC:SENDM: send msg 0x7f16e1c56490 dest x10001 seq 118669 type 65521 tkts x10002 mlen xb800e8 WAIT #0: nam='gcs remote message' ela= 180 waittime=1 poll=0 event=0 obj#=0 tim=1335939135635819 2012-05-02 02:12:15.635853 : GSIPC:RCVD: ksxp msg 0x7f16e167e0b0 sndr 1 seq 0.177741 type 32 tkts 0 2012-05-02 02:12:15.635875 : GSIPC:RCVD: watq msg 0x7f16e167e0b0 sndr 1, seq 177741, type 32, tkts 0 2012-05-02 02:12:15.636012 : GSIPC:TKT: collect msg 0x7f16e167e0b0 from 1 for rcvr -1, tickets 0 2012-05-02 02:12:15.636040 : kjbrcvdscn[0x0.1ae0f1][from 1][idx 2012-05-02 02:12:15.636060 : kjbrcvdscn[no bscn <= rscn 0x0.1ae0f1][from 1] 2012-05-02 02:12:15.636082 : GSIPC:TKT: dest (1:1) rtkt not acked 1  unassigned bufs 0  tkts 0  newbufs 0 2012-05-02 02:12:15.636102 : GSIPC:TKT: remove ctx dest (1:1) 2012-05-02 02:12:15.636125 : [kjmxmpm][type 32][seq 0.177741][msg 0x7f16e167e0b0][from 1] 2012-05-02 02:12:15.636146 : kjbmpocr(0xb0.6)seq 0x1,reqid=0x23a,(client 0x9fff7b58,0x1)(from 1)(lseq xdf0) 2????LMS????????? ??gcs remote message GSIPC ????SCN=[0x0.1ae0f0] block=1/89233???,??BAST kjbmpbast(0x15c91.1),?? block=1/89233??????? ??fairness??(?11.2.0.3???_fairness_threshold=2),?current block?KCL: F156: fairness downconvert,?Xcurrent DownConvert? Scurrent: Instance 2: SQL> select state,cr_scn_bas from x$bh where file#=1 and dbablk=89233 and state!=0; STATE CR_SCN_BAS ---------- ---------- 2 0 3 1756658 ??Instance 2 LMS ?cr block??? kjbmslset(0x15c91.1)) ????SEND QUEUE GSIPC:SNDQ: enq msg 0x7f16e1c56490? ???????Instance 1???? block: (1/89233)??? ??????: Instance 2: SQL> select CURRENT_RESULTS,LIGHT_WORKS from v$cr_block_server; CURRENT_RESULTS LIGHT_WORKS --------------- ----------- 29273 437 Instance 1 session A: SQL> SQL> select * from test; ID ---------- 2 2 SQL> select state,cr_scn_bas from x$bh where file#=1 and dbablk=89233 and state!=0; STATE CR_SCN_BAS ---------- ---------- 3 1761942 3 1761932 1 0 3 1761520 Instance 2: SQL> select CURRENT_RESULTS,LIGHT_WORKS from v$cr_block_server; CURRENT_RESULTS LIGHT_WORKS --------------- ----------- 29274 437 select * from test END OF STMT PARSE #140336529675592:c=0,e=337,p=0,cr=0,cu=0,mis=0,r=0,dep=0,og=1,plh=1357081020,tim=1335939668940051 EXEC #140336529675592:c=0,e=96,p=0,cr=0,cu=0,mis=0,r=0,dep=0,og=1,plh=1357081020,tim=1335939668940204 WAIT #140336529675592: nam='SQL*Net message to client' ela= 5 driver id=1650815232 #bytes=1 p3=0 obj#=0 tim=1335939668940348 *** 2012-05-02 02:21:08.940 kclscrs: req=0 block=1/89233 2012-05-02 02:21:08.940676 : kjbcro[0x15c91.1 76896.0][5] *** 2012-05-02 02:21:08.940 kclscrs: req=0 typ=nowait-abort *** 2012-05-02 02:21:08.940 kclscrs: bid=1:3:1:0:f:21:0:0:10:0:0:0:1:2:4:1:20:0:0:0:c3:49:0:0:0:0:0:0:0:0:0:0:0:0:0:0:0:0:0:0:4:3:2:1:2:0:1f:0:4d:26:a3:52:0:0:0:0:c7:c:ca:62:c3:49:0:0:0:0:1:0:17:8e:47:76:1:2:dc:5:a9:fe:17:75:0:0:0:0:0:0:0:0:0:0:0:0:99:ed:0:0:0:0:0:0:10:0:0:0 2012-05-02 02:21:08.940799 : kjbcro[0x15c91.1 76896.0][5] 2012-05-02 02:21:08.940833 : GSIPC:GMBQ: buff 0xba0ee018, queue 0xbb79a7b8, pool 0x60013fa0, freeq 0, nxt 0xbb79a7b8, prv 0xbb79a7b8 2012-05-02 02:21:08.940859 : kjbsentscn[0x0.1ae28c][to 2] 2012-05-02 02:21:08.940870 : GSIPC:SENDM: send msg 0xba0ee088 dest x20001 seq 177810 type 36 tkts xff0000 mlen x1680198 2012-05-02 02:21:08.940976 : kjbmscr(0x15c91.1)reqid=0xa(req 0xa4ff30f8)(rinst 1)hldr 2(infosz 200)(lseq x2b8) 2012-05-02 02:21:08.941314 : GSIPC:KSXPCB: msg 0xba0ee088 status 30, type 36, dest 2, rcvr 1 *** 2012-05-02 02:21:08.941 kclwcrs: wait=0 tm=707 *** 2012-05-02 02:21:08.941 kclwcrs: got 1 blocks from ksxprcv 2012-05-02 02:21:08.941818 : kjbassume[0x15c91.1][sender 2][mymode x1][myrole x0][srole x0][flgs x0][spiscn 0x0.0][swscn 0x0.0] 2012-05-02 02:21:08.941852 : kjbrcvdscn[0x0.1ae28d][from 2][idx 2012-05-02 02:21:08.941871 : kjbrcvdscn[no bscn ??????????????SCN=[0x0.1ae28c]=1761932 Version?CR block, ????receive????Xcurrent Block??SCN=1ae28d=1761933,Instance 1???Xcurrent Block???build????????SCN=1761932?CR BLOCK, ????????Current block,?????????'gc current block 2-way'? ?????????????request current block,?????kjbcro;?????Instance 2?LMS???????Current Block: Instance 2 LMS trace: 2012-05-02 02:21:08.448743 : GSIPC:RCVD: ksxp msg 0x7f16e14a4398 sndr 1 seq 0.177810 type 36 tkts 0 2012-05-02 02:21:08.448778 : GSIPC:RCVD: watq msg 0x7f16e14a4398 sndr 1, seq 177810, type 36, tkts 0 2012-05-02 02:21:08.448798 : GSIPC:TKT: collect msg 0x7f16e14a4398 from 1 for rcvr -1, tickets 0 2012-05-02 02:21:08.448816 : kjbrcvdscn[0x0.1ae28c][from 1][idx 2012-05-02 02:21:08.448834 : kjbrcvdscn[no bscn <= rscn 0x0.1ae28c][from 1] 2012-05-02 02:21:08.448857 : GSIPC:TKT: dest (1:1) rtkt not acked 2  unassigned bufs 0  tkts 0  newbufs 0 2012-05-02 02:21:08.448875 : GSIPC:TKT: remove ctx dest (1:1) 2012-05-02 02:21:08.448970 : [kjmxmpm][type 36][seq 0.177810][msg 0x7f16e14a4398][from 1] 2012-05-02 02:21:08.448993 : kjbmpbast(0x15c91.1) reqid=0x6 (req 0xa4ff30f8)(reqinst 1)(reqid 10)(flags x0) *** 2012-05-02 02:21:08.449 kclcrrf: req=48054 block=1/89233 *** 2012-05-02 02:21:08.449 kcl_compress_block: compressed: 6 free space: 7680 2012-05-02 02:21:08.449085 : kjbsentscn[0x0.1ae28d][to 1] 2012-05-02 02:21:08.449142 : kjbdeliver[to 1][0xa4ff30f8][10][current 1] 2012-05-02 02:21:08.449164 : kjbmssch(reqlock 0xa4ff30f8,10)(to 1)(bsz 344) 2012-05-02 02:21:08.449183 : GSIPC:AMBUF: rcv buff 0x7f16e18bcec8, pool rcvbuf, rqlen 1102 *** 2012-05-02 02:21:08.449 kclccctx: cleanup copy 0x7f16e1d94838 *** 2012-05-02 02:21:08.449 kcltouched: touch seconds 3271 *** 2012-05-02 02:21:08.449 kclgrantlk: req=48054 2012-05-02 02:21:08.449347 : [kjmpmsgi:compl][type 36][msg 0x7f16e14a4398][seq 177810.0][qtime 0][ptime 1119] WAIT #0: nam='gcs remote message' ela= 568 waittime=1 poll=0 event=0 obj#=0 tim=1335939668449962 2012-05-02 02:21:08.450001 : GSIPC:RCVD: ksxp msg 0x7f16e1bb22a0 sndr 1 seq 0.177811 type 32 tkts 0 2012-05-02 02:21:08.450024 : GSIPC:RCVD: watq msg 0x7f16e1bb22a0 sndr 1, seq 177811, type 32, tkts 0 2012-05-02 02:21:08.450043 : GSIPC:TKT: collect msg 0x7f16e1bb22a0 from 1 for rcvr -1, tickets 0 2012-05-02 02:21:08.450060 : kjbrcvdscn[0x0.1ae28e][from 1][idx 2012-05-02 02:21:08.450078 : kjbrcvdscn[no bscn <= rscn 0x0.1ae28e][from 1] 2012-05-02 02:21:08.450097 : GSIPC:TKT: dest (1:1) rtkt not acked 3  unassigned bufs 0  tkts 0  newbufs 0 2012-05-02 02:21:08.450116 : GSIPC:TKT: remove ctx dest (1:1) 2012-05-02 02:21:08.450136 : [kjmxmpm][type 32][seq 0.177811][msg 0x7f16e1bb22a0][from 1] 2012-05-02 02:21:08.450155 : kjbmpocr(0xb0.6)seq 0x1,reqid=0x23e,(client 0x9fff7b58,0x1)(from 1)(lseq xdf4) ???Instance 2??LMS???,???build cr block,??????Instance 1?????Current Block??????Instance 2??v$cr_block_server??????LIGHT_WORKS?????current block transfer??????,??????? CR server? Light Work Rule(Light Work Rule?8i Cr Server?????????,?Remote LMS?? build CR????????,resource holder?LMS???????block,????CR build If creating the consistent read version block involves too much work (such as reading blocks from disk), then the holder sends the block to the requestor, and the requestor completes the CR fabrication. The holder maintains a fairness counter of CR requests. After the fairness threshold is reached, the holder downgrades it to lock mode.)? ??????? CR Request ????Current Block?? ???:??????class?block,CR server??????? ??undo block?? undo header block?CR quest, LMS????Current Block, ????? ???? ??????? block cleanout? CR  Version??????? ???????? data blocks, ??????? CR quest  & CR received?(???????Light Work Rule,LMS"??"), ??Current Block??DownConvert???S lock,??LMS???????ship??current version?block? ??????? , ?????? ,???????DownConvert?????”_fairness_threshold“???200,????Xcurrent Block?????Scurrent, ????LMS?????Current Version?Data Block: SQL> show parameter fair NAME TYPE VALUE ------------------------------------ ----------- ------------------------------ _fairness_threshold integer 200 Instance 1: SQL> update test set id=id+1 where id=4; 1 row updated. Instance 2: SQL> update test set id=id+1 where id=2; 1 row updated. SQL> select state,cr_scn_bas from x$bh where file#=1 and dbablk=89233 and state!=0; STATE CR_SCN_BAS ---------- ---------- 1 0 3 1838166 ?Instance 1? ????,? ??instance 2? v$cr_block_server?? instance 1 SQL> select * from test; ID ---------- 10 3 instance 2: SQL> select state,cr_scn_bas from x$bh where file#=1 and dbablk=89233 and state!=0; STATE CR_SCN_BAS ---------- ---------- 1 0 3 1883707 8 0 SQL> select * from test; ID ---------- 10 3 SQL> select state,cr_scn_bas from x$bh where file#=1 and dbablk=89233 and state!=0; STATE CR_SCN_BAS ---------- ---------- 1 0 3 1883707 8 0 ................... SQL> / STATE CR_SCN_BAS ---------- ---------- 2 0 3 1883707 3 1883695 repeat cr request on Instance 1 SQL> / STATE CR_SCN_BAS ---------- ---------- 8 0 3 1883707 3 1883695 ??????_fairness_threshold????????,?????200 ????????CR serve??Downgrade?lock, ????data block? CR Request????Receive? Current Block?

    Read the article

  • What's new in ASP.Net 4.5 and VS 2012 - part 1

    - by nikolaosk
    I have downloaded .Net framework 4.5 and Visual Studio 2012 since it was released to MSDN subscribers on the 15th of August.For people that do not know about that yet please have a look at Jason Zander's excellent blog post .Since then I have been investigating the many new features that have been introduced in this release.In this post I will be looking into new features available in ASP.Net 4.5 and VS 2012.In order to follow along this post you must have Visual Studio 2012 and .Net Framework 4.5 installed in your machine.Download and install VS 2012 using this link.My machine runs on Windows 8 and Visual Studio 2012 works just fine. Please find all my posts regarding VS 2012, here .Well I have not exactly kept my promise for writing short blog posts, so I will try to keep this one short. 1) Launch VS 2012 and create a new Web Forms application by going to File - >New Web Site - > ASP.Net Web Forms Site.2) Choose an appropriate name for your web site.3) Build and run your site (CTRL+F5). Then go to View - > Source to see the HTML markup (Javascript e.t.c) that is rendered through the browser.You will see that the ASP.Net team has done a good job to make the markup cleaner and more readable. The ViewState size is significantly smaller compared to its size to earlier versions.Have a look at the picture below 4) Another thing that you must notice is that the new template makes good use of HTML 5 elements.When you view the application through the browser and then go to View Page Source you will see HTML 5 elements like nav,header,section.Have a look at the picture below  5) In VS 2012 we can browse with multiple browsers. There is a very handy dropdown that shows all the browsers available for viewing the website.Have a look at the picture below When I select the option Browse With... I see another window and I can select any of the installed browsers I want and also set the default browser. Have a look at the picture below  When I click Browse, all the selected browsers fire up and I can view the website in all of them.Have a look at the picture below There will be more posts soon looking into new features of ASP.Net 4.5 and VS 2012Hope it helps!!!

    Read the article

  • Cannot create file in directory even though it's writable by a group I belong to

    - by Alan Berndt
    I have a directory structure owned by a certain group, and I am a member of the group that owns these directories. I am able to create files in one directory, but not in another, even though the permissions are the same. alan@bricky:/mnt/storage/media$ stat Music Music\ \(Lossy\)/ File: `Music' Size: 34 Blocks: 8 IO Block: 4096 directory Device: fb00h/64256d Inode: 4215424 Links: 3 Access: (2775/drwxrwsr-x) Uid: ( 1001/ media) Gid: ( 1001/ media) Access: 2011-08-19 11:45:03.182586898 -0700 Modify: 2011-08-19 11:44:01.412840027 -0700 Change: 2011-08-19 11:45:02.734603240 -0700 File: `Music (Lossy)/' Size: 6 Blocks: 8 IO Block: 4096 directory Device: fb00h/64256d Inode: 1512056832 Links: 2 Access: (2775/drwxrwsr-x) Uid: ( 1001/ media) Gid: ( 1001/ media) Access: 2011-08-19 11:45:03.190586606 -0700 Modify: 2011-08-19 10:34:46.526530313 -0700 Change: 2011-08-19 11:45:02.738603094 -0700 alan@bricky:/mnt/storage/media$ touch Music/test alan@bricky:/mnt/storage/media$ touch Music\ \(Lossy\)/test touch: cannot touch `Music (Lossy)/test': Permission denied

    Read the article

  • AutoAudit 1.10c

    - by Paul Nielsen
    AutoAudit is a free SQL Server (2005, 2008) Code-Gen utility that creates Audit Trail Triggers with: · Created, Modified, and RowVersion (incrementing INT) columns to table · Creates View to reconstruct deleted rows · Creates UDF to reconstruct Row History · Schema Audit Trigger to track schema changes · Re-code-gens triggers when Alter Table changes the table Version 1.10c Adds: · Createdby and ModifiedBy columns. Pass the user to the column and AutoAudit records that username instead of the Suser_Sname...(read more)

    Read the article

  • Rotate screen using xrandr on Solaris 10

    - by sixtyfootersdude
    How do I call the xrandr command? I want to rotate my screen 90 deg. clockwise. Here is the usage: % xrandr -help usage: xrandr [options] where options are: -display <display> or -d <display> -help -o <normal,inverted,left,right,0,1,2,3> or --orientation <normal,inverted,left,right,0,1,2,3> -q or --query -s <size>/<width>x<height> or --size <size>/<width>x<height> -r <rate> or --rate <rate> or --refresh <rate> -v or --version -x (reflect in x) -y (reflect in y) --screen <screen> --verbose --dryrun --prop or --properties --fb <width>x<height> --fbmm <width>x<height> --dpi <dpi>/<output> --output <output> --auto --mode <mode> --preferred --pos <x>x<y> --rate <rate> or --refresh <rate> --reflect normal,x,y,xy --rotate normal,inverted,left,right --left-of <output> --right-of <output> --above <output> --below <output> --same-as <output> --set <property> <value> --off --crtc <crtc> --newmode <name> <clock MHz> <hdisp> <hsync-start> <hsync-end> <htotal> <vdisp> <vsync-start> <vsync-end> <vtotal> [+HSync] [-HSync] [+VSync] [-VSync] --rmmode <name> --addmode <output> <name> --delmode <output> <name> This is what I tried: % xrandr -o left X Error of failed request: BadMatch (invalid parameter attributes) Major opcode of failed request: 159 (RANDR) Minor opcode of failed request: 2 () Serial number of failed request: 16 Current serial number in output stream: 16 I am running Solaris 10.

    Read the article

  • How can I create a 4TB partition on my software RAID5 device?

    - by Kris Harper
    I have set up a RAID5 device with three 2TB hard drives using mdadm. The device was successfully created, but I cannot seem to create a partition on the device. When I try to make an ext3 or ext4 partition via Disk Utility, I get the following error Error creating partition: helper exited with exit code 1: In part_add_partition: device_file=/dev/md0, start=0, size=4000526106624, type= Entering MS-DOS parser (offset=0, size=4000526106624) MSDOS_MAGIC found found partition type 0xee => protective MBR for GPT Exiting MS-DOS parser Entering EFI GPT parser GPT magic found partition_entry_lba=2 num_entries=128 size_of_entry=128 Leaving EFI GPT parser EFI GPT partition table detected containing partition table scheme = 3 got it got disk new partition guid '' is not valid type '' for GPT appear to be malformed I have seen this question, but that seems to suggest using gparted to do the partitioning. I'm fine with doing that, but my RAID device doesn't show up in the list of gparted devices. I suspect because this is a RAID and not a regular disk. I have already created a GPT partition table on the device. How can I add a partition to my device?

    Read the article

  • Benchmarking hosting providers IO with Bonnie

    - by Derek Organ
    Ok, because of a bunch of projects I'm working on I've access to dedicated Servers on a 3 hosting providers. As an experiment and for educational purposes I decided to see if I could benchmark how good the IO is with each. Bit of research lead me to Bonnie++ So I installed it on the server and ran this simple command /usr/sbin/bonnie -d /tmp/foo The 3 machines in different hosting providers are all dedicated machines, one is a VPS, other two are on some cloud platform e.g. VMWare / Xen using some kind of clustered SAN for storage This might be a naive thing to do but here are the results I found. HOST A Version 1.03c ------Sequential Output------ --Sequential Input- --Random- -Per Chr- --Block-- -Rewrite- -Per Chr- --Block-- --Seeks-- Machine Size K/sec %CP K/sec %CP K/sec %CP K/sec %CP K/sec %CP /sec %CP xxxxxxxxxxxxxxxx 1G 45081 88 56244 14 19167 4 20965 40 67110 6 67.2 0 ------Sequential Create------ --------Random Create-------- -Create-- --Read--- -Delete-- -Create-- --Read--- -Delete-- files /sec %CP /sec %CP /sec %CP /sec %CP /sec %CP /sec %CP 16 15264 28 +++++ +++ +++++ +++ +++++ +++ +++++ +++ +++++ +++ xxxxxxxx,1G,45081,88,56244,14,19167,4,20965,40,67110,6,67.2,0,16,15264,28,+++++,+++,+++++,+++,+++++,+++,+++++,+++,+++++,+++ HOST B Version 1.03d ------Sequential Output------ --Sequential Input- --Random- -Per Chr- --Block-- -Rewrite- -Per Chr- --Block-- --Seeks-- Machine Size K/sec %CP K/sec %CP K/sec %CP K/sec %CP K/sec %CP /sec %CP xxxxxxxxxxxx 4G 43070 91 64510 15 19092 0 29276 47 39169 0 448.2 0 ------Sequential Create------ --------Random Create-------- -Create-- --Read--- -Delete-- -Create-- --Read--- -Delete-- files /sec %CP /sec %CP /sec %CP /sec %CP /sec %CP /sec %CP 16 24799 52 +++++ +++ +++++ +++ 25443 54 +++++ +++ +++++ +++ xxxxxxx,4G,43070,91,64510,15,19092,0,29276,47,39169,0,448.2,0,16,24799,52,+++++,+++,+++++,+++,25443,54,+++++,+++,+++++,+++ HOST C Version 1.03c ------Sequential Output------ --Sequential Input- --Random- -Per Chr- --Block-- -Rewrite- -Per Chr- --Block-- --Seeks-- Machine Size K/sec %CP K/sec %CP K/sec %CP K/sec %CP K/sec %CP /sec %CP xxxxxxxxxxxxx 1536M 15598 22 85698 13 258969 20 16194 22 723655 21 +++++ +++ ------Sequential Create------ --------Random Create-------- -Create-- --Read--- -Delete-- -Create-- --Read--- -Delete-- files /sec %CP /sec %CP /sec %CP /sec %CP /sec %CP /sec %CP 16 14142 22 +++++ +++ 18621 22 13544 22 +++++ +++ 17363 21 xxxxxxxx,1536M,15598,22,85698,13,258969,20,16194,22,723655,21,+++++,+++,16,14142,22,+++++,+++,18621,22,13544,22,+++++,+++,17363,21 Ok, so first off what is the best way to read the figures and are there any issues with really comparing these numbers? Is this in any way a true representation of IO Speed? If not is there any way for me to test that? Note: these 3 machines are using either Ubuntu or Debian (I presume that doesn't really matter)

    Read the article

  • Problem after resizing partition for Fedora under Vmware fusion

    - by user20196
    Hi, I am running FC9 under VMware Fusion 3.0 I wanted to resize my /dev/sda2 partition. In order to do that I did the following: 0. changed the size of the vmware file (under VMware settings). 1. rebooted the host to rescue mode without mounted disks 2. fdisk - removed & added /dev/sda2 - i had bigger /dev/sda2 3. lvm pvresize /dev/sda2 4. lvm pvdisplay - it showed me bigger size on /dev/VolGroup00 for /dev/sda2 5. lvm vgchange -a y - device-mapper: reload ioctl failed: Invalid argument - 2 logical volume(s) in volume group "VolGroup00" now active This is not true because there is no /dev/VolGroup00/LogVol00 My whole "/" disappeared. dmsetup table, shows: VolGroup00-LogVol01: 0 2097152 linear 8:2 38338944 VolGroup00-LogVol00: Can some one help me to solve this? Thank You.

    Read the article

  • SQL Windowing screencast session for Cuppa Corner - rolling totals, data cleansing

    - by tonyrogerson
    In this 10 minute screencast I go through the basics of what I term windowing, which is basically the technique of filtering to a set of rows given a specific value, for instance a Sub-Query that aggregates or a join that returns more than just one row (for instance on a one to one relationship). http://sqlserverfaq.com/content/SQL-Basic-Windowing-using-Joins.aspx SQL below... USE tempdb go CREATE TABLE RollingTotals_Nesting ( client_id int not null, transaction_date date not null, transaction_amount...(read more)

    Read the article

  • Ubuntu can't find the correct max resolution with Samsung SyncMaster SA300

    - by fatmatto
    i decided to install ubuntu also on my desktop PC (Windows has been exorcised from my life) but i am having some problems i didn't have with previous hardware configurations. My display is a Samsung SyncMaster SA300, on windows vista the maximum resolution (1920x1080) worked well, but now, ubuntu (after installing fglrx drivers) tells me that the maximum resolution is 1600x1200 I googled a lot last night, and i found a lot of people solving this (on different displays though) with xrandr. I was not able to do it, because xrandr keep complaining "you goddamn maximum resolution is 1600x1600". What xranrd clean command say is: mattia@fatdesktop:~$ xrandr Screen 0: minimum 320 x 200, current 1600 x 1200, maximum 1600 x 1600 DFP1 disconnected (normal left inverted right x axis y axis) CRT1 disconnected (normal left inverted right x axis y axis) CRT2 connected 1600x1200+0+0 (normal left inverted right x axis y axis) 0mm x 0mm 1600x1200 60.0*+ 1400x1050 60.0 1280x1024 60.0 47.0 43.0 1440x900 59.9 1280x960 60.0 1280x800 60.0 1152x864 60.0 47.0 43.0 1280x768 59.9 56.0 1280x720 60.0 50.0 1024x768 60.0 43.5 800x600 60.3 56.2 47.0 720x576 50.0 720x480 60.0 640x480 60.0 TV disconnected (normal left inverted right x axis y axis) CV disconnected (normal left inverted right x axis y axis) Then according to other internet posts and forums: mattia@fatdesktop:~$ cvt 1920 1080 60 # 1920x1080 59.96 Hz (CVT 2.07M9) hsync: 67.16 kHz; pclk: 173.00 MHz Modeline "1920x1080_60.00" 173.00 1920 2048 2248 2576 1080 1083 1088 1120 -hsync +vsync So now i have to add that modeline mattia@fatdesktop:~$ xrandr --newmode "1920x1080_60.00" 173.00 1920 2048 2248 2576 1080 1083 1088 1120 -hsync +vsync mattia@fatdesktop:~$ xrandr --addmode CRT2 1920x1080_60.00 And here comes the pain: mattia@fatdesktop:~$ xrandr --output CRT2 --mode 1920x1080_60.00 xrandr: **screen cannot be larger than 1600x1600 (desired size 1920x1080)** See? screen cannot be larger than 1600x1600 (desired size 1920x1080) At this point, the 1920x1080 option appears inside the resolution choice menu (the graphical one). But last night, when i tried to select it, my screen went black, and i had to power off the pc. Any clues? am i on the wrong path?

    Read the article

  • Using virt-install to mount multiple cdrom drives/images

    - by Dana the Sane
    I would like to create a windows xp guest from the windows xp upgrade cd I have, along with one of a few full versions I have around. However, when I reach the stage in the installer where I am prompted to insert a full version cd, the installer can't find it, i.e.: Setup could not read the CD you inserted, or the CD is not a valid Windows CD.. Is there a work-around for this?, my Googling didn't uncover anything. I've tried various combinations of mounting .iso files and specifying disks, such as: $sudo virt-install --accelerate --connect qemu:///system -n xpsp1 -r 2048 --disk ./vm/winxp_sp1.iso,device=cdrom --disk ./vm/windows.qcow2,size=12 --vnc --noautoconsole --os-type windows --os-variant winxp --vcpus 2 -c /dev/cdrom --check-cpu If I try to specify multiple cdrom drives, I receive an error: virt-install --accelerate --connect qemu:///system -n xpsp1 -r 2048 --disk ./vm/winxp_sp1.iso,device=cdrom --disk /dev/cdrom,device=cdrom --disk ./vm/windows.qcow2,size=12 --vnc --noautoconsole --os-type windows --os-variant winxp --vcpus 2 --check-cpu Starting install... ERROR IDE CDROM must use 'hdc', but target in use.

    Read the article

  • Desktop Fun: Beaches Theme Wallpapers

    - by Asian Angel
    Is your vacation still a few weeks or months away? Make the waiting a little easier by adding some of that vacation scenery to your desktop with our Beaches Theme Wallpapers collection. Note: Click on the picture to see the full-size image—these wallpapers vary in size so you may need to crop, stretch, or place them on a colored background in order to best match them to your screen’s resolution.                       For more fun wallpapers be certain to visit our new Desktop Fun section. Similar Articles Productive Geek Tips Windows 7 Welcome Screen Taking Forever? Here’s the Fix (Maybe)Desktop Fun: Starship Theme WallpapersDesktop Fun: Underwater Theme WallpapersDesktop Fun: Forest Theme WallpapersDesktop Fun: Fantasy Theme Wallpapers TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional Run Command Missing in Windows 7? Share High Res Photos using Divvyshot Draw Online using Harmony How to Browse Privately in Firefox Kill Processes Quickly with Process Assassin Need to Come Up with a Good Name? Try Wordoid

    Read the article

  • Resizing an iscsi LUN on an EMC under Linux RHEL 5

    - by niXar
    I expanded a LUN on my SAN (from 30G to 50G), and tried all kind of voodoo but it looks like the system still believes the device is still small, despite showing me the new size alright. # blockdev --getsize64 /dev/sdl 53687091200 # dd if=/dev/sdl skip=$(( 31*1024*1024*1024/512 )) count=1|hexdump -C dd: reading `/dev/sdl': Input/output error The dd line works for blocks below the 30G original size. If I reboot, the problem goes away, but I don't want to since the machine has a dozen VMs running. I tried various magic, such as: iscsiadm -m node -R -I iface0 ... to no avail. Note: I'm not using multipath.

    Read the article

  • Beginners security question

    - by Reg H
    Hi everyone, I'm still pretty new to web development, and have a question about security. Every day I look at the "Latest Visitors" in my CPanel, and today there were some strange entries (one is pasted below). Not knowing any better, it looks to me like there is some site that's referring users to my site, for some reason. Can someone explain what these really are, and if it's something to be concerned about? Thanks! Host: 77.68.38.175 /?p=http://teen-37.net/myid.jpg? Http Code: 404 Date: Feb 17 08:13:58 Http Version: HTTP/1.1 Size in Bytes: - Referer: - Agent: libwww-perl/5.805 * /?p=../../../../../../../../../../../../../../../proc/self/environ%00 Http Code: 404 Date: Feb 17 08:13:59 Http Version: HTTP/1.1 Size in Bytes: - Referer: - Agent: libwww-perl/5.805

    Read the article

  • RAID5 over LVM on Ubuntu Server 12.04.3

    - by April Ethereal
    I'm trying to create a RAID5 software array using LVM. I use VirtualBox as I'm only learning how LVM works. So I've created 4 virtual SCSI drives and then did the following: pvcreate /dev/sd[b-e] vgcreate /dev/sd[b-e] raid5_vg lvcreate --type raid5 -i 3 -L 1G -n raid_lv raid5_vg However, I get an error after the last command: WARNING: Unrecognised segment type raid5 Using default stripesize 64.00 KiB Rounding size (256 extents) up to stripe boundary size (258 extents) Cannot update volume group raid5_vg with unknown segments in it! So it looks like raid5 is not a valid segment type. "lvm segtypes" also doesn't contain 'raid5' entry: root@ubuntu-lvm:~# lvm segtypes striped zero error free snapshot mirror So my question is - how could I create RAID5 logical volume using LVM only? It seems that it is possible, I saw a few references (not for Ubuntu, unfortunately) for RedHat and Gentoo systems. I don't want to use mdadm for now, until I find out that it is mandatory. Some info about my system is below: root@ubuntu-lvm:~# uname -a Linux ubuntu-lvm 3.8.0I use Ubuntu Server 12.04.3 (i686)-29-generic #42~precise1-Ubuntu SMP Wed Aug 14 15:31:16 UTC 2013 i686 i686 i386 GNU/Linux root@ubuntu-lvm:~# dpkg -l | grep lvm ii lvm2 2.02.66-4ubuntu7.3 The Linux Logical Volume Manager Thanks.

    Read the article

  • My software is hosted on a "bad" website. Can I do anything about it?

    - by Abluescarab
    The software I've created is hosted on what you could call a "bad" website. It's hard to explain, so I'll just provide an example. I've made a free password generator. This, along with most of my other FREE software, is available on this website. This is their description of my software: Platform: 7/7 x64/Windows 2K/XP/2003/Vista Size: 61.6 Mb License: Trial File Type: .7z Last Updated: June 4th, 2011, 15:38 UTC Avarage Download Speed: 6226 Kb/s Last Week Downloads: 476 Toatal Downloads: 24908 Not only is the size completely skewed, it is not trial software, it's free software. The thing is that it's not the description I'm worried about--it's the download links. The website is a scam website. They apparently link to "cracks" and "keygens", but not only is that in itself illegal, they actually link to fake download websites that give you viruses and charge your credit card. Just to list things that are wrong with this website: they claim all software is paid software then offer downloads for keygens and cracks; they fake all details about the program and any program reviews and ratings; they and the downloads site they link to are probably run by the same person, so they make money off of these lies. I'm only a teenager with no means to pursue legal action. This means that, unfortunately, I can't do anything that will actually get results. I'd like my software to only be downloaded off my personal website. I have links to four legitimate locations to download my software and that's it. Essentially, is there anything I can do about this? As I said above, I can't pursue legal action, but is there some way I can discourage traffic to that website by blacklisting it or something? Can I make a claim on MY website to only download my software from the links I provide? Or should I just pay no mind? Because, honestly, it's a bit of a ways back in Google results. Thank you ahead of time.

    Read the article

< Previous Page | 381 382 383 384 385 386 387 388 389 390 391 392  | Next Page >