Search Results

Search found 14399 results on 576 pages for 'python noob'.

Page 387/576 | < Previous Page | 383 384 385 386 387 388 389 390 391 392 393 394  | Next Page >

  • How do I restrict foreign keys choices to related objects only in django

    - by Jeff Mc
    I have a two way foreign relation similar to the following class Parent(models.Model): name = models.CharField(max_length=255) favoritechild = models.ForeignKey("Child", blank=True, null=True) class Child(models.Model): name = models.CharField(max_length=255) myparent = models.ForeignKey(Parent) How do I restrict the choices for Parent.favoritechild to only children whose parent is itself? I tried class Parent(models.Model): name = models.CharField(max_length=255) favoritechild = models.ForeignKey("Child", blank=True, null=True, limit_choices_to = {"myparent": "self"}) but that causes the admin interface to not list any children.

    Read the article

  • How to retrieve items from a django queryset?

    - by sharataka
    I'm trying to get the video element in a queryset but am having trouble retrieving it. user_channel = Everything.objects.filter(profile = request.user, playlist = 'Channel') print user_channel[0] #returns the first result without error print user_channel[0]['video'] #returns error Models.py: class Everything(models.Model): profile = models.ForeignKey(User) playlist = models.CharField('Playlist', max_length = 2000, null=True, blank=True) platform = models.CharField('Platform', max_length = 2000, null=True, blank=True) video = models.CharField('VideoID', max_length = 2000, null=True, blank=True) video_title = models.CharField('Title of Video', max_length = 2000, null=True, blank=True) def __unicode__(self): return u'%s %s %s %s %s' % (self.profile, self.playlist, self.platform, self.video, self.video_title)

    Read the article

  • ndarray field names for both row and column?

    - by Graham Mitchell
    I'm a computer science teacher trying to create a little gradebook for myself using NumPy. But I think it would make my code easier to write if I could create an ndarray that uses field names for both the rows and columns. Here's what I've got so far: import numpy as np num_stud = 23 num_assign = 2 grades = np.zeros(num_stud, dtype=[('assign 1','i2'), ('assign 2','i2')]) #etc gv = grades.view(dtype='i2').reshape(num_stud,num_assign) So, if my first student gets a 97 on 'assign 1', I can write either of: grades[0]['assign 1'] = 97 gv[0][0] = 97 Also, I can do the following: np.mean( grades['assign 1'] ) # class average for assignment 1 np.sum( gv[0] ) # total points for student 1 This all works. But what I can't figure out how to do is use a student id number to refer to a particular student (assume that two of my students have student ids as shown): grades['123456']['assign 2'] = 95 grades['314159']['assign 2'] = 83 ...or maybe create a second view with the different field names? np.sum( gview2['314159'] ) # total points for the student with the given id I know that I could create a dict mapping student ids to indices, but that seems fragile and crufty, and I'm hoping there's a better way than: id2i = { '123456': 0, '314159': 1 } np.sum( gv[ id2i['314159'] ] ) I'm also willing to re-architect things if there's a cleaner design. I'm new to NumPy, and I haven't written much code yet, so starting over isn't out of the question if I'm Doing It Wrong. I am going to be needing to sum all the assignment points for over a hundred students once a day, as well as run standard deviations and other stats. Plus, I'll be waiting on the results, so I'd like it to run in only a couple of seconds. Thanks in advance for any suggestions.

    Read the article

  • find whether the string starts and ends with the same word

    - by Ajax
    I am trying to check whether the string starts and ends with the same word. egearth. s=raw_input(); m=re.search(r"^(earth).*(earth)$",s) if m is not None: print "found" my problem is when the string consists only of one word eg: earth At present I have hard coded this case by if m is not None or s=='earth': print "found" Is there any other way to do this? EDIT: words in a string are separated by spaces. looking for a regex solution some examples: "earth is earth" ,"earth", -- valid "earthearth", "eartheeearth", "earth earth mars" -- invalid

    Read the article

  • SQLAlchemy autocommiting?

    - by muckabout
    I have an issue with SQLAlchemy apparently committing. A rough sketch of my code: trans = self.conn.begin() try: assert not self.conn.execute(my_obj.__table__.select(my_obj.id == id)).first() self.conn.execute(my_obj.__table__.insert().values(id=id)) assert not self.conn.execute(my_obj.__table__.select(my_obj.id == id)).first() except: trans.rollback() raise I don't commit, and the second assert always fails! In other words, it seems the data is getting inserted into the database even though the code is within a transaction! Is this assessment accurate?

    Read the article

  • My QFileSystemModel doesn't work as expected in PyQt

    - by Skilldrick
    I'm learning the Qt Model/View architecture at the moment, and I've found something that doesn't work as I'd expect it to. I've got the following code (adapted from Qt Model Classes): from PyQt4 import QtCore, QtGui model = QtGui.QFileSystemModel() parentIndex = model.index(QtCore.QDir.currentPath()) print model.isDir(parentIndex) #prints True print model.data(parentIndex).toString() #prints name of current directory childIndex = model.index(0, 0, parentIndex) print model.data(childIndex).toString() rows = model.rowCount(parentIndex) print rows #prints 0 (even though the current directory has directory and file children) The question: Is this a problem with PyQt, have I just done something wrong, or am I completely misunderstanding QFileSystemModel? According to the documentation, model.rowCount(parentIndex) should return the number of children in the current directory. The QFileSystemModel docs say that it needs an instance of a Gui application, so I've also placed the above code in a QWidget as follows, but with the same result: import sys from PyQt4 import QtCore, QtGui class Widget(QtGui.QWidget): def __init__(self, parent=None): QtGui.QWidget.__init__(self, parent) model = QtGui.QFileSystemModel() parentIndex = model.index(QtCore.QDir.currentPath()) print model.isDir(parentIndex) print model.data(parentIndex).toString() childIndex = model.index(0, 0, parentIndex) print model.data(childIndex).toString() rows = model.rowCount(parentIndex) print rows def main(): app = QtGui.QApplication(sys.argv) widget = Widget() widget.show() sys.exit(app.exec_()) if __name__ == '__main__': main()

    Read the article

  • App Engine Django Form Uniqueness Validation?

    - by GeekTantra
    Is there a simpler way to use uniqueness validation with Django Forms in AppEngine? I understand that performance would be problem if we keep an uniqueness constraint but since the amount of data being added is very small performance is not a big concern, rather development time is a concern here. Any help is appreciated.

    Read the article

  • Element not found blocks execution in Selenium

    - by Mariano
    In my test, I try to verify if certain text exists (after an action) using find_element_by_xpath. If I use the right expression and my test pass, the routine ends correctly in no time. However if I try a wrong text (meaning that the test will fail) it hangs forever and I have to kill the script otherwise it does not end. Here is my test (the expression Thx user, client or password you entered is incorrect does not exist in the system, no matter what the user does): # -*- coding: utf-8 -*- import gettext import unittest from selenium import webdriver class TestWrongLogin(unittest.TestCase): def setUp(self): self.driver = webdriver.Firefox() self.driver.get("http://10.23.1.104:8888/") # let's check the language try: self.lang = self.driver.execute_script("return navigator.language;") self.lang = self.lang("-")[0] except: self.lang = "en" language = gettext.translation('app', '/app/locale', [self.lang], fallback=True) language.install() self._ = gettext.gettext def tearDown(self): self.driver.quit() def test_wrong_client(self): # test wrong client inputElement = self.driver.find_element_by_name("login") inputElement.send_keys("root") inputElement = self.driver.find_element_by_name("client") inputElement.send_keys("Unleash") inputElement = self.driver.find_element_by_name("password") inputElement.send_keys("qwerty") self.driver.find_element_by_name("form.submitted").click() # wait for the db answer self.driver.implicitly_wait(10) ret = self.driver.find_element_by_xpath( "//*[contains(.,'{0}')]".\ format(self._(u"Thx user, client or password you entered is incorrect"))) self.assertTrue(isinstance(ret, webdriver.remote.webelement.WebElement)) if __name__ == '__main__': unittest.main() Why does it do that and how can I prevent it?

    Read the article

  • Assign variable with variable in function

    - by freakazo
    Let's say we have def Foo(Bar=0,Song=0): print(Bar) print(Song) And I want to assign any one of the two parameters in the function with the variable sing and SongVal: Sing = Song SongVal = 2 So that it can be run like: Foo(Sing=SongVal) Where Sing would assign the Song parameter to the SongVal which is 2. The result should be printed like so: 0 2 So should I rewrite my function or is it possible to do it the way I want to? (With the code above you get an error saying Foo has no parameter Sing. Which I understand why, any way to overcome this without rewriting the function too much? Thanks in advance!

    Read the article

  • How do I create a Django ModelForm, so that it's fields are sometimes required, sometimes not?

    - by Graf
    Ok, here is the question. Imagine I have a ModelForm which have only two fields. like this one: class ColorForm(forms.Form): color_by_name = forms.CharField() color = forms.IntegerField(widget = forms.Select(choices=COLOR_CHOICES)) So a user can either input a color name, a choose it from a list. Color is required, but that doesn't mean, that user should enter it manually. There do I put validation, so that my code checks if user selected color in dropdownlist and if not then he should write it manually?

    Read the article

  • How to extend the Turbogears 2.1 login functionality

    - by Marc
    I'm using Turbogears 2.1 and repoze.who/what and am having trouble figuring out how to extend the basic authentication functionality. I am essentially attempting to require users to activate their account via an emailed link before they can login. If they try to login without activating their account, I want to display an appropriate error message. The default Turbogears functionality simply displays one message for all errors. I created my own authentication plugin which works fine. It won't allow users to login if they have not activated their account. However, the problem comes when I try to create the form and display custom error messages. How can I go about doing this? Thanks

    Read the article

  • threading.local equivalent for twisted.web?

    - by defnull
    In asynchronous environments, threading.local is not guaranteed to be context-local anymore, because several contexts may coexist within a single thread. Most asynchronous frameworks (gevent, eventlet) provide a get_current_context() functionality to identify the current context. Some offer a way to monkey-patch threading.local so it is local to 'greenthreads' or other framework-specific contexts. I cannot find such a functionality in the twisted documentation. How do I do this?

    Read the article

  • Django: Determining if a user has voted or not

    - by TheLizardKing
    I have a long list of links that I spit out using the below code, total votes, submitted by, the usual stuff but I am not 100% on how to determine if the currently logged in user has voted on a link or not. I know how to do this from within my view but do I need to alter my below view code or can I make use of the way templates work to determine it? I have read http://stackoverflow.com/questions/1528583/django-vote-up-down-method but I don't quite understand what's going on ( and don't need any ofjavascriptery). Models (snippet): class Link(models.Model): category = models.ForeignKey(Category, blank=False, default=1) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) modified = models.DateTimeField(auto_now=True) url = models.URLField(max_length=1024, unique=True, verify_exists=True) name = models.CharField(max_length=512) def __unicode__(self): return u'%s (%s)' % (self.name, self.url) class Vote(models.Model): link = models.ForeignKey(Link) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) def __unicode__(self): return u'%s vote for %s' % (self.user, self.link) Views (snippet): def hot(request): links = Link.objects.select_related().annotate(votes=Count('vote')).order_by('-created') for link in links: delta_in_hours = (int(datetime.now().strftime("%s")) - int(link.created.strftime("%s"))) / 3600 link.popularity = ((link.votes - 1) / (delta_in_hours + 2)**1.5) if request.user.is_authenticated(): try: link.voted = Vote.objects.get(link=link, user=request.user) except Vote.DoesNotExist: link.voted = None links = sorted(links, key=lambda x: x.popularity, reverse=True) links = paginate(request, links, 15) return direct_to_template( request, template = 'links/link_list.html', extra_context = { 'links': links, }) The above view actually accomplishes what I need but in what I believe to be a horribly inefficient way. This causes the dreaded n+1 queries, as it stands that's 33 queries for a page containing just 29 links while originally I got away with just 4 queries. I would really prefer to do this using Django's ORM or at least .extra(). Any advice?

    Read the article

  • Where is the help.py for Android's monkeyrunner

    - by Keyboardsurfer
    Hi, I just can't find the help.py file in order to create the API reference for the monkeyrunner. The command described at the Android references monkeyrunner <format> help.py <outfile> does not work when i call monkeyrunner html help.py /path/to/place/the/doc.html. It's quite obvious that the help.py file is not found and the monkeyrunner also tells me "Can't open specified script file". But a locate on my system doesn't bring me a help.py file that has anything to do with monkeyrunner or Android. So my question is: Where did they hide the help.py file for creating the API reference?

    Read the article

  • Write xml file with lxml

    - by systempuntoout
    Having a code like this: from lxml import etree root = etree.Element("root") root.set("interesting", "somewhat") child1 = etree.SubElement(root, "test") How do i write root Element object to an xml file using write() method of ElementTree class?

    Read the article

  • Simple wxPython Frame Contents Resizing - Ratio?

    - by Wes
    I have a wxPython app with one frame and one panel. On that panel are a number of static boxes, each of which has buttons and textboxes. I have just begun reading about sizers, but they seem like they might be more than what I need, or it could that they are exactly what I need but I don't know how to use them correctly! The frame currently opens at 1920 x 1080. If the user drags the bottom right corner to resize the app, I just want everything to get smaller or larger as needed to keep the same size ratio. Is this possible? Thank you! edit: additional info: I used wxPython 2.8 and Boa to construct the GUI. I am contemplating trying another gui ide. So after reading some more about sizers, I am thinking about doing the following: add a gridsizer and basically divide my window's elements into rows and columns, then set each row and column's size as necessary until I achieve the original layout. Then I guess set the rows and columns to resize correctly? Is this a decent idea?

    Read the article

  • Django, url tag in template doesn't work: NoReverseMatch

    - by Lukasz Jocz
    I've encountered a problem with generating reverse url in templates in django. I'm trying to solve it since a few hours and I have no idea what the problem might be. URL reversing works great in models and views: # like this in models.py @models.permalink def get_absolute_url(self): return ('entry', (), { 'entry_id': self.entry.id, }) # or this in views.py return HttpResponseRedirect(reverse('entry',args=(entry_id,))) but when I'm trying to make it in template I get such an error: NoReverseMatch at /entry/1/ Reverse for ''add_comment'' with arguments '(1L,)' and keyword arguments '{}' not found. My file structure looks like this: project/ +-- frontend ¦   +-- models.py ¦   +-- urls.py ¦   +-- views.py +-- settings.py +-- templates ¦   +-- add_comment.html ¦   +-- entry.html +-- utils ¦   +-- with_template.py +-- wsgi.py My urls.py: from project.frontend.views import * from django.conf.urls import patterns, include, url urlpatterns = patterns('project.frontend.views', url(r'^entry/(?P<entry_id>\d+)/', 'entry', name="entry"), (r'^entry_list/', 'entry_list'), Then entry_list.html: {% extends "base.html" %} {% block content %} {% for entry in entries %} {% url 'entry' entry.id %} {% endfor %} {% endblock %} In views.py I have: @with_template def entry(request, entry_id): entry = Entry.objects.get(id=entry_id) entry.comments = entry.get_comments() return locals() where with_template is following decorator(but I don't think this is a case): class TheWrapper(object): def __init__(self, default_template_name): self.default_template_name = default_template_name def __call__(self, func): def decorated_func(request, *args, **kwargs): extra_context = kwargs.pop('extra_context', {}) dictionary = {} ret = func(request, *args, **kwargs) if isinstance(ret, HttpResponse): return ret dictionary.update(ret) dictionary.update(extra_context) return render_to_response(dictionary.get('template_name', self.default_template_name), context_instance=RequestContext(request), dictionary=dictionary) update_wrapper(decorated_func, func) return decorated_func if not callable(arg): return TheWrapper(arg) else: default_template_name = ''.join([ arg.__name__, '.html']) return TheWrapper(default_template_name)(arg) Do you have any idea, what may cause the problem? Great thanks in advance!

    Read the article

  • Getting the previous line in Jython

    - by kdev
    I want to print the line immediately before the searched string. How can I do that? Lets say my two lines are AADRG SDFJGKDFSDF and I am searching for SDF. I have found SDFJGKDFSDF, but how can I obtain the previous line AADRG? Does file.readline()-1 work?

    Read the article

< Previous Page | 383 384 385 386 387 388 389 390 391 392 393 394  | Next Page >