SOLVED: Lisp: macro calling a function works in interpreter, fails in compiler (SBCL + CMUCL)
- by ttsiodras
As suggested in a macro-related question I recently posted to SO, I coded a macro called "fast" via a call to a function (here is the standalone code in pastebin):
(defun main ()
(progn
(format t "~A~%" (+ 1 2 (* 3 4) (+ 5 (- 8 6))))
(format t "~A~%" (fast (+ 1 2 (* 3 4) (+ 5 (- 8 6)))))))
This works in the REPL, under both SBCL and CMUCL:
$ sbcl
This is SBCL 1.0.52, an implementation of ANSI Common Lisp.
...
* (load "bug.cl")
22
22
$
Unfortunately, however, the code no longer compiles:
$ sbcl
This is SBCL 1.0.52, an implementation of ANSI Common Lisp.
...
* (compile-file "bug.cl")
...
; during macroexpansion of (FAST (+ 1 2 ...)). Use *BREAK-ON-SIGNALS* to
; intercept:
;
; The function COMMON-LISP-USER::CLONE is undefined.
So it seems that by having my macro "fast" call functions ("clone","operation-p") at compile-time, I trigger issues in Lisp compilers (verified in both CMUCL and SBCL).
Any ideas on what I am doing wrong and/or how to fix this?
