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  • How do I open a program via the command prompt in Windows 8?

    - by Ahmadul Hoq
    Suppose I have a program named any_program.exe and my operating system drive is C:. The location of the program is D:\Any_Folder\any_program.exe How do I start/execute that program via command prompt in Windows 8? I have tried the command line START any_program.exe, but it shows me an error that Windows cannot find 'any_program.exe'. Make sure you typed the name correctly, and then try again. By the way, it worked perfectly in Windows 7. And, if I type START notepad.exe or START firefox.exe (Firefox is not installed in C: drive), it works in Windows 8.

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  • How to install GRUB command-line tools on OSX?

    - by beakr
    I need access to grub-mkrescue for a project I'm working on. I know that the GRUB command-line tools come builtin to Linux, but how do I get them on OSX? Is there a package? Is it built into the system somewhere? Is there an installer? CLARIFICATION: The question is not about installing GRUB as a bootloader on the Mac. The question is about installing the GRUB command line tools to do things like create bootable disk images of other operating systems.

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  • Concatenating several .mp3 files into one .mp3

    - by Bakhtiyor
    As it was suggested here I am using cat command to concatenate several .mp3 files into one .mp3 file. Imagine, I have following .mp3 files in the current folder: 001001.mp3 001002.mp3 001003.mp3 001004.mp3 001005.mp3 or, like this: 096001.mp3 096002.mp3 096003.mp3 096004.mp3 I need to concatenate these .mp3 files in there ascending sequence, i.e. 001001.mp3+001002.mp3+001003.mp3+etc. In order to join these .mp3 files into one I am executing following command in the current folder: cat *.mp3 > final.mp3 I tested the final .mp3 file and it is what I am expected, but I need to be sure that above command picks files in there ascending sequence. Can I be sure that above command always concatenates files in the ascending sequence? Thank you Sir!

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  • chromium-browser --proxy-server debugging

    - by user3678068
    Many places online have pointed out to configure chromium proxy via command can be achieve with the following line chromium-browser --proxy-server=[username]:[password]@[host]:[port] but I got this result on every request. Here's the output in the command line right after executing the previous command. (They do not appear to be relevant. There are no new command line output when I try to visit a page) libGL error: failed to authenticate magic 30 libGL error: failed to load driver: vboxvideo ATTENTION: default value of option force_s3tc_enable overridden by environment. [29551:29551:0606/160459:ERROR:sandbox_linux.cc(268)] InitializeSandbox() called with multiple threads in process gpu-process I have double checked that the proxy credential works with the foxyproxy chrome plugin. What else can I try to figure this out? [Edit] Going to chrome://net-internals/#proxy and reading "Effective proxy settings" if I do chromium-browser with no flags, I get Use DIRECT connections. Source: GSETTINGS if chromium-browser --proxy-server=[host]:[port], I get a message box requesting to login, and under "Effective proxy settings": Proxy server: [host]:[port] if chromium-browser --proxy-server=[user]:[pass]@[host]:[port], "Effective proxy settings" shows: Use DIRECT connections

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  • How to check the process is already running or not

    - by TechGuru
    I want to check the particular process in already running or not. I refereed this Q&A. But I didn't get any specific solution. Following is the example that I tried: I have created abc.sh file and run this script on background, like sh abc.sh &. Now this file is running on background and I fire the ps aux | grep "abc" command. Following is the output of this command: prakash 3594 0.0 0.0 4388 820 pts/0 S+ 16:44 0:00 grep --color=auto abc After that I stop the abc.sh running script and fire the same command ps aux | grep "abc" command. But I am getting same output like: prakash 3594 0.0 0.0 4388 820 pts/0 S+ 16:44 0:00 grep --color=auto abc Is there any other way to find the process is running or not?

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  • How to set MANPATH without overriding defaults?

    - by balki
    I have added extra directories to $PATH by exporting PATH=/my/dirs:$PATH But I am not sure if I should do the same to MANPATH. Because default MANPATH is empty yet man command works. I found a command called manpath and its manual says If $MANPATH is set, manpath will simply display its contents and issue a warning.. Does this mean setting MANPATH is not the right way to add directories for man command to search for manual pages?

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  • Terminal exits program before able to accept Hashcat EULA

    - by Fluffaduff
    I'm trying to play around with hashcat,just using the examples included with the program, but before the command can run it requires me to accept the EULA. Instead of me being able to enter 'YES', the terminal appears to end the process immediately. Whenever I try to accept the EULA I get the expected 'YES: Command not found.' I don't think I'm using the command wrong, but I also don't know whats happening. http://i.imgur.com/ClloeK6.png

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  • Alternative to | more to display error results page by page

    - by Lane
    The command psql -d template_postgis2 -f /usr/share/postgresql/9.1/contrib/postgis-2.1/postgis.sql returns a list of errors that is too long to be displayed by scrolling up to the beginning of the error. I tried the same command with "| more" and "| less" added up at the end of the command but it does not display the message page by page as it should. I also tried to put the output in a file with "> file.txt" but I do not get in this new file what is displayed on the screen!! I don't understand why. I guess i can't do this with a psql command?? Is there any other way to get all the error message? Thanks for your help!

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  • Weird execution of ruby/git executables in Windows [migrated]

    - by Frexuz
    Something strange has happened. I can't run some command line executables in Windows anymore. Steps: Open cmd Run an executable, such as ruby -v or git -h When I do that, a new command prompt opens, running that command (I think, it's too fast to see), and instantly closes again. I've managed to print screen the new command prompt, and it shows that it's running inside this path: C:\Documents and Settings\Administrator\Local Settings\Temp\3582-490 Inside this folder, is the executable I'm tring to run. If I run ruby, then ruby.exe is in there. If I run git, then git.exe is in there. And it's always emptying the folder in between, so there is always just one .exe file

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  • Large transactions causing "System.Data.SqlClient.SqlException: Timeout expired" error?

    - by Michael
    My application requires a user to log in and allows them to edit a list of things. However, it seems that if the same user always logs in and out and edits the list, this user will run into a "System.Data.SqlClient.SqlException: Timeout expired." error. I've read comments about increasing the timeout period but I've also read a comment about it possibly caused by uncommitted transactions. And I do have one going in the application. I'll provide the code I'm working with and there is an IF statement in there that I was a little iffy about but it seemed like a reasonable thing to do. I'll just go over what's going on here, there is a list of objects to update or add into the database. New objects created in the application are given an ID of 0 while existing objects have their own ID's generated from the DB. If the user chooses to delete some objects, their IDs are stored in a separate list of Integers. Once the user is ready to save their changes, the two lists are passed into this method. By use of the IF statement, objects with ID of 0 are added (using the Add stored procedure) and those objects with non-zero IDs are updated (using the Update stored procedure). After all this, a FOR loop goes through all the integers in the "removal" list and uses the Delete stored procedure to remove them. A transaction is used for all this. Public Shared Sub UpdateSomethings(ByVal SomethingList As List(Of Something), ByVal RemovalList As List(Of Integer)) Using DBConnection As New SqlConnection(conn) DBConnection.Open() Dim MyTransaction As SqlTransaction MyTransaction = DBConnection.BeginTransaction() Try For Each SomethingItem As Something In SomethingList Using MyCommand As New SqlCommand() MyCommand.Connection = DBConnection If SomethingItem.ID > 0 Then MyCommand.CommandText = "UpdateSomething" Else MyCommand.CommandText = "AddSomething" End If MyCommand.Transaction = MyTransaction MyCommand.CommandType = CommandType.StoredProcedure With MyCommand.Parameters If MyCommand.CommandText = "UpdateSomething" Then .Add("@id", SqlDbType.Int).Value = SomethingItem.ID End If .Add("@stuff", SqlDbType.Varchar).Value = SomethingItem.Stuff End With MyCommand.ExecuteNonQuery() End Using Next For Each ID As Integer In RemovalList Using MyCommand As New SqlCommand("DeleteSomething", DBConnection) MyCommand.Transaction = MyTransaction MyCommand.CommandType = CommandType.StoredProcedure With MyCommand.Parameters .Add("@id", SqlDbType.Int).Value = ID End With MyCommand.ExecuteNonQuery() End Using Next MyTransaction.Commit() Catch ex As Exception MyTransaction.Rollback() 'Exception handling goes here End Try End Using End Sub There are three stored procedures used here as well as some looping so I can see how something can be holding everything up if the list is large enough. Other users can log in to the system at the same time just fine though. I'm using Visual Studio 2008 to debug and am using SQL Server 2000 for the DB.

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  • WPF Calling a custom command on a custom control (from a viewmodel?)

    - by user190615
    I want to take a snap of the visual tree of a custom wpf control when the user clicks a button in a toolbar. The control is bound to a viewmodel. I have a BitmapSource dp in the custom control holding the snapped image which is bound to a property on my VM. The BitmapSource dp on the control is updated via a custom command on the control. I've tied the toolbar button's command to call the controls command which updates the BitmapSource. Now the problem is the end result I want is when the user clicks the button, the control updates its image and then the vm offers to save this image. I cant wrap my mind around an mvvm way of doing this. One inelegant solution is that control fires an event after the image is updated which is routed to the viewmodel as a command(command behavior) but then if i want to do something else with the image on some other button click, all the commands bound to the events will fire. All thoughts appreciated. EDIT The command on the control is a RoutedCommand and the commands in my vm are Prism delegate commands.

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  • MySQL timeout only from office network to remote server, but other connections are fine

    - by Adam
    I've been developing these apps just fine on a local machine as has my co worker. We recently moved our work desks so we're now on a different floor of the building, but we only have one router that we're connected to. Since then, connecting to this one server appears to timeout more often than not. Occasionally I get through, and the loading is instantaneous. Anyhow we have these connections that were tested 1. my computer -> office network -> php pdo -> mysql server A - timeout 2. my computer -> office network -> mysql cli -> mysql server A - timeout 3. my computer -> office network -> mysql cli -> mysql server A - timeout 4. another pc -> office network -> mysql cli -> mysql server A - timeout 5. my computer -> mobile network -> mysql cli -> mysql server A - ok 6. my computer -> office network -> ssh server A -> mysql server A - ok 7. my computer -> office network -> ssh server B -> mysql server A - ok 8. server B web app -> php pdo -> mysql server A - ok 9. my computer -> office network -> php pdo -> mysql server B - ok 10. my computer -> office network -> mysql cli -> mysql server B - ok This has really stumped me.

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  • How to keep Ubuntu 11.10 and Kate editor w/terminal from changing command line when changing tabs?

    - by Kairan
    I am programming C using Kate editor in Ubuntu 11.10. It works great, but when I change tabs in Kate, the terminal line changes to the file path of the tab I click on. Normally this is not a big deal (other than annoyingly adding extra text to my terminal) however if I am currently RUNNNING a C program, it obviously will type at the command line, which is not so cool. Example terminal window for my C program (its at a menu): 1) select opt 1 2) select opt 2 Enter choice: (here it waits for prompt from user) Now when I click a tab in Kate, it wants to put in the cd / path of the file in that tab, such as: cd /home/user/os/files And of course since my terminal was waiting for prompt from user it gets that command.. not good. Perhaps there is no fix, but maybe someone knows? Obviously I could choose NOT to switch tabs or end program before switching tabs... Note: I probably made the mistake of putting this under StackOverflow which is more of a programming area - so though repost here might be best (I am not sure how to link the questions but will paste hyperlink to that post - I dont want to violate any stackoverflow/superuser violations) Suggestions on merging them are welcome or if I should delete one? StackOverFlow Question

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  • How can I both pipe and display output in Windows' command line?

    - by Bob
    I have a process I need to run within a batch file. This process produces some output. I need to both display this output to the screen and send (pipe) it to another program. The bash method uses tee: echo 'ee' | tee /dev/tty | foo Is there an equivalent for Windows? I am happy to use PowerShell if necessary. There are tee ports for Windows, but there does not appear to be an equivalent for /dev/tty, which complicates matters. The specific use-case here: I have a program (launch4j) that I need to run, displaying output to the user. At the same time, I need to be able to detect success or failure in the script. Unfortunately, this program does not set an exit code, and I cannot force it to do so. My current workaround involves piping to find, to search the output (launch4j config.xml | find "Successfully created") - however, that swallows the output I need to display. Therefore, I need some way to both display to the screen and send the ouput to a command - and this command should be able to set ERRORLEVEL (it cannot run asynchronously).

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  • DBA Command line options

    - by Anthony Shorten
    There are a number of database utilities supplied with the installation of the Oracle Utilities Application Framework based products. These are typically run in interactive mode where the utility prompts you for the values and then executes the required functionality. Did you know that the utilities also have command line options that allow you to run the utility in silent mode as well? You can assess the command line options by specifying the -h option on the command line. Here is an example of the oragensec command line options: oragensec -d <Owner,OwnerPswd,DbName> -u <Database Users> -r <ReadRole,UserRole> -l <logfile> -h where: -d <Owner,OwnerPswd,DbName> Database connect information for the target database. e.g. spladm,spladm,DB200ODB. -u <Database Users> A comma-separated list of database users where synonyms need to be created. e.g. spluser, splread -r <ReadRole,UserRole> Optional. Names of database roles with read and read-write privileges. Default roles are SPL_READ, SPL_USER. e.g. spl_read,spl_user -l <logfile> Optional. Name of the log file. -h Help The command line options allow the DBA to automate the exeucution either via a script or some utility can than execute utilities. This optin can apply to the majority of DBA utilities supplied with the product. Take a look at others.

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  • Wait for a single RabbitMQ message with a timeout

    - by Evgeny
    I'd like to send a message to a RabbitMQ server and then wait for a reply message (on a "reply-to" queue). Of course, I don't want to wait forever in case the application processing these messages is down - there needs to be a timeout. It sounds like a very basic task, yet I can't find a way to do this. I've now run into this problem with both py-amqplib and the RabbitMQ .NET client. The best solution I've got so far is to poll using basic_get with sleep in-between, but this is pretty ugly: def _wait_for_message_with_timeout(channel, queue_name, timeout): slept = 0 sleep_interval = 0.1 while slept < timeout: reply = channel.basic_get(queue_name) if reply is not None: return reply time.sleep(sleep_interval) slept += sleep_interval raise Exception('Timeout (%g seconds) expired while waiting for an MQ response.' % timeout) Surely there is some better way?

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  • How to configure a session timeout for Grails application?

    - by curd0
    In one of controllers in my Grails application I'm preserving a parameter value in a session variable like this: session.myVariable = params.myValue After that, I can access the saved value from different controllers/GSP-pages as long as I actively use the app. However, if I don't use my app for a while, even though my browser window is still open, the session variable looses it's value. Does this happens because the session expires? I was under impression that a session lives until the browser window is still open, but apparently I was wrong. What should I do to ensure all session variables I define in my Grails app don't expire until the browser is closed? Is there any way to set session timeout manually? Thank you in advance for your answers!

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  • How do I increase timeout for a cronjob/crontab?

    - by Mohit Ranka
    I have written a script that gets data from solr for which date is within the specified period, and I run the script using as a daily cron. The problem is the cronjob does not complete the task. If I manually run the script (for the same time period), it works well. If I reduce the specified time period, the script runs from the cron as well. So my guess is cronjob is timing out while running the script is there is much data to process. How do I increase the timeout for cronjob? PS - 1. The script I am running in cronjob is a bash script which runs a python script.

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  • setting a timeout using a manually created forms authentication ticket

    - by Nicklamort
    The constructors for manually creating FormsAuthenticationTicket objects force us to set an "expiration" value, and this value overrides the "timeout" setting in web.config in my tags, which is not what I want, because now the user doesn't timeout. The "session" just expires at the given time. I need to manually create my ticket for UserData reasons, and it is just the way I decided to build my app. I guess I could spend a whole lot of time and redo the way my app. authorizes, and store the "userdata" elsewhere... but this seems extremely tedious for something so small.. Is there anyway to manually create an Auth Ticket and still maintain timeout settings?! And by timeout, I mean resetting the timer on user activity. Not a fixed timeout! Please help!

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  • Building/Installing Required a52 Plugin

    - by user71139
    I am trying to compile and install the a52 plugin following the instructions from here: https://help.ubuntu.com/community/DigitalAC-3Pulseaudio This worked on Ubuntu 11.10 but gives me some errors when I try to compile the plugin on Ubuntu 12.04. I've searched for a solution however I couldn't find much on this topic in general, not to talk about a solution. I would really appreciate some help on this: bogdan@bogdan-desktop:~$ cd ~/tmp/ bogdan@bogdan-desktop:~/tmp$ cd alsa-plugins-1.0.25/ bogdan@bogdan-desktop:~/tmp/alsa-plugins-1.0.25$ make make all-recursive make[1]: Entering directory `/home/bogdan/tmp/alsa-plugins-1.0.25' Making all in oss make[2]: Entering directory `/home/bogdan/tmp/alsa-plugins-1.0.25/oss' /bin/bash ../libtool --tag=CC --mode=compile gcc -DHAVE_CONFIG_H -I. -I.. -Wall -g -I/usr/include/alsa -g -O2 -MT ctl_oss.lo -MD -MP -MF .deps/ctl_oss.Tpo -c -o ctl_oss.lo ctl_oss.c ../libtool: line 831: X--tag=CC: command not found ../libtool: line 864: libtool: ignoring unknown tag : command not found ../libtool: line 831: X--mode=compile: command not found ../libtool: line 997: *** Warning: inferring the mode of operation is deprecated.: command not found ../libtool: line 998: *** Future versions of Libtool will require --mode=MODE be specified.: command not found ../libtool: line 1141: Xgcc: command not found ../libtool: line 1141: X-DHAVE_CONFIG_H: command not found ../libtool: line 1141: X-I.: command not found ../libtool: line 1141: X-I..: command not found ../libtool: line 1141: X-Wall: command not found ../libtool: line 1141: X-g: command not found ../libtool: line 1141: X-I/usr/include/alsa: No such file or directory ../libtool: line 1141: X-g: command not found ../libtool: line 1141: X-O2: command not found ../libtool: line 1141: X-MT: command not found ../libtool: line 1141: Xctl_oss.lo: command not found ../libtool: line 1141: X-MD: command not found ../libtool: line 1141: X-MP: command not found ../libtool: line 1141: X-MF: command not found ../libtool: line 1141: X.deps/ctl_oss.Tpo: No such file or directory ../libtool: line 1141: X-c: command not found ../libtool: line 1192: Xctl_oss.lo: command not found ../libtool: line 1197: libtool: compile: cannot determine name of library object from `': command not found make[2]: *** [ctl_oss.lo] Error 1 make[2]: Leaving directory `/home/bogdan/tmp/alsa-plugins-1.0.25/oss' make[1]: *** [all-recursive] Error 1 make[1]: Leaving directory `/home/bogdan/tmp/alsa-plugins-1.0.25' make: *** [all] Error 2 bogdan@bogdan-desktop:~/tmp/alsa-plugins-1.0.25$

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  • How disable mysql command in sudoers file?

    - by Carlos A. Junior
    How i can disable /usr/bin/mysql command in sudoers file ? ... Actually I've tryed use with this way: %tailonly ALL=!/usr/bin/mysql But when i'm access if user 'tailonly' of group 'tailonly', this command still enabled. In resume, i'm only want that 'tailonly' user access 'tail -f /usr/app/*.log' ... This is possible ? Edit: With this config, the user 'tailonly' still can access mysql terminal with 'mysql' command: $: sudo su $: visudo Cmnd_Alias MYSQL = /usr/bin/mysql Cmnd_Alias TAIL=/usr/bin/tail -f /jacad/jacad3/logs/*.log # User privilege specification root ALL=(ALL:ALL) ALL # Members of the admin group may gain root privileges %admin ALL=(ALL) ALL # Allow members of group sudo to execute any command %sudo ALL=(ALL:ALL) ALL %swa ALL=/etc/init.d/jacad3 stop %swa ALL=/etc/init.d/jacad3 start %swa ALL=/etc/init.d/jacad3 restart %swa ALL=sudoedit /jacad/jacad3/bin/jacad_start.sh %tailonly ALL=ALL,!MYSQL

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