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  • Regular Expression: back references

    - by sixtyfootersdude
    sed 's/^\(\h*\)\(.*\)$/\1<!-- \2 -->/' web.xml I think that this should take this xml: <a> <d> bla </d> </a> And turn it into: <!-- <a> --> <!-- <d> --> <!-- bla --> <!-- </d> --> <!-- </a> --> But what is doing is this: <!-- <a> --> <!-- <d> --> <!-- bla --> <!-- </d> --> <!-- </a> -->

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  • Extract 2 numbers preceded with two different strings in a paragrapf using TCL Regular Expression

    - by Madhu
    Hi, I need to extract two different numbers preceded by two different strings. Employee Id-- Employee16(I need 16) and Employee links-- Employee links:2 (I need 2). Source String looks like following: Employee16, Employee name is QueenRose Working for 46w0d Billing is Distributed 65537 assigned tasks, 0 reordered, 0 unassigned 0 discarded, 0 lost received, 5/255 load received sequence unavailable, 0xC2E7 sent sequence Employee links: 2 active, 0 inactive (max not set, min not set) Dt3/5/10:0, since 46w0d, no tasks pending Dt3/5/10:10, since 21w0d, no tasks rcvd Employee is currently working in Hardware section. Employee19, Employee name is Edward11 Working for 48w4d Billing is Distributed 206801498 assigned tasks, 0 reordered, 0 unassigned 655372 discarded, 0 lost received, 9/255 load received sequence unavailable, 0x23CA sent sequence Employee links: 7 active, 0 inactive (max not set, min not set) Dt3/5/10:0, since 47w2d, tasks pending Dt3/5/10:10, since 28w6d, no tasks pending Dt3/5/10:11, since 18w4d, no tasks pending Dt3/5/10:12, since 18w4d, no tasks pending Dt3/5/10:13, since 18w4d, no tasks pending Dt3/5/10:14, since 18w4d, no tasks pending Dt3/5/10:15, since 7w2d, no tasks pending Employee is currently working in Hardware sectione. Employee6 (inactive) Employee links: 2 Dt3/5/10:0 (inactive) Dt3/5/10:10 (inactive) Employee7 (inactive) Employee links: 2 Dt3/5/10:0 (inactive) Dt3/5/10:10 (inactive) Tried with the following: Multilink(\d+)[^\n\r]*[^M]*Member links:\s+(\d+) But is not listing all the Ids and links. Can anybody help me getting this? Thanks in advance, Madhu.

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  • Django QuerySet ordering by expression

    - by Andrew
    How can i use order_by like order_by('field1'*'field2') For example i have items with price listed in different currencies, so to order items - i have to make currency conversion. class Currency(models.Model): code = models.CharField(max_length=3, primary_key=True) rateToUSD = models.DecimalField(max_digits=20,decimal_places=10) class Item(models.Model): priceRT = models.DecimalField(max_digits=15, decimal_places=2, default=0) cur = models.ForeignKey(Currency) I would like to have something like: Item.objects.all().order_by(F('priceRT')*F('cur__rateToUSD')) But unfortunately it doesnt work, i also faild with annotate. How can i permorm QuerySet ordering by result of value multiplication of 2 model's fields.

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  • Finding tags in query string with regular expression

    - by fatmatto
    Hi everybody! I have to set some routing rules in my php application, and they should be in the form /%var/something/else/%another_var In other words i beed a regex that returns me every URI piece marked by the % character, String marked by % represent var names so they can be almost every string. another example: from /%lang/module/controller/action/%var_1 i want the regex to extract lang and var_1 i tried something like /.*%(.*)[\/$]/ but it doesn't work.....

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  • Regular expression

    - by atno
    Hi I have an array that its first element might contains something like [some text, here. That's some text] I'm trying to figure out a pattern to check if such string exists and if not create it but having problem with making the pattern. Here's what I've done so far $pattern = '/^\[*\]$/'; if(preg_match($pattern,$exploded[0])){ $name = array_shift($exploded); }else{ $name = "[Unnamed import] - " .gmdate("His"); } But I always get [Unnamed import] - 032758 even when I'm sure that pattern match

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  • which regular expression will capture this sequence?

    - by John Smith
    The text follows this pattern <tr class="text" (any sequence of characters here, except ABC)ABC(any sequence of characters here, except ABC) <tr class="text" (any sequence of characters here, except ABC)ABC(any sequence of characters here, except ABC) <tr class="text" (any sequence of characters here, except ABC)ABC(any sequence of characters here, except ABC) <tr class="text" (any sequence of characters here, except ABC)ABC(any sequence of characters here, except ABC) so basically the above line might repeat itself multiple times, and the idea is to retrieve the first 3 characters immediately after ABC. I have tried regular expressions along the lines of \<tr class="text" [.]+ABC(?<capture>[.]{3}) but they all fail. Can someone give me a hint?

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  • Help me to split string with Regular Expression

    - by Lu Lu
    Hello, I have a string: CriteriaCondition={FieldName={*EPS}*$MinValue=(-201)$MaxValue=(304)$TradingPeriod=(-1)} Help me to get the first word which ends with the first word "={" & get the next following word which ends with "}". The result must be: Word1 = "CriteriaCondition" Word2 = "FieldName={EPS}$MinValue=(-201)$MaxValue=(304)$TradingPeriod=(-1)" And with the string "FieldName=(EPS)$MinValue=(-201)$MaxValue=(304)$TradingPeriod=(-1)", help me to split to pairs: FieldName EPS MinValue -201 MaxValue 304 TradingPeriod -1 Thanks.

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  • Pass a captured named regular expression to URL dictionary in generic view

    - by Trent Jurewicz
    I am working with a generic view in Django. I want to capture a named group parameter in the URL and pass the value to the URL pattern dictionary. For example, in the URLConf below, I want to capture the parent_slug value in the URL and pass it to the queryset dictionary value like so: urlpatterns = patterns('django.views.generic.list_detail', (r'^(?P<parent_slugs>[-\w])$', 'object_list', {'queryset':Promotion.objects.filter(category=parent_slug)}, 'promo_promotion_list'), ) Is this possible to do in one URLConf entry, or would it be wiser if I create a custom view to capture the value and pass the queryset directly to the generic view from my overridden view?

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  • Extract a regular expression match in R version 2.10

    - by tovare
    Hi, I'm trying to extract a number from a string. And do something like this [0-9]+ on this string "aaaa12xxxx" and get "12". I thought it would be something like: > grep("[0-9]+","aaa12xxx", value=TRUE) [1] "aaa12xxx" And then I figured... > sub("[0-9]+", "\\1", "aaa12xxxx") [1] "aaa12xxx" But I got some form of response doing: > sub("[0-9]+", "ARGH!", "aaa12xxxx") [1] "aaaARGH!xxx" There's a small detail I'm missing Please advice :-) I'm using R version 2.10.1 (2009-12-14) Thanks ! Comments on the solution The best solution is to ignore the standard functions and install Hadley Wickham's stringr package to get something that actually makes sense. Kudos to Marek for figuring out how the standard library worked.

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  • Regular Expression - Match only 7 chars?

    - by Simon
    I'm trying to match a SEDOL (exactly 7 chars: 6 alpha-numeric chars followed by 1 numeric char) My regex ([A-Z 0-9]{6})[0-9]{1} matches correctly but strings greater than 7 chars that begin with a valid match also match (if you see what I mean :)). For example: B3KMJP4 matches correctly but so does: B3KMJP4x which shouldn't match. Can anyone show me how to avoid this?

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  • Find last match with python regular expression

    - by SDD
    I wanto to match the last occurence of a simple pattern in a string, e.g. list = re.findall(r"\w+ AAAA \w+", "foo bar AAAA foo2 AAAA bar2) print "last match: ", list[len(list)-1] however, if the string is very long, a huge list of matches is generated. Is there a more direct way to match the second occurence of "AAAA" or should I use this workaround?

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  • Scala: Matching optional Regular Expression groups

    - by Brian Heylin
    I'm trying to match on an option group in Scala 2.8 (beta 1) with the following code: import scala.xml._ val StatementPattern = """([\w\.]+)\s*:\s*([+-])?(\d+)""".r def buildProperty(input: String): Node = input match { case StatementPattern(name, value) => <propertyWithoutSign /> case StatementPattern(name, sign, value) => <propertyWithSign /> } val withSign = "property.name: +10" val withoutSign = "property.name: 10" buildProperty(withSign) // <propertyWithSign></propertyWithSign> buildProperty(withoutSign) // <propertyWithSign></propertyWithSign> But this is not working. What is the correct way to match optional regex groups?

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  • how to fix my error saying expected expression before 'else'

    - by user292489
    this program intended to read a .txt, a set of numbers, file and wwrite to another two .txt files called even amd odd as follows: #include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) { int i=0,even,odd; int number[i]; // check to make sure that all the file names are entered if (argc != 3) { printf("Usage: executable in_file output_file\n"); exit(0); } FILE *dog = fopen(argv[1], "r"); FILE *feven= fopen(argv[2], "w"); FILE *fodd= fopen (argv[3], "w"); // check whether the file has been opened successfully if (dog == NULL) { printf("File %s cannot open!\n", argv[1]); exit(0); } //odd = fopen(argv[2], "w"); { if (i%2!=1) i++;} fprintf(feven, "%d", even); fscanf(dog, "%d", &number[i]); else { i%2==1; i++;} fprintf(fodd, "%d", odd); fscanf(dog, "%d", &number[i]); fclose(feven); fclose(fodd);

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  • Buggy Perl regular expression

    - by Tichomir Mitkov
    Hi, there I'm writing a program that has to get values from a file. In the file each line indicates an entity. Each entity has three values. For example: Value1 Value2 value3 I have a regular expresion to match them m/(.*?) (.*?) (.*?)/m; But it seems that the third value in never matched! The only way to match the third value is to add another value in the file and another "matching brackets" in the expresion. But this does not satisfy me. Thanks in Advance!

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