XPATH: multiple negations in for-each
- by Peter
I have the following simplified XML:
<?xml version="1.0" encoding="UTF-8" ?>
<MATMAS05>
<IDOC BEGIN="1">
<E1MARAM SEGMENT="1">
<MSGFN>005</MSGFN>
<MATNR>000000000000401436</MATNR>
<E1MARCM SEGMENT="1">
<MSGFN>005</MSGFN>
<WERKS>A120</WERKS>
<MMSTA>01</MMSTA>
</E1MARCM>
<E1MVKEM SEGMENT="1">
<VKORG>0120</VKORG>
<VMSTA>04</VMSTA>
</E1MVKEM>
</E1MARAM>
</IDOC>
</MATMAS05>
If <WERKS>=A120 and <MMSTA> is NOT '01' or '02' or '03' OR if <VKORG>=0120 and <VMSTA> is NOT '01' or '02' or '03' then the <MATNR> should be mapped to the target XML.
I came up with the following XSLT:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output encoding="UTF-8" method="xml" indent="yes"/>
<xsl:template match="/*">
<xsl:for-each
select="IDOC[(E1MARAM/E1MVKEM[VKORG='0120'][not(VMSTA='01' or VMSTA='02' or VMSTA='03')])
or (E1MARAM/E1MARCM[WERKS = 'A120'][not(MMSTA='01' or MMSTA='02' or MMSTA='03')])]">
<Item>
<ITEM_CODE>
<xsl:value-of select="E1MARAM/MATNR"/>
</ITEM_CODE>
</Item>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
But if I apply that XSLT I get the following unwanted output (because <MMSTA>='01'):
<?xml version="1.0" encoding="UTF-8"?>
<Item>
<ITEM_CODE>000000000000401436</ITEM_CODE>
</Item>
How can I solve this? I have tried around with that XPATH expression but I can't get the wanted result. What am I doing wrong in my XPATH?
Thank you for any ideas with this.
Best regards,
Peter
