Search Results

Search found 32044 results on 1282 pages for 'va list'.

Page 39/1282 | < Previous Page | 35 36 37 38 39 40 41 42 43 44 45 46  | Next Page >

  • how to remove a column of a list on SharePoint

    - by George2
    Hello everyone, I am using SharePoint 2007 + Windows Server 2008 with SharePoint 2007's publishing portal template. I have created a list with datasheet view on a page (I add the list by adding a Web Part - then select the list control to add it as a web part to the page.) When create the list, I have added 5 columns, and inserted some rows. My question is, how to remove one column of the list? thanks in advance, George

    Read the article

  • How to remove folder from Explorer's jump list

    - by m.floryan
    I'm using Windows 7 and Windows Explorer some folders were added to the taskbar jump list (under the Frequent section) that no longer exist. When I try to remove those folders from the jump list (using context menu's "Remove from this list" option) nothing happens and the folders are still shown. When I try to access those non-existing folders windows prompts that selected item is not available and asks whether I want to remove it from the list. Regardless if I select "Yes" or "No" the folder still remains in the list.

    Read the article

  • i m trying to return list<object> from webmethod but gives error

    - by girish
    System.InvalidOperationException: There was an error generating the XML document. --- System.InvalidOperationException: The type WebService.Property.Property_Users was not expected. Use the XmlInclude or SoapInclude attribute to specify types that are not known statically. at System.Xml.Serialization.XmlSerializationWriter.WriteTypedPrimitive(String name, String ns, Object o, Boolean xsiType) at Microsoft.Xml.Serialization.GeneratedAssembly.XmlSerializationWriter1.Write1_Object(String n, String ns, Object o, Boolean isNullable, Boolean needType) at Microsoft.Xml.Serialization.GeneratedAssembly.XmlSerializationWriter1.Write8_ArrayOfAnyType(Object o) at Microsoft.Xml.Serialization.GeneratedAssembly.ListOfObjectSerializer.Serialize(Object objectToSerialize, XmlSerializationWriter writer) at System.Xml.Serialization.XmlSerializer.Serialize(XmlWriter xmlWriter, Object o, XmlSerializerNamespaces namespaces, String encodingStyle, String id) --- End of inner exception stack trace --- at System.Xml.Serialization.XmlSerializer.Serialize(XmlWriter xmlWriter, Object o, XmlSerializerNamespaces namespaces, String encodingStyle, String id) at System.Xml.Serialization.XmlSerializer.Serialize(TextWriter textWriter, Object o, XmlSerializerNamespaces namespaces) at System.Xml.Serialization.XmlSerializer.Serialize(TextWriter textWriter, Object o) at System.Web.Services.Protocols.XmlReturnWriter.Write(HttpResponse response, Stream outputStream, Object returnValue) at System.Web.Services.Protocols.HttpServerProtocol.WriteReturns(Object[] returnValues, Stream outputStream) at System.Web.Services.Protocols.WebServiceHandler.WriteReturns(Object[] returnValues) at System.Web.Services.Protocols.WebServiceHandler.Invoke() public List<object> GetDataByModuleName(string ModuleName) { List<Property_Users> obj_UserList = new List<Property_Users>(); // performing some operation that add data to obj_UserList List < Object > myList = new List<object>(); return ConvertToObjectList<Property_Users>(obj_UserList); } public List<Object> ConvertToObjectList<N>(List<N> sourceList) { List<Object> result = new List<Object>(); foreach (N item in sourceList) { result.Add(item as Object); } return result; } [WebMethod] public List<object> GetDataByModuleName(string ModuleName) { List<object> obj_list = new List<object>(); obj_list = BAL_GeneralService.GetDataByModuleName(ModuleName); return obj_list; }

    Read the article

  • How to find nth element from the end of a singly linked list?

    - by Codenotguru
    The following function is trying to find the nth to last element of a singly linked list. For example: If the elements are 8->10->5->7->2->1->5->4->10->10 then the result is 7th to last node is 7. Can anybody help me on how this code is working or is there a better and simpler approach? LinkedListNode nthToLast(LinkedListNode head, int n) { if (head == null || n < 1) { return null; } LinkedListNode p1 = head; LinkedListNode p2 = head; for (int j = 0; j < n - 1; ++j) { // skip n-1 steps ahead if (p2 == null) { return null; // not found since list size < n } p2 = p2.next; } while (p2.next != null) { p1 = p1.next; p2 = p2.next; } return p1; }

    Read the article

  • How to get rid of white space between css horizontal list items?

    - by Curyous
    I've got the following test page and css. When displayed, there is a 4px gap between each list item. How do I get the items to be next to each other? <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Frameset//EN" "http://www.w3.org/TR/html4/frameset.dtd"> <html> <head> <link type="text/css" rel="stylesheet" href="/stylesheets/test.css" /> </head> <body> <div> <ul class="nav"> <li class="nav"><a class="nav" href="#">One1</a></li> <li class="nav"><a class="nav" href="#">Two</a></li> <li class="nav"><a class="nav" href="#">Three</a></li> <li class="nav"><a class="nav" href="#">Four</a></li> </ul> </div> </body> </html> The css: ul.nav, ul li.nav { display: inline; margin: 0px; padding: 0px; } ul.nav { list-style-type: none; } li.nav { background-color: red; } a.nav { background-color: green; padding: 10px; margin: 0px; } a:hover.nav { background-color: gray; }

    Read the article

  • How to create and display a list in Java?

    - by lox
    i have to create a list of ,let's say 50 people, (in Java) and display the list, and i don't really know how to do that. so this is what i have tried to do so far . please correct and complete some of my code . public class Person { String name; String stuff; } public class CreatePerson { public static void ang() { ArrayList<Person> thing=new ArrayList<Person>(); Scanner diskScanner = new Scanner(in); for(int i=0; i<50; i++){ Person pers = new Person(); out.print("name: "); pers.name=diskScanner.nextLine(); out.print("stuff: "); pers.stuff=diskScanner.nextLine(); thing.add(pers); break; } // Display people for (int i=0; i<50; i++) { out.println(??);{ } } }}

    Read the article

  • convert an int to list of individual digitals more faster?

    - by user478514
    All, I want define an int(987654321) <= [9, 8, 7, 6, 5, 4, 3, 2, 1] convertor, if the length of int number < 9, for example 10 the list will be [0,0,0,0,0,0,0,1,0] , and if the length 9, for example 9987654321 , the list will be [9, 9, 8, 7, 6, 5, 4, 3, 2, 1] >>> i 987654321 >>> l [9, 8, 7, 6, 5, 4, 3, 2, 1] >>> z = [0]*(len(unit) - len(str(l))) >>> z.extend(l) >>> l = z >>> unit [100000000, 10000000, 1000000, 100000, 10000, 1000, 100, 10, 1] >>> sum([x*y for x,y in zip(l, unit)]) 987654321 >>> int("".join([str(x) for x in l])) 987654321 >>> l1 = [int(x) for x in str(i)] >>> z = [0]*(len(unit) - len(str(l1))) >>> z.extend(l1) >>> l1 = z >>> l1 [9, 8, 7, 6, 5, 4, 3, 2, 1] >>> a = [i//x for x in unit] >>> b = [a[x] - a[x-1]*10 for x in range(9)] >>> if len(b) = len(a): b[0] = a[0] # fix the a[-1] issue >>> b [9, 8, 7, 6, 5, 4, 3, 2, 1] I tested above solutions but found those may not faster/simple enough than I want and may have a length related bug inside, anyone may share me a better solution for this kinds convertion? Thanks!

    Read the article

  • Use JQuery to check a checkbox in a parent list-item?

    - by Daniel O'Connor
    Hey Everyone, I'm brand new to Javascript and JQuery, so I've been reading up on it and am trying to check (and set inactive) a checkbox in a parent list-item when one of the children are checked. If this doesn't make any sense, take a look at the list structure. <ul> <li><input type="checkbox" name="items[]" value="88712003" id="88712003" /> Parent 1</li> <li><input type="checkbox" name="items[]" value="88712003" id="88712003" /> Parent 2 <ul> <li><input type="checkbox" name="items[]" value="21312341" id="21312341" /> Child 1</li> <li><input type="checkbox" name="items[]" value="21312341" id="21312341" /> Child 2</li> </ul> </li> <li><input type="checkbox" name="items[]" value="88712003" id="88712003" /> Parent 3</li> <li><input type="checkbox" name="items[]" value="88712003" id="88712003" /> Parent 4</li> </ul> If Child 1 or Child 2 is checked, I want the input in Parent 2 to be checked and set inactive. I've started working on it, but got stuck here: $(function(){ $('.child').click(function() { $(this).parent().parent().parent().toggle(); }); }); As you can see, I didn't make it far. Any help would be appreciated. Thanks!

    Read the article

  • How to use a divider in a navigation with list elements?

    - by Kris
    I want to create a navigation which got divider between each list element. Here is a simple HTML/CSS Code/Template : <nav> <ul> <li><a href="#">A</a></li> <li><a href="#">B</a></li> <li><a href="#">C</a></li> <li><a href="#">D</a></li> <li><a href="#">E</a></li> </ul> </nav> nav ul { list-style:none; float:right; } nav ul li { float:left; padding-left:10px; } nav ul li a { color:#111; font-family:Verdana; font-size:15px; text-decoration:none; } nav ul li a:hover { color:#9F3039; } so just a simple looking navigation which floats from the right side on a logo which is not displayed in the code here. Now I want to at devider between each link - I know I could do it with border-right and just use another class on my last listelement which set the border-right off, BUT I want to use a special kind of divider - an image. How can I do it best ?

    Read the article

  • learning C++ from java, trying to make a linked list.

    - by kyeana
    I just started learning c++ (coming from java) and am having some serious problems with doing anything :P Currently, i am attempting to make a linked list, but must be doing something stupid cause i keep getting "void value not ignored as it ought to be" compile errors (i have it marked where it is throwing it bellow). If anyone could help me with what im doing wrong, i would be very grateful :) Also, I am not used to having the choice of passing by reference, address, or value, and memory management in general (currently i have all my nodes and the data declared on the heap). If anyone has any general advice for me, i also wouldn't complain :P Key code from LinkedListNode.cpp LinkedListNode::LinkedListNode() { //set next and prev to null pData=0; //data needs to be a pointer so we can set it to null for //for the tail and head. pNext=0; pPrev=0; } /* * Sets the 'next' pointer to the memory address of the inputed reference. */ void LinkedListNode::SetNext(LinkedListNode& _next) { pNext=&_next; } /* * Sets the 'prev' pointer to the memory address of the inputed reference. */ void LinkedListNode::SetPrev(LinkedListNode& _prev) { pPrev=&_prev; } //rest of class Key code from LinkedList.cpp #include "LinkedList.h" LinkedList::LinkedList() { // Set head and tail of linked list. pHead = new LinkedListNode(); pTail = new LinkedListNode(); /* * THIS IS WHERE THE ERRORS ARE. */ *pHead->SetNext(*pTail); *pTail->SetPrev(*pHead); } //rest of class

    Read the article

  • How to convert object to string list?

    - by user1381501
    I want to get two values by using linq select query and try to convert object to string list. I am trying to convert list to list. The code as below. I got the error when I convert object to string list : return returnvalue = (List)userlist; public List<string> GetUserList(string username) { List<User> UserList = new List<User>(); List<string> returnvalue=new List<string>(); try { string returnstring = string.Empty; DataTable dt = null; dt = Library.Helper.FindUser(username, 200); foreach (DataRow dr in dt.Rows) { User user = new User(); spuser.id = dr["ID"].ToString(); spuser.name = dr["Name"].ToString(); UserList.Adduser } } catch (Exception ex) { } List<SharePointMentoinUser> userlist = UserList.Select(a => new User { name = (string)a.name, id = (string)a.id }).ToList(); **return returnvalue = (List<string>)userlist;** }

    Read the article

  • creating bounding box list

    - by Christian Frantz
    I'm trying to create a list of bounding boxes for each cube drawn, so I can use the boxes to intersect with a ray that my mouse position is casting, but I have no idea how. I've created a list that stores the boxes, but how am I getting the values from each box? for (int x = 0; x < mapHeight; x++) { for (int z = 0; z < mapWidth; z++) { cubes.Add(new Vector3(x, map[x, z], z), Matrix.Identity, grass); boxList.Add(something here); } } public Cube(GraphicsDevice graphicsDevice) { device = graphicsDevice; var vertices = new List<VertexPositionTexture>(); BuildFace(vertices, new Vector3(0, 0, 0), new Vector3(0, 1, 1)); BuildFace(vertices, new Vector3(0, 0, 1), new Vector3(1, 1, 1)); BuildFace(vertices, new Vector3(1, 0, 1), new Vector3(1, 1, 0)); BuildFace(vertices, new Vector3(1, 0, 0), new Vector3(0, 1, 0)); BuildFaceHorizontal(vertices, new Vector3(0, 1, 0), new Vector3(1, 1, 1)); BuildFaceHorizontal(vertices, new Vector3(0, 0, 1), new Vector3(1, 0, 0)); cubeVertexBuffer = new VertexBuffer(device, VertexPositionTexture.VertexDeclaration, vertices.Count, BufferUsage.WriteOnly); cubeVertexBuffer.SetData<VertexPositionTexture>(vertices.ToArray()); } There aren't any clearly defined variables for the bounds of each cube created, so where do I create the bounding box from?

    Read the article

  • Canonical representation of a class object containing a list element in XML

    - by dendini
    I see that most implementations of JAX-RS represent a class object containing a list of elements as follows (assume a class House containing a list of People) <houses> <house> <person> <name>Adam</name> </person> <person> <name>Blake</name> </person> </house> <house> </house> </houses> The result above is obtained for instance from Jersey 2 JAX-RS implementation, notice Jersey creates a wrapper class "houses" around each house, however strangely it doesn't create a wrapper class around each person! I don't feel this is a correct mapping of a list, in other words I'd feel more confortable with something like this: <houses> <house> <persons> <person> <name>Adam</name> </person> <person> <name>Blake</name> </person> </persons> </house> <house> </house> </houses> Is there any document explaining how an object should be correctly mapped apart from any opninion?

    Read the article

  • Database and query to store and retreive friend list [migrated]

    - by amr Kamboj
    I am developing a module in website to save and retreive friend list. I am using Zend Framework and for DB handling I am using Doctrine(ORM). There are two models: 1) users that stores all the users 2) my_friends that stores the friend list (that is refference table with M:M relation of user) the structure of my_friends is following ...id..........user_id............friend_id........approved.... ...10.........20 ..................25...................1.......... ...10.........21 ..................25...................1.......... ...10.........22 ..................30...................1.......... ...10.........25 ..................30...................1.......... The Doctrine query to retreive friend list id follwing $friends = Doctrine_Query::create()->from('my_friends as mf') ->leftJoin('mf.users as friend') ->where("mf.user_id = 25") ->andWhere("mf.approved = 1"); Suppose I am viewing the user no.- 25. With this query I am only getting the user no.- 30. where as user no.- 25 is also approved friend of user no.- 20 and 21. Please guide me, what should be the query to find all friend and is there any need to change the DB structure.

    Read the article

  • Cube chunk via list ToArray()

    - by Christian Frantz
    I've created a list of vertices that I call for each cube made in my array "cubes". When each cube is create, SetUpVertices is called which is a method that stores the 8 vertices of my cube. At the end of my list creation, I create a vertex buffer, and set the data of the list that contains vertices of all 25 cubes to that vertex buffer, effectively creating a "chunk" of cubes. The problem is that Invalid Operation Exception "The array is not the correct size for the amount of data requested." at the line vertices.ToArray(). I don't have an array for this, as the amount of cubes will be changing and arrays aren't dynamic. What could be the cause of this? for (int x = 0; x < 5; x++) { for (int z = 0; z < 5; z++) { SetUpVertices(); cubes.Add(new Cube(device, new Vector3(x, map[x, z], z), color)); } } vertexBuffer = new VertexBuffer(device, typeof(VertexPositionColor), 8, BufferUsage.WriteOnly); vertexBuffer.SetData<VertexPositionColor>(vertices.ToArray());

    Read the article

  • Building a List of All SharePoint Timer Jobs Programmatically in C#

    - by Damon Armstrong
    One of the most frustrating things about SharePoint is that the difficulty in figuring something out is inversely proportional to the simplicity of what you are trying to accomplish.  Case in point, yesterday I wanted to get a list of all the timer jobs in SharePoint.  Having never done this nor having any idea of exactly how to do this right off the top of my head, I inquired to Google.  I like to think my Google-fu is fair to good, so I normally find exactly what I’m looking for in the first hit.  But on the topic of listing all SharePoint timer jobs all it came up with a PowerShell script command (Get-SPTimerJob) and nothing more. Refined search after refined search continued to turn up nothing. So apparently I am the only person on the planet who needs to get a list of the timer jobs in C#.  In case you are the second person on the planet who needs to do this, the code to do so follows: SPSecurity.RunWithElevatedPrivileges(() => {    var timerJobs = new List();    foreach (var job in SPAdministrationWebApplication.Local.JobDefinitions)    {       timerJobs.Add(job);    }    foreach (SPService curService in SPFarm.Local.Services)    {       foreach (var job in curService.JobDefinitions)       {          timerJobs.Add(job);       }     } }); For reference, you have the two for loops because the Central Admin web application doesn’t end up being in the SPFarm.Local.Services group, so you have to get it manually from the SPAdministrationWebApplication.Local reference.

    Read the article

  • Building a List of All SharePoint Timer Jobs Programmatically in C#

    - by Damon
    One of the most frustrating things about SharePoint is that the difficulty in figuring something out is inversely proportional to the simplicity of what you are trying to accomplish.  Case in point, yesterday I wanted to get a list of all the timer jobs in SharePoint.  Having never done this nor having any idea of exactly how to do this right off the top of my head, I inquired to Google.  I like to think my Google-fu is fair to good, so I normally find exactly what I'm looking for in the first hit.  But on the topic of listing all SharePoint timer jobs all it came up with a PowerShell script command (Get-SPTimerJob) and nothing more. Refined search after refined search continued to turn up nothing. So apparently I am the only person on the planet who needs to get a list of the timer jobs in C#.  In case you are the second person on the planet who needs to do this, the code to do so follows: SPSecurity.RunWithElevatedPrivileges(() => {    var timerJobs = new List();    foreach (var job in SPAdministrationWebApplication.Local.JobDefinitions)    {       timerJobs.Add(job);    }    foreach (SPService curService in SPFarm.Local.Services)    {       foreach (var job in curService.JobDefinitions)       {          timerJobs.Add(job);       }     } }); For reference, you have the two for loops because the Central Admin web application doesn't end up being in the SPFarm.Local.Services group, so you have to get it manually from the SPAdministrationWebApplication.Local reference.

    Read the article

  • Building a List of All SharePoint Timer Jobs Programmatically in C#

    - by Damon
    One of the most frustrating things about SharePoint is that the difficulty in figuring something out is inversely proportional to the simplicity of what you are trying to accomplish.  Case in point, yesterday I wanted to get a list of all the timer jobs in SharePoint.  Having never done this nor having any idea of exactly how to do this right off the top of my head, I inquired to Google.  I like to think my Google-fu is fair to good, so I normally find exactly what I'm looking for in the first hit.  But on the topic of listing all SharePoint timer jobs all it came up with a PowerShell script command (Get-SPTimerJob) and nothing more. Refined search after refined search continued to turn up nothing. So apparently I am the only person on the planet who needs to get a list of the timer jobs in C#.  In case you are the second person on the planet who needs to do this, the code to do so follows: SPSecurity.RunWithElevatedPrivileges(() => {    var timerJobs = new List();    foreach (var job in SPAdministrationWebApplication.Local.JobDefinitions)    {       timerJobs.Add(job);    }    foreach (SPService curService in SPFarm.Local.Services)    {       foreach (var job in curService.JobDefinitions)       {          timerJobs.Add(job);       }     } }); For reference, you have the two for loops because the Central Admin web application doesn't end up being in the SPFarm.Local.Services group, so you have to get it manually from the SPAdministrationWebApplication.Local reference.

    Read the article

  • Numbered list in Report Builder export to word

    - by Daniel
    I have created a SQL Server Reporting Services Report Builder 3 report that contains a list of several items from a SharePoint list. I would like the list on the report to be a numbered list, so that when exported to Word, if a user adds another item to the document, the numbering is updated automatically. I can simulate a numbered list by creating a table and using 'RowNumber' in one of the columns, however this does not get rendered as a true numbered list. Is there any way to create a true numbered list in Report Builder 3

    Read the article

  • How to write a recursive function that returns a linked list of nodes, when given a binary tree of n

    - by Jian Lin
    I was once asked of this in an interview: How to write a recursive function that returns a linked list of nodes, when given a binary tree of nodes? (flattening the data) For some reason, I tend to need more than 3 to 5 minutes to solve any recursive problem. Usually, 15 to 20 minutes will be more like it. How could we attack this problem, such as a very systematic way of reaching a solution, so that they can be solved in 3 to 5 minute time frame?

    Read the article

  • How do I convert tuple of tuples to list in one line (pythonic)?

    - by ThinkCode
    query = 'select mydata from mytable' cursor.execute(query) myoutput = cursor.fetchall() print myoutput (('aa',), ('bb',), ('cc',)) Why is it (cursor.fetchall) returning a tuple of tuples instead of a tuple since my query is asking for only one column of data? What is the best way of converting it to ['aa', 'bb', 'cc'] ? I can do something like this : mylist = [] myoutput = list(myoutput) for each in myoutput: mylist.append(each[0]) I am sure this isn't the best way of doing it. Please enlighten me!

    Read the article

< Previous Page | 35 36 37 38 39 40 41 42 43 44 45 46  | Next Page >