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  • Call ASP.NET 2.0 Server side code from Javascript

    - by Kannabiran
    I'm struggling with this for the past 3 days. I need to call asp.net serverside code from Javascript when the user closes the browser. I'm using the following code to accomplish this. In my asp.net form I have various validation controls. Even if there are some validation errors, When I close the form the server side code works perfectly in my development box(windows 7). But the same code doesnt work in my production environment(windows server). Does it have something to do with the Validation summary or Validation controls. The button control has Causes validation set to false. So even if there is a validation error still my form will post back. Am I correct? I suspect the form is not getting post back to the server when there is a validation error. But i'm disabling all the validation controls in the javascript before calling the button click event. Can someone throw some light on this issue. There are few blogs which suggests to use JQUERY, AJAX (Pagemethods and script manager). function ConfirmClose(e) { var evtobj = window.event ? event : e; if (evtobj == e) { //firefox if (!evtobj.clientY) { evtobj.returnValue = message; } } else { //IE if (evtobj.clientY < 0) { DisablePageValidators(); document.getElementById('<%# buttonBrowserCloseClick.ClientID %>').click(); } } } function DisablePageValidators() { if ((typeof (Page_Validators) != "undefined") && (Page_Validators != null)) { var i; for (i = 0; i < Page_Validators.length; i++) { ValidatorEnable(Page_Validators[i], false); } } } //HTML <div style="display:none" > <asp:Button ID="buttonBrowserCloseClick" runat="server" onclick="buttonBrowserCloseClick_Click" Text="Button" Width="141px" CausesValidation="False" /> //Server Code protected void buttonBrowserCloseClick_Click(object sender, EventArgs e) { //Some C# code goes here }

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  • How to compare a string with an option value

    - by user225269
    I have this html form which has options: <tr> <td width="30" height="35"><font size="3">*List:</td> <td width="30"><input name="specific" type="text" id="specific" maxlength="25" value=""> </td> <td><font size="3">*By:</td> <td> <select name="general" id="general"> <font size="3"> <option value="YEAR">Year</option> <option value="ADDRESS">Address</option> </select></td></td> </tr> And I'm trying to have this as the form action: if ('{$_POST["ADDRESS"]}'="ADDRESS") Which will compare if the value in the option in the html form matches the word "Address". If it matches then it will execute this query: $saddress= mysql_real_escape_string($_POST['specific']);<--this is the input form where the user will put the specific address to search. mysql_query("SELECT * FROM student WHERE ADDRESS='$saddress'"); Please I need help in here, I thinks its wrong: if ('{$_POST["ADDRESS"]}'="ADDRESS")

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  • How to use JS to jump to a specific place in a page? Tried scrollIntoView, not working

    - by EmmyS
    I have a PHP form for discussions. Each message has its own response button, which is dynamically generated. I'm using javascript in the button to make a response form visible at the bottom of the page, but I can't for the life of me get the page to jump down to the form once it's visible. This is a problem for pages that have a lot of discussions on it, as some users may not know to scroll down and will just think the button didn't work. Here's what I have now for my button code: <a href="#" onClick="changeVisibility(3,'responseForm')"><img src="images/reply.jpg" border=0 /></a> The changeVisibility function looks like this: function changeVisibility(parentID, elementID) { document.getElementById(elementID).style.visibility="visible"; document.forms[0].parent_id.value=parentID; var el = document.getElementById(elementID); el.scrollIntoView(true); } In my form, I have a div whose id is set to responseForm. When clicking the button, the div does become visible, but the scrollIntoView is not working - I have to manually scroll down to see it. Any ideas?

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  • how to send value to the from action page from database

    - by Mayank swami
    I am creating a faq panel for there can be multiple answers for question and i want to take the answer id .because i am storing comment by answer id the problem is that how to sent the $answer_id to the comment_submit_process.php and how to recognize the answer ? $selected_ques= mysql_prep($_GET['ques']); $query = "SELECT * FROM formanswer where question_id = {$selected_ques}"; $ans= mysql_query($query); if($ans){ while($answer = mysql_fetch_array($ans)) //here is the form <form id="add-comment" action="comment_submit_process.php" > <textarea class="comment-submit-textarea" cols="78" name="comment" style="height: 64px;"></textarea> <input type="submit" name="submitbutton" value="Add Comment" class="comment-submit-button" > <br> <?php $ans_id= $answer['id']; echo $ans_id; ?> <input type="hidden" name="ques" value="<?php echo $_GET['$ans_id'] ?>" /> <span class="counter ">enter at least 15 characters</span> <span class="form-error"></span> </form> <?php }} ?>

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  • Aligning inputs on bootstrap using the Fluid Grid System

    - by sguha
    I am creating a form that requires the user to input their name and email address. The first line of the form has two inputs side by side for each part of the name and the 2nd line has one input for the email address that should be the same width as the first line combined. I'm trying to use the fluid grid system but can't line up the 2nd row with the first. <form action="/subscriptions" method="post"> <fieldset> <div class="control-group"> <label class="control-label" for="name">Name</label> <div class="controls row-fluid"> <input class="span2" id="first_name" name="first_name" placeholder="First" required="required" type="text"> <input class="span2" id="last_name" name="last_name" placeholder="Last" required="required" type="text"> </div> </div> <div class="control-group"> <label class="control-label" for="email">Email</label> <div class="controls row-fluid"> <input class="span4" id="email" name="email" type="email"> </div> </div> </fieldset> </form>? http://jsfiddle.net/sguha095/v4amX/

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  • Visual Studio project remains "stuck" when stopped

    - by Traveling Tech Guy
    Hi, Currently developing a connector DLL to HP's Quality Center. I'm using their (insert expelative) COM API to connect to the server. An Interop wrapper gets created automatically by VStudio. My solution has 2 projects: the DLL and a tester application - essentially a form with buttons that call functions in the DLL. Everything works well - I can create defects, update them and delete them. When I close the main form, the application stops nicely. But when I call a function that returns a list of all available projects (to fill a combo box), if I close the main form, VStudio still shows the solution as running and I have to stop it. I've managed to pinpoint a single function in my code that when I call, the solution remains "hung" and if I don't, it closes well. It's a call to a property in the TDC object get_VisibleProjects that returns a List (not the .Net one, but a type in the COM library) - I just iterate over it and return a proper list (that I later use to fill the combo box): public List<string> GetAvailableProjects() { List<string> projects = new List<string>(); foreach (string project in this.tdc.get_VisibleProjects(qcDomain)) { projects.Add(project); } return projects; } My assumption is that something gets retained in memory. If I run the EXE outside of VStudio it closes - but who knows what gets left behind in memory? My question is - how do I get rid of whatever calling this property returns? Shouldn't the GC handle this? Do I need to delve into pointers? Things I've tried: getting the list into a variable and setting it to null at the end of the function Adding a destructor to the class and nulling the tdc object Stepping through the tester function application all the way out, whne the form closes and the Main function ends - it closes, but VStudio still shows I'm running. Thanks for your assistance!

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  • How can I dynamically resize the jQuery Colorbox plugin?

    - by James Skidmore
    The AJAX content loaded in a Colorbox has some JavaScript included that resizes things within the content. Colorbox determines its sizing based on the sizes before all of the AJAX happens. How can I make the Colorbox resize after the content has been loaded? Here is a link where someone said that you can call colorbox() again after it's been loaded, but I can't figure out how to do that: http://groups.google.com/group/colorbox/browse_thread/thread/535d21c69e9006b0

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  • Displaying data from a linked table and displaying it as a list with HTML/PHP/MySQL

    - by user1672694
    I have three tables. students studentID | FirstName | LastName | Email | Form course CCode | Title courseenrolement courseenrolementid | studentID | ccode | complete | scode With the website, I have a page where I can view all the current enrolements and I wish to be able to view the list displaying the first name, surname and course title. I know I could do it with the following SQL (for the names): SELECT FirstName, LastName FROM student, courseenrolement WHERE courseenrolement.studentID = student.studentID But I am unsure how to get this to work using HTML/PHP. At present I only know how to display the studentID and CCode from the courseenrolement table using the following code: <ul> <?php foreach ($courseenrolements as $ce): ?> <li> <form action="" method="post"> <div> <?php htmlout($ce['studentID']); ?> <?php htmlout($ce['CCode']); ?> <input type="hidden" name="courseenrolementid" value="<?php echo $ce['courseenrolementid']; ?>"> <input type="submit" name="action" value="Edit"> <input type="submit" name="action" value="Delete"> </div> </form> </li> <?php endforeach; ?> </ul> which displays this: But I would like the names and course title. I managed to get it to show the names etc in the dropdown on the 'Add new' form, so I would assume it will be similar, but just unsure on how exactly. Thanks in advance

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  • Testing InlineFormset clean methods

    - by Rory
    I have a Django project, with 2 models, a Structure and Bracket, the Bracket has a ForeignKey to a Structure (i.e. one-to-many, one Structure has many Brackets). I created a TabularInline for the admin site, so that there would be a table of Brackets on the Structure. I added a custom formset with some a custom clean method to do some extra validation, you can't have a Bracket that conflicts with another Bracket on the same Structure etc. The admin looks like this: class BracketInline(admin.TabularInline): model = Bracket formset = BracketInlineFormset class StructureAdmin(admin.ModelAdmin): inlines = [ BracketInline ] admin.site.register(Structure, StructureAdmin) That all works, and the validation works. However now I want to write some unittest to test my complex formset validation logic. My first attempt to validate known-good values is: data = {'form-TOTAL_FORMS': '1', 'form-INITIAL_FORMS': '0', 'form-MAX_NUM_FORMS': '', 'form-0-field1':'good-value', … } formset = BracketInlineFormset(data) self.assertTrue(formset.is_valid()) However that doesn't work and raises the exception: ====================================================================== ERROR: testValid (appname.tests.StructureTestCase) ---------------------------------------------------------------------- Traceback (most recent call last): File "/paht/to/project/tests.py", line 494, in testValid formset = BracketInlineFormset(data) File "/path/to/django/forms/models.py", line 672, in __init__ self.instance = self.fk.rel.to() AttributeError: 'BracketInlineFormset' object has no attribute 'fk' ---------------------------------------------------------------------- The Django documentation (for formset validation) implies one can do this. How come this isn't working? How do I test the custom clean()/validation for my inline formset?

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  • Loading Modules in Angular

    - by SL Dev
    I'm new to AngularJS. In my efforts to learn, I've relied on the AngularJS tutorials. Now, I'm trying to build an app using the AngularSeed project template. I'm trying to make my project as modular as possible. For that reason, my controllers are broken out into several files. Currently, I have the following: /app index.html login.html home.html javascript app.js loginCtrl.js homeCtrl.js my app.js file has the following: 'use strict'; var app = angular.module('site', ['ngRoute']); app.config(function($routeProvider, $locationProvider) { $locationProvider.html5Mode(true); $routeProvider.when('/login', {templateUrl: 'app/login.html', controller:'loginCtrl'}); $routeProvider.when('/home', {templateUrl: 'app/home.html', controller:'homeCtrl'}); $routeProvider.otherwise({redirectTo: '/login'}); }); my loginCtrl.js file is very basic at the moment. It only has: 'use strict'; app.controller('loginCtrl', function loginCtrl($scope) { } ); My homeCtrl.js is almost the same, except for the name. It looks like the following: 'use strict'; app.controller('homeCtrl', function homeCtrl($scope) { } ); My index.html file is the angularSeed index-async.html file. However, when I load the dependencies, I have the following: // load all of the dependencies asynchronously. $script([ 'http://ajax.googleapis.com/ajax/libs/angularjs/1.2.0-rc.3/angular.min.js', 'http://ajax.googleapis.com/ajax/libs/angularjs/1.2.0-rc.3/angular-route.min.js', 'javascript/app.js', 'javascript/loginCtrl.js', 'javascript/homeCtrl.js' ], function() { // when all is done, execute bootstrap angular application angular.bootstrap(document, ['site']); }); My problem is, sometimes my app works and sometimes it doesn't. It's almost like something gets loaded before something else. Occasionally, I receive this error. Other times, I get an error in the console window that says: 'Uncaught ReferenceError: app is not defined' in loginCtrl.js. Sometimes it happens with homeCtrl.js. What am I doing wrong? It feels like I need to have my controllers in a module and pass that module in my app.config in the app.js file. However, a) I'm not sure if that allowed and b) I'm not sure how to do it.

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  • OpenSocial create activity from submit click

    - by russp
    Hi I'm "playing with OpsnSocial" and think I get a lot of it (well thanks to Googles' bits) but one question if I may. Creating an activity Lets say I have a form like this (simple) <form> <input type="text" name="" id="testinput" value=""/> <input type="submit" name="" id="" value=""/> </form> And I want to post the value of the text field (and or a message i.e "just posted" to the "users" activity. Do I use a function like this? function createActivity() { if (viewer) { var activity = opensocial.newActivity({ title: viewer.getDisplayName() + ' VALUE FROM FORM '}); opensocial.requestCreateActivity(activity, "HIGH", function() { setTimeout(initAllData,1000); }); } }; If so, how do I pass the text field value to it - is it something like this? var testinput = document.getElementById("testinput"); so the function may look like function createActivity() { if (viewer) { var activity = opensocial.newActivity({ title: viewer.getDisplayName() + testinput }); opensocial.requestCreateActivity(activity, "HIGH", function() { setTimeout(initAllData,1000); }); } }; And how do I trigger the function by using the submit button. In my basic JQuery I would use $('#submitID').submit(function(){ 'bits in here '}); Is at "simple as that i.e. use the createActivity function and it will use the OS framework to "post" to the activity.xml

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  • How to upload files to server using JSP/Servlet?

    - by Thang Pham
    How can I upload files to server using JSP/Servlet? I tried this: <form action="upload" method="post"> <input type="text" name="description" /> <input type="file" name="file" /> <input type="submit" /> </form> However, I only get the file name, not the file content. When I add enctype="multipart/form-data" to the <form>, then request.getParameter() returns null. During research I stumbled upon Apache Common FileUpload. I tried this: FileItemFactory factory = new DiskFileItemFactory(); ServletFileUpload upload = new ServletFileUpload(factory); List items = upload.parseRequest(request); // This line is where it died. Unfortunately, the servlet threw an exception without a clear message and cause. Here is the stacktrace: SEVERE: Servlet.service() for servlet UploadServlet threw exception javax.servlet.ServletException: Servlet execution threw an exception at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:313) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:852) at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588) at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489) at java.lang.Thread.run(Thread.java:637)

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  • Why does the '#weight' property sometimes not have any effect in Drupal forms?

    - by Adrian
    Hello, I'm trying to create a node form for a custom type. I have organic groups and taxonomy both enabled, but want their elements to come out in a non-standard order. So I've implemented hook_form_alter and set the #weight property of the og_nodeapi subarray to -1000, but it still goes after taxonomy and menu. I even tried changing the subarray to a fieldset (to force it to actually be rendered), but no dice. I also tried setting $form['taxonomy']['#weight'] = 1000 (I have two vocabs so it's already being rendered as a fieldset) but that didn't work either. I set the weight of my module very high and confirmed in the system table that it is indeed the highest module on the site - so I'm all out of ideas. Any suggestions? Update: While I'm not exactly sure how, I did manage to get the taxonomy fieldset to sink below everything else, but now I have a related problem that's hopefully more manageable to understand. Within the taxonomy fieldset, I have two items (a tags and a multi-select), and I wanted to add some instructions in hook_form_alter as follows: $form['taxonomy']['instructions'] = array( '#value' => "These are the instructions", '#weight' => -1, ); You guessed it, this appears after the terms inserted by the taxonomy module. However, if I change this to a fieldset: $form['taxonomy']['instructions'] = array( '#type' => 'fieldset', // <-- here '#title' => 'Instructions', // <-- and here for good measure '#value' => "These are the instructions", '#weight' => -1, ); then it magically floats to the top as I'd intended. I also tried textarea (this also worked) and explicitly saying markup (this did not). So basically, changing the type from "markup" (the default IIRC) to "fieldset" has the effect of no longer ignoring its weight.

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  • Forcing user to new page in php. (PHP newbie)

    - by JohnC
    Hello I'm a newbie web programmer. My background is writing Windows applications with sql. I'm putting together my 1st data entry screens in Php. I have a search form that links to a form that displays records in a grid. On each row of the grid I have a delete url to allow the user to remove a record. This links to a form delete.php (which calls the sql to remove the record). Ideally I would like to automatically take the user back to the search form rather than forcing the user to click on a link to do so. I have used ob_start with the header to do this elsewhere but cannot get it to work on this page. Is there another way to do it? (Using php 5 as part of LAMP) file delete.php <?php $id = $_GET['recordID']; //ob_start(); require_once('connections/local.php'); mysql_select_db($database_local, $local); mysql_query("DELETE FROM user_access WHERE id = {$id}") or die(mysql_error()); echo("Record ".$id." deleted"); echo("<br>"); //header("location:http://localhost/search7.htm); //ob_flush(); echo("<a href=\"http://localhost/search7.htm\">Search for Members</a>"); ?>

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  • Extjs - Loading Grid when call

    - by Oxi
    I have form and grid. the user must enter data in form fields then display related records in the grid. I want to implement a search form, e.g: user will type the name and gender of the student, then will get a grid of all students have the same name and gender. So, I use ajax to send form fields value to PHP and then creat a json_encode wich will be used in grid store. I am really not sure if my idea is good. But I haven't found another way to do that. The problem is when I set autoLoad to true in the store, the grid automatically filled with all data - not just what I asked for - So, I understand that I have to set autoLoad to false, but then the result not shown in the grid even it returned successfully in the firebug! I don't know what to do. My View: { xtype: 'panel', layout: "fit", id: 'searchResult', flex: 7, title: '<div style="text-align:center;"/>SearchResultGrid</div>', items: [ { xtype: 'gridpanel', store: 'advSearchStore', id: 'AdvSearch-grid', columns: [ { xtype: 'gridcolumn', dataIndex: 'name', align: 'right', text: 'name' }, { xtype: 'gridcolumn', dataIndex: 'gender', align: 'right', text: 'gender' } ], viewConfig: { id : 'Arr' ,emptyText: 'noResult' }, requires: ['MyApp.PrintSave_toolbar'], dockedItems: [ { xtype: 'PrintSave_tb', dock: 'bottom', } ] } ] }, My Store and Model: Ext.define('AdvSearchPost', { extend: 'Ext.data.Model', proxy: { type: 'ajax', url: 'AdvSearch.php', reader: { type: 'json', root: 'Arr', totalProperty: 'totalCount' } }, fields: [ { name: 'name'}, { name: 'type_and_cargo'} ] }); Ext.create('Ext.data.Store', { pageSize: 10, autoLoad: false, model: 'AdvSearchPost', storeId: 'AdvSearchPost' });

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  • XMLHttpRequest() and outputting csv file

    - by sjw
    Initially, I developed a javascript function to use window.open to post contents of a form to a new window which simply opened the new window and initiated a csv file download. Now on reflection, I find the opening of the window superfluous and am trying to just execute a XMLHttpRequest() to download the csv. I am not getting what I want and I'm not 100% sure that I can so I thought I'd ask here for some assistance. When a form is submitted, I want to take all the form values and post them to another page which builds an SQL string and builds a csv based on the contents. (This I can do and works fine with XMLHttpRequest() as seen below) var xhReq = new XMLHttpRequest(); var parameters = ""; for ( i=0; i<formObj.elements.length; i++ ) { parameters += formObj.elements[i].name + "=" + encodeURI( formObj.elements[i].value ) + "&"; } xhReq.open("POST", outputLocation, false); xhReq.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); xhReq.setRequestHeader("Content-length", parameters.length); xhReq.setRequestHeader("Connection", "close"); xhReq.send(parameters); document.write(xhReq.responseText); The code above calls the page ok, builds the csv ok, but it outputs the contents into the current browser window instead of initiating a csv file download. Can I achieve what I need using XMLHttpRequest() or am I going it about it the wrong way? Thanks

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  • Not delete params in URL, when sorting [ RAILS 3 ]

    - by kamil
    I have sortable table columns, made like that http://asciicasts.com/episodes/228-sortable-table-columns And I have simply filter options for two columns in table, made at select_tag (GET method). This two function don't work together. When I change filter, the sort parameter disappear and inversely. <th><%= sortable "Id" %></th> <th> Status<br/> <form method="get"> <%= select_tag(:status, options_for_select([['All', 'all']]+@statuses, params[:status]),{:onchange => 'this.form.submit()'}) %> </th> <th><%= sortable "Operation" %></th> <th> Processor<br/> <%= select_tag(:processor, options_for_select([['All', 'all']]+@processor_names, params[:processor]),{:onchange => 'this.form.submit()'}) %> </form> </th>

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  • Things in .NET Framework 4 that every programmer should know

    - by Faruz
    I recently moved to Visual Studio 2010 and upgraded my website to work with .NET Framework 4. (From VS 2008 - Framework 3.5) What are things I need to know to improve site speed, readability or memory use? For example, I found out that when I use AJAX ScriptManager, one of it's new properties is EnableCDN which enables me to load AJAX .js files from Microsoft CDN.

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  • Webkit browsers rendering CSS different than Mozilla Firefox...Why??

    - by JAG2007
    I'm styling a form that was already marked up (made some markup changes), and I normally work in Firefox to style so I can use firebug and the web developer toolbar. On this project, I noticed that my styles are displaying quite differently for one particular area (several elements) in webkit based browsers Chrome and Safari, than in Firefox (we won't even get into Internet Explorer, although it is siding with the Firefox display). I can't figure out though why the styles are displaying so differently. Normally there is some rule that I'm neglecting that Firefox just takes for granted, and the others need it specified. But here I'm not getting why it's displaying this way. In particular I'm referring to the bottom area of the form where users can enter their contact info, then submit the form. I'll attach screen shots for reference as to the discrepancy. Here's the URL so feel free to check it out on your own. Although be advised that this is a production page (already released) so if you try out the form, you WILL BE added to CURE's contact database. http://www.helpcurenow.org/survey2010 Here's the screen shots: Firefox (the way I intend it to look) Chrome, and then Safari - strange change to submit button As a bonus, if anybody wants to help me with figuring out why on earth IE7 wants to not show the background behind the questions only, and how to fix that I would be much obliged! Thanks very much.

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  • How to get the root path in JavaScript?

    - by Axel
    I am using mod_rewrite to remap the URLs in my website in the following format: http://www.mydomain.com/health/54856 http://www.mydomain.com/economy/strategy/911025/ http://www.mydomain.com/tags/obama/new The problem is that I am making AJAX calls to a file: http://www.mydomain.com/login.php And I don't want to write the FULL url or even use the ../ trick because there isn't a fixed level of folders. So, what i want is something to access the login.php from the root, whatever the domain name is: $.ajax({ type: "POST", url: "http://www.mydomain.com/login.php" });

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  • Rails Updating Nested Model Collection Select

    - by Timothy
    I have a contrived nested Rails form like the following <% form_for @a do |fa| %> <% fa.fields_for :b do |fb| %> <% fb.fields_for :c do |fc| %> <%= fc.label :option_id %> <%= fc.collection_select :option_id, ModelD.all(:select => "id, name"), :id, :name %> <% end %> <% end %> <% end %> and then somewhere else on the same page I have a remote form <% remote_form_for :modeld, ModelD.new, :url => new_modeld_path, :html => {:method => 'post'} do |f| %> <%= f.label :name %> <%= f.textarea :name %> <%= f.submit "Create" %> <% end %> Is there any way I could update all the collection selects in the first form using Ajax when I submit the second form? There are an arbitrary number of collection selects.

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  • How to implement Administrator rights in Java Application?

    - by Yatendra Goel
    I am developing a Data Modeling Software that is implemented in Java. This application converts the textual data (stored in a database) to graphical form so that users can interpret the data in a more efficient form. Now, this application will be accessed by 3 kinds of persons: 1. Managers (who can fill the database with data and they can also view the visual form of the data after entering the data into the database) 2. Viewers (who can only view the visual form of data that has been filled by managers) 3. Administrators (who can create and manage other administrators, managers and viewers) Now, how to implement 3 diff. views of the same application. Note: Managers, Viewers and Administrators can be located in any part of the world and should access the application through internet. One idea that came in my mind is as follows: Step1: Code all the business logic in EJBs so that it can be used in distributed environment (means which can be accessed by several users through internet) Step2: Code 3 Swing GUI Clients: One for administrators, one for managers and one for viewers. These 3 GUI clients can access business logic written in EJBs. Step3: Distribute the clients corresponding to their users. For instance, manager client to managers. =================================QUESTIONS======================================= Q1. Is the above approach is correct? Q2. This is very common functionality that various softwares have. So, Do they implement this kind of functionality through this way or any other way? Q3. If any other approach would be more better, then what is that approach?

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  • larger file upload problem with php

    - by chris
    I need to upload a csv file to a server. works fine for smaller files but when the file is 3-6 meg its not working. $allowedExtensions = array("csv"); foreach ($_FILES as $file) { if ($file['tmp_name'] > '') { if (!in_array(end(explode(".", strtolower($file['name']))), $allowedExtensions)) { die($file['name'].' is an invalid file type!<br/>'. '<a href="javascript:history.go(-1);">'. '&lt;&lt Go Back</a>'); } if (move_uploaded_file($file['tmp_name'], $uploadfile)) { echo "File is valid, and was successfully uploaded.\n"; } else { echo "Possible file upload attack!\n"; } echo "File has been uploaded"; } //upload form <form name="upload" enctype="multipart/form-data" action="<? echo $_SERVER['php_self'];?>?action=upload_process" method="POST"> <!-- MAX_FILE_SIZE must precede the file input field --> <input type="hidden" name="MAX_FILE_SIZE" value="31457280" /> <!-- Name of input element determines name in $_FILES array --> Send this file: <input name="userfile" type="file" /> <input type="submit" value="Send File" /> </form> I have also added this to htaccess php_value upload_max_filesize 20M php_value post_max_size 20M php_value max_execution_time 200 php_value max_input_time 200 Where am i going wrong?

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