Search Results

Search found 15970 results on 639 pages for 'absolute path'.

Page 39/639 | < Previous Page | 35 36 37 38 39 40 41 42 43 44 45 46  | Next Page >

• C# How to set source path of image within html pages to show in webbrowser control

  - by Royson

  Hi in my application there is web browser control to show some static html pages. The pages are displayed properly. but images are not displayed.. I tried with changing src-path but no success. my html file is located at bin folder. And i am assigning it as. FileStream source = new FileStream(@"..\HtmlPages\supportHtml.html", FileMode.Open, FileAccess.Read); if i open html files in browser, the images are displayed properly.. So, What is the correct path for images..?? If i set full path to src attribute of <img> tag..it works. but i think its not a proper way. :(

  Read the article

• How to find the physical path of a GSP file in a deployed grails application

  - by Deepak Mittal

  I need to find out the physical path of a grails GSP file. My requirement is that I want to create a new layout file at run-time and use that in the application. I have been able to achieve this without problem when the application runs on jetty (grails run-app), however, when I deploy the app on Jboss, the path at which the file needs to be created changes. So, ideally I would like to find out at runtime using some magical utility the path of a particular GSP (lets say main.gsp layout file) and I need to create my new layout in the same directory in which main.gsp reside. Any pointers? -Deepak

  Read the article

• Powershell: resolve path that might not exist?

  - by Eamon Nerbonne

  I'm trying to process a list of files that may or may not be up to date and may or may not yet exist. In doing so, I need to resolve the full path of an item, even though the item may be specified with relative paths. However, Resolve-Path prints and error when used with a non-existant file. For example, What's the simplest, cleanest way to resolve ".\newdir\newfile.txt" to "C:\Current\Working\Directory\newdir\newfile.txt" in Powershell? Note that System.IO.Path's static method use with the process's working directory - which isn't the powershell current location.

  Read the article

• PATH and CLASSPATH in Windows7 7 / Eclipse

  - by Richard Knop

  So I would like to set PATH and CLASSPATH system variables so I can use javac and java commands in the command line. I can just compile and run java programs in eclipse but I would also like to be able to run them through command line. This is where I have Java installed: C:\Program Files (x86)\Java jdk1.6.0_20 jre6 And this is where eclipse stores my Java projects: D:\java-projects HelloWorld bin HelloWorld.class src HelloWorld.java I have set up the PATH and CLASSPATH variables like this: PATH: C:\Program Files (x86)\Java\jdk1.6.0_20\bin CLASSPATH: D:\java-projects But it doesn't work. When I write: java HelloWorld Or: java HelloWorld.class I get error like this: Exception in thread “main” java.lang.NoClassDefFoundError: HelloWorld The error is longer, that's just the first line. How can I fix this? I'm mainly interested to be able to run compiled .class programs from the command line, I can do compiling in the eclipse.

  Read the article

• Importing war file into eclipse and build path problem

  - by Todd

  Hi, I am facing some weird problem when importing .war file into eclipse. The problem is, the build folder does not contain any necessary class folder. So when I try to set the build path, eclipse reports "Error while adding to build path. Reason: cannot nest output folder 'projectName/build/class' inside 'projectName/build'. From what I understand, 'build' folder is what classes get collected(as build version) right? I tried to ignore build path and just export .war file into tomcat server, but somehow servlet file keeps showing old code, which I changed in eclipse. So, I am thinking without proper build folder, exported .war will not contain modified servlect code.( I am sorry if this doesn't sound clear) What can I do to fix this problem? I already tried to create a whole new workspace and restarted eclipse several times and it didn't solve the problem.

  Read the article

• Problem with image path of html files viewed by webbrowser control

  - by Royson

  I have an webbrowser control on my form. I am able display html files in that control. But my page contains some images if i give absolute path to it then images are displayed. But if i give relative path then images are not shown in the pages. I have HtmlPages folder located at bin folder. And i am assigning FileStream source = new FileStream(@"..\HtmlPages\supportHtml.html", FileMode.Open, FileAccess.Read); webBrowser.DocumentStream = source; If i assign D:\myapp\bin\HtmlPages\file.png then there is no problem. My images are stored in same folder. If i open html files with webbrowser then images are displayed. What is the correct path to set ??

  Read the article

• I need an algorithm to find the best path

  - by user242635

  I need an algorithm to find the best solution of a path finding problem. The problem can be stated as: At the starting point I can proceed along multiple different paths. At each step there are another multiple possible choices where to proceed. There are two operations possible at each step: A boundary condition that determine if a path is acceptable or not. A condition that determine if the path has reached the final destination and can be selected as the best one. At each step a number of paths can be eliminated, letting only the "good" paths to grow. I hope this sufficiently describes my problem, and also a possible brute force solution. My question is: is the brute force is the best/only solution to the problem, and I need some hint also about the best coding structure of the algorithm.

  Read the article

• How to set source path of image within html pages to show in webbrowser control

  - by Royson

  Hi in my application there is web browser control to show some static html pages. The pages are displayed properly. but images are not displayed.. I tried with changing src-path but no success. my htmlpages folder is located at bin folder. And i am assigning it as. FileStream source = new FileStream(@"..\HtmlPages\supportHtml.html", FileMode.Open, FileAccess.Read); if i open html files in browser, the images are displayed properly.. So, What is the correct path for images..?? If i set full path to src attribute of <img> tag..it works. but i think its not a proper way. :( EDIT: If i assign d:\myapp\bin\HtmlPages\support.gif then image is displayed. And if i assign "..\HtmlPages\support.gif" or "support.gif" image is not shown.

  Read the article

• Parse filename from full path using regular expressions in C#

  - by WindyCityEagle

  How do I pull out the filename from a full path using regular expressions in C#? Say I have the full path C:\CoolDirectory\CoolSubdirectory\CoolFile.txt. How do I get out CoolFile.txt using the .NET flavor of regular expressions? I'm not really good with regular expressions, and my RegEx buddy and me couldn't figure this one out. Also, in the course of trying to solve this problem, I realized that I can just use System.IO.Path.GetFileName, but the fact that I couldn't figure out the regular expression is just making me unhappy and it's going to bother me until I know what the answer is.

  Read the article

• Android HelloWorld Build Path error

  - by BahaiResearch.com

  On my Mac I installed Eclipse, the SDK and created a new project, then hit build expecting to see my first helloworld app. I got the error "the project cannot be built until build path errors are fixed". After going thru all the path-like options in Preferences, I noticed that on the tab "Java Build Path" the "Google APIs [Android 2.2]" option did not have its check box checked. Checking it made the problem go away. It works now and I can see the app in the Emulator Have I not set up my environment correctly? I used all the defaults in Eclipse and the Android SDK.

  Read the article

• How to use a different path name in ProxyPass than the Tomcat context name

  - by Diptendu Dutta

  Hello, I am using Tomcat 5.5.9 and Apache 2.x We are trying to use a path name in ProxyPass that is different than the Tomcat context name. ProxyPass /path http://localhost:8080/contextname However, this does not work. When these two are the same then everything works fine. Most examples I see on the net also have the path equal to the Tomcat context name. I am using "context.xml" within the Tomcat context and do NOT have "server.xml" entries. Also, I am using plain httd.conf and NOT using any VirtualHost entries. Any help is appreciated. Regards, Diptenu

  Read the article

• attaching a file path in a html form

  - by sushant

  <form><label for="attachment">Attachment:</label> <input type="file" name="attachment" id="attachment"><input type="submit"></form> i want to attach the file path to a form. i am doing it using the following code. but i want that the pop up window should open to a specified path. say D:\newfolder, so that user need not go to D: and then newfolder to attach the file. is there any way i can set this predefined path. any help is really appreciated and also i am really sorry for formatting , i dont know how to format it.

  Read the article

• Why first arg to execve() must be path to executable

  - by EBM

  I understand that execve() and family require the first argument of its argument array to be the same as the executable that is also pointed to by its first argument. That is, in this: execve(prog, args, env); args[0] will usually be the same as prog. But I can't seem to find information as to why this is. I also understand that executables (er, at least shell scripts) always have their calling path as the first argument when running, but I would think that the shell would do the work to put it there, and execve() would just call the executable using the path given in its first argument ("prog" from above), then passing the argument array ("args" from above) as one would on the command line.... i.e., I don't call scripts on the command line with a duplicate executable path in the args list.... /bin/ls /bin/ls /home/john Can someone explain?

  Read the article

• Get the image file path

  - by Googler

  HI, I am trying to retrive the filname of the image file from a file path in my code. My filepath: c:\mydocuments\pictures\image.jpg which method can i use in c# to get he filename of the above mentioned path. Like String file = image.jpg I have used the system.drawing to get he path, but it returns null. my code: string file = System.drawing.image.fromfile(filepath,true); Is this the right way to get the image file name or is there any other inbuilt method in c#. Pls help me on this?

  Read the article

• How to get only a filename (not full path) into $1, using the PERL, regular expressions

  - by Scott

  I want to keep only the filenames (not full paths) and add the filename to some bbcode. Here is the HTML to be converted: <a href=/path/to/full/image.jpg rel=prettyPhoto><img rel=prettyPhoto src=/path/to/thumb/image.jpg /></a> Notice I cannot have rel="foo" (no double quotes).. Here is what I have in PERL, to perform the conversion: s/\<a href=(.+?)\ rel=prettyPhoto\>\<img rel=prettyPhoto src=(.+?) \/>\<\/a\>/\[box\]$1\[\/box\]/gi; This converts the HTML to: [box]/path/to/image.jpg[/box] But this is what I want as a result: [box]image.jpg[/box] The HTML must remain the same. So how do I change my PERL so that $1 contains only the filename?

  Read the article

• XPath selection from path in XML content

  - by Wayne Robinson

  I have the following XML: <root> <name>The name</name> <long> <path> <value>Some Value</value> </path> </long> <field>/root/name</field> <field>/root/long/path/value</field> </root> and I want to select these paths in the field tags however, when I try the following: <xsl:value-of select="/root/field[1]" /> all I get is the text value of the field. Is there a way of selecting the correct node from those values?

  Read the article

• JFileChooser returns incorrect path in OS X (folders only mode)

  - by Virat Kadaru

  I have a problem in java swing where the user has to select a folder, so I am using the code below. JFileChooser fc = new JFileChooser(); fc.setFileSelectionMode(JFileChooser.DIRECTORIES_ONLY); if(fc.showDialog(singleton, SELECT) == JFileChooser.APPROVE_OPTION) { File folder = fc.getSelectedFile(); String path = folder.getPath() + File.separatorChar + MYAPPFOLDER; } Now there are 2 ways a user may select the folder Navigate to the folder and select the folder Navigate to the folder, go into the folder, and click select Both ways work fine on windows but on OS X, I get If I do 1 : path = Users/<username>/Desktop/MYAPPFOLDER If I do 2 : path = Users/<username>/Desktop/Desktop/MYAPPFOLDER How do I avoid this 2nd case? Thanks in advance.

  Read the article

• Import python module NOT on path

  - by Vort3x

  I have read all the questions I could find on it on SO, but none answers my question. I have a module foo, containing util.py and bar.py. I want to import it in IDLE or python session. How do I go about this? I could find no documentation on how to import modules not in the current directory or the default python PATH. After trying import "<full path>/foo/util.py", and from "<full path>" import util The closest I could get was import imp imp.load_source('foo.util','C:/.../dir/dir2/foo') Which gave me Permission denied on windows 7.

  Read the article

• Elegant way to distinct Path or Entry key

  - by sum1stolemyname

  I have an application loading CAD data (Custom format), either from the local filesystem specifing an absolute path to a drawing or from a database. Database access is realized through a library function taking the drawings identifier as a parameter. the identifiers have a format like ABC 01234T56-T, while my paths a typical windows Paths (eg x:\Data\cadfiles\cadfile001.bin). I would like to write a wrapper function Taking a String as an argument which can be either a path or an identifier which calls the appropriate functions to load my data. Like this: Function CadLoader(nameOrPath : String):TCadData; My Question: How can I elegantly decide wether my string is an idnetifier or a Path to a file? Use A regexp? Or just search for '\' and ':', which are not appearing in the Identifiers?

  Read the article

• Identify machine (relatively) uniquely using unc path

  - by Gareth

  Using C#, and given that the user enters in a unc path. Is there a way to verify that 2 months down the line, when I'm writing a file to the unc path, that it is the same machine as when he entered it? i.e. I'm writing some sensitive information to the path, and want to stop someone from putting another machine on the network with the same name / share etc and grabbing the output. Or if the software is running on a laptop and the user plugs it into another network, and there just happens to be a machine with the same name / share... Any ideas, other than using the IP address (and verifying that its the same?). I don't necessarily have any rights on the remote machine other than write access to the unc share. Yes, I'm probably being paranoid, but would like to know if anything is possible...

  Read the article

• Creating a file path in C#

  - by Jason

  So I'm trying to create a path in C#. I use Environment.Machinename and store it a variable serverName. Then I create another string variable and have some other path extension in there. Here is my code so far: string serverName = Environment.MachineName; string folderName = "\\AlarmLogger"; No matter what I do I can't seem to obtain only one backslash prior to AlarmLogger. Any ideas how I can specify a path in C#? Edit: I'm wondering if my code doesn't seem to want to paste correctly. Anyways when i paste it I only see one backslash but my code has two. Because of the escape character sequence. But something like string test = @"\" + serverName + folderName doesn't seem to want to work for me.

  Read the article

• HYPER-V R2 Can not mount ISO from network location (UNC Path)

  - by Entity_Razer

  So, as the name suggest I'm trying to mount a ISO from a network share using the UNC path to a HYPER-V R2 Cluster. This is a pure Demo / test case setup with: 2x HYPER-V R2 1X NAS/iSCSI CSV Cluster Management is happening through the MMC with RSAT tools. So what i've done so far is: Set up the cluster and configure Quorum, add CSV Shares and disks, set up 1 Virtual Machine on the Hyper-1 node. What i'm trying to do is, you go to settings --- DVD Drive --- use network location ---- Pick ISO file and press "apply". Error I'm getting is either "User account does not have rights to mount iso". I changed that or stopped getting that message when I went to the HYPER-V Node settings and tabbed on: "Use Default Credentials Automatically". Now I stopped getting the "user does not have right..." message but I get the following: Error applying DVD Drive Changes Failed to remove device microsoft synthetic DVD Drive:" the specified network resource or device is no longer available" I've google'd the problem but am unable to find a solution. Anyone here able to help me out ? Much abbliged !

  Read the article

• hadoop install cluster

  - by chnet

  Is it possible to run hadoop on multi-node and these nodes install hadoop on different paths? I noticed the tutorial, such as Michael Noll's, http://www.michael-noll.com/tutorials/running-hadoop-on-ubuntu-linux-multi-node-cluster/, asks hadoop to be installed on different nodes with the same installation path. I tried to run hadoop on multi-node. Each node installed hadoop on different path. But not success. I noticed that the hadoop assume installation paths are the same in default.

  Read the article

• Proxy to either Rails app or Node.js app depending on HTTP path w/ Nginx

  - by Cirrostratus

  On Ubuntu 11, I have Nginx correctly serving either CouchDB or Node.js depending on the path, but am unable to get Nginx to access a Rails app via it's port. server { rewrite ^/api(.*)$ $1 last; listen 80; server_name example.com; location / { proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; proxy_set_header Host $http_host; proxy_pass http://127.0.0.1:3005/; } location /ruby { proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; proxy_set_header Host $http_host; proxy_pass http://127.0.0.1:9051/; } location /_utils { proxy_pass http://127.0.0.1:5984; proxy_redirect off; proxy_set_header Host $host; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; proxy_buffering off; # buffering would break CouchDB's _changes feed } gzip on; gzip_comp_level 9; gzip_min_length 1400; gzip_types text/plain text/css image/png image/gif image/jpeg application/x-javascript text/xml application/xml application/x ml+rss text/javascript; gzip_vary on; gzip_http_version 1.1; gzip_disable "MSIE [1-6]\.(?!.*SV1)"; } / and /_utils are working bu /ruby gives me a 403 Forbidden

  Read the article

• Macos default paths prepend my defined paths in vim

  - by Bogdan Gusiev

  I am trying to call some shell command from vim with like :!ls command. But unfortunately there are some default PATHS that prepends PATHs defined in the original shell. Here is the echo $PATH output in the original shell: /usr/local/heroku/bin:/Users/bogdan/.rvm/gems/ruby-1.9.3-p194/bin:/Users/bogdan/.rvm/gems/ruby-1.9.3-p194@global/bin:/Users/bogdan/.rvm/rubies/ruby-1.9.3-p194/bin:/Users/bogdan/.rvm/bin:/usr/local/bin:/usr/bin:/bin:/usr/sbin:/sbin:/usr/X11/bin:/Users/bogdan/.rvm/bin:/Users/bogdan/bin:/Users/bogdan/.rvm/bin:/usr/local/Cellar/git/1.7.12.2/libexec/git-core:/Users/bogdan/.rvm/bin and shell called within vim: /usr/local/bin:/usr/bin:/bin:/usr/sbin:/sbin:/usr/X11/bin:/Users/bogdan/.rvm/gems/ruby-1.9.3-p194@devauc/bin:/Users/bogdan/.rvm/gems/ruby-1.9.3-p194@global/bin:/Users/bogdan/.rvm/rubies/ruby-1.9.3-p194/bin:/Users/bogdan/.rvm/bin:/Users/bogdan/bin:/usr/local/Cellar/git/1.7.12.2/libexec/git-core:/Users/bogdan/.rvm/bin Why they appeared right there? How can I prevent that and make vim shell has original PATH variable.

  Read the article

< Previous Page | 35 36 37 38 39 40 41 42 43 44 45 46  | Next Page >