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  • SUM a pair of COUNTs from two tables based on a time variable

    - by Kevin O.
    Been searching for an answer to this for the better part of an hour without much luck. I have two regional tables laid out with the same column names and I can put out a result list for either table based on the following query (swap Table2 for Table1): SELECT Table1.YEAR, FORMAT(COUNT(Table1.id),0) AS Total FROM Table1 WHERE Table1.variable='Y' GROUP BY Table1.YEAR Ideally I'd like to get a result that gives me a total sum of the counts by year, so instead of: | REGION 1 | | REGION 2 | | YEAR | Total | | YEAR | Total | | 2010 | 5 | | 2010 | 1 | | 2009 | 2 | | 2009 | 3 | | | | | 2008 | 4 | I'd have: | MERGED | | YEAR | Total | | 2010 | 6 | | 2009 | 5 | | 2008 | 4 | I've tried a variety of JOINs and other ideas but I think I'm caught up on the SUM and COUNT issue. Any help would be appreciated, thanks!

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  • How could I compare these database values in PHP?

    - by Dan
    So a user selects from a drop down list a value. I take this value, put it into a variable, then select from the database the ID value of that table A holding the selected value also. So now I'm trying to use that ID value to get to a many-to-many relationship table that has the selected value from table A to a different table B. The many-to-many relationship table has both IDs. How can I compare this using PHP? So it would be like: $A = $_POST['a']; $sql = "SELECT a, aID from TABLEA WHERE a = $A"; What do I do then to compare the aID with the many-to-many relationships table, then get the other ID in that table and then take that ID to get values from table B?

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  • how to select all the data from many tables?

    - by Syom
    how to select all the data from many tables? i try `"SELECT * FROM `table1`, `table2`"` , but result none understandable for me. it returns only some rows from table1, and 3 times all the data from table2. i've red one same question here, but don't understand the answer. so could you help me? thanks in advance. update: when i try (SELECT * FROM `videos`) UNION (SELECT * FROM `users`) it returns #1222 - The used SELECT statements have a different number of columns

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  • Set AUTO_INCREMENT value programmatically

    - by Tim
    So this works... ALTER TABLE variation AUTO_INCREMENT = 10; But I want to do this; ALTER TABLE variation AUTO_INCREMENT = (SELECT MAX(id)+1 FROM old_db.varaition); but that doesnt work, and neither does; SELECT MAX(id)+1 INTO @old_auto_inc FROM old_db.variation ALTER TABLE variation AUTO_INCREMENT = @old_auto_inc; So does anyone know how to do this? ( I'm trying to ensure that AUTO_INCREMENT keys dont collide between an old and a new site and need to do this automatically. So I can just run a script when the new db goes live )

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  • PHP mysql_fetch does not return values

    - by Petr
    Hi, Being quite new with PHP, I cannot find any solution why this does not work. The query is OK and the resource is returned. But I dunno why fetch_assoc does not print values. Thanks $query=sprintf("SELECT ID,NAME FROM USERS WHERE PASS='%s' AND NAME='%s'",mysql_real_escape_string($p),mysql_real_escape_string($n)); $result=mysql_query($query); if ($result) { while ($row = mysql_fetch_assoc($result)) { echo $row['ID']; echo $row['NAME']; } } }

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  • Convert tax like IRS function to SQL

    - by CrashRoX
    Trying to convert this tax-like IRS function http://stackoverflow.com/questions/1817920/calculating-revenue-share-at-different-tiers to SQL. The assumption is the table would be one column (price) and the tiers will be added dynamically. My first attempt has some case statements that didn't work out well. I have since scrapped it :) Thanks for the help!

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  • Where I get wrong?

    - by Ole Jak
    I have PHP code like this require_once( "includes" . DIRECTORY_SEPARATOR . "constants.php"); $userID = validKey( $key ); $query = "select a.username, b.streamID from user a, streams b where a.id = b.userID;)"; $connection = mysql_connect(DB_SERVER,DB_USER,DB_PASS); if (!$connection) { die("Database connection failed: " . mysql_error()); } $db_select = mysql_select_db(DB_NAME,$connection); if (!$db_select) {die( "Database selection failed: " . mysql_error()); } $generated_table = mysql_fetch_array(mysql_query($query, $connection)); // line (*) print_r($generated_table); But PHP gives me error/worning and does not print anything out Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given on line (*) 1) Why It does not printed me anything out 2) Where am I wrong?

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  • Select past date from database x days from now

    - by Pr0no
    Consider the following table daterange _date trading_day ------------------------ 2011-08-01 1 2011-07-31 0 2011-07-30 0 2011-07-29 1 2011-07-28 1 2011-07-27 1 2011-07-26 1 2011-07-25 1 2011-07-24 0 2011-07-23 0 2011-07-22 1 2011-07-21 1 2011-07-20 1 2011-07-19 1 2011-07-18 1 2011-07-17 0 I'm in need of a query that returns a _date, x days before a given _date. When counting back, _days with trading_day = 0 should be ignored. A few examples: input | output -------------------------+------------ 1 day before 2011-07-19 | 2011-07-18 2 days before 2011-08-01 | 2011-07-28 (trading_day = 0 don't count) 3 days before 2011-07-29 | 2001-07-26 The first one is easy: SELECT _date FROM daterange WHERE trading_day = 0 AND _date < '2011-07-19' LIMIT 1 But I don't know how to query for the other examples. Do you?

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  • adding count( ) column on each row

    - by Arsenal
    I'm not sure if this is even a good question or not. I have a complex query with lot's of unions that searches multiple tables for a certain keyword (user input). All tables in which there is searched are related to the table book. There is paging on the resultset using LIMIT, so there's always a maximum of 10 results that get withdrawn. I want an extra column in the resultset displaying the total amount of results found however. I do not want to do this using a seperate query. Is it possible to add a count() column to the resultset that counts every result found? the output would look like this: ID Title Author Count(...) 1 book_1 auth_1 23 2 book_2 auth_2 23 4 book_4 auth_.. 23 ... Thanks!

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  • Online Hotel Booking System, Simultaneous Booking?

    - by KiiroSora09
    I'm asked to create an online booking system with online payment and I'm wondering what to do in the case when 2 customers booked for the same room(s) at the same time. For Example: At the same time: Customer1 and Customer2 booked for a standard room which only has 1 room available. (The Room availability will display that there is still 1 room available). And then they hit the 'confirm' button at the same time.

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  • Persisting Serializable Objects in Hibernate

    - by VeeArr
    I am attempting to persist objects that contain some large Serializable types. I want Hibernate to automatically generate my DDL (using Hibernate annotations). For the most part, this works, but the default database column type used by Hibernate when persisting these types is tinyblob. Unfortunately, this causes crashes when attempting to persist my class, because these types will not fit within the length of tinyblob. However, if I manually set the type (using @Column(columnDefinition="longblob")), it works fine. Is there any way to make the default binary type longblob instead of tinyblob, so that I don't need to manually specify the @Column annotation on each field?

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  • Yii 'limit' on related model's scope

    - by pethee
    I have a model called Guesses that has_many Comments. I'm making eager queries to this to then pass on as JSON as response to an API call. The relations are obviously set between the two models and they are correct(one2many <= belongs2) I added a scope to Comments called 'api' like this: public function scopes() { return array( 'api' => array( 'select' => 'id, comment, date', 'limit'=>3, 'order'=>'date DESC', 'together'=>true, ), ); } And I'm running the following one-liner query: $data = Guesses::model()->with('comments:api')->findAll(); The issue here is that when calling the 'api' scope using a with('relation'), the limit property simply doesn't apply. I added the 'together'=true there for another type of scope, plus I hear it might help. It doesn't make a difference. I don't need all the comments of all Guesses. I want the top 3 (or 5). I am also trying to keep the one-liner call intact and simple, manage everything through scopes, relations and parameterized functions so that the API call itself is clean and simple. Any advice?

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  • Very weird jquery/json problem...

    - by Scarface
    Hey guys I have finally located the cause of this problem...I just have no idea how to fix it and why it is happening. I have a jquery getjson function and it returns 0 results every 2-5 clicks on new topics or refreshes. For some reason if I change my query to sort results by ASC it always returns results and much quicker, but this poses a problem since I need results by DESC. If anyone has any ideas, I would greatly appreciate it because I am dumbfounded at this point. Here is my query but I need it by DESC SELECT time, user, message FROM comments WHERE topic_id='$topic_id' ORDER BY time ASC LIMIT 10 $.getJSON(files+"comments.php?action=view&load=initial&topic_id="+topic_id+"&t=" + (new Date()), function(json) { if(json.length) { for(i=0; i < json.length; i++) { $('#comment-list').prepend(prepare(json[i])); $('#list-' + count).fadeIn(1500); } } }); I return results like so while($row = mysql_fetch_array($res)){ $data[] = $row; } $out = json_encode($data); print $out;

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  • Where to store users visited pages?

    - by kofto4ka
    Hi there. I have a project, where I have posts for example. The task is next: I must show to user his last posts visit. This is my solution: every time user visits new (for him) topic, I create a new record in table visits. Table visits has next structure: id, user_id, post_id, last_visit. Now my tables visits has ~14,000,000 records and its still growing every day.. May be my solution isnt optimal and exists another way how to store users visits? Its important to save every visit as standalone record, because I also have feature to select and use users visits. And I cant purge this table, because data could be needed later month, year. How I could optimize this situation?

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  • RoR: Condition Always False - Why?

    - by Matt Hollingsworth
    Working in RoR 2.3.x. My quiz_results table has a row for user_id (3907) and result (0.1), and two users I'm looking at with no rows in the quiz_results table. This line keeps returining false: -if QuizResult.find_by_user_id(@user_id).present? But if I change it to anything that returns true, the next line reports an error on the * method: ="#{(QuizResult.average('score', :conditions => 'user_id = #{@user.id}') * 100).round}%" The beginning of the code is a loop: [email protected] do |user| Any ideas how to fix? Have tried unsuccessfully all day.

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  • Same Data Appear only once.

    - by friendishan
    I have the following code which produces following output:- <? $tablaes = mysql_query("SELECT * FROM members where id='$order[user_id]'"); $user = mysql_fetch_array($tablaes); $idsd=$user['id']; $rPaid=mysql_query("SELECT SUM(`price`) AS total FROM order_history WHERE type!='rent_referral' AND date>'" . strtotime($time1) . "' AND date<'" . strtotime($time2) . "'"); $hdPaid = mysql_fetch_array($rPaid); $sPaid=mysql_query("SELECT SUM(`price`) AS total FROM order_history WHERE user_id='$idsd' AND type!='rent_referral' AND date>'" . strtotime($time1) . "' AND date<'" . strtotime($time2) . "'"); while ($hPaid = mysql_fetch_array($sPaid)) { ?> <td><?=$user['username']?></td> <td><?=$hPaid['total']?></td> <? } ?> </tr> It appears like this http://dl.dropbox.com/u/14384295/darrenan.jpg I want same data to appear only once.. Like Username: Vegas and price with him only once.

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  • Sphinx without using an auto_increment id

    - by squeeks
    I am current in planning on creating a big database (2+ million rows) with a variety of data from separate sources. I would like to avoid structuring the database around auto_increment ids to help prevent against sync issues with replication, and also because each item inserted will have a alphanumeric product code that is guaranteed to be unique - it seems to me more sense to use that instead. I am looking at a search engine to index this database with Sphinx looking rather appealing due to its design around indexing relational databases. However, looking at various tutorials and documentation seems to show database designs being dependent on an auto_increment field in one form or another and a rather bold statement in the documentation saying that document ids must be 32/64bit integers only or things break. Is there a way to have a database indexed by Sphinx without auto_increment fields as the id?

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  • What information about a user is available via PHP?

    - by Camran
    This is about a classifieds website, where anyone may post classifieds. I have a security database which I intend to fill with information about the user who posts the classifieds. I intend to record information such as IP, name, tel, email, classified_text, classified_title etc etc. The reason for all this is that sometimes people become victims of fraud (fake classifieds etc). So I wonder, what information is possible to get from the poster which may help in tracking him/her down? IP is a given, but what else could be useful? And I would much like examples of how it would be useful also, as well as the code for it please, like $_SERVER['REMOTE_ADDR']. And btw, I use PHP and have Sql as a database. Thanks

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  • How to write this loop prettier?

    - by Tom
    I've just read this topic http://stackoverflow.com/questions/2930533/highlight-search-keywords-on-hover and actually I use pretty the same structure, but it looks awful. So can you give me an advice, how to write this loop prettier in one php file, I mean php and html at the same time? <table class="result"> <?php while ($row= mysql_fetch_array($result, MYSQL_ASSOC)) { $cQuote = highlightWords(htmlspecialchars($row['cQuotes']), $search_result); ?> <tr> <td style="text-align:right; font-size:15px;"><?php h($row['cArabic']); ?></td> <td style="font-size:16px;"><?php echo $cQuote; ?></td> <td style="font-size:12px;"><?php h($row['vAuthor']); ?></td> <td style="font-size:12px; font-style:italic; text-align:right;"><?php h($row['vReference']); ?></td> </tr> <?php } ?>

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  • SQL Server - How Do I Substract 2 Hours from Formatted Time

    - by user1842653
    I need to know how to add 2 hours to the below 'Completed' timestamp. Here is the Select statement Select Tsk.task_id,Tsk.org_id,Tsk.completed,Tsk.assgn_acct_id,name FROM tdstelecom.tasks As Tsk WHERE Tsk.task_id = '11094836' AND DATE(Tsk.completed) < CURDATE() AND DATE(Tsk.completed) >= DATE_SUB(CURDATE (),INTERVAL 180 DAY) Here are the results: 2012-08-22 14:18:14 Desired results: 2012-08-22 16:18:14

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  • Why is it inserting 0's instead of blank spaces into my DB using php?

    - by zeckdude
    I have an insert: $sql = 'INSERT into orders SET fax_int_prefix = "'.$_SESSION['fax_int_prefix'].'", fax_prefix = "'.$_SESSION['fax_prefix'].'", fax_first = "'.$_SESSION['fax_first'].'", fax_last = "'.$_SESSION['fax_last']; The value of all of these fields is that they are blank right before the insert. Here is an example of one of them I echo'd out just before the insert: $_SESSION[fax_prefix] = For some reason it inserts the integer 0, instead of a blank value or null, as it should. Why is it inserting 0's instead of blank spaces into my DB?

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  • PHP - Setting Database Info

    - by user1710648
    First off, I'm sorry if this shows no code which is not what Stack Overflow is about..But I have no clue where to go on this. I have a basic CMS I made, and I am trying to distribute it. I want to make it so that upon going to /cms/install for example, they set the database info, and different info to integrate into the CMS. Now my issue is, what would be the best method to allow the user to store that database info? A cookie seems to not be the right way..Could I store database info inside of a database? Not too sure where to go on this. More or less. What is the best way to temporarily store the database information the user gave before arrival of the full CMS.

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