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  • How to print an Objectified Element?

    - by BeeBand
    I have xml of the format: <channel> <games> <game slot='1'> <id>Bric A Bloc</id> <title-text>BricABloc Hoorah</title-text> <link>Fruit Splat</link> </game> </games> </channel> I've parsed this xml using lxml.objectify, via: tree = objectify.parse(file) There will potentially be a number of <game>s underneath <games>. I understand that I can generate a list of <game> objects via: [ tree.games[0].game[0:4] ] My question is, what class are those objects and is there a function to print any object of whatever class these objects belong to?

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  • How do I upload a files to google app engine app when field name is not known

    - by Michael Neale
    I have tried a few options, none of which seem to work (if I have a simple multipart form with a named field, it works well, but when I don't know the name I can't just grab all files in the request...). I have looked at http://stackoverflow.com/questions/81451/upload-files-in-google-app-engine and it doesn't seem suitable (or to actually work, as someone mentioned the code snipped it untested).

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  • Detect if 2 HTML fragments have identical hierarchical structure

    - by sergzach
    An example of fragments that have identical hierarchical structure: (1) <div> <span>It's a message</span> </div> (2) <div> <span class='bold'>This is a new text</span> </div> An example of fragments that have different structure: (1) <div> <span><b>It's a message</b></span> </div> (2) <div> <span>This is a new text</span> </div> So, fragments with a similar structure correspond to one hierarchical tree (the same tag names, the same hierarchical structure). How can I detect if 2 elements (html fragments) have the same structure simply with lxml? I have a function that does not work properly for some more difficult case (than the example): def _is_equal( el1, el2 ): # input: 2 elements with possible equal structure and tag names # e.g. root = lxml.html.fromstring( buf ) # el1 = root[ 0 ] # el2 = root[ 1 ] # move from top to bottom, compare elements result = False if el1.tag == el2.tag: # has no children if len( el1 ) == len( el2 ): if len( el1 ) == 0: return True else: # iterate one of them, for example el1 i = 0 for child1 in el1: child2 = el2[ i ] is_equal2 = _is_equal( child1, child2 ) if not is_equal2: return False return True else: return False else: return False The code fails to detect that 2 divs with class='tovar2' have an identical structure: <body> <div class="tovar2"> <h2 class="new"> <a href="http://modnyedeti-krsk.ru/magazin/product/333193003"> ?????? ?/? </a> </h2> <ul class="art"> <li> ???????: <span>1759</span> </li> </ul> <div> <div class="wrap" style="width:180px;"> <div class="new"> <img src="shop_files/new-t.png" alt=""> </div> <a class="highslide" href="http://modnyedeti-krsk.ru/d/459730/d/820.jpg" onclick="return hs.expand(this)"> <img src="shop_files/fr_5.gif" style="background:url(/d/459730/d/548470803_5.jpg) 50% 50% no-repeat scroll;" alt="?????? ?/?" height="160" width="180"> </a> </div> </div> <form action="" onsubmit="return addProductForm(17094601,333193003,3150.00,this,false);"> <ul class="bott "> <li class="price">????:<br> <span> <b> 3 150 </b> ???. </span> </li> <li class="amount">???-??:<br><input class="number" onclick="this.select()" value="1" name="product_amount" type="text"> </li> <li class="buy"><input value="" type="submit"> </li> </ul> </form> </div> <div class="tovar2"> <h2 class="new"> <a href="http://modnyedeti-krsk.ru/magazin/product/333124803">?????? ?/?</a> </h2> <ul class="art"> <li> ???????: <span>1759</span> </li> </ul> <div> <div class="wrap" style="width:180px;"> <div class="new"> <img src="shop_files/new-t.png" alt=""> </div> <a class="highslide" href="http://modnyedeti-krsk.ru/d/459730/d/820.jpg" onclick="return hs.expand(this)"> <img src="shop_files/fr_5.gif" style="background:url(/d/459730/d/548470803_5.jpg) 50% 50% no-repeat scroll;" alt="?????? ?/?" height="160" width="180"> </a> </div> </div> <form action="" onsubmit="return addProductForm(17094601,333124803,3150.00,this,false);"> <ul class="bott "> <li class="price">????:<br> <span> <b>3 150</b> ???. </span> </li> <li class="amount">???-??:<br><input class="number" onclick="this.select()" value="1" name="product_amount" type="text"> </li> <li class="buy"> <input value="" type="submit"> </li> </ul> </form> </div> </body>

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  • Function for averages of tuples in a dictionary

    - by Billy Mann
    I have a string, dictionary in the form: ('the head', {'exploded': (3.5, 1.0), 'the': (5.0, 1.0), "puppy's": (9.0, 1.0), 'head': (6.0, 1.0)}) Each parentheses is a tuple which corresponds to (score, standard deviation). I'm taking the average of just the first integer in each tuple. I've tried this: def score(string, d): for word in d: (score, std) = d[word] d[word]=float(score),float(std) if word in string: word = string.lower() number = len(string) return sum([v[0] for v in d.values()]) / float(len(d)) if len(string) == 0: return 0 When I run: print score('the head', {'exploded': (3.5, 1.0), 'the': (5.0, 1.0), "puppy's": (9.0, 1.0), 'head': (6.0, 1.0)}) I should get 5.5 but instead I'm getting 5.875. Can't figure out what in my function is not allowing me to get the correct answer.

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  • supervisord environment variables setting up application

    - by user1434844
    I'm running an application from supervisord and I have to set up an environment for it. There are about 30 environment variables that need to be set. I've tried putting all on one big environment= line and that doesn't seem to work. I've also tried multiple enviroment= lines, and that doesn't seem to work either. I've also tried both with and without ' around the env value. What's the best way to set up my environment such that it remains intact under supervisord control? Should I be calling my actual program (tornado, fwiw) from a shell script with the environment preloaded there? Ideally, I'd like to put all of the enviroment variables into an include file and load them with supervisor, but I'm open to doing it another way.

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  • BeautifulSoup: just get inside of a tag, no matter how many enclosing tags there are

    - by AP257
    I'm trying to scrape all the inner html from the <p> elements in a web page using BeautifulSoup. There are internal tags, but I don't care, I just want to get the internal text. For example, for: <p>Red</p> <p><i>Blue</i></p> <p>Yellow</p> <p>Light <b>green</b></p> How can I extract: Red Blue Yellow Light green Neither .string nor .contents[0] does what I need. Nor does .extract(), because I don't want to have to specify the internal tags in advance - I want to deal with any that may occur. Is there a 'just get the visible HTML' type of method in BeautifulSoup? ----UPDATE------ On advice, trying: p_tags = page.findAll('p',text=True) for i, p_tag in enumerate(p_tags): print str(p_tag) But that doesn't help - it just prints out: Red <i>Blue</i> Yellow Light <b>green</b>

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  • Updating section in ConfigParser (or an alternative)

    - by lyrae
    I am making a plugin for another program and so I am trying to make thing as lightweight as possible. What i need to do is be able to update the name of a section in the ConfigParser's config file. [project name] author:john doe email: [email protected] year: 2010 I then have text fields where user can edit project's name, author, email and year. I don't think changing [project name] is possible, so I have thought of two solutions: 1 -Have my config file like this: [0] projectname: foobar author:john doe email: [email protected] year: 2010 that way i can change project's name just like another option. But the problem is, i would need the section # to be auto incremented. And to do this i would have to get every section, sort of, and figure out what the next number should be. The other option would be to delete the entire section and its value, and re-add it with the updated values which would require a little more work as well, such as passing a variable that holds the old section name through functions, etc, but i wouldn't mind if it's faster. Which of the two is best? or is there another way? I am willing to go with the fastest/lightweight solution possible, doesn't matter if it requires more work or not.

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  • PyQt - QLabel inheriting

    - by Ockonal
    Hello, i wanna inherit QLabel to add there click event processing. I'm trying this code: class NewLabel(QtGui.QLabel): def __init__(self, parent): QtGui.QLabel.__init__(self, parent) def clickEvent(self, event): print 'Label clicked!' But after clicking I have no line 'Label clicked!' EDIT: Okay, now I'm using not 'clickEvent' but 'mousePressEvent'. And I still have a question. How can i know what exactly label was clicked? For example, i have 2 edit box and 2 labels. Labels content are pixmaps. So there aren't any text in labels, so i can't discern difference between labels. How can i do that? EDIT2: I made this code: class NewLabel(QtGui.QLabel): def __init__(self, firstLabel): QtGui.QLabel.__init__(self, firstLabel) def mousePressEvent(self, event): print 'Clicked' #myLabel = self.sender() # None =) self.emit(QtCore.SIGNAL('clicked()'), "Label pressed") In another class: self.FirstLang = NewLabel(Form) QtCore.QObject.connect(self.FirstLang, QtCore.SIGNAL('clicked()'), self.labelPressed) Slot in the same class: def labelPressed(self): print 'in labelPressed' print self.sender() But there isn't sender object in self. What i did wrong?

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  • google contacts api service account oauth2.0 sub user

    - by user3709507
    I am trying to use the Google Contacts API to connect to a user's contact information, on my Google apps domain. Generating an access_token using the gdata api's ContactsService clientlogin function while using the API key for my project works fine, but I would prefer to not store the user's credentials, and from the information I have found that method uses OAuth1.0 So, to use OAuth2.0 I have: Generated a Service Account in the developer's console for my project Granted access to the service account for the scope of https://www.google.com/m8/feeds/ in the Google apps domain admin panel Attempted to generate credentials using SignedJwtAssertionCredentials: credentials = SignedJwtAssertionCredentials( service_account_name=service_account_email, private_key=key_from_p12_file, scope='https://www.google.com/m8/feeds/', sub=user_email') The problem I am running into is that attempting to generate an access token using this method fails. It succeeds in generating the token when I remove the sub parameter, but then that token fails when I try to fetch the user's contacts. Does anyone know why this might be happening?

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  • Django url tag multiple parameters

    - by Overdose
    I have two similar codes. The first one works as expected. urlpatterns = patterns('', (r'^(?P<n1>\d)/test/', test), (r'', test2), {% url testapp.views.test n1=5 %} But adding the second parameter makes the result return empty string. urlpatterns = patterns('', (r'^(?P<n1>\d)/test(?P<n2>\d)/', test), (r'', test2),) {% url testapp.views.test n1=5, n2=2 %} Views signature: def test(request, n1, n2=1):

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  • about the post_save signal and created argument

    - by panchicore
    the docs says: post_save django.db.models.signals.post_save created A boolean; True if a -new- record was create. and I have this: from django.db.models.signals import post_save def handle_new_user(sender, instance, created, **kwargs): print "--------> save() "+str(created) post_save.connect(handle_new_user, sender=User) when I do in shell: u = User(username="cat") u.save() >>> --------> save() True u.username = "dog" u.save() >>> --------> save() True I expect a -------- save() False when I save() the second time because is an update? not?

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  • Test assertions for tuples with floats

    - by Space_C0wb0y
    I have a function that returns a tuple that, among others, contains a float value. Usually I use assertAlmostEquals to compare those, but this does not work with tuples. Also, the tuple contains other data-types as well. Currently I am asserting every element of the tuple individually, but that gets too much for a list of such tuples. Is there any good way to write assertions for such cases?

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  • Is there a replacement for Paste.Template?

    - by Jorge Vargas
    I have grown tired of all the little issues with paste template, it's horrible to maintain the templates, it has no way of updating an old project and it's very hard to test. I'm wondering if someone knows of an alternative for quickstart generators as they have proven to be useful.

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  • Check result of AX_PYTHON_MODULE in configure.ac

    - by tmatth
    In using the m4_ax_python_module.m4 macro in configure.ac (AX_PYTHON_MODULE), one can know at configure time if a given module is installed. It takes two arguments, the module name, and second argument which if not empty, will lead to an exit, useful when the module is a must-have. In the case where you don't want a fatal exit, how do you test in configure.ac which modules were found or not? They output "yes" or "no" when configure is run, but that's all I've found so far. Basically If I have these lines in configure.ac: AX_PYTHON_MODULE(json,[]) AX_PYTHON_MODULE(simplejson,[]) How do I test which of the two modules were found? See http://www.gnu.org/software/autoconf-archive/ax_python_module.html#ax_python_module for documentation about this macro.

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  • Django Piston - how can I create custom methods?

    - by orokusaki
    I put my questions in the code comments for clarity: from piston.handler import AnonymousBaseHandler class AnonymousAPITest(AnonymousBaseHandler): fields = ('update_subscription',) def update_subscription(self, request, months): # Do some stuff here to update a subscription based on the # number of months provided. # How the heck can I call this method? return {'msg': 'Your subscription has been updated!'} def read(self, request): return { 'msg': 'Why would I need a read() method on a fully custom API?' }

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  • Can I move beaker.SessionMiddleware to handle method somehow?

    - by Alexander A.Sosnovskiy
    It's a bit ugly that many lines of code fall into "__main__". Can someone give me a tip of how to move SessionMiddleware into handle method? I should notice that I use session in CoreXmlParser. Thanks in advance ! def handle(environ, start_response): req = webob.Request(environ) c = CoreXmlParser(req) resp = webob.Response(body=c(), charset = 'utf-8', status='200 OK', \ request=req, content_type='text/xml') resp(environ, start_response) return resp.app_iter if __name__ == '__main__': #parse config file for session options app = SessionMiddleware(handle, some_session_opts_here) from flup.server.fcgi import WSGIServer WSGIServer(app).run()

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  • Can I create class properties during __new__ or __init__?

    - by 007brendan
    I want to do something like this. The _print_attr function is designed to be called lazily, so I don't want to evaluate it in the init and set the value to attr. I would like to make attr a property that computes _print_attr only when accessed: class Base(object): def __init__(self): for attr in self._edl_uniform_attrs: setattr(self, attr, property(lambda self: self._print_attr(attr))) def _print_attr(self, attr): print attr class Child(Base): _edl_uniform_attrs = ['foo', 'bar'] me = Child() me.foo me.bar #output: #"foo" #"bar"

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  • Getting the previous line in Jython

    - by kdev
    I want to print the line immediately before the searched string. How can I do that? Lets say my two lines are AADRG SDFJGKDFSDF and I am searching for SDF. I have found SDFJGKDFSDF, but how can I obtain the previous line AADRG? Does file.readline()-1 work?

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  • Trie Backtracking in Recursion

    - by Darksky
    I am building a tree for a spell checker with suggestions. Each node contains a key (a letter) and a value (array of letters down that path). So assume the following sub-trie in my big trie: W / \ a e | | k k | | is word--> e e | ... This is just a subpath of a sub-trie. W is a node and a and e are two nodes in its value array etc... At each node, I check if the next letter in the word is a value of the node. I am trying to support mistyped vowels for now. So 'weke' will yield 'wake' as a suggestion. Here's my searchWord function in my trie: def searchWord(self, word, path=""): if len(word) > 0: key = word[0] word = word[1:] if self.values.has_key(key): path = path + key nextNode = self.values[key] return nextNode.searchWord(word, path) else: # check here if key is a vowel. If it is, check for other vowel substitutes else: if self.isWord: return path # this is the word found else: return None Given 'weke', at the end when word is of length zero and path is 'weke', my code will hit the second big else block. weke is not marked as a word and so it will return with None. This will return out of searchWord with None. To avoid this, at each stack unwind or recursion backtrack, I need to check if a letter is a vowel and if it is, do the checking again. I changed the if self.values.has_key(key) loop to the following: if self.values.has_key(key): path = path + key nextNode = self.values[key] ret = nextNode.searchWord(word, path) if ret == None: # check if key == vowel and replace path # return nextNode.searchWord(... return ret What am I doing wrong here? What can I do when backtracking to achieve what I'm trying to do?

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  • Unable to plot graph using matplotlib

    - by Aman Deep Gautam
    I have the following code which searches all the directory in the current directory and then takes data from those files to plot the graph. The data is read correctly as verified by printing but there are no points plotted on graph. import argparse import os import matplotlib.pyplot as plt #find the present working directory pwd=os.path.dirname(os.path.abspath(__file__)) #find all the folders in the present working directory. dirs = [f for f in os.listdir('.') if os.path.isdir(f)] plt.figure() plt.xlim(0, 20000) plt.ylim(0, 1) for directory in dirs: os.chdir(os.path.join(pwd, directory)); chd_dir = os.path.dirname(os.path.abspath(__file__)) files = [ fl for fl in os.listdir('.') if os.path.isfile(fl) ] print files for f in files: f_obj = open(os.path.join(chd_dir, f), 'r') list_x = [] list_y = [] for i in xrange(0,4): f_obj.next() for line in f_obj: temp_list = line.split() print temp_list list_y.append(temp_list[0]) list_x.append(temp_list[1]) print 'final_lsit' print list_x print list_y plt.plot(list_x, list_y, 'r.') f_obj.close() os.chdir(pwd) plt.savefig("test.jpg") The input files look like the following: 5 865 14709 15573 14709 1.32667e-06 664 0.815601 14719 1.55333e-06 674 0.813277 14729 1.82667e-06 684 0.810185 14739 1.4e-06 694 0.808459 Can anybody help me with why this is happening? Being new I would like to know some tutorial where I can get help with kind of plotting as the tutorial I was following made me end up here. Any help appreciated.

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  • Breadth first search all paths

    - by Amndeep7
    First of all, thank you for looking at this question. For a school assignment we're supposed to create a BFS algorithm and use it to do various things. One of these things is that we're supposed to find all of the paths between the root and the goal nodes of a graph. I have no idea how to do this as I can't find a way to keep track of all of the alternate routes without also including copies/cycles. Here is my BFS code: def makePath(predecessors, last): return makePath(predecessors, predecessors[last]) + [last] if last else [] def BFS1b(node, goal): Q = [node] predecessor = {node:None} while Q: current = Q.pop(0) if current[0] == goal: return makePath(predecessor, goal) for subnode in graph[current[0]][2:]: if subnode[0] not in predecessor: predecessor[subnode[0]] = current[0] Q.append(subnode[0]) A conceptual push in the right direction would be greatly appreciated. tl;dr How do I use BFS to find all of the paths between two nodes?

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