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  • How do i know in the detail view what cell in tableview was selected?

    - by Daniel Rotaru
    how can i know what tableview cell was selected?(being in the detail view) The problem is that. I have an table view controller. Here are parsed from the internet entries to the table. So it's a dynamic tabe view that loads from internet. I will not know how many entries will be in the table so i will not know what details view to call when i click a row. So i have maked one view. This view contains an calendar. On this calendar(wich is the detail iew) i will parse data from internet depending on the selected row. For exemple: i have table: entry 1, entry 2,entry 3,entry 4 When i click entry 2 i need to call a php with the argument entry 2. The php will know what entry on the table i have selected and will generate me the correct xml that i will parse. Here is my tableview didSelectRow function: - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { // Navigation logic -- create and push a new view controller if(bdvController == nil) bdvController = [[BookDetailViewController alloc] initWithNibName:@"BookDetailView" bundle:[NSBundle mainBundle]]; Villa *aVilla = [appDelegate.villas objectAtIndex:indexPath.row]; [self.navigationController pushViewController:bdvController animated:YES] And here is my self view function on detailviewcontroller: -(void)loadView { [super loadView]; self.title=@"Month" UIBarButtonItem *addButtonItem = [[UIBarButtonItem alloc] initWithTitle:@"ListView" style:UIBarButtonItemStyleDone target:self action:@selector(add:)]; self.navigationItem.rightBarButtonItem = addButtonItem; calendarView = [[[KLCalendarView alloc] initWithFrame:CGRectMake(0.0f, 0.0f, 320.0f, 373.0f) delegate:self] autorelease]; appDelegate1 = (XMLAppDelegate *)[[UIApplication sharedApplication] delegate]; myTableView=[[UITableView alloc]initWithFrame:CGRectMake(0, 260, 320, 160)style:UITableViewStylePlain]; myTableView.dataSource=self; myTableView.delegate=self; UIView *myHeaderView=[[UIView alloc]initWithFrame:CGRectMake(0, 0, myTableView.frame.size.width,2)]; myHeaderView.backgroundColor=[UIColor grayColor]; [myTableView setTableHeaderView:myHeaderView]; [self.view addSubview:myTableView]; [self.view addSubview:calendarView]; [self.view bringSubviewToFront:myTableView]; } I think that here in self load i need to make the if procedure.. If indexPath.row=x parse fisier.php?variabila=title_of_rowx but the question is how i know the indexPath variable?

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  • Request URL in Javascript, Fetch URL Content using Java Applet, return to Javascript?

    - by Sam G
    I'm in the process of making a little experiment, it grabs a YouTube page, and returns the highest quality MP4 link, then plays this in a HTML 5 Video element. Now I was using PHP with cURL to get the URL content (YouTube), but that only works on my local server (MP4 link is locked to IP address). I can't think of any other way to get the page content due to cross domain rules except a Java applet. So I've built a Java applet that should return the content of a URL. Java import java.applet.Applet; import java.awt.*; import java.io.ByteArrayOutputStream; import java.io.InputStream; import java.net.HttpURLConnection; import java.net.URL; public class URLFetcherabc extends Applet { public void init() { } public void paint(Graphics g) { g.drawString("Java loaded. Waiting for URL", 0, 10); } public String getURL(String url, String httpMethod) { try { URL u = new URL(url); HttpURLConnection conn = (HttpURLConnection)u.openConnection(); conn.setRequestMethod(httpMethod); InputStream is = conn.getInputStream(); ByteArrayOutputStream output = new ByteArrayOutputStream(); byte[] buffer = new byte[1024]; for (int bytesRead = 0; (bytesRead = is.read(buffer)) != -1; ) { output.write(buffer, 0, bytesRead); } return output.toString(); } catch (Exception e) { }return null; } } Now I've got the applet on the page, but every-time I call the function it returns nothing. Heres my HTML for including the applet. HTML <applet id="URLFetcher" name="URLFetcher" code="URLFetcherabc.class" archive="URLFetcher.jar" height="200" width="200" mayscript=""></applet> Java-Script function fetchurl(urltofetch) { var URLFetcher = document.getElementById("URLFetcher"); var result = URLFetcher.getURL(urltofetch); //Result = URL Content return result; } The function always returns null, in Java the function does work when passed a variable via other means (parameter etc). I've tried running other functions through Javascript and the Java applet does respond. I'm new to Java applets and communicating with them via Javascript, so I'm probably making either a small mistake somewhere or its completely wrong. Any ideas? Thanks

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  • Cocoa WebView won't render all images on OSX 10.8

    - by user2906962
    I'm currently developing an application for OS X, backwards compatible with OS X 10.6. At some point I create a WebView in which I load html content that I create dynamically. The html content is formed only of image links <img src= and text, there is no javascript or anything of that kind. All the images (there are only 5 png images) are stored locally and their size is 4 KB. The problem I have is that some images (those that are not on the visible side of the "scroll"), the very first time I run the application,the images are not shown unless I drag the window to another screen or load again the view controller that contains the WebView. In those cases the images appear on the "scroll" even if they are offsite. I've tried creating the WebView both with IB and programatically, I've used WebPreferences like Autosaves, AllowsAnimatedImages … I've tried using NSURLCache to load each image so that the WebView will get access to them easier ... same result. Taking into account that my code is quite extensive I'm gonna post only the bits that I think are relevant: NSString *finalHtml ... //contains the complete html CGRect screenRect = [self.fixedView bounds]; CGRect webFrame = CGRectMake(0.0f, 0.0f, screenRect.size.width, screenRect.size.height); self.miwebView=[[WebView alloc] initWithFrame:webFrame]; [self.miwebView setEditable:NO]; [self.miwebView setUIDelegate:self]; ... NSURLCache *URLCache = [[NSURLCache alloc] initWithMemoryCapacity:4 * 1024 * 1024 diskCapacity:20 * 1024 * 1024 diskPath:nil]; [NSURLCache setSharedURLCache:URLCache]; NSString *imagePath = [[NSBundle mainBundle] pathForResource:@"line" ofType:@"png"]; NSURL *resourceUrl = [NSURL URLWithString:imagePath]; NSURLRequest *request = [NSURLRequest requestWithURL:resourceUrl cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:10.0f]; [URLCache cachedResponseForRequest:request]; ... [self.miwebView setResourceLoadDelegate:self]; WebPreferences *webPref = [[WebPreferences alloc]init]; [webPref setAutosaves:YES]; [webPref setAllowsAnimatedImages:YES]; [webPref setAllowsAnimatedImageLooping:YES]; [self.miwebView setPreferences:webPref]; NSString *pathResult = [[NSBundle mainBundle] bundlePath]; NSURL *baseURLRes = [NSURL fileURLWithPath:pathResult]; [[self.miwebView mainFrame] loadHTMLString:finalHtml baseURL:baseURLRes]; [self.fixedView addSubview:self.miwebView]; I should also mention that if an image is caught somewhere in between the visible and non visible side of the "scroll" only the visible bit of the image is going to be rendered even if the page gets scrolled up ... so I think all this is some rendering issue ... I appreciate your help, thank you!

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  • What's causing this background-image to display "incorrectly" in Opera and Firefox?

    - by Sukasa
    I know this is something I'm probably doing wrong, so please don't incinerate me for the thread title. I'm trying to put together a small personal website using HTML 5/CSS3. I've checked with the w3c validator and the site and CSS file fully conform according to the validator (However the validator has a warning attached that it might not be perfect). I'm not sure how to explain it without a picture, so here's a comparison of Chrome/Opera/Firefox: So, you can sorta see how in Chrome the background image is in one non-repeating piece, whereas in Opera/Firefox the image has, oddly, been broken up and placed slightly differently. I'm confident this is due to an error on my part, but I've had no luck at all figuring out why the image is being mangled in Opera and Firefox. Here's the CSS that's relevant to this issue: /* Content Pane */ .content { position: absolute; left: 220px; width: 800px; top: 80px; min-height: 550px; background-color: rgba(8,12,42,0.85); } /* Headers */ .content hgroup { background: url("Header_Flat.png") no-repeat left top; min-height: 38px; padding-left: 28px; text-shadow: 0 0 8px #FFA9FF; color: Black; text-decoration: none; } .content hgroup h1 { display: block; } .content hgroup h3 { display: inline; position: relative; top: -12px; left: 20px; text-shadow: 0 0 6px #AFF9FF; } .content hgroup h4 { display: inline; position: relative; top: -12px; left: 20px; font-size: xx-small; text-shadow: 0 0 6px #AFF9FF; } And the HTML: <hgroup> <h1>New Site!</h1> <h3>Now with Bloom!</h3> <h4> - Posted Tuesday, May 11th 2010</h4> </hgroup> Can anyone see what I'm doing wrong?

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  • NullPointerException on TextView

    - by Stephen Adipradhana
    i get a null pointer exception and the program crash on each time i want to update the highscore text using setText(). what causes this problem? this code is when i set my layout, the layout is a part of the gameView using opengl, and i put the highscore textview on the upper left corner public void onCreate(Bundle savedInstanceState) { SFEngine.display = ((WindowManager)getSystemService(Context.WINDOW_SERVICE)).getDefaultDisplay();//ambl ukuran width height layar super.onCreate(savedInstanceState); gameView = new SFGameView(this); gameView.setLayoutParams(new RelativeLayout.LayoutParams(LayoutParams.MATCH_PARENT, LayoutParams.MATCH_PARENT)); RelativeLayout layout = new RelativeLayout(this); layout.setLayoutParams(new FrameLayout.LayoutParams(LayoutParams.MATCH_PARENT, LayoutParams.MATCH_PARENT)); TextView textBox = new TextView(this); textBox.setId(1); textBox.setText("HIGH SCORE"); textBox.setBackgroundColor(Color.BLUE); textBox.setWidth(SFEngine.display.getWidth()/2); textBox.setHeight(50); Button pauseButton = new Button(this); pauseButton.setText("PAUSE"); pauseButton.setHeight(50); pauseButton.setWidth(SFEngine.display.getWidth()/2); pauseButton.setOnTouchListener(new OnTouchListener(){ public boolean onTouch(View v, MotionEvent e) { //pause game SFEngine.isPlaying = false; Intent i1 = new Intent(SFGames.this, pause.class); gameView.onPause(); startActivityForResult(i1,0);//hrs pk result soalny mw blk lg return true; } }); RelativeLayout.LayoutParams lp_pause = new RelativeLayout.LayoutParams(RelativeLayout.LayoutParams.WRAP_CONTENT, RelativeLayout.LayoutParams.WRAP_CONTENT); RelativeLayout.LayoutParams lp_hs = new RelativeLayout.LayoutParams(RelativeLayout.LayoutParams.WRAP_CONTENT, RelativeLayout.LayoutParams.WRAP_CONTENT); lp_hs.addRule(RelativeLayout.ALIGN_PARENT_LEFT); lp_pause.addRule(RelativeLayout.ALIGN_PARENT_TOP); lp_pause.addRule(RelativeLayout.ALIGN_PARENT_RIGHT); textBox.setLayoutParams(lp_hs); pauseButton.setLayoutParams(lp_pause); layout.addView(gameView); layout.addView(textBox); layout.addView(pauseButton); setContentView(layout); and here is the setText code public boolean onTouchEvent (MotionEvent event){//buat nerima input user if(!SFEngine.isPlaying){ finish(); } textBox.setText("High Score :" + SFEngine.score);//here is the source of the prob .....

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  • Returning the Name of a column header

    - by Jason Kelly
    I need your help, Given the html table below, how can I create a javascript function that will, at the click of a mouse, alert me the name of the column header? Ie. if I click on the COLORS header, a javascript box will popup and alert("COLORS")? <html> <head> </head> <body> <table border="1" cellspacing="1" width="500"> <tr> <td>FRUITS</td> <td>COLORS</td> <td>VEGGIES</td> <td>NUMBERS</td> </tr> <tr> <td>apples</td> <td>red</td> <td>carrots</td> <td>123</td> </tr> <tr> <td>oranges</td> <td>blue</td> <td>celery</td> <td>456</td> </tr> <tr> <td>pears</td> <td>green</td> <td>brocoli</td> <td>789</td> </tr> <tr> <td>mangos</td> <td>yellow</td> <td>lettuce</td> <td>098</td> </tr> </table> </body> </html>

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  • PHP create page as a string after PHP runs

    - by John
    I'm stuck on how to write the test.php page result (after php has run) to a string: testFunctions.php: <?php function htmlify($html, $format){ if ($format == "print"){ $html = str_replace("<", "&lt;", $html); $html = str_replace(">", "&gt;", $html); $html = str_replace("&nbsp;", "&amp;nbsp;", $html); $html = nl2br($html); return $html; } }; $input = <<<HTML <div style="background color:#959595; width:400px;"> &nbsp;<br> input <b>text</b> <br>&nbsp; </div> HTML; function content($input, $mode){ if ($mode =="display"){ return $input; } else if ($mode =="source"){ return htmlify($input, "print"); }; }; function pagePrint($page){ $a = array( 'file_get_contents' => array($page), 'htmlify' => array($page, "print") ); foreach($a as $func=>$args){ $x = call_user_func_array($func, $args); $page .= $x; } return $page; }; $file = "test.php"; ?> test.php: <?php include "testFunctions.php"; ?> <br><hr>here is the rendered html:<hr> <?php $a = content($input, "display"); echo $a; ?> <br><hr>here is the source code:<hr> <?php $a = content($input, "source"); echo $a; ?> <br><hr>here is the source code of the entire page after the php has been executed:<hr> <div style="margin-left:40px; background-color:#ebebeb;"> <?php $a = pagePrint($file); echo $a; ?> </div> I'd like to keep all the php in the testFunctions.php file, so I can place simple function calls into templates for html emails. Thanks!

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  • Can't parse XML from AJAX response.

    - by Pavel
    Hi everyone. I'm having some problems with parsing the xml response from my ajax script. The XML looks like this: <IMAGE> <a href="address"> <img width="300" height="300" src="image.png class="image" alt="" title="LINKING"/> </a> </IMAGE> <LINK> www.address.com </LINK> <TITLE> This <i>is title</i> </TITLE> <EXCERPT> <p> And some excerpt </p> </EXCERPT> The code for js looks like this. function loadTab(id) { if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { xmlDoc=xmlhttp.responseXML; var title=""; var image=""; x=xmlDoc.getElementsByTagName("TITLE"); for (i=0;i<1;i++) { title=title + x[i].childNodes[0].nodeValue; } document.getElementById("ntt").innerHTML=title; x1=xmlDoc.getElementsByTagName("IMAGE"); for (j=0;j<1;j++) { image=image + x1[j].childNodes[0].nodeValue; } document.getElementById("nttI").innerHTML=image; } } var url = 'http://www.factmag.com/staging/page/?id='+id; xmlhttp.open("GET",url,true); xmlhttp.send(); } When I'm parsing it it pulls out the title but not the IMAGE tag contents. What I'm doing wrong? Can someone please tell me? Thanks in advance!

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  • How to call a set of variables functions based on class on a group of elements

    - by user1547007
    I have the following html code: <i class="small ele class1"></i> <i class="medium ele class1"></i> <i class="large ele class1"></i> <div class="clear"></div> <i class="small ele class2"></i> <i class="medium ele class2"></i> <i class="large ele class2"></i> <div class="clear"></div> <i class="small ele class3"></i> <i class="medium ele class3"></i> <i class="large ele class3"></i> <div class="clear"></div> <i class="small ele class4"></i> <i class="medium ele class4"></i> <i class="large ele class4"></i>? And my javascript looks like so: var resize = function(face, s) { var bb = face.getBBox(); console.log(bb); var w = bb.width; var h = bb.height; var max = w; if (h > max) { max = h; } var scale = s / max; var ox = -bb.x+((max-w)/2); var oy = -bb.y+((max-h)/2); console.log(s+' '+h+' '+bb.y); face.attr({ "transform": "s" + scale + "," + scale + ",0,0" + "t" + ox + "," + oy }); } $('.ele').each(function() { var s = $(this).innerWidth(); var paper = Raphael($(this)[0], s, s); var face = $(this).hasClass("class1") ? class1Generator(paper) : class4Generator(paper); /*switch (true) { case $(this).hasClass('class1'): class1Generator(paper); break; case $(this).hasClass('class2'): class2Generator(paper) break; case $(this).hasClass('class3'): class3Generator(paper) break; case $(this).hasClass('class4'): class4Generator(paper) break; }*/ resize(face, s); }); my question is, how could I make this line of code more scalable? I tried using a switch but The script below is calling two functions if one of the elements has a class, but what If i have 10 classes? I don't think is the best solution I created a jsFiddle http://jsfiddle.net/7uUgz/6/ //var face = $(this).hasClass("awesome") ? awesomeGenerator(paper) : awfulGenerator(paper);

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  • JQuery Ajax Updating MySQL Database, But Not Running Success Function

    - by myrmidon16
    I am currently using the JQuery ajax function to call an exterior PHP file, in which I select and add data in a database. Once this is done, I run a success function in JavaScript. What's weird is that the database is updating successfully when ajax is called, however the success function is not running. Here is my code: <!DOCTYPE html> <head> <script type="text/javascript" src="jquery-1.6.4.js"></script> </head> <body> <div onclick="addtask();" style="width:400px; height:200px; background:#000000;"></div> <script> function addtask() { var tid = (Math.floor(Math.random() * 3)) + 1; var tsk = (Math.floor(Math.random() * 10)) + 1; if(tsk !== 1) { $.ajax({ type: "POST", url: "taskcheck.php", dataType: "json", data: {taskid:tid}, success: function(task) {alert(task.name);} }); } } </script> </body> </html> And the PHP file: session_start(); $connect = mysql_connect('x', 'x', 'x') or die('Not Connecting'); mysql_select_db('x') or die ('No Database Selected'); $task = $_REQUEST['taskid']; $uid = $_SESSION['user_id']; $q = "SELECT task_id, taskname FROM tasks WHERE task_id=" .$task. " LIMIT 1"; $gettask = mysql_fetch_assoc(mysql_query($q)); $q = "INSERT INTO user_tasks (ut_id, user_id, task_id, taskstatus, taskactive) VALUES (null, " .$uid. ", '{$gettask['task_id']}', 0, 1)"; $puttask = mysql_fetch_assoc(mysql_query($q)); $json = array( "name" => $gettask['taskname'] ); $output = json_encode($json); echo $output; Let me know if you have any questions or comments, thanks.

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  • jquery mouseover animation jumping

    - by Sylph
    Hi all, I have a table which is looped in <li>. On mouseover each row, there will be a border shown, and the row id="resFunc" will be displayed. However, in IE, the animation jumps up and down. Anyone has similar experience or solution to solve this? Thanks in advance! <div id="resDetails" align="left"> <table width="400px" class="resBox"> <tr> <td><b>{creator}</b></td> </tr> <tr> <td colspan="2"><div class="edit{_id}" id="{_id}"> {title}</div></td> </tr> <tr style="display:none" class="url{_id}"> <td colspan="2" class="edit_url{_id}" id="{_id}">{url}</td> </tr> <tr> <td colspan="2" class="edit_area{_id}" id="{_id}">{description}</td> </tr> <tr id="resFunc{_id}" style="display:none"> <td colspan="2" align="right"><b><a href="#" id="{_id}" class="editRes">Edit</a>&nbsp;&nbsp; <a href="#" class="deleteResource" id="{_id}">Delete</a></b> </td> </tr> </table><br> </div> This is the onClick function :- $(".resBox").mouseover(function(){ var id = $(this).attr("id"); $(this).addClass('highlight'); $('#resFunc'+id).show(); }); $(".resBox").mouseout(function(){ var id = $(this).attr("id"); $(this).removeClass('highlight'); $('#resFunc'+id).hide(); });

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  • Jquery question : maintain focus upon appending a row?

    - by PoppySeedsAndAppleJuice
    The function below checks whether the id entered is already in the database, and if it is, then it adds some html to the table. I'm not sure if it's directly related to my issue or not, but, essentially, a user will place the focus on the id input field and enters an id. Using ajax, it posts to a php script and returns data if rows are found and nothing if it doesn't. If the user then tabs over to the next input field (zipcode), or clicks in another input field, they essentially have to do so twice. The cursor "flashes" in the field briefly and then focuses out. I tried adding in a focus(), but the behavior didn't change. So, the html looks like this: <table id="tableSearchData" class="searchlist" style="width: 789px;"> <thead> <tr> <th>ID</th> <th>Zip Code</th> <th>Radius (in miles)</th> </tr> </thead> <tbody> <tr class="odd"> <!-- PROBLEM is described below --> <!-- User clicks in <input name="id[]"> and ID is checked --> <!-- User presses "tab" or clicks in <input name="zipcode[] (in the *same* row) and cursor flashes, then goes out of focus so that the user has to click in the field again --> <td class="center sorting_1"><input type="text" value="" name="id[]"></td> <td class="center"><input type="text" value="" name="zipcode[]"></td> <td class="center"><input type="text" value="" name="radius[]"></td> </tr> </tbody> </table> Here's the jquery function... Like I said, I'm not sure if it's directly related to the problem I'm having, but, thought I should include it because I suppose it's likely there is something happening there... $("#tableSearchData > tbody > tr > td > input[name=id[]]").focusout(function() { var row = $(this).closest("tr").get(0); var sData = $(this).serialize(); $.ajax({ type: "POST", url: "checkid.php", data: sData, success: function(html) { $(row).replaceWith(html); $(".preset").each(function() { $(this).attr("disabled", true); }); $(row).closest("input[name=zipcode[]]").focus(); } }); });

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  • How do I create a class in Javascript?

    - by William
    This is what I got so far, and it's not working at all :( <!DOCTYPE html> <html lang="en"> <head> <title>Class Test</title> <meta charset="utf-8" /> <style> body { text-align: center; background-color: #ffffff;} #box { position: absolute; left: 610px; top: 80px; height: 50px; width: 50px; background-color: #ff0000; color: #000000;} </style> <script type="text/javascript"> document.onkeydown=function(event){keyDown(event)}; document.onkeyup=function(event){keyUp(event)}; var box = 0; function Player () { var speed = 5; var x = 50; var y = 50; } function update() { box.style.left = this.x + "px"; box.style.top = this.y + "px"; box.innerHTML = "<h6 style=\"margin: 0px 0px 0px 0px; padding: 0px 0px 0px 0px;\">X: "+ this.x + "<br /> Y: " + this.y + "</h6>"; } var player = new Player(); var keys = new Array(256); var i = 0; for (i = 0;i <= 256; i++){ keys[i] = false; } function keyDown(event){ keys[event.keyCode] = true; } function keyUp(event){ keys[event.keyCode] = false; } function update(){ if(keys[37]) player.x -= player.speed; if(keys[39]) player.x += player.speed; player.update(); } setInterval(update, 1000/60); </script> </head> <body> <div id="box" ></div> <script type="text/javascript"> box = document.getElementById('box'); box.innerHTML = "<h6 style=\"margin: 0px 0px 0px 0px; padding: 0px 0px 0px 0px;\">X: "+ player.x + "<br /> Y: " + player.y + "</h6>"; </script> </body> </html>

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  • Hoe to convert a JSON array of paths to images stored on a server into a javaScript array to display them? Using AJAX

    - by MichaelF
    I need for html file/ ajax code to take the JSON message and store the PATHS as a javaScript array. Then my buildImage function can display the first image in the array. I'm new to AJAX and believe my misunderstanding lies within the converting of the JSON to Javascript. I'm confused also about if my code creates a JSON array or object or either. I might need also to download a library to my app to understand JSON? Below is a PHP file loading the paths of the images. I believe json ecode is converting the PHP Array in a Json message. <?php include("mysqlconnect.php"); $select_query = "SELECT `ImagesPath` FROM `offerstbl` ORDER by `ImagesId` DESC"; $sql = mysql_query($select_query) or die(mysql_error()); $data = array(); while($row = mysql_fetch_array($sql,MYSQL_BOTH)){ $data[] = $row['ImagesPath']; } echo $images = json_encode($data); ?> Below is the script in is going to be loaded on an Cordova app. <!DOCTYPE html> <html> <head> <link rel="stylesheet" href="css/styles.css"> <link rel="stylesheet" href="css/cascading.css"> <script> function importJson(str) { // console.log(typeof xmlhttp.responseText); if (str=="") { document.getElementById("content").innerHTML=""; return; } if (window.XMLHttpRequest) { // code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else { // code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4) { //var images = JSON.parse(xmlhttp.responseText); document.getElementById("content").innerHTML=xmlhttp.responseText; } } xmlhttp.open("GET","http://server/content.php"); xmlhttp.send(); } function buildImage(src) { var img = document.createElement('img') img.src = src alert("1"); document.getElementById('content').appendChild(img); } for (var i = 0; i < images.length; i++) { buildImage(images[i]); } </script> </head> <body onload= "importJson();"> <div class="contents" id="content" ></div> <img src="img/logo.png" height="10px" width="10px" onload= "buildImage();"> </body>

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  • Creating a multiplatform webapp with HTML5 and Google maps

    - by Bart L.
    I'm struggling how to develop a webapp for Android and iOS. My first app was a simple todo app which was easy to test in my browser and it only used html, javascript and css. However, I have to create an app which uses Google Maps Api to get the location. I created a simple html5 page to test which places a marker on a map. It works fine when testing it on my local server. But when I create an .apk file for Android, the app doesn't work. So I'm wondering, isn't it possible to use it like this? Do I have the use the phonegap libraries to use their geolocation library? And if so, how do you handle the development of a webapp in phonegap for multiple OS? Do you have to install an Android environment and an iOS environment to each include the right phonegap library and to test them properly? Update: I use the following code on my webserver and it works perfectly. When I upload it in a zip-folder to the photogap cloud and install the APK file on my phone, it doesn't work. <!DOCTYPE html> <html> <head> <meta charset="utf-8"> <title>Simple Geo test</title> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.8/jquery.min.js"></script> </head> <body> <script type="text/javascript" src="http://maps.google.com/maps/api/js?sensor=true"></script> <script> function success(position) { var mapcanvas = document.createElement('div'); mapcanvas.id = 'mapcontainer'; mapcanvas.style.height = '200px'; mapcanvas.style.width = '200px'; document.querySelector('article').appendChild(mapcanvas); var coords = new google.maps.LatLng(position.coords.latitude, position.coords.longitude); var options = { zoom: 15, center: coords, mapTypeControl: false, navigationControlOptions: { style: google.maps.NavigationControlStyle.SMALL }, mapTypeId: google.maps.MapTypeId.ROADMAP }; var map = new google.maps.Map(document.getElementById("mapcontainer"), options); var marker = new google.maps.Marker({ position: coords, map: map, title:"You are here!" }); } if (navigator.geolocation) { navigator.geolocation.getCurrentPosition(success); } else { error('Geo Location is not supported'); } </script> <article></article> </body> </html>

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  • form inside tabview doesn't work

    - by user3536737
    i am working with jsf and primefaces , and here is what 've tried well i want to creat a tabview that get data from an arraylist in my bean i get for exemple 4 tabs , and inside each one i've created a hidden panel where i have a form with 2 input text to update informations , do i display the panel when i click on the second button Update , after that my panel is not hidden anymore , and i set the new values and click on the second button to update the informations , the problem is that the updating and the execution is working only for the first tab , it means when i try to update the new informations it works for the first one and for the other tabs it doesn't here is the code <p:tab title="#{rr.nom_ressource}"> <h:panelGrid> <h:graphicImage value="Ressources/images/emp.jpg" style="vertical-align:middle" /> <span style="font-size:15px; width:170px; display:inline-block;"> Nom : #{rr.nom_ressource} Type: #{rr.type_ressource} Specification: #{rr.experience} </span> <h:commandButton image="Ressources/images/delete.jpg" actionListener="#{SelectBean.act}" update=":form" style="vertical-align:middle" > Update </h:commandButton> <h:commandButton update=":outPanel" actionListener="#{SelectBean.mod1()}" image="Ressources/images/update.png" style="vertical-align:middle" > Modifier </h:commandButton> <h:form id="form111"> <p:growl id="growl" showDetail="true" sticky="true" /> <p:panel rendered ="#{SelectBean.bol}" closable="true" toggleable="true" id="outPanel" styleClass="outPanel" widgetVar="outpanel"> <h:outputLabel value="Nom " /> <h:inputText value="#{SelectBean.nom}" /> <br/> <h:outputLabel value="Experience " /> <h:inputText value="#{SelectBean.exp}" /> <br/> <h:commandButton value="Update" action="#{SelectBean.done}"/> </p:panel> </h:form> </h:panelGrid> </p:tab> for my managedbean the code is correct i think the problem is here

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  • Any suggestions for improvement on this style for BDD/TDD?

    - by Sean B
    I was tinkering with doing the setups with our unit test specifciations which go like Specification for SUT when behaviour X happens in scenario Y Given that this thing And also this other thing When I do X... Then It should do ... And It should also do ... I wrapped each of the steps of the GivenThat in Actions... any feed back whether separating with Actions is good / bad / or better way to make the GivenThat clear? /// <summary> /// Given a product is setup for injection /// And Product Image Factory Is Stubbed(); /// And Product Size Is Stubbed(); /// And Drawing Scale Is Stubbed(); /// And Product Type Is Stubbed(); /// </summary> protected override void GivenThat() { base.GivenThat(); Action givenThatAProductIsSetupforInjection = () => { var randomGenerator = new RandomGenerator(); this.Position = randomGenerator.Generate<Point>(); this.Product = new Diffuser { Size = new RectangularProductSize( 2.Inches()), Position = this.Position, ProductType = Dep<IProductType>() }; }; Action andProductImageFactoryIsStubbed = () => Dep<IProductBitmapImageFactory>().Stub(f => f.GetInstance(Dep<IProductType>())).Return(ExpectedBitmapImage); Action andProductSizeIsStubbed = () => { Stub<IDisplacementProduct, IProductSize>(p => p.Size); var productBounds = new ProductBounds(Width.Feet(), Height.Feet()); Dep<IProductSize>().Stub(s => s.Bounds).Return(productBounds); }; Action andDrawingScaleIsStubbed = () => Dep<IDrawingScale>().Stub(s => s.PixelsPerFoot).Return(PixelsPerFoot); Action andProductTypeIsStubbed = () => Stub<IDisplacementProduct, IProductType>(p => p.ProductType); givenThatAProductIsSetupforInjection(); andProductImageFactoryIsStubbed(); andProductSizeIsStubbed(); andDrawingScaleIsStubbed(); andProductTypeIsStubbed(); }

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  • elisp: posn-at-point returns nil after goto-char. How to update the display before posn-at-point?

    - by Cheeso
    In emacs lisp, posn-at-point is documented as: posn-at-point is a built-in function in C source code. (posn-at-point &optional POS WINDOW) . Return position information for buffer POS in WINDOW. POS defaults to point in WINDOW; WINDOW defaults to the selected window. . Return nil if position is not visible in window. Otherwise, the return value is similar to that returned by event-start for a mouse click at the upper left corner of the glyph corresponding to the given buffer position: (WINDOW AREA-OR-POS (X . Y) TIMESTAMP OBJECT POS (COL . ROW) IMAGE (DX . DY) (WIDTH . HEIGHT)) The posn- functions access elements of such lists. ok, now I've got a function that looks something like this: (defun my-move-and-popup-menu () "move the point, then pop up a menu." (goto-char xxxx) (setq p (posn-at-point)) (my-popup-menu p ...) ) Basically, move the point, then retrieve the screen position at that point, and then popup a menu at that screen position. But I am finding that posn-at-point returns non-nil, only if the xxxx character position (the after position) is visible in the window, before the call to goto-char. It seems that the position is not actually updated until exit from the function. If goto-char goes a long way, more than one screenful, then the retrieved position is always nil, and my code doesn't know where to popup the menu. The reason I suggest that the position is not actually updated until exit from the function - when the menu successfully pops up, the cursor is clearly visible in its previous location while the popup menu is being displayed. When I dismiss the menu, the cursor moves to where I expected it to move, after the goto-char call. How can I get the position to be really updated, between goto-char and posn-at-point, so that posn-at-point will not return nil? In a Windows Forms application I would call Form.Update() or something similar to update the display in the middle of an event handler. What's the emacs version of that?

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  • Confusion over C++ new operator and classes

    - by Nils
    Hi all I created a simple class in C++ which has a private dynamic array. In the constructor I initialize the array using new and in the destructor I free it using delete. When I instantiate the class using Class a = Class(..); it works as expected, however it seems I cannot instantiate it using the new operator (Like Class *a = new Class(..);), I always get a segmentation fault. What I don't understand is when I should use new to instantiate a class and when just call the constructor or should it be possible to instantiate a class either with new or by just calling the constructor. float** A = new float*[3]; for (int i=0; i<3; i++) { A[i] = new float[3]; } A[0][0] = 3; A[0][1] = 3; A[0][2] = 4; A[1][0] = 5; A[1][1] = 6; A[1][2] = 7; A[2][0] = 1; A[2][1] = 2; A[2][2] = 3; Matrix *M = new Matrix(A, 3, 3); delete[] A; delete M; Below the class definition.. class Matrix { private: int width; int height; int stride; float* elements; public: Matrix(float** a, int n, int m); ~Matrix(); }; Matrix::Matrix(float** a, int n, int m) { // n: num rows // m: elem per rows elements = new float[n*m]; for (int i=0; i<n; i++) { for (int j=0; j<m; j++) { elements[i*n + j] = a[n][m]; } } } Matrix::~Matrix() { delete[] elements; }

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  • How to pass some data to JQuery AJAX in CAKEPHP

    - by kwokwai
    Hi all, I am learning how to use JQuery to help check data availability. To start with it, I wrote a few lines of codes using cakePHP. I have written a function in a Controller for checking data input, and the URL is like this: http://www.mywebsite.com/controllers/action/avariable I was trying to pass the value in a Input TextBox field using the JQuery Ajax to the URL above,but I don't know why it is not working in passing a variable to the Controller's action. Could you help me out please? <Script language="javascript"> //<!-- $(document).ready(function(){ $(document).change(function() { var usr = $("#data\\[User\\]\\[name\\]").val(); if(usr.length >= 3){ $("#username").append('<span><img align="absmiddle" src="loader.gif" />Checking</span>'); $.ajax({ type: "POST", url: "http://www.mywebsite.com/controllers/action/", data: usr, success: function(msg){ if(msg == 'OK') { $("#username").append('<span><img align="absmiddle" src="accepted.png"/></span>'); } else { $("#username").append('<span>'+msg+'</span>'); } } }); } else { $("#username").append('<span>The username should have at least 3 characters.</span>'); } }); }); //--> </Script> <form name="adduser" id="adduser" method="post" action="/controllers/action2"> <table border=0 width="100%"> <tr> <td>Username</td> <td> <div id="username"> <input type=text name="data[User][name]" id="data[User][name]"> </div> </td> </tr> <tr> <td> <input type="submit" value="Send"> </td> </tr> </table> </form>

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  • PHP - not sure how to ask - regarding variables and $_POST

    - by Phil
    I have a PHP form. The form works but I'm trying to test to see if a value other than the first item has been selected. I can't figure out how to write the If statement. $products = array( '' => 1, 'Item 2' => 2, 'Item 3' => 3, 'Item 4' => 4, 'Item 5' => 5, 'Item 6' => 6 ); $html = generateSelect('products', $products); function generateSelect($name = '', $options = array()) { $html = '<select name="'.$name.'">'; foreach ($options as $option => $value) { $html .= '<option value='.$value.'>'.$option.'</option>'; } $html .= '</select>'; return $html; } In my table, the drop down box is displayed: <tr> <td style="width:{$left_col_width}; text-align:left; vertical-align:center; padding:{$cell_padding}; font-weight:bold; {$product[3]}">{$product[0]}</td> <td style="text-align:left; vertical-align:top; padding:{$cell_padding};"><select name="{$product[1]}"> <option value="1"></option> <option value="2">Item 2</option> <option value="3">Item 3</option> <option value="4">Item 4</option> <option value="5">Item 5</option> <option value="6">Item 6</option> </select></td> </tr> I use the following if statement to check to see if someone has entered a phone number. if they have not entered a phone number, then the "Phone:" text turns red. How do I do an if statement similar to this to verify that someone has selected a product option from the drop down box? if(!empty($_POST['phone'])) { $phone[2] = clean_var($_POST['phone']); if (function_exists('htmlspecialchars')) $phone[2] = htmlspecialchars($phone[2], ENT_QUOTES); } else { $error = 1; $phone[3] = 'color:#d20128;'; } it seems simple but I can't figure it out.

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  • Unable to get Stencil Buffer to work in iOS 4+ (5.0 works fine). [OpenGL ES 2.0]

    - by MurderDev
    So I am trying to use a stencil buffer in iOS for masking/clipping purposes. Do you guys have any idea why this code may not work? This is everything I have associated with Stencils. On iOS 4 I get a black screen. On iOS 5 I get exactly what I expect. The transparent areas of the image I drew in the stencil are the only areas being drawn later. Code is below. This is where I setup the frameBuffer, depth and stencil. In iOS the depth and stencil are combined. -(void)setupDepthBuffer { glGenRenderbuffers(1, &depthRenderBuffer); glBindRenderbuffer(GL_RENDERBUFFER, depthRenderBuffer); glRenderbufferStorage(GL_RENDERBUFFER, GL_DEPTH24_STENCIL8_OES, self.frame.size.width * [[UIScreen mainScreen] scale], self.frame.size.height * [[UIScreen mainScreen] scale]); } -(void)setupFrameBuffer { glGenFramebuffers(1, &frameBuffer); glBindFramebuffer(GL_FRAMEBUFFER, frameBuffer); glFramebufferRenderbuffer(GL_FRAMEBUFFER, GL_COLOR_ATTACHMENT0, GL_RENDERBUFFER, colorRenderBuffer); glFramebufferRenderbuffer(GL_FRAMEBUFFER, GL_DEPTH_ATTACHMENT, GL_RENDERBUFFER, depthRenderBuffer); glFramebufferRenderbuffer(GL_FRAMEBUFFER, GL_STENCIL_ATTACHMENT, GL_RENDERBUFFER, depthRenderBuffer); // Check the FBO. if(glCheckFramebufferStatus(GL_FRAMEBUFFER) != GL_FRAMEBUFFER_COMPLETE) { NSLog(@"Failure with framebuffer generation: %d", glCheckFramebufferStatus(GL_FRAMEBUFFER)); } } This is how I am setting up and drawing the stencil. (Shader code below.) glEnable(GL_STENCIL_TEST); glDisable(GL_DEPTH_TEST); glColorMask(GL_FALSE, GL_FALSE, GL_FALSE, GL_FALSE); glDepthMask(GL_FALSE); glStencilFunc(GL_ALWAYS, 1, -1); glStencilOp(GL_KEEP, GL_KEEP, GL_REPLACE); glColorMask(0, 0, 0, 0); glClear(GL_STENCIL_BUFFER_BIT); machineForeground.shader = [StencilEffect sharedInstance]; [machineForeground draw]; machineForeground.shader = [BasicEffect sharedInstance]; glDisable(GL_STENCIL_TEST); glColorMask(GL_TRUE, GL_TRUE, GL_TRUE, GL_TRUE); glDepthMask(GL_TRUE); Here is where I am using the stencil. glEnable(GL_STENCIL_TEST); glStencilOp(GL_KEEP, GL_KEEP, GL_KEEP); glStencilFunc(GL_EQUAL, 1, -1); ...Draw Stuff here glDisable(GL_STENCIL_TEST); Finally here is my fragment shader. varying lowp vec2 TexCoordOut; uniform sampler2D Texture; void main(void) { lowp vec4 color = texture2D(Texture, TexCoordOut); if(color.a < 0.1) gl_FragColor = color; else discard; }

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  • video player for HTML 5 page not loading

    - by philippe
    I'm using VideoJS to as my video player for a project I've been working on. Basically I have a div, and I wanted to have the video player within that div, however when I load the page nothing happens, and the video is never played. In fact, the video is never loaded nor shown in the page. I basically copied the example from VideoJS' page. Any thoughts? <div class="video-js-box"> <!-- Using the Video for Everybody Embed Code http://camendesign.com/code/video_for_everybody --> <div style="position: absolute; top: 50px; left: 600px; display:none"> <video id="example_video_1" class="video-js vjs-default-skin" controls preload="auto" width="640" height="264" poster="http://video-js.zencoder.com/oceans-clip.png" data-setup='{"example_option":true}'> <source src="http://video-js.zencoder.com/oceans-clip.mp4" type='video/mp4'></source> <source src="http://video-js.zencoder.com/oceans-clip.webm" type='video/webm'>></source> <source src="http://video-js.zencoder.com/oceans-clip.ogv" type='video/ogg'></source> </video> <!-- Download links provided for devices that can't play video in the browser. --> <p class="vjs-no-video"><strong>Download Video:</strong> <a href="http://video-js.zencoder.com/oceans-clip.mp4">MP4</a>, <a href="http://video-js.zencoder.com/oceans-clip.webm">WebM</a>, <a href="http://video-js.zencoder.com/oceans-clip.ogv">Ogg</a><br> <!-- Support VideoJS by keeping this link. --> <a href="http://videojs.com">HTML5 Video Player</a> by VideoJS </p> </div> <div style="clear:both;"></div> </div><!--main-->

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  • How do you hide an image tag based on an ajax response?

    - by Chris
    What is the correct jquery statement to replace the "//Needed magic" comments below so that the image tags are hidden or unhidden based on the AJAX responses? <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>JQuery</title> <style type="text/css"> .isSolvedImage{ width: 68px; height: 47px; border: 1px solid red; cursor: pointer; } </style> <script src="_js/jquery-1.4.2.min.js" type="text/javascript"> </script> </head> <body> <div id='true1.txt' class='isSolvedImage'> <img src="_images/solved.png"> </div> <div id='false1.txt' class='isSolvedImage'> <img src="_images/solved.png"> </div> <div id='true2.txt' class='isSolvedImage'> <img src="_images/solved.png"> </div> <div id='false2.txt' class='isSolvedImage'> <img src="_images/solved.png"> </div> <script type="text/javascript"> $(function(){ var getDivs = 0; //iterate div with class isSolvedImage $("div.isSolvedImage").each(function() { alert('div id--'+this.id); // send ajax requrest $.get(this.id, function(data) { // check if ajax response is 1 alert('div id--'+this.url+'--ajax response--'+data); if(data == 1){ alert('div id--'+this.url+'--Unhiding image--'); //Needed magic //Show image if data==1 } else{ alert('div id--'+this.url+'--Hiding image--'); //Needed magic //Hide image if data!=1 } }); }); }); </script> </body> </html>

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  • ie8 playing funny with list-style-position: inside

    - by LeeR
    Ok, So problem here... when using list-style-position:inside in IE8 the first like is indented but every line after that is not. So the new lines appear under the bullet. This is fine, but when I use a list with that css applied with an a tag within the li then the text automatically gets pushed to the second line, and the first line is empty. When I remove the a tag from the li then it jumps back up. Any idea on why this might be or is this a bug in the ie8 world or do I just need to double check my css? Any insights would be much appreciated. As asked here is some code <div id="sub_nav"> <ul> ... <li><a class="active_page" href="#">Liposculpture</a> <ul> <li><a href="#">What is Liposculpture?</a></li> <li><a href="#">About Liposculpture surgery</a></li> <li><a href="#" class="active_sub">After Liposculpture surgery</a></li> <li><a href="#">Post Op Instructions</a></li> <li><a href="#">Liposculpture Side Effects</a></li> <li><a href="#">Liposuction Introduction to</a></li> <li><a href="#">Tumescent Liposculpture</a></li> </ul> </li> ... </ul> </div> For the CSS I will try and show it best I can #sub_nav li { width: 200px; padding:4px 0; border-bottom: 1px #CCC solid; } #sub_nav li a { text-decoration: none; color:#555; padding:7px 15px 7px 15px; display: block; } #sub_nav li ul li { list-style-position: inside; list-style-type: disc; font: 11px Arial; padding-left:15px; color:#FFF; border-bottom: none; } #sub_nav li ul li a { padding:0; margin:0; text-indent: 0; } Hope this helps

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