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  • Detect if 2 HTML fragments have identical hierarchical structure

    - by sergzach
    An example of fragments that have identical hierarchical structure: (1) <div> <span>It's a message</span> </div> (2) <div> <span class='bold'>This is a new text</span> </div> An example of fragments that have different structure: (1) <div> <span><b>It's a message</b></span> </div> (2) <div> <span>This is a new text</span> </div> So, fragments with a similar structure correspond to one hierarchical tree (the same tag names, the same hierarchical structure). How can I detect if 2 elements (html fragments) have the same structure simply with lxml? I have a function that does not work properly for some more difficult case (than the example): def _is_equal( el1, el2 ): # input: 2 elements with possible equal structure and tag names # e.g. root = lxml.html.fromstring( buf ) # el1 = root[ 0 ] # el2 = root[ 1 ] # move from top to bottom, compare elements result = False if el1.tag == el2.tag: # has no children if len( el1 ) == len( el2 ): if len( el1 ) == 0: return True else: # iterate one of them, for example el1 i = 0 for child1 in el1: child2 = el2[ i ] is_equal2 = _is_equal( child1, child2 ) if not is_equal2: return False return True else: return False else: return False The code fails to detect that 2 divs with class='tovar2' have an identical structure: <body> <div class="tovar2"> <h2 class="new"> <a href="http://modnyedeti-krsk.ru/magazin/product/333193003"> ?????? ?/? </a> </h2> <ul class="art"> <li> ???????: <span>1759</span> </li> </ul> <div> <div class="wrap" style="width:180px;"> <div class="new"> <img src="shop_files/new-t.png" alt=""> </div> <a class="highslide" href="http://modnyedeti-krsk.ru/d/459730/d/820.jpg" onclick="return hs.expand(this)"> <img src="shop_files/fr_5.gif" style="background:url(/d/459730/d/548470803_5.jpg) 50% 50% no-repeat scroll;" alt="?????? ?/?" height="160" width="180"> </a> </div> </div> <form action="" onsubmit="return addProductForm(17094601,333193003,3150.00,this,false);"> <ul class="bott "> <li class="price">????:<br> <span> <b> 3 150 </b> ???. </span> </li> <li class="amount">???-??:<br><input class="number" onclick="this.select()" value="1" name="product_amount" type="text"> </li> <li class="buy"><input value="" type="submit"> </li> </ul> </form> </div> <div class="tovar2"> <h2 class="new"> <a href="http://modnyedeti-krsk.ru/magazin/product/333124803">?????? ?/?</a> </h2> <ul class="art"> <li> ???????: <span>1759</span> </li> </ul> <div> <div class="wrap" style="width:180px;"> <div class="new"> <img src="shop_files/new-t.png" alt=""> </div> <a class="highslide" href="http://modnyedeti-krsk.ru/d/459730/d/820.jpg" onclick="return hs.expand(this)"> <img src="shop_files/fr_5.gif" style="background:url(/d/459730/d/548470803_5.jpg) 50% 50% no-repeat scroll;" alt="?????? ?/?" height="160" width="180"> </a> </div> </div> <form action="" onsubmit="return addProductForm(17094601,333124803,3150.00,this,false);"> <ul class="bott "> <li class="price">????:<br> <span> <b>3 150</b> ???. </span> </li> <li class="amount">???-??:<br><input class="number" onclick="this.select()" value="1" name="product_amount" type="text"> </li> <li class="buy"> <input value="" type="submit"> </li> </ul> </form> </div> </body>

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  • What did I do wrong with this function?

    - by Felipe Galdino Campos
    I don't know what I did - it's wrong . Can someone help me? def insert_sequence(dna1, dna2, number): '''(str, str, int) -> str Return the DNA sequence obtained by inserting the second DNA sequence at the given index. (You can assume that the index is valid.) >>> insert_sequence('CCGG', 'AT', 2) 'CCATGG' >>> insert_sequence('TTGC', 'GG', 2) 'TTGGGC' ''' index = 0 result = ''; for string in dna1: if index == number: result = result + dna2 result = result + string index += 1 print(result)

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  • Write xml file with lxml

    - by systempuntoout
    Having a code like this: from lxml import etree root = etree.Element("root") root.set("interesting", "somewhat") child1 = etree.SubElement(root, "test") How do i write root Element object to an xml file using write() method of ElementTree class?

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  • combine lines from 2 prints to single line and insert into mysql database

    - by bleomycin
    Hello everyone i currently have this: import feedparser d = feedparser.parse('http://store.steampowered.com/feeds/news.xml') for i in range(10): print d.entries[i].title print d.entries[i].date How would i go about making it so that the title and date are on the same line? Also it doesn't need to print i just have that in there for testing, i would like to dump this output into a mysql db with the title and date, any help is greatly appreciated!

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  • BeautifulSoup: just get inside of a tag, no matter how many enclosing tags there are

    - by AP257
    I'm trying to scrape all the inner html from the <p> elements in a web page using BeautifulSoup. There are internal tags, but I don't care, I just want to get the internal text. For example, for: <p>Red</p> <p><i>Blue</i></p> <p>Yellow</p> <p>Light <b>green</b></p> How can I extract: Red Blue Yellow Light green Neither .string nor .contents[0] does what I need. Nor does .extract(), because I don't want to have to specify the internal tags in advance - I want to deal with any that may occur. Is there a 'just get the visible HTML' type of method in BeautifulSoup? ----UPDATE------ On advice, trying: p_tags = page.findAll('p',text=True) for i, p_tag in enumerate(p_tags): print str(p_tag) But that doesn't help - it just prints out: Red <i>Blue</i> Yellow Light <b>green</b>

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  • about the post_save signal and created argument

    - by panchicore
    the docs says: post_save django.db.models.signals.post_save created A boolean; True if a -new- record was create. and I have this: from django.db.models.signals import post_save def handle_new_user(sender, instance, created, **kwargs): print "--------> save() "+str(created) post_save.connect(handle_new_user, sender=User) when I do in shell: u = User(username="cat") u.save() >>> --------> save() True u.username = "dog" u.save() >>> --------> save() True I expect a -------- save() False when I save() the second time because is an update? not?

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  • finding and returning a string with a specified prefix

    - by tipu
    I am close but I am not sure what to do with the restuling match object. If I do p = re.search('[/@.* /]', str) I'll get any words that start with @ and end up with a space. This is what I want. However this returns a Match object that I dont' know what to do with. What's the most computationally efficient way of finding and returning a string which is prefixed with a @? For example, "Hi there @guy" After doing the proper calculations, I would be returned guy

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  • A good data model for finding a user's favorite stories

    - by wings
    Original Design Here's how I originally had my Models set up: class UserData(db.Model): user = db.UserProperty() favorites = db.ListProperty(db.Key) # list of story keys # ... class Story(db.Model): title = db.StringProperty() # ... On every page that displayed a story I would query UserData for the current user: user_data = UserData.all().filter('user =' users.get_current_user()).get() story_is_favorited = (story in user_data.favorites) New Design After watching this talk: Google I/O 2009 - Scalable, Complex Apps on App Engine, I wondered if I could set things up more efficiently. class FavoriteIndex(db.Model): favorited_by = db.StringListProperty() The Story Model is the same, but I got rid of the UserData Model. Each instance of the new FavoriteIndex Model has a Story instance as a parent. And each FavoriteIndex stores a list of user id's in it's favorited_by property. If I want to find all of the stories that have been favorited by a certain user: index_keys = FavoriteIndex.all(keys_only=True).filter('favorited_by =', users.get_current_user().user_id()) story_keys = [k.parent() for k in index_keys] stories = db.get(story_keys) This approach avoids the serialization/deserialization that's otherwise associated with the ListProperty. Efficiency vs Simplicity I'm not sure how efficient the new design is, especially after a user decides to favorite 300 stories, but here's why I like it: A favorited story is associated with a user, not with her user data On a page where I display a story, it's pretty easy to ask the story if it's been favorited (without calling up a separate entity filled with user data). fav_index = FavoriteIndex.all().ancestor(story).get() fav_of_current_user = users.get_current_user().user_id() in fav_index.favorited_by It's also easy to get a list of all the users who have favorited a story (using the method in #2) Is there an easier way? Please help. How is this kind of thing normally done?

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  • Django: Sum on an date attribute grouped by month/year

    - by Sébastien Piquemal
    Hello, I'd like to put this query from SQL to Django: "select date_format(date, '%Y-%m') as month, sum(quantity) as hours from hourentries group by date_format(date, '%Y-%m') order by date;" The part that causes problem is to group by month when aggregating. I tried this (which seemed logical), but it didn't work : HourEntries.objects.order_by("date").values("date__month").aggregate(Sum("quantity"))

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  • Django: Determining if a user has voted or not

    - by TheLizardKing
    I have a long list of links that I spit out using the below code, total votes, submitted by, the usual stuff but I am not 100% on how to determine if the currently logged in user has voted on a link or not. I know how to do this from within my view but do I need to alter my below view code or can I make use of the way templates work to determine it? I have read http://stackoverflow.com/questions/1528583/django-vote-up-down-method but I don't quite understand what's going on ( and don't need any ofjavascriptery). Models (snippet): class Link(models.Model): category = models.ForeignKey(Category, blank=False, default=1) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) modified = models.DateTimeField(auto_now=True) url = models.URLField(max_length=1024, unique=True, verify_exists=True) name = models.CharField(max_length=512) def __unicode__(self): return u'%s (%s)' % (self.name, self.url) class Vote(models.Model): link = models.ForeignKey(Link) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) def __unicode__(self): return u'%s vote for %s' % (self.user, self.link) Views (snippet): def hot(request): links = Link.objects.select_related().annotate(votes=Count('vote')).order_by('-created') for link in links: delta_in_hours = (int(datetime.now().strftime("%s")) - int(link.created.strftime("%s"))) / 3600 link.popularity = ((link.votes - 1) / (delta_in_hours + 2)**1.5) if request.user.is_authenticated(): try: link.voted = Vote.objects.get(link=link, user=request.user) except Vote.DoesNotExist: link.voted = None links = sorted(links, key=lambda x: x.popularity, reverse=True) links = paginate(request, links, 15) return direct_to_template( request, template = 'links/link_list.html', extra_context = { 'links': links, }) The above view actually accomplishes what I need but in what I believe to be a horribly inefficient way. This causes the dreaded n+1 queries, as it stands that's 33 queries for a page containing just 29 links while originally I got away with just 4 queries. I would really prefer to do this using Django's ORM or at least .extra(). Any advice?

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  • I can't login to my Django app when debug is set to False

    - by Eric
    I have a very strange problem, and I don't know how to fix or debug it. Short Story: I get locked out of my Django app when Debug is set to False. Long story: Case 1 (the first time it happened): 1. I enter my login info, but It just redirects to the login page. 2. I restart the server, try to login, and it works fine, I get in. 3. a few hours later I come back, log out, try to log back in and I can't. It just redirects to the login page. Case 2 (I figure out how to provoke the login failure): 1. I restart the server and am able to login to the site. 2. I log in and log out several times, everything is fine. 3. I go to a non-existing page and get a server error. 4. I log out and try to log back in, and I can't, just get redirected back to the login page. Case 3 (I can't provoke the login failure with Debug set to True): 1. I restart the server and am able to login to the site. 2. I log in and log out several times, everything is fine. 3. I go to a non-existing page and get a traceback. 4. I log out and log back in, everything works. 5. I wait and play around with it and can't get the login to fail while in Debug mode. Please help!

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  • argparse coding issue

    - by Carl Skonieczny
    write a script that takes two optional boolean arguments,"--verbose‚" and ‚"--live", and two required string arguments, "base"and "pattern". Please set up the command line processing using argparse. This is the code I have so far for the question, I know I am getting close but something is not quite right. Any help is much appreciated.Thanks for all the quick useful feedback. def main(): import argparse parser = argparse.ArgumentParser(description='') parser.add_argument('base', type=str) parser.add_arguemnt('--verbose', action='store_true') parser.add_argument('pattern', type=str) parser.add_arguemnt('--live', action='store_true') args = parser.parse_args() print(args.base(args.pattern))

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  • google contacts api service account oauth2.0 sub user

    - by user3709507
    I am trying to use the Google Contacts API to connect to a user's contact information, on my Google apps domain. Generating an access_token using the gdata api's ContactsService clientlogin function while using the API key for my project works fine, but I would prefer to not store the user's credentials, and from the information I have found that method uses OAuth1.0 So, to use OAuth2.0 I have: Generated a Service Account in the developer's console for my project Granted access to the service account for the scope of https://www.google.com/m8/feeds/ in the Google apps domain admin panel Attempted to generate credentials using SignedJwtAssertionCredentials: credentials = SignedJwtAssertionCredentials( service_account_name=service_account_email, private_key=key_from_p12_file, scope='https://www.google.com/m8/feeds/', sub=user_email') The problem I am running into is that attempting to generate an access token using this method fails. It succeeds in generating the token when I remove the sub parameter, but then that token fails when I try to fetch the user's contacts. Does anyone know why this might be happening?

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  • How to exclude results with get_object_or_404?

    - by googletorp
    In Django you can use the exclude to create SQL similar to not equal. An example could be. Model.objects.exclude(status='deleted') Now this works great and exclude is very flexible. Since I'm a bit lazy, I would like to get that functionality when using get_object_or_404, but I haven't found a way to do this, since you cannot use exclude on get_object_or_404. What I want is to do something like this: model = get_object_or_404(pk=id, status__exclude='deleted') But unfortunately this doesn't work as there isn't an exclude query filter or similar. The best I've come up with so far is doing something like this: object = get_object_or_404(pk=id) if object.status == 'deleted': return HttpResponseNotfound('text') Doing something like that, really defeats the point of using get_object_or_404, since it no longer is a handy one-liner. Alternatively I could do: object = get_object_or_404(pk=id, status__in=['list', 'of', 'items']) But that wouldn't be very maintainable, as I would need to keep the list up to date. I'm wondering if I'm missing some trick or feature in django to use get_object_or_404 to get the desired result?

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  • Django Piston - how can I create custom methods?

    - by orokusaki
    I put my questions in the code comments for clarity: from piston.handler import AnonymousBaseHandler class AnonymousAPITest(AnonymousBaseHandler): fields = ('update_subscription',) def update_subscription(self, request, months): # Do some stuff here to update a subscription based on the # number of months provided. # How the heck can I call this method? return {'msg': 'Your subscription has been updated!'} def read(self, request): return { 'msg': 'Why would I need a read() method on a fully custom API?' }

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  • Pyqt - QMenu dynamically populated and clicked

    - by mleep
    I need to be able to know what item I've clicked in a dynamically generated menu system. I only want to know what I've clicked on, even if it's simply a string representation. def populateShotInfoMenus(self): self.menuFilms = QMenu() films = self.getList() for film in films: menuItem_Film = self.menuFilms.addAction(film) self.connect(menuItem_Film, SIGNAL('triggered()'), self.onFilmSet) self.menuFilms.addAction(menuItem_Film) def onFilmRightClick(self, value): self.menuFilms.exec_(self.group1_inputFilm.mapToGlobal(value)) def onFilmSet(self, value): print 'Menu Clicked ', value

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  • can't use appcfg.py update gae

    - by user353998
    hello, recently i want to upload GAppProxy to GAE. but when i use the appcfg.py to update the files,there comes an error,it was: urllib2.URLError: urlopen error [Errno 8] _ssl.c:480: EOF occurred in violation of protocol i don't know why PS:i live in china,and may be because of the GFW. and when i use the type :appengine.google.com and then input the password,i can't redict to the index page,there is an error too,which says:ssl error

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  • How do you automatically remove the preview window after autocompletion in Vim?

    - by Ben Davini
    I'm using omnifunc=pythoncomplete. When autocompleting a word (e.g., os.), I get the list of eligible class members and functions, as expected, as well as a scratch buffer preview window with documentation about the selected member or function. This is great, but after selecting the function I want, the preview window remains. I can get rid of it with ":pc", but I'd like it just to automatically disappear after I've selected my function, a la Eclipse. I've played around with "completeopt" but to no avail.

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  • Problem opening Solr *.jsp pages with urllib2.urlopen.

    - by nestling
    I'm trying to open a page at http://localhost:8983/solr/admin/stats.jsp but urllib2.urlopen returns a blank string. It works fine for solr/ and solr/admin, but for all the pages above /solr/admin/ I get nothing but a blank string. 76]: t = urllib2.urlopen('http://localhost:8983/solr/admin/stats.jsp') 77]: s = t.read() 78]: s 78]: 79]: type(s) 79]: <type 'str'> 80]: urllib2.urlopen('http://localhost:8983/solr/admin/registry.jsp').read() 80]: In [84]: urllib2.urlopen('http://localhost:8983/solr/admin/schema.jsp').read() Out[84]: I know this isn't a problem with urllib2, but beyond that I am at a loss. I wish solr (or jetty) had an easy to get to log file, so that perhaps it could tell me its side of the story.

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  • Filtering with joined tables

    - by viraptor
    I'm trying to get some query performance improved, but the generated query does not look the way I expect it to. The results are retrieved using: query = session.query(SomeModel). options(joinedload_all('foo.bar')). options(joinedload_all('foo.baz')). options(joinedload('quux.other')) What I want to do is filter on the table joined via 'first', but this way doesn't work: query = query.filter(FooModel.address == '1.2.3.4') It results in a clause like this attached to the query: WHERE foos.address = '1.2.3.4' Which doesn't do the filtering in a proper way, since the generated joins attach tables foos_1 and foos_2. If I try that query manually but change the filtering clause to: WHERE foos_1.address = '1.2.3.4' AND foos_2.address = '1.2.3.4' It works fine. The question is of course - how can I achieve this with sqlalchemy itself?

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  • Filter across three tables using Django

    - by Vanessa MacDougal
    I have 3 django models, where the first has a foreign key to the second, and the second has a foreign key to the third. Like this: class Book(models.Model): year_published = models.IntField() author = models.ForeignKey(Author) class Author(models.Model): author_id = models.AutoField(primary_key=True) name = models.CharField(max_length=50) agent = models.ForeignKey(LitAgent) class LitAgent(models.Model): agent_id = models.AutoField(primary_key=True) name = models.CharField(max_length=50) I want to ask for all the literary agents whose authors had books published in 2006, for example. How can I do this in Django? I have looked at the documentation about filters and QuerySets, and don't see an obvious way. Thanks.

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  • Google App Engine getting verbose_name of a property from an instance

    - by Brian M. Hunt
    Given a model likeso: from google.appengine.ext import db class X(db.Model): p = db.StringProperty(verbose_name="Like p, but more modern.") How does one access verbose_name from x=X() (an instance of X)? One might expect that x.p.verbose_name would work, or alternatively x.properties()['p'].verbose_name, but neither seems to work. Thanks! EDIT: x.name.verbose_name = x.p.verbose_name

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