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  • Javascript: regular expression

    - by Dmitry Nesteruk
    I need to replace a substring from some string. I've already created corrected code for doing it. But I amn't sure is it best way. Please, see code below: var str = 'test ruby,ruby on rails,ruby,' var substr = 'ruby'; var reg = new RegExp(',' + substr + ',|^' + substr + ',', 'gi'); str.replace(reg, ','); //returns "test ruby,ruby on rails,"

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  • Correct expression for checking leap years

    - by Debanjan
    What will be the exact definition of leap year? AFAIK "A year which is divisible by 4 is a leap year. But for century years' the years which are divisible by 400 is a leap year." But that definition makes 100, 200, 300, 400.... upto 1700 NOT LEAP years! But in Gregorian calendar all of them are all leap year, check this out. You can also try "call 1700" in Linux to verify. So the correct algorithm for leap years would be: if ( (year % 4 == 0) && ( year <= 1700 || year % 100 != 0 || year % 400 == 0 )) printf("%d is a leap year.\n", year); else printf("%d is not a leap year.\n", year); But is this specific to Gregorian calendar? Even if that is the case why is it not mentioned here? Regards, PS:The history of Gregorian callender seems interesting check out the September month of 1752.

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  • How to replace the string based on an expression

    - by deepak
    I'm having a string where i'm using some placeholders to replace it with some values based on an object. It is like the following: Hello User <#= UserName #> I need to replace the <#= UserName # with a value. How can this be done with a regex? Please help. I dont want a string replace solution. There are somany placeholders and hardcoding the <#= UserName # and replace with the value is pointless

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  • How can I build value for "for-each" expression in XSLT with help of parameter

    - by Artic
    I need to navigate through this xml tree. <publication> <corporate> <contentItem> <metadata>meta</metadata> <content>html</content> </contentItem> <contentItem > <metadata>meta1</metadata> <content>html1</content> </contentItem> </corporate> <eurasia-and-africa> ... </eurasia-and-africa> <europe> ... </europe> </publication> and convert it to html with this stylesheet <ul> <xsl:variable name="itemsNode" select="concat('publicationManifest/',$group,'/contentItem')"></xsl:variable> <xsl:for-each select="$itemsNode"> <li> <xsl:value-of select="content"/> </li> </xsl:for-each> </ul> $group is a parameter with name of group for example "corporate". I have an error with compilation of this stylsheet. SystemID: D:\1\contentsTransform.xslt Engine name: Saxon6.5.5 Severity: error Description: The value is not a node-set Start location: 18:0 What the matter?

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  • Java regular expression: how to include '-'

    - by changed
    I am using this pattern and matching a string. String s = "//name:value /name:value"; if (s.matches("(//?\\s*\\w+:\\w+\\s*)+")) { // it fits } This works properly. But if I want to have a string like "/name-or-address:value/name-or-address:value" which has this '-' in second part, it doesn't work. I am using \w to match A-Za-z_, but how can I include - in that?

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  • Regular Expression: Allow letters, numbers, and spaces (with at least one letter or number)

    - by makeee
    I'm currently using this regex ^[A-Z0-9 _]*$ to accept letters, numbers, spaces and underscores. I need to modify it to require at least one number or letter somewhere in the string. Any help would be appreciated! This would be for validating usernames for my website. I'd actually like to support as many characters as I can, but just want to ensure that I prevent code injection and that characters will display fine for all users. So I'm definately open to regex validation suggestions that would support a wider set of characters.

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  • Write an expression in javascript

    - by Hero
    hi everybody... I need a javascript code that split a string like below: Input string: "a=aa| b=b||b | c=cc" Output: a=>aa b=>b||b c=>cc I'd written different codes like: split(/ \ | /) or Split(/ \| (?! \ |) /) but didn't work. please help me... I really need it fast.

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  • Regular Expression to Match All Characters after another Regex Match

    - by Anthony Wood
    I know this may sound a little confusing, so I am open to suggestions on renaming the title. Basically I have string such as C:...\Downloads\Folder\SubFolder\SubSubFolder. and I want to return the SubFolder and SubSubFolder only. So far, my Regex looks like (?=\\Downloads\\.*?\\).* which matches Downloads\Folder\SubFolder\SubSubFolder. Does anybody have any Ideas what I am missing???? All the solutions below seem to work (except if you didn't know "Folder"). Potentially a bug with the tool I was using to test the regular expressions.

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  • antlr line after line processing

    - by pawloch
    I'm writing simple language in ANTLR, and I'd like to write shell where I can put line of code, hit ENTER and have it executed, enter another line, and have it executed. I have already written grammar which execute all alines of input at one. Example input: int a,b,c; string d; string e; d=\"dziala\"; a=4+7; b=a+33; c=(b/11)*2; grammar Kalkulator; options { language = Java; output=AST; ASTLabelType=CommonTree; } tokens { NEG; } @header { package lab4; } @lexer::header { package lab4; } line : (assignment | declaration)* EOF ; declaration : type^ IDENT (','! IDENT)* ';'! ; type : 'int' | 'string' ; assignment : IDENT '='^ expression ';'! ; term : IDENT | INTEGER | STRING_LITERAL | '('! expression ')'! ; unary : (( negation^ | '+'! ))* term ; negation : '-' -> NEG ; mult : unary ( ('*'^ | '/'^) unary )* ; exp2 :mult ( ('-'^ | '+'^) mult)* ; expression : exp2 ('&'^ exp2)* ; fragment LETTER : ('a'..'z'|'A'..'Z'); fragment DIGIT : '0'..'9'; INTEGER : DIGIT+; IDENT : LETTER (LETTER | DIGIT)* ; WS : (' ' | '\t' | '\n' | '\r' | '\f')+ {$channel=HIDDEN;}; STRING_LITERAL : '\"' .* '\"'; and: tree grammar Evaluator; options { language = Java; tokenVocab = Kalkulator; ASTLabelType = CommonTree; } @header { package lab4; import java.util.Map; import java.util.HashMap; } @members { private Map<String, Object> zmienne = new HashMap<String, Object>(); } line returns [Object result] : (declaration | assignment { result = $assignment.result; })* EOF ; declaration : ^(type ( IDENT { if("string".equals($type.result)){ zmienne.put($IDENT.text,""); //add definition } else{ zmienne.put($IDENT.text,0); //add definition } System.out.println($type.result + " " + $IDENT.text);//write output } )* ) ; assignment returns [Object result] : ^('=' IDENT e=expression) { if(zmienne.containsKey($IDENT.text)) {zmienne.put($IDENT.text, e); result = e; System.out.println(e); } else{ System.out.println("Blad: Niezadeklarowana zmienna"); } } ; type returns [Object result] : 'int' {result="int";}| 'string' {result="string";} ; expression returns [Object result] : ^('+' op1=expression op2=expression) { result = (Integer)op1 + (Integer)op2; } | ^('-' op1=expression op2=expression) { result = (Integer)op1 - (Integer)op2; } | ^('*' op1=expression op2=expression) { result = (Integer)op1 * (Integer)op2; } | ^('/' op1=expression op2=expression) { result = (Integer)op1 / (Integer)op2; } | ^('%' op1=expression op2=expression) { result = (Integer)op1 \% (Integer)op2; } | ^('&' op1=expression op2=expression) { result = (String)op1 + (String)op2; } | ^(NEG e=expression) { result = -(Integer)e; } | IDENT { result = zmienne.get($IDENT.text); } | INTEGER { result = Integer.parseInt($INTEGER.text); } | STRING_LITERAL { String t=$STRING_LITERAL.text; result = t.substring(1,t.length()-1); } ; Can I make it process line-by-line or is that easier to make it all again?

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  • Perl Regular Expression [] for <>

    - by bmucklow
    So I am trying to read an XML file into a string in Perl and send it as part of a SOAP message. I know this is not ideal as there are methods for SOAP sending files, however, I am limited to having to use the SOAP that is set up, and it is not set up for sending with file support. Therefore I need to parse out the markup tags < and replace them with []. What is the best way to do this?

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  • VB.net Regular Expression

    - by xzerox
    Alright so I want to grab the information on a website thats between [usernames] and [/usernames] I know how to get the string but how would I use regex to only have the information in the middle. Remember I am going to be having more then one thing on the page.

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  • Regular Expression to parse SQL Structure

    - by user351429
    I am trying to parse the MySQL data types returned by "DESCRIBE [TABLE]". It returns strings like: int(11) float varchar(200) int(11) unsigned float(6,2) I've tried to do the job using regular expressions but it's not working. PHP CODE: $string = "int(11) numeric"; $regex = '/(\w+)\s*(\w+)/'; var_dump( preg_split($regex, $string) );

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  • Regular expression on a URL

    - by alphaexe
    I need to be able to catch when the URL contains a image of multiple file types or follow this syntax. http://localhost:8080/fdlic-web/webpic/101 Here is what i have so far. (.*)(jpg|gif|png|bmp|jpeg|webpic/(\d+))$

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  • using regular expression / Remove special characters with linq to sql

    - by Prasad
    How can i use regular expressions with linq to sql in the asp.net mvc(C#) application? The columns in my MSSQL table (Products) has some special characters like (, - % ',.....). While searching for a product i need to search without that special chareters. For ex.: I have a product say (ABC-Camp's / One), when i search for "abccamp", it should pull the product. I am trying the query like: from p in _context.pu_Products where p.User_Id == userId && p.Is_Deleted == false && p.Product_Name.ToLower().Contains(text.ToLower()) select new Product { ProductId = p.Product_Id, ProductName = p.Product_Name.Replace("’", "").Replace("\"", ""), RetailPrice = p.Retail_Price ?? 0M, LotSize = p.Lot_Size > 0 ? p.Lot_Size ?? 1 : 1, QuantityInHand = p.Quantity_In_Hand ?? 0 } But i need to search without any special characters...

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  • Php regular expression to match a div

    - by Thoman
    Hello all <div id="a"> <div id="b"> Foo </div> <div id="m"> Bar </div> </div> <div id="c"> Bar </div> I want find all object in id="a" and out put is <div id="a"> <div id="b"> Foo </div> <div id="m"> Bar </div> </div> Geat thanks.

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  • Regular expression matching in php

    - by user1836428
    I have this regexp: /(.*)(([0-9]([^a-zA-Z])*){7,}[0-9])(.*)/. Given the following values 0654535263 065453-.-5263 065asd4535263 Expected Results 06**** 06**** 06**** Actual Results 0654535263 06**** 065asd4535263 It does not match the last row because of the letters (I want to match from 0-3 letters) and it matches only last occurence (in the second row in example, it skips first row).

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  • PHP Regular Expression to quotations to attributes

    - by atwellpub
    hey Guys, I need to run a string of html through a regex function that checks to see if the attributes are closed in quotes, and if they aren't then close them. for example i want <img src=http://www.domain.com/image.gif border=0> to turn into <img src='http://www.domain.com/image.gif' border='0'> Can anyone help me?

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  • How to write a regular expression for "everything between X and Y" for use with preg_replace

    - by pg
    I want to take a variable called $encoded_str and and remove cd1, CD1 and anything between the first 'l' and the last blank space. So for example "lp6 id4 STRINGcd1" would return "STRING". I'm using PHP 4 for now so I can't use str_ireplace, I have this: $encoded_str=str_replace('CD1','',$encoded_str); $encoded_str=str_replace('cd1','',$encoded_str); $encoded_str=preg_replace('X','',$encoded_str); I've RTFM for preg_replace but am a bit confused. What should I replace the X with and can you suggest a decent introductory primer for writing regular expressions?

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