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  • Error when trying to use PDO object

    - by Nate
    EDIT: I'm going to put my code in here due to comments below. So sit tight for a few minutes ;-) Thanks! I'm an inexperienced php programmer and only found out about PDO a few days ago. I'm now trying to port my website code over to using PDO, but I am getting an error when I try to use the PDO object that I create. I'm using a CMS on my website, and it makes building page output kind of complicated, but I've tried to draw the structure of what is being called below: index.php -class myClass defined --method myFunction defined (it gets called on pageload & returns the page output) ---include file1.php ----require_once('mysql_connect.php') (creates pdo object) ----*I can use the pdo object here successfully* ----require_once('file2.php') -----require_once('mysql_connect.php') -----function myFunction2 defined ------*trying to use the pdo object here results in the error* The error I'm getting is: Fatal error: Call to a member function prepare() on a non-object in /home/rgcpanel/public_html/account/account_functions.php on line 147 Any idea what's going on?

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  • Update multiple rows with one query?

    - by kavoir.com
    I found something that works with updating one field at here: http://www.karlrixon.co.uk/articles/sql/update-multiple-rows-with-different-values-and-a-single-sql-query/ UPDATE person SET name = CASE id WHEN 1 THEN 'Jim' WHEN 2 THEN 'Mike' WHEN 3 THEN 'Precious' END WHERE id IN (1,2,3) My question is how to update more than one field? Such as: UPDATE person SET name = CASE, sex = CASE id WHEN 1 THEN 'Jim', 'female' WHEN 2 THEN 'Mike' 'male' WHEN 3 THEN 'Precious', 'male' END WHERE id IN (1,2,3) Which doesn't work of course. Tried a few other combination and failed. Any idea? Thanks!

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  • Take Current Snapshot of DB and send it to FTP in same PHP Scripts: Advice Needed

    - by Rachel
    Not sure if I can do it this way. I want to get current snapshot of the database and send it via FTP Server, both of this functionality should be implemented in PHP scripts. Here are the steps I am thinking on right now. In my php scripts(basically am extending an PDO into my Dao class and then preparing the query), $qry = SELECT * FROM MyTablename; $stmt = $this->prepare($qry); $stmt = $this->execute(); Now I will store $stmt in csv file using fputcsv or I will execute the sql command from the script itself and than try to store the result in the $file(csv file) note here that I do not have any csv file with me at this point to basically I will have to create one and let's say its $file, so then $file = fputcsv($stmt); or $file = exec("Select * from MyTablename"); Will this put all records in the file ? If yes, then I will use FTP Functionality to transfer file to the FTP Folder. I am not sure if this approach would work and also have concerns regarding the need of preparing the $qry Any suggestions or different approach advised would be highly appreciated. Thanks !!!

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  • Using * in SELECT Query

    - by libregeek
    I am currently porting an application written in MySQL3 and PHP4 to MySQL5 and PHP5. On analysis I found several SQL queries which uses "select * from tablename" even if only one column(field) is processed in PHP. The table has almost 60 columns and it has a primary key. In most cases, the only column used is id which is the primary key. Will there be any performance boost if I use queries in which the column names are explicitly mentioned instead of * ? (In this application there is only one method which we need all the columns and all other methods return only a subset of the columns)

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  • Hibernate constraint ConstraintViolationException. Is there an easy way to ignore duplicate entries?

    - by vincent
    Basically I've got the below schema and I'm inserting records if they don't exists. However when it comes to inserting a duplicate it throws and error as I would expect. My question is whether there is an easy way to make Hibernate to just ignore inserts which would in effect insert duplicates? CREATE TABLE IF NOT EXISTS `method` ( `id` bigint(20) NOT NULL AUTO_INCREMENT, `name` varchar(10) DEFAULT NULL, PRIMARY KEY (`id`), UNIQUE KEY `name` (`name`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=2 ; SEVERE: Duplicate entry 'GET' for key 'name' Exception in thread "pool-11-thread-4" org.hibernate.exception.ConstraintViolationException: could not insert:

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  • Select * from 'many to many' SQL relationship

    - by Rampant Creative Group
    I'm still learning SQL and my brain is having a hard time with this one. Say I have 3 tables: teams players and teams_players as my link table All I want to do is run a query to get each team and the players on them. I tried this: SELECT * FROM teams INNER JOIN teams_players ON teams.id = teams_players.team_id INNER JOIN players ON teams_players.player_id = players.id But it returned a separate row for each player on each team. Is JOIN the right way to do it or should I be doing something else? ----------------------------------------- Edit Ok, so from what I'm hearing, this isn't necessarily a bad way to do it. I'll just have to group the data by team while I'm doing my loop. I have not yet tried the modified SQL statements provided, but I will today and get back to you. To answer the question about structure - I guess I wasn't thinking about the returned row structure which is part of what lead to my confusion. In this particular case, each team is limited to 4 players (or less) so I guess the structure that would be helpful to me is something like the following: teams.id, teams.name, players.id, players.name, players.id, players.name, players.id, players.name, players.id, players.name, 1 Team ABC 1 Jim 2 Bob 3 Ned 4 Roy 2 Team XYZ 2 Bob 3 Ned 5 Ralph 6 Tom

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  • Syntax error, unexpected T_CONSTANT_ENCAPSED_STRING in PHP

    - by pmms
    mysql_connect("localhost","root",""); mysql_select_db("hitnrunf_db"); $result=mysql_query("select * from jos_users INTO OUTFILE 'users.csv' FIELDS ESCAPED BY '""' TERMINATED BY ',' ENCLOSED BY '"' LINES TERMINATED BY '\n' "); header("Content-type: text/plain"); header("Content-Disposition: attachment; filename=your_desired_name.xls"); header("Content-Transfer-Encoding: binary"); header("Pragma: no-cache"); header("Expires: 0"); print "$header\n$data"; in the above code in query string i.e string in side mysql_quey we are getting following error Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING in C:\wamp\www\samples\mysql_excel\exel_outfile.php on line 8 in query string '\n' charter is not identifying as string thats why above error getting

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  • In Django, how to create tables from an SQL file when syncdb is run

    - by Sidney
    Hi, How do I make syncdb execute SQL queries (for table creation) defined by me, rather then generating tables automatically. I'm looking for this solution as some particular models in my app represent SQL-table-views for a legacy-database table. So, I've created their SQL-views in my django-DB like this: CREATE VIEW legacy_series AS SELECT * FROM legacy.series; I have a reverse engineered model that represents the above view/legacytable. But whenever I run syncdb, I have to create all the views first by running sql scripts, otherwise syncdb simply creates tables for them (if a view is not found). How do I make syncdb run the above mentioned SQL?

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  • Query Only Specified Number Of Items From Parent/Child Categories

    - by RogeR
    I'm having trouble figureing out how to query every item in a certain category and only list the newest 10 items by date. Here is my table layout: download_categories category_id (int) primary key title (var_char) parent_id (int) downloads id (int) primary key title (var_char) category_id (int) date (date) I need to query every file in a main category that lets say has 100 items and 5 child categories and only spit out the last 10 added. I have functions right now that just add up all the files so I can get a count by category, but I can't seem to modify the code to only display a certain amount of items based on the date.

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  • Form is trying to save the login value of the submit button to my DB.

    - by Sergio Tapia
    Here's my Zend code: <?php require_once ('Zend\Form.php'); class Sergio_Form_registrationform extends Zend_Form { public function init(){ /*********************USERNAME**********************/ $username = new Zend_Form_Element_Text('username'); $alnumValidator = new Zend_Validate_Alnum(); $username ->setRequired(true) ->setLabel('Username:') ->addFilter('StringToLower') ->addValidator('alnum') ->addValidator('regex', false, array('/^[a-z]+/')) ->addValidator('stringLength',false,array(6,20)); $this->addElement($username); /*********************EMAIL**********************/ $email = new Zend_Form_Element_Text('email'); $alnumValidator = new Zend_Validate_Alnum(); $email ->setRequired(true) ->setLabel('EMail:') ->addFilter('StringToLower') ->addValidator('alnum') ->addValidator('regex', false, array('/^[a-z]+/')) ->addValidator('stringLength',false,array(6,20)); $this->addElement($email); /*********************PASSWORD**********************/ $password = new Zend_Form_Element_Password('password'); $alnumValidator = new Zend_Validate_Alnum(); $password ->setRequired(true) ->setLabel('Password:') ->addFilter('StringToLower') ->addValidator('alnum') ->addValidator('regex', false, array('/^[a-z]+/')) ->addValidator('stringLength',false,array(6,20)); $this->addElement($password); /*********************NAME**********************/ $name = new Zend_Form_Element_Text('name'); $alnumValidator = new Zend_Validate_Alnum(); $name ->setRequired(true) ->setLabel('Name:') ->addFilter('StringToLower') ->addValidator('alnum') ->addValidator('regex', false, array('/^[a-z]+/')) ->addValidator('stringLength',false,array(6,20)); $this->addElement($name); /*********************LASTNAME**********************/ $lastname = new Zend_Form_Element_Text('lastname'); $alnumValidator = new Zend_Validate_Alnum(); $lastname ->setRequired(true) ->setLabel('Last Name:') ->addFilter('StringToLower') ->addValidator('alnum') ->addValidator('regex', false, array('/^[a-z]+/')) ->addValidator('stringLength',false,array(6,20)); $this->addElement($lastname); /*********************DATEOFBIRTH**********************/ $dateofbirth = new Zend_Form_Element_Text('dateofbirth'); $alnumValidator = new Zend_Validate_Alnum(); $dateofbirth->setRequired(true) ->setLabel('Date of Birth:') ->addFilter('StringToLower') ->addValidator('alnum') ->addValidator('regex', false, array('/^[a-z]+/')) ->addValidator('stringLength',false,array(6,20)); $this->addElement($dateofbirth); /*********************AVATAR**********************/ $avatar = new Zend_Form_Element_File('avatar'); $alnumValidator = new Zend_Validate_Alnum(); $avatar ->setRequired(true) ->setLabel('Please select a display picture:'); $this->addElement($avatar); /*********************SUBMIT**********************/ $this->addElement('submit', 'login', array('label' => 'Login')); } } ?> Here's the code I use to save the values: public function saveforminformationAction(){ $form = new Sergio_Form_registrationform(); $request = $this->getRequest(); //if($request->isPost() && $form->isValid($_POST)){ $data = $form->getValues(); $db = $this->_getParam('db'); $db->insert('user',$data); //} } When trying to save the values, I recieve a ghastly error: Column 'login' not found.

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  • One to two relationship in Doctrine with YAML

    - by Jeremy DeGroot
    I'm working on my first Symfony project with Doctrine, and I've run into a hitch. I'm trying to express a game with two players. The relationship I want to have is PlayerOne and PlayerTwo each being keyed to an ID in the Users table. This is part of what I've got so far: Game: actAs: { Timestampable:- } columns: id: { type: integer, notnull: true, unique: true } startDate: { type: timestamp, notnull: true } playerOne: { type: integer, notnull: true } playerTwo: { type: integer, notnull: true } winner: { type: integer, notnull:true, default:0 } relations: User: { onUpdate: cascade, local: playerOne, foreign: id} User: { onUpdate: cascade, local: playerTwo, foreign: id} That doesn't work. It builds fine, but the SQL it generates only includes a constraint for playerTwo. I've tried a few other things: User: { onUpdate: cascade, local: [playerOne, playerTwo], foreign: id} Also: User: [{ onUpdate: cascade, local: playerOne, foreign: id}, { onUpdate: cascade, local: playerTwo, foreign: id}] Those last two throw errors when I try to build. Is there anyone out there who understands what I'm trying to do and can help me achieve it?

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  • how do I insert an hidden token in my form to prevent double posts? (PHP)

    - by jpjp
    I want to prevent users from accidentally posting a comment twice. I use the PRG (post redirect get) method, so that I insert the data on another page then redirect the user back to the page which shows the comment. This allows users to refresh as many times as they want. However this doesn't work when the user goes back and clicks submit again or when they click submit 100 times really fast. I don't want 100 of the same comments. I looked at related questions on SO and found that a token is best. But I am having trouble using it. //makerandomtoken(20) returns a random 20 length char. <form method="post" ... > <input type="text" id="comments" name="comments" class="commentbox" /><br/> <input type="hidden" name="_token" value="<?php echo $token=makerandomtoken(20); ?>" /> <input type="submit" value="submit" name="submit" /> </form> if (isset($_POST['submit']) && !empty($comments)) { $comments= mysqli_real_escape_string($dbc,trim($_POST['comments'])); //how do I make the if-statment to check if the token has been already set once? if ( ____________){ //don't insert comment because already clicked submit } else{ //insert the comment into the database } } So I have the token as a hidden value, but how do I use that to prevent multiple clicking of submit.

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  • How would I UPDATE these table entries with SQL?

    - by CT
    I am working on an Asset Database problem. I enter assets into a database. Every object is an asset and has variables within the asset table. An object is also a type of asset. In this example the type is server. Here is the Query to retrieve all necessary data: SELECT asset.id ,asset.company ,asset.location ,asset.purchaseDate ,asset.purchaseOrder ,asset.value ,asset.type ,asset.notes ,server.manufacturer ,server.model ,server.serialNumber ,server.esc ,server.warranty ,server.user ,server.prevUser ,server.cpu ,server.memory ,server.hardDrive FROM asset LEFT JOIN server ON server.id = asset.id WHERE asset.id = '$id' How would I write a query to update an asset?

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  • PHP function returns ZERO.

    - by hypnocode
    Hi guys, I'm having trouble with this PHP function. It keeps returning zero, but I know the SQL statement works because I've queried it myself. Any ideas what I'm doing wrong? The last line makes no sense to me...I'm editing this code that someone else wrote. This function should return a number in the hundreds, assuming the date is in March. Thanks! function getCountBetweenDays($day1,$day2,$service) { global $conn; if ($service==1){ $query = "SELECT COUNT(*) as NUM FROM `items` WHERE `modified` BETWEEN '$day1 00:00:00' AND '$day2 23:59:59';";} elseif($service==2){ $query = "SELECT COUNT(*) as NUM FROM `items` WHERE `modified` BETWEEN '$day1 00:00:00' AND '$day2 23:59:59';";} elseif($service==3){ $query = "SELECT COUNT(*) as NUM FROM `items` WHERE `modified` BETWEEN '$day1 00:00:00' AND '$day2 23:59:59';";} $result = mysql_query($query,$conn); $num = mysql_fetch_array ($result); return $num['NUM']; }

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  • How to determine the difference among dates in the same column?

    - by Vera
    How to determine the difference among dates of birth? +----------+----------+------------+ | id | name | birth | +----------+----------+------------+ | 00001 | Claws | 2010-04-17 | | 00002 | Claws | 2010-01-31 | | 00003 | Claws | 2009-11-31 | | 00004 | Claws | 2009-09-31 | | 00005 | Claws | 2009-07-31 | | 00006 | Claws | 2008-10-31 | +----------+----------+------------+ I would like to obtain this: +----------+----------+------------+------------------------------------------+ | id | name | birth | diff | +----------+----------+------------+------------------------------------------+ | 00001 | Claws | 2010-04-17 | diff (id1-id2) = 2010-01-31 - 2010-04-17 | | 00002 | Claws | 2010-01-31 | diff (id2-id3) = 2010-01-31 - 2009-11-31 | | 00003 | Claws | 2009-11-31 | diff (id3-id4) = 2010-01-31 - 2009-09-31 | If possible, ORDER BY diff DESC Thank you for helping Vera

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  • Is there a way to optimize this update query?

    - by SchlaWiener
    I have a master table called "parent" and a related table called "childs" Now I run a query against the master table to update some values with the sum from the child table like this. UPDATE master m SET quantity1 = (SELECT SUM(quantity1) FROM childs c WHERE c.master_id = m.id), quantity2 = (SELECT SUM(quantity2) FROM childs c WHERE c.master_id = m.id), count = (SELECT COUNT(*) FROM childs c WHERE c.master_id = m.id) WHERE master_id = 666; Which works as expected but is not a good style because I basically make multiple SELECT querys on the same result. Is there a way to optimize that? (Making a query first and storing the values is not an option. I tried this: UPDATE master m SET (quantity1, quantity2, count) = ( SELECT SUM(quantity1), SUM(quantity2), COUNT(*) FROM childs c WHERE c.master_id = m.id ) WHERE master_id = 666; but that doesn't work.

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  • Creating search functionality with Laravel 4

    - by Mitch Glenn
    I am trying to create a way for users to search through all the products on a website. When they search for "burton snowboards", I only want the snowboards with the brand burton to appear in the results. But if they searched only "burton", then all products with the brand burton should appear. This is what I have attempted to write but isn't working for multiple reasons. Controller: public function search(){ $input = Input::all(); $v= Validator::make($input, Product::$rules); if($v->passes()) { $searchTerms = explode(' ', $input); $searchTermBits = array(); foreach ($searchTerms as $term) { $term = trim($term); if (!empty($term)){ $searchTermBits[] = "search LIKE '%$term%'"; } } $result = DB::table('products') ->select('*') ->whereRaw(". implode(' AND ', $searchTermBits) . ") ->get(); return View::make('layouts/search', compact('result')); } return Redirect::route('/'); } I am trying to recreate the first solution given for this stackoverflow.com problem The first problem I have identified is that i'm trying to explode the $input, but it's already an array. So i'm not sure how to go about fixing that. And the way I have written the ->whereRaw(". implode(' AND ', $searchTermBits) . "), i'm sure isn't correct. I'm not sure how to fix these problems though, any insights or solutions will be greatly appreciated.

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  • Why does this query only select a single row?

    - by Joe
    SELECT * FROM tbl_houses WHERE (SELECT HousesList FROM tbl_lists WHERE tbl_lists.ID = '123') LIKE CONCAT('% ', tbl_houses.ID, '#') It only selects the row from tbl_houses of the last occuring tbl_houses.ID inside tbl_lists.HousesList I need it to select all the rows where any ID from tbl_houses exists within tbl_lists.HousesList

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  • SQL join produces one result only

    - by Rami
    Can anyone please tell me why this result is generation only one results? taking in mind that everything is set right and the three tables are populated correctly, i took out the group_concat and it worked but of course with a php undefined index error! SELECT `songs`.`song_name`, `songs`.`add_date`, `songs`.`song_id`, `songs`.`song_picture`, group_concat(DISTINCT artists.artist_name) as artist_name FROM (`songs`) JOIN `mtm_songs_artists` ON `songs`.`song_id` = `mtm_songs_artists`.`song_id` JOIN `artists` ON `artists`.`artist_id` = `mtm_songs_artists`.`artist_id` ORDER BY `songs`.`song_id` DESC LIMIT 10 so i'm guessing it's something related to group_concat. best regards, Rami

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  • social networking website database management

    - by Anup Prakash
    This could be very basic type of question for you! But for me it is very important. 1) How these(orkut, facebook or other) website store the images in server? Options: a) Keeping all the images in database by converting into bytecode/binary. b) Making a new folder for each user and saving photographs according to their library name. c) Or something else which i(Anup) didn't guess yet. Please reply me. Sayiing thanx to see my question and any many many thanx for answering my question.

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  • How to handle multiple openIDs for the same user

    - by Sinan
    For my site I am using a login system much like the one on SO. A user can login with his Facebook, Google (Gmail openID), Twitter account. This question is not about specific oAuth or openID implementations. The question is how to know if the same user logins with different providers. Let me give an example: Bobo comes to site logins to site by clicking on "Login with Facebook". Because this is his first visit we create an account for him. Later Bobo comes to the site. This time he clicks on "Login with Google". So how do I know if this is the same person so I can add this provider to his account instead of creating a new (and duplicate) account. Can I trust solely on email? What is the best way to handle this. How does SO do it? Any ideas?

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